For the circuit (i) Find the voltage vc and the current ic if the capacitor was initially uncharged and the switch is thrown into position A (ii) Find the voltage Vc and the current ic if the switch is thrown into position B. (iii) Plot the waveforms for the questions (i) and (ii) for both the voltage Vc and the current ic. Mark the time constant for part (1) and part (ii) in the waveforms with the corresponding values for current and voltage. [5+5+5 = 15) 20 k 12 R210 k 2 0.05 ur
Answers
A) The reactance of the capacitor is 159.2 ohms.
B) The total impedance is 2k - j159.2 ohms and the impedance diagram is a line segment from (0,0) to (2000,-159.2).
C) The current I is 59.94 mA at an angle of -4.52 degrees.
D) Vr = IR = 0.1199 V, Vc = IXc = -15.92 V.
E) Vr = e * R / (R + Xc) = 5.598 V, Vc = e * Xc / (R + Xc) = -744.9 V.
F) The power of R is 0.2398 mW.
G) The power supplied by the voltage source e is 0.2398 mW.
H) The phasor diagram is a right triangle with legs 5.598 V and -744.9 V, and hypotenuse 744.9 V.
I) The Fp of the network is 0.999.
J) The current and voltages in the time domain are i = 59.94sin(1000t - 4.52 degrees), Vr = 0.1199sin(1000t), and Vc = -15.92sin(1000t + 85.48 degrees).
A) The reactance of the capacitor can be calculated using the formula X = 1/(2pif×C), where f is the frequency of the source and C is the capacitance of the capacitor.
B) The total impedance can be calculated using the formula Z = √(R² + Xc²). The impedance diagram can be drawn by representing the resistance and reactance as the horizontal and vertical components of a right-angled triangle, respectively.
C) The current I can be calculated using Ohm's Law, I = V/Z, where V is the voltage of the source.
D) The voltages Vr and Vc using Ohm's Law can be calculated by multiplying the current I by the resistance R and reactance Xc, respectively.
E) The voltages Vr and Vc using the voltage divider rule can be calculated by dividing the voltage of the source by the total impedance and the reactance of the capacitor, respectively.
F) The power of R can be calculated using the formula P = Vr²/R.
G) The power supplied by the voltage source e can be calculated using the formula P = Vrms Irms cos(theta), where Vrms and Irms are the RMS values of the voltage and current, respectively, and theta is the phase angle between them.
H) The phasor diagram can be drawn by representing the voltage and current as vectors with magnitudes equal to their RMS values and directions determined by their phase angles.
I) The power factor (Fp) of the network can be calculated using the formula Fp = cos(theta), where theta is the phase angle between the voltage and current.
J) Current and voltages in the time domain can be obtained by using the phasor representation and converting the phasors back to time domain using the inverse phasor transform.
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Related Questions
the complexity of bfs and dfs
Answers
Answer:
BFS uses Queue to find the shortest path. DFS uses Stack to find the shortest path. ... Time Complexity of BFS = O(V+E) where V is vertices and E is edges. Time Complexity of DFS is also O(V+E) where V is vertices and E is edges.
Explanation:
For a bronze alloy, the stress at which plastic deformation begins is 275 MPa, and the modulus of elasticity is 115 GPa. (a) What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm2 without plastic deformation
Answers
Answer:
89375 N
Explanation:
Rearrange the formula for normal stress for F:
\(\sigma=\frac{F}{A}\)
\(F=\sigma*A\)
Convert given values to base units:
275 MPa = \(275*10^{6}\) Pa
325 \(mm^{2}\) = 0.000325 \(m^{2}\)
Substituting in given values:
F = \((275*10^{6})*(0.000325)=89375\) N
why is it difficult to dissolve cellulose in solvent that dissolve petroleum based polymers
Answers
The crystallinity of cellulose as well as its polar qualities makes it less difficult to dissolve. It has a three-dimensional hydrogen bond (H-bond) arrangement with the hydroxyl group connected to each polymer chain. On the other hand, Hydrocarbon polymers are nonpolar, and nonpolar solvents are used to dissolve them.
