for the equation t=sin^-1(a), state which letter represents the angle and which letter represents the value fo the trigonometric function.

Both investments have the same effective annual yield

To calculate the effective annual yield for different compounding periods, we can use the formula:

Effective Annual Yield = (1 + (interest rate / number of compounding periods))^number of compounding periods - 1

Using this formula, let's calculate the effective annual yields for each scenario:

Semiannually compounded:

Effective Annual Yield = (1 + (0.06 / 2))^2 - 1 ≈ 0.0609 or 6.1%

Quarterly compounded:

Effective Annual Yield = (1 + (0.06 / 4))^4 - 1 ≈ 0.0614 or 6.1%

Monthly compounded:

Effective Annual Yield = (1 + (0.06 / 12))^12 - 1 ≈ 0.0617 or 6.2%

Daily compounded:

Effective Annual Yield = (1 + (0.06 / 360))^360 - 1 ≈ 0.0618 or 6.2%

Compounded 1000 times per year:

Effective Annual Yield = (1 + (0.06 / 1000))^1000 - 1 ≈ 0.0618 or 6.2%

Compounded 100,000 times per year:

Effective Annual Yield = (1 + (0.06 / 100000))^100000 - 1 ≈ 0.0618 or 6.2%

For exercises 29-32, let's calculate the effective annual yields for each investment:

Investment 1: 8% compounded monthly

Investment 2: 8.25% compounded annually

Effective Annual Yield for Investment 1 = (1 + (0.08 / 12))^12 - 1 ≈ 0.0833 or 8.3%

Effective Annual Yield for Investment 2 = (1 + 0.0825)^1 - 1 = 0.0825 or 8.3%

Both investments have the same effective annual yield of 8.3%.

Investment 1: 5% compounded monthly

Investment 2: 5.25% compounded quarterly

Effective Annual Yield for Investment 1 = (1 + (0.05 / 12))^12 - 1 ≈ 0.0512 or 5.1%

Effective Annual Yield for Investment 2 = (1 + (0.0525 / 4))^4 - 1 ≈ 0.0524 or 5.2%

Investment 2 has a higher effective annual yield of 5.2%.

Investment 1: 5.5% compounded semiannually

Investment 2: 5.4% compounded daily

Effective Annual Yield for Investment 1 = (1 + (0.055 / 2))^2 - 1 ≈ 0.0552 or 5.5%

Effective Annual Yield for Investment 2 = (1 + (0.054 / 360))^360 - 1 ≈ 0.0547 or 5.5%

Both investments have the same effective annual yield of 5.5%.

Investment 1: 7% compounded annually

Investment 2: 6.85% compounded daily

Effective Annual Yield for Investment 1 = (1 + 0.07)^1 - 1 = 0.07 or 7.0%

Effective Annual Yield for Investment 2 = (1 + (0.0685 / 360))^360 - 1 ≈ 0.0696 or 7.0%

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A firm should record an impairment in the value of property, plant, or equipment by reducing the carrying amount of the asset and recognizing the impairment loss as an expense in the financial statements.

When the value of property, plant, or equipment is impaired, meaning its recoverable amount is lower than its carrying amount, a firm should recognize this impairment in its financial statements. The impairment is recorded by reducing the carrying amount of the asset to its recoverable amount, which is the higher of its fair value less costs to sell or its value in use. The difference between the carrying amount and the recoverable amount is recognized as an impairment loss and recorded as an expense in the income statement. This adjustment reflects the decrease in the value of the asset and allows the firm to accurately report its financial position and performance.

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Answer:

$11.50

Step-by-step explanation:

Hope this helps!!

Step-by-step explanation:

dk if this makes sense

a. Triangles ABC and DEF are not necessarily congruent.

b. ΔGHI ≅ ΔJKL by the SAS.

c. ΔMNO ≅ ΔPQR by the ASA.

Two triangles are congruent by the ASA congruence theorem if two angles and one included side of one triangle are congruent to two corresponding angles and an included side of the other triangle.

On the other hand, two triangles are congruent by the SAS congruence theorem if two sides and one included angle of one triangle are congruent to two corresponding sides and an included angle of the other triangle.

a. Triangles ABC and DEF only have an indicated pair of congruent angles and a pair of congruent sides which are not enough to prove the triangles congruent.

Therefore, they are not necessarily congruent.

b. The triangles are congruent.

ΔGHI ≅ ΔJKL by the SAS.

c. The triangles are congruent.

