g which fo the numbered hydroxyl groups reacts wit ht the circled hydrogen atom to form the new covalent bond i nthe dissacharide

Answer:

The answer to your question is given below

Explanation:

From the question given above, the following data were obtained:

Concentration (g/mL) = 0.04 g/mL

Concentration (g/L) =?

We can convert g/mL to g/L by doing the following:

1 g/mL = 1000 g/L

Therefore,

0.04 g/mL = 0.04 g/mL × 1000 g/L / 1 g/mL

0.04 g/mL = 40 g/L

0.04 g/mL is equivalent to 40 g/L.

Thus, the concentration (g/L) is 40 g/L

Answer: (Kr) 5s2

Explanation:

Apex

Question:

What occurs to the atoms of reactants in a chemical reaction?

Answer:

In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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Answer:

CaHPO4 i think

Explanation:

The right response is C) A person commutes to work on a bicycle or by taking public transit. This is an illustration of a sustainable behaviour that people or families may adopt since it lessens their carbon footprint and promotes energy conservation.

People may decrease their dependency on vehicles, which are a significant source of greenhouse gas emissions, by adopting a bicycle or public transit. This promotes a healthier environment and lowers air pollution.

Additionally, users may save money on petrol and automobile maintenance by switching from driving to public transit. People may also lessen their reliance on oil, which is a limited resource, by using bicycles or public transit. This environmentally friendly method can assist to protect the environment.

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Answer:

a specific amount edta is added to a specific amount of distilled water

Explanation:

The reaction order and specific reaction rate constant can be determined by performing the kinetics experiment on irreversible polymerization A. Kinetic experiments can be used to investigate the rate and mechanism of chemical reactions. Chemical kinetics is the study of chemical reactions' speed and pathway.

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To determine the original pressure of a 750 ml sample of helium (He) at 0 degrees Celsius, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law equation is:

(P1 × V1) / (T1) = (P2 × V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively.

V1 and V2 are the initial and final volumes, respectively.

T1 and T2 are the initial and final temperatures, respectively.

Let's assign the given values:

P1 = unknown (original pressure)

V1 = 750 ml (initial volume)

T1 = 0 degrees Celsius (initial temperature)

P2 = 2 atm (final pressure)

V2 = 500 ml (final volume)

T2 = 25 degrees Celsius (final temperature)

Before using the combined gas law equation, we need to convert the temperatures to Kelvin scale by adding 273.15 to both T1 and T2:

T1 = 0 + 273.15 = 273.15 K

T2 = 25 + 273.15 = 298.15 K

Now we can plug in the values into the combined gas law equation:

(P1 × 750 ml) / (273.15 K) = (2 atm × 500 ml) / (298.15 K)

To solve for P1, we can cross multiply and rearrange the equation:

P1 = (2 atm × 500 ml × 273.15 K) / (750 ml × 298.15 K)

P1 = 0.924 atm

Therefore, the original pressure of the 750 ml sample of helium at 0 degrees Celsius is approximately 0.924 atm.

Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.

A word equation is one in which the equation that is shown in the reaction is written in words rather than by the use of the chemical symbols of the elements that are involved.

We have the reaction; \(2H_{2} (g) + O_{2} (g) ---- > 2H_{2} O(l)\), in order for this reaction to be written in the word equation form we have; Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.

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Answer:

(NH4)3PO4 is 28.2 % N , 8.1% H, 20.8 % P and 43.0 % O by mass.

