EXPLANATION :
From the problem, triangles ADB and CDB are right triangles.
In a right triangle, the sine function is the opposite side divided by the hypotenuse.
Referring to the figure,
sin A = h/c and sin C = h/a which are both definitions of sine ratio.
So the reason is Definition of sine ratio
By multiplication property of equality, use cross multiplication to remove the denominators
That's
c sinA = h
and
a sin C = h
Equating both equations in h :
c sin A = a sin C by the reason of Substitution Property of Equality
Diving both sides by "ac"
\(\frac{c\sin A}{ac}=\frac{a\sin C}{ac}\)by the reason of Division Property of Equality
Then :
\(\frac{\sin A}{a}=\frac{\sin C}{c}\)Problem E4 Find the value of \( x \) if \( 3^{x} \log _{2} 4^{8}+\log _{11} 11^{3^{x}}=17 \)
The value of x is \(\log_{3}(\frac{-4\pm \sqrt{82}}{3})\) approximately equal to -1.1219 or 1.5219 (approx).
The given equation has two values of x, i.e., \(\log_{3}(\frac{-4+ \sqrt{82}}{3})\) and \(\log_{3}(\frac{-4- \sqrt{82}}{3})\).
Given: 3^{x} \log _{2} 4^{8}+\log _{11} 11^{3^{x}}=17
Since \log_{a}b^{c}=c\log_{a}b\implies3^{x} \log _{2} 4^{8}+\log _{11} 11^{3^{x}}
=17\implies 3^{x} (8\log _{2} 4)+3^{x}=17\implies 3^{x}(3^{x}+8)
=17
Now, we will find out all the possible values of x one by one as:3^{x}(3^{x}+8)=17\implies 3^{2x}+8*3^{x}-17=0\implies 3^{x}=\frac{-8\pm \sqrt{8^{2}-4*3*(-17)}}{2*3}\implies 3^{x}
=\frac{-8\pm \sqrt{328}}{6}\implies 3^{x}
=\frac{-8\pm 2\sqrt{82}}{6}\implies 3^{x}
=\frac{-4\pm \sqrt{82}}{3}\implies x
=\log_{3}(\frac{-4\pm \sqrt{82}}{3})
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according to the bureau of labor statistics, the average number of weeks an individual is unemployed is 26 weeks with a standard deviation of 9 weeks. suppose a random sample of 37 unemployed individuals is taken. find the probability that the sample average number of weeks unemployed is less than 23.5 weeks or greater than 25 weeks.
P( X≥23.5) = 0.5 + A(0.277)
The probability that a sample of size randomly selected value is greater mean greater than 23.5P( X≥23.5) = 0.5 + A(1.388)
Given that the mean of the Population = 26 weeks
The Standard deviation of the Population = 9 weeks
Let 'X' be a Normal distribution
Z = \(\frac{x-mean}{standard deviation}\)
Z = \(\frac{23.5-26}{9}\)
Z = -2.5/9
Z = -0.277
The probability that a single randomly selected value is greater than 23.5
P( X≥23.5) = P(Z≥-0.277)
P( X≥23.5) = 0.5 + A(-0.277)
P( X≥23.5) = 0.5 + A(0.277)
Let 'X' be a Normal distribution
Z = \(\frac{x-mean}{\frac{standard deviation}{\sqrt{n} } }\)
Z = \(\frac{23.5-26}{\frac{9}{\sqrt{25} } }\)
Z = -2.5/9/5
Z = -2.5/1.8
Z = -1.388
The probability that a sample of size randomly selected value is greater mean greater than 23.5
P( X≥23.5) = P(Z≥-1.388)
P( X≥23.5) = 0.5 + A(-1.388)
P( X≥23.5) = 0.5 + A(1.388)
Therefore,
The probability that a single randomly selected value is greater than 23.5P( X≥23.5) = 0.5 + A(0.277)
The probability that a sample of size randomly selected value is greater mean greater than 23.5P( X≥23.5) = 0.5 + A(1.388)
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A credit card starts new customers at a $2,000 limit when they are approved for a card. The company adds $500 annually to this limit for customers who pay their bill on time. Choose the equation below that gives the credit limit, Ln, of customers who have payed on time every year, and who are in their nth year of having the card. Then, use this equation to find the credit limit of a customer in their 10th year of having the card.