What exactly is cellulose?Cellulose is an organic molecule with the formula n that is a polysaccharide made up of a linear chain of hundreds to thousands of β linked D-glucose units. Cellulose is a structural component of the major cell wall of green plants, many algae, and oomycetes.
Cellulose is the principal component present in plant cell walls and aids in the plant's stiffness and strength. Although cellulose cannot be digested by humans, it is an essential source of fiber in the diet. Cellulose is utilized in the production of clothing and paper.
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Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl.
For each volume of HCl added, decide which of the components is a major species after the HCl has reacted completely.
Kb for CH3NH2 = 4.4 x 10-4.
What species are present based off what is being added?
200.00 mL HCl added
yes no H+
yes no H2O
yes no Cl-
yes no CH3NH2
yes no CH3NH3+
300.00 mL HCl added
yes no H+
yes no H2O
yes no Cl-
yes no CH3NH2
yes no CH3NH3+
Calculate the pH at the equivalence point for this titration?
Answers
Answer:
The answers are in the explanation. The pH is 5.91
Explanation:
The CH3NH2 reacts with HCl as follows:
CH3NH2 + HCl → CH3NH3⁺ + Cl⁻
When 200mL of HCl are added, the moles of CH3NH2 and HCl are reacting completely producing CH3NH3+ and Cl-. That means the species present are:
no H+. All reacted
yes H2O. Because the water is present in the solutions of HCl and CH3NH2
yes Cl-. Is a product of the reaction
Yes CH3NH2. Is consumed in the reaction but comes from the equilibrium of CH3NH3+
yes CH3NH3+. Is the other product of the reaction. MAJOR SPECIES
When 300.00mL of HCl are added, 100mL are in excess:
yes H+. Is in excess: H+ + Cl- = HCl in water. MAJOR SPECIES. Determine the pH of the solution.
yes H2O. Is present because the reactants are diluted.
yes Cl-. Is a product of reaction and comes from HCl.
Yes CH3NH2. The reactant is over but comes from the equilibrium of CH3NH3+
yes no CH3NH3+. Yes. Is a product and remains despite HCl is in excess.
To find the pH:
At equivalence point the ion that determines pH is CH3NH3+. Its concentration is:
0.100L * (0.200mol/L) = 0.0200 moles / 0.300L = 0.0667M CH3NH3+
The equilibrium of CH3NH3+ is:
Ka = Kw/kb = 1x10-14/4.4x10-4 = 2.273x10-11 = [H+] [CH3NH2] / [CH3NH3+]
As both [H+] [CH3NH2] comes from the same equilibrium:
[H+] = [CH3NH2] = X
2.273x10-11 = [X] [X] / [0.0667M]
1.5159x10-12 = X²
X = 1.23x10-6M = [H+]
As pH = -log [H+]
pH = 5.91
The pH at the equivalent point for this titration is "5.91".
pH Calculation:\(CH_3NH_2 = 0.200\ M\\\\ \text{volume} = 100.0\ mL = 0.100\ L\\\\HCl = 0.100\ M\\\\\)
We must now quantify the pH well at the equivalence point.
We know that even at the point of equivalence, moles of acid and moles of the base are equivalent. As such, first, we must calculate the number of moles of the given base.
Calculating the Moles in \(CH_3NH_2 = 0.200\ M \times 0.100\ L = 0.0200\ moles\)
Calculating the Moles in \(HCl = 0.0200 \ moles\)
Calculating the volume of \(HCl\):
\(\to \text{Molarity} = \frac{ \text{moles}}{\text{volume \ (L)}} \\\\\to \text{Volume} = \frac{\text{moles}}{\text{molarity}}\\\\\)
\(= \frac{0.0200 \ moles}{ 0.100\ M}\\\\= 0.200 \ L\\\\= 200 \ mL\\\\\)
Calculating the reaction among the acid and base:
\(CH_3NH_2 + HCl \longrightarrow CH_3NH_3^{+} + Cl^-\)
\(0.0200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.0200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.0200\)
Therefore the conjugate acid of the bases exists at the standard solution.
