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a store sold 54 t-shirts and 33 sweatshirts yesterday what is the ratio of the number of T-shirts sold to the number of sweatshirts


18:11

11:7

11:18

7:11

Answer: $12.6165

Step-by-step explanation:

Finance charge = Average daily balance × monthly periodic rate.

where,

Monthly periodic rate = APR / 12 months

Monthly periodic rate = 15.6% / 12

= 0.156 / 12

= 0.013

Finance charge = $970.50 × 0.013

= $12.6165

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Answer:

answer: $5

Step-by-step explanation:

If your asking whats 100% of $5 then $5 is the answer because $5 is 100% of $5

Answer:

$5

Step-by-step explanation:

\(\frac{y}{5} :\frac{100}{100}\)

y · 100 = 5 · 100

100y = 500

100y ÷ 100 = 500 ÷ 100

y = 5

By applying sample space concept, it can be concluded that the sample space for this experience is {(0,g), (0,f), (0,s), (1,g), (1,f), (1,s)}.

Sample space is the collection of all possible outcomes of an experiment.

Complement of a set A is a set whose members are members of the sample space but are not members of set A. It is mathematically written as \(A^{c}\).

Some code used in the problem:

1 = have insurance

0 = not have insurance

g = good

f = fair

s = serious

The sample space (S) for this experience describes all possible outcomes, combining the insurance possession and the condition.

S = {(0,g), (0,f), (0,s), (1,g), (1,f), (1,s)}

If A = event that the patient is in serious condition, then the outcomes in A = {(0,s), (1,s)}

If B = event that the patient is uninsured, then the outcomes in B = {(0,g), (0,f), (0,s)}

The outcomes in event \(B^{c}\) ∪ A can be obtained by determining the outcomes of \(B^{c}\).

\(B^{c}\) = {(1,g), (1,f), (1,s)}

so \(B^{c}\) ∪ A = {(1, g), (1, f), (1, s), (0, s)}

Original question:

A hospital administrator codes incoming patients suffering gunshot wounds according to whether they have insurance (coding 1 if they do and 0 if they do not) and according to their condition, which is rated as good (g), fair (f), or serious (s). Consider an experiment that consists of the coding of such patients.  

(a) Give the sample space of this experiment.  

(b) Let A be the event that the patients is in serious condition. Specify the outcomes in A.  

(c) Let B be the event that the patients is uninsured. Specify the outcomes in B.  

(d) Give all the outcomes in the event \(B^{c}\) ∪ A

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The lengths of the sides of the quadrilaterals ABCD and LMNO indicates that the proportions of the sizes of the two quadrilateral are different, and Kyle is correct

A quadrilateral is a polygon that has four sides and four interior angles.

The lengths of the sides of quadrilateral ABCD are;

AB = √((4 - 3)² + (2 - 1)²) = √2

BC = √((4 - 5)² + (2 - 5)²) = √(10)

CD = √((4 - 5)² + (2 - 5)²) = √(10)

AD = √((4 - 1)² + (2 - 3)²) = √(10)

Lengths of the sides of the quadrilateral LMNO are;

LM = √((16.4 - 14.2)² + (4.2 - 6.4)²) = √(9.68)

MN = √((16.4 - 23.4)² + (4.2 - 1.9)²) = √(54.29)

NO = √((21.1 - 23.4)² + (8.7 - 1.9)²) = √(51.53)

LO = √((21.1 - 14.2)² + (8.7 - 6.4)²) = √(52.9)

The lengths of three of the sides of the quadrilateral ABCD are congruent, while the quadrilateral LMNO is a scalene quadrilateral, therefore, the lengths of the sides of the quadrilateral are not proportional, and the quadrilaterals ABCD and LMNO are not similar, which indicates that Kyle is correct

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Explanation:

The original equation is in the form a+b = 1, where

a = sin(theta)

b = cos(theta)

Square both sides of a+b = 1 to get

(a+b)^2 = 1^2

a^2+2ab+b^2 = 1

(a^2+b^2)+2ab = 1

From here notice that a^2+b^2 is sin^2+cos^2 = 1, which is the pythagorean trig identity. So we go from (a^2+b^2)+2ab = 1 to 1+2ab = 1 to 2ab = 0 to ab = 0

Therefore,

sin(theta)*cos(theta) = 0

Answer:

sin ∅ cos ∅ = 0.

