Answer:
(f+g)(2)=5
Step-by-step explanation:
Subsitute 2 in for x in both functions. Then add the answers of the functions together.
Box of 24 chocolate contains 6 cream-filled. What is the probability of randomly selecting a cream filled
Chocolate
The probability of randomly selecting a cream filled
Chocolate is 1/4
Probability is the likelihood of an event will occur Probability of an event is find out by divide the number of favorable outcomes by the total number of possible outcomes. The simplest example is flipping of a coin. There are only two possible outcomes when you flip a coin. It wiil be either heads or tails.Total probability is always lie between 0 and 1Let E be the event of selecting cream filled chocolate.
Number of favourable outcome = 6
Total number of possible outcome = 24
Probability if selecting a cream filled chocolate = 6/24
= 1 / 4
Hence, the probability of randomly selecting a cream filled chocolate is 1/4
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If the Length of Rectangle is 12 cm and the Breadth is 10 cm . Find its Area .
Answer:
120 cm^2
Step-by-step explanation:
The area of a rectangle is it's length(l) times its width(w):
Area = l*w
Area = (12 cm)*(10 nm) = 120 cm^2
Question :-
If the Length of Rectangle is 12 cm and the Breadth is 10 cm . Find its Area .Answer :-
Area of Rectangle is 120 cm² .\( \rule {180pt} {2pt} \)
Given :-
Lenght of Rectangle = 12 cmBreadth of Rectangle = 10 cmTo Find :-
Area of Rectangle = ?Solution :-
As per the provided information in the given question, we have been given that the Lenght of Rectangle is 12 cm . Breadth of Rectangle is given 10 cm . And, we have been asked to calculate the Area of Rectangle .
For calculating the Area , we will use the Formula :-
\( \sf {Area \: of \: Rectangle = Lenght \times Breadth} \)Therefore , by Substituting the given values in the above Formula :-
⇒ Area of Rectangle = Lenght × Breadth
⇒ Area of Rectangle = 12 × 10
⇒ Area of Rectangle = 120
Hence :-
Area of Rectangle = 120 cm² .\( \underline {\rule {180pt} {4pt}} \)
in a randomized controlled experiment question content area bottom part 1 a. you control for random answers b. the control group receives treatment on even days only. c. you control for the effect that random numbers are not truly randomly generated d. there is a control group and a treatment group.
In a randomized controlled experiment, there is a control group and a treatment group.
This statement is i.e. option d is correct.
Randomized controlled experiments are commonly used in scientific research, particularly in medicine and psychology.
They are used to determine whether a treatment or intervention is effective or not.
In a randomized controlled experiment, the participants are randomly assigned to either the control group or the treatment group.
The control group is used as a comparison group and does not receive the treatment or intervention.
The treatment group, on the other hand, receives the treatment or intervention being studied.
There are several ways that a randomized controlled experiment can be designed to minimize the potential for bias. For example, in a randomized controlled experiment, random assignment of participants to groups helps to ensure that the two groups are similar at the outset of the study.
This reduces the likelihood that differences between the groups will be due to factors other than the treatment or intervention being studied.
Other ways that a randomized controlled experiment can be designed to minimize bias include blinding and use of placebos.
Blinding refers to the practice of keeping certain participants, such as those administering the treatment, unaware of which group a participant is in.
This helps to ensure that any differences between the two groups are not due to the expectations of the researchers or participants.
Use of placebos is another way to reduce bias in a randomized controlled experiment.
Placebos are inactive substances that are given to the control group to mimic the treatment group, ensuring that any differences between the groups are due to the treatment being studied and not other factors.
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which graph shows the solution to the system of linear equations?
y=-1/3x+1
y=-2x-3
y = -1/3x + 1
y = -2x - 3
We can compare the equations to the graphs and see which graph represents the intersection point of the two equations.
The first equation, y = -1/3x + 1, has a negative slope (-1/3) and a y-intercept of 1.
The second equation, y = -2x - 3, also has a negative slope (-2) and a y-intercept of -3.
Based on the slopes and y-intercepts, we can identify the correct graph by finding the point where the two lines intersect.
Unfortunately, since the graphs are not provided, I am unable to determine which specific graph shows the solution to the system of linear equations. I recommend referring to the graph representation of the equations and identifying the intersection point to determine the correct graph.
