Given: Triangle ABC Prove: m∠A=64°

By the triangle sum theorem, the sum of the angles in a triangle is equal to . Therefore, m∠A+m∠B+m∠C=180°. Using the Substitution Property, (4x)°+90°+(x+10)°=180°. To solve for x, first combine like terms to get 5x + 100 = 180. Using the Response area, 5x = 80. Then, using the division property of equality, x = 16. To find the measure of angle A, use the Response area to get m∠A=4(16)°. Finally, simplifying the expression gets m∠A=64°.

Answer:

acute

Step-by-step explanation:

Answer:

It C pls give brainlist

Step-by-step explanation:

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\)  ~  \(t_n_-_1\)

where, \(\bar X\) = sample proportion of defective items = 12,898

             s = sample standard deviation = 7,719

            n = sample size = 5

             \(\mu\) = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, \(\mu\) is ;

P(-2.776 < \(t_4\) < 2.776) = 0.95  {As the critical value of t at 4 degrees of

                                               freedom are -2.776 & 2.776 with P = 2.5%}  

P(-2.776 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 2.776) = 0.95

P( \(-2.776 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(2.776 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

P( \(\bar X-2.776 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+2.776 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95

95% confidence interval for \(\mu\) = [ \(\bar X-2.776 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X+2.776 \times {\frac{s}{\sqrt{n} } }\) ]

                                = [ \(12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }\) , \(12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }\) ]

                               = [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

If Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

To show that x is also an eigenvector of QT, we need to demonstrate that QT * x is a scalar multiple of x.

Given that Q is an orthogonal matrix, we know that QT * Q = I, where I is the identity matrix. This implies that Q * QT = I as well.

Let's denote x as the eigenvector corresponding to the eigenvalue λ1 This means that Q * x = λ1 * x.

Now, let's consider QT * x. We can multiply both sides of the equation Q * x = λ1 * x by QT:

QT * (Q * x) = QT * (λ1 * x)

Applying the associative property of matrix multiplication, we have:

(QT * Q) * x = λ1 * (QT * x)

Using the fact that Q * QT = I, we can simplify further:

I * x = λ1 * (QT * x)

Since I * x equals x, we have:

x = λ1 * (QT * x)

Now, notice that λ1 * (QT * x) is a scalar multiple of x, where the scalar is λ1. Therefore, we can rewrite the equation as:

x = λ2 * x

where λ2 = λ1 * (QT * x).

This shows that x is indeed an eigenvector of QT, with the eigenvalue λ2 = λ1 * (QT * x).

In conclusion, if Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

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The parts of the graph when labelled are :

There is the origin which is where the line starts from. The x-axis represents the independent variable, which is the variable that is being manipulated or changed in the experiment.

The y-axis represents the dependent variable, which is the variable that is being measured or observed. A trend line is a line drawn on the graph that shows the overall pattern or trend of the data. The x and y - intercepts are the points where the trend line crosses the x and y - axis.

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The linear function which represents a slope of -3 as required in the task content is; A two column table with five rows. The first column, x, has the entries, negative 5, negative 1, 3, 7. The second column, y, has the entries, 32, 24, 16, 8.

It follows that the task requires that a linear function whose slope, i.e rate of change is -2 is to be determined.

Since slope is the rate of change in y with respect to x;

The required linear function is; A two column table with five rows. The first column, x, has the entries, -5, -1, 3, 7. The second column, y, has the entries, 32, 24, 16, 8 so that we have;

Slope = (24 - 32) / (-1 -(-5)) = -8 / 4 = -2.

Remarks: The complete question is such that the required slope is -2.

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Answer: the second option

Step-by-step explanation:

i took the assignment

The mean of the sampling distribution of the difference in sample proportion is 0.13

The SD is given as 0.13 and option D is correct.

Standard deviation is a measure of the amount of variation or dispersion in a set of data values. It is a widely used statistic in probability and statistics that helps to quantify the average distance of individual data points from the mean (average) of the data set.

A small standard deviation indicates that the data points are closely clustered around the mean, while a large standard deviation implies that the data points are more spread out.

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Answer:

Step-by-step explanation:

Step 1:First Make 3/4 and 5/6 into like fractions.Find the L.C.M of 4 and  

            6,which is 12.

            3*3/4*3=9/12

             5*2/6*2=10/12

Step 2:Subtract 9/12 from 10/12,which is 1/12.

Step-by-step explanation:

I assume A n B means the intersection of the sets A and B.

that means all the elements that are in A and in B.

that is the set {1, 2}

Answer:

We can use the formula for the area of a rectangle to solve this problem. Let's assume that the length of the top of the bookcase is L and the width is b. Then, we can write:

L × b = 300

Solving for b, we get:

b = 300 / L

Since we don't know the length L, we cannot find the exact value of b. However, we can use the given information to make an estimate. Let's say that the length of the bookcase is 60 inches. Then, we have:

b = 300 / 60 = 5

So, if the length of the bookcase is 60 inches, the width needs to be at least 5 inches to accommodate Bria's soap carving collection. However, if the length is different, the required width will also be different.

