Answers
Answer:
Velocity and direction.
Explanation:
And speed
.
.
.
.
Related Questions
What has to happen to make new elements?
Answers
A 12 V battery is connected in series to a 50.0 ohm resistor and a 70.0 ohm resistor. What is the total resistance in the circuit?
Answers
Series connection
Net resistance
R1+R250+70120ohmExplanation:
We need to determine the total resistance also known as the net resistance that is occurring in the circuit. We need to combine the two resistors that are being used and that will give us the net.
50.0 ohm + 70.0 ohm
120.0 ohm
Answer: The net resistance is 120.0 ohm
List two types of current
Answers
Answer:
static and current electricity
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
Answers
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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Calculate the net force on the particle q1.
Answers
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
Refraction studes show that the Moho is depressed about 10 km beneath the center of the Hawaiian Islands. Assuming that this is the value of wo and that h=34 km, E= 70 GPa, v = 0.25. Pm Pw 2300 kg m-3, and g = 10 m s -2 determine the maximum bending stress in the lithosphere.
Answers
the maximum bending stress in the lithosphere is 202 MPa
hear
Given that Hite 34 km
12 2 70 9 Pa
N 2 0. 25
ρm- ρw= 2300 kgm 3
3 = 10 ms - 2
Moh depressed about 10km beneath the centre or Islands .
We know, flexural rigidity
Equation
D=E/12 (1 - V 2 )
be neath the center of Isla g
=70 x 109 pa x 103 x ( 10 m ) 312 (1 - 0.0625 )
=70 x 1021- Nm
=12X 019375Fox 10 212
=2 6: 222 x 102 Mm
Again , total maximum bending stress in the
lithosphere 6 = = 90 - ( 8 m - Pm ) 8 u
Where , Applied load of upper Surface of lithosph
We Replaced manthe rock thickness = 34 1
Bending stress = 6. 222 x 10' Alm- 2300 108 x 10->52 x 34 km
=n3 4
= 6. 2327 10 1/m- 230 0 kg x 10 m 2 x 34 x103 x]
=2 6 . 222 x 102/ nim - . 2300 X10 x 34x103 Pa
= 6222x1021 am 2 x 18 Alm
34x 34 x 34x( 103) ,m 3
6:222 X 102 Mm
2
3 4 x 3 4x34 x 109 m 3
2 6 .222 x 1012 na
34 x 34 x 39
6. 222
- x 10 2 pa
39, 304
2 0. 000 ( 5 8 307 10 - Pas
158, 83 X 108 pa .
-'. Bendig stress - 15.83 x108 pa . 782 x 10 Pa
2 15. 53 x108 pa - 7. 8 2x108 pc
Bendig stress=202 M Pa
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Question #1 A cabinet initially at rest on a horizontal surface requires a 115 N horizontal force to set it in motion. If the coefficient of static friction
between the cabinet and the floor is 0.38,what is the normal force exerted on the cabinet? What is the mass of the cabinet?
Step #4 Show all your work with units.
Step # 1. Draw a free body diagram with arrows and given
and known valuer
Answers
The Normal force = 302.63 N
How to solveFriction Force = 115 N
u*Normal force= friction,
u= 0.38,
N= 115/0.38
Therefore, the Normal force = 302.63 N
Mass is a fundamental feature of matter that quantifies the amount meaningful in an object. It is typically calculated in units of kilograms (kg) or grams (g). Mass is various from weight, that depends on the gravitational force pursuing an object, while mass debris constant although gravity.
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A 2.0-kilogram mass falls freely for 10. meters
near the surface of Earth. The total kinetic
energy gained by the object during its free fall
is approximately
Answers
The total kinetic energy gained by the object during its free fall is 2000.0 Joule.
What is kinetic energy?The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.
The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.
From the conservation of energy:
The total kinetic energy gained by the object during its free fall is = initial potential energy
= 2.0 × 10.0 × 10.0 Joule
= 2000.0 Joule.
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A 2.0-kilogram mass falls freely for 10 meters near the surface of Earth, and the total kinetic energy gained by the object during its free fall is approximately 196 J.
