To give a recursive definition of the functions max and min, we can start by defining the base case and then building upon it.
For the function max, the base case would be when we have only two numbers, a1 and a2. In this case, we would simply compare the two numbers and return the maximum.
max(a1, a2) =
- a1 if a1 > a2
- a2 if a2 > a1
To extend this definition to n numbers, we can use recursion. We first find the maximum of the first n-1 numbers using the same recursive definition. We then compare this maximum with the nth number and return the greater of the two.
max(a1, a2, ..., an) =
- max(a1, a2, ..., an-1) if max(a1, a2, ..., an-1) > an
- an if an > max(a1, a2, ..., an-1)
Similarly, for the function min, the base case would be when we have only two numbers, a1 and a2. In this case, we would simply compare the two numbers and return the minimum.
min(a1, a2) =
- a1 if a1 < a2
- a2 if a2 < a1
To extend this definition to n numbers, we can use recursion. We first find the minimum of the first n-1 numbers using the same recursive definition. We then compare this minimum with the nth number and return the smaller of the two.
min(a1, a2, ..., an) =
- min(a1, a2, ..., an-1) if min(a1, a2, ..., an-1) < an
- an if an < min(a1, a2, ..., an-1)
Therefore, we have provided recursive definitions of the functions max and min, where max(a1, a2,.. an) and min(a1, a2,. an) are the maximum and minimum of the n numbers a1, a2,.... an respectively.
Let's start with the base cases:
1. max(a1): In this case, the maximum value is a1 itself, as there's only one number.
2. min(a1): Similarly, the minimum value is a1 when there's only one number.
Now, let's define the recursive steps for both max and min functions:
1. max(a1, a2, ..., an):
- Compare a1 with the maximum value of the remaining n-1 numbers, i.e., max(a2, a3, ..., an).
- If a1 is greater than max(a2, a3, ..., an), then max(a1, a2, ..., an) = a1.
- Otherwise, max(a1, a2, ..., an) = max(a2, a3, ..., an).
2. min(a1, a2, ..., an):
- Compare a1 with the minimum value of the remaining n-1 numbers, i.e., min(a2, a3, ..., an).
- If a1 is smaller than min(a2, a3, ..., an), then min(a1, a2, ..., an) = a1.
- Otherwise, min(a1, a2, ..., an) = min(a2, a3, ..., an).
By using these recursive definitions, you can find the maximum and minimum of n numbers a1, a2, ..., an respectively.
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Which statement is true about parallel lines?
A. They intersect and are coplanar.
B. They intersect, but are not coplanar.
C. They do not intersect, but are coplanar.
D. They do not intersect and are not coplanar.
Answer:
C( They do not intersect, but are coplanar
Step-by-step explanation:
Parallel lines are coplanar (they lie in the same plane) and never intersect.
The statement that is true about parallel lines is that they do not intersect, but are coplanar: Option C is correct.
Lines are 2-dimensional figures that are used to connect two on more points in a xy-plane.
For two lines to be parallel, this means that the lines;
cannot meet each other i.e. they can not intersectThey can lie on the same plane i.e they can be coplanarHence we can conclude that the statement that is true about parallel lines is that they do not intersect, but are coplanar.
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The points (-1,-5) and (6, -5) are on a coordinate plane. What is the distance between the points?
Answer:
7
Step-by-step explanation:
the x-coordinates are -1 and 6. there's a distance of 7 between those two.
the y-coordinates are -5 and -5. there's a distance of 0 between those two.
(distance between points)² = 7² + 0² = 49 + 0 = 49.
take the square root of both sides:
distance between points = √49 = 7.
this would also have worked if the y-coordinates were different.
Let p be prime.
(a) Show that if x2 ≡ 0 (mod p), then x ≡ 0 (mod p).
(b) Show that if k ≥ 2, then x2 ≡ 0 (mod pk) has solutions with
x 6≡ 0 (mod pk).
2. (a) What is gcd(111; 11)? Using the Extended Euclidean algorithm,
find 11-1 mod 111.
(b) What is gcd(1111; 11)? Does 11-1 mod 1111 exist?
