Answer:
D. 51
Step-by-step explanation:
If UVW is congruent to EFC then FEC must be congruent to VUW
VUW= 51 so FEC= 51
The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.
Given that, ΔUVW≅ΔEFC.
What is the congruence theorem?Triangle congruence theorem or triangle congruence criteria help in proving if a triangle is congruent or not. The word congruent means exactly equal in shape and size no matter if we turn it, flip it or rotate it.
From the given triangle UVW, the measure of ∠U=51° and ∠W=82°.
We know that, the corresponding parts of congruent triangle are equal.
Here, ∠FCE=∠W=82°
∠FEC=∠U=51°
The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.
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Example A marksman takes 10 shots at a target and has probability 0.2 of hitting the target with each shot, independently of all other shots. Let X be the number of hits. (a) Calculate and sketch the PMF of X (b) Whai is the probabillity of scoring no hits? (c) What is the probability of scoring more hits than misses? (d) Find the expectation and the variance of X. (e) Suppose the marksman has to pay $3 to enter the shooting range and he gets $2 for each hit. Let Y be his profit. Find the expectation and the variance of Y (f) Now let's assume that the marksman enters the shooting range for free and gets the number of dollars that is equal to the square of the number of hits. let Z be his profit. Find the expectation of Z
a) PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
b) The probability of scoring no hits is the probability of X being 0.
c) The probability of scoring more hits than misses is the probability of X being greater than 5
d) E(X) = 10 * 0.2 and Var(X) = 10 * 0.2 * (1 - 0.2).
e) The expectation of Y: E(Y) = E(2X - 3) = 2E(X) - 3
The variance of Y: Var(Y) = Var(2X - 3) = 4Var(X)
f) The expectation of Z: E(Z) = E(X²)
What is probability?
Probability is a measure or quantification of the likelihood of an event occurring. It is a numerical value assigned to an event, indicating the degree of uncertainty or chance associated with that event. Probability is commonly expressed as a number between 0 and 1, where 0 represents an impossible event, 1 represents a certain event, and values in between indicate varying degrees of likelihood.
(a) To calculate the Probability Mass Function (PMF) of X, we can use the binomial distribution formula. Since the marksman takes 10 shots independently with a probability of 0.2 of hitting the target, the PMF of X follows a binomial distribution with parameters n = 10 (number of trials) and p = 0.2 (probability of success):
PMF of \(X(x) = C(n, x) * p^x * (1 - p)^{(n - x)}\)
Where C(n, x) represents the number of combinations or "n choose x."
Let's calculate the PMF for each value of X from 0 to 10:
PMF of X(0) = C(10, 0) * (0.2)⁰ * (0.8)¹⁰
PMF of X(1) = C(10, 1) * (0.2)¹ * (0.8)⁹
PMF of X(2) = C(10, 2) * (0.2)² * (0.8)⁸
...
PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
(b) The probability of scoring no hits is the probability of X being 0. So we calculate PMF of X(0):
PMF of X(0) = C(10, 0) * (0.2)⁰ * (0.8)¹⁰
(c) The probability of scoring more hits than misses is the probability of X being greater than 5. We need to calculate the sum of PMF of X from X = 6 to X = 10:
PMF of X(6) + PMF of X(7) + PMF of X(8) + PMF of X(9) + PMF of X(10)
(d) The expectation (mean) of X can be found using the formula:
E(X) = n * p
where n is the number of trials and p is the probability of success. In this case, E(X) = 10 * 0.2.
The variance of X can be calculated using the formula:
Var(X) = n * p * (1 - p)
In this case, Var(X) = 10 * 0.2 * (1 - 0.2).
(e) To calculate the expectation and variance of Y, we need to consider the profit from each hit. Each hit earns $2, and since X represents the number of hits, Y can be calculated as:
Y = 2X - 3
The expectation of Y can be calculated as:
E(Y) = E(2X - 3) = 2E(X) - 3
To calculate the variance of Y, we can use the property Var(aX + b) = a²Var(X) when a and b are constants:
Var(Y) = Var(2X - 3) = 4Var(X)
(f) Similarly, for Z, each hit earns a dollar amount equal to the square of the number of hits:
Z = X²
The expectation of Z can be calculated as:
E(Z) = E(X²)
Hence, a) PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
b) The probability of scoring no hits is the probability of X being 0.
