g if you changed the source wavelength to a longer wavelength, e.g. 600nm, how would the distance between the zero order maximum and the third order maximum change?
Answers
There would be an increase in the maximum order.
How will the wavelength change?If you change the source wavelength to a longer wavelength, for example, from 500 nm to 600 nm, the distance between the zero order maximum and the third order maximum would increase.
The distance between the diffraction peaks in a diffraction grating is proportional to the wavelength of the light. As the wavelength increases, the distance between the diffraction peaks also increases. The diffraction peaks are also proportional to the order of the diffraction. Therefore, as the wavelength increases, the distance between the zero order maximum and the third order maximum also increases.
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Related Questions
A house of mass 500 kg is lifted 25 m by balloons.
Calculate the increase in gravitational potential energy, Ep.
(g = 10 N/kg)
Enter your answer as a number - NO units
Answers
Gpe = 500*10*25
Gpe = 125000J
PLEASE HELP I PAY 88 POINTS AND THANK YOU AND BRAINLIEST
Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
Answers
Answer: Down below is the answer in complete sentences!
Explanation:
PART A:
Gravity and Acceleration are two additional forces acting upon the sled.
PART B:
Gravity will affect the sled by pulling it down, since the slope of the hill is negative.
Acceleration will affect the sled by gradually increasing it's speed, since the slope is downwards, which in addition to the initial force exerted plus gravity increases the speed, thus the sled accelerates.
on which day of the year does the sun reach its northernmost point on the celestial sphere?
Answers
The sun reaches its northernmost point on the celestial sphere on June 21st or 22nd, which is known as the summer solstice in the Northern Hemisphere.
During this time, the tilt of the Earth's axis is pointing towards the sun, resulting in the longest day and shortest night of the year in the Northern Hemisphere. Conversely, the Southern Hemisphere experiences the shortest day and longest night on this day, known as the winter solstice.
This phenomenon occurs due to the Earth's axial tilt of approximately 23.5 degrees and its orbit around the sun. As the Earth orbits around the sun, the tilt of its axis causes different parts of the planet to receive varying amounts of solar radiation, leading to the changes in seasons.
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A naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120
kHz and a wavelength of 3 mm. How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m.
and returns to hit the ship's sensor 3 seconds later?
Answer should be in meters
Answers
With the use of wave speed and echo formula, the distance is 540 m
What is Echo ?Echo can simply be defined as a reflection of sound wave. Where as, Sound wave is longitudinal wave.
Given that a naval navigator is using sonar to look for sunken cargo. The waves he is using have a frequency of 120 kHz and a wavelength of 3 mm.
The wave speed V = Fλ
Where
V = ?F = 120 KHz = 120,000λ = 3 mm = 0.003 mV = 120000 × 0.003
V = 360 m/s
How far away is the cargo if the sound wave is emitted at exactly 9:24 a.m. and returns to hit the ship's sensor 3 seconds later?
Speed V = 2S/t
where
S = distance ?t = time taken = 3 s360 = (2 × S)/3
360 × 3 = 2S
S = 1080/2
S = 540 m
Therefore, the cargo is 540 m away
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What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?
Answers
Answer:
6000 N toward west
Explanation:
F = ma
a = 30-15/10 = 1.5 m/s^2 towards west
m = 4000 kg
F = 4000 x 1.5 = 6000 N towards west
problem 6: a circuit is constructed as shown in the diagram to the right. r1 = 85 ω, r2 = 54 ω r3 = 71 ω, r4 = 41 ω, r5 = 144 ω, and r6 = 87 ω.
Answers
The circuit consists of resistors with values of 85 Ω, 54 Ω, 71 Ω, 41 Ω, 144 Ω, and 87 Ω. To provide a detailed explanation, we need to analyze the circuit's properties and calculate relevant quantities.
Resistors R1, R2, and R3 are connected in series, resulting in a total resistance (RT) of R1 + R2 + R3 = 85 Ω + 54 Ω + 71 Ω = 210 Ω. This combined resistance forms a branch with resistor R4, which is connected in parallel. The total resistance of this parallel branch (R4T) can be calculated using the formula 1/R4T = 1/R4 + 1/RT, giving 1/R4T = 1/41 Ω + 1/210 Ω. Solving this equation yields R4T ≈ 33.44 Ω.
