You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
A. The average speed you can use to pull the safe is 1.02 m/s
B. The time needed to pull the safe up is 17.65 s
A. How do i determine the velocity?First, we shall obtain the force. This is shown below:
Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?F = mg
F = 60 × 9.8
F = 588 N
Finally, we shall obtain the average speed. Details below:
Power = 600 WForce = 588 NAverage speed =?Power = force × average speed
600 = 588 × average speed
Divide both sides by 588
Average speed = 600 / 588
Average speed = 1.02 m/s
B. How do i determine the time?The time needed to pull the safe up can be obtained as follow:
Average speed = 1.02 m/sTotal distance = 18 mTime = ?Time = Total distance / average speed
Time = 18 / 1.02
Time = 17.65 s
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Complete question:
You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?
Part B
What is the time needed to pull the safe up?
Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with coefficient of kinetic friction uk 0.15. The block makes it up the incline to a second flat frictionless surface. What is the work done by friction? What is the velocity of the block at point C? The incline is 2.2m long at an angle 0=15
44.4 is the work done by friction 14.4 s the velocity of the block at point C . Correct Option a)
What is friction and example?Friction is the force that prevents solid surfaces, fluid layers, and material components from moving against each other. There are various kinds of friction.
Dry friction is the force that resists the relative lateral motion of two in touch solid surfaces. Dry friction is further classified as static friction ("stiction") between non-moving surfaces and kinetic friction ("stiction") between moving surfaces. Dry friction, with the exception of atomic or molecular friction, is caused by the interplay of surface characteristics known as asperities . Fluid friction explains the friction that occurs between sliding segments of a thick fluid.
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Full Question: In the figure below, a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with a coefficient of kinetic friction uk = 0.15. The block makes it up the incline to B a second flat frictionless surface. The incline is 22 m long at an angle = 15° What is the total work done in joules when the block goes from A to C and what is the speed of the block at point C in m/s? (fist value is work, second is speed) A) 44.4; 14.4 B) 44.4, -14.4 C) 14.4, 44.4 D) 44.4, 14.4 E) 44.4, 44.4
The driver of a train moving at 23m/s applies the breaks when it pases an amber signal. The next signal is 1km down the track and the train reaches it 76s later. The acceleration is -0.26s^2. Find its speed at the next signal.
Answer:
3.2 m/s
Explanation:
Given:
Δx = 1000 m
v₀ = 23 m/s
a = -0.26 m/s²
t = 76 s
Find: v
This problem is over-defined. We only need 3 pieces of information, and we're given 4. There are several equations we can use. For example:
v = at + v₀
v = (-0.26 m/s²) (76 s) + (23 m/s)
v = 3.2 m/s
Or:
Δx = ½ (v + v₀) t
(1000 m) = ½ (v + 23 m/s) (76 s)
v = 3.3 m/s
Or:
v² = v₀² + 2aΔx
v² = (23 m/s)² + 2(-0.26 m/s²)(1000 m)
v = 3.0 m/s
Or:
Δx = vt − ½ at²
(1000 m) = v (76 s) − ½ (-0.26 m/s²) (76 s)²
v = 3.3 m/s
As you can see, you get slightly different answers depending on which variables you use. Since 1000 m has 1 significant figure, compared to the other variables which have 2 significant figures, I recommend using the first equation.
A space probe is sent to an alien planet and conducts an experiment in order to determine the acceleration due to gravity on the planet. It produces the following table
Object Rock Grain of sand Metal bolt
Mass 20 grams 0.8 grams 79 grams
Recorded force of gravity :0.1224 N 0.00501 N 0.4871 N
Given this data, which of the following the closest approximation of the acceleration due to gravity on this planet
a
3.8 m/s^2
b
4.0 m/s^2
c
9.9 m/s^2
d
6.1 m/s^2
Answer: D. 6.1 m/s^2
Explanation:
What forms as a result of the wind's frictional force on water? Responses deep sea currents that move in a path opposite to the wind currents deep sea currents that move in a path opposite to the wind currents, surface currents that move in a path opposite to the wind currents surface currents that move in a path opposite to the wind currents surface currents that move in a path similar to the wind currents surface currents that move in a path similar to the wind currents deep sea currents that move in a path similar to the wind currents
The frictional force of the wind on water produces surface currents that travel in a pattern analogous to "wind currents".
Wind, temperature, water density, and the moon's gravitational pull may all affect ocean currents.
What results from the water's response to the frictional force of the wind?Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface. When wind constantly disturbs the surface of an ocean or lake, a wave crest is created.