On solving the provided question we can say that As a result, the credit equation limit of a client who has paid on time every year for the past ten years is $7,000.
What is equation?A mathematical equation is a formula that links two statements and uses the equals sign (=) to indicate equality. In algebra, an equation is a statement that demonstrates the equality of two mathematical expressions. The equal sign divides the variables 3x + 5 and 14 in the equation 3x + 5 = 14, for instance.
The relationship between the two sentences that are located on opposite sides of a letter is explained by a mathematical formula. Frequently, the symbol and the single variable are identical. like in 2x - 4 = 2, for example.
The following equation determines the credit limit, Ln, of customers who have made on-time payments each year and are in the nth year of card ownership:
Ln = $2,000 + $500n
where Ln stands for the credit limit in the nth year and n is the number of years the cardholder has had it.
In the equation above, we substitute n=10 to get a customer's credit limit after ten years of card use:
L10 = $2,000 + $500(10)
L10 = $2,000 + $5,000
L10 = $7,000
As a result, a client with a ten-year history of on-time payments has a credit limit of $7,000.
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A line passes through the points (-3,4) and (-8,14). Find this line’s slope. If the slope does not exist, you may enter DNE or NONE.
Answer:
-2
Step-by-step explanation:
\(\boxed{ slope = \frac{y _{1} - y_2 }{x_1 - x_2} }\)
where (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate
Slope
\( = \frac{14 - 4}{ - 8 - ( - 3)} \)
\( = \frac{10}{ - 8 + 3} \)
\( = \frac{10}{ - 5} \)
= -2
A circle with circumference 20 has an arc with a 72º central angle.
What is the length of the arc?
Answer:
l = x · c / 360
l = 72 · 20 / 360
l = 1440 / 360
l = 4
Step-by-step explanation:
1. write down the arc length formula.
2. replace x and c by their values
3. multiply and then divide to get l
what percentage of $898.01billion is spent on $161.4billion
The percentage of $898.01 billion that is spent on $161.4 billion is equal to 17.97%.
What is a percentage?In Mathematics, a percentage simply refers to any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.
In order to determine the percentage, we would use the following mathematical expression:
Percentage = 161.4/898.01 × 100
Percentage = 0.1797 × 100
Percentage = 17.97%
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Abbey Road Motors pays a percent commission to its sales people. They are paid
a percent of the profit the dealership makes on a car. If the profit is under $1,000,
the commission rate is 20%. If the profit is at least $1,000 and less than or equal to
$2,000, the commission rate is 20% of the first $1,000 and 24% of the remainder of
the profit. If the profit is above $2,000, the rate is 20% of the first $1,000 of profit,
24% of the next $1,000 of profit, and 29% of the amount of profit over $2,000. If p
represents the profit, express the commission c(p) algebraically as a split function.
Answer:
c(p) = {0.2 p ⇒ p < 1000
0.24 p - 40 ⇒ 1000 ≤ p ≤ 2000
0.29 p - 140 ⇒ p > 2000}
Step-by-step explanation:
* Lets explain how to solve the problem
- The profit is represented by p
1. If the profit is under $1,000, the commission rate is 20%
∵ The profit is p < 1000
∵ 20% of p = = 0.2 p
∵ c(p) is the function of the commission
∴ c(p) = 0.2 p when p < 1000
2. If the profit is at least $1,000 and less than or equal to $2,000, the
commission rate is 20% of the first $1,000 and 24% of the remainder
of the profit
- At least means greater than or equal
∵ The profit 1000 ≤ p ≤ 2000
- The commission is divided into 20% of first $1000 and 24% of
the reminder
∵ 20% of 1000 = = 200
∵ The remainder of the profit = p - 1000
∵ 24% of the remainder profit =
= 0.24(p - 1000) = 0.24 p - 240
∴ The total commission = 200 + 0.24 p - 240
∴ The total commission = 0.24 p - 40
∴ c(p) = 0.24 p - 40 when 1000 ≤ p ≤ 2000
3. If the profit is above $2,000, the rate is 20% of the first $1,000
