(Geometry)
I need help on #4 and #11, 12 and 13 please

Answer

If my answer is ok for you rate my answer

Answer:

-5 and -10

Step-by-step explanation:

-9-5(-5)

-9+25

=16

-9-5(-10)

-9+50

=41

The simplified sum of the expression ∑+1=−1 (2 − 1) is 2.

The given expression is the sum of (2 - 1) from i = -1 to n, where n = 1. Therefore, the expression can be simplified as follows:

∑+1=−1 (2 − 1) = (2 - 1) + (2 - 1) = 1 + 1 = 2

In this case, the value of n is 1, which means that the summation will only be performed for i = -1. The expression inside the summation is (2 - 1), which equals 1. Thus, the summation is equal to 1.

Adding 1 to the result of the summation gives:

∑+1=−1 (2 − 1) + 1 = 1 + 1 = 2

Therefore, the simplified sum of the expression ∑+1=−1 (2 − 1) is 2.

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Answer:

P is the independent variable, where as S is dependent on P

Answer:

how you doing

Step-by-step explanation:

Answer:

zxedrfcevrhybtjuyinkmu,l

Step-by-step explanation:

In this triangle, the product of tan A and tan C is `(BC)^2/(AB)^2`.

The given triangle ABC has angle A measuring 45 degrees, angle B measuring 90 degrees, and angle C measuring 45 degrees , Answer: `(BC)^2/(AB)^2`.

We have to find the product of tan A and tan C.

In triangle ABC, tan A and tan C are equal as the opposite and adjacent sides of angles A and C are the same.

So, we have, tan A = tan C

Therefore, the product of tan A and tan C will be equal to (tan A)^2 or (tan C)^2.

Using the formula of tan: tan A = opposite/adjacent=BC/A Band, tan C = opposite/adjacent=AB/BC.

Thus, tan A = BC/AB tan C = AB/BC Taking the ratio of these two equations, we have: tan A/tan C = BC/AB ÷ AB/BC Tan A * tan C = BC^2/AB^2So, the product of tan A and tan C is equal to `(BC)^2/(AB)^2`.

Answer: `(BC)^2/(AB)^2`.

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Answer:

11

Step-by-step explanation:

You add the 2 ones side by side and you get 11

The function is a quadratic function, and the standard form of a quadratic function is ax^2 + bx + c

The standard form of the function \(\mathbf{f(x) = (x - 2)^2 - 3}\) is \(\mathbf{f(x) = x^2 - 4x + 1}\)

The function is given as:

\(\mathbf{f(x) = (x - 2)^2 - 3}\)

Factor out (x - 2)^2

\(\mathbf{f(x) = (x - 2)(x - 2) - 3}\)

Expand the expression

\(\mathbf{f(x) = x^2 - 2x -2x + 4 - 3}\)

Simplify the like terms i.e. add -2x and -2x

\(\mathbf{f(x) = x^2 - 4x + 4 - 3}\)

Simplify the like terms i.e. add 4 and -3

\(\mathbf{f(x) = x^2 - 4x + 1}\)

Hence, the standard form of the function \(\mathbf{f(x) = (x - 2)^2 - 3}\) is \(\mathbf{f(x) = x^2 - 4x + 1}\)

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Answer:

the one above is all right except its a positive 4x, the question was

f(x) = (x + 2)2 - 3

not

f(x) = (x - 2)2 - 3

the real answer is: f(x) = x^2+4x+1

Extra people required is 50.

Each of the five workers should increase their efficiency to a rate of 15 sandwiches per 10 hour shift.

Proportions are defined as the concept where two or more ratios are set to be equal to each other.

Question 1 :

Number of associates = 30

Number of direct workers = 30 - 2 = 28

You work 8 hours a day and 5 days a week with two 15 minutes break or 30 minutes break per day.

