Gallium has two naturally occurring isotopes. The mass of gallium-69 is 68. 9256 amu and it is 60. 108% abundant. The mass of gallium-71 is 70. 9247 amu and it is 39. 892% abundant. Find the atomic mass of gallium

The dot and cross diagram is a way of representing a molecule along with its valence electrons and respective bonds. Valence electrons are drawn as a dot or a cross, each element will have a different connotation. Around the atoms, circles are drawn that indicate the bonds and how the electrons are shared.

Carbon has 4 valence electrons and oxygen has 6, the dot-and-cross diagram of CO2 will be:

Answer:

5.5 × 10²² formula units Al₂O₃

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

9.3 g Al₂O₃

Step 2: Define conversions

Avogadro's Number

Molar Mass of Al - 26.98 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al₂O₃ - 2(26.98) + 3(16.00) = 101.96 g/mol

Step 3: Convert

\(9.3 \ g \ Al_2O_3(\frac{1 \ mol \ Al_2O_3}{101.96 \ g \ Al_2O_3} )(\frac{6.022 \cdot 10^{23} \ formula \ units \ Al_2O_3}{1 \ mol \ Al_2O_3} )\) = 5.4928 × 10²² formula units Al₂O₃

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

5.4928 × 10²² formula units Al₂O₃ ≈ 5.5 × 10²² formula units Al₂O₃

The solubility of a compound in a particular solvent depends on several factors, including the polarity of the solvent and the solute. Nonane is a nonpolar solvent, which means that it cannot dissolve polar compounds effectively. In general, compounds with nonpolar properties are more soluble in nonane compared to polar compounds.

1-pentanol, ethanol and acetic acid are polar compounds because they contain a hydroxyl group (-OH) or carbonyl group (C=O) that makes them more soluble in polar solvents such as water. Benzene and ethyl methyl ketone are nonpolar compounds because they lack any polar functional groups and contain only carbon and hydrogen atoms.
Based on their polarities, we can predict that benzene and ethyl methyl ketone will be the most soluble in nonane because nonane is a nonpolar solvent. The polar compounds (1-pentanol, ethanol, and acetic acid) will not dissolve well in nonane due to their polarity. Acetic acid may have some solubility in nonane because it has a relatively small polar functional group and a large nonpolar hydrocarbon chain. In conclusion, the most soluble compound in nonane is likely to be benzene or ethyl methyl ketone, both of which are nonpolar. The polar compounds are not expected to be very soluble in nonane due to the nonpolar nature of the solvent.

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Answer:

At 30 degrees C, Bromine is a liquid.

Explanation:

Answer:

B! Hope this helps! :)

Explanation:

Explanation:

The degree of deflection directly relates to the mass of the ion: the lighter the ion, the greater the deflection and the heavier the ion, the lesser the deflection. The beam of ions is then detected

and the relative abundance of each isotope of an element canthen be determined.

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The greater the mass of the isotope lesser will be the amount of deflection. The amount of deflection is related to the mass of the isotope.

An isotope is one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behavior but with different atomic masses and physical properties.

As each isotope has a different mass number, this number is written after the element name for the atom. For example, an atom of carbon with a mass number of 12 will be labeled as an atom of carbon-12. Carbon-13 and carbon -14 is also examples of carbon atom.

Thus, the greater the mass of the isotope lesser will be the amount of deflection. Deflection is depend upon the mass of atom.

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Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

Answer:  132 liters. or 130 liters with 2 sig figs.

Explanation:  Use the ideal gas law:  PV = nRT

We want V, so rewrite and plug in data:

Temperture must be in Kelvin (add 273.15 to

V = (nRT)/P

V = (4.9 moles)*(0.0821 L*atm/molK)*(328.2K)/(1atm)

V = 132 liters (3 sig figs).  130 liters with 2 sig figs

Answer:

0.018 grams

Explanation:

The number of moles (n) in such number of atoms of Aluminum must be calculated by dividing the number of atoms (nA) by Avagadro's number i.e.

n = nA ÷ 6.02 × 10^23atoms

The number of atoms of Aluminum in this question has been given as: 3.99 x 10^20 atoms.

n = 3.99 x 10^20 ÷ 6.02 × 10^23

n = 3.99/6.02 × 10^(20-23)

n = 0.663 × 10^-3

n = 0.000663moles

Next, we convert the mole value to mass in grams by using the formula;

mole = mass/molar mass

mass = mole × molar mass

Molar mass of Al = 27g/mol

mass (g) = 0.000663 × 27

mass = 0.0179

mass of Aluminum is 0.018grams

Answer:

17 electron

Explanation:

because the number of the proton and number of electron is equal if ther is no charge

Answer:

The correct answers are C. Ammonium nitrate - NH4ClO and D. Ammonium phosphate - NH4(PO4)3

Explanation:

If the initial pressure of (CH3)20, is 135 torr, the final pressure after 1420s is 51.4torr .the half life is 1019s.

