For the FCF in Bubble 20 on the Plate Demo drawing, which datum
feature would have 2
points of contact with its TGC?

Answers

Answer 1

Datum Feature in Plate Demo Drawing Bubble 20

In the Plate Demo drawing bubble 20, the datum feature that would have two points of contact with its True Geometrical Counterpart (TGC) is the cylinder.

The Feature Control Frame (FCF) is used to provide a set of rules that determine how and where the feature's characteristics can deviate from their perfect feature. The datum feature and the TGC are two of the most critical components of the FCF.

A datum feature is a physical feature that represents a theoretically perfect surface or axis. In contrast, the TGC is a virtual condition that symbolizes the perfect datum feature's position, orientation, and form.

The datum feature and the TGC are used to provide a reference system that specifies the location, orientation, and form of all other features on the part. In bubble 20 of the Plate Demo drawing, the datum feature has two points of contact with its TGC.

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Related Questions

If the pressure head in the aquifer is 100 ft., calculate the effective stress (N/m") in the aquifer.
If the aquifer is pumped and the hydraulic head at some point is reduce by 12 ft., what will be the resulting changes in the pressure head (m), the effective stress (N/m*), the fluid pressure (N/m*), and the total stress (N/m? ?

Answers

The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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vehicle turn signals must be visible from _____ feet in normal sunlight.

Answers

Vehicle tail lights must be visible from 500 feet to the rear in normal sunlight.

For most of the vehicles around the world, the tail lights are red. The brake lights appear to be luminous red. Tail lights also include the backup lights. They are white in color. The idea of "red signifies stop". It has always been connected to danger and warnings. Red can be an indication of caution as well as dangerous plants and insects in the natural world around the world. Green signifies go.

The wavelength of red light is the highest of all the available wavelengths(620-750 nm). Due to this, we can travel the largest distance.

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A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using conservation of energy (start with Ebefore = Eafter).​

Answers

Answer:

\(mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1} \)

Space questions

Please help

Space questionsPlease help

Answers

Answer:

(1) The relationship between the altitude height, 'h', and the orbital speed, \(v_{orbit}\), of the satellite is an inverse relationship

\(v_{orbit}\) = 1/(h + R)

(2) The height of the satellite, is approximately 24,442 meters

(3) Please find attached the drawing showing the two lines that indicate the direction of the gravitational force on the satellites created with Microsoft Visio

Explanation:

(1) From the given data table, as the altitude increases, the orbital velocity decreases, therefore, the relationship between altitude, 'h', and orbital velocity, '\(v_{orbit}\)', is an inverse relationship which can be expressed as follows;

\(v_{orbit} = \sqrt{\dfrac{G \cdot M}{r} }\)

Where;

G = The universal gravitational constant

M = The mass of the Earth, or planet about which the satellite orbits

r = The distance between the center of the planet and the satellite = h + R

R = The radius of the planet

When \(v_{orbit}\) = 27,500, h = r - R = 1000

We have;

\(v_{orbit}\)² ∝ 1/r

\(v_{orbit}\)² = k/r = k/(R+ h)

When, \(v_{orbit}\)² = 27,500² = 756,250,000

r = h + R = 1000 + R

∴ 756,250,000 = k/(1000 + R)

(1,000 + R) × 756,250,000  = k

When, \(v_{orbit}\)² = 18,000² = 324,000,000

r = h + R = 10,000 + R

∴ 324,000,000 = k/(10,000 + R)

324,000,000 = ((1,000 + R) × 756,250,000)/(10,000 + R)

∴ 324,000,000×(10,000 + R) = (1,000 + R) × 756,250,000

R × (756,250,000 - 324,000,000) = 324,000,000×10,000 - 1,000 × 756,250,000

R = (324,000,000×10,000 - 1,000 × 756,250,000)/(756,250,000 - 324,000,000) = 5746.09600925

R = 5,746.09600925

k = (1,000 + R) × 756,250,000  = (1,000 + 5,746.09600925) × 756,250,000 = 5.1017351 × 10¹²

k = 5.1017351 × 10¹²

(2) When, \(v_{orbit}\) = 13,000 m/s, we have;