Explanation:

the formula In chemistry, the mass fraction of a substance within a mixture is the ratio w_{i} of the mass m_{i} of that substance to the total mass {\displaystyle m_{\text{tot}}} of the mixture. Expressed as a formula, the mass fraction is: {\displaystyle w_{i}={\frac {m_{i}}{m_{\text{tot}}}}.}

Answer:

9.33

Explanation:

balanced chemical equation:

2NH₃ + 3CuO → 3Cu + N₂ + 3H₂O

14 moles of NH3

2NH₃ → 3H₂O

14 * 2/3 = 9.33

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Answer:

\(HCN~~Ka=4.9x10^-^1^0\)

Explanation:

In this case, we have to remember the relationship between the Ka value and the pH. We can use the general reaction for any acid with his Ka value expression:

\(HA~->~H^+~+~A^-\)    \(Ka=\frac{[H^+][A^-]}{[HA]}\)

In the Ka expression, we have a proportional relationship between Ka and the concentration of \(H^+\). Therefore, if we have a higher Ka value we will have a smaller pH (lets keep in mind that with a higher

So, if we have to find the higher pH value we need to search the smaller Ka value in this case \(HCN~~Ka=4.9x10^-^1^0\).

I hope helps!

HCN has the highest pH among all the acids listed in the question.

The Ka is called the acid dissociation constant. It shows the extent to which an acid is ionized in water. The pH shows the hydrogen ion concentration of water. The higher the Ka, the higher the hydrogen ion concentration and the lower the pH.

Hence, HCN has the lowest Ka and the lowest hydrogen ion concentration. Therefore, HCN has the highest pH among all the acids listed in the question.

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The solid and the liquid coexist at the melting point, which is the point where the temperature remains constant during the phase transition.

In the given cooling curve, the melting point is at 50°C, indicated by the flat region on the curve between points C and D. At this point, the energy being released during cooling is used to overcome the energy required for the substance to transition from a liquid to a solid state.

Once all of the substance has solidified, the temperature begins to decrease again.

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Answer: all points on the curve between Q and S

Explanation: Where the graph looks like <-------->horizontal.

Answer:

The answer is " 10.39"

Explanation:

Calculating acid moles:

\(= 0.02000 \ L \times 0.1000 \ M \\\\= 0.002000\)

Calculating NaOH moles:

\(= 0.02012 \ L \times 0.1000 \ M \\\\= 0.002012\)

calculating excess in OH-  Moles:

\(= 0.002012 - 0.002000\\\\=0.000012\)

calculating total volume:

\(= 20.00 + 20.12\\\\ = 40.12 mL \\\\= 0.04012 L\)

\([OH-]= \frac{0.000012} { 0.0472}\)

           \(=0.00025 M\)

\(pOH = - \log 0.00025\)

        = 3.6

\(pH = 14 - pOH\)

      = 10.39

The three examples of giant ionic structures used in industrial world today include. NaCl: sodium chloride. NaBr: sodium bromide. NaF: sodium fluoride.

A giant ionic structure is also known as an ionic compound which has a regular repeating arrangement called an ionic lattice.

Typical examples of giant ionic structures include the following:

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Considering the definition of empirical and molecular formula, if the molecular formula mass of the compound is 60.0 g/mol, the molecular formula is N₂O₂.

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms.

The molecular formula is the chemical formula that indicates the number and type of distinct atoms present in the molecule. The molecular formula is the actual number of elements that make up a molecule.

The empirical formula and the molecular formula are generally related in the following way:

Molecular Formula = n× Empirical Formula

where n is n=molecular mass÷ empirical mass

In this case, in first place you need to convert the number of grams given into percentage as follow:

Assuming a 100 grams sample, the percentages match the grams in the sample. So you have:

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

Therefore the N: O mole ratio is 1: 1

Finally, the empirical formula is N₁O₁= NO

The molecular mass is 60.0 g/mol and the empirical mass is 30 g/mole. Then, the value of n is:

n=60 g/mole÷ 30 g/mole

Solving:

n=2

Being the Molecular Formula = n× Empirical Formula, the you can calculate:

Molecular Formula = 2× (NO)

Molecular formula= N₂O₂

Finally, the molecular formula is N₂O₂.

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The sample of the liquid has more energy than the sample of solid. Hence, option B is correct.

Thermal energy refers to the energy contained within a system that is responsible for its temperature.

