The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.
The given parameters;
initial temperature of metals, = \(T_m\)initial temperature of water, = \(T_i\) specific heat capacity of copper, \(C_p\) = 0.385 J/g.Kspecific heat capacity of aluminum, \(C_A\) = 0.9 J/g.Kboth metals have equal mass = mThe quantity of heat transferred by each metal is calculated as follows;
Q = mcΔt
For copper metal, the quantity of heat transferred is calculated as;
\(Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t\)
The change in heat energy for copper metal;
\(\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t\)
For aluminum metal, the quantity of heat transferred is calculated as;
\(Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t\)
The change in heat energy for aluminum metal ;
\(\Delta H = Q_A - Q_i\\\\\Delta H = (Q_i + 0.9m\Delta t) - Q_i\\\\\Delta H = 0.9m\Delta t\)
Thus, we can conclude that the magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.
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What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
Be suspicious of a sales pitch that promises results too good to be true.
Be wary of advisors who sell products.What are some guidelines for preventing quackery and fraud when shopping? Select
all that appy.
Select 4 correct answer(s)
-Be suspicious of a sales pitch that promises results too good to be true.
-Be wary of advisors who sell products. -Don’t do any research before shopping. -Be cautious of mail-order and internet sales. -Be wary of product claims. -If a celebrity or athlete promotes it-it must be good
The steps/guidelines for preventing quackery and fraud when shopping are :
Be suspicious of a sales pitch that promises results too good to be trueBe cautious of mail-order and internet sales Be wary of product claims Be wary of advisors who sell products What is Quackery and FraudQuackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.
Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :
If a sales pitch is too good to be true one should keep off from such product/service.when making internet sales and mail-order customers should be careful as there are a lot of imposters on the internet.Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above
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Which of the following is not a characteristic of electrical potential energy?
Answer:
It is a form of mechanical energy
Explanation:
What can you do to cause acceleration (positive or negative acceleration) in the objects in your table?
Answer: Acceleration is positive when a body speeds up and is negative when the body slows down.
Explanation: please don't hate me this is just my own opinion
How much money would be saved by turning off one 100.0-W lightbulb 3.0 h/day for 365 days if the
cost of electricity is
$0.12 per kWh?
Answer:
the money that would be saved is $13.14.
Explanation:
Given;
power consumed by the light bulb, P = 100 W = 0.1 kW
time of running the bulb, t = 3 hours for 365 days = 1,095 hours
cost rate of power consumption, C = $0.12 per kWh
Energy consumed by the light bulb for the given days;
E = Pt
E = 0.1 kW x 1,095 hr
E = 109.5 kWh
Cost of energy consumed = 109.5 kWh x $0.12 / kWh
= $13.14
Therefore, the money that would be saved is $13.14.
1.A motor is rated at 1.5 hp. At what speed in m/s can this motor raise a
200 kg load?
2. A bucket of water with a total weight of 50 Newtons is lifted at constant
velocity up a 10 meter deep well. If it takes 20 seconds to raise the bucket
this distance, what is the power required to lift the bucket?
Answer:
1. 0.57 m/s
2. 25 Watts
Explanation:
1. Determination of the speed.
We'll begin by converting 1.5 hp to watt (W). This can be obtained as follow:
1 hp = 745.7 W
Therefore,
1.5 hp = 1.5 hp × 745.7 W / 1 hp
1.5 hp = 1118.55 W
Next, we shall determine the force. This can be obtained as follow:
Mass (m) = 200 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = m × g
F = 200 × 9.8
F = 1960 N
Finally, we shall determine the speed. This can be obtained as follow:
Power (P) = 1118.55 W
Force (F) = 1960 N
Speed (v) =?
P = F × v
1118.55 = 1960 × v
Divide both side by 1960
v = 1118.55 / 1960
v = 0.57 m/s
Thus, the speed is 0.57 m/s
2. Determination of the power.
We'll begin by calculating the velocity. This can be obtained as follow:
Displacement = 10 m up
Time = 20 s
Velocity =?