Next, the parallel branch formed by R4T is connected in series with resistor R5, resulting in a new total resistance (RTotal) of R4T + R5 = 33.44 Ω + 144 Ω = 177.44 Ω. Finally, resistor R6 is connected in parallel with RTotal. The total resistance of this parallel combination (R6T) can be calculated using the formula 1/R6T = 1/R6 + 1/RTotal, which gives 1/R6T = 1/87 Ω + 1/177.44 Ω. Solving this equation yields R6T ≈ 59.53 Ω.
The circuit's total resistance can be broken down into series and parallel combinations. The overall resistance is approximately 210 Ω + 33.44 Ω + 144 Ω + 59.53 Ω, which can be simplified to approximately 447 Ω.
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Answer the following
1) A piece of gold weighis 240 g and has a volume of 20 cm^3. Find the density of gold.
2) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm
pls answer fast I will mark as brainlist
Answers
Answer:
1. 12 g/cm³
2. 0.5 m
Explanation:
1.
The weight of the gold is 240 g
The volume is 20 cm³
Density = Mass/ volume
Density = 240 / 20 = 12 g/cm³
2.
The formula for moment of a force is ;
Force * distance perpendicular between force and the turning point of force
Given that the moment of force is 12.5 Nm and force is 25 N then the perpendicular distance between the force and the turning point will be;
12.5 = 25 * d
12.5/25 = d
0.5 = d
d= 0.5 m
A radioactive element decays with a half-life of 9 years. if a mass of the element weighs 6 pounds at t=0, find the amount of the element after 11.5 years.
Answers
By the half-life of radioactive, the remaining mass of radioactive elements is 2.47 pounds.
We need to know about the half-life of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation
N = No(1/2)^(t/t'')
where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.
From the question above, we know that
t'' = 9 years
No = 6 pounds
t = 11.5 years
Calculate the remaining mass
N = No(1/2)^(t/t'')
N = 6(1/2)^(11.5/9)
N = 2.47 pounds
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will you help me please
Answers
Answer: True
Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.Un depósito de gran superficie se llena de agua hasta una altura de 0,3 m. En el fondo del depósito hay un orificio de 5 cm2 de sección por el que sale el agua con un chorro continuo. A) ¿Qué cantidad de líquido saldrá del depósito expresada en m3/s?
Answers
Answer:
a) El caudal de salida del chorro es \(1.213\times 10^{-3}\,\frac{m^{3}}{s}\).
Explanation:
a) Asúmase que el tanque se encuentra a presión atmósferica y que la sima del tanque tiene una altura de 0 metros. La rapidez de salida del chorro del depósito se determined a partir del Principio de Bernoulli, cuya línea de corriente entre la cima y la sima del tanque queda descrita por la siguiente ecuación:
\(\Delta z = \frac{v_{out}^{2}}{2\cdot g}\)
Donde:
\(\Delta z\) - Diferencia de altura, medida en metros.
\(g\) - Constante gravitacional, medida en metros por segundo al cuadrado.
\(v_{out}\) - Rapidez de salida del chorro, medida en metros por segundo.
Se despeja la rapidez de salida del chorro:
\(v_{out} = \sqrt{2\cdot g \cdot \Delta z}\)
Si \(g = 9.807\,\frac{m}{s^{2}}\) y \(\Delta z = 0.3\,m\), entonces la rapidez de salida del chorro es:
\(v_{out} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.3\,m)}\)
\(v_{out} \approx 2.426\,\frac{m}{s}\)
Ahora, la cantidad de líquido que sale del depósito por unidad de tiempo se obtiene al multiplicar la rapidez de salida del chorro por el área transversal del orificio. Esto es:
\(\dot V_{out} = v_{out}\cdot A_{t}\)
Donde:
\(v_{out}\) - Rapidez de salida del chorro, medida en metros por segundo.
\(A_{t}\) - Área transversal del orificio, medido en metros cuadrados.
\(\dot V_{out}\) - Caudal de salida del chorro, medido en metros cúbicos por segundo.
