given a 100-1000ul pipette, what is the lowest volume that you would feel comfortable pipetting? why?

answer:

Explanation:

the impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it. The impulse-momentum theorem is logically equivalent to Newton's second law of motion (the force law).

According to the impulse-momentum theorem, the amount of change in an object's momentum equal to the amount of force applied to the object over a certain amount of time. So, option B.

According to the impulse-momentum theorem, the impulse that is applied to an item is equal to the change in momentum.

It shows how an object's change in momentum depends on both the strength and duration of the applied forces.

Impulse is defined as the force acting for a short interval of time.

Impulse = F x t

The momentum of the object,

P = mv

So, the rate of change of momentum,

dP/dt = d(mv)/dt

dP/dt = mdv/t

dP/dt = ma = Force

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An activity that is relatively short in time (< 10 seconds) and has few repetitions predominately uses the Phosphagen energy system. The Phosphagen energy system is also known as the ATP-CP (adenosine triphosphate and creatine phosphate) system.

It is said that energy is produced through three systems in our body, i.e., ATP-CP system, lactic acid system, and aerobic system. The ATP-CP system is the first system, and it provides the quickest energy and is of the shortest duration. When an activity that is relatively short in time and has few repetitions, predominately uses the Phosphagen energy system, it gets its energy from the ATP-CP system.

When we perform an intense physical activity like a short sprint or jumping, it's all about the ATP-CP system. The ATP-CP system produces energy rapidly through the use of stored ATP (adenosine triphosphate) and CP (creatine phosphate).ATP (adenosine triphosphate) is the source of energy for muscle contractions. It is produced through the breakdown of foods we eat and stored in our muscle tissues. However, the ATP reserves are limited and only provide energy for about 3-5 seconds of intense activity.

CP (creatine phosphate), on the other hand, is a high-energy molecule stored in our muscles. It helps to quickly regenerate ATP when the muscles require energy, which allows the muscles to work longer. However, CP stores are also limited and provide energy for only 8-10 seconds of intense activity.

The Phosphagen energy system is used when the body performs an intense physical activity that lasts for a short duration and has few repetitions, like sprinting or jumping. The ATP-CP system is the first system that provides the quickest energy and is of the shortest duration.

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(a) Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶; (b) Trajectory is a straight line; (c) Radius = r = 3GM = 3 × Gravitational Constant × Mass of Sun, that is  3.762 × 10²⁰ m³s⁻² kg.

(a) We need to find the numerical value of the ratio 3GM/rc² at the surface of the sun. Substitute the given values into the equation. The mass of the sun (M) is 2.0 × 10³⁰ kg. Radius (r) is 7 × 10⁵ km.

Convert the radius from kilometers to meters,

r = 7 × 10⁵ km = 7 × 10⁸⁸ m

Calculating the ratio.

Ratio = (3GM)/(rc²)

\(= \frac{3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\= \frac{(6.67(10^{-11}))3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\\\\)

= (13.34 × 10¹⁹)/(63 × 10²⁴)

≈ 2.12 × 10⁻⁶

Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶.

(b) We neglect the right-hand side of the equation. That means the differential equation.

d'u = 0

Integrating both sides.

du = 0

Integrating again.

u = constant

This means that the trajectory is a straight line.

(c) We have to find the radius at which the trajectory of light forms a circular orbit around a black hole.

3GMu - u² = 0

3GMu = u²

Dividing both sides by u (assuming u ≠ 0).

3GM = u

Substituting u = 1/r.

3GM = 1/r

Rearranging the equation,

r = 3GM

3GM = 3 * (mass of the sun) * (gravitational constant)

Assuming the mass of the sun (M) is approximately 1.989 × 10³⁰ kg, we can compute,

3GM = 3 * (1.989 × 10³⁰ kg) * (6.67430 × 10⁻¹¹ m^3 kg⁻¹ s⁻²)

3GM ≈ 3.762 × 10²⁰ m³s⁻² kg

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The region marked X in the diagram shows that the objects have the same charge.