Velocity = Displacement / time
Velocity = 10 / 20
Velocity = 0.5 m/s
Finally, we shall determine the power. This can be obtained as follow:
Velocity (v) = 0.5 m/s
Force (F) = 50 N
Power (P) =?
P = F × v
P = 50 × 0.5
P = 25 Watts
Therefore, the power required to lift the bucket is 25 Watts
How are satellites used in GPS?
to keep the International Space Station in orbit
to communicate with the International Space Station
to communicate with possible extraterrestrial life
to pinpoint specific locations on Earth
Answer:
To pinpoint specific locations on Earth
Explanation:
The satellite has a full specific view of a specific area just like other satellites do. Satellites communicate together which also communicates with your GPS to give you an accurate location where you are or where you want to be. That is how satellites are used in GPS.
Hope this helps you out :)
Read the quotation from "Some Keep the Sabbath Going to Church
And instead of tolling the Bell, for Church,
Our little Sexton - sings.
What is the most likely reason for the poet to oppose the phrases "tolling the Bell" and "sings" in these lines?
The poet is expressing her belief that the second, more natural option is far more desirable than the first option.
The poet is hinting that religious worship should be considered a gloomy and serious activity
The poet is suggesting that those who worship in nature are more formal than those who worship in church.
The poet is contrasting her attitude about religion with her feelint about the natural world, which remains largely
unappreciated
Answer: the poet is expressing her belief that the second, more natural option is far more desirable than the first option
Explanation:
Answer:
a-The poet is expressing her belief that the second, more natural option is far more desirable than the first option.
Explanation:
How were the barriers to critical thinking presented?
Answer:
At a personal level, barriers to critical thinking can arise through: ... self-centred or societal/cultural-centred thinking (conformism, dogma and peer-pressure) unconscious bias, or selective perception. an inability to be receptive to an idea or point of view that differs from your own (close-mindedness)
Explanation:
Acceleration refers to any changes in
Answer:
speed
Explanation:
Which statement correctly describes a property of sound waves?
They have two kinds of movement.
They can travel through outer space.
They are generated by movements in Earth’s crust.
They require particles to transfer energy.
The statement that correctly describes a property of sound waves is that they require particles to transfer energy.
The correct option is D.
What are sound waves?A sound wave is a pattern of disturbance that occurs as a result of the movement of energy moving through a medium as it propagates away from the source of the sound (such as air, water, or any other liquid or solid matter).
Pressure waves are produced when an object vibrates, such as a ringing phone, and these waves are known as sound waves.
Sound waves are mechanical waves and require a material medium for their propagation.
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Pulsed dye lasers emit light of wavelength 585 nm in 0.45 ms pulses to remove skin blemishes such as birthmarks. The beam is usually focused onto a circular spot 5.0 mm in diameter. Suppose that the output of one such laser is 20.0 W. (a) What is the energy of each photon, in eV? (b) How many photons per square millimeter are delivered to the blemish during each pulse?
The solution posted in the textbook problem in part (b) converts 20 Watts to 20*10^-3 J/s but I am not understanding why. I also am uncertain as to why they change the answer in a from 3.39 * 10^-19 to 0.0339 * 10^-17? Is this necessary?
(a) The energy of photon in each eV is 2.12 eV
(b) 1.35 x 10^15 photons/mm^2 are delivered to the blemish during each pulse.
(a) To find the energy of each photon in eV, we can use the formula E = (hc) / λ, where E is the energy, h is Planck's constant (6.626 x 10^-34 Js), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength. We need to convert the energy to electron volts (eV), so we'll use the conversion factor of 1 eV = 1.6 x 10^-19 J.
E = (6.626 x 10^-34 Js * 3 x 10^8 m/s) / (585 x 10^-9 m) = 3.39 x 10^-19 J
Now, convert to eV:
E = 3.39 x 10^-19 J * (1 eV / 1.6 x 10^-19 J) = 2.12 eV
(b) To find the number of photons per square millimeter, we first need to find the total energy delivered in each pulse. We have the power output (20 W) and the pulse duration (0.45 ms).