The given function is:

The x-intercept is the value of x when y = 0.

The y-intercept is the value of y when x = 0.

.

∠A = 41.81°

To get measure of angle A, we would apply trigonometry ratio SOHCAHTOA:

opposite = side opposite the angle = 4

hypotenuse = 6

adjacent = base = AC = ?

Since we have been given the opposite and the hypotenuse, we would use the sine ratio:

Sin A = opposite/hypotenuse

Sin A = 4/6

sin A = 0.6667

A = 41.8129 degrees

To the nearest hundredth, ∠A = 41.81°

Answer:

12

Step-by-step explanation:

Given that,

f(x) = 2x² - 3x + 7

To find the value of f ( 2.5 ), replace x with 2.5 and solve the equation.

Let us solve it now.

f(2.5) = 2(2.5)² - 3×2.5 + 7

f(2.5) = 12.5 - 7.5 + 7

f(2.5) = 12

Answer:

\(f(x) = 2 {x}^{2} - 3x + 7 \\ f(2.5) = 2 {(2.5)}^{2} - 3(2.5) + 7 \\ f(2.5) = 12.5 - 7.5 + 7 \\ \boxed{f(2.5) = 12}\)

Answer:

All i have to say is be kind. Thats all.

Step-by-step explanation:

Answer:

the answer is b, c, d, a, respectively

To solve this problem, we need to find the lengths of the two pieces when the wire is cut into two parts. Let's denote the length of each leg of the triangle as\(\(x\).\)

The perimeter of the triangle is the sum of the lengths of its three sides. Since the two legs are equal in length, the perimeter can be expressed as \(\(2x + x = 3x\).\)

The length of the wire is given as 71 cm, so we have the equation \(\(3x = 71\).\)

Solving for\(\(x\),\) we divide both sides of the equation by 3:

\(\(x = \frac{71}{3}\).\)

Now that we know the length of each leg of the triangle, we can proceed to the next part of the problem.

The circumference of a circle is given by the formula \(\(C = 2\pi r\)\), where\(\(C\)\)is the circumference and r is the radius. In this case, the wire of length xis bent into the shape of a circle, so we can set the circumference equal to x and solve for the radius r:

\(\(x = 2\pi r\).\)

Substituting the value of x we found earlier, we have:

\(\(\frac{71}{3} = 2\pi r\).\)

Solving for r, we divide both sides of the equation by \(\(2\pi\):\)

\(\(r = \frac{71}{6\pi}\).\)

Therefore, the two pieces of wire will have lengths\(\(\frac{71}{3}\)\)cm and the radius of the circle will be\(\(\frac{71}{6\pi}\)\) cm.

In summary, when the 71 cm wire is cut into two pieces, one piece will have a length o\(\(\frac{71}{3}\)\)cm, which can be bent into the shape of an equilateral triangle with legs of equal length, and the other piece can be bent into the shape of a circle with a radius of \(\(\frac{71}{6\pi}\)\) cm.

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The length of AB is 78.

Given,

C bisects AB.

If AC = 8x - 1 and BC = 4x + 19.

We need to find the length of AB.

We have,

C bisects AB.

It means AB into two equal halves.

So,

A________C________B

AC = BC

AC = 8x - 1 and BC = 4x + 19

8x - 1 = 4x + 19

Subtracting -4x on both sides

8x - 1 - 4x = 4x + 19 - 4x

4x - 1  = 19

Adding 1 on both sides

4x - 1 + 1 = 19 + 1

4x = 20

x = 20/4

x = 5

AB = AC + BC

AB = 8x - 1 + 4x + 19

AB = 12x + 18

AB = 12 x 5 + 18

AB = 60 + 18

AB = 78

Thus the length of AB is 78.

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Answer:

E  =  324

Step by step explanation:

3(2+x)

open the parenthesis

= 6 + 3x

3(2+x) = 6 + 3x

Hence the statement of equality is true

H is the correct option

Answer:

  (a)  3x +y = 2

Step-by-step explanation:

You want the equation y = -3x +2 written in standard form.

The standard form of a linear equation is ...

  ax +by = c

where a, b, c are mutually prime integers with a ≥ 0. If a=0, then b > 0.

To put the given equation into that form, we can add 3x to both sides:

  3x +y = 3x -3x +2

  3x +y = 2

The given graph shows that the function is periodic and fluctuates between y = -2 and y = 2. So, the range of the function is [-2,2].

The graph covers one period, which is from x = -3 to x = 3, and then repeats itself indefinitely in both directions. So, the domain of the function is (-∞, ∞).

In general, the domain of a function consists of all the possible input values that the function can take. In this case, since the function repeats itself indefinitely, it can take any input value from negative infinity to positive infinity.

