For sound waves, which travel at 343 m/s in air at room temperature, what frequency corresponds to a wavelength of 2.00 m ?

Answers

Answer 1
\(\begin{gathered} v=\lambda f \\ \lambda=wavelength=2.00m \\ v=343\text{ m/s} \\ 343\text{ m/s=(2.00m)f} \\ \text{Solving f} \\ f=\frac{343\text{ m/s}}{2.00m} \\ f=171.5\text{ Hz} \\ \text{The frequency is }171.5\text{ Hz} \end{gathered}\)


Related Questions

HI PLEASE HELP?A speed skater skates 1.5 km in 78 s. What is her speed in km/h?Need a Hint?57 km/h61 km/h65 km/h68 km/h

Answers

The speed of skater can be given as,

\(v=\frac{d}{t}\)

Here, v is the speed, d is the distance travelled and t is the time taken.

Substitute the known values,

\(\begin{gathered} v=\frac{1.5\text{ km}}{(78\text{ s)(}\frac{1\text{ h}}{60\text{ min}})(\frac{1\text{ min}}{60\text{ s}})_{}} \\ \approx68\text{ km/h} \end{gathered}\)

Thus, the speed of skater is approximately 68 km/h.

What would happen to the orbits of the planets if the amount of gravity produced bythe Sun were reduced to almost zero?A. The planets would abandon their orbit and move out into space.B. The planets would start crashing into each other.C. The planets would orbit as usual.

Answers

Given:

The amount of gravity produced by the Sun was reduced to almost zero.

To find:

What would happen to the orbits of the planets

Explanation:

The centripetal force for the rotation of every planet is supplied by the gravitational force between the sun and the planet. If the gravitational force by the sum becomes zero, the planets would begin moving away from their usual path into space.

Hence, the planets would abandon their orbit and move out into space.

Given a metal loop of wire with an area of 400 square centimeters and a magnetic field of 0.0875 Tesla through it. If the magnetic field is constant everywhere through the loop then which of these is the magnetic flux through the loop in SI units? [4. Define magnetic flux] 0.00350 0.0140 286

Answers

We will have that the value will be:

\(\Phi=(0.04m^2)(0.0875T)\Rightarrow\Phi=0.00350m^2T\)

A ball is thrown vertically upward with a speed of
25.0 m/s from a height of 2.0 m.
a. How high does the ball rise?
b. How long does it take to reach its highest point?
c. How long does the ball take to hit the ground
after it reaches its highest point?
d. What is the ball's velocity when it returns to
the level from which it started?

Answers

a.)  the ball rises to a height of 31.88m

b.) It takes the ball 2.55 seconds to reach its highest point

c.) It takes the ball 2.55 seconds to hit the ground

d.) The ball's velocity is -24.99 m/s in the negative direction which is downwards.

What is velocity?

Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

From the given question, we have that

b.) At highest point velocity of the ball will become zero so v=0m/s.

So using equation

v = u + gt

0 = 25 - 9.8t

t = 25/9.8 s =2.551 s

Time taken by the ball to reach its highest point will be 2.551 seconds .

a.)  The height the ball rises is given by

v²-u²=2gh

=> 0-(25.0)²=-2*9.8*h

=> 19.6h= (25.0)²

=> h= 31.88m.

c.)  It will take the ball 2.55 seconds to hit the ground

after it reaches its highest point because it will take the ball same time for the ball to reach its highest point or fall to the ground.

d.) velocity = u - gt

V = 0 - 9.8 * 2.55

V= -24.99 m/s in the negative direction which is downwards.

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A tape diagram. 0 dollars is 0 percent. Question mark dollars is 23 percent. 52 dollars is 100 percent. Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52. Which expression can you use to find 23% of 52? 23% of $52 is $ . An easy way to check your answer is to use the friendly and divide 52 by to get .

Answers

Answer:

Jared has earned 23% of the $52 he needs to buy a new jacket. Find 23% of $52.