The term conduction has to do with the manner of charging in which charge is passed from one object to another. Induction involves charging objects without the objects touching each other.

The region marked X in the diagram shows that the objects have the same charge.

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Answer:

D

Explanation:

Answer:8.1g

Explanation:

Explanation:

you can find by using. volume = mass/ density of aluminium.

To find the value of V, we can use the equations of motion.

First, let's consider the acceleration phase. The particle starts from rest, so its initial velocity (u) is 0 m/s, and the acceleration (a) is 3 m/s². We want to find the velocity at the end of this phase, which we'll call V1.

Using the equation v = u + at, we can substitute the values:

V1 = 0 + (3 m/s²) * t1

V1 = 3t1

Next, during the constant speed phase, the velocity remains constant at V1 for a time T. The distance traveled during this phase is equal to the product of the velocity and time:

Distance1 = V1 * T

Finally, during the deceleration phase, the particle comes to rest with a deceleration (a') of -1.5 m/s². We want to find the time taken during this phase, which we'll call t2.

Using the equation v = u + at, where the final velocity (v) is 0, we can substitute the values:

0 = V1 + (-1.5 m/s²) * t2

t2 = V1 / 1.5

The total time for the motion is given as 1 minute, which is equal to 60 seconds. So we have:

t1 + T + t2 = 60 seconds

Now we can solve these equations simultaneously to find the value of V1 and subsequently V.

Substituting the expression for t2 in terms of V1 into the equation for total time:

t1 + T + V1 / 1.5 = 60

Rearranging, we get:

t1 + T = 60 - V1 / 1.5

Now, we can substitute the expression for Distance1 in terms of V1 and T into the above equation:

t1 + Distance1 / V1 = 60 - V1 / 1.5

Substituting Distance1 = V1 * T:

t1 + V1 * T / V1 = 60 - V1 / 1.5

Simplifying:

t1 + T = 60 - V1 / 1.5

Now, we can solve this equation to find the value of V1 and subsequently V.

Note: Since the given values for T and the total distance traveled are not provided, it is not possible to calculate the exact value of V without those values.

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Answer:

Approximately \(7.2\; {\rm m\cdot s^{-1}}\) (rounded up), assuming that this circle is vertical and \(g = 9.81\; {\rm m\cdot s^{-2}}\).

Explanation:

Let \(v\) denote the tangential speed of the ball, and let \(r\) denote the radius of the circle. Since the ball is in a circular motion, the acceleration on this ball would be equal to the centripetal acceleration \(a = (v^{2} / r)\). The net force on this ball would be \(F_{\text{net}} = m\, a = (m\, v^{2} / r)\).

The net force on this ball is also the vector sum of the tension \(T\) in the rope and the weight of the ball \(m\, g\):

\(F_{\text{net}} = (\text{weight}) + T\).

\(T = F_{\text{net}} - (\text{weight})\).

Note that:

\(\| T \| = \|F_{\text{net}} - (\text{weight})\| \le \|F_{\text{net}} \| + \| (\text{weight})\|\).

In other words, the magnitude of tension \(T\) is at most equal to \(\|F_{\text{net}} \| + \| (\text{weight})\| = (m\, v^{2} / r) + (m\, g)\), which happens when weight and net force are in opposite directions.

When the speed of the ball is maximized, the magnitude of tension \(T\) would be at the largest possible value of \(130\; {\rm N}\). Rearrange the equation and solve for speed \(v\):

\(\displaystyle \frac{m\, v^{2}}{r} + m\, g = \|T\|\).

\(\begin{aligned}v^{2} = \frac{r}{m}\, (\|T \| - m\, g) = \frac{r\, \|T\|}{m} - r\, g\end{aligned}\).

\(\begin{aligned}v &= \sqrt{\frac{r\, \|T\|}{m} - r\, g} \\ &= \sqrt{\frac{(1.2)\, (130)}{2.5} - (1.2)\, (9.81)}\; {\rm m\cdot s^{-1}} \\ &\approx 7.2\; {\rm m\cdot s^{-1}}\end{aligned}\).