I do not know the answer to this question. I need help
Answer:
(-6,-4)
Step-by-step explanation:
write 7.171717 as a mixed number
Answer:
7 17/99
Step-by-step explanation:
What is the value today of a money machine that will pay $4,161.00 per year for 23.00 years? Assume the first payment is made one year from today and the interest rate is 15.00%. Answer format: Currency: Round to: 2 decimal places.
the value today of the money machine is approximately $29,499.48.
The formula to calculate the present value of an annuity is:
PV = C * (1 - (1 + r)^(-n)) / r
PV is the present value
C is the cash flow per period
r is the interest rate per period
n is the number of periods
Cash flow per year (C) = $4,161.00
Number of years (n) = 23.00
Interest rate (r) = 15.00%
First, let's convert the annual interest rate to a decimal and calculate the interest rate per period:
r = 15.00% / 100 = 0.15
PV = $4,161.00 * (1 - (1 + 0.15)^(-23)) / 0.15
Using a calculator, we find that the present value (PV) is approximately $29,499.48.
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On its municipal website, the city of Tulsa states that the rate it charges per 5 CCF of residential water is $21.62. How do the residential water rates of other U.S. public utilities compare to Tulsa's rate? The data shown below ($) contains the rate per 5 CCF of residential water for 42 randomly selected U.S. cities.10.38 9.08 11.7 6.4 12.32 14.43 15.4610.02 14.4 16.08 17.5 19.08 17.88 12.7516.7 17.25 15.54 14.7 18.81 17.89 14.818.32 15.95 26.75 22.22 22.66 20.88 23.3518.95 23.6 19.16 23.65 27.7 26.95 27.0426.89 24.58 37.76 26.41 38.91 29.36 41.55(a)Formulate hypotheses that can be used to determine whether the population mean rate per 5 CCF of residential water charged by U.S. public utilities differs from the $21.62 rate charged by Tulsa. (Enter != for ≠ as needed.)H0:Ha:(b)What is the test statistic for your hypothesis test in part (a)? (Round your answer to three decimal places.)What is the p-value for your hypothesis test in part (a)? (Round your answer to four decimal places.)(c)At α = 0.05, can your null hypothesis be rejected? What is your conclusion?Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.(d)Repeat the preceding hypothesis test using the critical value approach.State the null and alternative hypotheses. (Enter != for ≠ as needed.)H0:Ha:Find the value of the test statistic. (Round your answer to three decimal places.)State the critical values for the rejection rule. Useα = 0.05.(Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused tail.)test statistic≤test statistic≥State your conclusion.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Do not reject H0. The mean rate per 5 CCF of residential water throughout the United States does not differ significantly from the rate per 5 CCF of residential water in Tulsa.Reject H0. The mean rate per 5 CCF of residential water throughout the United States differs significantly from the rate per 5 CCF of residential water in Tulsa.
The null hypothesis for the data will be 21.62 and the alternate hypothesis is 2.02 for the p-value for the data is 0.2253 .
The charge at which anything happens is referred to as the velocity at which it happens.
The required details for mean rate :
(a) H0: µ = 21.62
Ha: µ ≠ 21.62
(b) t = -1.231
p-value = 0.2253
(c) Stop rejecting H0 right now. No longer significantly different from the domestic water tariff in Tulsa, the suggested household water charge per five CCF for the entire USA.
(d) H0: µ = 21.62
Ha: µ ≠ 21.62
t = -1.231
check statistic ≥ 2.020
Don't dismiss H0 any longer. The suggested five CCF residential water charge for the entirety of the USA is no longer significantly different from the five CCF residential water tariff in Tulsa.
The P-value is higher at 0.05, the level of significance. The impact in this instance is negligible. The attempt to reject the null hypothesis failed.
The conclusion is that there is insufficient statistical support to determine whether other American cities have a different mortality rate than Tulsa.
The crucial values for t at this level of significance are t=2.019.
Given that the statistic t = -1.15 is inside the acceptance range in this case, the null hypothesis is not disproved.
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What is the surface area of the cylinder with height 7 mi and radius 4 mi? Round to the nearest thousandth
Answer:
Refer to the attached file
Hope it helps...
