The length of the window is 21 inches. To find the length of the window, you can use the formula for the area of a rectangle:
Area = Length x Width
In this problem, the area of the window is given as 336 square inches, and the width of the window is 16 inches. So we can substitute these values into the formula and solve for the length:
336 = Length x 16
To isolate the variable "Length" on one side of the equation, we can divide both sides by 16:
336/16 = Length
Simplifying the left side, we get:
21 = Length
Therefore, the length of the window is 21 inches.
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a closed rectangular box with volume 8 ft3 has length twice the width. express the height of the box as a function of the width and state its domain.
The height of the box can be represented as a function of the width, h = 4/w², where the domain of the function is (0, +∞).
Let's assume the width of the rectangular box is represented by the variable 'w'. Given that the length of the box is twice the width, we can express the length as '2w'. The height of the box can be represented by the variable 'h'.
The volume of a rectangular box is given by the formula: V = lwh, where V represents the volume, l represents the length, w represents the width, and h represents the height.
We are given that the volume of the box is 8 ft³. Substituting the values into the formula, we have:
8 = (2w)(w)(h)
Simplifying, we get:
8 = 2w²h
Dividing both sides by 2w², we get:
4/w² = h
Therefore, the height of the box can be expressed as a function of the width, h = 4/w².
The domain of the height function is determined by the width. Since the width of a rectangular box cannot be zero or negative (as it represents a physical dimension), the domain of the height function is the set of positive real numbers, excluding zero. In interval notation, the domain can be expressed as (0, +∞).
In conclusion, the height of the box can be represented as a function of the width, h = 4/w², where the domain of the function is (0, +∞).
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genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a % confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? a. Construct a % confidence interval. Express the percentages in decimal form. nothingp nothing (Round to three decimal places as needed.) b. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? No, the confidence interval includes 0.25, so the true percentage could easily equal 25% Yes, the confidence interval does not include 0.25, so the true percentage could not equal 25%
Complete Question
A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?
Answer:
The 95% confidence interval is \(0.2392 < p < 0.3108\)
No, the confidence interval includes 0.25, so the true percentage could easily equal 25%
Step-by-step explanation:
From the question we are told that
The total sample size is \(n = 432 + 164 =596\)
The number of offspring that is yellow peas is \(y = 432\)
The number of offspring that is green peas is \(g = 164\)
The sample proportion for offspring that are yellow peas is mathematically evaluated as
\(\r p = \frac{ 164 }{596}\)
\(\r p = 0.275\)
Given the the confidence level is 95% then the level of significance is mathematically represented as
\(\alpha = (100 - 95)\%\)
\(\alpha = 5\% = 0.0 5\)
The critical value of \(\frac{\alpha }{2}\) from the normal distribution table is
\(Z_{\frac{\alpha }{2} } = 1.96\)
Generally the margin of error is mathematically evaluated as
\(E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }\)
=> \(E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }\)
=> \(E = 0.0358\)
The 95% confidence interval is mathematically represented as
\(\r p - E < p < \r p + E\)
=> \(0.275 - 0.0358 < p < 0.275 + 0.0358\)
=> \(0.2392 < p < 0.3108\)
Consider the complex number ^w = , where z = x+iy and I = square root of -1. a) If w = I, determine z in the form z = r cos theta. b) Prove that w = (x3+2x+y3+y) + 1 (x+2y+2)/ (x+2)2+y2
c)Hence show that when Re(w) = 1 the points (x,y) lie on a straight line, l_1, and write down its gradient. d)Given arg(z)= arg(w) = pie/4,
a) If w = I, then we can write w = 0 + I. This means that x = 0 and y = 1. Using the polar form of a complex number, we can write z = r cos theta + I r sin theta. Since x = 0 and y = 1, we can write z = r cos theta + I r sin theta = 0 + I. This means that r cos theta = 0 and r sin theta = 1. Since cos theta = 0, theta = pi/2. Therefore, z = r cos (pi/2) = I.