13,000² = 5.1017351 × 10¹²/(5,746.09600925 + h)

∴ 5,746.09600925 + h = 5.1017351 × 10^(12)/(13,000²) = 30187.7816568

h = 30187.7816568 - 5,746.09600925 = 24,441.6856476

The height of the satellite, h ≈ 24,442 meters

(3) Please find attached the drawing showing the two lines indicating the direction of the force of gravity exerts on the satellites created with Microsoft Visio.

Space questionsPlease help
Space questionsPlease help

A 5.00-kg sphere is moving at a speed of 4.00 m/s. An identical sphere is at rest. The two spheres collide. The first sphere moves off at a 60.0° angle to the left of its original path. The second sphere moves off in a direction 90.0° to the right of the first sphere’s final path. Assuming no friction, what are the speeds of the two spheres as they separate?

Answers

The final speeds of the spheres are 3.47 m/s and 3.08 m/s.

We can use conservation of momentum to solve this problem since there are no external forces acting on the system.

The initial momentum of the system is:

p_initial = m₁ * v₁ + m₂ * v₂

where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).

After the collision, the momentum of the system is:

p_final = m₁ * v1' + m₂ * v₂'

where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).

Using conservation of momentum, we can set the initial and final momenta equal to each other:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'

We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)

0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)

Solving the first equation for v₂', we get:

v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))

Substituting this expression into the second equation and solving for v₁', we get:

v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))

Plugging in the given values and solving, we get:

v₁' = 3.47 m/s

v₂' = 3.08 m/s

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The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?

Answers

Answer:

Tt can be calculated by copy

A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. What is the momentum of the rocket?

Answers

A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.

According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.

A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.

We are required to determine the momentum of the rocket.

Consider the fuel-filled rocket as a system.

We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas

We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.

Therefore: Momentum of rocket = - momentum of expelled gas

The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.

Hence, the momentum of the rocket is -1500 kg m/s.

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Give a short introduction to alternative energy​

Answers

Answer:

Alternative energy is energy sources other than fossil fuels, including renewable sources and nuclear energy. However, nuclear energy is not classified as a renewable energy source, because it is mined from uranium and thorium elements, which cannot be replenished. Hoped this helped!!!

Which force is represented by the arrow at
B?


A) Force of friction

B) Force of gravity

C) Tension force

D) Normal force ​

Which force is represented by the arrow at B?A) Force of friction B) Force of gravityC) Tension force

Answers

A is pulling the block straight down toward the center of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

Answer:

A is pulling the block straight down toward the center of the Earth, no matter what the slope of the plane may be. A is the force of gravity.

The directions of B and C both depend on the slope of the plane.

B is a force that's parallel to the plane, pulling the block UP the plane. B is the force of friction.

C is a force perpendicular to the plane, preventing the block from falling down through the plane. C is the normal force.

Explanation:

1. A car moving to the right at 30 m/s, slows down 5 m/s every second until it comes to a stop.
a). At what time will the car come to a stop?
b). How far did the car travel by the time it came to a stop?

Answers

I think he is correct with the 6 m/s

learning goal: to understand the role of friction in a state of equilibrium. a chair weighing 70.0 n rests on a level floor that is not frictionless. a man pushes on the chair with a force f

Answers

The magnitude of the normal force that the floor exerts on the chair is 93.79 Ncoefficient of static friction μ is 0.32

What is coefficient of static friction?The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it."The highest ratio of applied force to normal force with no motion is called the coefficient of static friction." We all understand that a force called friction resists motion. If we carefully notice, there is a point at which the body opposes movement after force is applied to move it from rest.The things that are creating friction determine the coefficient of static friction's value. Its value typically ranges from 0 to 1, but it can also be higher than 1.

