for water to change into the gas phase, energy is required to break hydrogen bonds between h2o molecules. this energy is referred to as:

Answer:

1/2

Explanation:

According to this question, the gene coding for fur color in rabbits contains two alleles viz: alelle for brown fur ( B) is dominant, while the allele for black fur ( b) is recessive. This means that an heterozygous rabbit (Bb) will have brown fur.

Based on the question, one rabbit has the dominant allele for brown fur and the recessive allele for black fur i.e genotype Bb, another rabbit has two recessive alleles i.e. genotype bb. If these two rabbits cross i.e. Bb × bb, the proportion of the offsprings produces will have Bb, Bb, bb and bb genotype.

Bb is dominant, hence, 1/2 of the offsprings will be brown furred.

one species of rabbit, . the two rabbits have offspring, what are the

As the temperature increases the kinetic energy of particles increases and as a result, there is an increase in the movement of particles.

Here the volume of the gas is kept constant as the student takes the gas in a rigid container. So here we can apply Gay Lussac's Law. The law states that "  pressure exerted by a gas (of a given mass and kept at a constant volume) varies directly with the absolute temperature of the gas." That is the pressure is directly proportional to the temperature.

As the temperature increases the kinetic energy increases, thus the movement of particles increases. As the particle movement is increased the collision on the wall of the container increases. Pressure is the force exerted per unit area, as a result, the pressure increases.

   P ∝ T

  P = k× T, where k is the proportionality constant

P/T = k

P1/T1 = P2/T2

0.70/299 = P2/ 425

 P2 = (0.70 ×425) / 299

      = .99 atm

The pressure is thus increased and the motion of the particle is increased

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For benzene (C_6H_6), AE = 30 and NE = 38. The structure of benzene can be represented as a hexagon with alternating double and single bonds as shown below:  This structure allows for the eight-electron deficiency to be eliminated. Each carbon atom in the benzene ring forms three covalent bonds to other atoms in the ring, satisfying the octet rule. The double bonds between the carbon atoms in the ring each provide two electrons, while the single bonds provide one electron, allowing for the deficiency to be filled.

Benzene is an organic compound with the chemical formula C₆H₆. The benzene molecule is composed of six carbon atoms bonded in a ring, with one hydrogen atom attached to each carbon atom.

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Answer:

It's d love

Explanation:

Answer:

have a negative electrical charge of one (-1)

Explanatio

Electrons have an electrical charge of negative one. When you think electron, always think -1

The formula of the molecule made by adding one fructose to a molecule of lactose is C24H42O21.

When fructose is added to lactose, a glycosidic bond forms between the fructose and lactose molecules. Lactose is a disaccharide consisting of one molecule of glucose and one molecule of galactose, linked by a β-glycosidic bond. Fructose, on the other hand, is a monosaccharide. The addition of one fructose molecule to lactose results in the formation of a trisaccharide. The fructose molecule attaches to the lactose molecule at the hydroxyl group of either the glucose or galactose unit, forming a new glycosidic bond.

The formula of the resulting molecule, C24H42O21, represents the combined molecular formula of the fructose, glucose, galactose, and the water molecule that is released during the formation of the glycosidic bond. This trisaccharide retains the general structure and properties of its constituent sugars but possesses a unique arrangement due to the formation of the glycosidic bond.

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Answer:

Formation of precipitate?

Explanation: When you do that the thingy dissolves the thingy so the thingy dissolves into nothingness of the nothing...

Answer:

13.6 g

Explanation:

The mass of BeF₂ present in 655 ml of a solution that is 0.442 M is equal to 13.82 g.

We can calculate the concentration of a solute in a solution in terms of molarity, molality, and normality.

The molarity of a particular solution can be determined from the number of moles of a solute per unit volume of the solution.

The Molarity of the particular solution can be determined from the mathematical formula mentioned below:

Molarity = Moles/Volume of the Solution

Given, the molarity of BeF₂ solution = 0.442 M

The volume of the BeF₂ solution, V = 655 ml = 0.655 L

The molar mass of the BeF₂, M = 47.01 g/mol

Molarity of BeF₂ solution = m/(M × V)

0.442 = m/ (47.01 × 0.655)

m = 13.82 g

Therefore, 13.82 g of BeF₂ is required for the given solution.