b) To prove that w = (x^3+2x+y^3+y) + I (x+2y+2)/ (x+2)^2+y^2, we can substitute the values of x and y from the equation w = x + I y into the equation and simplify.
w = (x^3+2x+y^3+y) + I (x+2y+2)/ (x+2)^2+y^2
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= (x^3+2x+y^3+y) + I (x+2y+2)/ (x^2+4x+4+y^2)
= w
Therefore, the equation is true.
c) When Re(w) = 1, this means that the real part of w is equal to 1. Therefore, x^3+2x+y^3+y = 1. We can rearrange this equation to get y^3+y = 1-x^3-2x. Taking the derivative of both sides with respect to x, we get 3y^2 dy/dx + dy/dx = -3x^2-2. Solving for dy/dx, we get dy/dx = (-3x^2-2)/(3y^2+1). This is the gradient of the line l_1.
d) Given that arg(z) = arg(w) = pi/4, this means that the angle of both z and w is equal to pi/4. Using the polar form of a complex number, we can write z = r cos (pi/4) + I r sin (pi/4) and w = s cos (pi/4) + I s sin (pi/4). Since the angles are equal, this means that r cos (pi/4) = s cos (pi/4) and r sin (pi/4) = s sin (pi/4). Therefore, r = s and z = w.
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Find the values of x and y in parallelogram PQRS. PTy, TRx1, QTy, TSx = 7x+ 11
The values of x and y of the parallelogram PQRS are x = 2 and y = 11
What is the side length of the parallelogram?We're given the dimensions of parallelogram PQRS as;
PT = y
TR = 5x + 1
QT = 2y
TS = 6x + 10
T is the intersection of the two diagonals PR and QS and so the diagonals bisect each other.
The diagonal PR is cut into PT and TR, both of which are congruent or equal. Thus, PT = TR.
Similarly, the other diagonal QS is split in half as well. The two equal pieces are QT and TS. So QT = TS.
PT = TR
y = 5x + 1
and
QT = TS
2y = 6x + 10
Plugging the values gives;
2y = 6x + 10
2(y) = 6x + 10
2(5x + 1) = 6x + 10
2*5x + 2*1 = 6x + 10
10x + 2 = 6x + 10
10x + 2 - 6x = 6x + 10 - 6x
4x + 2 = 10
4x + 2 - 2 = 10 - 2
4x = 8
4x/4 = 8/4
x = 2
If x = 2, then y is...
y = 5x+1
y = 5*x+1
y = 5*2+1
y = 10+1
y = 11
Thus, the values of x and y of the parallelogram PQRS are x = 2 and y = 11
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Will a large-sample confidence interval be valid if the population from which the sample is taken is not normally distributed? explain
A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.
Yes, the large-sample confidence interval will be valid.
What is meant by normal distribution?A normal distribution is a type of continuous probability distribution for a real-valued random variable in statistics.
The normal distribution, also known as the Gaussian distribution, is a symmetric probability distribution about the mean, indicating that data near the mean occur more frequently than data far from the mean.
The confidence interval will be valid regardless of the shape of the population distribution as long as the sample is large enough to satisfy the central limit theorem.
What does a large sample confidence interval for a population mean?A sample is considered large when n ≥ 30.
By 'valid', it means that the confidence interval procedure has a 95% chance of producing an interval that contains the population parameter.
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Please Helppp pleaseeeeeeee pleaseeee
Answer:
Step-by-step explanation:
I can't see the screenshot
so like yeah
Round to the nearest tenth for the right triangle, wouldn't it be 20 or am I wrong?
I will give the crown this it is prob easy f(x) = f(x) = 1,264(1.09)x
Answer:
1377.76x
Step-by-step explanation:
Simplify 1264*1.09
Answer:
1377.76x
(give the person above the crown)
how many different three-step paths along the edges of a cube are there that take you from vertex $a$ to vertex $b$? (a step is from a vertex to an adjacent vertex sharing an edge.)
The total number of different paths which we can have as calculated from the given data is 6.
To know the number of different three-step paths along the edges of a cube are there that take us from vertex a to vertex b.
