Answers
According to the given data the acceleration of each car is a) 3.0 m/^s b) 4.0 m/s^2 c) -3.0 m/s^2 d) 2.5 m/s^2
What is an acceleration?The rate about which velocity fluctuates is titled acceleration. Acceleration typically signals a shift in speed, but not necessarily. An item that continues a circular course while maintaining a constant speed is still moving forward because the orientation of its motion is rotating.
The following equation can be used to determine each car's acceleration: acceleration = (final velocity - beginning velocity) / time period. For each car, the computation is as follows:
a) acceleration = (11.0 - 2.0) / 3.0 = 3.0 m/s^
b) acceleration = (3.0 - (-5.0)) / 2.0 = 4.0 m/s^2
c) acceleration = (-5.0 - 1.0) / 2.0 = -3.0 m/s^2
d) acceleration = (25.0 - 0.0) / 10.0 = 2.5 m/s^2
Because the vehicle is slowing down rather than accelerating, the acceleration of automobile "c" is negative.
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Related Questions
A crate with a mass of 35.0 kg is pushed with a horizontal force of 150 N. The crate moves at a constant speed across a level, rough surface a distance of 5.85 m
Answers
(a) The work done by the 150 N force is 877.5 Joules.
(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.
To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.
(a) The applied force's work may be estimated using the following formula:
Work = Force * Distance * cos(theta)
where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.
As a result, the applied force's work is:
Work = 150 N * 5.85 m * cos(0) = 877.5 J
So, the work done by the 150 N force is 877.5 Joules.
(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.
The frictional work may be estimated using the following formula:
Work = Force of Friction * Distance * cos(theta)
The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.
Thus, the work done by friction is:
Work = 150 N * 5.85 m * cos(180) = -877.5 J
Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.
The coefficient of kinetic friction may be calculated using the following equation:
Friction Force = Kinetic Friction Coefficient * Normal Force
The normal force equals the crate's weight, which may be computed as:
Normal Force = mass * gravity
where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.
Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N
Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:
Force of Friction = coefficient of kinetic friction * Normal Force
150 N = coefficient of kinetic friction * 343 N
coefficient of kinetic friction = 150 N / 343 N ≈ 0.437
As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.
In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.
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what is the average velocity of a van that moves from 0 to 60 m east and 20 seconds
Answers
Explanation:
I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I
A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current running from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]
Answers
Answer:
Explanation:
Force on a current carrying wire in a magnetic field
= B i L where B is magnetic field , i is current and L is length of the wire .
Putting in the given values in the question
force on a current carrying wire in a magnetic field = .001 T x i x .5 m
5 x 10⁻⁴ i N .
weight of the wire = .050 kg x 9.8 m/s²
= .49 N .
For equilibrium
5 x 10⁻⁴ i = .49
i = 980 A .
If a 15-ohm resistor is connected in parallel with a 30 ohm-resistor, the equivalent resistance is?
Answers
Answer:
Explanation:
in parallel combination equivalent resistence =
1/R=1/R1 + 1/R2
1/2=1/15+1/30
1/2=1*2+1*1/30
1/R=3/30
R*3=30*1
R=30/3
R=10 ohm
Explanation:
Equilibrium resistance=1/R1 +1/R2
\( = \frac{1}{15} + \frac{1}{30} \\ = \frac{2 + 1}{30} \\ \frac{1}{r} = \frac{3}{30} \\ resistance \: = \frac{30}{3} \\ = 10 \: ohms\)
You are trying to catch the mutated mouse and you have a rope
that both you and the mouse are pulling with a force of 500 Newtons,
but the rope does not move.
How much work is done?
PLS ANSWER ASAP! WILL MARK AS BRAINLYIST!!!!!
time left (5:00)!!
Answers
Answer:
none no work cuz no motion
Explanation:
GOOD LUCK
A car has a mass of 1200 kg and a velocity of 14 m/s. Calculate the
momentum of the car.
Answers
Answer:
p = 16,800
Explanation:
You are standing on a scale in an elevator that is moving upward with a constant velocity. The scale reads 600 N. The following table shows five options for what the scale reads when the elevator slows down as it comes to a stop, when it is stopped, and when it picks up speed on down. Which one of the five options correctly describes the scale's readings? Note that the symbol < means "less than" and > means "greater than."