of profit, 24% of the next $1,000 of profit, and 29% of the amount
of profit over $2,000
∵ The profit p > 2000
- The commission is divided into 20% of first $1000 and 24% of the
next $1,000 of profit, and 29% of the amount of profit over $2,000
∵ 20% of 1000 = = 200
∵ 24% of 1000 = = 240
- The amount of profit over $2,000 = p - 2000
∵ 29% of the amount of profit over $2,000 =
= 0.29(p - 2000)
= 0.29 p - 580
∴ The total commission = 200 + 240 + 0.29 p - 580
∴ The total commission = 0.29 p - 140
∴ c(p) = 0.29 p - 140 when p > 2000
* The commission function is:
c(p) = {0.2 p ⇒ p < 1000
0.24 p - 40 ⇒ 1000 ≤ p ≤ 2000
0.29 p - 140 ⇒ p > 2000}* Lets explain how to solve the problem
- The profit is represented by p
1. If the profit is under $1,000, the commission rate is 20%
∵ The profit is p < 1000
∵ 20% of p = = 0.2 p
∵ c(p) is the function of the commission
∴ c(p) = 0.2 p when p < 1000
2. If the profit is at least $1,000 and less than or equal to $2,000, the
commission rate is 20% of the first $1,000 and 24% of the remainder
of the profit
- At least means greater than or equal
∵ The profit 1000 ≤ p ≤ 2000
- The commission is divided into 20% of first $1000 and 24% of
the reminder
∵ 20% of 1000 = = 200
∵ The remainder of the profit = p - 1000
∵ 24% of the remainder profit =
= 0.24(p - 1000) = 0.24 p - 240
∴ The total commission = 200 + 0.24 p - 240
∴ The total commission = 0.24 p - 40
∴ c(p) = 0.24 p - 40 when 1000 ≤ p ≤ 2000
3. If the profit is above $2,000, the rate is 20% of the first $1,000
of profit, 24% of the next $1,000 of profit, and 29% of the amount
of profit over $2,000
∵ The profit p > 2000
- The commission is divided into 20% of first $1000 and 24% of the
next $1,000 of profit, and 29% of the amount of profit over $2,000
∵ 20% of 1000 = = 200
∵ 24% of 1000 = = 240
- The amount of profit over $2,000 = p - 2000
∵ 29% of the amount of profit over $2,000 =
= 0.29(p - 2000)
= 0.29 p - 580
∴ The total commission = 200 + 240 + 0.29 p - 580
∴ The total commission = 0.29 p - 140
∴ c(p) = 0.29 p - 140 when p > 2000
* The commission function is:
c(p) = {0.2 p ⇒ p < 1000
0.24 p - 40 ⇒ 1000 ≤ p ≤ 2000
0.29 p - 140 ⇒ p > 2000}
what is a type ii error? rejecting a false null hypothesis accepting a false alternate hypothesis rejecting a false alternate hypothesis failing to reject a false null hypothesis
A type II error is a statistical term used to describe the failure to reject a false null hypothesis. It occurs when the null hypothesis is actually false but is not rejected because the statistical test failed to find significant evidence against it.
In other words, it happens when an alternative hypothesis is true, but we fail to reject the null hypothesis.
Types of errors in hypothesis testing
There are two types of errors in hypothesis testing:
Type I error: Rejecting a true null hypothesis
Type II error: Failing to reject a false null hypothesis.Type I error occurs when a true null hypothesis is rejected while Type II error occurs when a false null hypothesis is not rejected. These types of errors are inversely related, meaning that a decrease in one type of error causes an increase in the other.
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Which algebraic expression represents "the product of a number and eight"? 8 + n 8n n – 8 StartFraction n Over 8 EndFraction
Answer: 8n
Step-by-step explanation:
Suppose the number is 'n'
Its product with number eight is given by
\(\Rightarrow n\times 8=8n\)
Answer:
8n
Step-by-step explanation:
edguenity 2020-2021
Please help on this
Answer:
5.025m
Step-by-step explanation:
The clothesline also creates an upside-down triangle with two sides being 5m, 0.5m, and the hypotenuse being the clothesline.
We can use the pythagorean theorem to find the length of the clothesline.
5 squared +.5 squared= the length of the clothesline squared
25+.25= the square root of 25.25
= 5.025
Answer:
Your answer would be:
5.025m
Step-by-step explanation:
5 sq + 0.5sq = the length of the clothesline sq
25 + 0.25= the square root of 25.25
= 5.025m
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anyone know how to do this ?