For the first path no of different ways = 3
For the second path no of different ways = 2
For the third path no of different ways = 1
Therefore , the total number of ways
= 3 x 2 x 1
= 6
The solid three-dimensional shape also known as a cube has six square faces, eight vertices, and twelve edges. A cube is also known as a hexahedron.
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K(8) if K(x) = 17 – 3(–x – 1)
Answer: k(8)=44
Step-by-step explanation:
We know that k(x)=17-3(-x-1) and we a trying to figure out what k(8) is
Sub 8 in for x and solve
k(8)=17-3(-(8)-1)
k(8)=17-3(-9)
k(8)=17-(-27)
k(8)=44
EASY PLEASE HELP I NEED ANSWER TO SEVEN
Answer: a, 9x10^9, largest number 900000000
Answer: greatest is A.
Step-by-step explanation:
Which pair of angles are alternate exterior angles of parallel lines v and w?
b° and d°
a° and b°
a° and d°
a° and c°
Answer:
a and d
Step-by-step explanation:
v and w are parallel lines
R is the transversal
Alternate exterior means on the opposite sides of the transversal and outside of the parallel linea
a and d are alternate exterior angles
A matched-subjects experiment produced a t statistic with a df of 19. How many subjects participated in this study
The number of subjects who participated in the study is 20.
To determine the number of subjects who participated in the study, we need to understand the relationship between the degrees of freedom (df) and the sample size in a t-test.
In a matched-subjects experiment, participants are typically matched based on certain characteristics or variables to create pairs or groups. Each pair or group is then exposed to different conditions or treatments, and the differences within each pair or group are analyzed.
This type of design is often used to minimize individual differences and increase the precision of the study.
In a matched-subjects t-test, the degrees of freedom are calculated based on the difference scores between the pairs or groups. The formula to calculate the degrees of freedom is:
df = n - 1
Where 'n' represents the number of pairs or groups.
In a matched-subjects design, each pair contributes one degree of freedom.
Given that the t statistic has a df of 19, we can set up the equation:
19 = n - 1
Solving for 'n', we add 1 to both sides:
19 + 1 = n - 1 + 1
20 = n
In summary, based on the given information, there were 20 subjects who participated in the matched-subjects experiment.
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The question may have one or more than one option correct
\(\displaystyle\int_0^1 \dfrac{x^4(1-x)^4}{1+x^2}dx\)
The correct option is/are
A) 22/7 - π
B) 2/105
C) 0
D) 71/15 - 3π/2
Answer:
To solve the integral, we can use partial fractions and then integrate each term separately. The integrand can be written as:
\(\dfrac{x^4(1-x)^4}{1+x^2} = \dfrac{x^4(1-x)^4}{(x+i)(x-i)}\)
Using partial fractions, we can write:
\(\dfrac{x^4(1-x)^4}{(x+i)(x-i)} = \dfrac{Ax+B}{x+i} + \dfrac{Cx+D}{x-i}\)
Multiplying both sides by (x+i)(x-i), we get:
\(x^4(1-x)^4 = (Ax+B)(x-i) + (Cx+D)(x+i)\)
Substituting x=i, we get:
\(i^4(1-i)^4 = (Ai+B)(i-i) + (Ci+D)(i+i)\)
Simplifying, we get:
\(16 = 2Ci + 2B\)
Substituting x=-i, we get:
tex^4(1+i)^4 = (Ci+D)(-i-i) + (Ai+B)(-i+i)\)
Simplifying, we get:
\(16 = 2Ai + 2D\)
Substituting x=0, we get:
\(0 = Bi + Di\)
Substituting x=1, we get:
\(0 = A+B+C+D\)
Solving these equations simultaneously, we get:
A = -22/7 + π
B = 0
C = 22/7 - π
D = -2/5
Therefore, the integral can be written as:
\(\int_0^1 \dfrac{x^4(1-x)^4}{1+x^2}dx = \int_0^1 \left[\dfrac{-22/7+\pi}{x+i} + \dfrac{22/7-\pi}{x-i} - \dfrac{2/5}{1+x^2}\right]dx\)
Integrating each term separately, we get:
\(\int_0^1 \dfrac{-22/7+\pi}{x+i}dx = [-22/7+\pi]\ln(x+i) \bigg|_0^1 = [\pi-22/7]\ln\left(\dfrac{1+i}{i}\right)\)
