Give an example of two cars that have the same speed but different velocities.

Answer: hey

Explanation:

The transfer function of the active low-pass Butterworth filter in Figure P7-7 is given by G(s)=V 2 (s)/V 1(s) = 1.5858/(1 + (1/ωc)s).

This can be seen by analyzing the circuit and applying the basic principles of Laplace transforms. The transfer function is of the same form as the transfer function of the Butterworth filter in Example 7-3, which was given by G(s)=V 2 (s)/V 1(s) = 1/(1 + (1/ωc)s). The only difference is in the numerator constant.

In Figure P7-7, the numerator constant is 1.5858 due to the gain of 1.5858 of the VCVS. This gain increases the magnitude of the output signal, resulting in the different numerator constant. The denominator polynomial, however, is the same in both cases, since the two capacitors have equal values. Thus, the transfer functions of the two Butterworth filters are the same, except for the different numerator constants.

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Answer:

845 m

Explanation:

Given in the y direction:

v₀ = 0 m/s

a = 10 m/s²

t = 13 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (13 s) + ½ (10 m/s²) (13 s)²

Δy = 845 m

Answer:

150000000000

Explanation:

speed= distance/time

Answer:

12m/s

Explanation:

60/5=12

Answer:

Explanation:

Solution,

Distance(d)=60m

Time(t)=5sec

Now,

A.speed=d/t

A.speed=60/5=12m/s

When θ = 0°, the normal stress on the element remains the same as the initial stress, while the shearing stress is zero. This is because the stress vector is perfectly aligned with the plane's normal, leading to no stress component acting parallel to the plane.

About normal and shearing stresses on an element when θ = 0°.

Normal stress refers to the stress that acts perpendicular to the plane of an element, while shearing stress acts parallel to the plane. When θ = 0°, the angle between the stress vector and the plane's normal is also zero. In this case, the stress acting on the element will be completely normal stress, and there will be no shearing stress.

To determine the normal stress (σ) and shearing stress (τ) at any angle, we typically use stress transformation equations, which are derived from the equations of equilibrium and Mohr's Circle. However, when θ = 0°, the transformation equations simplify, as the sine and cosine of 0° are 1 and 0, respectively. Consequently, at θ = 0°, the normal stress (σ) remains unchanged, and the shearing stress (τ) becomes zero.

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Answer:

Mass

No matter where an object is in the universe, the more matter an object has, the more mass it will have as well.

The trip takes a total of 1.5 hours and has an average speed of 40 mph.

To calculate the time taken for each leg of the trip, we can use the formula time = distance/speed.

For the first leg of the trip, the car travels 15 miles at a speed of 45 mph. Using the formula, we find that the time taken for this leg is 15/45 = 0.33 hours.

For the second leg of the trip, the car travels another 15 miles but at a speed of 30 mph. Using the formula, we find that the time taken for this leg is 15/30 = 0.5 hours.

To find the total time for the trip, we add the times for each leg: 0.33 hours + 0.5 hours = 0.83 hours.

To calculate the average speed for the entire trip, we use the formula average speed = total distance/total time. The total distance traveled is 15 miles + 15 miles = 30 miles. The total time taken is 0.83 hours. Plugging these values into the formula, we find that the average speed for the trip is 30/0.83 = 36.14 mph.

Therefore, the trip takes a total of 1.5 hours and has an average speed of 40 mph.

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Answer:

8550 Joules of energy.

Explanation:

                                                                                             = -8550 J

The required mass of the object when net force on it, distance moved and final velocity are given is calculated to be 4 kg.

The net force on the unknown mass object is 20 N.

Distance travelled is 10 m.

Final velocity is 10 m/s.

The object starts from rest, so u = 0.

Mass of the object is to be calculated.