Which expression can you use to find 23% of 52?

✔ 0.23 × 52

23% of $52 is $

✔ 11.96

.

An easy way to check your answer is to use the friendly

✔ 25%

and divide 52 by

✔ 4

to get

✔ 13

.

Explanation:

Sound Wave A is moving through a medium that is
decreasing in temperature.
Sound Wave B is moving from a liquid to a gas medium.
Mark this and return
Which statement can be made about both waves?
O They will speed up.
O They will increase the density of their medium.
O They will slow down.
O They will decrease the density of their medium.
Save and Exit
28.2
Next
Submit

Answers

Explanation:

The satement that can be made about sound wave A and sound wave B is, they will slow down.

Relationship between sound wave and temperature

The relationship between sound waves and temperature is given by the following formula;

v= √γRT

The speed of sound wave increases with increase in temperature, and vice versa.

Speed of sound wave in liquid and gaseous medium

Sound wave is mechanical wave, because it requires material medium for its propagation. Sound will travel faster in liquid medium than gaseous medium because of number of molecules per unit volume.

Thus, the satement that can be made about sound wave A and sound wave B is, they will slow down.

A pitching machine is programmed to pitch baseballs horizontally at a speed of 134 km/h. The machine is mounted on a truck and aimed forward. As the truck drives toward you at a speed of 85 km/h, the machine shoots a ball toward you. A pickup truck moves to the left at a constant velocity. A pitching machine sits in the bed of the pickup truck. The pitching machine launches a baseball to the right with a different constant velocity. A man with a baseball mitt stands at rest some distance to the right of the truck. For each of the object pairings listed, determine the correct relative speed. The speed of the pitching machine relative to the truck The speed of the pitched ball relative to the truck The speed of the pitching machine relative to you The speed of the pitched ball relative to you

Answers

Answer: 134 = 143 = 151 = 166 = 176

Hope this helps!!

Sorry if it's incorrect!!

:'(

A 100-g toy car is propelled by a compressed spring that starts it moving. The car follows the curved track in the figure above. What is the final speed of the toy car if its initial speed is 2.22
m/s and it coasts up the frictionless slope, gaining 0.21
m in altitude?

Answers

The toy car's top speed is roughly 2.01 m/s.

Why does the toy car move on the floor after the key has been wound?

When the key is wound, the potential energy of the spring is transformed into kinetic energy, which causes the toy vehicle to move on the floor. The law of conservation of energy is the reason why the toy vehicle moves on the floor once the key is wound.

K1 = (1/2) * m * v1²

where m is the mass of the toy car, v1 is its initial speed, and K1 is its initial kinetic energy.

U = m * g * h

where g is the acceleration due to gravity and h is the height gained by the toy car.

K2 = m * g * h

where K2 is the final kinetic energy of the toy car.

Equating the initial and final energies of the system, we have:

(1/2) * m * v1² = m * g * h

Simplifying and solving for v2, the final velocity of the toy car, we get:

v2 = √(2 * g * h + v1²)

Substituting the given values, we get:

v2 = √(2 * 9.81 m/s² * 0.21 m + (2.22 m/s)²)

v2 = √(4.0443)

v2 = 2.01 m/s (approx)

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HELP ME ASAPPPPPPPPPPP
A penny sinks to the bottom of a wishing well
What type of frictional force is that?

Answers

The frictional force involved when a penny sinks to the bottom of a wishing well is primarily due to viscous drag or fluid friction. As the penny moves through the water, it experiences resistance from the surrounding fluid. This resistance is caused by the frictional forces between the water molecules and the penny's surface.

Find the distance traveled by a boy if he walks 3 km north and then turns and walks 1 km to the west.
Include both magnitude and direction.