Then we must calculate the new molar mass of \(CH_3NH_3^+\).
Total volume\(= 100 + 200 = 300\ mL = 0.300\ L\)
\([CH_3NH_3^+] = \frac{0.0200\ mole}{ 0.300\ L}= 0.0667\ M\)
Using the ICE table
\(CH_3NH_3^+ + H_2O \longrightarrow CH_3NH_2 + H_3O^+\)
\(I \ \ \ \ \ \ \ \ \ \ 0.0667 \ \ \ \ \ \ \ \ \ 0\ \ \ \ \ \ \ \ \ 0\\\\C\ \ \ \ \ \ \ \ -x\ \ \ \ \ \ \ \ +x \ \ \ \ \ \ \ \ +x\\\\E \ \ \ \ \ \ \ \ \ \ \ \ 0.0667-x \ \ \ \ \ \ \ \ \ \ \ \ +x \ \ \ \ \ \ \ \ \ \ \ \+x\\\\\to Ka = \frac{[CH_3NH_2] [H_3O^+] }{[CH_3NH_3^+]}\)
Calculating \(K_a\) from \(K_b\)
\(\to K_a \times K_b = 1\times 10^{-14}\\\\\to K_a = \frac{1\times 10^{-14}}{4.4\times 10^{-4}} = 2.27\times 10^{-11}\\\\\)
\(= 2.27\times 10^{-11} \\\\= x\times \frac{x}{(0.0667-x)}\)
The x in the 0.0667-x can be ignored since the Ka value is just too small and it also does not follow the five percent criteria.
\(\to 2.27 \times 10^{-11} \times 0.0667 = x_2\\\\\to x_2 = 1.515\times 10^{-12}\\\\\to x = 1.23\times 10^{-6}\ M\\\\\to [H_3O^+] = x = 1.23\times 10^{-6}\ M\\\\\)
We have the formula to calculate pH.
\(\to pH = - \log [H_3O^+] = - \log 1.23\times 10^{-6}\ M= 5.91\)
The pH at the equivalent point for this titration is "5.91".
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2.13 LAB: Count characters Write a program whose input is a string which contains a character and a phrase, and whose output indicates the number of times the character appears in the phrase. Ex: If the input is: n Monday the output is: Ex: If the input is: z Today is Monday the output is: 0 Ex: If the input is: n It's a sunny day the output is: 2 Case matters. Ex: If the input is: n Nobody the output is: 0 n is different than N. 2477/2.1898342.cx32997 LAB ACTIVITY 2.13.1: LAB: Count characters 0/10 main.py
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A string is normally regarded as a type of data and is frequently implemented as an array data structure made up of bytes (or words) that stores a series of components, usually characters, using a character encoding.
What is string?A string is normally regarded as a type of data and is frequently implemented as an array data structure made up of bytes (or words) that stores a series of components, usually characters, using a character encoding. Other data types and structures that use sequences (or lists) of items can also be referred to as string. Traditionally, a string in computer programming is a collection of characters that can be either a literal constant or a type of variable. The latter can either have fixed length and allow for element mutations (after creation). Text and character data are stored in strings. Consider the string of characters that make up "Hello World." C lacks a String type that would make it simple to generate string variables, unlike many other programming languages.user_string=input(str())
character=user_string[0]
phrase=user_string[1]
count=0
for i in phrase:
if i == character:
count = count+1
if count!= 1:
print(str(count) + " " + character + "'s")
else:
print(str(count) + " " + character)
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tìm phản lực gối tựa
Answers
Answer:
jwjehevrvbdbejd HB dbnwjsishrb t bxjwbkozkwnwn shxvbebhgvevhehjhr. jebn
are trains cool because if they are then my dad didn't beat me
Answers
Answer:
I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too
A car is driven over a curb twice—once very slowly and once quite rapidly. What would you need to know about the car in the second case that you did not need to know in the first case if you were required to find the tire force that resulted from going over the curb?