The force is given by the expression, F = m a

Making 'm' as subject, we have,

m = F/a ---(1)

Acceleration can be found using the expression, v² - u² = 2 a s ---(2)

a = (v² - u²)/2 s = (10² - 0)/(2×10) = 100/20 = 5 m/s²

Using it in (1),

m = F/a = 20/5 = 4 kg

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Explanation:

1. Gamma Ray

2. Ultraviolet

3. X - ray

4. Visible

5. Infrared

6. Microwave

7. Radio

Shorter - 1, 2, 3

Longer - 5, 6, 7

The EMR is a region of the frequencies that clovers waves from 10 25 Hz to the wavelength of thousand of km. These are divided into separate bands.

Hence the EMR is completed by the above waves.

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Answer:

the greater the half life is the slower the rate of decay will be.

Explanation:

half life of a radioactive substance is inversely proportional to the radioactive decay.

Answer:

B. The greater the half life is, the slower the rate of decay will be

Explanation: Most living things contain carbon-14, an unstable isotope of carbon that has a half-life of around 5,000 years. That means that when scientists dig up fossil bones, they can figure out how old they are by measuring the amount of carbon-14 remaining in the bones.

The force experienced will be 8E-15 N.

A thin circular sheet of glass with a diameter of 7 meters has been rubbed with a cloth on one of its surfaces, resulting in a uniform charge.

A chloride ion, consisting of a chlorine atom which has gained an extra electron, passes near the glass sheet. When the chloride ion is 0.8 mm away from the center of the sheet, it experiences an electric force of 8E-15 N, directed towards the glass sheet. Using the value 8.85e-12 C2/(N·m2), this force can be calculated as follows:

F = 8.85e-12 x (Q1 x Q2) / d2

Where Q1 and Q2 are the charge of the chloride ion and the glass sheet, respectively, and d is the distance between them (0.8 mm).

Therefore, the force experienced by the chloride ion is 8E-15 N, as expected.

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Thinking about Planck's law, the Red star would give off the most orange light.

According to Planck's Law, distinct atoms and molecules can emit or take in power in discrete portions simplest. The smallest amount of strength that can be emitted or absorbed inside the form of electromagnetic radiation is called quantum.

Planck's Law describes the quantity of spectral radiance at a particular wavelength radiated through a black body in equilibrium. The equation is E=hv.

The floor temperature of a celeb determines the color of mild it emits. Blue stars are warmer than yellow stars, which are hotter than red stars. The bright orange celebrity Arcturus is particularly noteworthy for its massive right motion, The color is a characteristic of their floor temperatures.

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Answer:

Explanation:

Vector quantities are those quantities which needs both magnitude and direction for their description.

Here, in all the options except option B, there is no direction. This means, other options are scalar quantities and option B is only vector quantity.

Physical Quantities : These are the quantities of the physics which can me measured.

There are two types of physical quantities,

Vector quantities are those quantities which needs both magnitude and direction for their description. Example : Velocity, acceleration etc.

Scalar quantities are those quantities which needs only magnitude for their description. Example : Speed , distance etc.

Air masses and ocean currents can interact in several ways. Some of the ways that air masses and ocean currents can interact are listed below:

1. A significant factor in air mass formation is the amount of moisture present in the air, and this is largely influenced by ocean currents. The temperature and moisture levels in the air masses are affected by the temperature and moisture levels in the ocean currents.

2. The ocean currents affect the temperature of the air above it. As ocean currents travel across the globe, they influence the temperature of the atmosphere above them. The warm water in the Gulf Stream, for example, heats the air above it and creates a warmer climate in the regions it passes.

3. The temperature and moisture content of air masses affect the ocean currents by causing variations in pressure. Differences in pressure result in winds, which can drive the ocean currents.

4. The atmosphere's winds and ocean currents affect each other. A prevailing westerly wind, for example, can push ocean currents from west to east.

5. Ocean currents play a critical role in the planet's carbon and heat transfer. The ocean currents transport carbon dioxide and heat throughout the planet.

6. The ocean currents affect the climate of the coastal areas. Coastal areas are impacted by ocean currents, which can bring either warm or cold water to the coasts. The Gulf Stream, for example, influences the coastal weather in North-Western Europe by bringing in warm water.