We know ,

For the 1st order reaction we have the reaction in terms of pressure is

Pₓ = P₀ e⁻kt

lnPₓ = lnP₀ - kt

kt = lnP₀ -lnPₓ  = 2.303log P₀/Pₓ

t = (2.303/k) logP₀/Pₓ

Where ,

k = rate constant = 6.8×10⁻4 s⁻1

P₀ = initial pressure = 135torr

Pₓ= final pressure

t = time taken = 1420s

putting the values in the places of the symbol ,

1420 =( 2.303 / 6.8 ×10⁻4 ) log 135/Pₓ

1420 = (2.303×10^4/6.8 ) ×log 135/Pₓ

(1420×6.8 / 2.303×10^4) = log 135/Pₓ

0.41928 = log 135/Pₓ

135/Pₓ = 10^0.41928 = 2.6259

Pₓ = 135/2.6259 = 51.4 torr

Hence , the final pressure after 1420s is 51.4torr .

b) the half life formula is given by ,

T1/2 = 0.693/k = 0.693 / 6.8×10⁻4 = 0.1019×10^4 =1019s

Hence , the half life is 1019s .

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Answer:

The speed of sound in air is 333.33 m/s

Explanation:

The parameters given are the time it takes for the sound to male it to the cliff and back = 30 times in 9 seconds

Distance to the cliff = 50 meters

Therefore, the sound covers a distance of 30 × 100 = 3000 meters in 9 seconds

Which give the speed of sound in air using the formula for speed = Distance/Time

Therefore, the speed of sound in air = 3000/9 = 333.33 m/s.

The volume of these objects can be found by water displacement. A volume of water sufficient to cover the object is placed in a graduated cylinder and the volume read. The object is added to the cylinder and the volume read again.

Answer:

Displacement is a method used for measuring the volume of an irregular solid and it is in cubic units.

Once a digital recording is made, the bandwidth is set in place. An analog recording is considered unlimited. Therefore, it can move to a higher and higher resolution without losing its original quality.

For this question, since we are given the pressure, number of moles and temperature to find the volume, we have to use the ideal gas equation.

pV = nRT

Now lets put in the values

V = (0.263 mol x 8.314 J/mol x 307 k)/1.15 atm

V = 583.722 L

.

Answer:

D.

Explanation:

The electron cloud has negligible mass. Most mass come from the nucleus.

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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The molar mass of h2x is 38.18 g.

The molar mass of a chemical compound is defined because the mass of a pattern of that compound is divided by using the amount of substance that's the number of moles in that sample, measured in moles. The molar mass is a bulk, no longer molecular, an asset of a substance.

Calculation:-

H2X + 2NaOH ----> Na2X + 2H2O

1 mole = 2 NaOH

H₂X = 2.10 g

volume of NaOH = 50 ml = 0.05 L

Molarity = mole /volume

             = (mass/molar mass) / volume

    2* 0. 550   = (2.1/molar mass) / 0.05

molar mass = 2.1/0.55 * 0.05 *2

                   =  38.18 g

Molar mass is defined because of the mass in grams of 1 mole of a substance. The devices of molar mass are grams in line with mole, abbreviated as g/mol. The mass of an unmarried isotope of any given element (the isotopic atomic mass) is a cost concerning the mass of that isotope to the mass of the isotope carbon-12.

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Disclaimer:- your question is incomplete, please see below for the complete question.

A 2.10 g sample of H2X reacts completely with 50.0 mL of 0.550 M NaOH solution. What is the molar mass of H2X?

a. 153.

b. 306.

c. 99.3.

d. 45.8.

Answer:

18 grams of water

Explanation:

The Balance Chemical Reaction is as follow,

                     2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation,

                     160 g (2 moles) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                     40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                     X =  (40 g × 72 g) ÷ 160 g

                     X  =  18 g of H₂O

Hope This Helps!