Answers
Answer:
You'd need to know things like the weight of the car, the spring constant of the suspension springs.
Explanation:
Driving over the curb slowly does not have much of an "impact" because of the small potential energy it has but to find the force that results from going over the curb at a much higher speed, you would need to know the weight of the car since it directly impact the force that it applies. You also would need to know about the car's suspension, the spring material, how stiff the springs are and their spring constant to calculate the force they absorb.
I hope this answer helps.
Mr. and Ms. Boren have two children, John and Jane. When eating out they will go to a restaurant that serves only hamburgers or one that serves only chicken. Before going out, the family votes to decide on the restaurant. The majority wins, except when Mom and Dad agree, and in that case, they win. Any other tie votes produce a trip to the chicken restaurant.
Required:
Design a logic circuit that will automatically select the restaurant when everyone votes.
Answers
Explanation:
The logic is captured in the Karnaugh map of the first attachment. M and D refer to Mom and Dad, respectively, and A and B refer to the children. A logic 1 is a vote for Chicken, 0 is a vote for Hamburger.
The logic in attachment 2 shows an implementation using And and Or gates. The effective equation is ...
chicken = (m·d) + (m+d)·(a+b)
The logic in attachment 3 shows an implementation using an 8-input selector. The dots at the inputs represent inversion, so those inputs to the selector represent a logic 1 (chicken).
need urgent help!!
Determine the point(s) P on the line e with equation x−6 = ( y−3)/4 = ( 1−z)/3
for which the line connecting P with Q(2, −6, 5) is perpendicular to e.
Answers
The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.
How are quartiles determined?In order to quartile a set of data with n items (numbers), we choose the n/4th, n/2nd, and n/4th items. Interpolation between the adjacent items is used if indexes n/4, n/2, or 3n/4 are not integers.For instance, the first quartile Q1 of ordered data is the 25th item, the second quartile Q2 is the 50th item, and the third quartile Q3 is the 75th item. The fourth quartile Q4 would be the highest item of data, and the zeroth quartile Q0 would be the minimum item; however, these extreme quartiles are referred to as the minimum and maximum of a set, respectively.Calculation:Statistical file: {2, -6, 5}
Quartile Q1: -6
Quartile Q2: 2
Quartile Q3: 5.
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2. A wire, 1.5mm diameter, supports a mass of 60kg. calculate the stress.
Answers
Answer:
Therefore, the stress on the wire is 1.05 x 10^9 Pa.
Explanation:
To calculate stress, we need to know the force applied to the wire and its cross-sectional area.
The first step is to calculate the cross-sectional area of the wire:
A = πr² = π(0.75mm)² = π(0.00075m)² = 5.58 x 10^-7 m²
Next, we need to calculate the force applied to the wire due to the weight of the mass:
F = m*g = 60kg * 9.81 m/s² = 588.6 N
Now we can calculate the stress:
stress = F/A = 588.6 N / 5.58 x 10^-7 m² = 1.05 x 10^9 Pa
Therefore, the stress on the wire is 1.05 x 10^9 Pa.
A wing model is tested in a subsonic wind tunnel at standard sea-level conditions with a velocity of 100 m/s. The wing area and chord are 1.5 m2 and 0.45 m respectively. The moment about the c. g. when the lift is zero is found to be -12.4 N. m. When the model is pitched to another AOA, the lift and moment about the c. g. are measured to be 3675 N and 20.67 N. m., respectively. Calculate the value of the moment coefficient about the aerodynamic center (acmC) and the location of the aerodynamic center with respect to c. g..
