Gino walks 300 meters East, then turns and walks 400 meters North. What is the distance traveled by Gino?

1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum

Mass is conserved in a reaction if the of the initial reactant masses equals the of the masses of products

The law of conservation of mass is a fundamental principle in chemistry that states that the total mass of a closed system remains constant during a chemical reaction. This means that the mass of the reactants before a chemical reaction is equal to the mass of the products after the reaction.

The mass of the reactants before the reaction is equal to the mass of the products after the reaction. This confirms that the law of conservation of mass holds true for this chemical reaction.

This principle is essential in chemistry as it allows us to make predictions about the outcome of a reaction based on the starting materials. It also helps to ensure the accuracy of experimental measurements, as any discrepancy between the expected and observed masses can indicate an error in the experiment.

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The value of force exerted on the women will be normal of the lift in positive x direction .

Acceleration is defined as change of velocity divided by time.

Since lift is moving upward at a steady speed , that means no change of speed has been taken place . hence no acceleration.

There is no external acceleration acting on the lift . Hence there will be  two forces, one is the force of gravity and the other is upward normal force from the elevator.

N = mg if the elevator is at rest or moving at constant velocity

The value of force exerted on the women will be normal of the lift in positive x direction

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Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.

The acceleration of the car between 2 and 5 seconds is 0m/\(s^{2}\).

How can the velocity time graph be used to determine the acceleration?

Calculating acceleration involves dividing the change in velocity, expressed in meters per second, by the time required for the change, expressed in seconds. The acceleration is measured in m/\(s^{2}\).

As we are aware, velocity = distance / time.

And acceleration = velocity / time.

The linear graph shows that the distance travelled at the time interval of 2 seconds is 10 m. Hence the velocity(\(v_{1}\)) =10/2 = 5m/s.

The graph shows that the distance travelled is 25 m at time interval of 5 seconds. Hence the velocity (\(v_{2}\)) =25/5 = 5m/s.

Acceleration between 2 and 5 seconds is now calculated as

(\(v_{1}\)-\(v_{2}\)) / (\(t_{2}\)-\(t_{1}\)) = (5-5)/(5-2) = 0 m/\(s^{2}\)

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Answer:

A)   F = - 8.5 10² N,  B)   I = 21 N s

Explanation:

A) We can solve this problem using the relationship of momentum and momentum

          I = Δp

in this case they indicate that the body rebounds, therefore the exit speed is the same in modulus, but with the opposite direction

         v₀ = 8.50 m / s

         v_f = -8.50 m / s

         F t = m v_f -m v₀

         F = \(m \frac{(v_f - v_o)}{t}\)

let's calculate

         F = \(1.00 \ \frac{(-8.5-8.5)}{2 \ 10^{-2}}\)

         F = - 8.5 10² N

B) let's start by calculating the speed with which the ball reaches the ground, let's use the kinematic relations

         v² = v₀² - 2g (y- y₀)

as the ball falls its initial velocity is zero (vo = 0) and the height upon reaching the ground is y = 0

         v = \(\sqrt{2g y_o}\)

calculate  

         v = \(\sqrt{2 \ 9.8 \ 10}\)

         v = 14 m / s

to calculate the momentum we use

         I = Δp

         I = m v_f - mv₀

when it hits the ground its speed drops to zero

we substitute

         I = 1.50 (0-14)

         I = -21 N s

the negative sign is for the momentum that the ground on the ball, the momentum of the ball on the ground is

        I = 21 N s

(a)The force that the foot applied on the ball will be 175 N.

(b)The impulse experienced by the rock during its fall will be 21 Ns.

The change in momentum of an item when it is operated upon by a force for a period of time is known as an impulse.Impulse is given by the change in momentum,

I=ΔP

The given data in the question will be

m is the mass of soccer ball = 1.00 kg

u is the velocity by which ball hits =5.00 m/sec

v is the velocity by which ball rebounds=8.50 m/sec.

(a) The force that the foot applied on the ball will be 175 N.

If the ball rebounds  with the the velocity of 8.50m/sec then

\(\rm F= \frac{m(v-u)}{t} \\\\\rm F= \frac{1(8.50-5.00)}{2.00\times10^{-2}}\\\\\rm F=175 N\)

Hence the force that the foot applied on the ball will be 175 N.