Direct rate = 150 units per hour

Number of working hours in a week with break = 8 × 5 = 40 hours per week Number of working hours in a week = 7.5 hours per day × 5 days a week

                                                            = 37.5 hours per week

Units that department produce in a 40 hour week = 37.5 × 150 = 5625 units

28 people produce 5625 units in a week

Let x people produce 10,000 + 5625 = 15,625 units in a week

Using proportion,

28 : 5625 = x : 15,625

28 / 5625 = x / 15,625

x = (28 × 15,625) / 5625 = 77.78 ≈ 78

Extra people required = 78 - 28 = 50

Question 2 :

Number of sandwiches made in 10 minutes = 1

Number of sandwiches made in 10 hours = 60

5 workers are there. one worker makes 60/5 = 12 sandwiches

But Deli want number of sandwiches in 10 hours = 75

One worker should make 75/5 = 15 sandwiches instead of 12.

Number of sandwiches made in 8 minutes should be 1.

So the working efficiency on each worker should be increased and produce each one should produce 15 sandwiches in a 10 hour shift.

Hence extra people required in question 1 is 50 and efficiency of each worker in question 2 should be increased to 15 sandwiches in 10 hours shift.

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It is true that the population mean can be used to refer to the expected value of a random variable X.

The anticipated value of a random variable in probability theory is the long-run average of all iterations of the experiment.

The expected value in rolling a six-sided die is 3.5, since the average of all the numbers that come up will approach 3.5 as the number of rolls approaches infinity. An expected value is a key aspect of many decision-making situations, including gambling, insurance, and stock evaluation. The expected value can also be referred to as the population mean.

The statement "The expected value of a random variable X can be referred to as the population mean" is therefore accurate.

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B (23x5)-s

1) Gathering the data:

5 6th grade classes of 23 students

S= absent students

2) Since S represent the absent students. The question is How many went to the museum.

Then the expression that represents the absent students

is

5 classes of 23 students:

(23 x 5)

Minus the number of absent students, so:

(23x5)-s

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

\(2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\)

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

\((\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1\)

Answer: the lower limit is 1.555g and the upper limit is 1.564g

Step-by-step explanation:

a mg is:

1mg = 0.001g

Then we need to look at the third digit after the decimal point.

Then the weight 1.56g is rounded around this.

Remember that if the third digit after the decimal point is 5 or bigger, then we round up.

if the third digit is smaller than 5, then we round down.

Now, the maximum possible value of this weight is when the third digit is equal to 4 (4 mg) where because it is smaller than 5, we round it down to 1.56g

Then the maximum is 1.564g

And the minimum value is when we have:

w = 1.555g

Because the third digit is a 5, we round it up to 1.56g.

So the lower limit is 1.555g and the upper limit is 1.564g

Answer:

can you plz rewrite the question I want to help but I can't see it. you can even take a picture of the question.

Answer:

y 7

= =0

x x0

2 2-+x/

− 0-

16 16+x-/

x 0 0x

+  0+

39 8

Step-by-step explanation:

The four criteria that can be used to prove triangles are congruent and can be used to prove the triangles are congruent.

Triangle congruence: Two triangles are said to be congruent if all three of their corresponding sides and all three of their corresponding angles have the same measurements. These triangles can be moved around, rotated, flipped, and turned to have a same appearance. They match up with one another when moved.

The four criteria that can be used to prove triangles are congruent are SAS (Side-Angle-Side), ASA (Angle-Side-Angle), AAS (Angle-Angle-Side), and SSS (Side-Side-Side). Additionally, CPCTC (Corresponding Parts of Congruent Triangles are Congruent) can be used to prove the triangles are congruent.

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Answer:

-3

Step-by-step explanation:

Colin has lived by the biblical ideal of avoiding debt, purchasing the lowest item, repaying a loan, and being financially honest.

With an auto loan, you may borrow money from a bank and use it to purchase a vehicle. The loan must be repaid with interest over a defined period of time in fixed instalments from you.