Given details :

Weight of chair W = 70 NForce P = 39 NAngle = 38°

1.Force equilibrium in x direction

∑ \(F{x}\) = 0

F - 39 cos Ф = 0

As Ф = 38°

F = 39 cos38°

F = 30.73 N

Force equilibrium in y direction

∑ \(F{y}\) = 0

N = W + P sin38°

   =  70 + 39 sin38°

N = 93.79 N

Thus the normal force on chair = 93.79 N

From the free body diagram

F = μN

30.73 = μ x 93.79

μ = 30.73 / 93.79 = 0.32

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a curve in a road forms part of a horizontal circle. as a car goes around it at constant speed 14.0 m/s, the horizontal total force on the driver has magnitude 149 n. what is the total horizontal force on the driver if the speed on the same curve is 23.9 m/s instead

Answers

The total horizontal force on the driver when the speed on the same curve is 23.9 m/s is approximately 570.5 N.

To find the total horizontal force on the driver when the speed on the same curve is 23.9 m/s instead, we can use the concept of centripetal force. The centripetal force Fc is given by the formula: \(Fc = (mv^2) / r\), where m is the mass of the driver, v is the speed of the car, and r is the radius of the curve.

First, we need to determine the mass of the driver using the given information:
149 N =\((m * (14.0 m/s)^2) / r\)

We can rearrange the equation to find the mass: m =\((149 N * r) / (14.0 m/s)^2\)
Now we want to find the centripetal force at the new speed of 23.9 m/s.

We can use the same formula: \(Fc_new = (m * (23.9 m/s)^2) / r\)


We can substitute the mass equation we found earlier into this equation:
\(Fc_new = ((149 N * r) / (14.0 m/s)^2) * (23.9 m/s)^2 / r\)
The r values cancel each other out, leaving: \(Fc_new = 149 N * (23.9 m/s)^2 / (14.0 m/s)^2\)

Now, calculate the new force:
\(Fc_new = 149 N * (23.9^2 / 14.0^2) ≈ 570.5 N\)
So, the total horizontal force on the driver when the speed on the same curve is 23.9 m/s is approximately 570.5 N.

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If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force

of the spring?

Answers

Answer:

0.25N

Explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

According to the Laws of Proportionality, if a resistor in a parallel circuit has twice the resistance of a second resistor, it will have _______________ the current of the second resistor.

Answers

In a parallel circuit, if a resistor has twice the resistance of another resistor, it will have half the current of the second resistor.

In a parallel circuit, the Laws of Proportionality state that the total current flowing into the circuit is divided among the individual branches or resistors. According to Ohm's Law, the current passing through a resistor is inversely proportional to its resistance. This means that as the resistance of a resistor increases, the current passing through it decreases.

When two resistors are connected in parallel, they share the same voltage across them. However, the current passing through each resistor can vary depending on their individual resistances. If we have two resistors in parallel and one has twice the resistance of the other, the resistor with the higher resistance will allow less current to flow through it compared to the resistor with lower resistance.

To understand why this happens, let's consider an analogy with water pipes. Imagine two pipes connected in parallel, where one pipe has a wider diameter than the other. The wider pipe will allow more water to flow through it, while the narrower pipe will restrict the flow of water. Similarly, in a parallel circuit, the resistor with higher resistance acts as a bottleneck, limiting the amount of current that can pass through it.

In summary, if a resistor in a parallel circuit has twice the resistance of a second resistor, it will have half the current of the second resistor. The current is inversely proportional to the resistance, meaning that an increase in resistance leads to a decrease in current flow.

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Help please!!!! What is the difference between the type of smog experiences by cities in the eastern United States and that found in Southern California?

Answers

Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

What is Smog?

Smog development and infiltration over Los Angeles. haze and air pollution in the entire community.