Friction slows the wind, which also changes its direction. This phenomenon might lead to surface roughness variations along regional boundaries or turbulence in winds near the surface. Turbulence stirs the lower atmosphere.
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cual es la principal fuente de energia mas utilizada en un generador electrico
Answer:
Agua
Explanation:
Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
Describe the motion of an object experiencing blueshift
A source travelling in the direction of the observer causes Doppler blueshift.
When an object is moving towards us, the light from the object is known as blueshift.
The phrase refers to any relative motion, that causes a decrease in the wavelength and rise in frequency, including those that take place outside of the visible spectrum.
During the motion of the object towards us, blueshift will happen, thus shifting light to shorter wavelengths on the blue side of the spectrum.
This causes the color to shift from the red to the blue end of the spectrum in visible light.
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How are vibration waves and energy related to sounds
In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. ... In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
Answer:
because vibration waves are made by sound
8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page
The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.
The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.
When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.
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How much work is needed to transfer 767.1 kC of charge in one hour through a potential rise of 567.78 V ?
The change in potential energy ΔU of a system where a charge q moves through a potential difference ΔV is:
\(\Delta U=q\Delta V\)The work needed to move a charge q through a potential difference ΔV is the same as the change in potential energy of the system. Then, replace q=767.1kC and ΔV=567.78V to find the work needed to complete the described process:
\(\begin{gathered} \Delta U=q\Delta V \\ =(767.1kC)(567.78V) \\ =435,544kJ \end{gathered}\)Therefore, the amount of work needed to complete such a process is approximaely 435,544 kiloJoules.
PLEASE HELP ASAP! 100 PTS! 5 QUESTIONS - Pls Show Your Work!!!!
1. Two carts are pushed apart with a spring attached to one of the carts. The carts have masses of 1.2 kg and 2.5 kg. The 2.5 kg cart (Cart B) has a velocity of 1.5 m/s after they spring apart. Find the velocity of the 1.2 kg. cart.
2. An 6,000 kg train car moves at 20.0 m/s until it bumps into a stationary 6,000 kg car and latches onto it. What is the speed of the two cars linked together?
3. A single 1,000 kg train car moving at 5.0 m/s collides with the back of two 1,000 kg train cars linked together. It latches onto the car it strikes as the two parts of the coupled cars exert forces on each other. What is the speed of the cars immediately afterward?
4. A 15.0 kg cart and a 20 kg cart are locked together with a compressed spring between them. They are then released so that the spring pushes the two carts apart. The 20 kg cart is moving at 5.0 m/s afterward. How fast is the 15.0 kg cart moving?
5. A firecracker stuck into a 150 g apple explodes and sends five apple fragments in different directions. The vector sum of momenta 1, 2, 3, and 4 is found from a video of the event to have components px = 1.20 kg m/s, py = 0.80 kg m/s (with no other component). The mass of the fifth fragment is 0.050 kg. What is its velocity right after the explosion?
The final velocity of the 1.2 Kg cart is 3.1 m/s. The final velocity of the coupled mass of cars can be determined using the conservation of momentum. The final velocity is 10 m/s.
What is momentum ?Momentum of an object is the product of mass and velocity of the object. In a collision, the total momentum is conserved.
Here, initially the carts were rest. Hence, their initial momentum is zero.
then (1.2 kg × v) + (2.5 kg × 1.5 m/s) = 0
then , velocity of 1.2 kg = (2.5 × 1.5)/1.2 = 3.1 m/s.
Similarly the total initial momentum of the two car of mass 6000 kg is equal to the their final momentum.
The initial momentum of the stationary car is zero.
then (6000 kg × 20 m/s) + 0 = (6000 + 6000 kg)v.
The final velocity of the coupled mass v is then calculated as:
v = (6000 kg × 20 m/s)/12000 kg = 10 m/s.
Therefore, the final velocity of the coupled mass will be 10 m/s.
Using conservation of momentum concept all others can be found.
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what is the acceleration of a 10 kg mass pushed by a 5 N force
Answer:
The formula is a = F m so in this case a = 5 10 = 0.5 m s 2
Explanation:
A bicycle wheel is mounted on a fixed, frictionless axle, with a light string wound around its rim. The wheel has moment of inertia I=kmr2, where m is its mass, r is its radius, and k is a dimensionless constant between zero and one. The wheel is rotating counterclockwise with angular speed ω0_0, when at time t=0 someone starts pulling the string with a force of magnitude F. Assume that the string does not slip on the wheel.