Answer:
yes
Step-by-step explanation:
1) Explain the problem of unit root in standard regression and in time-series models and Explain how to use the Dickey-Fuller and augmented Dickey-Fuller tests to detect this. In clearly and detailed . Kindly type your answers . Course Econometrics
The problem of unit root in standard regression and time-series models arises when a variable exhibits a non-stationary behavior, meaning it has a trend or follows a random walk. Unit root tests, such as the Dickey-Fuller and augmented Dickey-Fuller tests, are used to detect the presence of a unit root in a time series. These tests examine whether the coefficient on the lagged value of the variable is significantly different from one, indicating the presence of a unit root.
In standard regression analysis, it is typically assumed that the variables are stationary, meaning they have a constant mean and variance over time. However, many economic and financial variables exhibit non-stationary behavior, where their values are not centered around a fixed mean but instead follow a trend or random walk. This presents a problem because standard regression techniques may produce unreliable results when applied to non-stationary variables.
Time-series models, such as autoregressive integrated moving average (ARIMA) models, are specifically designed to handle non-stationary data. They incorporate differencing techniques to transform the data into a stationary form, allowing for reliable estimation and inference. Differencing involves computing the difference between consecutive observations to remove the trend or random walk component.
The Dickey-Fuller test and augmented Dickey-Fuller test are commonly used to detect the presence of a unit root in a time series. These tests examine the coefficient on the lagged value of the variable in a regression framework. The null hypothesis of the tests is that the variable has a unit root, indicating non-stationarity, while the alternative hypothesis is that the variable is stationary.
The Dickey-Fuller test is a simple version of the test that includes only a single lagged difference of the variable in the regression. The augmented Dickey-Fuller test extends this by including multiple lagged differences to account for potential serial correlation in the data. Both tests provide critical values that can be compared to the test statistic to determine whether the null hypothesis of a unit root can be rejected.
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Is a rational number? Why or why not?
\( \sqrt{7} \)
Answer:
No, it is a irrational number
Step-by-step explanation:
Answer: Irrational or not rational
Step-by-step explanation:
square root of 7 is 2.64575131
Rational numbers are numbers that can be expressed in fractions.
Square root of 7 can't be made by dividing 2 integers.
Can you please help me
The vertices of ΔFGH are F(-2,4), G(4,4), and H(1,-2), then the coordinates of the orthocenter of ΔFGH are ( 1 , 5/2 ) or ( 1 , \(2\frac{1}{2}\) ).
Graph ΔFGH . To find the orthocenter, find the point where two of the three altitudes intersect.
Find an equation of the altitude from F to GH.
The slope of GH is,
= 4-(-2)/4-1
= 4+2/4-1
= 6/3
= 2
So the slope of the altitude, which is perpendicular to GH, is -1/2
y - \(y_{1}\) = m (x - \(x_{1}\))
y - 4 = -1/2 ( x - (-2) )
y - 4 = -1/2 (x+2)
y - 4 = -1/2x - 1
y = -1/2x -1 + 4
Find an equation of the altitude from F to GH.
The slope of FH is,
= -2-4/1-(-2)
= -6/1+2
= -6/3
= -2
So the slop of the altitude is, 1/2
y - \(y_{1}\) = m (x - \(x_{1}\))
y - 4 = 1/2 ( x - 4 )
y - 4 = 1/2x - 2
y = 1/2x -2 + 4
y = 1/2x + 2
Solve the resulting system of equations \(\left \{ {{y = -1/2x + 3} \atop {y = 1/2x + 2 }} \right.\) to find the point of intersection of the altitudes.
Adding the two equations to eliminate \(x\) results in 2y = 5 or y = 5/2
y = 1/2x + 2
5/2 = 1/2x + 2
1/2 = 1/2x
x = 1
Therefore,
The coordinates of the orthocenter of ΔFGH are ( 1 , 5/2 ) or ( 1 , \(2\frac{1}{2}\) ).
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Ashley has baked 17 cakes for a bake sale. She can bake 2 cakes with each additional stick of butter
she buys. How many additional sticks of butter does she need in order to make 41 cakes?