c) The probability of scoring more hits than misses is the probability of X being greater than 5
d) E(X) = 10 * 0.2 and Var(X) = 10 * 0.2 * (1 - 0.2).
e) The expectation of Y: E(Y) = E(2X - 3) = 2E(X) - 3
The variance of Y: Var(Y) = Var(2X - 3) = 4Var(X)
f) The expectation of Z: E(Z) = E(X²)
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a) PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
b) The probability of scoring no hits is the probability of X being 0.
c) The probability of scoring more hits than misses is the probability of X being greater than 5
d) E(X) = 10 * 0.2 and Var(X) = 10 * 0.2 * (1 - 0.2).
e) The expectation of Y: E(Y) = E(2X - 3) = 2E(X) - 3
The variance of Y: Var(Y) = Var(2X - 3) = 4Var(X)
f) The expectation of Z: E(Z) = E(X²)
What is probability?
Probability is a measure or quantification of the likelihood of an event occurring. It is a numerical value assigned to an event, indicating the degree of uncertainty or chance associated with that event. Probability is commonly expressed as a number between 0 and 1, where 0 represents an impossible event, 1 represents a certain event, and values in between indicate varying degrees of likelihood.
(a) To calculate the Probability Mass Function (PMF) of X, we can use the binomial distribution formula. Since the marksman takes 10 shots independently with a probability of 0.2 of hitting the target, the PMF of X follows a binomial distribution with parameters n = 10 (number of trials) and p = 0.2 (probability of success):
PMF of
Where C(n, x) represents the number of combinations or "n choose x."
Let's calculate the PMF for each value of X from 0 to 10:
PMF of X(0) = C(10, 0) * (0.2)⁰ * (0.8)¹⁰
PMF of X(1) = C(10, 1) * (0.2)¹ * (0.8)⁹
PMF of X(2) = C(10, 2) * (0.2)² * (0.8)⁸
......
PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
(b) The probability of scoring no hits is the probability of X being 0. So we calculate PMF of X(0):
PMF of X(0) = C(10, 0) * (0.2)⁰ * (0.8)¹⁰
(c) The probability of scoring more hits than misses is the probability of X being greater than 5. We need to calculate the sum of PMF of X from X = 6 to X = 10:
PMF of X(6) + PMF of X(7) + PMF of X(8) + PMF of X(9) + PMF of X(10)
(d) The expectation (mean) of X can be found using the formula:
E(X) = n * p
where n is the number of trials and p is the probability of success. In this case, E(X) = 10 * 0.2.
The variance of X can be calculated using the formula:
Var(X) = n * p * (1 - p)
In this case, Var(X) = 10 * 0.2 * (1 - 0.2).
(e) To calculate the expectation and variance of Y, we need to consider the profit from each hit. Each hit earns $2, and since X represents the number of hits, Y can be calculated as:
Y = 2X - 3
The expectation of Y can be calculated as:
E(Y) = E(2X - 3) = 2E(X) - 3
To calculate the variance of Y, we can use the property Var(aX + b) = a²Var(X) when a and b are constants:
Var(Y) = Var(2X - 3) = 4Var(X)
(f) Similarly, for Z, each hit earns a dollar amount equal to the square of the number of hits:
Z = X²
The expectation of Z can be calculated as:
E(Z) = E(X²)
Hence, a) PMF of X(10) = C(10, 10) * (0.2)¹⁰ * (0.8)⁰
b) The probability of scoring no hits is the probability of X being 0.
c) The probability of scoring more hits than misses is the probability of X being greater than 5
d) E(X) = 10 * 0.2 and Var(X) = 10 * 0.2 * (1 - 0.2).
e) The expectation of Y: E(Y) = E(2X - 3) = 2E(X) - 3
The variance of Y: Var(Y) = Var(2X - 3) = 4Var(X)
f) The expectation of Z: E(Z) = E(X²)
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what is the quotient of the expression
\( \frac{21a {}^{3} b - 14ab {}^{2} + 7ab}{7ab} \)
The diagonal AC is drawn in parallelogram ABCD Which method can NOT be used to prove that AABC is congruent to ACDA?
AASA
B SSA
C SAS
DSSS
Answer:
B SSA
Step-by-step explanation:
Geometric proofs can be used to show that the two triangles are congruent using ASA, SAS and SSS.