ΔMNO ≅ ΔPQR by the ASA.

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On a standardized exam, the scores are normally distributed with a mean of 140 and a standard deviation of 20. The z-score of a person who scored 140 on the exam is 0

The z-score of a person who scored 140 on an exam can be calculated using the formula z = (x - μ) / σ

where x is the exam score, μ is the mean of the exam scores, and σ is the standard deviation of the exam scores.

In this case, x = 140, μ = 140, and σ = 20.

Plugging these values into the formula, we get z = (140 - 140) / 20 = 0

Therefore, the z-score of a person who scored 140 on the exam is 0.

The z-score represents the number of standard deviations away from the mean that a particular value falls. A z-score of 0 indicates that the value is equal to the mean, which is 140 in this case. If a z-score is positive, it means that the value is above the mean, and if it is negative, it means that the value is below the mean. For example, a z-score of 1 indicates that the value is one standard deviation above the mean, and a z-score of -1 indicates that the value is one standard deviation below the mean.

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The volume of the solid generated when r is rotated about the line y=4 is 512/15π

In math the term called volume in math is defined as a mathematical quantity that shows the amount of three-dimensional space occupied by an object or a closed surface.

Here we know that let r be the region bounded by the parabola y=x² and the line y=4.

Then the volume of the solid generated when r is rotated about the line y=4 is calculated by using the formula,

=> V = π ∫ᵇₐ [(h - f(x))]² dx

Here we have to apply the values on it, then we get,

=> V = π ∫₋₂² [(4 - x²)]² dx

By Using symmetry this can be written as,

=> V = 2π ∫₋₂² [16 - 8x² + x⁴] dx

When Solving the integral, then we get,

=> V = 2π (16x - 8/3x³ + 1/5x⁵)²₀

Here by Applying the fundamental theorem of calculus, then we get,

=> V = 2π (16(2) - 8/3(2)³ + 1/5(2)⁵) - 2π (16(0) - 8/3(0)³ + 1/5(0)⁵)

When we simplify this then we get

=> V = 512/15 π

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The perimeters of the two composite figures are listed below:

Case C: 50.913π mm

Case D: 20.310 cm

In this problem we find two composite figures, whose perimeter have to be found. Perimeter is the length of all borders of the figure. The first figure is formed two semicircles and the second figure is formed by two semicircles and two right triangles, whose perimeter formulas are:

Semicircle

s = π · r

Triangle

s = b + h + p

Where:

Case c - The perimeter of the shape is:

s = π · (28 mm) + π · (14 mm) + 28 mm

s = 50.913π mm

Case d - The perimeter of the shape is:

s = 2π · (1.8 cm) + 2 · (4.5 cm)

s = 20.310 cm

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Answer:

Each child will have 3/16 pound of Halloween candy.

Step-by-step explanation:

To find out how much candy each sibling gets, we need to divide 3/4 by 4

3/4 divided by 1/4 = 3/16

Therefore, our answer is 3/16.

Answer: 83r^2 - 59 + 60

Step-by-step explanation:

R^2 - 59R - 82r^2 + 60

= 83r^2 - 59 + 60

Bending moment curve equation below point A will be:

M = 15x - 3x² for 0 ≤ x ≤ b

Determination of shear and bending moment curves.

For the beam and loading shown, we can do the following:

Equation of shear curve (above point A):V = RA - w.x

For x = a,V = RA - w.a

For x = b,V = RA - w.b

Since the loading is symmetric, RA = w(a + b) / 2= (6 * 5) / 2= 15kNV = 15 - 6a for a ≤ x ≤ b

Equation of shear curve (below point A):

V = RA - w.x

For x = 0,V = RA - w.0RA = w(a + b) / 2= (6 * 5) / 2= 15kNV = 15k for 0 ≤ x ≤ a

The shear curve equation becomes;

V = 15k for 0 ≤ x ≤ a

V = 15 - 6a for a ≤ x ≤ b

Equation of bending moment curve (above point A):

M = RAx - ½w.x²For 0 ≤ x ≤ a,

M = 15x - ½(6x²) = 15x - 3x²For a ≤ x ≤ b,

M = 15x - 6a(x - a) - ½(6x²)= 15x - 6ax + 6a² - 3x²

The bending moment curve equation above point A becomes:

M = 15x - 3x² for 0 ≤ x ≤ a

M = 15x - 6ax + 6a² - 3x² for a ≤ x ≤ b

Equation of bending moment curve (below point A):

M = RAx - ½w.x²For 0 ≤ x ≤ b,

M = 15x - ½(6x²) = 15x - 3x²

The bending moment curve equation below point A becomes;

M = 15x - 3x² for 0 ≤ x ≤ b

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The rate at which the radius is changing when the radius is 3 centimeters and the height is 7 centimeters is -0.114 cm/sec.