WRITE THE EQUATION THEN SOLVE PLEASEEEE. THANK YOU SO MUCH
Answer:
12 additional sticks of butter
Step-by-step explanation:
First, create an equation. Let y represent the number of additional sticks of butter needed, and let x represent the number of cakes made.
y = \(\frac{x}{2}\) will be the equation.
Since she has already baked 17 cakes, she will need to bake 24 more cakes to make 41 cakes.
Plug in 24 as x into the equation, and solve for y:
y = \(\frac{x}{2}\)
y = \(\frac{24}{2}\)
y = 12
So, she will need 12 additional sticks of butter
4х – Зу = 15
x - 2y = 0 solve using substitution please show work
Answer:
(6,3)
Step-by-step explanation:
I'm going to start with the second one.
x - 2y = 0
+2y +2y
x = 0 + 2y which is the same as (x = 2y)
Now plug that in for the x-value in the other equation.
4(2y) - 3y = 15
8y - 3y = 15
5y = 15
Divide both sides by 5
y = 3
Here is where you are going to plug it back into the first one we did.
x - 2(3) = 0
x - 6 = 0
+6 +6
x = 6
So the answer is (6,3)
Hope that helps and have a great day!
what is greater 23/20 or 110%
Answer:
23/20
Step-by-step explanation:
110% of 20 is 22/20, so 23/20 is more.
Step-by-step explanation:
23/20 = 1,15
110% = 1,1
1,15 > 1,1
⇒ 23/20 > 110%
BC←→ is tangent to circle A at point B . DC=16 and BC=24 . Find the length of AB¯¯¯¯¯¯¯¯ and AC¯¯¯¯¯¯¯¯ .
Answer:
Step-by-step explanation:
5
Transform the equation to isolate x: ax = bx + 1. How is the value of x related to the difference of a and b?
(please help me)
Answer:
x = 1/a-b.
x is the reciprocal of the difference of a and b.
x is 1 over the difference of a and b.
x is the quotient of 1 and the difference of a and b.
Step-by-step explanation:
i did it
The transformation of the given equation ax = bx + 1 for the x will be 1/(a - b).
What is the substitution of an equation?In the by substitution method, one of the equations is calculated for one of the variables, which is then transferred back into the other equation where the chosen variable is a replacement, and the second equation is then calculated for. The first variable is then home safely.
In other words, substitution is a method to find the value of variables x and y by just substituting x and y to another equation.
The substitution method is more good than the elimination method.
Given that the equation
ax = bx + 1
Transfer bx to the left side
ax- bx = 1
Take common x from the left-hand side
x(a - b) = 1
Divide a - b on both sides
x = 1/(a - b) hence it will be the correct transformation.
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Triangle ABC is dilated with the origin as the center of the dilation. Which ordered pair could represent the image of point C (5,2) after the dilation
The ordered pair that could be the image point is (a) (2.5,1)
How to determine the ordered pair that could be the image pointFrom the question, we have the following parameters that can be used in our computation:
Point C = (5, 2)
This means that
C = (5, 2)
The point is dilated using the origin as a center of the origin
So, the image point is
C = k(5, 2)
Let k = 1/2
So, we have
C = 1/2(5, 2)
Evaluate
C' = (2.5, 1)
Hence, the ordered pair that could be the image point is (a) (2.5,1)
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Question
Triangle ABC is dilated with the origin as the center of the dilation. Which ordered pair could represent the image of point C(5, 2) after the dilation?
A (2.5,1)
B (5,−2)
C (7.5,4.5)
D (−1,−4)
What is the binomial factor of x³ 125?
x³-125= (x−5)(x^2+5x+25)
Hence, it has 1 real root and 2 imaginary roots.
What is binomial factor?Factors in polynomial equations with exactly two terms are called binomial factors. Because binomials are simple to solve and their roots are the same as the polynomial's roots, binomial factors are fascinating. Finding a polynomial's roots begins with factoring it.
Note that (x3 + a3 )may typically be factored as ( x -a ) ( x^2 + an x + a 2).
Similarly,
x^3-125
=( x^3-5^3 )
=( x−5) ( x^2 + 5 x + 25 ).
x³-125= (x−5)(x^2+5x+25).
Hence by solving this we get one real root as 5 and other two roots are imaginary.
