for the compound ba(oh)2 what are the formulas of all the species you expect to be present in aqueous solution?

Answer:

1) Element

2) Compound

3) Element

4) Mixture

5) Compound

6) Element

7) Compound

8) Mixture

9) Mixture

10) Mixture

11) Compound

12) Mixture

Explanation:

A compound refers to a combination of two or more atoms of the same or different elements Eg NH3.

A mixture refers to any combination of substances which do not chemically reavt together and are separable by physical methods.

An element refers to a substance that contains only one type of atom.

Answer: D) Sufficient kinetic energy

Explanation:

Answer:

b

Explanation:

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2.50 litres of a 10.0 M solution require the preparation of 25.0 moles of ethylene glycol.

Excellent antifreeze, anti-boil, and anti-corrosive qualities are produced when antifreeze and water are mixed in a 50/50 ratio. The proportion of conventional ethylene glycol to water in severely cold conditions can reach 70% antifreeze, 30% water. The maximum antifreeze to water ratio when using DEX-COOL® is 60/40.

moles = concentration (M) x volume (L)

Given that the desired concentration is 10.0 M and the volume needed is 2.50 L, the setup for calculating the total number of moles of ethylene glycol can be written as:

moles = 10.0 M x 2.50 L

moles = 25.0 mol

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The answer is 67 108.0888km/s.

To determine the pKb1 of CO32-, we can use the relationship between pKa and pKb for conjugate acid-base pairs:

pKa + pKb = pKw

where pKw is the ionization constant of water, which is approximately 14. Therefore, we can rearrange the equation to solve for pKb:

The pKb value represents the negative logarithm of the equilibrium constant (Kb) for the reaction of a base with water. In this case, we are interested in the equilibrium reaction between CO32- and water, which can be represented as CO32- + H2O ⇌ HCO3- + OH-.

By utilizing the relationship pKa + pKb = pKw, we can rearrange the equation to solve for pKb. Given that pKa1 of H2CO3 is 6.35, we subtract this value from pKw (approximately 14) to obtain pKb1

pKb = pKw - pKa

pKb1 = 14 - 6.35 = 7.65

Since none of the given answer choices matches the calculated value, it seems there might be an error or omission in the available options. Please double-check the answer choices provided or refer to additional information to obtain the correct pKb1 value for CO32-.

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Answer:

# of neutrons

Explanation:

its how isotope is defined

Answer:

Explanation:

1. The characteristics of an acid are that it has a sour taste, reacts with metals, and turns blue litmus paper into red.

2. When you add TOO MUCH solute to a solution, the solution becomes saturated at some point. It will not dissolve anymore and will remain solid instead.

3. A mixture contains an acid and a base.

4. You test a liquid, and its pH is 7. This liquid is Neutral.

5. Lemon juice, apple juice, and Vinegar all have pH measurements below seven (7), making them acidic.

6. Ammonia, blood, and drain cleaner all have pH measurements above seven (7), making them basic.

7. Erosion is another word for eating away at material.

8. Vinegar can be an acid or base because it is a good conductor of electricity.

9. Cation is a positive ion and Anion is a negative ion.

10. Two or more substances mixed but not chemically combines are a Mixture.

Answer:c

Explanation:

As the combined mass of the HCl and NaOH is 15 grams before the reaction. Therefore the mass after the reaction will be 15 grams according to the law of conservation of mass. Therefore, option (C) is correct.

Matter can be transformed form via physical changes and chemical changes from one form to another form, during any of these changes, the total mass is conserved. The same quantity of matter exists before and after the chemical or physical as none of the matter is created or destroyed.

The balanced equation between the reaction of HCl and NaOH:

\(HCl +NaOH \longrightarrow H_2O +NaCl\)

According to the law of conservation of mass, the mass of HCl and NaOH will be equal to the mass of the products water and NaCl.

As mentioned in the question the combined mass of HCl and NaOH measured before the reaction is 15 grams. Therefore, the mass of the products in the closed container will be equal to 15 grams as well.

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Your question was incomplete,  most probably the complete question was,

Fernando places 15 ml of HCl and 50 ml of NaOH in 100 ml of a beaker. He places them on a scale together and measures the combined mass of 15 grams.