Answers
In aerodynamics, the pitching moment on an airfoil is the moment (or torque) produced by the aerodynamic force on the airfoil if that aerodynamic force is applied at the aerodynamic center of the airfoil rather than the pressure center.
The pitching moment on an airplane's wing is part of the overall moment that must be balanced using the lift on the horizontal stabilizer. Section 5.3 A pitching moment, in general, is any moment operating on the pitch axis of a moving body.
The lift on an airfoil is a dispersed force that acts at a location known as the center of pressure. On a cambered airfoil, however, there is movement when the angle of attack varies.
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consider the pressure driven flow of glycerin at 20◦c in the annular region between two coaxial cylinders with inner radius r1
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In the given scenario, the flow is pressure-driven, which means that the flow rate is determined by the pressure difference between the two ends of the coaxial cylinders. Additionally, the flow is confined to the annular region between the cylinders, with glycerin as the working fluid at a temperature of 20°C.
The pressure-driven flow of glycerin at 20°C in the annular region between two coaxial cylinders with an inner radius r1 can be described by the Hagen-Poiseuille equation. This equation relates the flow rate of a viscous fluid in a cylindrical pipe to the pressure difference across the pipe and the properties of the fluid and the pipe.
The Hagen-Poiseuille equation states that the flow rate (Q) is directly proportional to the pressure difference (∆P), the fourth power of the radius (r^4), and inversely proportional to the viscosity (μ) and the length of the pipe (L).
Mathematically, it can be expressed as:
Q = (π/8) * (∆P) * (r1^4 - r2^4) / (μ * L)
where r2 is the outer radius of the annular region.
In the given scenario, the flow is pressure-driven, which means that the flow rate is determined by the pressure difference between the two ends of the coaxial cylinders. Additionally, the flow is confined to the annular region between the cylinders, with glycerin as the working fluid at a temperature of 20°C.
By using the Hagen-Poiseuille equation, you can calculate the flow rate of glycerin in this system by plugging in the relevant values for ∆P, r1, r2, μ, and L.
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describe the historical development of building material being used in the construction indsury
Answers
Answer:
Construction, the techniques and industry involved in the assembly and ... Early building materials were perishable, such as leaves, branches, and animal hides. ... The well-developed masonry technology of Mesopotamia was used to build large ... although its precise description is unknown; the concealed faces of stones
Explanation:
At the beginning of last year, tarind corporation budgeted $1,000,000 of fixed manufacturing overhead and chose a denominator level of activity of 500,000 machine-hours. At the end of the year, tari's fixed manufacturing overhead budget variance was $14,000 favorable. Its fixed manufacturing overhead volume variance was $20,000 favorable. Actual direct labor-hours for the year were 525,000. What was tari's total standard machine-hours allowed for last year's output?.
Answers
The tari's total standard machine-hours allowed for last year's output 600,000 hours
Budgeted at start of year: $100,000 fixed manufacturing overhead for 500,000 machine hours
Standard = $100,000 / 500,000 hours = $0.2 fixed overhead / maching hour
At end of year, manufacturing overhead volume was $20,000 favorable which means
$20000 / $1=0.2 = 100000 additional hours.
Total Standard Machine Allowance Allowed for output = 500,000 + 100,000 = 600,000 hours.
the use of one machine running for an hour as a basis for cost estimation and operating effectiveness evaluation. In order to determine the contribution margin per machine hour for a specific product: a. Total cost per unit divided by the quantity of machine hours required to produce each unit of the target product. The manufacturing overhead cost divided by the activity driver yields the predetermined overhead rate. For instance, if machine hours were the activity driver, you would divide overhead costs by the anticipated number of machine hours.
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15. Concerning blood, which virus poses the greatest risk for workers?
A) O HIV
B) O Hepatitis C
C) O Hepatitis A
D) O Hepatitis B
Answers
Answer:
I think the answer is A. HIV
Turning operations that require heavy material removal typically use what setting on the
engine lathe?