Dado que \(v_{out} = 2.426\,\frac{m}{s}\) y \(A_{t} = 5\,cm^{2}\), el caudal de salida del chorro es:
\(\dot V_{out} = \left(2.426\,\frac{m}{s} \right)\cdot (5\,cm^{2})\cdot \left(\frac{1}{10000}\,\frac{m^{2}}{cm^{2}} \right)\)
\(\dot V_{out} = 1.213\times 10^{-3}\,\frac{m^{3}}{s}\)
El caudal de salida del chorro es \(1.213\times 10^{-3}\,\frac{m^{3}}{s}\).
Please help the question is the picture below.
Answers
Its 30 kg cause I got 30 kg dude.
i’ve done it on paper.
consider the collision between a car and a light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored
Answers
The truck applies the same force to the car that the car applies to the truck. The truck applies the same force to the car that the car applies to the truck. According to Newton's third law, action and reaction have the same magnitude and move in the opposite direction.
What is force?Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.
The direction of the force is the point where force is applied, and the application of force is the point where force is applied.
The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica.
The truck exerts the very same force on the car as the car exerts on the truck. The truck exerts this very same force on the car as the car exerts on the truck.
Action and reaction have the same amplitude and move in the opposite direction, according to Newton's third law.
Thus, this can be the comparison in the given scenario.
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Your question seems incomplete, the complete question is:
Consider the collision between a car and a
light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored.
Compare the forces if the light truck is standing
still when the car hits it.
If the temperature of the air (ambient temperature) is 30°C and a metal ball cools from 100°C to 70°C in 15 minutes. Find how long it will take for the metal ball to reach a temperature of 40°C. Given that this this process can be modelled by dT -=-k(T-To), where the symbols have their usual meanings. dt (5)
Answers
The equation dT/dt = -k(T - To) represents the rate of change of temperature with respect to time, where T is the temperature of the metal ball at a given time, To is the ambient temperature, k is the cooling constant, and dT/dt denotes the derivative of temperature with respect to time.
We can solve this first-order differential equation to find the time it takes for the metal ball to reach a temperature of 40°C.
Given:
Initial temperature (T0) = 100°C
Final temperature (T) = 40°C
Ambient temperature (To) = 30°C
The equation can be rewritten as:
dT / (T - To) = -k dtIntegrating both sides:
∫ dT / (T - To) = -k ∫ dt
Applying the natural logarithm:
ln|T - To| = -kt + C
To determine the constant C, we use the initial condition:
ln|T0 - To| = -k(0) + C
ln|T0 - To| = C
Substituting the values:
ln|100 - 30| = ln|70| = C
The equation becomes:
ln|T - To| = -kt + ln|70|
Now, we can solve for the time it takes for the metal ball to reach a temperature of 40°C.
ln|T - To| = -kt + ln|70|
ln|40 - 30| = -k(t) + ln|70|
ln|10| = -kt + ln|70|
ln(10) - ln(70) = -kt
Simplifying,
ln(10/70) = -kt
Rearranging the equation to solve for time (t):
t = -ln(10/70) / k
To find the value of the cooling constant k, we can use the given information that the metal ball cools from 100°C to 70°C in 15 minutes.
ln(70 - 30) = -k(15)
ln(40) = -15k
Solving for k:
k = -ln(40) / 15
Now we can substitute the value of k into the equation for time (t):
t = -ln(10/70) / (-ln(40) / 15)
t ≈ 10.97 minutes
Therefore, it will take approximately 10.97 minutes for the metal ball to reach a temperature of 40°C.
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A baseball team has 25 players. The average mass of a player is 84.4 kg. If this team is riding a bus that is travelling at 26.9 m/s, how much momentum does the team (without the bus) truly have?
What's the Solution?
Answers
The baseball team (without the bus) has a momentum of 56,819 kg*m/s.
The momentum of an object is defined as the product of its mass and velocity. To calculate the momentum of the baseball team, we need to find the total mass of the team and the velocity of the team relative to the ground (which is the velocity of the bus since the team is riding on it).
The total mass of the team is given by:
mass of team = number of players x average mass per player
mass of team = 25 players x 84.4 kg/player = 2,110 kg
The velocity of the team relative to the ground is the same as the velocity of the bus, which is given as 26.9 m/s.
Therefore, the momentum of the baseball team is:
momentum = mass x velocity
momentum = 2,110 kg x 26.9 m/s
momentum = 56,819 kg*m/s.