Total energy = power * pulse duration = 20 W * 0.45 x 10^-3 s = 9 x 10^-3 J
Now, divide the total energy by the energy of a single photon:
Number of photons = (9 x 10^-3 J) / (3.39 x 10^-19 J/photon) = 2.65 x 10^16 photons
Next, find the area of the circular spot:
Area = π * (diameter / 2)^2 = π * (5 x 10^-3 m / 2)^2 = 1.96 x 10^-5 m^2
Now, convert the area to square millimeters:
Area = 1.96 x 10^-5 m^2 * (1000 mm / 1 m)^2 = 19.6 mm^2
Finally, divide the number of photons by the area to get the number of photons per square millimeter:
Photons per square millimeter = (2.65 x 10^16 photons) / (19.6 mm^2) = 1.35 x 10^15 photons/mm^2
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If the error in the angle is 0.50, the error in sin 90o is
At the given erro in angle, the error in the measurement of sin 90 degrees would be 0.001.
Percentage errorThe percentage error of any measurement is obtained from the ratio of the error to the actual measurement.
The error of sin 90 degrees is calculated as follows;
sin 90 = 1
error in measurement = sin(90 - 0.5)
error in measurement = sin(89.5) = 0.999
Error in sin 90 degreesError in sin 90 degrees = 1 - 0.999
Error in sin 90 degrees = 0.001
Thus, at the given erro in angle, the error in sin 90 degrees would be 0.001.
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A 1.40-kg block is on a frictionless, 30 ∘ inclined plane. The block is attached to a spring (k = 40.0 N/m ) that is fixed to a wall at the bottom of the incline. A light string attached to the block runs over a frictionless pulley to a 60.0-g suspended mass. The suspended mass is given an initial downward speed of 1.60 m/s .
How far does it drop before coming to rest? (Assume the spring is unlimited in how far it can stretch.)
Express your answer using two significant figures.
Answer:
0.5
Explanation:
because the block is attached to the pulley of the string
Potential energy is
OA. energy of moving charges
OB. energy of motion
O C. nuclear energy
D.
energy of position or location
Explanation:
potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.
Hopefully this helps! :)
If a small motor does 200 J of work to move a toy car 40 m, what force does it exert?
The force exerted during a work of 200 J done to move a toy car 40 m is 5 N
W = F * d
W = Work done
F = Force
d = Distance
W = 200 J
d = 40 m
F = W / d
F = 200 / 40
F = 5 N
The force exerted to move an object is work done. It is denoted as W. Its unit is Joules.
Therefore, the force exerted is 5 N
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Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.
Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.
The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.
These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.
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What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
The Taipei Tower is a 508 meter, 101 story skyscraper. If you were to toss a orange of 0.13 kg off the top, how much kinetic energy would it have when it hits the sidewalk? Ignore air resistance .
Answer:
647.19 J
Explanation:
By the conservation of energy, the potential energy when you toss the orange is converted to kinetic energy when it hits the sidewalk, so
Ef = Ei
KE = PE
KE = mgh
Where m is the mass, g is 9.8 m/s², and h is the height of the Tower. Replacing m by 0.13 kg and h by 508 meters, we get
KE = (0.13kg)(9.8 m/s²)(508 m)
KE = 647.19 J
So, the orange would have 647.19 J of kinetic energy when it hits the sidewalk.
100 POINTS AND BRAINLIST FOR BEST ANSWER!
Please help me i have a 77% in science and i need to bring it up today bc its the end of grades today. If you help me you are seriously the best person in the world, theres 4 questions.
Answer:
Air moves from regions of high pressure to regions of low pressure.
Explanation:
When airs moves horizontally from regions of high pressure to low pressure, it creates wind. If the difference between high and low pressure is greater, then it makes the wind faster.
Best of Luck!
Answer:
C. Air moves from regions of high pressure to regions of low pressure.
Explanation:
The air from the regions of high pressure will hold onto that pressure. So, when it moves into the regions with low pressure it'll turn into wind.