Answers
The fan pressure differential gage on an air handler reads 12 cm H2O. What is this pressure differential in kiloPascals
Answers
Answer:
\(1.18\ \text{kPa}\)
Explanation:
g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)
h = Height of reading = 12 cm
\(\rho\) = Density of water = \(1000\ \text{kg/m}^3\)
Pressure due to height difference is given by
\(P=\rho gh\\\Rightarrow P=1000\times 9.81\times 12\times 10^{-2}\\\Rightarrow P=1177.2\ \text{Pa}=1.1772\ \text{kPa}\approx 1.18\ \text{kPa}\)
The pressure differential is \(1.18\ \text{kPa}\).
According to the question,
Height of reading, \(h = 12 \ cm\)Density of water, \(\rho = 1000 \ kg/m^3\)Acceleration due to gravity, \(g = 9.8 \ m/s^2\)The formula will be:
→ \(P = \rho g h\)
By putting the values, we get
\(= 1000\times 9.8\times 12\times 10^{-2}\)
\(= 1177.2 \ Pa\)
\(= 1.18 \ kPa\)
Thus the answer above is correct.
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If 500j of work is required to carry a charge from one point to another through a potential difference of 20v what is the magnitude of the charge
Answers
W = Q × ΔV
500 J = Q × 20V
Q = 25C
Ferroconcrete is reinforced concrete that combines concrete and ________. A. Lead c. Copper b. Iron d. Aluminum.
Answers
Answer:
B. Iron
Explanation:
took the test.
Match the job descriptions with the job titles.
biomedical engineer
radiologist
employee benefits manager
Develop policies and provide information to staff members.
Develop artificial human limbs and organs.
Diagnose patients using X-ray scans.
Answers
Answer:
this
Explanation:
biomedical student - develop artificial human organs and limbsradiologist - diagnose patients using X-ray scansEmployee benefits manager - develop policies and provide information to staff membersTrue or false To fasten a duct hanger to a gypsum board wall, the best fastener would be an anchor shield
Answers
The given statement of "To fasten a duct hanger to a gypsum board wall, the best fastener would be an anchor shield" is false.
Why is the above statement false?Anchor shields are typically used to secure objects to concrete or masonry walls.
For fastening a duct hanger to a gypsum board wall, the best fastener would be a toggle bolt or a self-drilling drywall screw. These fasteners are specifically designed for use in drywall and can provide a secure hold for the duct hanger.
Therefore, one can say that Anchor shields may not provide a secure hold in drywall, as they are designed for use in masonry or concrete.
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write a paragraph about what this passage is about?
Accurate estimates of cost are vital to the suc- cess of a construction project. Developing such estimates in great detail is the responsibility of the construction estimator. Usually employed by a gen- eral contractor, the construction estimator factors in everything from the price of lumber to the cost of renting a large crane for a day, the labor pay rates to insurance coverage, and expected loss of time resulting from bad weather. The resulting estimate is used as the basis for the contractor to competitively bid on the construction contract. For firms building single homes or residential developments, such an estimate is used to set the selling price of the homes. Construction estimators usually begin with a set of detailed building plans that provide dimensions and other information needed to begin the estimate. In most cases, the estimator also visits the site. This visit provides information on terrain, site access, drainage, and the availability of utilities. Next, careful analyses of material and labor requirements are done. These are called takeoffs and are entered on standard estimating forms. The estimator must identify and enter on the forms the exact quantities of each item that the contrac- tor must provide. If portions of the work (such as plumbing or electrical) are subcontracted, the esti- mator must usually analyze the bids submitted by the subcontractors. Decisions involving sequenc- ing of operations must be made, since improperly scheduled equipment, materials, or work crews may cause delays and increased costs. Allowances must be made for shipping delays, waste and damage to materials, weather problems, and so on. While most construction estimators are employed by building contractors, some work for large architec- tural or engineering firms. Estimators may also operate their own consulting businesses, providing fee-based services to contractors, government agencies, and building owners or financing organizations. Educational requirements for construction esti- mators usually consist of a degree in a field such as construction management, engineering, or archi- tecture. A strong aptitude for mathematics and pro- ficiency with computer software are also valuable assets. Many estimators also have practical expe- rience in construction work, giving them familiarity with materials, job practices, and the various spe- cialty trades. Additional on-the-job training is usually provided, since each company has its own specific way of preparing and presenting estimates. Professional certification is voluntary, but ben- eficial. Such certification is administered by two professional organizations—the Association for the Advancement of Cost Engineering and the Society of Cost Estimating and Analysis. The requirements vary, but include a number of years of professional experience and passing an examination.
