Given the equation 2co o2 --> 2co2, how many grams of co2 form if 34.0 grams of co are combined with excess oxygen?

Answer:

Solution:

Explanation:

V1   =   3.00m3

T1   =    150kPa

V2  =   1.20m3

T2  =     x

As ,

    V1    =    V2

     T1            T2

    3.00  =  1.20

      150        X

3.00 x X  =  150 x  1.20

3.00X  =   180

X   =  180

         3.00

X  =  60 kPa

The final pressure can be calculated using Boyle's law. The final pressure of the gas if the volume is increased from 3 m³ to 1.20 m³ with an initial pressure of 150 kPa is obtained as 375 kPa.

Boyle's law states that at constant temperature, the volume of a gas is inversely proportional to the pressure of the gas. Hence, volume decreases with increase in pressure and vice versa.

If P₁ and V₁ be the initial pressure and volume respectively and P₂, V₂ be their final quantities, then the relation between them can be written as:

P₁  V₁  =  P₂ V₂ .

It is given that the initial volume and pressure is  3 m³ and 150 kPa and the final volume is  1.20 m³ . Then, the final pressure is calculated as follows:

P₂ =  P₁  V₁ / V₂

   = (3 m³  ×  150 kPa) /  1.20 m³

   = 375 kPa

Hence, the final pressure of the gas will be 375 kPa.

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The spin quantum number has values of +1212 or -1212.

The spin quantum number is a property of the electron itself.

The electron is a subatomic particle with an electric charge of one elementary charge less than positive. It is represented by the symbol for. Given that they have no known components or substructure and are a member of the first generation of lepton particles, electrons are typically regarded as elementary particles. Approximately 1/1836th of a proton's mass is that of an electron. An intrinsic half-integer value angular momentum (spin) with units of the decreased Planck constant, is one of the electron's quantum mechanical properties. The Pauli exclusion principle states that since electrons are fermions, they can never share the same quantum state. Electrons, like all elementary particles, have the ability to interact with other particles and behave like waves when they are diffracted, similar to how light does.

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Answer:

Here’s the answer

Explanation:

Since 273 k – 243 k equals 30, the temperature change for an object going from 273 k to 243 k is 30 k.

Colors and temperatures can both be measured in Kelvin: A temperature unit commonly used in science is the Kelvin scale. Lord Kelvin created the scale after realizing the need for one with absolute zero as the zero point, which translates to 0 K as the lowest attainable temperature, or -273,15 °C.

On the Kelvin scale, a body's temperature cannot be negative. Since the Kelvin scale's absolute zero represents the lowest temperature that may exist, it is impossible for it to be negative.

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"The species that would be expected to have the highest concentration in the 0.1 M solution of H₂S is HS⁻ (option c)."

In a 0.1 M solution of hydrogen sulfide (H₂S), the species that would be expected to have the highest concentration depends on the dissociation equilibrium of H₂S. Hydrogen sulfide is a weak diprotic acid, meaning it can donate two protons (H⁺) in separate steps. The dissociation of H₂S can be represented as follows:

H₂S ⇌ H⁺ + HS⁻ (Equation 1)

HS⁻ ⇌ H⁺ + S²⁻ (Equation 2)

To determine which species will have the highest concentration, we need to examine the acid dissociation constants (Ka) for these equilibria.

From Equation 1, the equilibrium constant expression can be written as:

Ka1 = [H⁺][HS⁻] / [H₂S]

From Equation 2, the equilibrium constant expression can be written as:

Ka₂ = [H⁺][S²⁻] / [HS⁻]

In a dilute solution like 0.1 M, we assume that the dissociation of H₂S is incomplete, so we can make the approximation [H₂S] ≈ 0.1 M. Therefore, the concentration of H₂S is approximately constant.

Now, let's consider the pKa values for these equilibria. The pKa1 value for H₂S is approximately 7, and the pKa₂ value for HS⁻ is approximately 14.

Since pKa₁ is lower than pKa₂, it means that the equilibrium represented by Equation 1 is more favorable than the one represented by Equation 2. Thus, at equilibrium, the concentration of HS- will be higher than that of S2-.