After the HCl and NaOH react, Fernando measures the mass again. Using the mass before the reaction, what is the mass after the reaction? Remember, It is in a closed system.

A. 5.00 grams

B. 10.00 grams

C. 15.00 grams

D. 20.00 grams

The correct answer is D. Higher sample capacity is not an advantage of open tubular (column) GC over packed (column) GC.

Open tubular (column) GC has several advantages over packed (column) GC, including higher resolution, shorter analysis time, and increased sensitivity. These advantages stem from the fact that open tubular columns have a smaller internal diameter, resulting in a larger surface area for interaction between the analyte and the stationary phase, and faster separation times.

However, higher sample capacity is not an advantage of open tubular (column) GC over packed (column) GC. Packed columns can handle larger sample sizes, making them more suitable for certain applications where a higher sample throughput is required. Therefore, the correct answer is D, "higher sample capacity is not an advantage of open tubular GC over packed column GC."

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Answer:

it would be ionic

copper forms a cation and oxygen forms an anion

those charges represent the e-s that are transferred during bonding

oxygen is -2 so will accept 2 e-s to achieve noble gas configuration

Explanation:

The moral mass of NaOH required is 40 g/mol. Thus, the mass of NaOH which will be required to prepare 500 mL of 0.1M solution is 2.0 g.

For the given information of NaOH

Use the dilution equation M1V1 = M2V2

0.1M x 500 ml = 6.0M x V2

Solve for V2 = 8.33ml

Take 8.33 ml of the concentrated 6.0M NaOH in a volumetric pipet and put into a 500mL volumetric flask. Add distilled water to the 500mL mark of the flask. Mix well.

You needed to use the molarity formula: moles of solute/Liters of solution to find how many moles of solute you needed.

You correctly converted 500 mL to 0.5 L.

Now, we can put the information we already have into the formula

We want a solution with 0.1 M

So, we will do 0.1=x/0.5; 0.1*0.5

Solving for x, we find that we need 0.05 moles of solute NaOH.

The molar mass of NaOH is 40 g/mol. Thus, the mass of NaOH which will be required to prepare 500 mL of 0.1M solution is 2.0 g.

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Answer: 25.8 g of \(Cl_2\) will be produced from the decomposition of 73.4 g of \(AuCl_3\)

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles\)

The balanced chemical reaction is:

\(2AuCl_3\rightarrow 2Au+3Cl_2\)  

According to stoichiometry :

2 moles of \(AuCl_3\) produce =  3 moles of \(Cl_2\)

Thus 0.242 moles of  will produce= \(\frac{3}{2}\times 0.242=0.363mol\) of \(Cl_2\)

Mass of \(Cl_2\)= \(moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g\)

Thus 25.8 g of \(Cl_2\) will be produced from the decomposition of 73.4 g of \(AuCl_3\)

A substance that is capable of acting as both an acid and a base is E. Amphoteric.

An amphoteric substance is one that can exhibit both acidic and basic properties depending on the conditions it is in. It can donate a proton (act as an acid) in the presence of a base and accept a proton (act as a base) in the presence of an acid. This dual behavior is due to the presence of functional groups or chemical properties that allow the substance to interact with both acidic and basic species.

Examples of amphoteric substances include water (H\(_{2}\)O) and amino acids. These substances play important roles in various chemical reactions and biological processes due to their ability to act as both acids and bases.

Option E is answer.

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Phenolphthalein turns pink in basic conditions when the central carbon atom is deprotonated. The thyacyanine dyes have absorption peaks at 423 nm, 557 nm, 650 nm, and 758 nm.



 The structure responsible for the pink coloration of phenolphthalein is the one with an additional protonated hydroxyl group (-OH+) attached to the central carbon atom, resulting in a positive charge on the oxygen atom. This structure can be represented as O=C(OC1=CC=CC=C1C2=CC=C(O+)C=C2)C3=CC=CC=C3. The molecule appears pink in a basic or alkaline solution (pH greater than 8.2). In this pH range, the hydroxide ions (OH-) in the solution deprotonate the central carbon atom, generating the pink-colored ion. In acidic solutions (pH less than 8.2), the molecule is colorless as the central carbon atom remains protonated.