Have a great day :P
Anyone know the answer to this? simplify -2/5 + 4/3
Answer:
Step-by-step explanation:
-2/5 +4/3
Find common denominator
-2/5; so 5x3=15 4/3; so 3x5=15
what you do to the bottom you must do to the top
-2x3=-6 and 4x5=20
your new fractions would be;
-6/15 + 20/15=
14/15
A sum is invested in a building society at 4% interest per annum and after 3 years
the value of the investment is £562.43. How much was originally invested?
Answer:
Original value of investment = £500 (Approx.)
Step-by-step explanation:
Given:
Rate per year = 4%
Number of year = 3 years
Value of investment after 3 year = £562.43
Find:
Original value of investment
Computation:
A = P[1+r]ⁿ
562.43 = P[1+4%]³
562.43 = P[1+0.04]³
562.43 = P[1.04]³
562.43 = P[1.1248]
Original value of investment = 562.43 / 1.1248
Original value of investment = 500.026
Original value of investment = £500 (Approx.)
A + B + C = 12
4A - 4B + 2C = -16 -
3A + 3B - C = 4
Solve the system
Answer:
Step-by-step explanation:
Add them all together which is
ABC124A4B2C-16-3A3B-C yep
researcher wishes to estimate within $300 the true average amount of money a county spends on road repairs each year. the population standard deviation is known to be $900. how large a sample must be selected if she wants to be 90% confident in her estimate?
Estimated large sample size need to be selected for the 90% of confidence level with standard deviation of $900 is equal to 24.
Standard deviation = $900
Confidence level = 90%
Estimate the required sample size,
Use the formula for the margin of error,
Margin of Error = Z × (standard deviation / √(sample size))
where Z is the z-score corresponding to the desired level of confidence.
Using attached z-score table,
For 90% confidence level, Z = 1.645.
Rearrange the formula to solve for the sample size,
Sample size = (Z × standard deviation / margin of error) ^ 2
Substituting the given values, we get,
⇒ Sample size = (1.645 × 900 / 300) ^ 2
⇒ Sample size = 24.35
Round up to the nearest whole number = 24
Therefore, need a sample size of at least 28 to ensure that it is large enough to achieve the desired level of confidence level.
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If a chi-square goodness of fit test ends in a significant result it means that the expected frequencies are significantly different than the observed frequencies.
a) True
b) False
The statement given "If a chi-square goodness of fit test ends in a significant result it means that the expected frequencies are significantly different than the observed frequencies." is true because because if a chi-square goodness of fit test ends in a significant result, it means that the expected frequencies are significantly different from the observed frequencies.
The chi-square goodness of fit test is a statistical test used to determine if observed categorical data follows an expected distribution. It compares the observed frequencies in different categories with the expected frequencies based on a specified distribution or hypothesis.
If the test yields a significant result, it indicates that there is a significant difference between the observed frequencies and the expected frequencies. In other words, the data does not fit the expected distribution, and there is evidence to suggest that the observed frequencies are not simply due to chance.
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What is the quotient 3x3 10x2 10x 4 )/( x 2?.
After solving, the quotient (3x^3 + 10x^2 + 10x + 4) ÷ (x + 2) is 3x^2 + 4x + 2.
In the question, we have to find the quotient (3x^3 + 10x^2 + 10x + 4) ÷ (x + 2).
The polynomial is 3x^3 + 10x^2 + 10x + 4.
We have to divide the given equation by x + 2 to find the quotient.
Four operations, namely divide, multiply, subtract, and bring down, can be used to break down the division process into phases.
1: Find the appropriate integer to use as the divisor for the given number.
2: Multiply the integer (quotient) and divisor to obtain the amount to be deducted from the payout.
3: Deduct the amount from the dividend.
4: Bring down the balance and any additional digits from the dividend in step four.
5: Continue the procedure outlined above until the remainder equals zero or less than the divisor.
x+2 ) 3x^3 + 10x^2 + 10x + 4 ( 3x^2 + 4x + 2
3x^3 + 6x^2
- -
___________
4x^2 + 10x
4x^2 + 8x
- -
______________
2x + 4
2x + 4
- -
____________
0
Hence, the quotient (3x^3 + 10x^2 + 10x + 4) ÷ (x + 2) is 3x^2 + 4x + 2.