(c) Find gcd(x; 11), where x consists of n repeated 1s. What can you
say about 11-1 mod x as a function of n?
a) If \(x^2\) ≡ 0 (mod p), then x ≡ 0 (mod p). b) x = \(p^{k-1\) is a solution to \(x^2\) ≡ 0 (mod \(p^k\)) where x ≠ 0 (mod \(p^k\)). 2) a) \(11^{-1\) mod 111 is -10, or equivalently, 101 (mod 111). b) \(11^{-1\) mod 1111 does not exist. c) \(11^{-1\) mod x does not exist.
(a) To show that if \(x^2\) ≡ 0 (mod p), then x ≡ 0 (mod p), we can use the property that if a ≡ b (mod p) and c ≡ d (mod p), then ac ≡ bd (mod p).
Given \(x^2\) ≡ 0 (mod p), we can rewrite it as \(x^2\) - 0 ≡ 0 (mod p), which simplifies to \(x^2\) ≡ 0 (mod p).
Now, we can multiply both sides of the congruence by x to obtain x * \(x^2\) ≡ x * 0 (mod p), which further simplifies to \(x^3\) ≡ 0 (mod p).
Since \(x^3\) ≡ 0 (mod p), it implies that x ≡ 0 (mod p) since any number multiplied by 0 is always 0.
Therefore, if \(x^2\) ≡ 0 (mod p), then x ≡ 0 (mod p).
(b) To show that if k ≥ 2, then \(x^2\) ≡ 0 (mod \(p^k\)) has solutions with x ≠ 0 (mod \(p^k\)), we can choose x = \(p^{k-1\).
If we substitute this value of x into the congruence \(x^2\) ≡ 0 (mod \(p^k\)), we get \((p^{k-1})^2\) ≡ 0 (mod \(p^k\)), which simplifies to \(p^{2k-2\) ≡ 0 (mod \(p^k\)).
Since 2k-2 ≥ k for k ≥ 2, it implies that \(p^{2k-2\) is divisible by \(p^k\), and hence \(p^{2k-2\) ≡ 0 (mod \(p^k\)).
Therefore, x = \(p^{k-1\) is a solution to \(x^2\) ≡ 0 (mod \(p^k\)) where x ≠ 0 (mod \(p^k\)).
(a) To find gcd(111, 11), we can use the Euclidean algorithm:
111 = 11 * 10 + 1
11 = 1 * 11 + 0
Since the remainder is 1, the gcd(111, 11) is 1.
Using the Extended Euclidean algorithm, we can find \(11^{-1\) mod 111 by working backwards in the Euclidean algorithm:
1 = 111 - 11 * 10
Rearranging the equation, we get 11 * (-10) + 111 * 1 = 1.
Therefore, \(11^{-1\) mod 111 is -10, or equivalently, 101 (mod 111).
(b) To find gcd(1111, 11), we can again use the Euclidean algorithm:
1111 = 11 * 101 + 0
Since the remainder is 0, the gcd(1111, 11) is 11.
However, \(11^{-1\) mod 1111 does not exist because gcd(1111, 11) is not equal to 1. In order for the modular inverse to exist, the numbers must be coprime (gcd = 1).
(c) When we find gcd(x, 11), where x consists of n repeated 1s, we can observe the pattern:
gcd(11...11, 11) = 11 * (n - 1) + 1 = 11n - 10
Therefore, gcd(x, 11) is equal to 11n - 10, where n represents the number of repeated 1s in x.
Regarding \(11^{-1\) mod x, it exists if and only if gcd(x, 11) = 1. From the expression above, we can see that if n = 1, gcd(x, 11) = 1 and \(11^{-1\) mod x exists. However, for n > 1, gcd(x, 11) will not equal 1, and thus, \(11^{-1\) mod x does not exist.
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The function f(x) = 7x + 15 models the time in minutes that a customer will wait to get an oil change if there are x cars in line.
How long will a customer wait if they are the fifth car in the line?