Assigning the spectral characteristics to each molecule:

The molecule with a maximum absorption wavelength of 423 nm has an extinction coefficient of 8.5x10^3 (L.mol.cm^-1).

The molecule with a maximum absorption wavelength of 557 nm has an extinction coefficient of 1.5x10^1 (L.mol.cm^-1).

The molecule with a maximum absorption wavelength of 650 nm has an extinction coefficient of 2.3x10^2 (L.mol.cm^-1).

The molecule with a maximum absorption wavelength of 758 nm has an extinction coefficient of 2.5x10^2 (L.mol.cm^-1).

By matching the spectral characteristics with the respective molecule numbers, we can conclude that molecule 1 has the absorption at 423 nm, molecule 2 has the absorption at 557 nm, molecule 3 has the absorption at 650 nm, and molecule 4 has the absorption at 758 nm.

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Key concepts

Physics

Chemistry

Density

Liquids

Introduction

You probably know that when solid objects are placed in liquid, they can sink or float. But did you know that liquids can also sink or float? In fact, it is possible to stack different layers of liquids on top of one another. The key is that all the different layers must have different densities. You can stack them by picking several liquids with a range of densities or by varying the density of one liquid by adding chemicals such as sugar or salt to it. If you choose colored liquids or add food coloring to each layer, you can even create a whole rainbow of colors in one single glass! Want to see for yourself? In this science activity you will stack several liquids—one by one—and create a colorful density column!

Background

Whether an object sinks or floats depends on its density compared with the density of the liquid into which it is dropped. All types of matter—solids as well as liquids—are made up of many different atoms. Depending on the mass of these atoms, their size and the way they are arranged, different substances will have different densities. The density is characteristic for each individual compound and defined as the mass of a compound divided by its volume. In other words, the more matter there is in a certain amount of volume, the denser a substance is. One cubic centimeter of rock, for example, is much heavier than a cubic centimeter of wood. This is because there is much more matter in the same volume of rock compared with the wood.

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Liquids can also have different densities. Freshwater, for example, has a density of about one gram per cubic centimeter at room temperature. Any compound—liquid or solid—that has a higher density than water will sink whereas substances with a lower density than that will float. You can test that for yourself by gathering several liquids that you have in your kitchen such as vegetable oil, corn syrup, dishwashing soap, water, rubbing alcohol and more. Which one of these do you think will sink or float in water? Find out in this activity!

Materials

Glass or cup

Water

Food coloring

Scissors

Rubber band (wide)

Small piece of wax

Popsicle stick

At least two small, clear jars or transparent mini cups (two ounces) with lids

Permanent marker

Masking tape

Three tablespoons

Dark corn syrup

Vegetable oil

Penny

Paper towels

Rubbing alcohol, dishwashing soap and other liquids (optional)

Sugar (optional)

Preparation

Gather all your materials at a workspace that can tolerate spills of all the liquids.

Fill a cup with tap water and add a couple of drops of food coloring to the water.

Ask an adult to help you cut and prepare small pieces (about 0.5 by 0.5 centimeter) of the rubber band, the popsicle stick and the wax.

Place the two empty jars in front of you (without the lids) and label them “1” and “2” with a piece of tape and the permanent marker.

Procedure

Take a clean tablespoon and pour two tablespoons of corn syrup in jar 1.

With the second tablespoon, carefully pour two tablespoons of colored water into jar 1 on top of the corn syrup. What happens to the water on top of the corn syrup? Does it mix or stay separate?

Use the third clean tablespoon to pour two tablespoons of vegetable oil in jar “1” on top of the colored water. Do you see mixing of the liquids? What happens to the oil? Does it float on top or sink to the bottom?

Now take empty jar 2 and add the same liquids—but in reverse order. Start by pouring in two tablespoons of vegetable oil.

Answer:a mouse

Explanation:

Answer: a mouse

Explanation:

Therefore, the mixture fraction is 0.

A diffusion flame occurs when two gases are mixed under specific conditions.

The term "mixture fraction" is used to describe the ratio of the amount of fuel to the total mass of fuel and oxidizer in a diffusion flame.

Let's calculate the mixture fraction by using the given information:

XCH4 = 0.095XN2

= 0.7XCP2

= 0.145XH2O

= 0.06

The sum of all mixture fraction should equal 1.