We can get the roots by using discriminant formula.
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question 3 in the analyze stage of the data life cycle, what might a data analyst do? select all that apply.
In the analyze stage of the data life cycle, the data analyst will use the spreadsheet to aggregate the data and use the formulas to perform the calculations
The data life cycle is defined as the time period that that data exist in you system. Usually the data management experts finds the six or more stages in the data life cycle
The data analyst is the person who use the interpreted data and analyze the data in order to solve the problems
The analyze stage is the one of the main stages of the data life cycle. In the stage data analyst will use the spreadsheet to aggregate the data in the system and use the formulas to perform the calculations in the system
Therefore, the data analyst will use the spreadsheet to aggregate the data and use the formulas to perform the calculations
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Willl
Give
Brainlist
Answer
:))
Answer:
\(x=54^{o}\)
Step-by-step explanation:
Angles of straight line: 126 and x = 180
\(x+126=180\)
\(x=180-126\)
\(x=54^{o}\)
{CHECK: \(54+126=180\)}
hope this helps.....
cupcake delight shop made 4 1/2 as much revenue on doughnuts as muffins. if total sales were 44,000 what dollar amount of each was sold?
The revenue from muffins was $8,000. To find the revenue from doughnuts: 4.5x = 4.5 * 8,000 = $36,000 Therefore, the cupcake delight shop sold $8,000 worth of muffins and $36,000 worth of doughnuts.
Let's use the given terms and set up a system of equations to solve this problem:
Let x be the revenue from muffins, and y be the revenue from doughnuts. We know the following:
1. y = 4.5x (Cupcake Delight Shop made 4 1/2 times as much revenue on doughnuts as muffins)
2. x + y = 44,000 (Total sales were $44,000)
Now we'll solve the system of equations step-by-step:
Step 1: Replace y with 4.5x in the second equation (using equation 1):
x + 4.5x = 44,000
Step 2: Combine the x terms:
5.5x = 44,000
Step 3: Divide both sides by 5.5 to solve for x:
x = 8,000
Step 4: Plug x back into equation 1 to find y:
y = 4.5 * 8,000
y = 36,000
So, Cupcake Delight Shop sold $8,000 worth of muffins and $36,000 worth of doughnuts.
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The dollar amount of muffins sold is $8,000, and the dollar amount of doughnuts sold is $36,000.
To solve this problem, let's assign variables to the revenue for doughnuts and muffins:
Let D = revenue from doughnuts
Let M = revenue from muffins
We are given that the shop made 4 1/2 times as much revenue on doughnuts as muffins:
D = 4.5M
We are also given that the total sales were $44,000:
D + M = 44,000
Now, we can solve for the dollar amount of each item sold:
Replace D with 4.5M in the second equation:
4.5M + M = 44,000
Combine like terms:
5.5M = 44,000
Divide by 5.5 to isolate M:
M = 44,000 / 5.5
M = 8,000
Plug the value of M back into the first equation to find the value of D:
D = 4.5M
D = 4.5 × 8,000
D = 36,000.
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SOLVE THE PROBLEM, PLEASE! :(
Answer:
First Blank: 5
Second Blank: 5
Third Blank: -1
Fourth Blank: -1
Fifth Blank: 3
Step-by-step explanation:
10x+15y=15
-10x+2y=-32
__________
17y=-17
__ ___
17 17
y=-1
2x+3(-1)=3
2x-3=3
+3 +3
________
2x=6
__ __
2 2
x=3
what is the range and domain of this question? im unsure
Answer:
Step-by-step explanation:
Domain is the independent variable (x)
Range is the dependent variable (y)
For each of these you would just put what x and y are equal to
For the Domain you would put:
0<=x<=3
<= is less than or equal to
For the Range you would put
1<=y<=4
The line is a function
using the definitional proof, show that xlogx is o(x2) but that x2is not o(xlog(x)).
To prove that xlogx is o(x^2), we need to show that there exists a positive constant c and a positive integer N such that for all x greater than N, we have:
|xlogx| ≤ cx^2
Let's start by rewriting xlogx as:
xlogx = xlnx
Now we can use integration by parts to find the antiderivative of xlnx:
∫xlnxdx = x^2/2 * ln(x) - x^2/4 + C
where C is the constant of integration. Since ln(x) grows slower than any positive power of x, we can see that xlogx is O(x^2).