What is the significance of the total kinetic energy?The total kinetic energy gained by a falling object is calculated as follows:
KE = 0.5 × m × \(v^2\) ( m=mass , v = final velocity)
the fall can be calculated as v = √(2 * g * h)
Given that, m = 2.0 kg, h = 10.0 m, g = 9.8 m/\(s^2\)
v = √(2 ×9.8 × 10) = √(196) = 14.0 m/s
KE = 0.5 × 2.0 kg ×\(14^2\) = 0.5 × 2.0 kg × 196 \(m^2/s^2\) = 196 J
Hence, a 2.0-kilogram mass falls freely for 10 meters near the surface of Earth, and the total kinetic energy gained by the object during its free fall is approximately 196 J.
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a bottle full of water has a mass of 45g when full of mercury.its mass is 360g if the mass of the empty bottle is 20g. calculate the density of the mercury. state the order in which the reading will be taken
Answers
The density of mercury can be calculated using the formula:
Density = (mass of mercury) / (volume of mercury)
To calculate the volume of the mercury, we need to subtract the volume of the bottle from the volume of the bottle filled with mercury.
Volume of bottle = Volume of bottle filled with mercury - Volume of mercury
Let's assume that the volume of the bottle filled with mercury is V1 and the volume of the bottle is V2. We can then write:
Density of mercury = (mass of mercury) / (V1 - V2)
Given that the mass of the empty bottle is 20g, we can calculate the mass of the mercury as follows:
Mass of mercury = (mass of bottle filled with mercury) - (mass of empty bottle)
= 360g - 20g
= 340g
The mass of the bottle filled with water is 45g. Therefore, the mass of the mercury in the bottle is:
Mass of mercury = 360g - 45g = 315g
Let's assume that the density of the bottle is negligible. We can then calculate the volume of the mercury as follows:
Volume of mercury = (mass of mercury) / (density of mercury)
Substituting the values we have:
315g / (density of mercury) = (V1 - V2)
We know that the mass of the water in the bottle is 45g, which means that the mass of the mercury is (360g - 45g) = 315g. Therefore, the volume of the mercury is equal to the volume of the water. We can then write:
Volume of mercury = Volume of water = (mass of water) / (density of water)
The density of water is 1 g/cm³. Substituting the values we have:
315g / (density of mercury) = 45g / 1 g/cm³
Solving for the density of mercury, we get:
Density of mercury = (315g * 1 g/cm³) / 45g
= 7 g/cm³
Therefore, the density of mercury is 7 g/cm³.
The order in which the readings will be taken is as follows:
1. Mass of empty bottle
2. Mass of bottle filled with mercury
3. Mass of bottle filled with water (or the mass of the bottle filled with mercury and the mass of the empty bottle, from which we can calculate the mass of the mercury)
4. Volume
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♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
A computer and monitor use 800J of electric energy each second. The monitor produces 30J of light
energy each second. The fan in the computer converts 15J each second into kinetic energy. The lights on
the tower give off 10J of light energy. If all the remaining energy is converted into heat, what percentage
of the initial electric energy was converted into useful forms
Answers
Throughout the reflection, make sure
you have a copy of the Student Guide and your data tables.
In this experiment, the
was intentionally manipulated. This was the independent variable
The dependent variable measured was the
Answers
Induced current
Explain why adding globes in parallel makes no difference to their brightness? What did you notice about the current?
(immediate response please)
Answers
Adding globes in parallel makes no difference to their brightness because all the bulbs glowed with the same brightness indicating that the current flowing through the bulbs had the same value.
The current in each light bulb was the same.
What is electric current?An electric current is a flow of electrons as a result of a potential difference between two points in conductor.
Electrons are negatively-charged particles that are one of the fundamental particles of an atom. The flow of electrons through a conductor is able to do work.
Two or more globes in a simple parallel circuit do not experience any drop in the voltage, thus allowing the maximum flow of electric current. Also, connecting devices in a parallel circuit ensures that if one of the component lops is disconnected, the flow of current through the other loops remains intact.
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In this circuit, what is the potential difference across C4?