Hence, the fraction of oxygen is:

XF = 1 - (XCH4 + XN2 + XCP2 + XH2O)

XF = 1 - (0.095 + 0.7 + 0.145 + 0.06)

XF = 1 - 1XF

= 0

Now, let's calculate the mixture fraction:

f = XCH4/XF

f = 0.095/0

f = 0

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Answer:

The answer is "2.5 mole"

Explanation:

The reaction for producing \(NH_3\) can be defined as follows:

Reaction:

\(N_2+ 3H_2 \rightarrow 2NH_3\)

According to the above reaction, to produce 2 moles of \(NH_3\)  we need 1 mole of nitrogen:

So, according to the question to produce 5.0 mole \(NH_3\) the required \(N_2\):

\(\Rightarrow \ 5.0 \ mole \ of \ NH_3 \times \frac{1 \ mole\ of \ N_2}{2 \ mole \ of NH_3}\\\\\Rightarrow 5.0 \times \frac{1}{2}\\\\\Rightarrow 2.5\ mole\\\)

To produce 5.0 mole \(NH_3\)  we need 2.5 mole \(N_2\)

To dissolve 257.01 g of Ba(OH)2 in a 0.5 L solution, you would need a volumetric flask with a capacity of at least 0.5 L. Typically, a 500 mL volumetric flask would be suitable for preparing a 0.5 L solution.

To make a 0.5 L (500 mL) solution of 3M Ba(OH)2, you would need to select a volumetric flask with a capacity of at least 0.5 L to accommodate the solution.

Since the molarity (M) of the solution is given, which represents moles of solute per liter of solution, you need to determine the number of moles of Ba(OH)2 required.

Moles = Molarity x Volume (in liters)

For a 0.5 L solution of 3M Ba(OH)2, the number of moles can be calculated as:

Moles = 3 mol/L x 0.5 L = 1.5 moles

Ba(OH)2 has a molar mass of approximately 171.34 g/mol.

Mass = Moles x Molar mass

Mass = 1.5 moles x 171.34 g/mol = 257.01 g

To dissolve 257.01 g of Ba(OH)2 in a 0.5 L solution, you would need a volumetric flask with a capacity of at least 0.5 L. Typically, a 500 mL volumetric flask would be suitable for preparing a 0.5 L solution.

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Answer:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)X

Explanation:

¡Hola!

En este caso, de acuerdo con el concepto de sal, la cual está generalmente dada por la presencia de al menos un metal y un no metal, es posible encontrar cuatro tipos de estas; hidrácidas, oxácidas, básicas y ácidas, en las que las primeras dos son neutras pero la segunda tiene presencia de oxígeno, la tercera tiene iones hidróxido adicionales y la cuarta iones hidrógeno de más.

Debido a la anterior, es posible relacionar cada pareja de la siguiente manera:

1. Hidracidas a. MX

2 Acidas c. MHXO

3. Oxacidas  b. MXO

4. Basicas d. M(OH)XO

En las que M se refiere a un metal, X a un no metal, H a hidrógeno y O a oxígeno.

¡Saludos!

Answer:

D. by repeating trials during an experiment

Explanation:

chile its actually d

Explanation:

Based on the calculations performed in this experiment, the same mass of a solute with a significantly higher molar mass would have a larger effect on the boiling point elevation. As a result, the same mass of a solute with a higher molar mass will have a greater effect on the boiling point elevation.

Boiling point elevation is a thermodynamic phenomenon that occurs when the boiling point of a solvent (a substance that dissolves a solute to create a solution) is increased by adding another substance, the solute, to it. When a solute is added to a solvent, it lowers the freezing point and raises the boiling point of the solvent, which is known as the boiling point elevation.The formula for boiling point elevation is: ∆Tb = Kbm