So, the domain is (-∞, ∞). The range of a function, on the other hand, consists of all the possible output values that the function can produce.

In this case, the function oscillates between y = -2 and y = 2, so the range is [-2,2]. The interval notation for the domain is (-∞, ∞) and for the range is [-2,2].

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Answer:

\(t = \frac{3sr}{2a \ + \ 5s}\)

Step-by-step explanation:

Given expression;

\(S = \frac{2at}{3r - 5t}\)

To make "t" the subject of the formula, cross and multiply;

\(S(3r - 5t) = 2at\\\\\)

open the bracket;

3sr - 5st = 2at

collect like terms together;

3sr = 2at + 5st

Factor out "t" on the right hand side;

3sr = t(2a + 5s)

Finally, make "t" the subject of the formula by dividing both sides by (2a + 5s).

\(t = \frac{3sr}{2a \ + \ 5s}\)

Answer: To find A and B such that g(x) = f(x) is bijective, we need to ensure that g(x) satisfies the conditions for a bijective function, namely, that it is both injective and surjective.

To show that g(x) is injective, we need to show that for any distinct x1, x2 in A, g(x1) ≠ g(x2). We can do this by assuming that g(x1) = g(x2) and then showing that it leads to a contradiction.

So, let's assume that g(x1) = g(x2). Then, we have:

f(x1) = f(x2)

x1(x1-1) = x2(x2-1)

x1^2 - x1 = x2^2 - x2

x1^2 - x2^2 - x1 + x2 = 0

(x1 - x2)(x1 + x2 - 1) = 0

Since x1 and x2 are distinct, we must have x1 + x2 = 1.

But this is impossible, since x1 and x2 are both real numbers, and the sum of two real numbers cannot equal 1 unless one of them is complex. Therefore, our assumption that g(x1) = g(x2) must be false, and g(x) is injective.

To show that g(x) is surjective, we need to show that for any y in B, there exists at least one x in A such that g(x) = y. In other words, we need to find an expression for x in terms of y.

So, let's solve the equation f(x) = y for x:

x(x-1) = y

x^2 - x - y = 0

Using the quadratic formula, we get:

x = (1 ± √(1 + 4y))/2

Since we want to define g(x) on R, we need to ensure that the expression under the square root is non-negative. This means that 1 + 4y ≥ 0, or y ≥ -1/4.

Therefore, we can define A = [-1/4, ∞) and B = [0, ∞), and g(x) = f(x) is a bijective function from A to B.

The inverse of matrix A, if it exists, is:

A^(-1) = [7/43, 2/43; 10/43, 9/43]

To find the inverse of a matrix A, we need to determine if the matrix is invertible by calculating its determinant. If the determinant is non-zero, then the matrix has an inverse.

Given the matrix A = [9, -2; -10, 7], we can calculate its determinant as follows:

det(A) = (9 * 7) - (-2 * -10)

= 63 - 20

= 43

Since the determinant is non-zero (43 ≠ 0), we can proceed to find the inverse of matrix A.

The formula to calculate the inverse of a 2x2 matrix is:

A^(-1) = (1/det(A)) * [d, -b; -c, a]

Plugging in the values from matrix A and the determinant, we have:

A^(-1) = (1/43) * [7, 2; 10, 9]

Simplifying further, we get:

A^(-1) = [7/43, 2/43; 10/43, 9/43].

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The graph of y = 3 x 2^x passes through the coordinate points (2,12) and (3,24).

To write a question in the form of y=a x b^x that passes through the coordinate points (2,12) and (3,24), we need to solve for the values of a and b.

First, let's substitute the coordinates (2,12) into the equation:
12 = a x b^2

Next, let's substitute the coordinates (3,24) into the equation:
24 = a x b^3

We now have two equations with two unknowns (a and b), which we can solve using algebra.

From the first equation, we can solve for a:
a = 12 / b^2

We can then substitute this value of a into the second equation:
24 = (12 / b^2) x b^3

Simplifying this equation, we get:
2 = b

We can then substitute this value of b back into the equation for a:
a = 12 / 2^2
a = 3

Therefore, the equation of the graph that passes through the coordinate points (2,12) and (3,24) is:
y = 3 x 2^x

We can check that this equation is correct by plugging in the coordinates:
When x = 2: y = 3 x 2^2 = 12
When x = 3: y = 3 x 2^3 = 24
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Answer:

18cm

Step-by-step explanation:

The ratio is given by: 7.5/2.5=3

DE = 6 × 3 = 18 cm

or

DC/CB = x/AB

7.5/2.5 = x/6

3=x/6

x=6×3=18 cm

Answer:

Approximatly normal

Step-by-step explanation:

Answer:

approximately normal

Step-by-step explanation:

check conditions for constructing a confidence interval about a proportion:

- random sample or randomized experiment?

- 10 % when sampling without replacement, check n≤1/10N (40 students is enough to assume 10%)

- large count

all conditions are met so it is safe to assume distribution will be approximately normal