The rate at which the height is changing, dh/dt = 0.6 cm/sec; radius, r = 3 cm; height, h = 7 cm. To find the rate at which the radius is changing when the radius is 3 centimeters and the height is 7 centimeters, we need to find the value of dr/dt.

From the given data, the volume of the cylinder, V = πr²h

Differentiating the above equation w.r.t t, we get:

dV/dt = π(2r dr/dt h + r² dh/dt)

But we are asked to find the rate at which the radius is changing when the radius is 3 cm and the height is 7 cm, so substituting the values in the above equation, we get:

dV/dt = π(2 × 3 × dr/dt × 7 + 3² × 0.6)

At r = 3 cm and h = 7 cm,

dV/dt = π(2 × 3 × dr/dt × 7 + 3² × 0.6)

dV/dt = π(42 dr/dt + 5.4)

When r = 3 cm and h = 7 cm, dh/dt = 0.6 cm/sec

∴ dV/dt = π(42 dr/dt + 5.4)= 0.6 cm³/sec

Solving for dr/dt, we get:

π(42 dr/dt + 5.4) = 0.6

π × (42 dr/dt) = (0.6 - 5.4)

dr/dt = -4.8/42

dr/dt = -0.114 cm/sec

Thus, the rate at which the radius is changing is -0.114 cm/sec (negative sign indicates that the radius is decreasing).

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Answer:Jeff read 11 books I believe

Step-by-step explanation:hope this helps

Answer:

83.333% or 0.83333

Explanation:

Base on the given conditions, formulate:

\(\dfrac{1}{2} \div\dfrac{3}{5}\)

Write as a single fraction:

\(\dfrac{\dfrac{1}{2\times3} }{5}\)

Calculate the product or quotient:

\(\dfrac{\dfrac{1}{6} }{5}\)

Divide a fraction by multiplying its reciprocal:

\(\dfrac{5}{6}\)

get the result: 83.333% or 0.83333

Answer: 83.333% or 0.83333

The formula for calculating the effective annual rate of interest with quarterly compounding is:

(1 + r/4)^4 - 1 = A/P

where r is the quarterly interest rate, A is the final amount, and P is the principal.

In this case, P = $2,000, A = $3,000, and the time period is 7 years or 28 quarters.

So we have:

(1 + r/4)^4 - 1 = 3000/2000

(1 + r/4)^4 = 1.5

1 + r/4 = (1.5)^(1/4)

r/4 = (1.5)^(1/4) - 1

r = 4[(1.5)^(1/4) - 1]

To get the effective annual rate, we need to convert the quarterly rate to an annual rate by multiplying by 4:

effective annual rate = 4[(1.5)^(1/4) - 1] ≈ 8.84%

Therefore, the effective annual rate of interest at which $2,000 will grow to $3,000 in seven years if compounded quarterly is approximately 8.84%, rounded to 2 decimal places.

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The statement is false because adding a vector to a set of vectors can increase its span, but the new span is not necessarily the same as the original span.

The statement is false. To prove this, consider three vectors u1, u2 and u3 that span R3, and a vector u4 that is not a linear combination of

u1, u2 and u3.

The span of

{u1, u2, u3, u4}

will be a subset of the span of

{u1, u2, u3}.

This means that the span of

{u1, u2, u3, u4}

will contain all the vectors that the span of {u1, u2, u3} contains, plus the vector u4. However, it does not necessarily mean that the span of

{u1, u2, u3, u4} will be the same as the span of {u1, u2, u3},

as there may be other vectors that are in the span of

{u1, u2, u3, u4}

but not in the span of {u1, u2, u3}. Hence, the statement is false.

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The complete question is

Determine if the statement is true or false, and justify your answer. If (u1, u2, u3) spans R3, then so does (u1, u2, uz, u). O False. Consider u4 =0 True, the span of a set of vectors can only increase (with respect to set containment) when adding a vector to the set. O True, since the span of {ul, u2, u3, u4} is a subset of the span of {u1, u2, us), O False. Consider u4 = 0. The span of {u1, u2, u3, u4} is a subset of the span of {u1, u2, us}, but the span of {u1, u2, u3, u4} is not the same as the span of {u1, u2, us}.