Burning sulfur-containing fossil fuels, particularly coal, causes sulfurous smog, also referred to as "London smog," which is characterized by a high concentration of sulfur oxides in the atmosphere.

The two primary substances in automotive exhaust are nitrogen oxides, which are created in scorching internal combustion engines, and hydrocarbons, which are derived from gasoline.

Therefore, Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

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It takes a sample of molecules 10 s to diffuse 1.0 mm. how long will it take to diffuse 2.0 mm ?

Answers

The time taken to diffuse 2.00 mm will be 20 seconds.

The velocity of diffusion(v) is given by the following formula:

v = Distance/Time

We are given that it takes a sample of molecules 10 seconds to diffuse 1.00 mm.

Thus, its velocity is

v = 1.0 mm/10 s = 0.1 mm/s

In the second case, the distance is given, so we can calculate the time required for diffusion by again applying the same formula

0.1 = 2.00 mm/Time

On rearranging above equation, we get

Time = 20 seconds

Thus, the time taken to diffuse 2.00 mm will be 20 seconds.

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a thin, straight, uniform rod of length 1.10 m and mass 250 kg hangs from a pivot at one end. what is its period for small-amplitude oscillations?

Answers

The period for a small amplitude oscillation on a thin, straight, uniform rod 1.10 m long and 250 kg mass hangs from a pivot at one end = 2.09 s.

Harmonic vibration

Harmonic vibration is the alternating motion of an object through an equilibrium point that has a fixed frequency and period. An example of harmonic vibration is a pendulum.

Period (T) is the time needed to do one vibration. Meanwhile, the frequency (f) is the number of vibrations that occur in one second. The period and frequency of the pendulum depend on the length of the string and the acceleration due to gravity, and are independent of the mass of the pendulum. The period and frequency of the pendulum can be expressed using the following equation:

T  = 2\(\pi\)\(\sqrt{\frac{L}{g} }\)

f = \(\frac{1}{2\pi }\)  \(\sqrt{\frac{L}{g} }\)

Where,

T = period (s)

f = frequency (Hz)

L = length (m)

g = acceleration of gravity (9.8 m/s²)

We have,

L = 1.10 m

So,

T = 2\(\pi\)\(\sqrt{\frac{L}{g} }\)

= 2\(\pi\)\(\sqrt{\frac{1.10}{9.8} }\)

= 2.09 s

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What must happen for salt and water to form a solution?
O A. The salt and the water must combine to form a new substance.
B. The salt and the water must combine chemically.
C. The water must displace the salt.
O D. The salt must dissolve in the water.

Answers

The answer would be D

w(0)>0 at what time does the body come to momentary rest in its rotation angular acceleration is bt^3

Answers

The body comes to momentary rest at time t = sqrt(2/(3b*w(0)^2)).

The angular acceleration of the body is given by bt^3, and since w(0)>0, the angular velocity is increasing. At some point, the body will reach its maximum angular velocity and then start to slow down.

The body will come to momentary rest when its angular velocity is zero. Using the formula for angular velocity, w = w(0) + integral(bt^3), and setting it equal to zero, we can solve for the time t. Simplifying the equation yields t = sqrt(2/(3bw(0)^2)). Therefore, the body comes to momentary rest at time t = sqrt(2/(3bw(0)^2)).

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After running, your friend lies down on the tile floor because he says the "coldness" of the tile transfers to his body and helps him cool down faster.
Is his statement correct? Explain your reasoning in complete sentences. Help please thank you

Answers

Energy floating hands with a constant chill. growing desire to resist the Führer Only after he had a difficult time recovering from his push-ups.

Which scenario best exemplifies convectional heat transfer?

steaming water Heat from the flame travels into the saucepan when the water boils, warming the liquid at the bottom of the pan. As the hot water rises as well as the cooled water falls to replace it, a passed through ( transmitted is produced.

How can convection efficiently move heat?