The particles in the liquid are the same as in the solid but they have more energy. To melt solid energy is required to overcome the attraction between the particles and allow them to pull them apart. The energy is provided when the solid is heated up.

Hence, option B is correct.

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Answer:

Given:

Volume of wet hydrogen gas (Vwet) = 4.00 L

Pressure (P) = 737 torr

Temperature (Twet) = 23.0°C = 296 K

To find:

Volume of dry hydrogen gas (Vdry) at STP (Tdry = 273 K and Pdry = 760 torr)

Solution:

Convert temperature to Kelvin: T = Twet = 23.0°C + 273 = 296 K

Use the combined gas law: P1V1/T1 = P2V2/T2

Plug in values: P1 = P, V1 = Vwet, T1 = T, P2 = Pdry = 760 torr, T2 = Tdry = 273 K

Solve for V2 (Vdry): Vdry = Vwet x Pdry x T / P x Tdry

Substitute values: Vdry = 4.00 L x 760 torr x 296 K / 737 torr x 273 K

Simplify: Vdry ≈ 3.48 L

Therefore, the volume of dry hydrogen gas at STP is approximately 3.48 L.

So the answer key is correct, but their method may have been incorrect.

The terms that best describe the isomeric relationship between staggered and eclipsed ethane are B: "conformational, achiral, diastereomers."

An isomeric relationship refers to the relationship between two or more chemical compounds having the same molecular formula but differing in the arrangement of their atoms. Isomers can be classified into different types such as structural isomers, stereoisomers, and conformational isomers based on the differences in their molecular structure.

In the context of this question the isomeric relationship between staggered and eclipsed ethane is described as "conformational, achiral, diastereomers.

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Carbon atoms may thus form bonds to as many as four other atoms. For example, in methane (CH 4​start subscript, 4, end subscript), carbon forms covalent bonds with four hydrogen atoms

__________________________________________________________

Answer:

0.011 mol CO₂

General Formulas and Concepts:

Chemistry - Gas Laws

Combined Gas Law: PV = nRT

Temperature Conversion: K = °C + 273.15

Explanation:

Step 1: Define

250 mL

-24°C

95 kPa

Step 2: Identify Conversions

Temp Conversion

1000 mL = 1 L

Step 3: Convert

\(250 \ mL(\frac{1 \ L}{1000 \ mL} )\) = 0.25 L

-24°C + 273.15 = 249.15 K

Step 4: Find Moles

Step 5: Check

We are given 2 sig figs. Follow sig fig rules and round.

0.011465 mol CO₂ ≈ 0.011 mol CO₂

Answer:

There can be numerous derived quantities all branching from the basic 7 base quantities.

Explanation:

The  derived SI units are

m/s² that is of acceleration that is rate of change of velocity

m/s is the SI unit of velocity that is rate of change of displacement

Nm is the SI unit of Torque i.e T= rxF

and so on

Answer: No because a solution is a homogeneous MIXTURE of two or more substances. Water is a pure substance. It is made of hydrogen and oxygen, but shares none of their properties. So it’s pure.

Explanation:

Answer:

3 moles of O2

Explanation:

From the equation you can see that the ratio of H2 to O2 is  2:1

  so   6 mole of hydrogen will require  3 mole of O2

HC6H7O5- acts as the base in the following equation, which is written as follows:

H3O+ + HC6H7O5-(aq) ----->Water + H2C6H7O5(aq)(l).

Any substance that accepts a hydrogen ion is a base. This suggests that HC6H7O5- accepts the hydrogen ion from an acid in the reaction to be written.

HC6H7O5- acts as the base in the following equation, which is written as follows:

H3O+ + HC6H7O5-(aq) ----->Water + H2C6H7O5(aq)(l).

any substance that, when dissolved in water, is slippery to the touch, tastes bitter, transforms indicators into different colors (such as turning red litmus paper blue), reacts with acids to produce salts, and triggers specific chemical reactions (base catalysis). Examples of bases include ammonia or its organic derivatives in water solutions and the hydroxides of alkali and alkaline earth metals (sodium, calcium, etc.). (amines). In water solutions, these substances cause hydroxide ions (OH-). (see Arrhenius theory).