Answers
The inference is that the summary of the passage is that accurate estimates of cost are vital to the success of a construction project.
What is an inference?It should be noted that an inference simply means the conclusion that can be deduced based on the information that's given by the author.
It was stated in the passage that developing accurate estimates in great detail is the responsibility of the construction estimator.
Construction estimators usually begin with a set of detailed building plans that provide dimensions and other information needed to begin the estimate.
Therefore, the inference is that the summary of the passage is that accurate estimates of cost are vital to the success of a construction project
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Which battery cable is bolted to the vehicle frame to allow the metal structure of the vehicle to serve as a large conductor to carry current?
Answers
Answer:
The Negative battery cable is used to bolt the vehicle frame to allow the metal structure of the vehicle to serve as a large conductor to carry current.
Explanation:
Battery cable is large automotive cable. Like smaller types of automotive wire, it is available in PVC and cross-linked forms. Click here to read an earlier post explaining the differences between PVC and cross-linked wire insulation.
One type of PVC battery cable is SGT cable. It is rated to 80°C and therefore can be used in starters or battery grounds. Cross-linked battery cables can also be used in starter and battery ground applications, and they are more resistant to heat, abrasion, and aging than PVC cable.
Two types of cross-linked battery cable are SGX and STX. They are rated to 125°C. Of the three types of battery cable (SGT, SGX, amd STX), STX has the thinnest wall, making it a popular choice for automotive applications with limited space.
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A rate of 0.42 minute per piece is set for a forging operation. The operator works on the job for a full eight-hour day and produces 1,500 pieces. Use a standard hour plan.
Required:
a. How many standard hours does the operator earn?
b. What is the operator's efficiency for the day?
c. If the base rate is 9.80 per hour, compute the earnings for the day.
d. What is the direct labor cost per piece at this efficiency?
e. What would be the proper piece rate (rate expressed in money) for this job, assuming that the above time standard is correct?
Answers
Answer:
b. What is the operator's efficiency for the day?
AND
e. What would be the proper piece rate (rate expressed in money) for this job, assuming that the above time standard is correct?
Explanation:
The scale of the blueprint tells us the
of drawing to real space?
Answers
Answer:
yes
Explanation:
blueprint of the construction is a prediction of project its is slightly auto cad
QUESTION 22
When measuring the thickness of a component measuring around .0015 inches, which of the following measuring tools would be most
accurate?
A machinist rule
A dial caliper
Answers
A micrometer is used to gauge a component's thickness at about.0015 inches.
What is micrometer?A micrometer, also referred to as a micrometer screw gauge, is an instrument with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, machining, and most mechanical trades, along with other metrological instruments like dial, Vernier, and digital calipers.An instrument for measuring flat surfaces or various geometries is a micrometer. For instance, the pipe's inner diameter or thickness. For extremely accurate measurements, engineers and petrologists employ micrometers in practically every industry. They are widely utilized for crucial metrological tasks like measuring diameters, analyzing depths, taking accurate measurements of components, and characterizing surfaces. The former usage was incompatible with the SI's official adoption of the unit prefix micro-, indicated by the symbol, in 1960, which led to the requirement for this.To learn more about micrometer refer to:
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Furnace external static pressure should be tested by?