Step-by-step explanation:

(sin∅+cos∅)^2 = 1^2 = 1

(sin∅+cos∅)^2  = sin^2∅ + cos^2∅ + 2sin ∅ cos ∅ = 1

But  sin^2∅ + cos^2∅ = 1, so:  

2sin ∅ cos ∅ + 1 = 1

2 sin ∅ cos ∅ = 1 - 1 = 0

sin ∅ cos ∅ = 0.

45 billion Korean Won is equal to 45 million US Dollars.

The formula for  (USD) is USD = KRW / 1000. To calculate 45 billion won in USD, we must first convert KRW to USD. 45 billion KRW is equal to 45,000,000,000 KRW. Using the formula above, we can calculate the amount of USD:

USD = 45,000,000,000 KRW / 1000

USD = 45,000,000 USD

Therefore, 45 billion won is equal to 45 million US Dollars.

To better understand this conversion, it is important to remember that one US Dollar is equal to 1000 Korean Won. As an example, if you have 10,000 Korean Won, you can convert that to USD by dividing 10,000 by 1000, which equals 10 USD. The same concept applies when converting larger numbers. To convert 45 billion KRW to USD, we must divide 45,000,000,000 by 1000, which equals 45,000,000 USD.

In conclusion, 45 billion Korean Won is equal to 45 million US Dollars.

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The power of the test is low and not sufficient to detect a significant difference between the two treatments with the given sample size of 35.

To calculate the expected power of the test, we need to consider the survival rates, the significance level, and the sample size. Let's follow these steps:

Determine the proportions
Old treatment survival rate (p1) = 0.75
New treatment survival rate (p2) = 0.85

Determine the significance level
Two-sided significant difference level (α) = 0.05

Calculate the pooled proportion
Pooled proportion (p) = (p1 + p2) / 2 = (0.75 + 0.85) / 2 = 0.80

Calculate the standard error
Standard error (SE) = √(p × (1 - p) × (1/n1 + 1/n2)) = √(0.80 × (1 - 0.80) × (1/35 + 1/35)) ≈ 0.065

Calculate the test statistic (z)
z = (p2 - p1) / SE = (0.85 - 0.75) / 0.065 ≈ 1.54

Find the critical value for the two-sided significant difference at the 5% level
z_critical = 1.96 (from a standard normal distribution table)

Calculate the power of the test
In this case, since the test statistic is smaller than the critical value (1.54 < 1.96), we cannot reject the null hypothesis at the 5% significance level.
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\(\\ \sf\longmapsto 1^2\times \dfrac{1}{4}m^2\)

\(\\ \sf\longmapsto \dfrac{1}{4}m^2\)

Now

\(\\ \sf\longmapsto \dfrac{1}{4}m^2\times -6m\)

\(\\ \sf\longmapsto \dfrac{-6}{4}m^3\)

\(\\ \sf\longmapsto \dfrac{-3}{2}m^3\)

The solution of the system of equations f(x) = 2^x + 1 and g(x) = 3^x is x = 1

From the question, we have the following parameters that can be used in our computation:

f(x) = 2^x + 1

g(x) = 3^x

The above expression is a system of exponential equations

We are required to solve by graph

That implies that we graph the equations in the system on the same plane and write out ordered pairs from the point of intersection of the equations in the system

Next, we plot the graph

See attachment for the graph of the equations

The ordered pairs of the intersection point is (1, 3)

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Answer:

Let ac=ab=5

With this, bc= 5√2

Step-by-step explanation:

So to find ad, Let ad be x

5√2=(2)(x)

(5√2/2)= x

This proves that bc=2ad

Answer:

f(1) = 2

f(n) = 2 × f(n - 1) , n ≥ 2

Step-by-step explanation:

the point of coordinates (1 , 2) is on the graph

Then

f(1) = 2

…………………………

We notice that :

f(2) = 4

f(3) = 8

f(4) = 16

16/8 = 8/4 = 4/2 = 2/1 = 2

________________________

This means the common ratio

of the geo sequence = 2

Hence ,

f(n) = 2 × f(n - 1)

Answer: f(n) = 2 × f(n - 1) , n ≥ 2

Step-by-step explanation:

Answer:

i dont get it is it an angle or a triangle

The valid conclusion about the mean of the number of times the drivers had to take the driving test is that it is greater than 1.

