Answer:
x are 2,3,4,5,6. Y are -12,-15,-16,-15,-12 .
5) Cindy is catering a dinner for a conference with 225 guests. She plans to serve a
pasta course and figures she needs 6 oz of pasta per guest. How many pounds of
pasta will she need to order?
Answer:
Solution given;
total guest =225
She plans to serve 6 oz of pounds
we have
1 oz=0.0625 pounds
6oz=6*0.0625 =0.375 pounds
since
she serve 0.375 Pounds for each
225 guest needs =0.375*225=84.375 pounds
84.375 pounds of pasta will she need to order.
Milo's Ice Cream Factory sold more than 45 waffle cones yesterday. Which of the following inequalities represents the number of waffle cones Milo's Ice Cream Factory sold yesterday?
A.
x 45
D.
x < 46
Answer:
I believe the answer would be x<46
Answer:
I'm fairly sure that it would be D, or the final answer.
Step-by-step explanation:
Since he sold more than 45 waffle cones, x would not equal 45. This is why D is correct. Hope it helps!
The two-way table shows the number of ninth and tenth graders who prefer going to sporting events or going to the movies. Among tenth graders, what is the relative frequency of preferring sporting events? Express your answer as a decimal, and round it to the nearest hundredth if necessary. Enter your answer in the box. Sporting events Movies 9th graders 9 4 10th graders 6 8.
Relative frequency is the ratio of the number of times a data or outcome occurs to the total outcomes. The relative frequency among the tenth grades students of preferring sporting events round to the nearest tenth is 0.43.
Given information-
In the given table,
The number of ninth grade student who prefer going to sporting events is 9.
The number of ninth grade student who prefer going to movie is 4.
The number of tenth grade student who prefer going to sporting event is 6.
The number of tenth grade student who prefer going to movie is 8.
Relative frequencyRelative frequency is the ratio of the number of times a data or outcome occurs to the total outcomes. It can be calculated dividing the number of times an event occurs by the total number of times event occurs.
The total time the combined sporting event and the movies is preferred by the 10th grade student,
\(6+8=14\)
The total time the sporting event is preferred by the 10th grade student is 6. Thus among tenth graders students, the relative frequency \(f_r\) of preferring sporting events can be calculated as,
\(f_r=\dfrac{6}{14}\)
\(f_r=0.4285\)
Round to the nearest tenth,
\(f_r=0.43\)
Thus the relative frequency among the tenth grades students of preferring sporting events round to the nearest tenth is 0.43.
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for f(x)=x^2,sketch the graph of g(x)=f(-5x+10)
The graph of g(x) = f(-5x+10) is given in the figure.
What is a graph?A diagram showing the relation between two variable quantities,each measured along one of a pair of axes at right angles.
It is given that f(x) = x^2
and g(x ) = f(-5x+10)
Now putting the value of f(x) in g(x) we get,
g(x) = f(-5x+10) = (-5x+10)^2
So, g(x) = (-5x+10)^2
now, making the table for g(x),
x g(x)
0 100
1 81
2 0
3 25
4 100
5 225
Hence,the graph of g(x) = f(-5x+10) is given in the figure.
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Select the correct answer.
Which graph corresponds to the following inequality?
-2x - 3y < 6
The graph that correspond to the inequality is the graph in option D
How to know the corresponding graphsome interpretation on the information from the question include
shading above a line is greater than and shading below is less thandashed lines mean the inequality do not have "equal to"With the equation: -2x - 3y < 6. Bearing less than, using the guide above, we lookout for graph that have dotted line and shaded above the line
The quality described makes the 4th graph the correct option
other consideration is the intercept
the first equation at x= 0, -2x - 3y < 6 y < -2 (0, -2)
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Quadrilaterals HIJK and ABCD are congruent. The side length of each square on the grid is 1 unit. Which of the following sequences or transformations maps HIJK to ABCD?
The sequence of transformations that maps HIJK to ABCD is sequence B: reflection over line HÌ, then a translation 6 units to the right and 3 units down.
What is quadrilateral ?
A quadrilateral is a polygon with four sides and four vertices. The term "quadrilateral" comes from the Latin words "quadri" meaning "four" and "latus" meaning "side". Quadrilaterals can have different shapes and properties, including rectangles, squares, parallelograms, trapezoids, and kites.
Since quadrilaterals HIJK and ABCD are congruent, we can map one onto the other using a sequence of transformations. We need to determine which of the given sequences of transformations maps HIJK to ABCD.