Thermal energy is transferred from heated to cool places by convection. Convection is the process by which warmer portions of a gas or liquid move toward cooler areas of the same liquid or gas. Then, cooler liquid or gas replaces the heated portions that have ascended higher.

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a piston pump has nine pistons. each piston has a diameter of 1.6 cm and a 2.6 cm stroke. at 1800 rpm it produces 69.5 l/min. what is the volumetric efficiency of the pump (as a decimal)?

Answers

At 1800 rpm, a pump with nine pistons, each with a diameter of 1.6 cm and a stroke of 2.6 cm, produces 69.5 l/min. The volumetric efficiency of the pump is calculated as 0.83.

The formula for volumetric efficiency (\(\eta_v\)) is the actual flow rate (\(Q_{actual}\)) divided by the theoretical flow rate (\(Q_{theoritical}\)).

Mathematically, the formula is given as,

\(Q_{theoritical}=N \times A_d \times L\times V\)

Where N is the number of pistons, \(A_d\)  is the piston cross-sectional area, L = the stroke length of the pistons, V = the pump speed in revolutions per minute (rpm).

The diameter (d) of the pistons is given as 1.6 cm, so the radius (r) will be:

\(d/2 = r = 0.8 cm\)

The cross-sectional area (A) of the pistons is:

\(A = \pi \times r^2 = \pi \times (0.8 cm)^2\\ =2.01 cm^2\)

We are given that the piston stroke (L) is 2.6 cm and the pump speed (V) is 1800 rpm. Number of pistons (N) = 9

The theoretical flow rate (Q_{theoretical) of the pump is given by

\(Q_{theoretical} = N \times A_d \times L \times V\\= 9 \times 2.01 cm^2 \times 2.6 cm \times 1800 rpm\\=83.9 L/min\)

We are also given that the pump produces 69.5 L/min at 1800 rpm.

So, the actual flow rate is,

\(Q_{actual} = 69.5 L/min\)

Therefore, the volumetric efficiency of the pump is calculated as:

\(\eta_v = Q_{actual} / Q_{theoretical}\\= \frac{69.5 L/min}{83.9 L/min}\\= 0.83\)

Therefore, the volumetric efficiency of the pump is approximately 0.83.

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The distance between the sun and the earth is 1.5 * 10^11. Use this information to calculate the mass of the sun.

I understand you're supposed to set the force of gravity equal to your centripetal force but why can't I use g=G(M/r^2) and solve for M, plugging in 9.81 as g, 6.67*10^-11 as G, and 1.5 * 10^11 as r?

Answers

Answer:

47288483 miles

Explanation:

It was revealed to me in a dream

How can ground-based telescopes equipped with adaptive optics yield images as detail-rich as those from old space missions?

Answers

Ground-based telescopes equipped with adaptive optics can yield detail-rich images comparable to those from old space missions by compensating for the atmospheric distortions that degrade the image quality.

The Earth's atmosphere introduces turbulence that causes images captured by ground-based telescopes to be blurry and less detailed. Adaptive optics technology addresses this issue by actively measuring and correcting for the atmospheric distortions in real-time.

It uses deformable mirrors and wavefront sensors to analyze the distortions and make precise adjustments to the telescope's optics.

By continuously adapting to the atmospheric conditions, adaptive optics can compensate for much of the blurring effect, resulting in images that approach the clarity and resolution achieved by space-based telescopes.

This enables ground-based telescopes to capture detailed images of astronomical objects and phenomena, rivaling the quality of those obtained by older space missions.

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A ball of mass m is attached to a string of length L. It is being swung in a vertical circle with enough speed so that the string remains taut throughout the ball's motion. Assume that the ball travels freely in this vertical circle with negligible loss of total mechanical energy. At the top and bottom of the vertical circle, the ball's speeds are v_t and v_b, and the corresponding tensions in the string are T_t and T_b. T_t and T_b (vectors) have magnitudes T_t and T_b.
Find T_b - T_t, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle.
Express the difference in tension in terms of m and g. The quantities v_t and v_b should not appear in your final answer.