Question 1 :

V1/T1 = V2/T2

3.0L/273K = V2/373K

To get the value of Z, cross multiply

3.0L x 373K = 273K x V2

1119 = 273V2

Divide both sides by 273

1119/273 = 273V2/273

4.10L = V2

The new volume is 4.10 liters

Question 2 :

P1/T1 = P2 /T2

P1 = 880 kPA= 880 *10^3 Pa

T1 = 250 K

T2 = 303 K

P2 =?

Substituting for P2

P2 = P1 T2/ T1

P2 = 880 kPa * 303 / 250

P2 = 266,640 kPa/ 250

P2 = 1066.56 kPa.

The new pressure of the gas is 1066.56 kPa

Question 3 :

Given that:

Volume of gas V = 4.80L

(since 1 liter = 1dm3

4.80L = 4.80dm3)

Temperature T = 62°C

Convert Celsius to Kelvin

(62°C + 273 = 335K)

Pressure P = 2.9 atm

Number of moles of gas N = ?

Apply ideal gas equation

pV = nRT

2.9atm x 4.8dm3 = n x (0.0082 atm dm3 K-1 mol-1 x 335K)

13.92 atm dm3 = nx 2.747 atm dm3 mol-1

n = 13.92/2.747

n = 5.08 moles

There are 5.08 moles of gas contained in the sample

Question 4 :

Volume of gas V = 3.47L

(since 1 liter = 1dm3

3.47L = 3.47dm3)

Temperature T = 85.0°C

Convert Celsius to Kelvin

(85.0°C + 273 = 358K)

Pressure P = ?

Number of moles of gas N = 0.100 mole

Apply ideal gas equation

pV = nRT

p x 3.47dm3 = 0.10 x (0.0082 atm dm3 K-1 mol-1 x 358K)

p x 3.47dm3 = 0.29 atm dm3

p = (0.29 atm dm3 / 3.47 dm3)

p = 0.085 atm

If 1 atm = 760 mm Hg

0.085atm = 0.085 x 760

= 64.6 mm Hg

The pressure of the gas is 64.6 mm hg

a.)  The Volume of water displaced is  3 ml

b.)  The final density of the mineral is 4.1 g/ml.

(a) The volume of water displaced is the ratio of the volume containing mineral to the volume excluding mineral.

Volume of water displaced = Volume with mineral - Volume without mineral

Volume of water displaced = 53 ml - 50 ml

Volume of water displaced = 3 ml.

(b) The following formula can be used to determine the mineral's density:

Mass / Volume equals density.

The difference between the mass of the mineral and the mass without the mineral is the mass of the mineral.

Mass of mineral = Mass with mineral - Mass without mineral

Mass of mineral = 12.3 g - 0 g (since the mass without mineral is not given)

Mass of mineral = 12.3 g

By deducting the volume without the mineral from the volume with, one may determine the volume of the mineral.

Volume of mineral = Volume with mineral - Volume without mineral

Volume of mineral = 53 ml - 50 ml

Volume of mineral = 3 ml

Therefore, the density of the mineral is:

Density = Mass of mineral / Volume of mineral

Density = 12.3 g / 3 ml

Density = 4.1 g/ml

Therefore, the final density of the mineral is 4.1 g/ml.

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Emerging scientific ideas are new theories or ideas that are gaining attention in the scientific community, but have not yet been fully accepted or confirmed.

Emerging ideas refer to the new and innovative ideas or theories that have yet to gain full scientific acceptance. While a scientific consensus is a view or theory that has been universally accepted and confirmed by multiple experiments or research, an emerging scientific idea is a new and unproven theory or idea that is gaining attention in the scientific community. These emerging ideas may also be referred to as scientific hypotheses. In contrast to scientific consensus, emerging scientific ideas have not yet been subjected to rigorous testing and confirmation.

They are generally proposed to explain new observations or experimental results, which have not yet been fully understood or explained by established scientific theories. Emerging scientific ideas can have the potential to challenge the current scientific consensus. If an emerging scientific idea is found to be valid, it can ultimately lead to the establishment of a new scientific consensus. For example, the emerging scientific idea of the Higgs boson particle led to the discovery of a new field in particle physics, which is now an established scientific consensus.

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If a non-volatile sugar is  added to water , the vapor pressure of liquid will tend to decreases and this reduction of vapor pressure is said to be proportional to the numbers of mole fraction of solute that was added to it.