Here, ∆Tb is the boiling point elevation, Kb is the molal boiling point elevation constant, and m is the molality of the solution. To understand this, let us take an example: Suppose a solution containing 1.0 mol of sodium chloride (NaCl) is dissolved in 1.0 kg of water. The molality of the solution is 1.0 mol / 1.0 kg = 1.0 m. In addition, the Kb for water is 0.51 °C/molal, which means that the boiling point elevation is 0.51 °C when the molality of the solution is 1.0 mol/kg.So, the boiling point of the solution will be raised by 0.51 °C, which can be calculated using the above formula.Calculation performed in this experiment:Boiling point elevation = ΔTb = Kb . mTherefore, based on the above formula, the boiling point elevation is directly proportional to the molality of the solution, which, in turn, is directly proportional to the number of moles of solute in the solution. Furthermore, the number of moles of solute is proportional to the mass of the solute (in grams) divided by its molar mass (in grams/mol).So, if a solute with a significantly higher molar mass is added to the solvent, it will have a larger effect on the boiling point elevation. As a result, the same mass of a solute with a higher molar mass will have a greater effect on the boiling point elevation.

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To determine which element is oxidized and which is reduced in a redox equation, you need to look at the change in oxidation states of each element.

The element that has a decrease in oxidation state is being reduced, while the element that has an increase in oxidation state is being oxidized.

For example, in the equation \(Cu + 2AgNO_3 \rightarrow Cu(NO_3)2 + 2Ag\), copper \((Cu)\) is being oxidized from an oxidation state of \(0 to +2\), while silver \((Ag)\) is being reduced from an oxidation state of \(+1 $ to 0\). Therefore, \(Cu\) is the oxidizing agent and Ag is the reducing agent in this equation.

To determine which element is oxidized and which is reduced in a redox equation, follow these steps:

So, in the example redox equation \(Zn(s) + Cu^{2} +(aq) \rightarrow Zn^{2} +(aq) + Cu(s)\), the element \(Zn\) is oxidized and the element \(Cu\) is reduced.

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If the net effect of all graded potentials is hyperpolarization, the membrane potential will become more negative.


Graded potentials are small changes in membrane potential caused by the flow of ions across the membrane. They can be either depolarizing or hyperpolarizing, depending on the type of ion and direction of flow. If the net effect of all graded potentials is hyperpolarization, this means that the majority of the graded potentials were hyperpolarizing and caused the membrane potential to become more negative.

This could happen, for example, if inhibitory signals were received by a neuron, causing it to become more resistant to firing. Hyperpolarization makes it harder for the neuron to reach its threshold for action potential firing, so if the net effect is hyperpolarization, the neuron will be less likely to fire.

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Answer:

It helps us to insure what will the current rate will be to those subject or nartual disaster can conquere

Answer:

Yes it is indeed

Explanation:

Thanks if you found this helpful

The balanced chemical equation is  \(\rm C_3H_8 + 5O_2- \rightarrow 3CO_2 + 4H_2O\).

Chemical equation is defined as a formulation of mathematics that captures the chemical reaction. We can learn about the reactants and products involved in a chemical reaction by developing a chemical equation. It includes the symbols for the atoms of each element found in the compound, together with a count of how many of each element there are overall in the form of subscripts.

Chemical equations must be balanced in order to satisfy the law of conservation of mass, which states that "the total mass of all products of reaction in a chemical reaction is equal to the total mass of all reactants." A chemical equation is said to be balanced when the number of various elemental atoms on the reactants and products sides are equal. Chemical equations must be balanced by a process of trial and error.

Thus, the balanced chemical equation is \(\rm C_3H_8 + 5O_2- \rightarrow 3CO_2 + 4H_2O\).

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That oil sands executive is greedy and heartless and therefore can't be trusted when she claims is Ad hominem attack. So, Option B is correct.

4-  The argument in question 4 is an example of an ad hominem attack. This is due to the argument's focus on the character of the oil sands executuive rather than the actual problem, which is how to improve the company's environmental record.

The argument holds that the executive cannot be believed when she says she wants to improve the company's environmental record because she is avaricious and callous. This is an error in logic, though, as the executive's character may not necessarily be related to the company's environmental policies.

5-  The argument in question 5 is an example of an appeal to ignorance. This is because the argument states that there is no proof that humans are causing climate change, so it must be natural causes. Just because there is no conclusive proof that humans are causing climate change, it does not mean that they are not.

The argument assumes that just because there is no evidence to the contrary, the argument must be true. This is a logical fallacy.

So, Option B is correct.

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