f(x) = 4x³ + 5x² 3x6
g(x) = 4x - 5
Find (f - g)(x).

The inequality tha calculates the possible values of x is x < 2

From the question, we have the following parameters that can be used in our computation:

The figure

Where, we have

3x + 2 < 10

And, we have

2x + 6 < 10

Evaluate the expressions

So, we have

3x < 8 and 2x < 4

Evaluate

x < 8/3 and x < 2

Hence, the inequality tha calculates x is x < 2

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The measure of the unknown sides is equivalent to 12.6

The given figure is a circle geometry with the perpendicular lines intersecting both segments of the circle.

We need to determine the measure of x. Since the measure of the perpendicular lines are equal, hence the measure of the line of the segments will also be equal.

Hence:

x = 6.3 + 6.3

x = 12.6

Therefore the measure of x from the given diagram is equivalent to 12.6

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Answer:

(2x + 3)(x - 5)

Step-by-step explanation:

2x² - 7x - 15

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 15 = - 30 and sum = - 7

the factors are - 10 and + 3

use these factors to split the x- term

2x² - 10x + 3x - 15 ( factor the first/second and third/fourth terms )

= 2x(x - 5) + 3(x - 5) ← factor out (x - 5) from each term

= (2x + 3)(x - 5) ← in factored form

Blank 1 is 3

Blank 2 is 5

Answer: 120 yds

Step-by-step explanation:

48+30+24+18+120 yds

The value of the expression 9 − (8 ÷ 4) x 3 + 7 is 10.

What is parentheses?

Parentheses, also known as round brackets, are punctuation marks that are used in mathematical expressions to group numbers and/or mathematical operations together.

In mathematics, parentheses are used to indicate which operations should be performed first when evaluating an expression.

To evaluate the expression 9 − (8 ÷ 4) x 3 + 7, we need to apply the order of operations, which is a set of rules that defines the order in which mathematical operations are performed.

The order of operations is as follows:

1. Parentheses (or brackets)

2. Exponents (or powers, roots)

3. Multiplication and Division (from left to right)

4. Addition and Subtraction (from left to right)

Using this order of operations, we evaluate the expression step by step:

First, we need to perform the division within the parentheses:

8 ÷ 4 = 2

The expression becomes: 9 - 2 x 3 + 7

Next, we perform the multiplication:

2 x 3 = 6

The expression becomes: 9 - 6 + 7

Finally, we perform the addition and subtraction from left to right:

9 - 6 + 7 = 10

Therefore, the value of the expression 9 − (8 ÷ 4) x 3 + 7 is 10.

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Answer:

a) 0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b) 0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c) 0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d) 0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e) 0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\(\mu\) is the mean in the given interval.

Poisson distributed, with a mean of 0.6 trips per year

This means that \(\mu = 0.6n\), in which n is the number of years.

a.The family did not make a trip to an amusement park last year.

This is P(X = 0) when n = 1, so \(\mu = 0.6\).

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 0) = \frac{e^{-0.6}*(0.6)^{0}}{(0)!} = 0.5488\)

0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b.The family took exactly one trip to an amusement park last year.

This is P(X = 1) when n = 1, so \(\mu = 0.6\).

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 1) = \frac{e^{-0.6}*(0.6)^{1}}{(1)!} = 0.3293\)

0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c.The family took two or more trips to amusement parks last year.

Either the family took less than two trips, or it took two or more trips. So

\(P(X < 2) + P(X \geq 2) = 1\)

We want

\(P(X \geq 2) = 1 - P(X < 2)\)

In which

\(P(X < 2) = P(X = 0) + P(X = 1) = 0.5488 + 0.3293 = 0.8781\)

\(P(X \geq 2) = 1 - P(X < 2) = 1 - 0.8781 = 0.1219\)

0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d.The family took three or fewer trips to amusement parks over a three-year period.

Three years, so \(\mu = 0.6(3) = 1.8\).