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The complete question is:
What is the quotient (3x^3 + 10x^2 + 10x + 4) ÷ (x + 2)?
Create another line perpendicular to AB passing through C on AB. Measure the angle at the intersection to verify your result. Take a screenshot of your work, and paste it below.
Line passing through AB is perpendicular. A pair of angles that are linear have an angle sum of 180 degrees. The lines are therefore shown to be perpendicular to one another because the angles are 90 degrees in size.
Define perpendicular.Two lines intersect to generate perpendicular lines, and the angle formed between the two lines must be 90 degrees (right angle).
Given,
Create another line perpendicular to AB passing through C on AB..
Line passing through AB is perpendicular.
Two lines are perpendicular if they cross at a point where a pair of linear congruent angles results. In a plane, a transversal is perpendicular to the other line if it is parallel to one of the two parallel lines.
A pair of angles that are linear have an angle sum of 180 degrees. The lines are therefore shown to be perpendicular to one another because the angles are 90 degrees in size. The linear pair perpendicular theorem is demonstrated by this.
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(a) what is the probability that the first sample following the mean shift produces a statistics that plots inside the control limits?
The probability that the first sample following the mean shift produces a statistics that plots inside the control limits: β ^{m-1}( 1-β )
What is Probability?
The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.
Pr(shift found on mth sample) = Pr (not detected for (m-1) samples) x Pr (detected on mth)
= [ 1-(1-β) ]^{m-1} ( 1-β )
=β ^{m-1}( 1-β )
the anticipated number of subgroups to be examined before the shift is seen
ARL=1/{1-β}
Shift not detected on the first sample following the shift:
Pr = 1-(1-β) = β
Pr n successive samples that are outside of the control limits
= ( 1- β )^{n}
f) the likelihood that at least one out of n consecutive statistical plots will fall outside the control limit.
=[1- ( 1- β )]^{n}
=β^{n}
Hence, The probability that the first sample following the mean shift produces a statistics that plots inside the control limits is β ^{m-1}( 1-β )
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For each equation, explain what you could do first to each side of the equation so that there would be no fractions.
To simplify the equations so that there would be no fractions, we
1. Multiply both sides by 8
2. Multiply both sides by 12
3. Multiply both sides by 10
4. Multiply both sides by 30
Simplifying an equation so that there would be no fractionsFrom the question, we are to determine what we could do first to each side of the equations so that there would be no fraction
1. (4x -4)/8 = (x +2)/4
Multiply both sides by the LCM of the denominators
The denominators are 8 and 4
The LCM of 8 and 4 is 8
Thus,
Multiply both sides by 8
8 × (4x -4)/8 = 8 × (x +2)/4
4x -4 = 2(x +2)
2. 3(4 - r)/6 = (4 + r) /4
Multiply both sides by the LCM of the denominators
The denominators are 6 and 4
The LCM of 6 and 4 is 12
Thus,
Multiply both sides by 12
12 × 3(4 - r)/6 = 12 × (4 + r) /4
2 × 3(4 - r) = 3(4 + r)
6(4 - r) = 3(4 + r)
3. (5q + 3)/10 = (q + 2)/5
Multiply both sides by the LCM of the denominators
The denominators are 10 and 5
The LCM of 10 and 5 is 10
Thus,
Multiply both sides by 10
10 × (5q + 3)/10 = 10 × (q + 2)/5
(5q + 3) = 2(q + 2)
4. 4(b - 7)/15 = (b + 3)/10
Multiply both sides by the LCM of the denominators
The denominators are 15 and 10
The LCM of 15 and 10 is 30
Thus,
Multiply both sides by 30
30 × 4(b - 7)/15 = 30 × (b + 3)/10
2 × 4(b - 7) = 3(b + 3)
8(b - 7) = 3(b + 3)
Hence, we will multiply both sides of the equation by 30
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Help pleaseeeee. Tyyy
Answer:
Option B.
Step-by-step explanation:
The measure of cage is 90 feet by 40 feet.
Length of rope \(=40\sqrt{2}\) foot
It is clear that, length of rope is greater than one side of cage and raw a line which divides the cage in two parts as shown in below figure.
We need to find the shaded area.