To prove that x^2 is not o(xlog(x)), we need to show that for any positive constant c, there does not exist a positive integer N such that for all x greater than N, we have:
|x^2| ≤ c|xlogx|
Assume that such a constant c and integer N exist. Then, we have:
|x^2| ≤ c|xlogx|
Dividing both sides by |xlogx| (which is positive for x > 1), we get:
|x|/|logx| ≤ c
As x approaches infinity, the left-hand side of this inequality approaches infinity, while the right-hand side remains constant.
Therefore, the inequality cannot hold for large enough x, and we have shown that x^2 is not o(xlog(x)).
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please help need done before 2
Answer:
130.25ft
Step-by-step explanation:
a^2+b^2=c^2
5.5^2+10^2=
30.25+100=
construct the discrete probability distribution for the random variable described. express the probabilities as simplified fractions. the number of tails in 44 tosses of a coin.
The probability of getting a tail on any given toss is 1/2.
The random variable X represents the number of tails in 44 tosses of a coin. Since there are two possible outcomes (heads and tails) for each toss, the probability of getting a tail on any given toss is 1/2.
We can use the binomial distribution formula to calculate the probability of getting a specific number of tails in 44 tosses. The formula is:
P(X = k) = (44 choose k) * (1/2)^44
where "k" represents the number of tails we want to calculate the probability for, and "44 choose k" represents the number of ways we can get k tails in 44 tosses.
Using this formula, we can calculate the probability of getting 0, 1, 2, ..., 44 tails, and we get the following probability distribution:
X = 0: P(X = 0) = (44 choose 0) * (1/2)^44 = 1/17592186044416
X = 1: P(X = 1) = (44 choose 1) * (1/2)^44 = 44/17592186044416
X = 2: P(X = 2) = (44 choose 2) * (1/2)^44 = 946/17592186044416
...
X = 42: P(X = 42) = (44 choose 42) * (1/2)^44 = 946/17592186044416
X = 43: P(X = 43) = (44 choose 43) * (1/2)^44 = 44/17592186044416
X = 44: P(X = 44) = (44 choose 44) * (1/2)^44 = 1/17592186044416
Note that the sum of all these probabilities is 1, which means that one of these outcomes must occur. Also, we can see that the distribution is symmetric around the mean (22 tails) since the probability of getting k tails is the same as the probability of getting 44-k tails.
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Jack is standing on the ground talking on his mobile phone. He notices a plane flying at an altitude of
2400 metres. If the angle of elevation to the plane is 70° and by the end of his phone call it has an angle
of elevation of 50°, determine the distance the plane has flown during Jack’s phone call - use the cosine rule
Using the cosine rule, the distance the plane has flown during Jack's phone call can be calculated by taking the square root of the sum of the squares of the initial and final distances, minus twice their product, multiplied by the cosine of the angle difference.
To determine the distance the plane has flown during Jack's phone call, we can use the cosine rule in trigonometry.
The cosine rule relates the lengths of the sides of a triangle to the cosine of one of its angles.
Let's denote the initial distance from Jack to the plane as d1 and the final distance as d2.
We know that the altitude of the plane remains constant at 2400 meters.
According to the cosine rule:
\(d^2 = a^2 + b^2 - 2ab \times cos(C)\)
Where d is the side opposite to the angle C, and a and b are the other two sides of the triangle.
For the initial angle of elevation (70°), we have the equation:
\(d1^2 = (2400)^2 + a^2 - 2 \times 2400 \times a \timescos(70)\)
Similarly, for the final angle of elevation (50°), we have:
\(d2^2 = (2400)^2 + a^2 - 2 \times 2400 \times a \times cos(50)\)
To find the distance the plane has flown, we subtract the two equations:
\(d2^2 - d1^2 = 2 \times 2400 \times a \times (cos(70) - cos(50))\)
Now we can solve this equation to find the value of a, which represents the distance the plane has flown.
Finally, we calculate the square root of \(a^2\) to find the distance in meters.
It's important to note that the angle of elevation assumes a straight-line path for the plane's movement and does not account for any changes in altitude or course adjustments that might occur during the phone call.
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