Option Elevator slows down Elevator is stopped Elevator picks up speed
as it comes to a half on its way back down
(a) >600 N >600 N >600 N
(b) <600 N 600 N <600 N
c) >600 N 600 N <600 N
(d) <600 N <600 N <600 N
(e) <600 N 600 N >600 N
Answers
Answer:
C. >600 N 600 N <600 N
Explanation:
The scale's reading when when the elevator slows down as it comes to a stop, when it is stopped, and when it picks up speed on down is >600 N, 600 N, <600 N respectively.
To understand this we have to first understand weight.
What is weight?Weight is a product of mass and gravitational acceleration.Weight W = mg , where m = mass of an object , g = gravitational acceleration.The gravitational force increases as the height of an object increases.What happens to scale's reading when an elevator changes its position? The scale's reading is 600 N.When an elevator goes upwards and slows down , the Earth's gravity pulls it down so the force will be 600 N + force applied by earth so it will be >600 N.When an elevator stops it is at its natural height so, the force will be 600 N.When an elevator picks up speed on down, the force will be less than 600 N so it will be <600 N.So, the scale's reading is >600 N 600 N <600 N, hence the correct answer is option C.
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A hollow spherical iron shell floats almost completely submerged in water. The outer diameter is 60.0 cm, and the density of iron is 7.87 g∕c m cubed . Find the inner diameter in cm. Express to 3 sig figs.
Answers
Answer:
The inner diameter is 57.3 cm
Explanation:
The inner diameter of the hollow spherical iron shell can be found using the weight of the sphere (\(W_{s}\)) and the weight of the water displaced (\(W_{w}\)):
\( W_{s} = W_{w} \)
\( m_{s}*g = m_{w}*g \)
\( D_{s}*V_{s} = D_{w}*V_{w} \)
Where D is the density and V is the volume
\( D_{s}*\frac{4}{3}\pi*(\frac{d_{o}^{3} - d_{i}^{3}}{2^{3}}) = \frac{4}{3}\pi*(\frac{d_{o}}{2})^{3} \)
Where \(d_{o}\) is the outer diameter and \(d_{i}\) is the inner diameter
\( D_{s}*(d_{o}^{3} - d_{i}^{3}) = d_{o}^{3} \)
\( D_{s}*d_{i}^{3} = d_{o}^{3}(D_{s} - 1) \)
\( 7.87*d_{i}^{3} = 60.0^{3}(7.87 - 1) \)
\( d_{i} = 57.3 cm \)
Therefore, the inner diameter is 57.3 cm.
I hope it helps you!
Which type of energy is always generated, at least in small amounts, when an energy transfer or transformation occurs?
A. potential energy
B. thermal energy
C. chemical energy
D. radiant energy
Answers
Answer:
B. Thermal energy
Explanation:
The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in voltage), then its new current would be
Answers
Answer:
I = 0.09[amp] or 90 [milliamps]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
Now, we replace the values of the first current into the equation
V = 180*10^-3 * R
V = 0.18*R (1)
Then we have that the resistance is doubled so we have this new equation:
V = I*(2R) (2)
The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.
V = V
0.18*R = I*2*R
I = 0.09[amp] or 90 [milliamps]
A 602-kg elevator starts from rest and moves upward for 2.60 s with constant acceleration until it reaches its cruising speed, 1.72 m/s. Answer parts a and b.
Answers
The distance traveled by the elevator is 2.0136 m.
Given values: Mass, m = 602 kg. Initial velocity, u = 0 m/s. Time taken, t = 2.60 s. Final velocity, v = 1.72 m/s.(a) Find the acceleration of the elevator. The formula to calculate the acceleration is given below:
a = (v - u)/t Substitute the given values in the above equation and get the acceleration value.
a = (1.72 - 0)/2.60a = 0.6615 m/s²Therefore, the acceleration of the elevator is 0.6615 m/s².