(b)The impulse experienced by the rock during its fall will be 21 Ns.

According to Newton's third equaton of motion.

\(\rm v^2=u^2+2gh\\\\\rm v^2=2\times9.81\times10.0\\\\\rm v=\sqrt{2\times9.81\times10.0} \\\\\rm v= 14.0071 m/sec\)

Due to the free fall condition the initial velocity is zero,

Impulse is given by the change in momentum,

I=ΔP

I=m(v-u)

\(\rm I=m(v-u)\\\\\rm I=1.50(14.0-0)\\\\\rm I=21 Ns\)

Hence the impulse experienced by the rock during its fall will be 21 Ns.

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Explanation: galaxy

Answer:

I guess the answer is c the f am not wrong

Answer:

0.5m

Explanation:

v=f×lamda

v is 300m/s, f is 600Hz, lamda is ?

lamda=v/f

lamda=300/600

lamda =3/6=1/2m

Answer:

(a) The acceleration oF the car is \(-1764.7 m/s^2\) or -180.1 g’s.

(b) The magnitude of the force on the driver's body is 123529 Newtons

Explanation:

Given that:

The initial velocity of the car before the impact, u=172.8 km/h

Or, \(u =172.8 \times \frac {1000}{3600} m/s= 48m/s\)

As the car came to a complete stop after the collision, so the final velocity of the car, v=0.

The time required to stop the car completely, \(t=2.72\times 10^{-2} s\)

(a) Assuming the acceleration is constant, so

Acceleration, \(a= (v-u)/t\)

So, \(a=\frac {0-48}{2.72\times 10^{-2}}=-1764.7 m/s^2\)

Now, expressing the acceleration in the unit od "g's",

\(a=-1764.7\times \frac{g}{g} \\\\\Rightarrow a=-1764.7 \;m/s^2\times \frac{g}{9.8\; m/s^2} \\\\\Rightarrow a=-180.1 g\)

Hence, the acceleration od the car is -1764.7 \(m/s^2\) or -180.1 g’s.

(b) Mass of the driver of the car, m=70.0 kg

The acceleration of the body of the driver is the same as the acceleration of the car.

So, the acceleration faced by the driver, \(a= -1764.7 m/s^2\)

As forec = mass x acceleration, so

The force on the driver's body = 70 x (-1764.7)= -123529 Newtons.

The negative sign means the force is in the opposite direction of the direction of motion of the car.

Hence, the magnitude of the force on the driver's body is 123529 Newtons

A subtype discriminator is the attribute in the supertype entity that determines to which entity subtype each supertype occurrence is related. Option (a) is correct.

The entity supertype is a concept in a database schema that represents a group of entities that share the same attributes or characteristics. A subtype is a subset of entities that possess specific distinguishing characteristics or attributes that are not present in the supertype. A subtype will have at least one different attribute or relationship, apart from all of the characteristics that the supertype contains.

A subtype is a refinement of a supertype entity. An entity type, known as the supertype, has multiple subtypes that can be derived from it. Subtypes may be exclusive (disjoint) or nonexclusive (overlapping). Exclusive subtypes contain nonoverlapping entities, whereas nonexclusive subtypes have overlapping entities.

Supertype and subtype entities can be used in conjunction with the entity-relationship model. A subtype is a distinct entity that has one or more attributes that are specific to it but not present in its supertype. The subtype of an entity is said to be derived from its supertype by extension or specialization.

Therefore, option (a) is correct.

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Sediment near mid-ocean ridges is thinner, younger, more volcanic in composition, and coarser in grain size than sediment that is farther away.

Sediment that is closer to a mid-ocean ridge is younger and less compacted compared to sediment that is farther away.

This is because the sediment closer to a mid-ocean ridge has been recently deposited, while sediment farther away has had more time to compact and solidify.

Sediment is any particulate matter that has accumulated over time as a result of various geological and biological processes. Weathering and erosion of rocks on land, as well as volcanic activity and hydrothermal vents on the ocean floor, can all contribute to sediment formation. Sediments may be transported by wind, water, or ice and deposited in various locations throughout the planet's surface.

A mid-ocean ridge is a long, underwater mountain range that runs through the world's oceans. It is created by the movement of tectonic plates, which are the massive, slowly moving slabs of rock that make up the Earth's outer shell.