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Answer:

B.K2(OH)2 i think that is the answer

A brother is bragging about doing a bench press of 4000 grams at the gym. 4000 grams is equal to 8.818 pounds.

The bench press or chest press is training or weight training to strengthen your arm and chest muscles. It is done by laying down on a bench and pushing and pulling up the bars with weight.

It is a common weight-lifting exercise in gyms. Trainers use accordingly weight on the basis of the trainee's weight and strength that is doing the bench press, and the weight is measured differently in different countries. Eight-pound is not a very big amount.

In America, weight is measured in pounds, one kg is 1000 grams and

1 gram is 0.00220462

4000 x 0.00220462

4000 grams will be 8.818 pounds.

Thus, 4000 grams is equal to 8.818 pounds.

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Answer:

3.36 × 10^-19 J

Explanation:

From the formula;

E= hc/wavelength

h= 6.6 ×10^-34 Js

c= 3 × 10^8 ms-1

Wavelength= 589 ×10^-9 m

E= hc/ wavelength

E=6.6 ×10^-34 × 3 × 10^-8/ 589 ×10^-9

E= 3.36 × 10^-19 J

Answer: 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given

Explanation:

The question requires us to determine the amount of hydrogen gas (H2) that would be obtained when 10.0g of metallic magnesium (Mg) and 10.0g of chloridric acid (HCl) are reacted.

The following unbalanced chemical equation was provided:

To solve this problem, we'll need:

1) obtain the balanced chemical equation;

2) determine the limiting reactant considering the amount of reactants used and the stoichiometry of the reaction;

3) calculate the mass of hydrogen gas produced, considering the limiting reactant

1) Balancing the chemical equation

From the unbalaced chemical equation, we can see that there is the same amount of Mg on both sides of the equation, but we need to adjust the amount of H and Cl atoms.

There are 2 Cl atoms and 2 H atoms on the right side, and 1 Cl and 1 H atom on the left side, thus we can adjust the coefficient of HCl from 1 to 2 to adjust these elements. The balanced chemical equation can be written as:

2) Determining the limiting reactant

Now that we know the balanced chemical equation, we can say that 2 moles of HCl are necessary to react with 1 mol of Mg. Thus, we can write:

1 mol Mg ----------------------- 2 mol HCl

From this stoichiometric relation, we can calculate the amount of HCl that would be necessary to react with 10.0 g of Mg.

First, let's determine the amount of moles of Mg contained in 10.0g of this metal and the number of moles of HCl in 10.0g of this acid:

(the atomic mass of Mg is 24.31 amu, which is numerically identical to its molar mass, 24.31 g/mol, and the molar mass of HCl is 36.4g g/mol)

Therefore, 0.411 moles of Mg and 0.274 moles of HCl were used in the reaction.

Next, we can determine how many moles of HCl would be necessary to react with 0.411 moles of Mg:

1 mol Mg ----------------------- 2 mol HCl

0.411 mol Mg ----------------- x

Solving for x, we have that 0.822 moles of HCl would be necessary to react with the given amount of Mg. Since the amount actually used of HCl (0.274 mol) is smaller than the necessary amount, we can say that HCl is the limiting reactant.

3) Calculating the mass of H2 obtained

Using the limiting reactant and the stoichiometry of the reaction, we can determine the amount of H2 that could be produced.

From the balanced chemical equation, we know that 2 moles of HCl are necessary to produce 1 mol of H2. Thus, we can write:

2 mol HCl ------------------- 1 mol H2

0.274 mol HCl ------------ y

Solving for y, we have that 0.137 moles of H2 would be obtained.

We can convert the number of moles of H2 to its correspondent mass as it follows (the molar mass of H2 is 2.016 g/mol):

Therefore, 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given.