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a. low melting point: Nonmetals. b. shiny: Metals. c. poor conductor: Nonmetals. d. ductile: Metals. e. malleable: Metals. f. brittle: Nonmetals. g. good conductor: Metals. h. high melting point: Metals

a. Low melting point is generally displayed by nonmetals. Metals tend to have high melting points.

b. Metals are typically shiny due to their ability to reflect light.

c. Nonmetals are generally poor conductors of heat and electricity.

d. Metals are ductile, meaning they can be drawn into thin wires without breaking.

e. Metals are malleable, meaning they can be hammered into thin sheets or shapes without shattering.

f. Nonmetals are usually brittle, meaning they are prone to breaking or shattering when subjected to stress.

g. Metals are good conductors of heat and electricity.

h. Metals typically have high melting points compared to nonmetals.

It's important to note that these are general trends and not absolute characteristics for all metals or nonmetals. Some exceptions or variations may exist within specific elements or compounds.

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Answer:

80.2

Explanation:

we subtract 18.2 from the total percentage which is 100%

The measured dipole moment of a polar covalent compound is 1.11 D with a percent ionic character of 18.2%. Therefore, the bond length of this compound will be 1.270 angstrom.

Dipole moment results due to the separation of charges in a compound. Dipole moment can occur between the two ions present in an ionic bond or between the atoms present in a covalent bond. Dipole moment occurs due to the differences in electronegativity of atoms. The larger the difference in electronegativity between ions, the larger the dipole moment of the compound.

The bond length of the compound can be calculated with the help of the formula:

Measured dipole moment = 1.11 D

Theoretical bond length = 4.8×bond length

Percentage ionic character =  (μ₁ / μ₂) × 100

where, μ₁ = μ theoretical,

μ₂ = μ experimental

Putting the values in formula we get,

18.2 = (1.11/ 4.8 × bond length) × 100

Bond length = (1.11/ 4.8 × 18.2) × 100

Bond length = 111/ 87.36

Bond length = 1.270

Therefore, the bond length of the dipole is 1.270 angstrom.

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There are many scenarios in which the situation in question may take place, the rule is that for this to happen, the temperature and pressure of the gas must change by the same amount.

As stated, the temperature and the pressure of the enclosed gas may change, in which they may increase or decrease, but the change must be by the same magnitude for each value. What this means is that is temperature increases by 5, so then must the pressure.

This is due to the relationship between the temperature and the pressure of an enclosed gas when using the combined gas law. The law takes the form of a fraction in which the pressure is found as part of the numerator and the temperature is part of the denominator, therefore, by increasing at the same rate, the final product and the volume will not be affected.

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Answer:

A scenario where volume dosent change is when both temperature and pressure are doubled or tripled

Explanation:

p1v1/t1=p2v2/t2

The first step of the reaction, we have  reaction between a nucleophile and an electrophile.

We can see that in the first step of the reaction, we have  reaction between a nucleophile and an electrophile. In this case, the electrophile would have to be an alkyl halide which produces a carbocation as show in the image attached. What we have here is quite similar or  like most of the organic reactions, this reaction occurs in a number of detailed or smaller steps and each step of the reaction is going to help to bring us closer to the end product of the entire steps of the reaction which is wat we target as we carry out the particular reaction.The second step involves the reduction of the alkyne with the use of a Lindlar catalyst. As such the reaction is poisoned and it stops at the alkyne stage rather than going on to obtain the alkane.

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The carbon engineering technologies forward the carbon dioxide capturing methods. The first step involved in the air contactor is given below:

\(\rm CO_{2} + 2 KOH \rightarrow H_{2}O + K_{2}CO_{3}\)

Nowadays evolution of greenhouse gases such as carbon dioxide is causing serious issues such as global warming. Industries and factories are uncontrollably release these gases to the atmosphere.

Carbon engineering designs the techniques for direct capture of carbon dioxide. The methods include an air contactor with the reaction given above and a pelletizer where, the KOH and calcium carbonate produces calcium hydroxide.

A calcinator decomposes the calcium carbonate forming the carbon dioxide  which is  captures.

\(\rm CaCO_{3} \rightarrow CO_{2} + CaO\)

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The compound that would show major fragment ions at m/z 73 and 59 is (B) OH CH3CH CH2CHCH3 OH. This compound is an alcohol with the molecular formula C6H12O2.

When analyzing the fragmentation pattern of a compound in mass spectrometry, the m/z values correspond to the mass-to-charge ratio of the ions formed. In this case, the compound forms two significant fragment ions at m/z 73 and 59.