When two plates pull apart, magma rises from the mantle and cools, forming new oceanic crust. As this process continues, the new crust pushes the existing crust outwards, creating a ridge. Sediment is often found near mid-ocean ridges because of the volcanic activity that occurs in these areas.

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The EGC for a flexible metal conduit connection to a motor supplied with a 20A circuit is a 12 AWG copper conductor.

The EGC (Equipment Grounding Conductor) for a flexible metal conduit connection to a motor supplied with a 20A circuit is determined by the sizing requirements of the NEC (National Electrical Code). The NEC specifies the minimum size of the EGC based on the size of the circuit conductors and the type of conduit used.

To determine the minimum size of the EGC, we need to consult the NEC Table 250.122, which provides the minimum size of the EGC based on the size of the circuit conductors.

Since the circuit is supplied with a 20A current, we will assume that the circuit conductors are sized accordingly. According to the NEC Table 310.15(B)(16), a 20A circuit typically uses a 12 AWG copper conductor.

Next, we need to determine the type and size of the flexible metal conduit used for the connection. Different types of conduits have different requirements for the EGC sizing. For instance, for a flexible metal conduit, the NEC Table 250.122 specifies that a 12 AWG copper conductor should be used if the conduit is 3/4" or smaller.

Therefore, based on the information provided, the EGC for a flexible metal conduit connection to a motor supplied with a 20A circuit is a 12 AWG copper conductor.

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Answer:

72 N

Explanation:

Applying,

F = (m'+m)a..................... Equation 1

Where F = Force, m' = First mass, m = second mass, a = acceleration.

From the question,

m' = 2 kg, m = 4 kg, a = 12 m/s²

Substitute these values into equation 1

F = 12(2+4)

F = 12×6

F = 72 N

Answer:

X is ammeter and Y is voltmeter

Explanation:

The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.

Ammeter is a measuring instrument used to measure the current in a circuit by connecting the meter in series with the circuit.

Ammeter is a measuring instrument used to measure the potential difference between two points by connecting the meter in parallel to the points.

Meter X is an ammeter since it is connected in series and meter Y is a voltmeter because it is connected in parallel.

The pressure also doubled when the temperature did. answer P2=2atm.

According to Gay-Lussac Law, pressure and temperature have a direct relationship: P1/T1=P2/T2.

As long as the volume is kept constant, pressure and temperature will both rise or fall together.

The pressure would also double if the temperature did. The energy of the molecules would grow with increased temperature, and more collisions would occur, increasing pressure.

Double the temperature of a sample of gas that is at STP 1 atm and 273 K.

1atm/273K=P₂/546K\sP₂=2atm

The pressure increased by the same factor as the temperature.

Everything we eat, drink, or use contains energy. The fundamental body functions of the body are powered and governed by energy.

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The pressure put on the ground by trains has decreased by a ratio of 62.5.

The n + x is used to represent sleeper density. The number of sleepers needed for one rail length is shown by the symbol n + x in this case. A rail's length is given by n. The necessary number of sleepers is 17 13 multiplied by 1000, which comes to 1307.69 x 1308 Numbers.

It is the quantity of sleepers necessary to support a rail-length of railroad track. Its formula is (n + x), where n is the length of a rail in meters and x is a constant with a range of 3 to 6 (the length of a rail for broad gauge (B.G.) track is 13 meters, while that for meter gauge (M.G.) track is 12 meters).

2.5 * 25 = 62.5.

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The linear function expressing pressure (p) as a function of depth (d) is: p = 0.03d + 1. The pressure at a depth of 660 ft is approximately 20.8 atm.

a) To find a linear function that expresses pressure as a function of depth, we can use the given data points (depth, pressure) = (100 ft, 4 atm) and (200 ft, 7 atm).

Let's denote the depth as "d" and the pressure as "p". We can set up a linear equation in the form p = mx + b, where m represents the rate of change of pressure with respect to depth, and b is the y-intercept.

Using the two data points, we can find the slope (m) as:

m = (change in pressure) / (change in depth)

= (7 atm - 4 atm) / (200 ft - 100 ft)

= 3 atm / 100 ft

= 0.03 atm/ft

Substituting one of the data points (100 ft, 4 atm) into the linear equation, we can find the y-intercept (b):

4 atm = 0.03 atm/ft * 100 ft + b

b = 4 atm - 3 atm

b = 1 atm

Therefore, the linear function expressing pressure (p) as a function of depth (d) is:

p = 0.03d + 1

b) To determine the pressure at a depth of 660 ft using the function from part (a), we substitute d = 660 ft into the equation:

p = 0.03 * 660 + 1

p = 19.8 + 1

p ≈ 20.8 atm

Thus, the pressure at a depth of 660 ft is approximately 20.8 atm.