Therefore, the species that would be expected to have the highest concentration in the 0.1 M solution of H₂S is HS⁻ (option c).

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Answer:

Kinetic energy is always 12mv2 , which in this case, is 3.2 J. Explanation: 12mv2=12(0.1 )(8.0)2=3.2J.

A  100. ml of sodium hydroxide solution with a pH of 13.00 can be converted to a sodium hydroxide solution with a pH of 12.00  by diluting the solution with distilled water to a total volume of 1.00 L . The correct answer is C.

  pH = -log[H⁺]

[H⁺] i s concentration of H⁺

to find the volume we should use the diluting method by comparing the concentration of initial solution to final solution

[H⁺] = 10^pH

pH 13,  [H⁺] = 10¹³

pH 12,  [H⁺] = 10¹²

so.

[H⁺]₁ V₁ =pH 13,  [H⁺]₂ V₂

10¹³ . 100 mL = 10¹² V₂

V₂ = 1000 mL = 1L

So 100. ml of sodium hydroxide solution with a ph of 13.00 can be converted to a sodium hydroxide solution with a pH of 12.0 by diluting the solution with distilled water to a total volume of 1.00 L

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Answer:

163 L CO₂

Explanation:

Step 1: Find conversion

1 mol = 22.4 L at STP

Step 2: Use Dimensional Analysis

\(7.29 \hspace{2} mol \hspace{2} CO_2(\frac{22.4 \hspace{2} L \hspace{2} CO_2}{1 \hspace{2} mol \hspace{2} CO_2} )\) = 163.296 L CO₂

Step 3: Simplify

We have 3 sig figs

163.296 L CO₂ ≈ 163 L CO₂

Answer:

wym??

Explanation:

To determine the new concentration of Fe3+ when 3.00 mL of 0.00200 M iron(III) nitrate is diluted to a total volume of 10.00 mL, we can use the concept of dilution.

First, we need to calculate the number of moles of Fe3+ in the initial 3.00 mL of 0.00200 M iron(III) nitrate. The number of moles can be calculated using the formula:

moles = concentration × volume

moles = 0.00200 M × 0.00300 L

moles = 0.000006 mol

Next, we determine the final volume of the solution, which is 10.00 mL.

Now we can use the dilution formula to find the final concentration:

C1V1 = C2V2

C1 = initial concentration

V1 = initial volume

C2 = final concentration

V2 = final volume

Rearranging the formula:

C2 = (C1V1) / V2

C2 = (0.00200 M × 0.00300 L) / 0.01000 L

C2 = 0.0006 M

Therefore, the new concentration of Fe3+ after dilution is 0.0006 M in a total volume of 10.00 mL.

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Answer:

A

Explanation:

The book encountered friction which turned some of the energy into heat.

Answer:

Membrane

Explanation:

Unlike a bacteria , an animal cell contains membrane which bounds organelles.

In the given reaction, the mole ratio of carbon monoxide reacting to the amount of carbon dioxide being produced is 1:3. So option D is correct.

The balanced chemical equation for the reaction is:

CO + Fe2O3 → 2 Fe + 3 CO2

To determine the mole ratio of carbon monoxide (CO) reacting to the amount of carbon dioxide (CO2) being produced, we compare the coefficients of CO and CO2 in the balanced equation.

From the equation, we see that the coefficient of CO is 1, while the coefficient of CO2 is 3. This means that for every 1 mole of carbon monoxide that reacts, 3 moles of carbon dioxide are produced.

Therefore, the mole ratio of CO to CO2 is 1:3.

This implies that for every 1 mole of CO that reacts, 3 moles of CO2 are formed. It is important to note that the mole ratio is determined from the coefficients in the balanced chemical equation and provides information about the stoichiometry of the reaction. So option D is correct.

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The mass percent of phenol in the solution is 26.01%.

To calculate the mass percent of phenol in the solution, we need to know the total mass of the solution and the mass of phenol in the solution.