However, there is no such thing as SSA in geometry because an angle and two sides can not show congruence of triangles. This is so because the angle is not an included angle.
suppose you have a function of two variables, nand k; for instance h(n, k).if you are told that h(n, k)
Given a function of two variables, n and k, denoted as h(n, k), the function describes a mathematical relationship or operation that depends on the values of both n and k. Further details about the specific function, its definition, or purpose are required to provide a more comprehensive explanation.
A function of two variables, h(n, k), typically represents a mathematical relationship or operation that involves two independent variables, n and k. The specific form and purpose of the function can vary widely depending on the context or problem at hand.
To understand the behavior and properties of the function h(n, k), additional information is needed. This may include the mathematical expression defining the function, any constraints or conditions on the variables, and the intended interpretation or application of the function.
The function h(n, k) could represent various scenarios, such as a cost function in economics, a probability distribution in statistics, or a mathematical model in a scientific context. Without more details, it is challenging to provide a specific explanation or analysis of the function and its implications.
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I also need help with 1,000,000 in exponential form , 10x10 , and 10,000 x10 please
Answer:
Step-by-step explanation:
To convert the value 1,000,000 to an exponential form means we are to write the value in multiples of 10. Breaking down the values in multiples of 10 will give;
1,000,000 = 10 * 10 * 10 * 10 * 10 * 10 (it is broken down into 6 places because the value contains 6 zeros)
Express in exponential form
1,000,000 = (10 * 10 * 10) * (10 * 10 * 10)
1,000,000 = (10³) * (10³)
1,000,000 = 10³⁺³
1,000,000 = 10⁶
Hence the value 1,000,000 in exponential form is expressed as 1 * 10⁶
For 10 * 10:
10 * 10 = 10¹ * 10¹
10 * 10 = 10¹⁺¹
10 * 10 = 10²
10 * 10 = 1 * 10²
The value of the expression 10*10 in exponential form is 1 * 10²
For 10,000 * 10:
10,000 * 10 = (10*10*10*10) * 10
10,000 * 10 = (10⁴) * 10¹
10,000 * 10 = 10⁴⁺¹
10,000 * 10 = 1 * 10⁵
Hence, The value of the expression 10000*10 in exponential form is 1 * 10⁵
Triangle JKL has vertices J(−3, 2), K(1, −3), and L(3, 1). If the triangle is dilated by a scale factor of 1, what will be the new location of point K?
I need help
Select all that apply.
Which of the following expressions have a quotient of -1?
1/7
(-1)/(-7)
(-1)/7
1/(-7)
Can two different square have equal area?
Answer:
The given statement is true. Reason: Area of a square = side × side Therefore, two squares that have the same area will have sides of the same lengths.
hop this helps
mark me brainliest
Step-by-step explanation:
Carlisle Transport had $4,520 cash at the beginning of the period. During the period, the firm collected $1,654 in receivables, paid $1,961 to supplier, had credit sales of $6,916, and incurred cash expenses of $500. What was the cash balance at the end of the period?
To calculate the cash balance at the end of the period, we need to consider the cash inflows and outflows.
Starting cash balance: $4,520
Cash inflows: $1,654 (receivables collected)
Cash outflows: $1,961 (payments to suppliers) + $500 (cash expenses)
Total cash inflows: $1,654
Total cash outflows: $1,961 + $500 = $2,461
To calculate the cash balance at the end of the period, we subtract the total cash outflows from the starting cash balance and add the total cash inflows:
Cash balance at the end of the period = Starting cash balance + Total cash inflows - Total cash outflows
Cash balance at the end of the period = $4,520 + $1,654 - $2,461
Cash balance at the end of the period = $4,520 - $807
Cash balance at the end of the period = $3,713
Therefore, the cash balance at the end of the period is $3,713.
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Ryan invested \$4,800$4,800 in an account in the year 1990, and the value has been growing exponentially at a constant rate. The value of the account reached \$6,300$6,300 in the year 1998. Determine the value of the account, to the nearest dollar, in the year 2007.
well, from 1990 to 1998 is 8 years, and we know the amount went from $4800 to $6300, let's check for the rate of growth.