\(\int_0^1 \dfrac{22/7-\pi}{x-i}dx = [22/7-\pi]\ln(x-i) \bigg|_0^1 = [22/7-\pi]\ln\left(\dfrac{1-i}{-i}\right)\)
\(\int_0^1 \dfrac{-2/5}{1+x^2}dx = -\frac{2}{5}\tan^{-1}(x)\bigg|_0^1 = -\frac{2}{5}\tan^{-1}(1) + \frac{2}{5}\tan^{-1}(0) = -\frac{2}{5}\tan^{-1}(1)\)
Therefore, the correct options are:
A) \(\pi-\frac{22}{7}\)
B) \(\frac{2}{105}\)
C) 0
D) \(\frac{71}{15}-\frac{3\pi}{2}\)
Chess top uses the periodic inventory system. For the current month, the beginning inventory consisted of 200 units that cost p65 each. During the month, the company made two purchases: 300 units at p68 each and 150 units at p70 each. Chess top also sold 500 units during the month. Using the average cost method, what is the amount of ending inventory?.
The ending inventory amount is p68,000: (200 x 65) + (300 x 68) + (150 x 70) - (500 x 68) = 68,000.
1. Calculate the total cost of the beginning inventory: 200 units x p65 = p13,000
2. Calculate the total cost of the first purchase: 300 units x p68 = p20,400
3. Calculate the total cost of the second purchase: 150 units x p70 = p10,500
4. Calculate the total cost of the units sold: 500 units x p68 = p34,000
5. Calculate the total cost of the ending inventory amount : (13,000 + 20,400 + 10,500) - 34,000 = p68,000
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Find the inverse function of h(x)=-2/3x+6
Answer:
-3/2 (x - 6)
Step-by-step explanation:
Answer:
2nd option
Step-by-step explanation:
whats 500x200÷90+35
Answer:1146.11111
500*200 = 100,000
100,000 / 90 = 1111.11111
1111.11111+35 = 1146.11111
g the arrival rate is 9 / hour and the service rate is 14 / hour. the arrival and service distributions are not known so we can't use the m/m/1 formulas. if the average waiting time in the line is 18 minutes, then what is the total time spent in the system (at the carwash)
Based on the given information, we know that the arrival rate is 9 customers per hour and the service rate is 14 customers per hour. Since the arrival and service distributions are not known, we cannot use the m/m/1 formulas to calculate the average waiting time and total time spent in the system.
However, we can still use the Little's Law formula to relate the average number of customers in the system to the average waiting time. Little's Law states that the average number of customers in the system (N) is equal to the product of the arrival rate (λ) and the average time spent in the system (T), or N = λT.
Since we want to find the total time spent in the system, we can rearrange the formula to solve for T. Thus, T = N / λ.
We know from the given information that the average waiting time in the line is 18 minutes. Therefore, the average time spent in the system for a customer is T = 18 minutes + (1/14 hour), which is equal to 1.9 hours.
To calculate the total time spent in the system, we need to add the waiting time to the service time. Since the service rate is 14 customers per hour, the service time per customer is 1/14 hour or approximately 4.3 minutes. Thus, the total time spent in the system is approximately 22.3 minutes or 0.37 hours.
In summary, the average time spent in the system for a customer is 1.9 hours, and the total time spent in the system is approximately 22.3 minutes or 0.37 hours.
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please help me like i’m almost failing my math class please please please help
1) The figure shows a translation.
2) It is translation because every point of the pre - image is moved the same distance in the same direction to form an image.
3) Point A from the pre - image corresponds with Point D on the image.
We have to given that,
There are transformation of triangles are shown.
Now, From figure all the coordinates are,
A = (- 5, 3)
B = (- 4, 7)
C = (- 1, 3)
D = (- 1, - 2)
E = (0, 1)
F = (3, - 2)
Hence, We get;
1) The figure shows a translation.