Since only two out of the 100 drivers needed to take the test exactly once and nobody needed to take it more than three times, we can infer that the majority of drivers required at least two attempts to pass the driving test. This implies that the mean of the number of times they had to take the test is greater than 1.

If the mean were less than or equal to 1, it would suggest that a significant portion of the sample passed the test on their first attempt, contradicting the information given. Similarly, if the mean were equal to or greater than 3, it would imply that a considerable number of drivers needed to take the test more than three times, which is also inconsistent with the provided data.

The fact that only two drivers passed on their first attempt and none needed more than three attempts indicates that the majority of drivers required multiple attempts to pass the test. Therefore, the mean of the number of times they had to take the test is greater than 1.

The valid conclusion about the mean of the number of times the drivers had to take the driving test is that it is greater than 1. This conclusion is based on the information provided, which states that only two out of the 100 drivers needed to take the test exactly once and nobody needed to take it more than three times.

From the given data, we can infer that the majority of drivers required multiple attempts to pass the driving test. If the mean were less than or equal to 1, it would suggest that a significant portion of the sample passed the test on their first attempt, which contradicts the information provided. Similarly, if the mean were equal to or greater than 3, it would imply that a considerable number of drivers needed to take the test more than three times, which is also inconsistent with the given data.

Therefore, based on the fact that only two drivers passed on their first attempt and none needed more than three attempts, we can conclude that the mean of the number of times they had to take the test is greater than 1.

Understanding statistical measures, such as the mean, is crucial in interpreting data and drawing accurate conclusions. The mean represents the average value of a variable and provides insights into the central tendency of a data set. By considering the given information and analyzing the data, we can make valid conclusions about the mean in this scenario.

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Answer:

See the image for solution.

Brainlist please!!

Given f(x,y) = x³ -2xy + xy³ + 3y². We are to find fxy.The function f(x,y) can be represented as,  f(x,y) = x³ - 2xy + xy³ + 3y²To find fxy,

we must first differentiate f(x,y) with respect to x and then y. We will obtain fxy by differentiating this result with respect to y. Below is the step-by-step solution:

Step 1: Find fx. f(x,y) = x³ - 2xy + xy³ + 3y² ∂/∂x f(x,y) = 3x² - 2y + y³ ………..(1)

Step 2: Find fy. f(x,y) = x³ - 2xy + xy³ + 3y² ∂/∂y f(x,y) = -2x + 3xy² + 6y………..(2)

Step 3: Find fxy. Differentiating (2) with respect to x, we get ∂/∂x (∂/∂y f(x,y)) = ∂/∂x (-2x + 3xy² + 6y) ∂²f/∂xdy = 3y²Differentiating (1) with respect to y, we get ∂/∂y (∂/∂x f(x,y)) = ∂/∂y (3x² - 2y + y³) ∂²f/∂ydx = 3y²Therefore, fxy = ∂²f/∂xdy = ∂²f/∂ydx = 3y²

In conclusion, we obtained f(x,y) = x³ - 2xy + xy³ + 3y², fx = 3x² - 2y + y³, fy = -2x + 3xy² + 6y, and fxy = 3y². Therefore, the answer is 3y².

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She must put in at least 5 raisins so that the probability of a randomly chosen slice have no raisins is 0.01.

a. If she puts 100 raisins into a batch of dough, the probability that a randomly chosen slice of bread contains no raisins is\((20-1/20)^100\), which is equal to 0.36.

b. If she puts 200 raisins into a batch of dough, the probability that a randomly chosen slice of bread contains 5 raisins is\((200C5)*(20-5/20)^195\), which is equal to 0.0122.

c. To find the number of raisins she must put in so that the probability that a randomly chosen slice will have no raisins is 0.01, we can use the formula \((20-1/20)^x = 0.01\), where x is the number of raisins. Solving for x yields x = 4.76 or 5. Therefore, she must put in at least 5 raisins so that the probability of a randomly chosen slice have no raisins is 0.01.