A) 28 minutes
B) 35 minutes
C 43 minutes
D) 50 minutes
Answer:
D 50 minutes
Step-by-step explanation:
If the customer is the fifth car in line then x = 5, so
f(5) = 7(5) + 15
f(5) = 35 +15
f(5) = 50
cost of 5 pens is RS 10 what is the cost of one pen
Answer:
Rs 2
Step-by-step explanation:
5 pen =Rs 10
1 pen = 10÷2
=Rs 2
А
E E
С
D
B
If mZACD = 100°, then mZACE = [?]°
Answer:
80 degrees
Step-by-step explanation:
a line is always 180 degrees
one side of that line is 100
so, just subtract 100 from 180
you get 80
180 - 100 = 80
most mis's use sophisticated mathematical models or statistical techniques. group of answer choices true false
The statement "Most MIS's use sophisticated mathematical models or statistical techniques" is generally true.
Management Information Systems (MIS) play a crucial role in modern organizations by providing valuable insights into various aspects of the business.
These systems gather data from different sources and transform it into meaningful information for decision-making purposes.
To make sense of the collected data, MIS rely on sophisticated mathematical models and statistical techniques.
Mathematical models are used to represent real-world situations and relationships mathematically.
These models can range from simple equations to complex algorithms that simulate and predict business processes.
By using mathematical models, MIS can analyze data, identify patterns, and make predictions or projections.
Statistical techniques, on the other hand, provide methods for summarizing and analyzing data to extract meaningful information.
MIS employ statistical techniques such as regression analysis, hypothesis testing, data visualization, and forecasting to uncover insights and support decision-making.
By leveraging these sophisticated mathematical models and statistical techniques, MIS can handle large volumes of data, identify trends and patterns, perform predictive analysis, and provide valuable insights for effective decision-making in areas such as resource allocation, strategic planning, inventory management, and customer behavior analysis.
Therefore, it is safe to say that most MIS's utilize sophisticated mathematical models and statistical techniques to process and analyze data, enabling organizations to make informed decisions based on accurate and meaningful information.
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a state college introduced one-week study skills for new freshman students. at the end of the academic year, the college compared the gpas of their freshman with the corresponding gpas of freshman at a neighboring state college who did not recieve the course. this study is an example of
This study is an example of a nonequivalent control group posttest-only design.
When comparing posttest-only designs, a major limitation to the one-group posttest-only design is that it lacks a control or comparison group. Quasi-experimental research is research that resembles “true” experimental research. Like in a true experiment, an independent variable is manipulated. The “After-only with control group” experimental design.
Again, this design involves establishing two matched samples or groups of respondents. There is no measurement taken from either group before the experimental variable is introduced and the control group is not subsequently subjected to the experimental variable.
The nonequivalent control group posttest-only design compares at least two groups where one group has received a treatment/intervention and the other has not using an after-treatment/intervention test.
Thus, this study is an example of a nonequivalent control group posttest-only design.
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what are the equations to the graph
Can someone help me no bots or ill report ill also give brainly when their is 2 answer
The equations are y=3x-1 and y=-3x+5
I’ll try to solve it in the comments if you still have time
factorial calculator create a program that calculates the factorial of the number entered by the user
In order to create a program that calculates the factorial of the number entered by the user, follow the steps given below:
Step 1: Start the program.
Step 2: Take input from the user in the form of an integer.
Step 3: Initialize a variable to store the factorial of the input integer. Let's name it 'fact'.
Step 4: Assign the value of fact to 1.
Step 5: Start a for loop and run it from 1 to the input integer. Assign the loop variable to i.
Step 6: Inside the loop, update the value of fact as fact=fact*i.
Step 7: End the loop.
Step 8: Print the value of fact as output.
Step 9: End the program.
Here is the code that implements the above steps:
import java. util.Scanner;
public class Main {public static void main(String[] args)
{
Scanner input = new Scanner(System.in);
System. out.println("Enter a number: ");
int n = input.nextInt();
int fact = 1;
for (int i=1; i<=n; i++)
{
fact = fact * i;
}
System.out.println("Factorial of "+n+" is "+fact);
}
}
The above program first prompts the user to enter a number.
Then it calculates and prints the factorial of the number entered by the user using the formula given below:
n! = n*(n-1)*(n-2)*...*3*2*1
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when computing the correlation​ coefficient, what is the effect of changing the order of the variables on​ r?