2) It is translation because every point of the pre - image is moved the same distance in the same direction to form an image.
3) Point A from the pre - image corresponds with Point D on the image.
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A cyclist travels 6 miles in 15 minutes. What is her average speed in mph?
Answer:
24 miles per hour
Step-by-step explanation:
A cyclist travels 6 miles in 15 minutes. What is her average speed in mph?
Step one:
given data
distance= 6 miles
time= 15 minutes
convert minutes to hours
15 minutes is 0.25hours
Step two:
speed= distance/time
speed= 6/0.25
speed= 24 miles per hour
Pls help which one is it
Answer:
A
Step-by-step explanation:
For a movie 310 people bought tickets. Tickets cost $8 for students and $11 do adults. Ticket sales-added up to $3,074
How many patrons would you have had to poll to limit the width of the confidence interval to one slice?
The width of the interval to be one slice, the margin of error would be half of that, which is 0.5 slice.
To determine the number of patrons needed to limit the width of the confidence interval to one slice, we need to consider a few factors.
First, we need to know the desired level of confidence. Let's assume a 95% confidence level.
Next, we need to know the margin of error, which is half the width of the confidence interval. Since we want the width of the interval to be one slice, the margin of error would be half of that, which is 0.5 slice.
To calculate the sample size needed, we can use the formula:
n = (Z * σ / E)²
Where:
- n is the required sample size
- Z is the Z-score for the desired confidence level (95% corresponds to a Z-score of approximately 1.96)
- σ is the standard deviation (if known)
- E is the margin of error
Assuming we know the standard deviation (σ), we can plug in the values to calculate the sample size.
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what is the volume occupied by a mixture of 0.522 mol of N2 and 0.522 mol of O2 GASES AT .83 ATM AND 42.7C?
the volume occupied by the mixture of N2 and O2 gases at 0.83 atm and 42.7°C is approximately 41.62 liters.
To find the volume occupied by the mixture of gases, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure of the gases (in atm)
V = volume of the gases (in liters)
n = number of moles of gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature of the gases (in Kelvin)
First, let's convert the temperature from Celsius to Kelvin:
T(K) = T(C) + 273.15
T(K) = 42.7 + 273.15
T(K) = 315.85 K
Now we can calculate the volume:
For N2:
n(N2) = 0.522 mol
P(N2) = 0.83 atm
T = 315.85 K
For O2:
n(O2) = 0.522 mol
P(O2) = 0.83 atm
T = 315.85 K
Using the ideal gas law for each gas:
V(N2) = (n(N2) * R * T) / P(N2)
V(O2) = (n(O2) * R * T) / P(O2)
Calculating the volumes:
V(N2) = (0.522 * 0.0821 * 315.85) / 0.83
V(N2) ≈ 20.81 L
V(O2) = (0.522 * 0.0821 * 315.85) / 0.83
V(O2) ≈ 20.81 L
Since the number of moles and pressure are the same for both gases, the volumes will also be the same.
To find the total volume occupied by the mixture of gases, we can sum the individual volumes:
V(total) = V(N2) + V(O2)
V(total) = 20.81 + 20.81
V(total) ≈ 41.62 L
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Charlie's bag contains 4 blue pens and 3 red pens. He pulls out a pen at random, replaces it in the bag, and then pulls out a second pen at random. If the first pen is blue, what is the probability that the second pen is red
Three irrational numbers are given below. Select the option that correctly plots the approximate value of each number on the number line. First step shows the addition of 2 and square root of 5. Second step shows the subtraction of pi and 2. Third step shows division of square root of 21 by 2. A. A number line from 0 to 5 is divided into 5 equal parts. Square root of 21 over 2 is at the second part. Pie minus 2 is at the third part and 2 plus square root of 5 is at the fifth part. B. A number line from 0 to 5 is divided into 5 equal parts. 2 plus Square root of 5 is at the second part. Square root of 21 over 2 is at the third part and pie minus 2 is at the fifth part. C. A number line from 0 to 5 is divided into 5 equal parts. Pie minus 2 is at the second part. 2 plus square root of 5 is at the third part and square root of 21 over 2 is at the fifth part. D. A number line from 0 to 5 is divided into 5 equal parts. Pie minus 2 is at the second part. Square root of 21 over 2 is at the third part and 2 plus square root of 5 is at the fifth part.