This is

\(P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)\)

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 0) = \frac{e^{-1.8}*(1.8)^{0}}{(0)!} = 0.1653\)

\(P(X = 1) = \frac{e^{-1.8}*(1.8)^{1}}{(1)!} = 0.2975\)

\(P(X = 2) = \frac{e^{-1.8}*(1.8)^{2}}{(2)!} = 0.2678\)

\(P(X = 3) = \frac{e^{-1.8}*(1.8)^{3}}{(3)!} = 0.1607\)

\(P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607 = 0.8913\)

0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e.The family took exactly four trips to amusement parks during a six-year period.

Six years, so \(\mu = 0.6(6) = 3.6\).

This is P(X = 4). So

\(P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}\)

\(P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.1912\)

0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

Probabilities are used to determine the chances of events.

The given parameters are:

\(p = 0.6\)

The distribution is given as a Poisson distribution.

So, we have:

\(P(x) = \frac{e^{-\mu} \times \mu^x}{x!}\)

Where:

\(\mu = np\)

Last year means that:

\(n = 1\) --- the number of years.

No trip, means that:

\(x = 0\)

So, we have:

\(\mu = np\)

\(\mu = 1 \times 0.6\)

\(\mu = 0.6\)

The probability becomes

\(P(x) = \frac{e^{-\mu} \times \mu^x}{x!}\)

\(P(0) = \frac{e^{-0.6} \times 0.6^0}{0!}\)

\(P(0) = \frac{0.5488 \times 1}{1}\)

\(P(0) = 0.5488\)

Hence, the probability that the family did not make a trip to an amusement park last year is 0.5488

This means that:

x = 1.

So, we have:

\(P(x) = \frac{e^{-\mu} \times \mu^x}{x!}\)

\(P(1) = \frac{e^{-0.6} \times 0.6^1}{1!}\)

\(P(1) = \frac{0.5488 \times 0.6}{1}\)

\(P(1) = 0.3293\)

Hence, the probability that the family took exactly one trip to an amusement park last year is 0.3293

This means that:

x = 2,3...

So, we make use of the following complement rule:

\(P(x\ge 2) = 1 - P(x < 2)\)

This gives

\(P(x\ge 2) = 1 - P(0) - P(1)\)

So, we have:

\(P(x\ge 2) = 1 - 0.5488 - 0.3293\)

\(P(x\ge 2) = 0.1219\)

Hence, the probability that the family took two or more trips to an amusement park last year is 0.1219

For a three-year period, we have:

\(n = 3\)

So, the mean of the distribution is:

\(\mu = np\)

\(\mu = 3 \times 0.6\)

\(\mu = 1.8\)

The probability is then represented as:

\(P(x \le 3) = P(0) + P(1) + P(2) + P(3)\)

Calculate P(0) to P(3) using:

\(P(x) = \frac{e^{-\mu} \times \mu^x}{x!}\)

So, we have:

\(P(0) = \frac{e^{-1.8} \times 1.8^0}{0!}\)

\(P(0) = \frac{0.1653 \times 1}{1}\)

\(P(0) = 0.1653\)

\(P(1) = \frac{e^{-1.8} \times 1.8^1}{1!}\)

\(P(1) = \frac{0.1653 \times 1.8}{1}\)

\(P(1) = 0.2975\)

\(P(2) = \frac{e^{-1.8} \times 1.8^2}{2!}\)

\(P(2) = \frac{0.1653 \times 3.24}{2}\)

\(P(2) = 0.2678\)

\(P(3) = \frac{e^{-1.8} \times 1.8^3}{3!}\)

\(P(3) = \frac{0.1653 \times 5.832}{6}\)

\(P(3) = 0.1607\)

So, we have:

\(P(x \le 3) = P(0) + P(1) + P(2) + P(3)\)

\(P(x \le 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607\)

\(P(x \le 3) = 0.8913\)

Hence, the probability that the family took three or fewer trips to amusement parks over a three-year period is 0.8913

A six-year period means that:

\(n = 6\)

So, the mean of the distribution is:

\(\mu = np\)

\(\mu = 6 \times 0.6\)

\(\mu = 3.6\)

The probability is then calculated as:

\(P(x) = \frac{e^{-\mu} \times \mu^x}{x!}\)

So, we have:

\(P(4) = \frac{e^{-3.6} \times 3.6^4}{4!}\)

\(P(4) = \frac{0.0273 \times 167.9616}{24}\)

\(P(4) = 0.1911\)

Hence, the probability that the family took exactly four trips to amusement parks over a six-year period is 0.1911

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2+3x=62

3x=60

x=20

Hope this helps! Brainliest? :D

Answer:

we conclude that only two points (-5, 5) and (-1, 4) satisfy the system of inequalities.

Step-by-step explanation:

Given the system of inequalities

y > 2x+3

y+3x ≤ 1

Checking the point (0, 5)

Let us substittue the point (0, 5) to check if it is satisfies system of inequalities

y > 2x+3

5 > 2(0) + 3

5 > 3

True

now check for the second inequality

y+3x ≤ 1

5 + 3(0) ≤ 1

5 ≤ 1

False

Therefore, the point (0, 5) does not satisfy the system of inequalities

Checking the point (-5, 5)

Let us substittue the point (-5, 5) to check if it is satisfies system of inequalities

y > 2x+3

5 > 2(-5) + 3

5 > -10+3

5 > -7

True

now check for the second inequality

y+3x ≤ 1

5 + 3(-5) ≤ 1

5-15 ≤ 1

-10 ≤ 1

True

Therefore, the point (-5, 5) satisfies the system of inequalities.

Checking the point (-1, 4)

Let us substittue the point (-1, 4) to check if it is satisfies system of inequalities

y > 2x+3

4 > 2(-1) + 3

4 > -2+3

4 > 1

True

now check for the second inequality

y+3x ≤ 1

4 + 3(-1) ≤ 1

4-3 ≤ 1

1 ≤ 1

True

Therefore, the point (-1, 4) satisfies the system of inequalities.

Checking the point (0, -5)

Let us substitute the point (0, -5) to check if it satisfies the system of inequalities

y > 2x+3

-5 > 2(0) + 3

-5 > 0+3

-5 > 3

False

now check for the second inequality

y+3x ≤ 1

-5 + 3(0) ≤ 1

-5+0 ≤ 1

-5 ≤ 1

True

Therefore, the point (0, -5) does not satisfy the system of inequalities.

Checking the point (-3, -3)

Let us substitute the point (-3, -3) to check if it satisfies the system of inequalities

y > 2x+3

-3 > 2(-3) + 3

-3 > -6+3

-3 > -3

False

now check for the second inequality

y+3x ≤ 1

-3 + 3(-3) ≤ 1

-3 - 9 ≤ 1

-12 ≤ 1

True

Therefore, the point (-3, -3) does not satisfy the system of inequalities.

Hence, we conclude that only two points (-5, 5) and (-1, 4) satisfy the system of inequalities.

Answer: Changing the radius of an object by a given amount has a greater effect on the volume than changing the height by the same amount. The volume of a cylinder is given by the formula V = πr²h, where V is the volume, r is the radius, and h is the height. If we change the radius by a given amount, say x, the new radius would be r+x. Hence, the new volume would be V' = π(r+x)²h = π(r²+2rx+x²)h = V + 2πrxh + πx²h. We can see that the volume change equals 2πrxh + πx²h. The first term is proportional to both the radius and the height, whereas the second term is proportional to the square of the radius and the height. Assuming that the height change is also x, the new volume would be V'' = πr²(h+x) = V + πr²x. We can see that the volume change is proportional to the radius squared and the change in height. Therefore, changing the radius by a given amount has a greater effect on the volume than changing the height by the same amount.

Thus, Ron's share is $24,000, Nick's share is $18,000, Mary's share is $18,000, and Margaret's share is $72,000.