By Pythagoras theorem:
\(hypotenuse^2=base^2+perpendicular^2\)
\((40\sqrt{2})^2=(40)^2+perpendicular^2\)
\(3200=1600+perpendicular^2\)
\(3200-1600=perpendicular^2\)
\(1600=perpendicular^2\)
\(40=perpendicular\)
So, it is a square.
From the figure it is clear that the shaded area contains 1/8th part of circle are half part of square.
Area of circle is
\(A_1=\pi r^2\)
\(A_1=\pi (40\sqrt{2})^2\)
\(A_1=3200\pi\)
Area of square is
\(A_2=a^2\)
\(A_2=(40)^2\)
\(A_2=1600\)
Area of shaded portion is
\(A=\dfrac{A_1}{8}+\dfrac{A_2}{2}\)
\(A=\dfrac{3200\pi}{8}+\dfrac{1600}{2}\)
\(A=400\pi+800\)
\(A=400(\pi+2)\)
The required area is \(400(\pi+2)\) sq. ft.
Therefore, the correct option is B.
After a minor collision, a driver must take his car to one of two body shops in the area. Consider the following events. D=driver takes his car to shop D. L = driver takes his car to shop L. T= the work is complete on time. B= the cost is less than or equal to the estimate (under budget). a. Complete the tree diagram by filling in the missing path probabilities. b. What is the probability that the car is repaired under budget, on time, and with company D? c. What is the probability that the cost of the repair exceeds the estimate? d. What is the probability that the car is repaired under budget, given that it is ready on time? B 0.455 T + 0.226 B' D B 0.378 0.634 T' B' B 0.895 т. L B B 0.844 0.995 T' B'
(a) The tree diagram by filling in the missing path probabilities by subtracting the given value by 1 is given below.
(b) The probability that the car is repaired under budget, on time, and with company D is 0.00652.
(c) The probability that the cost of the repair exceeds the estimate is 0.3909.
(d) The probability that the car is repaired under budget, given that it is ready on time is 0.5804.
D = driver takes his car to shop D.
L = driver takes his car to shop L.
T= the work is complete on time.
B= the cost is less than or equal to the estimate (under budget).
(a) We have to complete the tree diagram by filling in the missing path probabilities.
The complete tree diagram is given below:
We used to complete the tree
1 - 0.634 = 0.366
1 - 0.226 = 0.774
1 - 0.844 = 0.156
(b) We have to determine the probability that the car is repaired under budget, on time, and with company D.
P(DTB) = 0.634 × 0.226 × 0.455
P(DTB) = 0.00652
(c) We have to determine the probability that the cost of the repair exceeds the estimate.
P(B') = P(DTB') + P(DT'B') + P(LTB') + P(LT'B')
P(B') = 0.634 × 0.226 × 0.545 + 0.634 × 0.774 × 0.622 + 0.366 × 0.156 × 0.105 + 0.366 × 0.844 × 0.005
P(B') = 0.390855
P(B') = 0.3909
(d) We have to determine the probability that the car is repaired under budget, given that it is ready on time.
P(B|T) = P(BT)/P(T)
P(B|T) = (0.634 × 0.226 × 0.455 + 0.366 × 0.156 × 0.895)/(0.634 × 0.226 + 0.366 × 0.156)
P(B|T) = 0.580373
P(B|T) = 0.5804
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the residents of a city voted on whether to raise property taxes. the ratio of yes and no votes was 7 to 4. if there were 8679 total votes, how many yes votes were there
Answer:
5523
Step-by-step explanation:
When dealing with ratios like these you want to add the two sides together ( 7 +4 = 11). Another way to write this question is to find 7/11 of 8679 which you would do by dividing 8679 by 11 and multiplying by 7 to give you 5523
1. Quelle était la température à midi ce jour-là ?
Answer: You put this in math when this is french, if you want this in english, the translation is ”what was the temperature at noon that day”
Step-by-step explanation:
for which intervals is the function positive? select each correct answer. (0, 6) (−4, 0) [−6, −4) (6, 8]
To find out the intervals for which the given function is positive, we need to analyze the sign of the function in different intervals.
Here is the solution: Let f(x) be the given function.
Then,\(f(x) = (x + 4)(x − 6)(x − 8)\)
We can see that the function f(x) changes its sign when x = −4, 6, and 8.
So, these are the critical points that divide the real line into different intervals.