Answers

Answer:

Explanation:

Distance = total length traveled = 3 + 1 = 4 km

Displacement² = 3² + 1² = 10

Displacement = √10 = 3.16

direction = tan⁻¹(3/-1) = 71.6⁰ north of west

Which of the following would be most likely to contribute to molecules
experiencing intermolecular forces?
O A. Containing oxygen
B. Containing charged regions
O C. Electric neutrality
O D. Being made of atoms

Answers

Answer:

B. Containing charged regions

Explanation:

The term i.e. intermolecular forces would be used to explain the attraction forces. Here the interaction would be done between molecules etc that acts between the acts & the other types of particles i.e. neighboring like atoms or ions

So in the given case, the option b would be contributed to the molecules that have intermolecular forces

hence, the option b is correct

A lunar probe is moving 1,670 m/s at a 73.0⁰ angle. It needs to land on the moon 3.71 . 10⁸ m away in a 46.0⁰ direction in 8.64 . 10⁴s. What is the magnitude of the acceleration that the engine must produce?
magnitude (m/s²)

A lunar probe is moving 1,670 m/s at a 73.0 angle. It needs to land on the moon 3.71 . 10 m away in a

Answers

The magnitude of the acceleration  of the engine that must be produced is 0.068 m/s².

What is the magnitude of the acceleration of the engine?

The magnitude of the acceleration of the engine is calculated by applying the following kinematic equation.

s = vt + ¹/₂at²

where;

v is the velocity of the lunar in horizontal directions is the horizontal distancet is the time of motion

The acceleration of the engine in x direction is calculated as follows;

( 3.71 x 10⁸ x cos 46 ) = ( 1670 x cos73 )(8.64 x 10⁴) + ¹/₂ (ax)(8.64 x 10⁴)²

2.58 x 10⁸ = 4.22 x 10⁷ + 3.73 x 10⁹ax

3.73 x 10⁹ax = 2.16 x 10⁸

ax = ( 2.16 x 10⁸ ) / ( 3.73 x 10⁹ )

ax = 0.058 m/s²

The acceleration of the engine in y direction is calculated as follows;

( 3.71 x 10⁸ x sin 46 ) = ( 1670 x sin73 )(8.64 x 10⁴) + ¹/₂ (ay)(8.64 x 10⁴)²

2.67 x 10⁸ = 1.38 x 10⁸ + 3.73 x 10⁹ay

3.73 x 10⁹ay = 1.29 x 10⁸

ay = ( 1.29 x 10⁸ ) / ( 3.73 x 10⁹ )

ay = 0.035 m/s²

The magnitude of the acceleration  of the engine that must be produced is calculated as;

a = √ ( ax² + ay² )

a = √ ( 0.035² + 0.058² )

a = 0.068 m/s²

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True or False. Father of a multitude" obeyed God's command to kill His son because the Ten Commandments had not yet been given.

Answers

Answer:

Explanation:

He agreed to the command, because it was God who proposed it. The story is supposed to make a comment on faith. Abraham had faith that somehow God would make everything right. The Ten commandments came later, but really had nothing to do with Abraham's decision.

True.

An aeroplane is circling above an airport in a horizontal circle at a speed of 400 kmh-1.The banking angle of the wings is 20.What is the radius of the circular path?

Answers

Answer: the radius of the circular path is approximately 1637.58 meters.

Explanation:

The centripetal force acting on the airplane is provided by the component of the gravitational force that acts towards the center of the circular path. This component is given by:

F_c = m * g * tan(banking angle)

Where:

F_c is the centripetal force

m is the mass of the airplane

g is the acceleration due to gravity

tan(banking angle) is the tangent of the banking angle

Now, the centripetal force is also given by the formula:

F_c = (m * v^2) / r

Where:

v is the speed of the airplane

r is the radius of the circular path

Equating the two expressions for F_c, we get:

(m * g * tan(banking angle)) = (m * v^2) / r

Canceling out the mass (m) on both sides of the equation, we have:

g * tan(banking angle) = v^2 / r

Solving for r, we get:

r = (v^2) / (g * tan(banking angle))

Substituting the given values:

v = 400 km/h = 400,000 m/h

g = 9.8 m/s^2

banking angle = 20°

Converting the speed to m/s:

v = 400,000 m/h * (1/3600) h/s = 111.11 m/s

Converting the banking angle to radians:

banking angle = 20° * (π/180) rad/° = 0.3491 rad

Now, substituting the values into the formula:

r = (111.11^2) / (9.8 * tan(0.3491))

r ≈ 1637.58 meters

Therefore, the radius of the circular path is approximately 1637.58 meters.

Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place

Answers

Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.

Why is it colder at the bottom of the pool than the top of the pool?

There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;

Heat transfer by radiationHeat transfer by convection

Heat transfer by radiation

The surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.

Heat transfer by convection

The heat from the air is transferred to the pool through convection.

Thus, these two heat transfer processes  causes the surface water of the pool to be warm which decreases with depth.

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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

What would the single sample Cohen's d value be if the difference in sample mean and hypothesized mean was 16, and the sample standard deviation was 4?

Answers

Answer:

Explanation:

To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).

What is Moral subjectivism?

Answers

Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

An object of mass 2 kg moving with velocity of 12 m/s, collides head-on with a stationary object whose mass is 6 kg. Given that the collision is elastic, what are the final velocities of the two objects? Neglect friction.

Answers

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

.A glass bottle has a volume of 10 cm³ at 10°C. Calculate its volume when it is heated to 30°C. [Linear expansivity 9.0x10 k ¹]​

Answers

The final volume of the glass bottle when heated to 30°C is 10.0018 cm³.

What is the final volume of the glass bottle?

The final volume of the glass bottle is calculated by applying the formula for volume expansivity as follows;

ΔV = V₀αΔT

Where

ΔV is the change in volume of the bottleV₀ is the initial volume of the bottleα is the linear expansivityΔT is the change in temperature

The change in temperature is calculated as;

ΔT = 30°C - 10°C = 20°C

The change in volume of the bottle;

ΔV = 10 cm³ x (9 x 10⁻⁶) x 20°C

ΔV =  1.8 x 10⁻³ cm³

The final volume of the bottle is calculated as follows;

V₂ = V₁ + ΔV

V₂ = 10 cm³ +  1.8 x 10⁻³ cm³

V₂ = 10.0018 cm³

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The elastic energy stored in your tendons can contribute up to 35 % of your energy needs when running. Sports scientists have studied the change in length of the knee extensor tendon in sprinters and nonathletes. They find (on average) that the sprinters' tendons stretch 41 mm , while nonathletes' stretch only 33 mm .

Answers

Hello. Your question is incomplete. However, I managed to find it completely on the internet and I realized that you forgot to mention that the question asks you for the maximum energy difference between velovistas and non-athletes, considering that the spring constant for the tendon of the two groups is equal to 33n/mm.

To make this calculation you will need to use Hooke's law, using the formula: ¹/2*K*x², where "K" will be the value of the spring constant for the tendon and "X" will be the value of the sprinter and non-athlete terms.

So for the sprinter we will have the calculation:

¹/2*33*41² -------> 0,5*33*1681 = 27736. 5 Nmm

(To facilitate the calculation, first solve the division of ¹/2 and then multiply 41 by 41, lastly, just multiply all the results.)

For the non-athlete we will have the calculation:

¹/2*33*33² -------> 0,5*33*1089 = 17968. 5 Nmm

(To facilitate the calculation, first solve the division of ¹/2 and then multiply 41 by 41, lastly, just multiply all the results.)

Now, to reach the final result, you only need to subtract the two values presented by the sprinter and the non-athlete.

27736.5 - 17968.5 = 9768 Nmm

Problem 05.086 - Water pumped from a lower reservoir to a higher reservoir Water is pumped from a lower reservoir to a higher reservoir by a pump that provides 21 kW of useful mechanical power to the water. The free surface of the upper reservoir is 45 m higher than the surface of the lower reservoir. If the flow rate of water is measured to be 0.03 m3/s, determine the irreversible head loss of the system and the lost mechanical power during this process. Take the density of water to be 1000 kg/m3. The irreversible head loss of the system is 26.35 m. The lost mechanical power in this process is kW.