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Answer:

(a) The optimum banking Decreases

(b) The optimum banking Increases

(c) The optimum banking is approximately 86.88°

Explanation:

(a) The equation of motion on a banked road is given as follows;

\(v = \sqrt{R \cdot g \times \left(\dfrac{tan (\theta) + \mu}{1 - \mu \cdot tan (\theta) }\right) }\)

For no friction, we have;

v = √(R·g·tan(θ))

Where;

R₁ = The radius of the road

g = The acceleration due to gravity ≈ 9.81 m/s² = Constant

θ₁ = The bank angle

μ = The coefficient pf friction = Constant

v = The vehicle's speed

If the radius doubles, for no friction, we have;

v² = R·g·(tan(θ))

tan(θ) = v²/(R·g)

Therefore, when the radius doubles, tan(θ) becomes smaller and therefore, the optimum banking angle θ decreases (becomes smaller)

(b) When the speed doubles, we have;

v₁ = 2·v

∴ tan(θ₁) = (v₁)²/(R·g) = 4·(v)²/(R·g) = 4·tan(θ)

When the speed doubles, tan(θ) increases and therefore, the optimum banking angle θ increases increases

(c) The radius negotiated by the car, R = 80 cm = 0.8 m

The speed of the car, v = 12 m/s

From tan(θ) = v²/(R·g), we have;

tan(θ) = 12²/(0.8 × 9.81) ≈ 18.349

θ ≈ arctan(18.349°) ≈ 86.88°

The electric field is twice the force exerted  by one charge at the midpoint between two opposite charges.

The electric field is a vector field that describes the force experienced by a charged particle in a given location. When two opposite charges are placed near each other, they create an electric field that points away from one charge and towards the other.

However, at the midpoint between the two charges, the electric field due to each charge does not cancels out, resulting in a net electric field of non-zero. This means that a charged particle placed at this location would experience any force due to the electric field.

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Newton's law of cooling states that the rate of temperature change of a body is proportional to the difference between its temperature and the ambient temperature. Using Euler's method, an M-file function called Bodycooling can be created to solve this problem and compute the temperature and its derivative over a given time period. The results can be plotted in MATLAB to visualize the temperature variation over time.

a) The equation can be written in finite divided differences suitable for Euler's method as:

(T_i+1 - T_i) / Δt = -k(T_i - T_ambient)

b) Here is an example of the Bodycooling.m function in MATLAB:

```MATLAB

function [time, temperature, derivative] = Bodycooling(ambientTemp, k, timesteps, initialTemp, totalTime)

   time = linspace(0, totalTime, timesteps + 1);

   temperature = zeros(1, timesteps + 1);

   derivative = zeros(1, timesteps + 1);

   temperature(1) = initialTemp;

   for i = 1:timesteps

       derivative(i) = -k * (temperature(i) - ambientTemp);

       temperature(i+1) = temperature(i) + derivative(i) * (time(i+1) - time(i));

   end

end

```

c) To compute the temperature and temperature derivative from t = 0 to 20 min with a step size of 2 min, using ambient temperature Ta = 20 °C and k = 0.019 min^(-1), you can call the Bodycooling function as follows:

```MATLAB

ambientTemp = 20;

k = 0.019;

timesteps = 10; % (20 min / 2 min)

initialTemp = 70;

totalTime = 20;

[time, temperature, derivative] = Bodycooling(ambientTemp, k, timesteps, initialTemp, totalTime);

```

d) To plot the temperature as a function of time, you can use the following MATLAB code:

```MATLAB

plot(time, temperature);

xlabel('Time (min)');

ylabel('Temperature (°C)');

title('Temperature of the Body over Time');

grid on;

```

Executing this code will display a plot showing the temperature of the body as a function of time.

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Minimum stream velocity necessary to transport quartz particle that is 0.1 centimeter in diameter in a stream is : 5.0 cm/s.

Velocity is the directional speed of object in motion as indication of its rate of change in position as observed from particular frame of reference  as measured by particular standard of time.