Use the following values in your calculation:
V = 12.0 V
C1 = 3.0 ?F
C2 = 2.0 ?F
C3 = 2.0?F
C4 = 1.0 ?F
C5 = 4.0 ?F
V4 =
Answers
The potential difference across C4 can be found using the equation V = V4 - V3. Using the given values, V = 12.0V, C1 = 3.0 ?F, C2 = 2.0 ?F, C3 = 2.0 ?F, C4 = 1.0 ?F, and C5 = 4.0 ?F, we can solve for V4.
V4 = 12.0V + (3.0 ?F + 2.0 ?F + 2.0 ?F + 1.0 ?F) / (1.0 ?F + 4.0 ?F)
V4 = 12.0V + (8.0 ?F / 5.0 ?F)
V4 = 12.0V + 1.6V
V4 = 13.6V
Therefore, the potential difference across C4 is 13.6V - 12.0V = 1.6V.
The potential difference across C4 can be determined using the formula Q = CV. Where Q represents the charge stored in the capacitor, C represents capacitance, and V represents the potential difference across the capacitorTo determine the potential difference across C4, we can use the formula Q = CV. To determine Q, we need to determine the equivalent capacitance of the circuit.
The equivalent capacitance of capacitors in parallel is equal to the sum of their capacitance. The equivalent capacitance of capacitors in series is equal to the reciprocal of the sum of their reciprocals.C1, C2, and C3 are in series, and their equivalent capacitance is given by:C_eq1=1/((1/C1)+(1/C2)+(1/C3))=1/(1/3+1/2+1/2)=3/7 μF{C_eq1=1/((1/C1)+(1/C2)+(1/C3))=1/(1/3+1/2+1/2)=3/7μF}C_eq2 is the equivalent capacitance of C4 and C5 in parallel.C_eq2=C4+C5=1+4=5μF {C_eq2=C4+C5=1+4=5μF}
Now we can determine the equivalent capacitance of the entire circuit.C_eq=C_eq1+C_eq2=3/7+5=38/7μF{C_eq=C_eq1+C_eq2=3/7+5=38/7μF}Now, we can determine the charge stored in the circuit.Q=C_eqV=38/7*12= 65.14μC{Q=C_eqV=38/7*12=65.14μC}To determine the potential difference across C4, we can use the formula Q = CV.V=C4Q/C4= 65.14/1 = 65.14V{V=C4Q/C4=65.14/1=65.14V}Therefore, the potential difference across C4 is 65.14 V.
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
Answers
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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what is the processes found at a divergent boundary that helps form metamorphic rocks, igneous rocks, and sedimentary rocks. I need the process name for each one pls
Answers
At a divergent boundary, heat and pressure can cause metamorphism, magma can solidify to form igneous rocks, and sediments can accumulate and lithify to form sedimentary rocks. These three processes contribute to the formation of various types of rocks.
At a divergent boundary, three main processes occur that can lead to the formation of metamorphic, igneous, and sedimentary rocks:
1. Metamorphic rocks: Heat and pressure from the divergent boundary can cause existing rocks to be metamorphosed, or transformed, into new rocks with different textures and mineral compositions. This process is called metamorphism.
2. Igneous rocks: Magma, which is molten rock, can rise to the surface at a divergent boundary and cool and solidify to form igneous rocks. This process is called solidification or crystallization.
3. Sedimentary rocks: Sediments, such as sand and mud, can accumulate in the low-lying areas near a divergent boundary, such as in rift valleys or on the continental shelf. Over time, these sediments can be compacted and cemented together to form sedimentary rocks. This process is called lithification.
Hence, Heat and pressure at a divergent boundary can produce metamorphism, solidify magma to create igneous rocks, and accumulate and lithify sediment to create sedimentary rocks. Different sorts of rocks are formed as a result of these three processes.