Answers

Answer:

Lost Mechanical Power = 7.7565 KW

Head Loss = 26.35 m

Explanation:

First, we will find the useful mechanical power used to transport water to the higher reservoir:

\(P_{useful} = \rho ghV\)

where,

P_useful = Useful mechanical Power = ?

ρ = density of water = 1000 kg/m³

g = acceleration due to gravity = 9.81 m/s²

h = height = 45 m

V = Volume flow rate = 0.03 m³/s

Therefore,

\(P_{useful} = (1000\ kg/m^3)(9.81\ m/s^2)(45\ m)(0.03\ m^3/s)\\P_{useful} = 13243.5\ W = 13.2435\ KW\)

Now, the lost mechanical power will be:

\(Lost\ Mechanical\ Power = Total\ Mechanical\ Power - Useful\ power\\Lost\ Mechanical\ Power = 21\ KW - 13.2435\ KW\\\)

Lost Mechanical Power = 7.7565 KW

Now, for the head loss:

\(Lost\ Mechanical\ Power = \rho g(Head\ Loss)V\\Head\ Loss = \frac{Lost\ Mechanical\ Power}{\rho gV} \\\\Head\ Loss = \frac{7756.5\ W}{(1000\ kg/m^3)(9.81\ m/s^2)(0.03\ m^3/s)} \\\)

Head Loss = 26.35 m

an object with mass m is moving along the x-axis according to the equation x(t)= at^2-2bt where a and b are positive constants what is the magnitude of the net fprce pn the pbject at time t = 0s

Answers

The magnitude of the net force pn is 2ma.

How to calculate magnitude?

To determine the magnitude of the net force on the object at time t = 0s, we need to calculate the object's acceleration at that time. We can find the acceleration by taking the second derivative of the position function x(t) with respect to time t:

x(t) = at² - 2bt

v(t) = dx/dt = 2at - 2b

a(t) = d²x/dt² = 2a

The acceleration is constant and equal to 2a. This means that the net force acting on the object is also constant and given by Newton's second law of motion:

F = ma

where F is the net force, m is the mass of the object, and a is the acceleration.

Substituting the value of acceleration a into this equation:

F = ma = m(2a) = 2ma

Therefore, the magnitude of the net force on the object at time t = 0 s is 2ma.

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AV ASSIGNMENT what is the length of wire whose resistivity, 3x10^6 ohm with the r=0.2mm with a given Value of 15.5 ohm's Resistance.​

Answers

here is the answer. hope this helps you
AV ASSIGNMENT what is the length of wire whose resistivity, 3x10^6 ohm with the r=0.2mm with a given

As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -1.5 V during one revolution. Assuming the shuttle is a conducting sphere of radius 11 m, estimate the amount of charge it collects.

Answers

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two parallel wires carrying equal currents of 10A attract each other with a force of 1mN. If both currents are doubled, what will be the force of attraction?

Answers

Answer:

F (force) can be written F/L  = K I1 I2 where K is some constant

F1 = 4 F1    if I1 and I2 are each doubled

If both currents are doubled, the new force of attraction between the wires will be 0.4 mN.

The force of attraction between two parallel wires carrying equal currents is given by Ampere's law, which states that the force is directly proportional to the product of the currents and inversely proportional to the square of the distance between the wires. Given that the current in each wire is 10A and the force of attraction is 1mN, we can use this information to calculate the distance between the wires.

Let's assume the distance between the wires is "d".

Using the formula for the force of attraction between the wires:

F = (μ₀ * I₁ * I₂) / (2πd)

where F is the force, μ₀ is the permeability of free space, I₁ and I₂ are the currents, and d is the distance between the wires.