As, Q = V * A

given that the diameter of the particle = 0.1 cm

V is stream velocity , A is cross sectional area of stream and Q is stream flow

Given a particle with a diameter of 0.1 cm,

To determine the stream velocity we use a stadia rod to measure at least 5 meters down ( depth of stream ) three times and then take average value which will be used to determine cross sectional area of the stream but given that the width of the stream is not given the closet value to the stream velocity will be = 5.0 cm/s.

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Answer:

Below

Explanation:

Find acceleration first

vf = vo + at     (starts from rest so vo = 0)

8 = 0 + at    

8 = at

d = vo t + 1/2 a t^2     (substitute 8 in for 'at')

200 = 0 t  + 1/2 (8) t

200 / 4 = t = 50 seconds for front of train to pass her at 8 m/s

  acceleration = change in velocity / change in time = 8 / 50 = .16 m/s^2

Back of train has to travel 120 meters at initial v = 8 m/s  and accelerating  at .16 m/s^2   :

  d = vo t + 1/2 a t^2

 120 = 8 t + 1/2 ( .16 ) t^2

           .16t^2 + 8t - 120 = 0      Quadratic Formula shows t = 13.25 s

vf = vo  + a t

vf = 8 m/s  + .16 m/s^2 ( 13.25 s) = 10.1 m/s

Answer:

Infrasound vs. Ultrasound: Infrasound is sound that is below the lower limit of human hearing, below 20 Hz, and ultrasound is above the upper limit of human hearing, above 20,000 Hz.  Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes, graphing rock and oil developments underneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, a few creatures, for example, whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, water falls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

Explanation:

idk how many words this is but its a start for u to add on to and i hope this helps and its in my own words - pls mark me brainiest

Answer:

Ultrasound vs. Infrasound Research Exploration

Beyond the limit of human hearing, ultrasound is above 20,000 Hz. Under the limit of human hearing, infrasound is below 20 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes as well as graphing rock and oil developments beneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, creatures like whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, waterfalls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

(Not turned in yet, but this is what i have so far. Good luck 8th graders <33)

-Sav xx

The statement is False. Depending on the metal and the temperature, the crystal structure of metal can change.

Structure is the arrangement of and relationship between the parts or elements of something complex. It can refer to physical structures, such as buildings, bridges, and roads, or to abstract structures, such as systems, theories, and ideas. Structures are the foundation of any built environment, and the study of them helps us to understand how the world works. Structures help to shape the world around us, and can provide stability, strength, and support. It can also help us to organize and simplify complex information, and make connections between different parts of our lives. Structures can be seen everywhere, from the structure of a molecule to the structure of a government.

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Answer:

:) :::::::::::::::::::::::::::::::))))

When monochromatic light shines through two slits and then onto a screen, as the screen is moved closer, the interference fringes will become wider and more closely spaced, while the overall brightness of the interference pattern will increase.

When monochromatic light shines through two slits and then onto a screen, interference fringes are formed due to the wave nature of light. These fringes result from the constructive and destructive interference of the light waves that pass through the two slits. As the screen is moved closer, the interference fringes will become wider and more closely spaced. This is because the distance between the slits and the screen is decreasing, which causes the angle of diffraction to increase. This increased angle of diffraction leads to a wider distribution of the light waves, resulting in wider and more closely spaced interference fringes. Additionally, as the screen is moved closer, the overall brightness of the interference pattern will increase because more light is being concentrated within a smaller area on the screen.

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Answer:

14.2m/s^2

Explanation:

The centripetal acceleration of the race car is 14.22 m/s².

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

Given that: Speed of the race car: v = 80.0 meter/second.

Radius of the racetrack: r = 450 meter.

Hence, the centripetal acceleration of the car is = v²/r

= (80.0)²/450 m/s²

= 14.22 m/s².

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Answer:  Mass

Explanation:

Answer:

Explanation:

Let b be the height of the building, and y the height of the ball at time t, given by

y = b - 1/2 gt²

where g = 9.8 m/s² is the magnitude of the acceleration due to gravity.

It takes the ball 8 s to reach the ground, at which point y = 0, so that

0 = b - 1/2 (9.8 m/s²) (8 s)²

b = 1/2 (9.8 m/s²) (8 s)²

b = 313.6 m