Sequence A involves a 270° rotation about point J, followed by a translation 9 units to the right and 8 units down.
Sequence B involves a reflection over the line HÌ, followed by a translation 6 units to the right and 3 units down.
To determine which sequence maps HIJK to ABCD, we can apply each sequence to the vertices of HIJK and see if the resulting image matches the vertices of ABCD.
Starting with sequence A, we apply the rotation and translation to the vertices of HIJK:
Vertex H(-2, 1) is rotated 270° about J(-2, 2) to get H'(0, 0). Then we translate 9 units to the right and 8 units down to get H''(9, -8).
Vertex I(-3, -1) is rotated 270° about J(-2, 2) to get I'(1, -3). Then we translate 9 units to the right and 8 units down to get I''(10, -11).
Vertex J(-2, 2) is fixed by the rotation and then translated 9 units to the right and 8 units down to get J''(7, -6).
Vertex K(0, 0) is rotated 270° about J(-2, 2) to get K'(-2, -2). Then we translate 9 units to the right and 8 units down to get K''(7, -10).
The resulting image of HIJK under sequence A has vertices H''(9, -8), I''(10, -11), J''(7, -6), and K''(7, -10). We can see that these vertices do not match the vertices of ABCD, so sequence A does not map HIJK to ABCD.
Next, we apply sequence B to the vertices of HIJK:
Vertex H(-2, 1) is reflected over line HÌ to get H'(-4, 3). Then we translate 6 units to the right and 3 units down to get H''(2, 0).
Vertex I(-3, -1) is reflected over line HÌ to get I'(-1, 1). Then we translate 6 units to the right and 3 units down to get I''(5, -2).
Vertex J(-2, 2) is reflected over line HÌ to get J'(-4, 4). Then we translate 6 units to the right and 3 units down to get J''(2, 1).
Vertex K(0, 0) is reflected over line HÌ to get K'(-2, 2). Then we translate 6 units to the right and 3 units down to get K''(4, -1).
The resulting image of HIJK under sequence B has vertices H''(2, 0), I''(5, -2), J''(2, 1), and K''(4, -1). We can see that these vertices match the vertices of ABCD, so sequence B maps HIJK to ABCD.
Therefore, the sequence of transformations that maps HIJK to ABCD is sequence B: reflection over line HÌ, then a translation 6 units to the right and 3 units down.
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Two friends are planning for a gathering. The food budget is modeled by one half times the absolute value of the quantity x minus 110 end quantity equals 6 comma where x is the amount spent on food. What are the least and greatest amounts that the two friends could spend on food?
$98, $122
$104, $116
$107, $113
$110, $122
Answer:
If im not wrong It's the second option
$104, $116
Step-by-step explanation:
Hope this helped !!
Using the absolute value function, the least and greatest amounts that the two friends could spend on food are $98 and $122. so A choice is correct.
What is the absolute value function?The absolute value function is defined by:
f(x) = x, x ≥ 0.
f(x) = x, x < 0.
Hence, the example of the function is:
|x| = a means that x = a or x = -a.
In this given problem, the equation is:
0.5|x - 110| = 6.
Then, removing the 0.5:
|x - 110| = 6/0.5
|x - 110| = 12.
Applying the definition of the absolute value function, we have that
x - 110 = -12 or x - 110 = 12.
For the least amount, we have that;
x - 110 = -12 -> x = $98.
For the greatest amount, we have that;
x - 110 = 12 -> x = $122.
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Which is a simplified form of the expression -6a + 2(2a + 2)?
A.-2a + 4
B. -2a - 4
C. 2a + 4
D. 2a - 4
Answer:
-2a +4
Step-by-step explanation:
-6a + 2(2a + 2)
Distribute
-6a +4a +4
Combine like terms
-2a +4
Answer:
Answer A is correct
Step-by-step explanation:
First Solve the brackets
\( - 6a + 2(2a + 2) \\ - 6 a+ 4a + 4\)
Then combine like terms
\( - 6 a+ 4a + 4 \\ - 2 a + 4\)
A small business celebrates serving 5,110 customers in there first year of business how many customers did they average each day?
Answer:
14
Step-by-step explanation:
Average means the amount over days. So 5110/365 days is 14 customers average each day.
Answer:
14 customers per day on average.
Step-by-step explanation:
number of customers (5,110) divided by days in a year (365) is 14.
pls help me with this
Answer:
Step-by-step explanation:
Jenn is the fastest swimmer.