Lenders will aim for a credit score of at least 750 when you apply for a vehicle loan.

The additional costs won't dramatically raise the price of the automobile because of the low interest rate. The periodic payments won't put undue strain on your current or next finances.

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If we evaluate at infinity, we get the following:

                  \(\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{7x - 1}{\sqrt[3]{5x^3 + 4x - 2}}} = \frac{\infty}{\infty} \end{gathered}$}\)

Which is an indeterminacy of ∞ / ∞. Therefore, we must multiply and divide by the highest degree monomial (either in numerator or denominator). In this case it is 1/x—since the denominator involves a cube root, then the "monomial" x³ is considered to be a monomial of degree 1—. So:

                    \(\large\displaystyle\text{$\begin{gathered}\sf L= \lim_{x \to \infty}\frac{7x-1 }{\sqrt[3]{5x^3+4x-2 } }\cdot\frac{\frac{1}{x} }{\frac{1}{x} } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \ \ = \lim_{x \to \infty}\frac{\frac{7x}{x}-\frac{1}{x } }{\sqrt[3]{\frac{5x^3}{ x^{3} }+\frac{4x}{x^{3} }-\frac{2}{x^{3} } } } \end{gathered}$}\\\)

                       \(\large\displaystyle\text{$\begin{gathered}\sf \ \ = \lim_{x \to \infty}\frac{7-\frac{1}{x} }{\sqrt[3]{ 5+\frac{4 }{x^{2} } -\frac{2}{x^{3} } } } \end{gathered}$}\)

That when "evaluating at infinity" we have:

\(\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{7 - \frac{1}{x}}{\sqrt[3]{5 + \frac{4}{x^2} - \frac{2}{x^3}}}} = \frac{7 - 0}{\sqrt[3]{5 + 0 - 0}} = \frac{7}{\sqrt[3]{5}} \end{gathered}$}\)

Answer:

x = 2.36603 or 0.633975

Step-by-step explanation:

Here we want to solve the quadratic equation using the completing the square method.

2x^2-6x + 3 = 0

divide through by 2 first;

x^2 -3x + 3/2 = 0

x*2 -3x = -3/2

Half the x term will be -3/2 and squaring it is 9/4

we add this to both sides

x^2-3x/2 + 9/4 = -3/2 + 9/4

(x-3/2)^2 = 3/4

Finding square root of both sides

x-3/2 = √(3/4)

x = 3/2 ± √(3/4)

x = 3/2 + √(3/4) or x = 3/2-√(3/4)

which becomes

x = 2.36603 or 0.633975

Answer:

~ 340

Step-by-step explanation:

A = pi * r^2

The big circle is r1 = 12cm so the small r2=6cm

A= A1 - A2 = (pi * r1^2)-( pi*r2^2) = 339,29 ~ 340 square cm

If the radius of the small circle is 12cm then: r1 = 24cm and r2 = 12cm and calculate it the same way

The present value of the sequence of annual payments of Rs 25000 each, the first being made at the end of the 5th year and the last being paid at the end of the 12th year, if money is worth 6% is Rs. 158620.39.

1: We can use the formula to calculate the present value of the annuity:

P = A x [1 - (1+i)^-n] / i

Where

P = Present Value

A = Annuity

i = Interest Raten = Number of payments

2: Calculate the present value of each payment using the formula:

P1 = 25000 / (1.06)⁵

P2 = 25000 / (1.06)⁶

P3 = 25000 / (1.06)⁷

P4 = 25000 / (1.06)⁸

P5 = 25000 / (1.06)⁹

P6 = 25000 / (1.06)¹⁰

P7 = 25000 / (1.06)¹¹

P8 = 25000 / (1.06)¹²

3: Substitute the values into the formula to find the present value:

P = P1 + P2 + P3 + P4 + P5 + P6 + P7 + P8

P = (25000 / (1.06)⁵) + (25000 / (1.06)⁶) + (25000 / (1.06)⁷) + (25000 / (1.06)⁸) + (25000 / (1.06)⁹) + (25000 / (1.06)¹⁰) + (25000 / (1.06)¹¹) + (25000 / (1.06)¹²)

P = 158620.39

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The amount of the remittance from ABC is $1,960.