The force F pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for this configuration.1. Find the magnitude of the angular velocity ω of the wheel when the string has been pulled a distance d.2. Express the angular velocity ω of the wheel in terms of the displacement d, the magnitude F of the applied force, and the moment of inertia of the wheel Iw.
Answer:
x3
Explanation:
trying to find the inetria magnitude of the wheel
This is the question I need help with
Answer:
Explanation:
If we ASSUME that a CCW torque is positive
τ = 10sin135[8.0] - 16sin90[4.0] + 19sin160[3.0] = 12 N•m
as the result is positive, the net torque is CCW.
6th grade measuring wavelengths!
PLEASE HELP!
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
What is frequency?The number of vibrations counted per second is called frequency. A wave is a group of vibrations that are referred to as energy. The bottom node is known as the crest, and the top node is known as the trough.
The frequency of an alternating current is the number of full cycles per second. The hertz, also known as Hz, is the accepted unit of frequency. The frequency of a current is 1 Hz if one cycle is completed per second; 60 cycles per second equals 60 Hz.
There are 8 waves so assume one wave is 1 cm so wavelength is 8 cm and frequency of wave = speed of light/ wavelength
frequency = \(3*10 ^{8} / .08\)
Frequency = 37.5 *\(10^{8}\) Hz
Wavelength of the given wave is 8 cm and frequency is 37.5 *\(10^{8}\) Hz.
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a ball of mass 100g moving at a velocity of 100m/s collides with another ball of mass 400g moving at 50m/s in same direction, if they stick together calculate the velocity and loss of energy
Answer:
Velocity of the two balls after collision: \(60\; \rm m \cdot s^{-1}\).
\(100\; \rm J\) of kinetic energy would be lost.
Explanation:
VelocityBecause the question asked about energy, convert all units to standard units to keep the calculation simple:
Mass of the first ball: \(100\; \rm g = 0.1\; \rm kg\).Mass of the second ball: \(400\; \rm g = 0.4 \; \rm kg\).The two balls stick to each other after the collision. In other words, this collision is a perfectly inelastic collision. Kinetic energy will not be conserved. The velocity of the two balls after the collision can only be found using the conservation of momentum.
Assume that the system of the two balls is isolated. Thus, the sum of the momentum of the two balls will stay the same before and after the collision.
The momentum of an object of mass \(m\) and velocity \(v\) is: \(p = m \cdot v\).
Momentum of the two balls before collision:
First ball: \(p = m \cdot v = 0.1\; \rm kg \times 100\; \rm m \cdot s^{-1} = 10\; \rm kg \cdot m \cdot s^{-1}\).Second ball: \(p = m \cdot v = 0.4\; \rm kg \times 50\; \rm m \cdot s^{-1} = 20\; \rm kg \cdot m \cdot s^{-1}\).Sum: \(10\; \rm kg \cdot m \cdot s^{-1} + 20 \; \rm kg \cdot m \cdot s^{-1} = 30 \; \rm kg \cdot m \cdot s^{-1}\) given that the two balls are moving in the same direction.Based on the assumptions, the sum of the momentum of the two balls after collision should also be \(30\; \rm kg \cdot m \cdot s^{-1}\). The mass of the two balls, combined, is \(0.1\; \rm kg + 0.4\; \rm kg = 0.5\; \rm kg\). Let the velocity of the two balls after the collision \(v\; \rm m \cdot s^{-1}\). (There's only one velocity because the collision had sticked the two balls to each other.)
Momentum after the collision from \(p = m \cdot v\): \((0.5\, v)\; \rm kg \cdot m \cdot s^{-1\).Momentum after the collision from the conservation of momentum: \(30\; \rm kg \cdot m \cdot s^{-1}\).These two values are supposed to describe the same quantity: the sum of the momentum of the two balls after the collision. They should be equal to each other. That gives the equation about \(v\):
\(0.5\, v = 30\).
\(v = 60\).
In other words, the velocity of the two balls right after the collision should be \(60\; \rm m \cdot s^{-1}\).
Kinetic EnergyThe kinetic energy of an object of mass \(m\) and velocity \(v\) is \(\displaystyle \frac{1}{2}\, m \cdot v^{2}\).
Kinetic energy before the collision:
First ball: \(\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.1\; \rm kg \times \left(100\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J\).Second ball: \(\displaystyle \frac{1}{2} \, m \cdot v^2 = \frac{1}{2}\times 0.4\; \rm kg \times \left(50\; \rm m \cdot s^{-1}\right)^{2} = 500\; \rm J\).Sum: \(500\; \rm J + 500\; \rm J = 1000\; \rm J\).The two balls stick to each other after the collision. Therefore, consider them as a single object when calculating the sum of their kinetic energies.