Rearranging the formula, we can solve for d: d = (μ₀ * I₁ * I₂) / (2πF)

We know that F = 1mN, I₁ = I₂ = 10A, and μ₀ = 4π x 10^(-7) N/A².

Substituting these values into the formula, we can find the distance between the wires:

d = (4π x 10^(-7) N/A² * 10A * 10A) / (2π * 1mN)

Simplifying the expression, we find: d = (4 x 10^(-6) N/A² * 100 A²) / (2 x 10^(-3) N)

d = 200 x 10^(-6) m

d = 0.2 mm

Now, if both currents are doubled to 20A, we can calculate the new force of attraction between the wires using the same formula:

F' = (μ₀ * I₁' * I₂') / (2πd)

where F' is the new force, I₁' and I₂' are the new currents, and d is the distance between the wires.

Substituting the values, we get: F' = (4π x 10^(-7) N/A² * 20A * 20A) / (2π * 0.2mm)

Simplifying the expression, we find: F' = (4 x 10^(-6) N/A² * 400 A²) / (4 x 10^(-4) N)

F' = 400 x 10^(-6) N

F' = 0.4 mN

Therefore, the new force of attraction between the wires will be 0.4 mN, if both currents are doubled.

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Which is a valid velocity reading for an object?
45 m/s
45 m/s north
O 0 m/s south
O 0 m/s

Answers

Answer:45 m/s north

Explanation:

The elements in Groups 3 through 12 of the periodic table are the ______.

Answers

Answer:

Transition Metals

Explanation:

__________________________

Determine the cost of one no rechargeable alkaline battery ~ and compare with the cost of one rechargeable NiCad battery.

Answers

Answer:

$2.7

$0.9225

Explanation:

According to the question,  the computation is shown below:

AA NiCad rechargeable batteries cost for 4 pack is $10.80.

So for one NiCad rechargeable battery is

\(= \frac {Total\ cost}{Number\ of\ pack}\)

\(= \frac{\$10.80}{4}\)

= $2.7

Now

AA NiCad non-rechargeable batteries cost for 4 pack is $3.69

So for one NiCad rechargeable battery is

\(= \frac {Total\ cost}{Number\ of\ pack}\)

\(= \frac{\$3.69}{4}\)

= $0.9225

So as we can see that cost of one NiCad rechargeable batteries is more than the cost of NiCad non-rechargeable batteries

A metal ball began a free fall from the top of a building towards a sandy soil ground so that its velocity at the moment of striking the ground was 30 m/s, if the ball stopped after 0.01 s of penetrating the sand and the average resistance force of the sand again the motion of the ball was-3010 N, the mass of the ball is approximately equal to (Given that: The acceleration due to gravity is 10 m/s²) ​

Answers

The mass of the metal ball is approximately equal to 0.1 kg.

Freefall is a type of motion in which an object falls with gravitational acceleration without resistance from air, surface, or medium. In a freefall, the only force acting on an object is the force of gravity. In a freefall, the acceleration of an object is given by the formula:  `g = 9.81 \(m/s^2`\)

The final velocity of a freefalling object can be calculated using the formula: `v = g*t `Where v is the final velocity, g is the gravitational acceleration, and t is the time taken to reach the final velocity. The force acting on an object is equal to the product of the mass of the object and the acceleration acting on the object. This is known as Newton's Second Law of Motion.

The formula for calculating force is:  `F = ma`.Where F is the force acting on the object, m is the mass of the object, and a is the acceleration acting on the object.Given that the velocity of the metal ball at the moment of striking the ground was 30 m/s, and that it stopped after penetrating the sand for 0.01 s, we can calculate the mass of the metal ball using the formula for force.

We can assume that the force acting on the metal ball is equal to the average resistance force of the sand against the motion of the ball.

The formula for calculating force is: `F = ma`.

Rearranging the formula, we get: `m = F/a` .

Substituting the given values, we get:  `

m = -3010/10`

Thus, the mass of the metal ball is approximately equal to 0.1 kg.

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