The correlation coefficient (r) measures the strength and direction of the linear relationship between two variables. The value of r ranges from -1 to +1, where a value of -1 indicates a perfect negative correlation, +1 indicates a perfect positive correlation, and 0 indicates no correlation.
The correlation coefficient's sign will not change when the order of the variables in a correlation study is changed, but the coefficient's numerical value might. This is due to the symmetry of the correlation coefficient with regard to the two variables under comparison.
For instance, if you calculate the correlation coefficient between X and Y and the result is r = 0.7, it indicates that Y tends to rise as X does. The correlation coefficient between the variables Y and X will have the same sign (+ or -) but a different numerical value if the variables are computed in a different order.
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f(x) = -2 sin(x)
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum
value on the graph closest to the first point.
The graph of the function f(x) = -2sin(x) starts at the midline (y = 0) and reaches its maximum or minimum point closest to the midline at (π/2, -2).
Start by plotting the midline, which is the x-axis (y = 0). This is the starting point for the graph.
Find the maximum or minimum point on the graph closest to the midline. In this case, the maximum or minimum point is a maximum point because the coefficient of sin(x) is negative (-2). The maximum point occurs at π/2 on the x-axis.
Plot the maximum point on the graph at (π/2, -2). This point represents the highest or lowest point on the graph closest to the midline.
From the maximum point, the graph will start to decrease. Since the coefficient of sin(x) is -2, the graph will have a steeper slope compared to the graph of sin(x).
As x increases from π/2, the graph will continue to decrease until it reaches the next minimum point, which will be at 3π/2.
Continue plotting points on the graph by evaluating the function at various x-values and connecting them smoothly to create a sinusoidal curve.
Repeat the pattern of the graph for every interval of 2π, as the sine function is periodic.
Finally, label the x-axis as "x" and the y-axis as "f(x)" or "y" to indicate the function being graphed.
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the average height of a woman in the united states is 63.6 inches with a standard deviation of 2 inches. the average height of a man in the united states is 69 inches with a standard deviation of 2.8 inches. the inside length of a standard casket is 78 inches. what z-score would a man have if he was exactly 78 inches tall?
The z-score for a man who is exactly 78 inches tall is 3.214. This indicates that his height is 3.214 standard deviations above the mean height for men in the United States, which is quite unusual.
To find the z-score for a man who is exactly 78 inches tall, we first need to calculate the man's height in terms of standard deviations from the mean.
The formula for calculating the z-score is:
z = (x - μ) / σ
where x is the value we want to convert to a z-score, μ is the mean, and σ is the standard deviation.
In this case, the man's height is x = 78 inches, and the mean and standard deviation for men's heights are μ = 69 inches and σ = 2.8 inches, respectively.
Plugging these values into the formula, we get:
z = (78 - 69) / 2.8 = 3.214
Therefore, the z-score for a man who is exactly 78 inches tall is 3.214. This means that the man's height is 3.214 standard deviations above the mean height for men in the United States.
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i roll five fair dice. i tell you at least two dice landed on 4, 5, or 6. what is the probability that there are exactly 4 dice that landed on a 4, 5, or 6
Using binomial probability, the probability of having exactly 4 dice on 4, 5 or 6 is 5/32.
What is the probability that there are exactly 4 dice that landed on a 4, 5, or 6?Using binomial probability, we can calculate the probability that out of the 5 dice thrown, the probability of having exactly 4 dice on 4, 5 or 6 can be calculated as;
\(P(X=k) = C(n, k) * p^k * (1-p)^(^n^-^k^)\)
In the given data;
n = 5
k = 4
p = 3/6 = 1/2
Using the binomial probability formula, we can calculate:
P(X=4) = C(5, 4) * (1/2)⁴ * (1 - 1/2)⁵⁻⁴
P(X=4) = 5 * (1/2)⁴ * (1/2)¹
P(X=4) = 5 * (1/16) * (1/2)
P(X=4) = 5/32
Therefore, the probability that exactly 4 dice land on a 4, 5, or 6 when rolling five fair dice is 5/32.
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Which expression simplifies to 4v13?