Time and speed is inverse proportion. If speed is more, the time taken will be less. So, who takes less time will be the fastest swimmer
We can tell from the table that Jenn is the fastest swimmer. She has the lowest time and fastest speed
solve The Following Using The Distributive Property
(-75) x173+173x(-25)
Answer:
Step-by-step explanation:
(-75) x173+173x(-25)
173(-75-25)
173(-100)
-17300
What’s the y & x for this?
according to the energy information association (eia.doe.gov), the price per gallon of unleaded gasoline in the gulf coast region as of 09/23/19 is normally distributed with a mean of $2.25 and standard deviation of $0.12. suppose you take a random sample of 100 gas stations in the gulf south. what is the probability that the average price per gallon is between $2.22 and $2.28? select one: 0.8164 0.8904 0.7458 none of these are correct. 0.9876
The probability that the average price per gallon of unleaded gasoline is between $2.22 and $2.28 in the Gulf Coast region is 0.8164.
To find the probability, we can use the Central Limit Theorem, which states that the sampling distribution of the sample mean approaches a normal distribution, regardless of the shape of the population distribution, when the sample size is sufficiently large.
In this case, we are given that the population of unleaded gasoline prices in the Gulf Coast region is normally distributed with a mean of $2.25 and a standard deviation of $0.12. Since we have a sample size of 100, which is considered large, we can assume that the sample mean will be approximately normally distributed.
To find the probability that the average price per gallon is between $2.22 and $2.28, we need to standardize the values using the z-score formula:
z = (x - μ) / (σ / √n),
where x is the desired value, μ is the mean, σ is the standard deviation, and n is the sample size.
For $2.22:
z1 = (2.22 - 2.25) / (0.12 / √100) = -0.03 / 0.012 = -2.5.
For $2.28:
z2 = (2.28 - 2.25) / (0.12 / √100) = 0.03 / 0.012 = 2.5.
Next, we need to find the cumulative probability associated with these z-scores using a standard normal distribution table or calculator. The probability between these two z-scores represents the probability that the average price falls within the specified range.
Using a standard normal distribution table or calculator, we find that the probability of a z-score between -2.5 and 2.5 is approximately 0.8164.
Therefore, the correct answer is 0.8164.
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Question 1
Answer
Solve 4/9 - 4/10
Answer:
4/90
Step-by-step explanation:
4/9 - 4/10
40/90 - 36/90
4/90
Answer:
4/90
Step-by-step explanation:
butterfly method:
4 * 10 = 40.
4 * 9 = 36.
40 - 36 = 4.
= 4/90.
hope this helps.
a) Determine the minimum extrusion force (F) required to carry out this operation. Hence determine whether a 200 tonne (∼2×106 N) capacity extruder is capable of carrying out this extrusion. Assume that the volume of the material stays constant. The appropriate homogeneous work model equation is: F=σyA0lnI1/ I0 In the above equation: A0= Cross-sectional area before extrusion I1= Length after extrusion I0= Length before extrusion Question 7 An aluminium billet with a yield strength (σy) of 130MPa is to be hot extruded from a diameter of 80 mm down to a diameter of 20 mm.
The extruder capacity is 2x10^6 N, which is greater than |F|, so the 200-tonne extruder is capable of carrying out this extrusion process.
To determine the minimum extrusion force (F) required for the hot extrusion process, we can use the homogeneous work model equation:
F = σyA0ln(I1/I0)
Given:
Diameter before extrusion (D0) = 80 mm
Diameter after extrusion (D1) = 20 mm
Yield strength (σy) = 130 MPa
First, we need to calculate the cross-sectional areas before and after extrusion.
A0 = π(D0/2)^2
A1 = π(D1/2)^2
Substituting the values, we get:
A0 = π(80/2)^2
= π(40)^2
= 1600π mm^2
A1 = π(20/2)^2
= π(10)^2
= 100π mm^2
Next, we need to calculate the lengths before and after extrusion.
I0 = π(D0)^2
I1 = π(D1)^2
I0 = π(80)^2
= 6400π mm
I1 = π(20)^2
= 400π mm
Now, we can substitute the values into the equation:
F = σyA0ln(I1/I0)
= (130 MPa)(1600π mm^2)ln(400π mm / 6400π mm)
Simplifying:
F = (130 MPa)(1600π mm^2)ln(1/16)
= (130 MPa)(1600π mm^2)(-2.7726)
≈ -719932.12π MPa mm^2
Therefore, the minimum extrusion force required is approximately -719932.12π MPa mm^2.