\(\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6300\\ P=\textit{initial amount}\dotfill &\$4800\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{years}\dotfill &8\\ \end{cases} \\\\\\ 6300=4800(1 + \frac{r}{100})^{8} \implies \cfrac{6300}{4800}=(1 + \frac{r}{100})^8\implies \cfrac{21}{16}=(1 + \frac{r}{100})^8\)
\(\sqrt[8]{\cfrac{21}{16}}=1 + \cfrac{r}{100}\implies \sqrt[8]{\cfrac{21}{16}}=\cfrac{100+r}{100} \\\\\\ 100\sqrt[8]{\cfrac{21}{16}}=100+r\implies 100\sqrt[8]{\cfrac{21}{16}}-100=r\implies \stackrel{\%}{3.46}\approx r\)
now, with an initial amount of $4800, up to 2007, namely 17 years later, how much will that be with a 3.46% rate?
\(\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &4800\\ r=rate\to 3.46\%\to \frac{3.46}{100}\dotfill &0.0346\\ t=years\dotfill &17\\ \end{cases} \\\\\\ A=4800(1 + 0.0346)^{17} \implies A=4800(1.0346)^{17}\implies A \approx 8558.02\)
PQ= RQ and PS= RS a=?
The measure of angle a is 15 degrees and this can be determined by using the properties of the isosceles triangle.
What are interior angles?In geometry, interior angles are formed in two ways. One is inside a polygon, and the other is when parallel lines cut by a transversal. Angles are categorized into different types based on their measurements.
Given:
The length of the segment PQ is equal to the length of the segment RQ.The length of the segment PS is equal to the length of the segment RS.The following steps can be used in order to determine the measure of angle a:
Step 1 - According to the given data, it can be concluded that triangle PQR and triangle PSR are isosceles triangles.
Step 2 - Apply the sum of interior angle property on triangle PQR.
\(\angle\text{Q}+\angle\text{P}+\angle\text{R}=180\)
\(\angle\text{Q}+2\angle\text{R}=180\)
\(2\angle\text{R}=180-60\)
\(\angle\text{R}=60^\circ\)
Step 3 - Now, apply the sum of interior angle property on triangle PSR.
\(\angle\text{P}+\angle\text{S}+\angle\text{R}=180\)
\(\angle\text{S}+2\angle\text{R}=180\)
\(2\angle\text{R}=180-90\)
\(\angle\text{R}=45^\circ\)
Step 4 - Now, the measure of angle a is calculated as:
\(\angle\text{a}=60-45\)
\(\angle\text{a}=15\)
The measure of angle a is 15 degrees.
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Find Sn for the following geometric sequences described.
From the question, the sum of each of the geometric sequence are;
1) 31 3/4
2) 340
3) 11/16
4) -6, 12, -24
What is geometric sequence?
We have that;
Sn = a(1 -\(r^n\))/1 - r
Sn = 16(1 \(- (1/2)^7\))1 - 1/2
Sn = 16(1 - 1/128)/1/2
Sn = 16(127/128) * 2
Sn = 31 3/4
2) Un = a\(r^n\) -1
256 = \(4(4)^n-1\)
64 =\(4^n-1\)
\(4^3 = 4^n-1\)
n = 4
Sn= \(4(4^4 - 1)\)/4 - 1
Sn = 340
3) Since we have a5 then n = 5
Sn = 1(1 - (\(-1/2)^5\))/1 -(-1/2)
Sn = 33/32 * 2/3
= 11/16
4) 30= a(1 -\((-2)^4\))/1 - (-2)
30 = a(-15)/3
30 = -5a
a = 30/-5
a = -6
Then the first three terms are;
-6, 12, -24
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A young sumo wrestler decided to go on a special high − -protein diet to gain weight rapidly. After 1 1 11 months, he weighed 1 4 0 k i l o g r a m s . 140 kilograms. He gained weight at a rate of 5 . 5 k i l o g r a m s 5.5 kilograms per month. Let y y represent the sumo wrestlers weight ( i n k i l o g r a m s ) (in kilograms) after x months. Whats the y-intercept?
Given:
After 11 months, sumo wrestler weighed 140 kilograms.
He gained weight at a rate of 5.5 kilograms per month.
To find:
The y-intercept of the equation which represents y the sumo wrestlers weight (in kilograms) after x months.
Solution:
Let y represent the sumo wrestlers weight (in kilograms) after x months.
It is given that he gained weight at a rate of 5.5 kilograms per month.
So, slope of the line is 5.5.
After 11 months, sumo wrestler weighed 140 kilograms. It means the line passes through the point (11,140).