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could newton laws or keplers 3rd law be applied to the hot gas orbiting the nucleus of m87 to determine the mas of the central black hole
Answers
Both Newton's laws and Kepler's third law can be used to estimate the mass of the black hole in M87, and combining the information obtained from both methods has led to the discovery that the black hole is approximately 6.5 billion times the mass of the sun.
Yes, both Newton's laws and Kepler's third law can be used to determine the mass of the central black hole in M87 by analyzing the motion of the hot gas orbiting the nucleus.
Newton's laws of motion can be applied to the orbiting gas to determine the centripetal force acting on it, which is related to the gravitational force between the gas and the central black hole. This, in turn, can be used to calculate the mass of the black hole.
Kepler's third law can also be used to determine the mass of the black hole by analyzing the orbital period and distance of the gas from the black hole. The law states that the square of the orbital period is proportional to the cube of the semi-major axis of the orbit, which can be used to calculate the mass of the black hole.
By combining the information obtained from both methods, astronomers have been able to estimate the mass of the central black hole in M87 to be approximately 6.5 billion times the mass of the sun. This groundbreaking discovery was made possible by the Event Horizon Telescope, which is a network of telescopes that are able to observe black holes and their surroundings in unprecedented detail.
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Which new idea did copernicus introduce that significantly modified the geocentric model of the universe?.
Answers
Copernican heliocentrism was a novel concept that fundamentally altered the geocentric view of the universe.
What fresh concept did Copernicus bring that fundamentally altered the geocentric model?The father of modern astronomy is Nicolaus Copernicus, a Polish astronomer and mathematician. The heliocentric hypothesis of the solar system, which he initially put forth, states that Earth and other planets rotate around the sun.
Nicolaus Copernicus created the Copernican heliocentrism astronomical theory, which was first presented in print in 1543. This theory put the Sun in the center of the cosmos, stationary, and had Earth and the other planets orbit it at uniform speeds in circular orbits modified by epicycles.
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Be sure to answer all parts. chlorine has two naturally occurring isotopes, 35cl and 37cl. what is the mass number of each? how many protons, neutrons, and electrons are present in each?
Answers
Chlorine has two naturally occurring isotopes, \(^{35}Cl\) and \(^{37}Cl\).
What is the mass number, number of protons, neutrons, and electrons are present in \(^{35}Cl\)?
The mass number of \(^{35}Cl\) is 35.
The number of protons present in \(^{35}Cl\) is 17.
The number of neutrons present in \(^{35}Cl\) is 18.
The number of electrons present in \(^{35}Cl\) is 17.
What is the mass number, number of protons, neutrons, and electrons are present in \(^{37}Cl\)?
The mass number of \(^{37}Cl\) is 37.
The number of protons present in \(^{37}Cl\) is 17.
The number of neutrons present in \(^{37}Cl\) is 20.
The number of electrons present in \(^{37}Cl\) is 17.
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Develop a logical argument as to why television satellites, which broadcast information as electromagnetic radiation, can send signals from the vacuum of space?
Answers
The correct answer to this open question is the following.
Although you did not include options for this question, we can say the following.
Trying to be clear and concise, television satellites, which broadcast information as electromagnetic radiation, can send signals from the vacuum of space because electronic radiation can travel throughout space with no medium that transports it. Electronic radiation needs no material channel or medium to travel such as wires or cable.
That is how technology has developed wonders such as satellite communications for telephone, TV, or the internet. Information, data, sound, and images travel through transverse waves that easily move through the vacuum of space.
Electromagnetic radiations are defined as waves that do not require a medium for propagation. The EM waves have electric and magnetic vectors that do not require any medium to propagate.
The arguments can be explained as:
The Television antennae receive the signals in the form of electromagnetic waves.
The waves are transmitted from the satellites present in space. These waves are then transmitted to the TV station, where the information is then broadcasted. Other electronic devices such as cellular phones, computers, and FM radios have been developed using the propagation of the EM waves.
Thus, the EM waves do not require propagation due to which the signals can be easily transmitted from space.
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an automobile manufacturer claims that its product will travel 1.2 km in 20 s, starting from rest. what is the magnitude of the constant acceleration required to do this? answer in units of m/s 2 .