To determine whether a 200-tonne (2x10^6 N) capacity extruder is capable of carrying out this extrusion, we need to convert the force to newtons:
F (in newtons) = -719932.12π MPa mm^2 * 1 N/1 MPa mm^2
= -719932.12π N
Since the force is negative, we can take the absolute value to compare it with the extruder capacity:
|F| ≈ 719932.12π N
The extruder capacity is 2x10^6 N, which is greater than |F|, so the 200-tonne extruder is capable of carrying out this extrusion process.
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per's debate team at thunderbird high sclusel, 20% of the members are sophomores, 39% arts and the closing argent, the team has a probability of 0 253 of winning the debute. if a junior gives that closing argument, the probabilay of if or cloons, the probability of winning is 083 (4) find the probability that the tests wins the debate (b) describe the design of a simulation to estimate the probability that a sophomore is never selected to give the closing argument in the next 3 debutes explain clearly how you would use a table of random digits to carry out the simulation (e) the dotplot below shows the number of sophomores chosen in 50 simulated sets of 5 debates in which 20% of the time a sophomore is selected and 80% of the time a junior or senice is selected to give the closing argument for the team in the next 5 debates, a sophomore was never chosen to give the closing argument. the sophomores on the team claim that they were purposely ignored. use the results of the simulation to determine if there is convincing evidence that the sophomores were purposely ignored.
Here to solve the probability of this sum, it is difficult to say that the probability without no information.
(a)The probability that the team wins the debate with a junior giving the closing argument is 0.083.
(b) To design a simulation to estimate the probability that a sophomore is never selected to give the closing argument in the next 3 debates, one could randomly assign a closing argument speaker for each debate using a table of random digits. The table would have two columns: one for sophomores and one for juniors and seniors. The probability of a sophomore being selected would be 20%, and the probability of a junior or senior being selected would be 80%. The simulation would be run for 3 debates and the number of times a sophomore is never selected would be recorded. This process would be repeated a number of times to estimate the probability of a sophomore never being selected. (e) Based on the dot plot, it appears that there is some evidence that the sophomores were purposely ignored, as there are several simulated sets of 5 debates where a sophomore was not selected to give the closing argument. However, without more information, it is difficult to say for certain if this is enough evidence to support the claim that the sophomores were purposely ignored.
A larger sample size or a more detailed analysis of the simulation results may be needed to make a more convincing determination.
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The table below shows the results of a survey that asked 1052 adults from a certain country if they favored or opposed a tax to fund education. A person is selected at
random. Complete parts (a) through (c).
(a) Find the probability that the person opposed the tax or is female.
P(opposed the tax or is female) =
(Round to the nearest thousandth as needed.)
(b) Find the probability that the person supports the tax or is male.
P(supports the tax or is male) =
(Round to the nearest thousandth as needed.)
(c) Find the probability that the person is not unsure or is female.
P(is not unsure or is female)=
(Round to the nearest thousandth as needed.)
The complete options are P(opposed the tax or is female) = 0.28, b. P(supports the tax or is male) = 0.15, c. P(is not unsure or is female) 0.025.
What is the probability?Probability refers to a possibility that deals with the occurrence of random events.
(a) The probability that the person opposed the tax or is female.
P(opposed the tax or is female) = 298 / 1052 = 0.28
(b) The probability that the person supports the tax or is male.
P(supports the tax or is male) = 168/1052 = 0.15
(c) The probability that the person is not unsure or is female.
P(is not unsure or is female) = 27 / 1052 = 0.025
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A player kicks a soccer ball off of the ground. The height of the ball is modeled by the equation h(t)=-\frac34\left(t-4\right)^2+12h(t)=− 3/4 (t−4)^2 +12.
After how many seconds does the ball hit the ground?
Answer:
Step-by-step explanation:
We can solve this in either of two approaches: Mathematically or Graphically.
Mathematically
y=-(3/4)(x-4)^2+12 where y is the height of the ball, and x is the time, in seconds.
We want to know how many seconds for the height to be 0, so y=0.
0 = -(3/4)(x-4)^2+12
-12 = -(3/4)(x-4)^2
12*(4/3) = (x-4)^2
16 = (x-4)^2
x = 8 and 0 (the initial point).]