Mass of the two balls, combined: \(0.5\; \rm kg\).Velocity of the two balls right after the collision: \(60\; \rm m\cdot s^{-1}\).Sum of the kinetic energies of the two balls right after the collision:
\(\displaystyle \frac{1}{2} \, m \cdot v^{2} = \frac{1}{2}\times 0.5\; \rm kg \times \left(60\; \rm m \cdot s^{-1}\right)^2 = 900\; \rm J\).
Therefore, \(1000\; \rm J - 900\; \rm J = 100\; \rm J\) of kinetic energy would be lost during this collision.
Taigas, tundra and tropical rainforests share what common abiotic component?
Answer:
water
Explanation:
hope this helps
A yo-yo is released from a stationary hand and spins freely without slipping as the string unwinds. Simultaneously, the yo-yo moves downwards 0.70 m. The radius of the yo-yo is 0.008 m, the mass is 0.05 kg, and the rotational inertia is 3.5 * 10 -5kg*m 2 . a. Calculate the initial gravitational potential energy
The initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be calculated by multiplying the mass of an object with the square of its velocity. Kinetic energy is a form of energy that is associated with the movement of objects. It is released when objects collide or when objects are deformed. Kinetic energy can also be converted into other forms of energy, such as thermal energy, sound energy and electrical energy.
The initial gravitational potential energy of the yo-yo is equal to the change in height multiplied by the weight of the yo-yo. The weight of the yo-yo can be calculated using the equation W = m × g, where m is the mass and g is the acceleration due to gravity. Therefore, the initial gravitational potential energy of the yo-yo is equal to 0.05 kg ×9.8 m/s2 ×0.70 m = 0.343 Joules.
b. Calculate the initial rotational kinetic energy of the yo-yo.
The initial rotational kinetic energy of the yo-yo is equal to ½Iω2, where I is the rotational inertia and ω is the angular velocity. The angular velocity can be calculated using the equation ω = v/r, where v is the linear velocity and r is the radius of the yo-yo. Therefore, the initial rotational kinetic energy of the yo-yo is equal to ½ × 3.5 ×10-5 kg×m2 ×(0.70m/ 0.008m)2 = 0.000912 Joules.
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The half-life of cesium-137 is 30 years. Suppose that we start with 60 grams of cesium-137 in a storage pool.
How many half-lives will it take for there to be 10 grams of cesium-137 in the storage pool? (Round answer to two decimal places.)
How many years is that? (Round answer to one decimal place.)
9514 1404 393
Answer:
2.58 half-lives77.5 yearsExplanation:
The remaining amount, in terms of t half-lives, is ...
q(t) = 60·(1/2)^t
We want t when q(t) = 10, so ...
10 = 60·(1/2)^t
1/6 = (1/2)^t . . . . . . divide by 60
log(1/6) = t·log(1/2) . . . . take logs
t = log(1/6)/log(1/2) = -0.778151/-0.30103 ≈ 2.58496
It will take about 2.58 half-lives for there to be 10 grams remaining.
In years, that is 2.58×30 = 77.5 years.
programmable array logic (pal) has fixed or and programmable and array gates.group of answer choicestruefalse
Programmable Array Logic (PAL) has a programmable AND array and a fixed OR array.
Programmable Array Logic (PAL) is a logic device.
It is used to implement a logical function.It is an easy to use device because only AND gates are programmable, but it has a limited programming for AND gate.A PAL consists of a small programmable read-only memory (PROM) and additional output logic used to implement the specific logic function required with limited components.In PAL, a programmable AND gate is followed by a fixed OR gate.A typical PAL IC may have eight inputs, eight outputs, and eight sections, each consisting of eight wide AND-OR arrays.Hence PAL has programmable AND array and a fixed OR array.
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Which graph shows the change in velocity of an object in free fall?
Answer:
The graph of the velocity of an object in free fall would look like a straight line sloping downward. As the object falls, its velocity increases at a constant rate, so the graph of its velocity versus time will be a straight line with a negative slope. This is because acceleration due to gravity is a constant -9.8 meters per second squared, so the velocity of a free-falling object will increase by 9.8 meters per second every second.
Therefore, the graph that shows the change in velocity of an object in free fall is a straight line with a negative slope. Here is an example of such a graph:
Free Fall Velocity Graph
Which units are used to measure both velocity and speed? choose three options.