For compound (B), the m/z 73 ion can be formed by breaking the C-C bond between the central CH and CH2 groups, resulting in an ion with the structure CH3CH(OH)CH2+. The m/z 59 ion can be generated by breaking the C-O bond in the OH group and losing an H from the adjacent CH2, creating the ion CH3CHCH2CHCH3+.

In summary, compound (B) OH CH3CH CH2CHCH3 OH is the one that would show major fragment ions at m/z 73 and 59 due to the fragmentation patterns explained above.

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Answer:

100% of the energy entering earth's atmosphere comes from the sun. ~50% of the incoming energy is absorbed by the earth's surface i.e. the land and oceans. ~30% is directly reflected back to space by clouds, the earth's surface and different gases and particles in the atmosphere (the earth's albedo is 0.3 on average)

Explanation:

:)

Answer:

The answer that completes the question are in BOLD:

At chemical equilibrium, the amount of PRODUCT AND REACTANT REMAIN CONSTANT because the RATES OF THE FORWARD AND REVERSE REACTIONS ARE EQUAL.

Explanation:

In a reversible chemical reaction, an equilibrium is said to be achieved when the rates of the forward reaction is equal to that of the reverse reaction. A reversible reaction is one in which products are formed from reactants simultaneously with the formation of reactants from products.

The combination of two or more substances called REACTANTS gives rise to another substance called PRODUCT, which can in turn give rise to Reactants again. With time, the rate at which the reactants give rise the products, which is called the FORWARD REACTION will be equal to the rate at which the products give rise to the reactants, which is called REVERSE REACTION. At this point, the chemical reaction is said to be in a STATE OF EQUILIBRIUM.

When the rate at which both reaction occurs becomes equal i.e. at an equilibrium state, the concentration of both the reactants and the products becomes constant i.e. no longer changes. Hence, the amount of the reactants forming the products is the same as the amount of products forming the reactants.

N.B: At chemical equilibrium, the amount of the reactants and products does not necessarily equals zero (0). It simply means that there is no net change in the concentration/amount of both reactants and products.

The empirical formula for the hydrocarbon is CH₂.

The combustion reactions are :

C + O₂ --> CO₂

H₂ + 1/2 O₂ --> H₂O

The molar mass of CO₂ =b 44 g/mol

The Mass of Carbon, C = (15.4 g CO₂)(1mol/44g)(1 mol C/1 mol CO₂)(12 g/mol)

The Mass of Carbon, C = 4.2 g C

The Mass of H = 5 - 4.2

The Mass of H = 0.8 g

The Moles C = 4.2 / 12 = 0.35

The Moles H = 0.8 / 1 = 0.8

Dividing by the smallest one :

The Moles of C = 1

The Moles of H = 2

The empirical formula of the hydrocarbon is CH₂ with the complete combustion of the 5 g of hydrocarbon.

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Wine was produced 37 years ago (1984 as usual year 15,2021) that is shown in the calculations below.

Reaction rate is calculated using the formula rate = Δ[C]/Δt, where Δ[C] is the change in product concentration during time period Δt. The rate of reaction can be observed by watching the disappearance of a reactant or the appearance of a product over time.

The time can be represented as follows:

t= 2.303\∧ log A0/A

∧= 0.693/t 1/2

The rate of a reaction is proportional to the reciprocal of the time taken. Rate α 1 time Rate is inversely proportional to time. Units: s-1, min-1 etc.

The given parameters are as follows:

t1/2=12.3

A0=5.5

A=0.688

t= 2.303/(0.693/12.3) log (5.5/0.688)

t=36.9

t=37 years

Thus, wine was produced 37 years ago (1984 as usual year 15,2021)

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Answer: 15.8 g of \(KMnO_4\) will be required to produce 1.60 grams of \(O_2\)

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} O_2=\frac{1.60g}{32g/mol}=0.05moles\)

\(2KMnO_4\rightarrow K_2MnO_4+MnO_2+O_2\)

According to stoichiometry :

As 1 mole of \(O_2\) is given by = 2 moles of \(KMnO_4\)

Thus 0.05 moles of \(O_2\) is given by =\(\frac{2}{1}\times 0.05=0.10moles\)  of \(KMnO_4\)

Mass of \(KMnO_4=moles\times {\text {Molar mass}}=0.10moles\times 158g/mol=15.8g\)

Thus 15.8 g of \(KMnO_4\) will be required to produce 1.60 grams of \(O_2\)

Answer:

copper carbonate reaction is known as the termed of thermal decomposition

reaction

Answer:

B. H2SO4 + BaCl 2 --------> BaSO4 + 2HCl

Explanation:

Neutralization reactions are characterized by their reactants of acids and bases reacting to form salt and water. All of the options except B, have formation of salt and water. Also, B is more likely a percipitation reaction (also a double displacement reaction) and not neutralization.