The mass of phenol in the solution can be calculated as follows:

mass of phenol=volume of phenol x density of phenol

mass of phenol = 400.0 ml x 1.070 g/ml

mass of phenol = 428.0 g

The total mass of the solution can be calculated by adding the mass of phenol and the mass of water:

total mass of solution = mass of phenol + mass of water

total mass of solution = 428.0 g + (1217.9 ml x 1.000 g/ml)

total mass of solution = 1645.9 g

Now we can calculate the mass percent of phenol in the solution:

mass percent of phenol = (mass of phenol / total mass of solution) x 100%

mass percent of phenol = (428.0 g / 1645.9 g) x 100%

mass percent of phenol = 26.01%

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Answer:

positively charged nucleons are 24

Explanation:

Given element:

           ₂₄⁵⁰ Cr

The superscript before the symbol of the atoms is mass number

The subscript before the symbol is the atomic number

  Cr is the symbol of the atom

Now,

Atomic number is the number of protons in an atom.

The protons are the positively charged particles in an atom.

For this specie, the positively charged nucleons are 24

Answer:

Dark matter and dark energy raise some of the biggest questions in the study of space and physics. Lots of scientists are using observations and math to figure out what these are. This will help us understand more about our amazing universe, where there is always more to discover and more to learn.

Some of the most important concerns in the study of space and physics are raised by dark matter and dark energy. Many scientists are utilizing math and observations to determine what they are.

Dark matter is a part of the cosmos that can only be detected by its gravitational pull, not by its brightness. The universe's matter-energy ratio is made up of 30.1 percent dark matter, 69.4 percent dark energy, and "regular" visible matter (0.5 percent).

The existence of dark matter also referred to as the "missing mass," was first suggested by Swiss-American astronomer Fritz Zwicky, who found that the mass of all the stars in the Coma cluster of galaxies only made up about 1% of the mass required to prevent the galaxies from escaping the cluster's gravitational pull in 1933.

Until the 1970s, when American astronomers Vera Rubin and W. Kent Ford observed a similar phenomenon, the existence of this missing mass was unknown. At that time, the mass of the stars visible in a typical galaxy was only about 10% of the mass needed to keep those stars orbiting the galaxy's center.

Generally speaking, the rate at which stars circle the galactic nucleus is independent of how far away from the nucleus they are; in fact, orbital velocity either remains constant or slightly rises with distance instead of decreasing as would be predicted.

This requires a linear relationship between the mass of the galaxy inside the orbit of the stars and their separation from the galaxy's centre. However, this interior material emits no visible light, thus the term "dark matter."

Therefore, many scientists are utilizing math and observations to determine what they are.

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Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

Then attraction holds individual covalent molecules together as a solid are the force that hold the atom together if the each atom nucleus for the shared pair of electrons. the covalent compounds have very low melting point and boiling point.

The covalent bond form between the atoms by the sharing of electron. when there is no much difference in electronegativity of the atoms then the electrons are equally shared between two atoms. the mutual sharing of electrons formed covalent bond . the compound is called as covalent compound or molecules.  the molecules held by very weak intermolecular forces and it is very easy to break them . so, they have low melting point and boiling point.

Thus, Then attraction holds individual covalent molecules together as a solid are the force that hold the atom together if the each atom nucleus for the shared pair of electrons .the covalent compounds have very low melting point and boiling point.

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Answer:

i think it c

Explanation:

Answer:

Heat = 3138J

Explanation:

In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.

Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):

Q = C×m×ΔT

Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)

Replacing:

Q = 4.184J/molK×50g×15°C

Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).

Answer:

heat=3138j

Explanation:

In the system, the sample of Copper is releasing heat that produce the increasing in the temperature of water.

Using the equation of calorimeter, we can find the heat released for the sample of copper (The same that is absorbed for the water):

Q = C×m×ΔT

Where Q is heat, C is specific heat (For water: 4.184J/molK), m is the mass of water (50g) and ΔT is change in temperature of water (40°C-25°C = 15°C)

Replacing:

Q = 4.184J/molK×50g×15°C

Q = 3138J is the heat released for the sample of Copper (The same absorbed for the water).

Thermohaline circulation that occur in the ocean part that flows across sea surface help to supply heat to polar regions.

The thermohaline circulation refer to a section and region of the ocean circulation which is majorly driven by heat gradient and freshwater that flows across the sea surface and also from the mixture of heat and salt that occur at the inside part of the ocean.