We can check the sign of f(x) in each interval using the following table:x-∞-4-40668f(x)+-+-+-+
\(:x-∞-4-40668f(x)+-+-+-+\)
Therefore, the intervals for which the function is positive are (−4, 0) and (6, 8).
Hence, the correct options are (−4, 0) and (6, 8).
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what is 1257÷45 I really need help
Exact Form:
419/15
Decimal Form:
27.93...
Mixed Number Form:
27 14/15
Hope this helps(:
If Kiran solves the equation for p, which equation would result?
Answer: i have a answer but it is not up there srry
Step-by-step explanation:
Extra Credit:
Simplify the following completely:
3(x2-6x+1)+
3xy-5x+7y+3(x-y)-4(y-x)+82-6xy+ 5y-4x+22y-y2 + 4x² - 17x
Answer:
7x² -3xy -y² -37x +27y +85
Step-by-step explanation:
You want to simplify 3(x² -6x +1) +3xy -5x +7y +3(x -y) -4(y -x) +82 -6xy +5y -4x +22y -y² +4x² -17x.
Simplifying an expressionA simplified expression has no parentheses, and like terms combined.
3(x² -6x +1) +3xy -5x +7y +3(x -y) -4(y -x) +82 -6xy +5y -4x +22y -y² +4x² -17x . . . . . given
3x² -18x +3 +3xy -5x +7y +3x -3y -4y +4x +82 -6xy +5y -4x +22y -y² +4x² -17x . . . . . eliminate parentheses
(3 +4)x² +(3 -6)xy +(-1)y² +(-18 -5 +3 +4 -4 -17)x +(7 -3 -4 +5 +22)y +(3 +82) . . . . . group like terms
7x² -3xy -y² -37x +27y +85
Simplify the following completely is \($$=7 x^2-37 x-y^2+27 y-3 x y+85$$\)
\($3\left(x^2-6 x+1\right)+3 x y-5 x+7 y+3(x-y)-4(y-x)+82-6 x y+5 y-4 x+22 y-y^2+4 x^2- 17x$\)
Group like terms
\(=3\left(x^2-6 x+1\right)+3(x-y)-4(y-x)+4 x^2+3 x y-6 x y-5 x-17 x-4 x-y^2+7 y+5 y+22 y+82$$\)
Add similar elements: \($3 x y-6 x y=-3 x y$\)
\($=3\left(x^2-6 x+1\right)+3(x-y)-4(y-x)+4 x^2-3 x y-5 x-17 x-4 x-y^2+7 y+5 y+22 y+82$\)
Add similar elements: \($-5 x-17 x-4 x=-26 x$\)
\($$=3\left(x^2-6 x+1\right)+3(x-y)-4(y-x)+4 x^2-3 x y-26 x-y^2+7 y+5 y+22 y+82$$\)
Add similar elements: \($7 y+5 y+22 y=34 y$\)
\($$=3\left(x^2-6 x+1\right)+3(x-y)-4(y-x)+4 x^2-3 x y-26 x-y^2+34 y+82$$\)
Add similar elements: \($7 y+5 y+22 y=34 y$\)
\($$=3\left(x^2-6 x+1\right)+3(x-y)-4(y-x)+4 x^2-3 x y-26 x-y^2+34 y+82$$\)
Expand \($3\left(x^2-6 x+1\right): \quad 3 x^2-18 x+3$\)
\($$=3 x^2-18 x+3+3(x-y)-4(y-x)+4 x^2-3 x y-26 x-y^2+34 y+82$$\)
Expand \($3(x-y): \quad 3 x-3 y$\)
\($$=3 x^2-18 x+3+3 x-3 y-4(y-x)+4 x^2-3 x y-26 x-y^2+34 y+82$$\)
Expand \($-4(y-x): \quad-4 y+4 x$\)
\($$=3 x^2-18 x+3+3 x-3 y-4 y+4 x+4 x^2-3 x y-26 x-y^2+34 y+82$$\)
Group like terms
\($$=3 x^2+4 x^2-18 x+3 x+4 x-26 x-y^2-3 y-4 y+34 y-3 x y+3+82$$\)
Add similar elements: \($3 x^2+4 x^2=7 x^2$\)
\($$=7 x^2-18 x+3 x+4 x-26 x-y^2-3 y-4 y+34 y-3 x y+3+82$$\)
Add similar elements: \($-18 x+3 x+4 x-26 x=-37 x$\)
\($$=7 x^2-37 x-y^2-3 y-4 y+34 y-3 x y+3+82$$\)
Add similar elements: \($-3 y-4 y+34 y=27 y$ $=7 x^2-37 x-y^2+27 y-3 x y+3+82$\)
Add the numbers: \($3+82=85$\)
\($$=7 x^2-37 x-y^2+27 y-3 x y+85$$\)
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a pennant is shaped like a right triangle, with hypotenuse 15 feet. the length of one side of the pennant is three feet longer than the length of the other side. find the length, in feet, of the two sides of the pennant.