(b) Find the distance traveled by the elevator. The formula to calculate the distance is given below:
s = ut + 1/2at²Substitute the given values in the above equation and get the distance traveled by the elevator.
s = 0(2.60) + 1/2(0.6615)(2.60)²s = 2.0136 m.
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a roller coaster weighs 2000 kg This ride includes an initial vertical drop of 59.3 m.
Assume that the roller coaster has a speed of nearly zero as it crests the top of the hill.
If the track was frictionless, find the speed of the roller coaster at the bottom of
the hill.
Answers
The speed of the roller coaster at the bottom of the hill if the track was frictionless is 34.04 m/s.
Given that the weight of the roller coaster is 2000 kg and the initial vertical drop of the ride is 59.3 m. We are to find the speed of the roller coaster at the bottom of the hill if the track was frictionless.We know that the roller coaster will lose potential energy due to the vertical drop. Assuming there is no friction, the potential energy will be converted into kinetic energy at the bottom of the hill.Considering the conservation of energy between the potential and kinetic energy, we can set the initial potential energy equal to the final kinetic energy. We can use the formula to calculate potential energy, which is PE = mgh where m = 2000 kg, g = 9.8 m/s², and h = 59.3 m. Therefore,PE = 2000 kg × 9.8 m/s² × 59.3 m = 1,157,924 JWe can use the formula to calculate kinetic energy, which is KE = 1/2mv² where m = 2000 kg and v is the final velocity. Therefore,KE = 1/2 × 2000 kg × v².The total energy remains constant as we know there is no friction. Therefore the final kinetic energy will be equal to the initial potential energy,1,157,924 J = 1/2 × 2000 kg × v²v² = (2 × 1,157,924 J) / 2000 kgv² = 1157.924v = √1157.924v = 34.04 m/s.
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A mass M = 4 kg attached to a string of length L = 2.0 m swings in a horizontal circle with a speed V. The string maintains a constant angle \theta\:=\:θ = 35.4 degrees with the vertical line through the pivot point as it swings. What is the speed V required to make this motion possible?
Answers
Answer:
The velocity is \(v = 2.84 1 \ m/s\)
Explanation:
The diagram showing this set up is shown on the first uploaded image (reference Physics website )
From the question we are told that
The mass is m = 4 kg
The length of the string is \(L = 2.0 \ m\)
The constant angle is \(\theta = 35.4 ^o\)
Generally the vertical forces acting on the mass to keep it at equilibrium vertically is mathematically represented as
\(Tcos (\theta ) - mg = 0\)
=> \(mg = Tcos (\theta )\)
Now let the force acting on mass horizontally be k so from SOHCAHTOA rule
\(sin (\theta ) = \frac{k }{T}\)
=> \(k = T sin \theta\)
Now this k is also equivalent to the centripetal force acting on the mass which is mathematically represented as
\(F_v = \frac{m v^2}{r}\)
So
\(k = F_v\)
Which
=> \(T sin \theta= \frac{ m v^2}{ r }\)
So
\(\frac{Tsin (\theta )}{Tcos (\theta )} = \frac{mg}{ \frac{mv^2}{r} }\)
=> \(Tan (\theta ) = \frac{v^2}{ r * g }\)
=> \(v = \sqrt{r * g * tan (\theta )}\)
Now the radius is evaluated using SOHCAHTOA rule as
\(sin (\theta) = \frac{ r}{L}\)
=> \(r = L sin (\theta)\)
substituting values
\(r = 2 sin ( 35.4 )\)
\(r = 1.1586 \ m\)
So
\(v = \sqrt{1.1586* 9.8 * tan (35.4 )}\)
\(v = 2.84 1 \ m/s\)
Which circuit has the larger equivalent resistance: a circuit with two 10 ohm resistors connected in parallel or a circuit with two 10 ohm resistors connected in series?
Answers
Answer:
A circuit with two 10 ohm resistors connected in series.
Explanation:
The formula for the equivalent resistance for resistors in parallel is
\(\frac{1}{Rt} = \frac{1}{R1} + \frac{1}{R2}\) So if R1=R2= 10 \(\frac{1}{Rt} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10} <=> Rt =\frac{10}{2} =5 ohm\)
The formula for the equivalent resistance for resistors in series is
Rt = R1 + R2 So Rt= 10 + 10 = 20
Please help I need help I can’t fail .