Therefore, Thermohaline circulation help to supply heat to polar regions.

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Answer:

A.) aldehyde is the answer

From the given structural formula, the compound is ethanamide and thus, belongs to the group of amides. Thus, the correct option is B.

Amide is a functional group of organic compounds having an acyl group (R-C=O) linked to amine group (-NR¹R² where R¹ and R² are hydrogen atoms or alkyl groups). The amide functional group is given as -CON= (not double bond with N, but two distinct single bonds).

Amides can be classified into the following types depending on the moiety attached to nitrogen other than the carbonyl carbon:

1. Primary amides - amide in which the nitrogen atoms is attached to two hydrogen atoms

2. Secondary amides - in which the nitrogen atom is attached to one hydrogen and one alkyl group.

3. Tertiary amides - in which the nitrogen atom is attached to two alkyl groups.

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Answer:

Peroxide is a polyatomic ion consisting of two bonded oxygen atoms. This ion can form a compound with another atom,one of which is hydrogen Peroxide.

Typically two oxygen atoms make a neutral compound, which is oxygen gas. Peroxide can be written as 0-22

The frequency of a red laser that has a wavelength of 676 nm would be 4.43 x \(10^{14\) hertz.

The frequency and wavelength of a wave are related by the following equation:

λf = c

Where λ is the wavelength of the wave in meters, f is the frequency in Hertz, and c is the speed of light in a vacuum.

in this case, λ = 676 nm = 6.76 x \(10^{-7\) m

c = 299,792,458 m/s

Making f the subject of the formula:

f = c/λ

  = 299,792,458/6.76 x \(10^{-7\)

  = 4.43 x \(10^{14\) hertz

In other words, the frequency of a red laser that has a wavelength of 676 nm would be 4.43 x \(10^{14\) hertz.

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Explanation:    The relocation of organisms across geographical boundaries occurs naturally by various means. Since humans began exploring the globe, however, the rate of new species being introduced into regions has greatly increased. In some cases, humans have dispersed species on purpose; for instance, many plants were transported from Europe to North America for agricultural and ornamental purposes. Others were transported accidentally by ship, train, airplane - even on the shoes of hikers.

     Some species may be introduced and not be able to survive in their new habitat. Others may find optimal conditions for growing, reproducing, and adapting to the new environment, and their populations soar. For instance, lack of predators may contribute to their rapid population increases.

Addition of acid to an equilibrium solution of a slightly soluble ionic compound will increase the solubility of the compound if: the anion is a weak base.

According to the Bronsted-Lowry theory of acids and bases, an acid is defined as a proton donor while a base is defined as a proton acceptor. If a strong acid is added to a slightly soluble ionic compound, then it will break down into its constituent ions.

Therefore, if the anion is a weak base, it will be able to react with the acid, forming a conjugate acid that is more soluble than the original ionic compound. This will increase the solubility of the compound.

In summary, if the anion is a weak base, the addition of acid to an equilibrium solution of a slightly soluble ionic compound will increase the solubility of the compound.

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Answer:

Secure landfills Landfilling of hazardous solid or containerized waste is regulated more stringently than landfilling of municipal solid waste. Hazardous wastes must be deposited in so-called secure landfills, which provide at least 3 metres (10 feet) of separation between the bottom of the landfill and the underlying bedrock or groundwater table.

Explanation:

Answer: 1/64 grams of however much originally there is

Explanation:

each half life half of the material has decayed so 0.5*0.5*0.5*0.5*0.5*0.5=1/64

0.16g/L is the density of helium at 2.15 atm and -45 C. The substance's mass per cubic centimetre of volume is known as its density.

The substance's mass per cubic centimetre of volume is known as its density. Although the Latin letter D may also be used, the sign most frequently used for density is . Density is expressed mathematically as the mass divided by volume.

Where m represents the mass, V is the volume, and is the density. Density is sometimes roughly described as the amount of weight every unit volume (for example, in the oil and gas business in the United States).

P×V = n×R×T  

n = 2.15×1 /8.314×228

  =0.04mole

density =0.04×4

             =0.16g/L

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