Answer:

this was from plato

Step-by-step explanation:

Answer:

Any point on the circle must be at a distance from the center equal to the length of the circle’s radius. In this example, the radius is 3.61 units, AC = 4.24, and AD = 3.61. Point D, which lies on the circle, has the same distance from the center as the length of the radius. Point C, which lies outside the circle, is at a different distance from the center than the length of the radius.

Answer:

Please find attached pdf

Step-by-step explanation:

Answer:

D) 2(4a+7)

Step-by-step explanation:

when one divides both the number by 2 you get 4a+7 so the answer is 2(4a+7)

Answer:opdwjopgf2j[

'jgkwr'ogwe'fk'rwokg{:VKSW?fvrewdgrwji{"ODRI

Step-by-step explanation:

The reaction of the graduate student on inflation is that a cost-of-living increase to her stipend.      

Inflation is the pace of expansion in costs over a given time-frame. Inflation is regularly a wide measure, like the general expansion in costs or the expansion in the typical cost for many everyday items in a country.

Inflation is term which states there is an expansion in the cost level for any labor and products.

In the unique situation, a set of experiences graduate living in the US got a payment of 18,000 dollar. However, there is a critical expansion that US economy endures. In this way the expense of products and the administrations accessible to individuals increments quickly. Individuals presently need to spend more on everything. Accordingly the alumni understudy requirements to request the typical cost for most everyday items to be remembered for the payment as need might arise to spend more on living.

Thus, graduate student argue on the a cost-of-living increase to her stipend.      

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The area of the parallelogram is \(\sqrt{132}\).

A parallelogram is a quadrilateral with two pairs of parallel sides. The opposite sides of a parallelogram are equal in length, and the opposite angles are equal in measure. Also, the interior angles on the same side of the transversal are supplementary. Sum of all the interior angles equals 360 degrees.

Given that,

vertices k(1, 1, 3), l(1, 3, 5), m(6, 9, 5), and n(6, 7, 3)

Area of Parallelogram = |KL × KN|

KL = (1, 1, 3) - (1, 3, 5) = (0, 2, 2)

KN = (1, 2, 3) - (3, 7, 3) = (2, 5, 0)

Area of the parallelogram = cross product of two vectors, represented by the adjacent sides.

Area of Parallelogram = |(0, 2, 2) × (2, 5, 0)|

                                    = |i(2 × 0 - 5 × 2) - j(0 × 0 - 2 × 2) + k(0 × 5 - 2 × 2)|

                                    = |i(-10) - j(-4) + k(-4)|

                                    = |-10i + 4j - 4k|

                                    = \(\sqrt{(-10)^{2}+(4)^{2}+(-4)^{2} }\)

                                    = \(\sqrt{100+16+16}\)

                                    = \(\sqrt{132}\)

Hence, The area of the parallelogram is \(\sqrt{132}\).

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As similarity theorem, the value of x that will make the triangles similar by SSS similarity theorem is 77.

Similarity theorem:

In math, similarity theorem refers the line segment splits two sides of a triangle into proportional segments if and only if the segment is parallel to the triangle's third side.

Given,

Here we need to find the t value of will make the triangles similar by the similarity theorem.

For example, we are told that the 2 triangles are similar by SSS theorem.

Here we know that, SSS means Side - Side -Side and it is a congruence theorem which states that the 3 corresponding sides of two triangles have same ratio, then we can say that the two triangles are congruent by SSS theorem

Therefore, in the triangles ,applying the SSS postulate gives;

=> x/35 = 44/20

Then by applying the multiplication property of equality, let us multiply both sides by 35 to get;

=> x = (44 * 35)/20

When we simplify this one then we get,

=> x = 77

Therefore, the value of x is 77.

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Answer:

Hi there, your answers here are 44% and 33%.

To convert 4/9 to a percent, first we can write it as a decimal - 0.44444444444. To get this decimal, we divide 4 by 9. Then, we multiply this decimal by 100 to get 44.4444444444, or roughly 44%.

To convert 7/21 to a percent, first we can write it as a decimal - 0.33333333333. To get this decimal, we divide 7 by 21. Then, we multiply this decimal by 100 to get 33.3333333333, or roughly 33%.