Answer:
Step-by-step explanation:
It’s v208
4. A ball is thrown upward from the top of a building and has a height in feet of
y = -16x2 + 32x + 60 after x seconds.
A box is 50 cm long. which of these is closest to the length of this box in feet? (1 inch = 2.54 cm)
To find the closest measurement in feet to the length of a box given in centimeters, we need to convert the centimeters to feet using the conversion factor 1 inch = 2.54 cm. By converting the length of the box
The length of the box is given as 50 cm. To convert this length to feet, we need to go through two conversion steps. First, we convert centimeters to inches using the conversion factor 1 inch = 2.54 cm:
50 cm * (1 inch / 2.54 cm) = 19.69 inches
Next, we convert inches to feet using the fact that there are 12 inches in a foot:
19.69 inches * (1 foot / 12 inches) = 1.64 feet
Therefore, the closest measurement to the length of the box, 50 cm, in feet is approximately 1.64 feet.
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what is : 1.25 + (-0.75)
Answer:
0.5
Step-by-step explanation:
use a cauculator
Answer:
0.50
Step-by-step explanation:
You can rewrite this as 1.25 - 0.75. When you do this, you will get 0.50
Please help:)...........
Part (a)
Answer: x = 0-----------------
Work Shown:
\(3\left(\frac{x}{7}+2\right) = 6\\\\\frac{x}{7}+2 = \frac{6}{3}\\\\\frac{x}{7}+2 = 2\\\\\frac{x}{7} = 2-2\\\\\frac{x}{7} = 0\\\\x = 7*0\\\\x = 0\\\\\)
In step 2, I divided both sides by 3. In step 4, I subtracted 2 from both sides. In step 6, I multiplied both sides by 7.
================================================
Part (b)
Answer: x = 3-----------------
Work Shown:
\(2\left(\frac{5x}{3}-1\right) = 8\\\\\frac{5x}{3}-1 = \frac{8}{2}\\\\\frac{5x}{3}-1 = 4\\\\\frac{5x}{3} = 4+1\\\\\frac{5x}{3} = 5\\\\5x = 3*5\\\\5x = 15\\\\x = \frac{15}{5}\\\\x = 3\\\\\)
The steps are fairly similar to part (a). The steps were
divide both sides by 2 (step 2)add 1 to both sides (step 4)multiply both sides by 5 (step 6)divide both sides by 5 (step 8)Solve for zzz.
Assume the equation has a solution for zzz.
-p\cdot(d+z) = -2z+59−p⋅(d+z)=−2z+59
The solution to the given algebraic equation is \(\mathbf{z = \dfrac{59+pd}{(p+2)}}\)
Solving algebraic equations:Algebraic equations are mathematical expressions with variables, coefficients, and arithmetic operations. To solve algebraic expressions with two or more variables, the required variable to be solved must be the subject of the formula:
From the given information, we have:
\(\mathbf{-p\cdot(d+z) = -2z+59}\)
So, the first step in solving this algebraic is to open the bracket.-pd +pz = -2z + 59
Collect like termspz + 2z = 59 + pd
Factorize the left-hand side of the equationz(p+2) = 59 + pd
Make (z) the subject of the formula:\(\mathbf{z = \dfrac{59+pd}{(p+2)}}\)
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drag the gray arrow so that it is pointing midway between horizontal and vertical, heading downward and toward the right. extend it as far as it will go. what do you notice about the speed of the star as compared to the speed of the star relative to earth?
The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.
These are due to the Doppler effect, the equation of frequency detected by the observer as
\(f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } }\) where \(\beta = \frac{v}{c}\), v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.
Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
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y= x square + 14x -9
what is the 95% confidence interval estimate of the difference in traffic between a rural and urban location? assume that all other independent variables remain constant.
To find the confidence interval statistical analysis such as hypothesis testing or regression analysis is used. However, it is impossible to calculate without data.
To estimate the difference in traffic between a rural and urban location with a 95% confidence level, you would need specific data or information about the traffic counts or relevant measurements from both locations. The confidence interval estimate can be obtained using statistical analysis techniques such as hypothesis testing or regression analysis.