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Find the ratio of the diameter of aluminum to silver wire, if they have the same resistance per unit length (as they might in household wiring).dAl/dAg =
Answers
Given:
The resistance per unit length of aluminum is equal to the resistance per unit length of silver i.e.,
\(\frac{R_{Al}}{l_{Al}}=\frac{R_{Ag}}{l_{Ag}}\)Required: The ratio
\(\frac{d_{Al}}{d_{Ag}}\)Explanation:
The resistance of aluminum is given by the formula
\(\begin{gathered} R_{Al}=\rho_{Al}\frac{l_{Al}}{A_{Al}} \\ \frac{R_{Al}}{l_{Al}}=\frac{\rho_{Al}}{\pi(r_{Al})^2} \\ \frac{R_{Al}}{l_{Al}}=\frac{\rho_{Al}}{\pi(\frac{d_{Al}}{2})^2} \end{gathered}\)The resistance of silver is given by the formula
\(\begin{gathered} R_{Ag}=\rho_{Ag}\frac{l_{Ag}}{A_{Ag}} \\ \frac{R_{Ag}}{l_{Ag}}=\frac{\rho_{Ag}}{\pi(r_{Ag})^2} \\ \frac{R_{Ag}}{l_{Ag}}=\frac{\rho_{Ag}}{\pi((d_{Ag})\/2)^2} \end{gathered}\)Since,
\(\frac{R_{Al}}{l_{Al}}=\frac{R_{Ag}}{l_{Ag}}\)On substituting the values, the ratio can be calculated as
\(\begin{gathered} \frac{\rho_{Al}}{\pi(\frac{d_{Al}}{2})^{2}}=\frac{\rho_{Ag}}{\pi(\frac{(d_{Ag})}{2})^{2}} \\ \frac{\rho_{Al}}{(d_{Al})^2}=\frac{\rho_{Ag}}{(d_{Ag})^2} \\ \frac{(d_{Al})^2}{(d_{Ag})^2}=\frac{\rho_{Al}}{\rho_{Ag}} \\ \frac{d_{Al}}{d_{Ag}}=\sqrt{\frac{\rho_{Al}}{\rho_{Ag}}} \end{gathered}\)Thus, the ratio is
\(\frac{d_{Al}}{d_{Ag}}=\sqrt{\frac{\rho_{Al}}{\rho_{Ag}}}\)Final Answer: The ratio of the diameter of aluminum to silver is the square root of the ratio of resistivity of aluminum to silver.
How heavier elements formed during stellar nucleosynthesis and evolution?
Answers
Answer:
i honestly think its 21
Explanation:
da memes
10 + 10 =21
Which description tells two processes scientists think move Earth's lithospheric plates?
Responses
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and friction between the plate and the asthenosphere
gravity acting on the edges of plates and friction between the plate and the asthenosphere
convection in the mantle and pressure of magma on the edge of the plate
Answers
The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.
What is the Earth's lithosphere?The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.
The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.
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Answer: convection in the mantle and pressure of magma on the edge of the plate
Explanation: I took the unit test
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
Answers
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 275 N in the positive x direction to try and move the 61 kg refrigerator. The coefficient of static friction is 0.58. (a) How much static frictional force does the floor exert on the refrigerator
Answers
Answer:
f = 347.08 N
Explanation:
The frictional force exerted by the floor on the refrigerator is given as follows:
\(f = \mu R = \mu W\)
where,
f = frictional force = ?
μ = coefficient of static friction = 0.58
W = Weight of refrigerator = mg
m = mass of refrigerator = 61 kg
g = acceleration due to gravity = 9.81 m/s²
Therefore,
\(f = \mu mg\\f = (0.58)(61\ kg)(9.81\ m/s^2)\\\)
f = 347.08 N
x-14=42 x=56
56______a solution
Answers
The human eye is very sensitive to light having a wavelength of 5.51 ✕ 10-7 m, which is in the green-yellow region of the visible electromagnetic spectrum. What is the frequency of this light?
Answers
Answer:
\(F = 5.44 * 10^{14}\ Hz\)
Explanation:
Given
\(Wavelength = 5.51 * 10^{-7}m\)
Required
Determine the Frequency (F)
Represent the wavelength with W
The relationship between W and F is:
\(F = \frac{c}{W}\)
Where
c = Speed of Light
\(c = 3 * 10^8 m/s\)
Substitute values for c and W
\(F = \frac{3 * 10^8}{5.51 * 10^{-7}}\)
\(F = \frac{3 * 10^{8+7}}{5.51}\)
\(F = 0.5444646098 * 10^{8+7}\)
\(F = 0.5444646098 * 10^{15}\)
\(F = 5.444646098 * 10^{14}\)
\(F = 5.44 * 10^{14}\ Hz\)
Explain how the movement of the Moon around the Earth c langes we see at night?