She must put in at least 5 raisins so that the probability of a randomly chosen slice have no raisins is 0.01.

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Angle-Angle (AA) similarity postulate,  if two angles of one triangle are congruent to two angles of another, then the triangles are similar.

Similar triangles are the triangles that have corresponding sides in proportion to each other and corresponding angles equal to each other. Similar triangles look the same but the sizes can be different.

As per the diagram,

Triangles RPQ & RST are similar since

∠P = ∠S & ∠Q = ∠T

Side - side - side (SSS) similarity theorem - If the lengths of the corresponding sides of two triangles are proportional, then the triangles are similar.

Triangles RPQ & RST are similar since

RP/RS = RQ/RT = ST/PQ

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Answer:

AV and DV both are correct

Answer:

B' = (-6,6)

Step-by-step explanation:

The coordinates of B are (-2,2)

If the figure is to become 3 times as large, B' would be 3(-2,2) = (-6,6)

What are the slope and y-intercept of

25x - 20y = 100

-20y = 100 - 25x

20y = 25x - 100 (dividing by 20)

y= (25/20)x - 5

y= (5/4)x - 5

So, the slope is 5/4 and the y-intercept is 5.

Answer:

Find the equivalent ratio for the total shapes:

Total Black Shapes : Total White Shapes = 5 : 11

Multiply by 2:

Total Black Shapes: Total White Shapes = 10 : 22

Step-by-step explanation:

Let x be the number we want to find:

x + 2x + 3x = 660

6x = 660

x = 660/6 = 110

2x = 220

3x = 330

Answer:

110, 220 and 330.

Step-by-step explanation:

x + 2x + 3x = 660

6x = 660

x = 110,

The radical form of the expression  (5ab)\(^\frac{3}{2}\)  is √(125 a³b³).

Simply put, simplifying a radical eliminates the need to find any more square roots, cube roots, fourth roots, etc. when expressing it in its simplest radical form. Additionally, it entails eliminating any radicals from the denominator of a fraction.

The sign used to represent the square root or nth root. Square-root-containing expressions are known as radical expressions.

Radical equation  = b\(\frac{m}{n}\)  

= \(\sqrt[n]{b^m}\)

So,

(5ab)\(^\frac{3}{2}\) = \(\sqrt[2]{5^3}\)

\(\sqrt[2]{5^3}\) a³ b³

5³ = 125

√(125 a³b³)

The radical form of the expression  (5ab)\(^\frac{3}{2}\)  is √(125 a³b³).

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The perimeter of rhombus ABCD is 20 units.

To determine the perimeter of rhombus ABCD, we need to find the lengths of its sides. Given the coordinates of the four vertices of the rhombus (A, B, C, D), we can use the distance formula to calculate the lengths of the sides.

The coordinates of the vertices are as follows:

A(1,1), B(-2,-3), C(-5,1), D(-2,5)

Using the distance formula, we can find the lengths of the sides AB, BC, CD, and DA.

AB = √[(x2 - x1)^2 + (y2 - y1)^2]

= √[(-2 - 1)^2 + (-3 - 1)^2]

= √[9 + 16]

= √25

= 5 units

BC = √[(-5 - (-2))^2 + (1 - (-3))^2]

= √[9 + 16]

= √25

= 5 units

CD = √[(-2 - (-5))^2 + (5 - 1)^2]

= √[9 + 16]

= √25

= 5 units

DA = √[(1 - (-2))^2 + (1 - 5)^2]

= √[9 + 16]

= √25

= 5 units

Since all four sides have a length of 5 units, the perimeter of rhombus ABCD is the sum of the lengths of its sides:

Perimeter = AB + BC + CD + DA

= 5 + 5 + 5 + 5

= 20 units

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