Answers
The amount of constant acceleration needed to accomplish this is:
6 m/s2.
What is constant acceleration?A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.
Given;
The car will drive a distance of d = 1.2 km
To convert 1.2 km to m
1.2 x 1000
= 1200 m.
beginning speed of the car, where u = 0.
Travel time, t = 20 s
To get the constant acceleration, use the following kinematic equation;
d = ut + ¹/₂at²
1200 = 0 + ¹/₂(20)²a
1200 = 400 /2
1200 = 200a
a = 1200 / 200
a = 6 m/s²
Therefore, 6 m/s² of constant acceleration is needed to accomplish this.
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The amount of constant acceleration needed to accomplish this is 6 m/s2.
What is constant acceleration?A velocity change that does not alter over time is referred to as a constant acceleration. A car's average acceleration remains steady at 20 mph per minute even if it increases its speed by 20 mph in one minute and another 20 mph the next.
Given;
The car will drive a distance of d = 1.2 km
To convert 1.2 km to m
1.2 x 1000
= 1200 m.
beginning speed of the car, where u = 0.
Travel time, t = 20 s
To get the constant acceleration, use the following kinematic equation;
d = ut + ¹/₂at²
1200 = 0 + ¹/₂(20)²a
1200 = 400 /2
1200 = 200a
a = 1200 / 200
a = 6 m/s²
Therefore, 6 m/s² of constant acceleration is needed to accomplish this.
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Please help, will give brainliest:
The spacecraft OSIRIS-REx is currently orbiting Bennu at an average distance from its center of mass of 1000 meters. At this distance, it takes 24 hours and 57 minutes to complete one orbit. What is its average orbital velocity?
Answers
Answer:
v = 0.0251 km/h
Explanation:
Given that,
The average distance from its center of mass of 1000 meters.
The time taken is 24 hours and 57 minutes to complete one orbit
We need to find the orbital velocity of the spacecraft OSIRIS-REx.Let it is v. SO,
\(v=\dfrac{2\pi r}{t}\)
Putting all the values,
\(v=\dfrac{2\pi \times 100}{24\ hours\ and\ 57\ minutes}\\\\v=\dfrac{2\pi \times 100}{(86400+3420)}\\\\v=0.00699\ m/s\)
or
v = 0.0251 km/h
So, the average orbital velocity is 0.0251 km/h.
Estimate the difference in air pressure between the top and the bottom of the Empire State building in New York City? It is 380 m tall and is located at sea level. Express as a fraction of atmospheric pressure at sea level.Express your answer using two significant figures.
Answers
A fraction of atmospheric pressure at sea level is 0.047.
Atmospheric pressure, also known as barometric strain, is the stress within the environment of Earth. the same old surroundings is a unit of stress described as one zero one,325 Pa, which is equal to 1013.25 millibars, 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.
Atmospheric sea level is known as
P sealevel = P atm = 1.01325*10^5 N/m^2
Now pressure at the bottom of empire state will be
P1 = 1.01325*10^5 N/m^2
Pressure at the top of empire state will be:
P2 = P1 - rho*g*h
rho = density of air = 1.29 kg/m^3
g = 9.81 m/sec^2
h = height of empire state = 380 m
P2 = 1.01325*10^5 - 1.29*9.81*380
P2 = 96516.138 N/m^2
Now
DeltaP = P1 - P2 = 1.01325*10^5 - 96516.138
DeltaP = 4808.862 N/m^2
So fraction will be:
N = DeltaP/Psealevel
N = 4808.862/1.01325*10^5
N = 0.04745 = 4.745*10^-2
In two significant figures
N = 4.7*10^-2 = 0.047
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at+waht+temperature+must+you+run+this+reaction+to+achieve+97%
Answers
Temperature is the degree of hotness or coldness of an object or substance. The SI unit of temperature is Kelvin."97%": The question suggests that a reaction must be run at a specific temperature to achieve 97% yield or completion. Yield refers to the amount of product obtained from a reaction.
To achieve 97% yield or completion, the reaction must be run at a specific temperature. Temperature plays an essential role in chemical reactions since it affects the rate of reaction, activation energy, and equilibrium. The temperature at which a reaction runs optimally, producing the most product, is known as the reaction's optimum temperature. As a result, the temperature must be controlled during a chemical reaction.To achieve 97%, the reaction must be run at a specific temperature.