The point slope form of the line is
\(y-y_1=m(x-x_1)\)
where, m is slope of the line.
\(y-140=5.5(x-11)\)
\(y-140=5.5x-60.5\)
Add 140 on both sides.
\(y-140+140=5.5x-60.5+140\)
\(y=5.5x+79.5\)
Therefore, the required equation is \(y=5.5x+79.5\).
Substitute x=0, to find the y-intercept of this equation.
\(y=5.5(0)+79.5\)
\(y=79.5\)
Therefore, the y-intercept is 79.5. It means initial weight of sumo is 79.5 kilograms.
Can someone help me with this geometry question I will mark brainliest.
Answer:
14.2
Step-by-step explanation:
6 + 6sin(30) + 6cos(30) = 14.2
Use the SOHCAHTOA, see below picture.
The function h is given by h ( t ) = ( 1 − t ) ( 8 + 16 t ) models the height of a ball in feet, t seconds after it is thrown.
Where are the zeros of the function?
______and______
Are both zeros meaningful and why?
At what height is the ball thrown?
9514 1404 393
Answer:
zeros: t = 1, t = -1/2no: the domain of the function is t ≥ 08 feetStep-by-step explanation:
The zeros are the values of t that make the factors zero.
1 -t = 0 ⇒ t = 1
8 +16t = 0 ⇒ t = -8/16 = -1/2
The equation is used to model height after the ball is thrown. We don't expect it to be a good model before the ball is thrown (t < 0), so the zero in that region is extraneous.
Only the positive zero is in the function's domain, so that is the only one that is meaningful.
__
When t = 0 (at the time the ball is thrown), the function value is ...
h(0) = (1 -0)(8 +0) = 8
The ball is thrown from a height of 8 feet.
what is the length of a line segment with endpoints (3,-6) and (-2,6) ?
Answer:
13
Step-by-step explanation:
Will give brainliest for right answer. Absurd answer will be reported.
Answer:
Option 1
Step-by-step explanation:
Arc MK is equal to the sum of arcs ML and LK.
in a certain game, a fair die is rolled and a player gains 20 points if the die shows a 6. if the die does not show a 6, the player loses 3 points. if the die were to be rolled 100 times, what would be the expected total gain or loss for the player?
The expected gain or loss is an illustration of mean and expected values.
The expected total gain is 83 points
The given parameters are:
Addition of 20 points for rolling a 6Removal of 3 points for not rolling a 6The probability of rolling a 6 in a fair die is 1/6.
The probability of not rolling a 6 in a fair die is 5/6.
So, the expected gain in each game is:
\(\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}\)
\(\mathbf{E(x) = \frac{20}6 - \frac{15}6}\)
Take LCM
\(\mathbf{E(x) = \frac{5}6}\)
\(\mathbf{E(x) = 0.83}\)
The number of games is 100.
So, the expected gain is:
\(\mathbf{Gain = 100 \times 0.83}\)
\(\mathbf{Gain = 83}\)
Hence, the expected total gain is 83 points
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Please help someone!!! this has 5 questions in total, please answer all of them. Will give brainliest to the best answer!!!
The goalie on the Iceblades hockey team saves (blocks) 73% of the opponent's shots. With 10 minutes to go, the Iceblades are ahead by one goal, and they will win if the other team does not score. The other team takes 5 shots in the final 10 minutes. The Iceblades do not score any more goals. The table shows pairs of random digits. The pairs in each group simulate the 5 shots taken by the opponent.
Answer the questions to estimate the probability that the Iceblades will win the game.
1. The paired digits 00 to 99 represent 100 shots. Let 00 to 72 = a shot that is saved. Which digits represent a goal scored? Explain.
2. Each group represents the 5 shots taken by the other team. To win the game, the Iceblades cannot let the other team score any goals. For a group to be a success, how many of the 5 shots does the goalie need to save?
3. Group 1 is a success. Explain why.
4. In this simulation, which groups are successes? How many successes are there in the 10 groups?
5. Estimate the probability the Iceblades will win the game. Give your answer as a percent.
1. In this scenario, the goalie saves 73% of the opponent's shots. Therefore, any digits from 00 to 72 represent shots that are saved, as they fall within the range of the goalie's saving ability.
2. To win the game, the Iceblades cannot let the other team score any goals. Therefore, the goalie needs to save all 5 shots taken by the other team for a group to be a success.