Explanation:
third and fifth option along with the first one are right
A mass is attached to the end of a spring and set into oscillation on a horizontal frictionless surface by releasing it from a stretched position. The position of the mass at any time is described by x = (8.8 cm)cos[2t/(4.18 s)]. Determine the following.
(a) period of the motion
(b) frequency of the oscillations
Hz
(c) first time the mass is at the position
x = 0
(d) first time the mass is at the site of maximum compression of the spring
A. The period of the motion is 4.18 s
B. The frequency of the oscillations
Hz is 0.2393 Hz
C. The first time the mass is at the position
x = 0 is 2.09 s
D. The first time the mass is at the site of maximum compression of the spring is 6.27s
How do we determine the values?a) The period of motion is given by the time it takes for the mass to complete one full oscillation. From the equation given, x = (8.8 cm)cos[2t/(4.18 s)], we can see that the function is in the form x = A cos(ωt + φ). The period of the motion T is given by the reciprocal of the angular frequency ω, which is T = 2π/ω.
In this case, the angular frequency is given by the coefficient of t in the argument of the cosine function, 2t/(4.18 s). So,
T = 2π/(2/(4.18 s)) = 4.18 s
b) The frequency of oscillations, f, is given by the reciprocal of the period, so
f = 1/T = 1/4.18 s^-1 = 0.2393 Hz
c) To find the first time the mass is at the position x = 0, we need to find the value of t when the cosine function is equal to 1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * 1 = 8.8cm
so,
cos[2t/(4.18 s)] = 1
t = (4.18 s)/2 = 2.09 s
d) To find the first time the mass is at the site of maximum compression of the spring, we need to find the value of t when the cosine function is equal to -1.
x = (8.8 cm)cos[2t/(4.18 s)] = 8.8cm * (-1) = -8.8cm
so,
cos[2t/(4.18 s)] = -1
t = (4.18 s) + (2.09 s) = 6.27s
It should be noted that the mass will be at the site of maximum compression at t = 6.27s and t = 2.09s + 4.18s = 6.27s + 4.18s = 10.45s and so on.
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A Motorcycle Jump. You are planning to make a jump with your motorcycle by driving over a ramp that will launch you at an angle of 30.0° with respect to the horizontal. The front edge of the ramp on which you are supposed to land, however, is 25.0 ft lower than the edge of the launch ramp (i.e., your launch height).
(a) Assuming a launch speed of 55.0 mph, at what horizontal distance from your launch point should the landing ramp be placed?
(b) In order to land smoothly, the angle of the landing ramp should match the direction of your velocity vector when you touch down. What should be the angle of the landing ramp?
a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.
(b) the angle of the landing ramp is 30°.
How do we calculate?(a)
Launch speed = 55.0 mph * (1.467 ft/s)
= 80.685 ft/s
Horizontal distance = Launch speed * Time of flight
Vertical velocity = Launch speed * sin(30.0°)
Time to reach maximum height = Vertical velocity / g
Vertical distance = (1/2) *g * t²
and Time = √(2 * Vertical distance / g)
Total time of flight = 2 * Time to reach maximum height + Time for descent
Horizontal distance = Launch speed * Total time of flight
The Vertical velocity = 80.685 ft/s * sin(30.0°)
= 40.3425 ft/s
Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²
Time to reach maximum height = 1.253 s
Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)
Time of descent = 0.913 s
Total time of flight = 2 * 1.253 s + 0.913 s
Total time of flight = 3.419 s
In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s
horizontal distance = 276.298 ft
b.
the angle of the landing ramp is 30.0 be the same as the launch angle.
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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A weightlifter curls a 25 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ .
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Energy burn by the weightlifter = potential energy
Potential energy = mgh
Potential energy = 25.(9.8)(0.50)
Potential energy = 122.5 Joule.
Assume 25% of efficiency so energy burn = 122.5*25/100
energy burn = 30.625 joule
Number of times = 1260/30.625
Number of times = 42 times.
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
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A beam of light, incident on a flat water surface, reflects from the mirror-like surface so that the angle of incidence equals the angle of reflection. The water has waves. Would individual light beams obey the law of reflection in this case?
Answer:
a protractor
Explanation:
because protractors measure angles
A constant voltage of 11.00 V has been observed over a certain time interval across a 1.20 H inductor. The current through the inductor, measured as 1.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 7.00 A at the end of the time interval. How long was this time interval
Answer:
0.65 sec
Explanation:
V = L*ΔI/Δt
so Δt = L*ΔI/V = 1.20 * (7.00 - 1.00)/11.00 = 0.65 sec