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An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
Answers
When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
Let Va is the velocity of the airplane
Va is the velocity of the wind
When flying against the wind then
(Va+Vw)*(3.2 hours) = 640
3.2Va + 3.2Vw = 640
3.2Vw = 640 - 3.2Va
Vw = 200 - Va----------------(1)
When flying with the wind:
(Va-V)*(2 hours) = 640km
2Va - 2Vw = 640
Va - Vw = 320 ----------------(2)
Putting the value of VW in equation (2) we get
Va - (200-Va) = 320
2Va = 320 +200
2Va = 520
Va = 260
Putting this value in equation (2)
Vw =Va - 360
Vw = 100
Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
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A proton moves at 2.50 x 10^6 m/s horizontally at a right angle to a magnetic field. What is the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally
Answers
The strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is 0.0414 T.
Understanding Magnetic FieldTo balance the weight of the proton and keep it moving horizontally, we need to apply a magnetic field with a strength equal to the gravitational force acting on the proton.
The force experienced by a charged particle moving in a magnetic field is given by the formula:
F = q * v * B
where:
F is the magnetic force,
q is the charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.
The weight of the proton is given by the formula:
Weight = mass * acceleration due to gravity
Since the proton is moving horizontally, the gravitational force is balanced by the magnetic force. Therefore:
F = Weight
q * v * B = mass * acceleration due to gravity
Given the following constants:
charge of a proton (q) = 1.6 x 10⁻¹⁹ C,
mass of a proton (mass) = 1.67 x 10⁻²⁷ kg
acceleration due to gravity (g) = 9.8 m/s².
Substituting the known values into the equation, we can solve for the magnetic field strength (B):
B = (mass * gravitational acceleration) / (q * v)
B = (1.67 x 10⁻²⁷ kg * 9.8 m/s²) / (1.6 x 10⁻¹⁹ C * 2.50 x 10⁶ m/s)
B = 0.0414 T
Therefore, the strength of the magnetic field required to exactly balance the weight of the proton and keep it moving horizontally is approximately 0.0414 Tesla (T).
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What defines a mixture?
for sience
Answers
Hope this helps :)
3. nasa's asteroid sample return mission, osiris-rex, will be the first u.s. mission to return samples from the asteroid, bennu, to earth for further study. bennu absorbs most of the sunlight that hits it and later radiates this energy away as heat. this radiation gives bennu a tiny push, called the yarkovsky effect, which gradually changes its orbit over time. accurate measurements of the yarkovsky effect on bennu will be collected by precisely tracking osiris-rex as it orbits the asteroid. the factors that contribute to the yarkovsky effect are: a. composition, topography, gravitational forces, and radiative heat of sunlight b. composition, energy transport through the surface, temperature, and topography c. composition, luminosity, absolute magnitude, and temperature d. composition, chondrules, organic matter, and gravitational forces
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Composition, energy transport through the surface, temperature, and topography are the factors in asteroid that contribute to the yarkovsky effect.
The Yarkovsky effect is a result of the differential heating of an asteroid's sides by sunlight, which can cause a minor thrust force to be exerted. A spacecraft called OSIRIS-REx was launched by NASA in September 2016 with the goal of capturing and collecting samples from the asteroid Bennu. In October 2020, it made a successful landing on the asteroid. In addition to gathering an asteroid sample and bringing it back to Earth, OSIRIS-REx will study the Yarkovsky effect on Bennu in order to create viable methods for diverting asteroids that are headed straight for the planet.
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Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
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Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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The structure of an atom consists of ________.
A.
a proton surrounded by neutrons
B.
a nucleus surrounded by electrons
C.
a nucleus containing protons and electrons
D.
a "cloud" of protons, electrons, and neutrons
Answers
Answer:
The correct answer is B. a nucleus surrounded by electrons.
In the Constitution of Canada, it says that voting is everyone's duty and responsibility. What are the five most important elements of the Canadian electoral process that a newcomer should know about in terms of their responsibilities as a voter? Present your choices with explanations.
Answers
Explanation:
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ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
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Answers
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.