3. Group 1 is a success because the goalie saves all 5 shots taken by the other team. Since no goals are scored, the Iceblades maintain their one-goal lead and are on track to win the game.
4. In this simulation, the successes are the groups where the goalie saves all 5 shots. Based on the information given, Group 1 is the only success. Therefore, there is one success in the 10 groups.
5. Since there is only one success out of the 10 groups, the estimated probability of the Iceblades winning the game would be 1 out of 10, or 1/10. Expressed as a percentage, this is equal to 10%.
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Jerry has a scaled down version of his new statue he wants to make in art class. His model is 8in tall and 15in wide. He wants the statue to be 4ft to fit in his backyard. How tall should it be
Based on a scale factor of 3.75, the new statue that Jerry is making should be 30ft tall (height).
What is the scale factor?The scale factor is the ratio that compares the measurement of an object with its scaled down or scaled up model.
The scale factor compares the measurements of the model with the real object's.
The scaled down model:
Height = 8 inches
Width = 15 inches
The Statue:
Width = 4 ft
The scale factor = 3.75 (15 ÷ 4)
Therefore, the height of the statue, using the scale factor, should be = 30ft (8 x 3.75)
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Solve for 8x + 17 = 41 for x. Show your work.
The value οf x is 3
What is variable?A variety οf issues are resοlved by algebraic calculatiοns that treat variables like explicit integers in a single cοmputatiοn. The quadratic fοrmula, fοr instance, can be used tο sοlve any quadratic equatiοn by exchanging the variables in the quadratic fοrmula fοr the numerical values οf the cοefficients in the equatiοn.
A variable in mathematical lοgic is either a symbοl fοr an undefined term οf the theοry (a meta-variable), οr it is a fundamental οbject οf the theοry that is changed withοut cοnsidering any pοtential intuitive meaning.
Given
8x+17 = 41
Sοlving fοr variable 'x'
Add '-17' tο each side.
17 + -17 + 8x = 41 + -17
Or, 8x=24
Divide each side by '8'
Or, x=3
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Find the volume of the sphere. Use 3.14 for it. Round to the tenths if necessary. Don't forget to include your
label in the answer. Use ^ to show an exponent.
Hey there! I'm happy to help!
First let's find the radius. The radius is half of the diameter.
9/2=4.5
Here's how to find the volume of any sphere.
You cube the radius.
4.5³=91.125
You multiply by 3.14
91.125(3.14)=286.1325
And finally we multiply by 4/3.
286.1325(4/3)=381.51
We round to the nearest tenth, giving us a volume of 381.5 in^3.
Have a wonderful day! :D
9 in = 3 in
v = 3,14x 3 x 3
= 28,26
answerers about Caca Andika from IndonesiaA set of pens contains pens that write with different colors of ink: 4 blue, 3 black, 2 red, and 1 purple. Write a numerical expression to represent how many pens a teacher will have if 12 sets of pens are ordered.
The teacher will have a total of 120 pens if 12 sets of pens are ordered.
To find the total number of pens a teacher will have if 12 sets of pens are ordered, we can start by finding the total number of pens in one set and then multiply it by 12.
In one set, there are 4 blue pens, 3 black pens, 2 red pens, and 1 purple pen. To find the total number of pens in one set, we can simply add the number of pens of each color:
Total pens in one set = 4 + 3 + 2 + 1 = 10
Therefore, the numerical expression to represent how many pens a teacher will have if 12 sets of pens are ordered is:
12 × 10 = 120
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One page of a petition can hold p signatures. You were able to get 4p+5 people to sign the petition. Your friend was able to get 2p−3 people to sign the petition. Write an expression in simplest form that represents the number of people that you and your friend got to sign the petition.
Answer:
6p - 2
Step-by-step explanation:
The expression that needs to be made in this question refers to the total number of people that signed the petition. To calculate this we need to add the total number of signatures that both you and your friend were able to acquire. Once we do this we simply combine like terms in order to simplify the expression as much as possible.
4p + 5 + 2p - 3
4p + 2p + 5 - 3
6p - 2
Therefore, the total and simplified expression for the total number of signatures would be 6p - 2
The G.C.F of 2 numbers is 36. The product of the 2 numbers is 23328. What is the
L.C.M of the 2 numbers? PLS ANSWER!
Given:
The G.C.F of 2 numbers is 36.