Since, the length of one side of the pennant is 3 feet longer than the length of the other side. Therefore, the length, in feet, of the two sides of the pennant are 9 inches and 3 inches.
Hypotenuse:
The hypotenuse is the longest side of a right triangle, opposite the right angle. The length of the hypotenuse can be found using the Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.
Pythagorean Theorem:
In mathematics, the Pythagorean Theorem or Pythagorean Theorem is the fundamental relationship in Euclidean geometry between the three sides of a right triangle. It states that the area of a square whose side is the hypotenuse (opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation for the lengths of sides a, b and hypotenuse c, often called the Pythagorean equation:
a²+ b² = c²
According to the Question:
Now, By the Pythagorean Equation:
x²+(x - 3)² = 15²
x²+ x²-6x+9 = 225
2x²- 6x+ 9 - 225 = 0
2x²- 6x- 216 = 0
divide both sides by 2
x²- 3x- 108 =0
factor
(x- 9)(x+ 12)=0
x - 9 = 0
x = 9 inches
x- 3 = 3 inches
x and x- 3 are the legs and the hypotenuse is 15 inches
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Calculate the surface area of a cylinder that has a diameter of 12 cm and a height of 23 cm
The surface area of a cylinder is 1093.04 square cm with a diameter of 12 cm and a height of 23 cm.
Surface Area of Cylinder = 2πr (r + h)
Where π (pi) = 3.14,r is the radius of the cylinder,h is the height of the cylinder
Given that the diameter of the cylinder is 12 cm, we can find the radius of the cylinder by dividing the diameter by 2.r = 12/2 = 6 cm
Therefore, the radius of the cylinder is 6 cm.
Given that the height of the cylinder is 23 cm. So, h = 23 cm.
Now, we can plug in the values in the surface area formula.
Surface Area of Cylinder = 2πr (r + h)
Surface Area of Cylinder = 2 x 3.14 x 6 (6 + 23)
Surface Area of Cylinder = 2 x 3.14 x 6 (29)
Surface Area of Cylinder = 2 x 3.14 x 6 x 29
Surface Area of Cylinder = 1093.04 square cm
Therefore, the surface area of the cylinder is 1093.04 square cm.
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3. The function defined by m(h) = 300 * (3/4) ^ h represents the amount of a medicine, in milligrams, in a patient's bodyrepresents the number of hours after the medicine is administered . a. What does m(0.5) represent in this situation?
This means that after 0.5 hours, 259.81 milligrams of the medicine remain on the patient's body.
What does m(0.5) represent in this situation?We know that the exponential function defined by:
\(m(h) = 300*(3/4)^h\)
Represents the amount of a mediciene, in milligrams, after a number of hours h.
We want to see what does m(0.5) represent. This is the exponential function evaluated in h = 0.5
Then, it just represents the amount of medicine, in miligrams, in a patient's body present 0.5 hours after the medicine was administered.
Replacing h = 0.5 we get:
\(m(0.5) = 300*(3/4)^{0.5} = 259.81\)
This means that after 0.5 hours, 259.81 milligrams of the medicine remain on the patient's body.
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HELP!!! Choose the expression that would be easier to simplify if you used the associative
property to change the grouping.
A. 17+[(-41)+(-26)]
O B. 3+G +
C. 67 +(91 +9)
D. (8 + 3) ++
Answer: C.
Step-by-step explanation: The associative property states that you will get the same answer for an expression regardless of the way you group it. If we changed 67 + (91 + 9) to (67 + 91) + 9, we would get the same answer for both expressions, 167