In the case above,  the vapor pressure of the solution is known to be lowered if compared to the vapor pressure of the pure solution.

Therefore if a non-volatile solute is said to be place or added to a pure solution such as water, the vapor pressure of the solution will be reduced than that of the pure solution.

Hence, the statement that If a non-volatile sugar is  added to water , the vapor pressure of liquid will tend to decreases and this reduction of vapor pressure is said to be proportional to the numbers of mole fraction of solute that was added to it is correct.

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Yes, even if you handle the slide gently during staining and use minimal water when rinsing, you still have to heat fix. Heat fixation is a critical step that fixes and immobilizes the bacterial cells onto the slide, allowing them to withstand staining, dehydration, and other subsequent procedures.

In essence, heat fixation kills the bacterial cells, makes them stick to the slide, and makes the staining process easier and more effective. Moreover, heat fixation has been proven to provide better results than other fixation methods. Heat fixation is faster and easier to do than other fixation methods. It also causes less shrinkage and distortion of the bacterial cells, making them easier to view and interpret. In short, heat fixation is essential for the best possible staining results and should not be overlooked.
Heat fixation is an important procedure in microbiology that ensures accurate staining results. Heat fixation is a process by which bacterial cells are killed and fixed to the slide, making them adhere more strongly to the slide. This process is important because it immobilizes the cells and allows them to withstand the staining, washing, and other subsequent procedures. If you handle the slide gently during staining and use minimal water when rinsing, it is still necessary to heat fix. This is because heat fixing kills the cells and makes them stick to the slide. Without heat fixing, the cells may fall off during staining and rinsing, or they may get washed away, resulting in inaccurate results.

In conclusion, heat fixation is a crucial step in microbiology that should not be ignored. It is a simple procedure that can be performed quickly and easily and ensures accurate staining results. Even if you handle the slide gently during staining and use minimal water when rinsing, you still need to heat fix the bacterial cells to ensure they adhere to the slide and withstand the subsequent procedures.

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The molecule H₁₂O₆ does not exist in nature. The formula H₁₂O₆ suggests the presence of 12 hydrogen atoms and 6 oxygen atoms.

However, such a configuration is highly unstable and does not conform to the principles of chemical bonding and stability. In a typical molecule of water (H₂O), two hydrogen atoms are bonded to one oxygen atom. The Lewis structure for water would represent this bonding arrangement. Each hydrogen atom contributes one valence electron, and oxygen contributes six valence electrons.

The Lewis structure for water would show two lines (representing covalent bonds) connecting the oxygen atom to each hydrogen atom. Additionally, the oxygen atom would have two lone pairs of electrons (represented by dots) surrounding it. It is important to note that the Lewis structure represents the valence electron arrangement in a molecule and provides insight into its bonding and geometry.

However, the Lewis structure alone may not capture the full 3D shape and molecular properties. In the case of H₁₂O₆, the presence of 12 hydrogen atoms and 6 oxygen atoms is highly unlikely due to the unfavorable electron configuration and excessive charge repulsion.

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The self-diffusivity (D) of copper can be calculated by using the given data and the equation c(x, t) = (x²/4Dt) * (√(R/D) - 1).

The equation c(x, t) = (x²/4Dt) * (√(R/D) - 1) relates the concentration of the radioactive isotope of copper (c) at a distance (x) from the end of the bar to the self-diffusivity (D) of copper and the annealing time (t).

I₁ = It counts/(min m²)

= 500 counts/(min m²)

I₂ = 500 counts/(min m²)

x₁ = mm

x₂ = 400 mm

t = 10 hours

= 600 minutes

We can use the given equation with the measured counts (I₁ and I₂) to calculate the ratio R/D.

R/D = (I₂/I₁)²

Substituting the values:

R/D = (500/500)²

= 1

We may now rearrange the equation to find D:

D = (x²/4ct) * (√(R/D) - 1)

Substituting the known values:

D = (x₁²/4ct) * (√(1/D) - 1)

= (x₁²/4ct) * (√(1/D) - 1)

Substituting the given values:

x₁ = mm

= 0.001 m

t = 10 hours

= 600 minutes

D = (0.001²/4 * 0.001 * 600) * (√(1/D) - 1)

= 1.6667 * (√(1/D) - 1)

To determine the value of D, we can numerically solve this equation. By substituting different values for D and iterating until the equation is satisfied, we can determine the self-diffusivity of copper.

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