\( \text{Given, Concentration of HCl}= 10 {}^{ - 6} M\)

\( \text{After Dilution conc. of HCl =} \frac{10 {}^{ - 6} }{100} = {10}^{ - 8}M \)

\( \therefore \text{pH = - log[H}^{ + } ]\)

\( \therefore \text{ pH }= - \log [{} {10}^{ - 8}] = 8\)

\( \text{But} \: \text{This} \: \text{Is} \: \text{Not True Because} \\ \text{ An Acidic Solution Cannot have} \text{pH Greater than 7.} \\ \text{ In this case} [ {H}^{ + } ] \text{ Ions Of Water Molecule} \\ \: \text {Cannot Be Neglected.}\)

\( {[H}^{ + } ] = {[H}^{ + } ] _{HCl} +{ [H + }^{ } ] _{H_2 O}\)

\([H {}^{ + } ][OH {}^{ - } ] = 10 {}^{ - 14} \\ [H {}^{ + } ] = {10}^{ - 7} \\ [H {}^{ + } ] \text{total} = {10}^{ - 8} + {10}^{ - 7} \\ = {10}^{ - 8} (1 + 10) \\ = 11 \times {10}^{ - 8} \)

\( \text{Now from, pH} = - \text{log}[H {}^{ + } ] \\ = \text{ - log}(11 \times {10}^{ - 8} ) \\ = - \text{ log}11 - \text{ log} {10}^{ - 8} \\ = 6.957\)

Answer:

The electronic configuration of ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Explanation:

Lithium metal, Li will lose 1 electron to lithium ion Li+. Chlorine atom, Cl will receive the 1 electron to form the chloride ion Cl- as shown by the following equation below:

Li —> Li+ + e

Cl+ e —> Cl-

Combine both equation

Li + Cl + e —> Li+ + Cl- + e

Cancel out 'e'

Li + Cl —> Li+ Cl-

Thus, we can write the electronic configuration for the reaction as follow:

Before reaction:

Li (3) => 1s2 2s1

Cl (17) => 1s2 2s2 2p6 3s2 3p5

After reaction

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Therefore, the electronic configuration of the ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Answer:

H2 is a gas which forms when two hydrogen atoms bond together and become a hydrogen molecule. H2 is also called molecular hydrogen.It consists of two protons and two electrons. Consequently it is the most common form of Hydrogen because it is stable with a neutral charge.

Explanation:

The statement for the element hydrogen typically exists as the compound H2, "it is stable with a neutral charge."

An element is a substance that cannot be divided into smaller substances through normal chemical processes. All matter is composed of elements, which are the basic building blocks.

The hydrogen molecule is the most basic covalently bound material. H2 is a gas created when two hydrogen atoms combine to form a hydrogen molecule. Molecular hydrogen is another name for H2. There are two protons and two electrons in it. As a result of its stability and neutral charge, it is the most prevalent type of hydrogen. H2 is a molecule that is not a free radical.

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what is a chemical reaction?

A chemical reaction is a process in which one or more reactants are transformed into one or more products. Chemical elements and compounds are both substances. The component atoms of the reactants are rearranged in a chemical reaction, resulting in distinct compounds as products.

Answer:

100

Explanation:

Answer:

It’s B just did it

Explanation:

Answer:

B.

Explanation: i just tookthe quiz ya welcome.

Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, -1.046KJ of heat are given off when 5.0 g of water cools from 75 °C to 25 °C.

Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.

Mathematically,

Enthalpy=mass of water× specific heat capacity of water× Change in temperature

mass of water= 5.0 g

specific heat capacity of water=4.186J/g°C

Change in temperature=final temperature - initial temperature

= 25 °C- 75 °C

=-50°C

Substituting all the given values in the above equation, we get

Enthalpy=5.0× 4.186× -50°C

Enthalpy=-1,046.5J=-1.046KJ

Therefore, -1.046KJ of heat are given off when 5.0 g of water cools from 75 °C to 25 °C.

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