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Answer:

Mechanical energy is the ordered movement of the molecules as a single unit. Thermal energy is the random movement of the molecules. Mechanical energy can be 100% converted to thermal energy, but thermal energy cannot be fully converted to mechanical energy.

A&L Engineering, as an engineer, you've been tasked with evaluating the durability of three common materials used in the design of cell phone cases.

These materials include:Carbon FiberPolycarbonateTPUExplanation:Carbon fiber is a lightweight, durable, and corrosion-resistant composite material. It is often used in the aerospace, automotive, and sporting goods industries.Polycarbonate is a thermoplastic polymer that is strong, shatter-resistant, and lightweight. It is often used in the production of CDs, DVDs, and eyeglass lenses.

TPU (thermoplastic polyurethane) is a flexible, soft material that is abrasion-resistant and provides excellent impact protection. It is often used in the production of phone cases, as well as sporting equipment and medical devices.To evaluate the durability of these materials, you can conduct a series of tests to measure their resistance to impacts, scratches, and bending.

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Answer:

A is correct!

Explanation:

e2020

Answer:

a

Explanation:

right on edge :)

Answer:

The influx of Ca2+ triggers the release of neurotransmitters stored in synaptic vesicles (B) by exocytosis.

hope this helps.

Answer:

Initial momentum: \(0\; {\rm kg \cdot m \cdot s^{-1}}\).

Final momentum: \(150\; {\rm kg \cdot m\cdot s^{-1}}\).

Force on the mass (assuming that the force is constant): \(75\; {\rm N}\).

Impulse on the mass: \(150\; {\rm kg \cdot m \cdot s^{-1}}\).

Explanation:

The momentum \(p\) of an object is equal to the product of mass \(m\) and velocity (a vector) \(v\).

The initial momentum of this mass was \(0\; {\rm kg \cdot m \cdot s^{-1}}\) since the velocity of this object was initially \(0\; {\rm m\cdot s^{-1}}\).

At \(v = 3\; {\rm m\cdot s^{-1}}\), the momentum of this mass (\(m = 50\; {\rm kg}\)) would be:

\(\begin{aligned}p &= m\, v \\ &= 50\; {\rm kg} \times 3\; {\rm m\cdot s^{-1}} \\ &= 150\; {\rm kg \cdot m \cdot s^{-1}}\end{aligned}\).

Assume that the external force \(F\) on this mass is constant. By Newton's Second Law of motion, the external force on this mass would be equal to the rate of change in the momentum of this mass.

Since the momentum of this mass increased by \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\) in \(\Delta t = 2\; {\rm s}\), the external force on this mass would be:

\(\begin{aligned}F &= \frac{\Delta v}{\Delta t} \\ &= \frac{150\; {\rm kg \cdot m \cdot s^{-1}}}{2\; {\rm s}} \\ &= 75\; {\rm kg \cdot m \cdot s^{-2}} \\ &= 75\; {\rm N}\end{aligned}\).

The impulse of an external force on an object is equal to the change in the momentum of that object. Since the change in momentum of this mass was \(\Delta v = 150\; {\rm kg \cdot m \cdot s^{-1}}\), the corresponding impulse would also be \(150\; {\rm kg \cdot m\cdot s^{-1}}\):

\(\begin{aligned}J &= \Delta v \\ &= 150\; {\rm kg \cdot m\cdot s^{-1}} \\ &= 150\; {\rm N \cdot s}\end{aligned}\).

Answer:

F=200 N

a=10m/s2

F=ma

m=F/a=200/10=20m

Explanation:

(a) For constructive interference the two waves will have higher amplitude of 10 cm.

(b) For destructive interference the two waves will have zero amplitude.

For constructive interference the two waves will have higher amplitude after constructive interference.

Resulting amplitude = 5 cm + 5cm = 10 cm

For destructive interference the two waves will have zero amplitude after destructive interference.

Resulting amplitude = 5 cm - 5cm = 0

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