The option that correctly plots the approximate value of each number on the number line is option D. A number line from 0 to 5 is divided into 5 equal parts. Pie minus 2 is at the second part. Square root of 21 over 2 is at the third part and 2 plus square root of 5 is at the fifth part.
How did we arrive at the option?First step shows the addition of 2 and square root of 5. Second step shows the subtraction of pi and 2. Third step shows division of square root of 21 by 2. This is expressed below:
2 + √5 ≈ 3.2 (approximate value)
π - 2 ≈ 1.1 (approximate value)
√21/2 ≈ 2.4 (approximate value)
So, following the steps above, the approximate value of each number on the number line is option D. A number line from 0 to 5 is divided into 5 equal parts. Pie minus 2 is at the second part. Square root of 21 over 2 is at the third part and 2 plus square root of 5 is at the fifth part.
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PLEASE HELP If the lengths of two sides of a triangle are 2 and 6, then the length of the third side cannot be:
a)5
b)6
c)7
d)4
Answer:
I think is A
Step-by-step explanation:
But I'm not sure
at the movie theatre child admission is 6.50 and adult admission is 9.80 On Tuesday, four times as many adult tickets as child tickets were sold, for a total sales of 1279.60 How many child tickets were sold that day
We find that 28 child tickets were sold on Tuesday.
To determine the number of child tickets that were sold on Tuesday, let x be the number of child tickets that were sold. Then, the number of adult tickets sold was four times the number of child tickets sold. Thus, the number of adult tickets sold is 4x.
The cost of one child ticket is $6.50, and the cost of one adult ticket is $9.80. Therefore, the total sales can be represented by the equation:6.50x + 9.80(4x) = 1279.60
Simplifying this equation gives: 6.50x + 39.20x = 1279.60
Combining like terms, the equation can be further simplified to:
45.70x = 1279.60 Solving for x gives: x = 28
Therefore, 28 child tickets were sold on Tuesday
In conclusion, if we assume that the number of child tickets sold is x, then we can calculate the number of adult tickets sold to be 4x. By multiplying the number of child tickets sold by the price of one child ticket and the number of adult tickets sold by the price of one adult ticket and adding the two values together, we obtain the total sales equation. Using this equation, we solve for x by simplifying and combining like terms.
Therefore, we find that 28 child tickets were sold on Tuesday.
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PLS HELP ASAP
Merlin wants to make more money selling fake beards this month than
he did last month. All black beards in his shop cost the same amount of
money, and all red beards in his shop cost $25.
Let B represent the number of black beards and R represent the
number of red beards that Merlin can sell to make more money than he
made last month.
20B+25R>350
According to the inequality, how much money did Merlin make last
month, and how much does each black beard cost?
Can Merlin achieve his goal by selling 6 black beards and 8 red
beards? explain why.
Answer:
According to the inequality, how much money did Merlin make last month more than? -> 350 dollars
Can Merlin achieve his goal by selling 6 black beards and 8 red
beards? explain why.
Yes, black beard sum will total up to $120 and red beard sum will total up to $200, $120+$200 = $320
$320 < $350
Step-by-step explanation:
plz mark as brainliest!
A number divided by 7 equals 3/21
Answer:
Step-by-step explanation:
21
Answer:
The answer is 3
Step-by-step explanation:
I dobt have an explanation, but if u use a calc then u can see that it equals 3/21.
write the equation in pointslope form of the line that passes through the given point with the given slope.
(4,-2) ;m=0.5
Answer:
y+2=.5(x-4)
Step-by-step explanation:
y-y₁=m(x-x₁)
y-(-2)=.5(x-4)
or
y+2=.5(x-4)