Answers
Answer: We can see the moon at night because the earth spins in a circle wall it is going around the sun so when the sun go down and the moon comes up the suns light will go over the top of earth and hite the moon the all the light that is hite the moon will bounce off it and the moon it a light color and light shins off lighter colored thing and it will have a little proportion of that light will come and hite earth make the moon very easy to see at night and the most light hits the moon when if it a full moon and is the most brite.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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A car traveled to the right 4.2 km and made a 90 degree turn and traveled straight for
another 2.6 km. What is the total displacement of the car? Be sure to show your work.
Answers
Answer:
4.9 km
Explanation:
\(\sqrt{4.2^2+2.6^2}=4.9 km\)
Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.
Answers
Can you answer this question?
Answers
The equivalent resistance between the point A and B is 0.95 ohm.
Define resistance ?
Resistance means the degree to which a substance or device opposes the passage of an electric current, causing energy dissipation. It is measured in ohms, symbolized by the Greek letter omega (Ω). Resistance is also defined as the opposition offered by a body or substance to the passage through it of a steady electric current.
What is meant by ohms law?
Ohm's law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit. It states that the current through a conductor between two points is directly proportional to the voltage across the two points. The law is named after Georg Simon Ohm, a German physicist who discovered it,
Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be
1 / R = (1 /R3) + (1 / R4) + (1 / R6)
= (1 / 4.4) + (1 / 3.5) + (1 / 6.6)
1 / R = 0.79
R = 1.43 ohm.
Next solving R6 and leg of this resistance which are in series connection,
r = R + R6
= 1.43 + 7.1)
r = 8.53 ohm.
Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,
1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)
= 1.04 ohm
Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.
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Two long parallel wires 0.552 meter apart are each carrying 1.75 amperes of current, as shown(a) Find the magnitude and direction of the magnetic field at point A due to the current in the top wire. (b) Find the magnitude and direction of the force per unit length this field exerts on the bottom wire.
Answers
,Given,
Distance between two-wire, d=0.552 m
Current through the wires, I=1.75 A
(a) The magnetic field at a point on the bottom wire due to top wire is given by,
\(B_a=\frac{\mu_0I_1}{2\pi d}\)Where μ₀ is the permeability of the free space.
The direction is given by the right-hand thumb rule. According to this, the direction of the magnetic field produced by top wire will into the plane of the two wires.
On substituting the known values in the above equation,
\(B_a=\frac{4\pi\times10^{-7}\times1.75}{2\pi\times0.552}=6.34\times10^{-7}\text{ T}\)The force per unit length is given by,
\(F=I_2\times B_a\)The direction is given by the right-hand rule. According to this the force is directed towards the top wire.
On substituting the known values in the above equation,
\(F=1.75\times6.34\times10^{-7}=1.11\times10^{-6}\text{ N}\)Therefore the magnetic field acting on the bottom wire due to the current in the top wire is 6.34×10⁻⁷ T and the magnetic force due to this field is 1.11×10⁻⁶ N
The image to the left shows Earth’s major plates. A geologist is studying a plate boundary indicated by the arrow. Fill in the blank to complete the statement about the plate boundary. This boundary is between the African Plate and the Plate.
Answers
Answer:
The Eurasian Plate
Explanation:
The Eurasian plate is one of the most extended on Earth, crossing all of Asia and Europe. The Eurasian plate is between the North American and the African Plates on the north and west sides. The Eurasian plate crushed up above the Indian plate. The Tibetan plateau and the Himalayan mountain range formed due to the crush between the Eurasian Plate and Indian Plate, which started 50 million years ago.
Answer:
The Eurasian plate.
Explanation:
I took an assinment on Edge 2020.
Find the radius and the circumference to the nearest hundredth when d ≈ 3.6 in. Use 3.14 for π. Drag and drop the correct number into each box to complete the answers.
The radius is approximately _ inches.
The circumference is approximately _ inches.
Answers
Explanation:
the radius is always half of the diameter.
so, the radius is approximately 3.6/2 = 1.8 in.
and the circumference of a circle is
2×pi×r = d×pi = 3.6×3.14 = 11.304 ≈ 11.3 in.