Let's denote the original scholarship amount as "P."

According to the given information, Margaret receives $72,000, which means the remaining scholarship amount for the other three individuals is P - $72,000.

Ron receives 1/3 of the scholarship, which can be represented as (1/3)(P - $72,000). Nick receives 1/4 of the scholarship, which can be represented as (1/4)(P - $72,000). Mary receives the same as Nick, so Mary's share is also (1/4)(P - $72,000).

Now, we can sum up all the shares to equal the original scholarship amount:

Ron's share + Nick's share + Mary's share + Margaret's share = P

(1/3)(P - $72,000) + (1/4)(P - $72,000) + (1/4)(P - $72,000) + $72,000 = P

To simplify the equation, we can combine like terms:

(P/3 - $24,000) + (P/4 - $18,000) + (P/4 - $18,000) + $72,000 = P

Combining the fractions and constants:

(4P + 3P - 3P + 12P)/12 - $24,000 - $18,000 - $18,000 + $72,000 = P

16P/12 - $48,000 = P

Multiplying both sides of the equation by 12 to eliminate the denominator:

16P - $576,000 = 12P

Subtracting 12P from both sides of the equation:

4P = $576,000

Dividing both sides of the equation by 4:

P = $144,000

Therefore, the original scholarship amount is $144,000.

Ron's share: (1/3)($144,000 - $72,000) = $24,000

Nick's share: (1/4)($144,000 - $72,000) = $18,000

Mary's share: (1/4)($144,000 - $72,000) = $18,000

Margaret's share: $72,000

Thus, Ron's share is $24,000, Nick's share is $18,000, Mary's share is $18,000, and Margaret's share is $72,000.

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Answer:

Which one is at the bottom? if the one at the bottom is 0 then the answer is 0. If its not then its related to pemdas or something else

Step-by-step explanation:

Answer:

? = 4

4 is the answer

Step-by-step explanation:

heart = 21

rainbow = 7

unicorn horn = 9

so, we have

heart + rainbow + rainbow = 35

21 + 7 + 7 = 35

heart + unicorn horn + rainbow = 37

21 + 9 + 7 = 37

rainbow + unicorn horn + unicorn horn =25

7 + 9 + 9 = 25

unicorn horn + unicorn horn + rainbow - heart = ?

9 + 9 + 7 - 21 = 4

So, the pairs of numbers that would represent the simple main effect of therapy (factor a) at the group setting (b2) in this example would be a1b2 (cognitive-behavioral therapy at the group setting) and a2b2 (relaxation therapy at the group setting).

In a 2x2 factorial design, there are two independent variables, each with two levels. This means that there are a total of four treatment conditions in the experiment. The simple main effect of one of the independent variables (in this case, factor a) at a specific level of the other independent variable (in this case, b2) refers to the effect of that independent variable on the dependent variable when the other independent variable is held constant at a specific level.

To understand this concept more clearly, let's consider an example. Suppose that in your experiment, factor a is the type of therapy (cognitive-behavioral therapy vs. relaxation therapy) and factor b is the type of treatment setting (individual vs. group). In this case, the simple main effect of therapy (factor a) at the group setting (b2) would refer to the effect of therapy on the dependent variable when the treatment setting is held constant at the group level.

The simple main effect of therapy (factor a) at the group setting (b2) would be calculated by comparing the mean response for the cognitive-behavioral therapy condition (a1b2) to the mean response for the relaxation therapy condition (a2b2). This would allow you to determine whether there is a significant difference in the mean response between the two therapy conditions when the treatment setting is held constant at the group level.

So, to answer your question, the pairs of numbers that would represent the simple main effect of therapy (factor a) at the group setting (b2) in this example would be a1b2 (cognitive-behavioral therapy at the group setting) and a2b2 (relaxation therapy at the group setting).

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Answer:

I think the answer is -4 .