The product of the 2 numbers is 23328.
To find:
The L.C.M. of the 2 numbers.
Solution:
If a and b are two numbers, then
\(L.C.M.(a,b)\times H.C.F.(a,b)=a\times b\) ...(i)
We know that H.C.F. is equal to G.C.F.
Putting H.C.F. (a,b)= 36 and \(a\times b=23328\) in (i), we get
\(L.C.M.(a,b)\times 36=23328\)
Divide both sides by 36.
\(L.C.M.(a,b)=\dfrac{23328}{36}\)
\(L.C.M.(a,b)=648\)
Therefore, the L.C.M. of the 2 numbers is 648.
kurt bought 10 packs of sunflower seeds and 4 pots. each pack of seeds cost $4, and each post for $12. how.much did kurt spend in all
Answer:
$88
Step-by-step explanation:
Select the correct answer.
The class sizes of the Introductory Psychology courses at a college are shown below.
121, 134, 106, 93, 149, 130, 119, 128
The college adds a new Honors Introductory Psychology course with 45 students. What effect does the new class size have on the center and spread of the class sizes of the Introductory Psychology courses at the college?
A. The value of the center increases and the distribution has a larger spread.
B. The value of the center decreases and the distribution has a smaller spread.
C. The value of the center decreases and the distribution has a larger spread.
D. The value of the center increases and the distribution has a smaller spread.
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
does someone mind helping me with this problem? Thank you!
Answer:
5.20
Step-by-step explanation:
48 / 9.23 = 5.20043336945
rounded to tenth is 5.20
Hope This Helped
Answer:5.20
Step-by-step explanation:
48 / 9.23 = 5.20
find the remainder in the taylor series centered at the point a for the following function. then show that limn→[infinity]rn(x)=0 for all x in the interval of convergence. f(x)=e−x, a=0
First find a formula for f^n(x). f^n(x) = (Type an exact answer.) Next, write the formula for the remainder. R_n(x) = /(n 1)!^n 1, for some value c between x and 0 (Type exact answers.) Find a bound for |R_n(x)| that does not depend on c, and thus holds for all n, Choose the correct answer below. A. |R_n(x)| greaterthanorequalto 1/(n 1)!(x-theta)^n 1 B. |R_n(x) lessthanorequalto e|x|/(n 1)! |x|^n 1 C. |R_n(X)| lessthanorequalto 1/(n 1)! (x-e)^n 1 D. |R_n(X)| lessthanorequalto e^x/(n 1)! x^n 1 E. |R_n(X)| greaterthanorequalto e^|x|/(n 1)! |x|^n 1 F. |R_n(x) greaterthanorequalto e^-x/(N 1)!|x-e|
To find the remainder in the Taylor series centered at a=0 for f(x)=e^(-x), we start by finding the nth derivative of f(x). Differentiating f(x) repeatedly, we observe that f^n(x) = (-1)^n * e^(-x).
The formula for the remainder in the Taylor series is given by R_n(x) = (f^(n+1)(c) * (x-a)^(n+1))/(n+1)!, where c is some value between x and a.
For our function, f^(n+1)(x) = (-1)^(n+1) * e^(-x), so the remainder becomes R_n(x) = (-1)^(n+1) * e^(-c) * (x-0)^(n+1)/(n+1)!
To find a bound for |R_n(x)| that does not depend on c, we can use the fact that e^(-c) is always less than or equal to 1. Therefore, we have |R_n(x)| ≤ (x)^(n+1)/(n+1)!.
Based on this, the correct answer is A. |R_n(x)| ≥ 1/(n+1)!(x-θ)^(n+1), where θ is some value between x and 0.
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What is the corresponding point on the unit circle for the given radian measure?
0=5pi/3
The corresponding point on the unit circle for the angle θ = 5pi/3 is given by: (0,5, -0.866).
What is the unit circle?
Basically, the unit circle is a circle with a radius of 1. It is used in trigonometry to help define and understand angles and their associated trigonometric values. The unit circle is centered at the origin (0, 0) of the coordinate plane, and each point on the circle is defined by its distance from the origin and its angle from the positive x-axis.
What is area of circle ?
The area of circle can be defined as the product of pi and square of radius of a given circle.
In this problem, we have that θ = 5pi/3 , hence:
cos θ = 0.5
sin θ = -0.866
Thus the point is (0,5, -0.866).
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