Typically, the process involves collecting data on traffic counts or related variables from both the rural and urban locations. Then statistical methods are applied to calculate the confidence interval estimate based on the sample data. The specific formula or method used would depend on the nature of the data and the analysis approach chosen.
Without specific data or information about the traffic counts or measurements, it is not possible to provide a numerical estimate for the 95% confidence interval of the difference in traffic between a rural and urban location.
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6 friends are selling crafts at a show. They each need to pay $7.20 to cover the table rental. They each sell 3 items. If every item is the same price, and the 6 friends make a total of $25.20, what was the sale price of each item?
Answer:
$1.40
Step-by-step explanation:
you just divide 25.20 by 18 (6 friends x 3 items) and thats it
Pls help if your good at math I’ll mark brainliest and a thank you:)
A. -1/2
B. 2
c. 1 / 2
D. -2
Answer:
C. 1/2
Plzzzzz give me Brainliest!!!!!
1. Use the distance formula (FOR COORDINATES) to find the distance between A(-6, 4) and B(5,-3).
Answer: \(\sqrt{170}\)
Step-by-step explanation:
Distance formula: a^2+b^2=c^2 where c is the distance between two points
(-6-5)^2 + (4-(-3))^2=c^2
(-(6+5))^2 + (4+3)^2=c^2
(-11)^2 + 7^2=c^2
121 + 49=c^2
c^2=170
c=\(\sqrt{170}\) ==> distance between A and B
THIS NEEDS TO BE OVER WITHHHHHH
1. -2 + 4w Excluded value: w = 0 (division by zero is undefined)
2. 3/(a-5) Excluded value: a = ±5 (division by zero is undefined)
3. -4(n+16)(n-16)/(n-8) Excluded value: n = 8 (division by zero is undefined)
How did we get the values?1. -2w²/w² + 4w
= -2 + 4w (simplify by canceling out the common factor of w²)
Excluded value: w = 0 (division by zero is undefined)
2. 3a+15/a²-25
= 3(a+5)/(a+5)(a-5)
= 3/(a-5) (simplify by canceling out the common factor of a+5)
Excluded value: a = ±5 (division by zero is undefined)
3. 4n²-256/8-n
= 4(n+16)(n-16)/-(n-8)
= -4(n+16)(n-16)/(n-8) (simplify by factoring the numerator and multiplying by -1)
Excluded value: n = 8 (division by zero is undefined)
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Stacy studies math for Ž of an hour per day and science for Ž of an hour per day.How many total hours does she study in 5 days?5A.of an hourB.5of an hour30C.106hoursD.25 hoursE.356hours
Given data:
The number of hour Stacy studied maths is 2/6 hour.
The number of hour Stacy studied science is 3/6 hour.
The total number of hours Stacy studied in 5 days is,
\(\begin{gathered} 5(\frac{2}{6}+\frac{3}{6})=5\times\frac{5}{6} \\ =\frac{25}{6} \end{gathered}\)Thus, the total number of hours Stacy studied in 5 days is 25/6 hours, so option (D) is correct.
Pls help me answer this it is due tomorrow pls help
Check the picture below.
\(\cfrac{1}{6}+\cfrac{1}{4}\implies \cfrac{(2)1+(3)1}{\underset{\textit{using this LCD}}{12}}\implies \cfrac{5}{12}~\hfill {\Large \begin{array}{llll} > \end{array}} ~\hfill \cfrac{1}{6}+\cfrac{1}{6}\implies \cfrac{2}{6}\implies \cfrac{1}{3}\)
notice, 1/4 is really larger than 1/6 of the same whole.
Use the side-splitting theorem to solve for x .
NEED ASAP
For triangle EFD, the value of x is 24 units.
We know that the side-splitting theorem states that, 'if a line is parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally.'
For triangle EFD we can obaserve that GH is parallel to side ED.
By applying the side-splitter theorem to triangle EFD,
⇒ FG/GE = FH/HD
Here, FG = 18 units, GE = 6 units, HD = 8 units
substituting values,
⇒ 18/6 = x/8
⇒ 3 = x/8
⇒ x = 3 × 8
⇒ x = 24 units
Therefore, the value of x is 24 units.
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