Answers
Answer:
A
Explanation:
Gas particles move fastest.
Plasma lacks fixed volume and shape.
Liquid lacks fixed shape, but has fixed volume.
Solid has both fixed volume and shape.
Anastasia constructed a simple circuit with a battery and a light bulb. She knows that the resistance of the light bulb is 10
2 and that the voltage given to the light bulb is 12 V. What is the current through the light bulb?
Answers
Answer:
Simple Single Loop Circuits. J. E σ. = ∆V = IR ... To find the current, use the total voltage and equivalent resistance: S. V ... A circuit contains a 48-V battery and two 240Ω light bulbs.
What happens to pressure if temperature increases?
Answers
Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The fracture plane is helical, and is very difficult to heal. Mechanically, it occurs due to an applied torsion load on the bone. Recall that a state of pure shear occurs within the material when torsion is applied on a cylinder, and the bone can be idealized as a cylinder. Let a femur bone be subjected to a torque of T 50 N-m. Assume body weight of the person to be W- 80 Kgs, while each leg is subjected to half of that weight. Given radius of the bone r 10 mm. Compute the principal stresses and shear stresses, as well as orientation of planes on which these stresses are realized.
Answers
Answer:
principal stresses :б1 = 32.62mPa б2 = 31.38mPa
Max Shear stress : 16.31 mPa
Orientation of max principle plane = 44.43°
Orientation of minimum principal plane = 134.43°
Explanation:
Given data:
Torque = 50 N-m
weight = 80 kgs
half of weight is subjected to each leg
radius of bone = 10 mm = 0.010 m
a) Determine the principal stresses and shear stress
first calculate the max shear stress ( this will occur in the outermost element
= 16T / π*d^3 where : T = 50 , d = 0.020 m
hence max shear stress = 32 mPa
next determine compressive stress
= ( 40*g) / π/4*d^2 . where : d = 0.020 m , g = 9.81
hence compressive stress = 1.24 mPa
draw and calculate the radius of Mohr's circle
radius of Mohr's circle = 32.0060
Hence principal stresses = 32.0060 ± 0.62
б1 = 32.62mPa
б2 = 31.38mPa
attached below is the remaining part of the solution
The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
Answers
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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Because many drug addicts who came through the courts admit that they started on marijuana, marijuana likely causes addiction to hard drugs,
Deductive or Inductive?
Answers
The statement is an example of faulty deductive reasoning, specifically the fallacy of hasty generalization.
Is the statement Deductive or Inductive?The statement is an example of faulty deductive reasoning. The conclusion that marijuana causes addiction to hard drugs is not supported by the premise that many drug addicts who came through the courts admit that they started on marijuana.
Inductive reasoning would involve observing a large number of cases and drawing a general conclusion based on that evidence. However, the given statement only presents a small sample of drug addicts who came through the courts and cannot be used to make a general conclusion about the relationship between marijuana use and addiction to hard drugs.
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The time taken by a mass projected vertically
upwards to reach the maximum height (with air
resistance not neglected) is 10 sec. The time of
descent of the mass from the same height will be
Answers
Answer:
10s
Explanation:
The time to get to the maximum would be the same as the time to get down to the maximum unless somehow gravity’s changes during the duration it goes up to and from maximum height.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
Answers
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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You leave Fort worth ,Texas,at 2:41 p.m. and arrive in Dallas at 3:23 p.m. , covering a distance of 58km. what is your average speed in metres per second ?
Answers
Answer:
Explanation:
The time taken to travel from Fort Worth to Dallas is:
t = 3:23 pm - 2:41 pm = 42 minutes = 0.7 hours
The distance covered is:
d = 58 km
The average speed is:
v = d/t = 58 km / 0.7 hours = 82.86 km/h
To convert km/h to m/s, we can use the conversion factor:
1 km/h = 0.2778 m/s
Therefore, the average speed in m/s is:
v = 82.86 km/h × 0.2778 m/s/km = 23.06 m/s (rounded to two decimal places)
So the average speed is 23.06 m/s.