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Explanation:
It typically should take less than five minutes to measure a residential system’s static pressure. Here are sample instructions for a furnace and an external coil:
STEP 1: Locate the appropriate locations to drill the test ports on the supply side (+) between the furnace and the coil, and on the return side (-) between the filter and the furnace. Center the test ports for neat appearance. Stay away from any coils, cap tubes, condensate pans, or circuit boards to avoid damage. Always look before you drill.
a balanced delta-connected load is supplied by a 60-hz three-phase source with a line voltage of 240 v. each load phase draws 6 kw at a lagging power factor of 0.8. find:
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Explanation:
Line current: To find the line current, we can use the formula:
I = P / (√3 * V * cos(Φ))
where:
I = line current (A)
P = power per phase (W)
V = line-to-line voltage (V)
cos(Φ) = power factor (lagging, so cos(Φ) = 0.8)
Plugging in the values:
I = 6 kW / (√3 * 240 V * 0.8) = 20.5 A
Phase current: To find the phase current, we divide the line current by √3:
I_phase = I / √3 = 20.5 A / √3 = 11.7 A
Total power: To find the total power, we multiply the power per phase by 3:
P_total = 3 * 6 kW = 18 kW
Apparent power: The apparent power, S, can be found using the formula:
S = √(P^2 + Q^2)
where:
P = real power (W)
Q = reactive power (VAR)
To find the reactive power, Q, we can use the formula:
Q = P / tan(Φ) = P / tan(arccos(cos(Φ)))
Plugging in the values:
Q = 6 kW / tan(arccos(0.8)) = 7.5 kVAR
S = √(6 kW^2 + 7.5 kVAR^2) = √(36 + 56.25) kVA = 9 kVA
The results show that the balanced delta-connected load is supplied by a 60-Hz three-phase source with a line voltage of 240V and draws a total of 18 kW of real power at a lagging power factor of 0.8. The line current is 20.5 A and the phase current is 11.7 A. The apparent power is 9 kVA.
A lake with a surface area of 525 acres was monitored over a period of time. During onemonth period the inflow was 30 cfs (ie. ft3 /sec), the outflow was 27 cfs, and a 1.5 in seepage loss was measured. During the same month, the total precipitation was 4.25 inches. Evaporation loss was estimated as 6 inches. Estimate the storage change for this lake during the month.
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Answer:
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
Explanation:
We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:
\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)
Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.
Monthly inflow
\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)
Monthly outflow
\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)
\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)
Seepage losses
\(V_{seepage} = s_{seepage}\cdot A_{lake}\)
Where:
\(s_{seepage}\) - Seepage length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)
Evaporation losses
\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)
Where:
\(s_{evaporation}\) - Evaporation length loss, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)
Precipitation
\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)
Where:
\(s_{precipitation}\) - Precipitation length gain, measured in feet.
\(A_{lake}\) - Surface area of the lake, measured in square feet.
If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:
\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)
\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)
Finally, we estimate the storage change of the lake during the month:
\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)
\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)
The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.
The volume of water gained and the loss of water through flow,
seepage, precipitation and evaporation gives the storage change.
Response:
The storage change for the lake in a month is 1,582,823.123 ft.³How can the given information be used to calculate the storage change?Given parameters:
Area of the lake = 525 acres
Inflow = 30 ft.³/s
Outflow = 27 ft.³/s
Seepage loss = 1.5 in. = 0.125 ft.
Total precipitation = 4.25 inches
Evaporator loss = 6 inches
Number of seconds in a month is found as follows;
\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)
Number of seconds in a month = 2592000 s.
Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³
1 acre = 43560 ft.²
Therefore;
525 acres = 525 × 43560 ft.² = 2.2869 × 10⁷ ft.²
Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³
Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³
Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³
\(Storage \, change \, \Delta V = \mathbf{V_{fl} - V_s + V_p - V_e}\)Which gives;
ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123
The storage change, ΔV = 1,582,823.123 ft.³Learn more about water resources and hydrology here:
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