Step-by-step explanation:

Let me know if it's right or wrong.

first you would have to go on the right side of the X axis and put a point on 2 and go up 3 and place a point there.

next you can do the same thing but got the the left side of the X axis and that will be the negative side of the numbers.

Answer:

y = -1

Step-by-step explanation:

the x always has to be 0 so when you look at the point it is (0, -1 ) therefore the y = -1

Answer:

The coordinates are (3,1)

Step-by-step explanation:

Answer:

B) \(\sqrt{13}\)

Step-by-step explanation:

1.  \(d = \sqrt{(-3-0)^2+(-2-0)^2}\)

2. \(d=\sqrt{(-3)^2+(-2)^2}\)

3. \(d=\sqrt{9+4}\)

4. \(d=\sqrt{13}\)

\(\sqrt{13} = 3.60555..\)

Answer:

im pretty sure its y is more than or equal to 3x - 4

Step-by-step explanation:

Answer:

slope:-2/3

y-intercept= 2

equation y= -2/3x+2

Step-by-step explanation:

pick two points from graph then plug to the formula to find the equation

Answer:

She should find the squares between 4.2 and 4.3

Step-by-step explanation:

The square of 4.2 was too low and the square for 4.3 was too high so the answer is between the two.

Answer:

$47.48

Step-by-step explanation:

Let x = the amount owed Sept.

x + x - 2.23 = 292.43  Combine like terms

2x -2.23 = 292.43  Add 2.23 to both sides

2x - 2.23 + 2.23 = 292.43 + 2.23

2x = 294.66  Divide both sides by 2

\(\frac{2x}{2}\) = \(\frac{294.66}{2}\)

x = 147.33 this is the bill for September

Oct. 147.33 -2.23 = 145.10 This is the Bill for Oct.

Total:

147.33 + 145.10 = 292.43

292.43 ÷ 3 = 97.48  This is what each will owe rounded to the nearest penny.

Answer:

The common difference in the given sequence is 5.

Step-by-step explanation:

The common difference in the sequence is 5 because they all add by 5 each time for example 5 + 5= 10 and 10+5=15

Answer:

? = 92°

Step-by-step explanation:

the chord- chord angle ? is half the sum of the measures of the arcs intercepted by the angle and its vertical angle, that is

? = \(\frac{1}{2}\) (LM + AK) = \(\frac{1}{2}\) (120 + 64)° = \(\frac{1}{2}\) × 184° = 92°

Answer:

n = 4.5

Step-by-step explanation:

10 - 5.5 = n

Answer:

I feel like its 4.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

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The number 100 would land in column 2

Given that we have the array of numbers

The length of each row in the array is 7

Dividing 100 by 7, we have

100/7 = 14 Remainder 2

This means that

Column = 2

In (a), we have

100/7 = 14 Remainder 2

This means that

Row = 14

Here, we have

The length of each row in the array is 6

Dividing 100 by 6, we have

100/6 = 16 Remainder 3

So, the location of 100 in rows of 6 numbers is row 16 and column 3

Let the length of each row in the array be n

Dividing 100 by n, we have

100/n = q Remainder r

This means that the location of 100 in rows of n numbers is row q and column r

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(x^{4}\)+ c\(x^{3}\). The coefficient of the highest degree term (x^5) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and \(x^{2}\) + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set.

Part A: A fifth-degree polynomial with three terms in standard form would be written as a\(x^{2}\) + b\(y^{2}\)+ c. The coefficient of the highest degree term (\(x^{5}\)) must be non-zero and all the terms must be written in descending order of the degree. This is the definition of standard form for polynomials.

Part B: The closure property states that a set is closed under a certain operation if performing that operation on any two elements of the set produces a result that is also an element of the set. In this case, the set is polynomials and the operation is subtraction. An example of this property can be seen by subtracting two polynomials, such as 4\(x^{2}\) + 3x - 5 and  + 2. The result of this subtraction would be 3\(x^{2}\) + 3x - 5, which is also a polynomial and therefore an element of the set, demonstrating the closure property.

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