No, not all waves move through various materials at the same pace. The characteristics of the medium itself, the kind of wave, and the frequency of the wave are only a few of the variables.

that affect how quickly a wave moves through a given medium. Sound waves, for instance, go through various materials at varying rates, depending on the density and elasticity of the medium. In general, solids transmit sound more quickly than liquids or gases do. Similar to how sound waves go through various materials at various rates, depending on the refractive index of the medium. Light waves, for example, constantly travel in a vacuum at a constant speed of around 299,792,458 meters per second (or about 186,282 miles per second). Nevertheless, as they go on.

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Answer:

(c) the male vocal cord is longer

Explanation:

Males have a lower pitch in their voises than females, elongating men's vocal cords.

I am joyous to assist you at any time.

Voice of man is heavy compared to a woman because male vocal cord is longer.

The change is caused by an enlargement in the vocal folds, generating a more serious and adult voice. Generally speaking, the male voice is deeper than the female voice because the vocal muscles grow more in men than in women.

Males have a lower pitch in their voises than females, elongating men's vocal cords.

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Answer:

If the driver is wearing a seat belt, the seat belt rather than the windshield applies the unbalanced force that stops the driver's forward motion. The force from the seat belt is applied over a longer time, so the force causes less damage.

Explanation:

Answer:

/

Explanation:

Answer:

dark-field microscopy

Explanation:

A darkfield microscope can be regarded as a brightfield microscope with a significant modification to condenser. There is an opaque disk, with a diameter of about 1cm placed in between the illuminator and condenser lens, the disk responsible for the blocking of most of the light from the illuminator, passing through the condenser to objective lens , which will then form hollow cone of light that has its focus on the specimen. Using a darkfield microscope the light that get to the objective is the only refracted or reflected light of structures in the specimen. And the image formed usually display a bright object with a dark background.

It should be noted that darkfield microscope is a type of microscopy works by allowing only light waves that have reflected from or refracted though the sample to enter the lens system.

In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.

Alpha decay is a type of radioactive decay in which the nucleus of an atom emits an alpha particle which leads to transforming into a new atomic nucleus by losing two protons. During beta decay, the proton in the nucleus is transformed into a neutron and and neutron is transformed into proton while on the other hand, gamma decay is a type of decay in which nucleus changes from a higher energy state to a lower energy state due to the release of electromagnetic radiation.

So we can conclude that In alpha decay, the nucleus loses two protons, in beta decay, the nucleus either loses or gains a proton whereas in gamma decay, no change in proton number occurs only energy is released.

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The correct answer is option C.

Maxwell right hand thumb rule: if we hold a current carrying conductor in our right hand such that the thumb indicates the direction of current then the curling of fingers shows the direction of magnetic field around the conductor.

Here the current is counterclockwise so by use of Maxwell right hand thumb rule the direction of magnetic field is straight up.

Using Fleming right hand rule that States that if the fore-finger, middle finger and the thumb of left hand are stretched mutually perpendicular to each other, such that fore-finger points in the direction of magnetic field, the middle finger points in the direction of the motion of positive charge, then the thumb points to the direction of the force.

So, the current, when viewed from above, seems to move around loop in counterclockwise direction points straight up is because of Maxwell's Thumb Rule.

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The efficiency of the engine is 28.6%.

A wasted energy is energy that can not be utilized to do work. In this case, any energy that is not converted into electrical energy can be seen as a wasted energy.

Now recall that energy is the ability to do work. According to the second law of thermodynamics, the conversion of energy from one form to another is not hundred percent efficient hence some energy is usually lost in the process and this is called wasted energy.

Now we know that;

Energy available = 7,000J

Wasted energy =  5,000J

Useful energy = 7,000J  -  5,000J = 2,000J

Efficiency of the engine =  2,000J/ 7,000J  * 100/1

=28.6%

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Answer:

flujo de energia

Explanation:

Answer:

same,

my advise is you add more points it will make everyone anwser quicker.