It will reach the ground in 8 seconds
Graphically
Plot the function and find the time, x, when the graph passes through the x axis (after t = 0). Attached.
Refer to the drawing below. Which of the following fractions results when the area
of triangle ABC is divided by the area of the square?
a. 2/3
b. 1/4
c. 1/3
d. 1/2
e. 3/4
Answer:
Step-by-step explanation:
a
2 Write the equation of the line that goes
through (-2, 4) and is parallel to the line y = 1/2 x + 2
hi
if the twi lines are parallel , they have the same slope.
So slope is 1/2.
equation of a line is : mx +p
The line goes throught (-2 ; 4)
We have 1/2 ( -2) + p = 4
- 2/2 +p = 4
-1 +p = 4
p = 4+1
p = 5
equation of the line is y = 1/2x +5
Define Chi square test OR Tests of significance based on Chi-Square. A: -Various tests of significance described previously have mostly applicable to only quantitative data and usually to the data which are approximately normally distributed. It may also happens that we may have data which are not normally Inference: (i) If Z0 ≤ Ze we accept the H0 (ii) If Z0 >Ze we reject the H0 Example: A test of the breaking strengths of two different types of cables was conducted using samples of n1 = n2 = 100 pieces of each type of cable. Do the data provide sufficient evidence to indicate a difference between the mean breaking strengths of the two cables? Use 0.01 level of significance. x = 1925 and sigm = 40 and X2 = 1905, sigma = 30
The Chi-square test is a statistical test used to determine if there is a significant difference between observed and expected frequencies in categorical data. In this example, the test is used to assess whether there is a significant difference in the mean breaking strengths of two types of cables.
The Chi-square test of significance is employed when dealing with categorical or nominal data. It compares the observed frequencies with the frequencies that would be expected if the variables were independent. In this case, the breaking strengths of the two cables are the variables of interest.
To perform the test, the first step is to define the null hypothesis (H0) and the alternative hypothesis (Ha). In this example, H0 assumes that there is no difference in the mean breaking strengths of the two cables, while Ha suggests that there is a difference.
Next, the test statistic, denoted by X2 (chi-square), is calculated using the formula X2 = Σ[(O - E)²/E], where O represents the observed frequencies and E represents the expected frequencies under the assumption of independence.
To determine the expected frequencies, we need to estimate the means and variances of the breaking strengths. Here, x = 1925 and sigma = 40 for the first cable, and x = 1905 and sigma = 30 for the second cable.
Once the test statistic is calculated, it is compared to a critical value from the Chi-square distribution with degrees of freedom equal to (r - 1)(c - 1), where r is the number of rows and c is the number of columns in the contingency table. The significance level of 0.01 determines the critical value.
If the calculated X2 value is greater than the critical value, we reject the null hypothesis and conclude that there is sufficient evidence to indicate a difference in the mean breaking strengths of the two cables. Conversely, if the calculated X2 value is less than or equal to the critical value, we fail to reject the null hypothesis and conclude that there is no significant difference.
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Find the value of x and the indicated angles.
Answer:
x = 33Indicated angles: 126°Step-by-step explanation:
We can tell that 4x - 6 is equal to 2x + 60 because they are vertically opposite angles. Now, let's solve.
=> 4x - 6 = 2x + 60=> 4x - 2x = 6 + 60=> 2x = 66=> x = 33Since we have found the required variable, we can now solve the indicated variables.
Given angles:
4(33) - 62(33) + 60Let's solve 4(33) - 6 first.
4(33) - 6132 - 6126Therefore, 4(33) - 6 measures about 126°. Now, let's solve 2(33) + 60.
2(33) + 6066 + 60126We can clearly see that both angles are equal (126 = 126) Because of vertically opposite angles.
Conclusion:
Therefore, the required variable is 'x = 33' and when we substitute the variable in both angles, we find that both angles show 126°.
Hoped this helped.
\(BrainiacUser1357\)
Adapt the proof in the text that there are infinitely many primes to prove that there are infinitely many primes of the form 3k + 2, where k is a nonnegative inte- ger. (Hint: Suppose that there are only finitely many such primes 91,92, ..., In, and consider the number 39192 ... 9n – 1.]
We must conclude that there are infinitely many primes of the form 3k + 2, where k is a non-negative integer.
To adapt the proof:
We can use a similar contradiction argument.
Suppose that there are only finitely many primes of the form 3k + 2, say p1, p2, ..., pn.