Answers

The difference in tension in terms of m and g is given by T_b - T_t = 2mg

To find the difference in tension T_b - T_t, we will first analyze the forces acting on the ball at the top and bottom of the circle and then compare the magnitudes.
1. At the top of the circle:
- The tension force T_t is acting downward.
- The gravitational force mg is also acting downward.
The net force at the top is the sum of these forces:
F_t = T_t + mg
2. At the bottom of the circle:
- The tension force T_b is acting upward.
- The gravitational force mg is acting downward.
The net force at the bottom is the difference of these forces:
F_b = T_b - mg
Since the total mechanical energy is conserved, we can equate the centripetal forces acting on the ball at the top and bottom of the circle:
\(m(v_t^2) / L = m(v_b^2) / L\)
As we can see, the mass m and length L cancel out:
\(v_t^2 = v_b^2\)
Now we can relate the forces to the centripetal acceleration:
At the top: \(F_t = m(v_t^2) / L\)
At the bottom: \(F_b = m(v_b^2) / L\)Substituting the expressions for F_t and F_b, we get:
\(T_t + mg = m(v_t^2) / L\)
\(T_b - mg = m(v_b^2) / L\)
Since \(v_t^2 = v_b^2\), we can set the centripetal forces equal to each other:
m(v_t^2) / L = m(v_b^2) / L
Now subtract the equation for the forces at the top from the equation for the forces at the bottom:
(T_b - mg) - (T_t + mg) = 0
Simplifying the equation, we get:
T_b - T_t = 2mg
So, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle is 2mg.

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An object originally at rest, is accelerated uniformly along a straight line to a speed of 8m/s in 2s. What is the acceleration of the object?​

Answers

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)

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Which of these forms of radiation passes most easily through the disk of the milky way?.

Answers

The milky way disk is the structure through which infrared radiation travels most readily.

What do infrared rays serve for?

There are several applications for infrared radiation, including thermal imaging, remote controls, fiber optic cabling, infrared astronomy, even meteorology. The greenhouse effect is caused in part by the fact because water vapor or other greenhouse gases absorb infrared light.

What types of things emit infrared radiation?

Definition of infrared radiation It is a type of radiant energy that we perceive as heat but which is invisible to the human eye (sometimes referred to as infrared light). Two of the most notable examples of infrared radiation are the sun and fire.

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a 500 n force is applied to a 25 m/s2 object . The mass of the object is ____

Answers

Answer:

20kg

Explanation:

ΣF = ma

500N = 25m

m = 20kg

When a wave moves from one medium to another, which properties of the wave change? choose all that apply.

Answers

In most cases, when wave refract, frequency and amplitude will be constant while wavelength and speed will change.

PROPERTIES OF WAVES

The four properties of waves are:

FrequencyAmplitudeWavelengthSpeed

When a wave moves from one medium to another, the wave will undergo refraction.

When a wave move for instance, from water to glass, the wave will refract by changing direction. In most scenario, the frequency of the wave will be constant while the wavelength of the wave will change. Since the wavelength will change, the speed will also change.

Therefore, when a wave moves from one medium to another, the properties of the wave that change are wavelength and wave speed.

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If a student is sitting in their chair and the leg of the chair breaks the student will __________ toward the floor because the gravity is a greater force.
A.Accelerate
B.Force
C.Balance
D.Speed

Answers

Answer:

theyll accelerate towards the floor :)

C because it gonna balance

a large stone of 20kg and small stone of 5kg are dropped simultaneously from certain height. Which one reaches on the ground first? why? Pls tell me the answer and describe it please​

Answers

The 20kg would reach the ground first because it is the heavier object which means gravity will be pulling on the object harder then the 5kg
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