Answer: 22.45

Explanation: it's right, trust me

Answer:

4,350,000 and 0.0000000006

Answer:

The answer is B.

Explanation:

They are in control of the experiment, they can change it the variables to better help the experiment.

Answer:

b

Explanation: its b

Answer: I do not know (is this an RP question? ;-;)

Explanation:

Answer:

Applications in which ionizing radiation are not used are  

MRI

ultrasound

laser surgery

Explanation:

hope its right

bestfriend

Create the Android App, set up the project, design the user interface, handle user input, perform calculations, and display the results.

Creating an Android App that calculates force and density can be done by following these steps:

Set up the project in Android Studio.

Design the layout of the user interface using XML, including TextViews, EditTexts, and a Button.

Define the necessary variables and views in the Java code.

Set an onClickListener for the button to perform the calculations.

Retrieve the user input from the EditText fields and convert them to appropriate data types.

Calculate the force using the formula F = ma and the entered mass and acceleration.

Display the calculated force in the result TextView.

Repeat steps 5-7 for calculating density if desired.

Run the app on an Android emulator or device to test its functionality.

The Simplifying User Input App developed in class can serve as a guide for implementing the user interface and handling user input.

You would need to modify the code to incorporate the force and density calculations based on the provided equations.

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Answer:

d = 11.77 m

Explanation:

Given that,

A ball is droped off the side of a bridge after 1.55 seconds.

We need to find how far it has fallen.

It will fall under the action of gravity. It would mean that a = g = 9.8 m/s²

Let it is fallen at a distance d. d can be calculated using second equation of motion as follows :

\(d=ut+\dfrac{1}{2}at^2\)

Put u = 0 and a = g

So,

\(d=\dfrac{1}{2}\times 9.8\times (1.55)^2\\\\d=11.77\ m\)

Hence, it will fall at a distance of 11.77 m.

Answer:

-11.77!!!! DONNT FORGET NEGATIVE

Explanation:

The mass of the water in the cylinder is 777.84 grams.


1. To calculate the mass, we first need to find the volume of water in the cylinder.
2. We are given the total volume of the cylinder (485.1 cm³) and the height of the water (7.2 cm).
3. Calculate the volume of the cylinder filled with water: (Volume of the entire cylinder / total height) * height of water = (485.1 cm³ / total height) * 7.2 cm.
4. Unfortunately, we do not have the total height of the cylinder. We cannot proceed with this calculation without that information.

However, if you meant to say that the volume of the water is 485.1 cm³, then:
1. Convert the volume of the water to mass: mass = volume x density (density of water is approximately 1 g/cm³).
2. Calculate the mass of the water: 485.1 cm³ * 1 g/cm³ = 485.1 grams.
3. Therefore, the mass of the water in the cylinder would be 485.1 grams.

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4.) The magnitude of vector is equal to the magnitude of vector is the statement correct about these two vector.

A quantity or occurrence with independent aspects for both magnitude and direction is called a vector. The term might also refer to a quantity's mathematical or geometrical representation. Velocity, momentum, force, electromagnetic fields, and weight are a few examples of vectors in nature.

Scalars only have magnitude, although vectors have included direction. It can be misleading because magnitude emerges for both scalars and vectors. For scientists, particular quantities—like speed—have very specific definitions. Speed is the scalar magnitude of a velocity vector, thus according definition.

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(a) The kinetic energy of the cart when it moves is 2/3 the way down is 1/3mgh.

(b) The total mechanical energy of the cart at the given height of 5 m is 5mg.

The potential energy of the cart when it is 2/3 way down the given height of 5 m is calculated as follows;

ΔP.E = mghf - mgh₀

ΔP.E = mg(hf - h₀)

ΔP.E = mg(2h/3 - h)

ΔP.E = -¹/₃mgh

ΔK.E = -ΔP.E

ΔK.E = ¹/₃mgh

M.A = P.E + K.E

M.A = ²/₃mgh + ¹/₃mgh

M.A = mgh

M.A = mg(5)

M.A = 5mg

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