The given information states that merchandise is sold for $2,000 with terms of 2/10, n/30 to ABC. The terms 2/10, n/30 imply a 2% discount if payment is made within 10 days, with the full amount due within 30 days.

Since ABC sends a remittance on Dec. 26, it means the payment is made after the discount period but within the credit period. Therefore, ABC is not eligible for the discount of 2%.

To calculate the amount of the remittance, we simply subtract the discount from the total amount. In this case, the discount is $2,000 * 2% = $40. Thus, the remittance amount is $2,000 - $40 = $1,960.

In conclusion, the amount of the remittance from ABC is $1,960, as they did not qualify for the early payment discount.

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Answer:

12x²-2/14x²-9

Step-by-step explanation:

Since the denominators are the same you can ignore them.

9x²+3- (-3x²)+5

Simplyfies to 12x²-2

\(\bold{\text{Answer:}\quad \dfrac{2(6x^2-1)}{14x^2-9}}\)

Step-by-step explanation:

\(.\quad \dfrac{9x^2+3}{14x^2-9}-\dfrac{-3x^2+5}{14x^2-9}\\\\\\=\dfrac{9x^2+3}{14x^2-9}+\dfrac{-(-3x^2+5)}{14x^2-9}\\\\\\=\dfrac{9x^2+3}{14x^2-9}+\dfrac{3x^2-5}{14x^2-9}\\\\\\=\dfrac{9x^2+3+3x^2-5}{14x^2-9}\\\\\\=\dfrac{12x^2-2}{14x^2-9}\\\\\\=\large\boxed{\dfrac{2(6x^2-1)}{14x^2-9}}\)

Answer:

\(\frac{2}{7}\)

Step-by-step explanation:

Triangle ABC is similar to triangle DEC, because all angles in one triangle are equal to angles in the other triangle.

That means that corresponding sides have the same ratio. Side AB and side DE are corresponding sides. Since there are no unknowns we can calculate the ratio (scale factor).

Since we are looking for scale factor of triangle DEC to triangle ABC, we put side AB (which is in triangle ABC) in the numerator.

\(\text{scale factor} = \frac{\text{AB}}{\text{DE}} = \frac{6}{21} = \frac{2}{7}\)

I've marked corresponding sides and angles in the attached picture.

Answer:

Step-by-step explanation:

the answer is No its not similar

because the factors don't work

The value of the Test Statistic for this hypothesis test under the given condition round Z to the 100ths place is 1.96.

in the case of finding out that if Gingko is effective in improving short term memory we need to use hypothesis test considering there are two possibilities in null hypothesis

Ha: μ1 = μ2 ----( there is no difference measured between means of two groups)

Hb: μ1 ≠μ2 ------( there is difference measured between means of two groups)

formula for this test statistics is

\(Z = (x'1 - x'2) / \sqrt{(s1^2/n1 + s2^2/n2)}\)

here,

x'1 and x'2 = sample means

s1 and s2 = sample standard deviation

n1 and n2 = sample sizes

hence, the values are

x'1 = 6.1

x'2 = 5.6

s1 = 1.2

s2 = 1

n1 = 100

n2 = 105

staging the values in the given equation

\(Z = (6.1 - 5.6) / \sqrt{(1.2^2/100 + 1^2/105) }\)

≈ 1.96

The value of the Test Statistic for this hypothesis test under the given condition round Z to the 100ths place is 1.96.

Hence the value is greater than of z at α/2 = 0.025 we conclude that Gingko is effective in improving short term memory. so the supplements are effective.

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