Let N = 3p1p2...pn + 2. Note that N is of the form 3k + 2 for some non-negative integer k.
Now, let's consider the prime factorization of N. Either N is prime and of the form 3k + 2, in which case we have found a new prime of the desired form, contradicting our assumption that there are only finitely many such primes. Or, N is composite and has a prime factorization consisting only of primes of the form 3k + 1 (since any prime of the form 3k + 2 would divide N). But this implies that N itself is of the form 3k + 1.
Now, let's consider the number M = 3N + 2. M is also of the form 3k + 2, and so must have a prime factorization consisting only of primes of the form 3k + 1. But since N is of the form 3k + 1, we have
M = 3(3p1p2...pn + 1) + 2 = 9p1p2...pn + 5. This means that M has a prime factorization consisting of primes of the form 3k + 2, which contradicts our assumption that there are only finitely many such primes.
Therefore, we must conclude that there are infinitely many primes of the form 3k + 2, where k is a non-negative integer.
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A rectangular box has a square base with a edge length of X cm and a height of h cm. The volume of the box is given by V = x^2× H cm^3. Find the rate at which the volume of the box is changing when the edge length of the base is 12 cm, that edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
Answer: To find the rate at which the volume of the box is changing, we need to find the derivative of the volume with respect to time, which is the rate of change of the volume with respect to time.
The volume of the box is given by the equation:
V = x^2 * h
To find the rate of change of the volume, we need to find the derivative of this equation with respect to time:
dV/dt = d/dt (x^2 * h)
= 2x * dx/dt * h + x^2 * dh/dt
At the moment when the edge length of the base is 12 cm and the height of the box is 6 cm, we can substitute the values into the equation:
dV/dt = 2 * 12 * (-2) * 6 + 12^2 * 1
= -144 + 144
= 0
So the rate at which the volume of the box is changing is 0 cm^3/min, which means the volume of the box is not changing.
Step-by-step explanation:
At Sascha's Salad Bar, customers make their own salads and pay by the ounce. Jenny paid $6.16 for a 22-ounce salad. How much would a 16-ounce salad cost?
Answer:
I think it is 4.48.
Explain:
6.16/22 is 0.28 Then 0.28 times 16 is 4.48.
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Find the following for f(r) = x^3 - 12.r:
All critical points with (.. y) coordinates.
To find the critical points of the function f(x) = x^3 - 12x and their corresponding y-coordinates, we need to determine the values of x where the derivative of the function is equal to zero.
To find the critical points, we first calculate the derivative of f(x) with respect to x, which is f'(x) = 3x^2 - 12. Then, we set f'(x) equal to zero and solve for x:
3x^2 - 12 = 0
Simplifying the equation, we get:
x^2 - 4 = 0
Using the quadratic formula or factoring, we find that x = 2 and x = -2 are the solutions. These are the x-coordinates of the critical points.
To determine the y-coordinates, we substitute these x-values back into the original function:
For x = 2, y = f(2) = (2)^3 - 12(2) = -16
For x = -2, y = f(-2) = (-2)^3 - 12(-2) = 16
Therefore, the critical points of f(x) = x^3 - 12x are (2, -16) and (-2, 16), where the x-coordinate represents the critical point and the y-coordinate represents the corresponding value of the function at that point.
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A pair of jeans was 30% off the original price. The sale resulted in a $24 discount. What is the original price in a percent?
Answer:
16%
Step-by-step explanation:
$16.8
what is the absolute value of 1 1/4 and -11/6
The difference of the square of a number and 36 is equal to 5 times that number. Find the negative solution.
The Negative solution is -4 or Negative number is -4
The difference of the square of a number and 36 is equal to 5 times that number.
To find the negative solution.
Now, According to the question:
Let the unknown number be = x
Given that:
\(x^{2} -36 = 5x\\\\x^{2} -5x-36=0\\\)
Factories the above Equation:
\(x^{2} -9x+4x-36=0\\\\\)
x (x - 9) + 4 (x - 9) = 0
(x + 4) (x - 9 ) = 0
x + 4 = 0 and x - 9 = 0
x = -4 and x = 9
Hence, The Negative solution is -4
What is Factories Method?
Factorization is the process of reducing the bracket of a quadratic equation, instead of expanding the bracket and converting the equation to a product of factors which cannot be reduced further.
Learn more about Factorization at:
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Is A triangle with side lengths 24,32, 42 a right angle?
Answer:
No its not a right angle.