When seismic waves encounter a new layer of earth materials they will either
telling us about the composition of that layer.
Answers
According to seismic waves, the Earth's interior is made up of a number of concentric shells, including a solid inner core, a liquid outer core, a mantle, and a thin outer crust.
What seismic waves, a new layer of earth materials?The wave's course will be bent or refracted as it enters the new layer if it moves at a different speed there. The wave will be somewhat curved in the direction of the contact between the two layers if it can move through it more quickly in the new layer.
Therefore, We can learn about just the layers that make up the Earth by understanding how waves behave as they pass through various materials.
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A locomotive engine pulls a train with a constant force comment on whether its acceleration will increase or decrease if more coaches are added to the train
Answers
Explanation:
the acceleration will be unchanged according to newton second law of motion
A locomotive engine pulls a train with a constant force then its acceleration will increase if more coaches are added to the train because the mass of the system would increase
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
Force = mass ×acceleration
As given in the problem if a locomotive engine pulls a train with a constant force
As given the force is constant but if the number of coaches increases the mass of the train increase to balance the constant force acceleration will decrease.
Thus, if a locomotive engine pulls a train with a constant force then its acceleration will increase if more coaches are added to the train because the mass of the system would increase.
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Which is the best description of biodiversity?
1. All animals in an ecosystem
2. The variety of the type of life within the biosphere
3. The study of life
3. The variety of plants on Earth
Answers
Answer:2
Explanation:
Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 36.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.
Answers
Answer:
\(F=1152N\)
Explanation:
From the question we are told that:
Mass/one sec \(m=36.0kg/s\)
Incident water stream \(v=16.0m/s\)
Exiting water stream \(v'=-16.0m/s\)
Generally the equation for Force is mathematically given by
\(F=\frac{mv-mu}{t}\)
\(F=\frac{36(-16-16)}{1}\)
\(F=1152N\)
A person jogs eight complete laps around a quarter-mile track in a total time of 12.5 min. Calculate (a) the average speed and (b) the average velocity, in m/s. Note: 1 mile = 1609 m.
Answers
\(\large\displaystyle\text{$\begin{gathered}\sf \huge \bf{\underline{Data:}} \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf 1\ mile = 1609.34 \ m \end{gathered}$}\)\(\large\displaystyle\text{$\begin{gathered}\sf 1/4 \ mile = 402.33 \ m \end{gathered}$}\)\(\large\displaystyle\text{$\begin{gathered}\sf 12.5 \not{min}*\frac{60 \ s}{1\not{min}}=750 \ s \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{A) \ Calculate \ the \ average \ speed: } \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf 402.33 \ m*8 \ laps = 3218.64 \ m \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf d=3218.64 \ m \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf V=\frac{d}{t} \ \ \ \ \ \ V= \frac{3218.64 \ m }{750 \ s} \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V=4.29 \ m/s \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf \bf{B) \ Calculate \ the \ average \ speed \ in \ m/s} \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf V=402.33 \ m \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf t=750 \ s \end{gathered}$}\)
\(\large\displaystyle\text{$\begin{gathered}\sf V=\frac{D}{T} \ \ \ \ \ V=\frac{402.33 \ m}{750 \ s} \end{gathered}$}\\\\\\\large\displaystyle\text{$\begin{gathered}\sf V= 0.53 \ m/s \end{gathered}$}\)
A train is travelling at a uniform speed of 140 km/h. How long will it take to cover a
distance of 560 km?
(
Answers
The work done on a 10. 0-kilogram mass to give it a speed of 5. 00 meters per second is.
Answers
Answer:
125 joules.
Explanation:
The work done on an object to give it a certain velocity can be calculated using the formula:
W = (1/2)mv²
where W is the work done, m is the mass of the object, and v is its final velocity.
Substituting the given values, we get:
W = (1/2)(10.0 kg)(5.00 m/s)²
W = (1/2)(10.0 kg)(25.0 m²/s²)
W = 125 J
Therefore, the work done on the 10.0-kilogram mass to give it a speed of 5.00 meters per second is 125 joules.