The greater the pressure, the stronger the wind and vise versa.
Hope this helps!
what is a everyday activities examples of newtons 1 law of motion
Answer:
bouncing a baskletball
Explanation:
Answer:someone kicking a soccer ball.
Explanation:
Because the ball isn’t in motion until acted on by another object (the foot)
please help me, i need to show my work but im dont know how
Three people are in an elevator, The people have a total 185 kg. The elevator has a mass of 250 kg. When the evelavtor begins to move the elevator and the people accelerate upward with a acceleration of 1.50 m/s ^ 2 What the net force?
The net force will be equal to 4915.5 N when the elevator accelerates upward with an acceleration of 1.50 m/s².
What is tension?Tension can be described as a force along the length of a flexible medium such as a cable, rope, etc. Tension is a pulling force but it can not be a pushing force.
When the elevator moves upward with acceleration (a). The net force will be equal to:
Fₙ = mg + ma
Where m is the mass of the object and 'g' is the gravitational acceleration.
Given the total mass of three people = 185 Kg
The mass of the elevator = 250 Kg
Then the total mass, m = 185 + 250 = 435 Kg
The acceleration of the elevator, a = 1.50 m/s²
The net force of the elevator will be: F = 435 × 9.8 + 435 × 1.50
F = 4915.5 N
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How do your results from ray tracing compare to your results from using the thin-lens equation?
What is the focal length of a convex lens that produces an image 10 cm away with a magnification of -0.5? Show all calculations in your answer.
Hint: Use the definition of magnification and the thin-lens equation.
Answer:
20cm
Explanation:
A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image (image distance can be negative or positive depending on the nature of the image).
According to the lens equation
\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\) where;
f is the focal length of the lens
u is the object distance
v is the image distance
If the magnification is - 0.6
mag = v/u = -0.5
v = -0.5u
since v = 10cm
10 = -0.5u
u = -10/0.5
u =-20 cm
Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f
\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm\)
Hence the focal length of the convex lens is 20cm
Pls helppp
Bumper car A (281 kg) moving +2.82 m/s
makes an elastic collision with bumper
car B (265 kg) moving -1.72 m/s. What is
the velocity of car A after the collision?
V
(Unit = m/s)
Remember: right is +, left is -
Enter
Explanation: For some reason, it would not let me click the "ADD YOUR ANWER" button, because it stated that my answer had some sort of "Inappropriate" word or something, so instead I attached two images of the answer that I had written down.
Example 2.13 The acceleration a of a particle in a time t is given by the equation a = 2+ 5t^2. Find the instantaneous velocity after 3s. Solution
Answer:
the instantaneous velocity is 51 m/s
Explanation:
Given;
acceleration, a = 2 + 5t²
Acceleration is the change in velocity with time.
\(a = \frac{dv}{dt} \\\\a = 2 + 5t^2\\\\The \ acceleration \ (a) \ is \ given \ so \ we \ have \ to \ find \ the \ velocity \ (v)\\\\To \ find \ the \ velocity, \ integrate\ both \ sides \ of \ the \ equation\\\\2 + 5t^2 = \frac{dv}{dt} \\\\\int\limits^3_0 {(2 + 5t^2)} \, dt = dv\\\\v = [2t + \frac{5t^3}{3} ]^3_0\\\\v = 2(3) + \frac{5(3)^3}{3} \\\\v = 6 + 5(3)^2\\\\v = 6 + 45\\\\v = 51 \ m/s\)
Therefore, the instantaneous velocity is 51 m/s
If the moon crossed the meridian at midnight what phase must the moon be in?
Answer:
Waxing Gibbous
Explanation:
New Moon Rises at sunrise, transits meridian at noon, sets at sunset
Explanation:
A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.
Answer:
a) P = 70054.3 W, b) P = 18820 W, c) P = 14116.7 W
Explanation:
Power is defined as work per unit of time
P = W / t = F x / t
P = F v
a) in this case the velocity is constant, let's use the equilibrium relation to find the force.
Let's set a reference system with the x axis parallel to the plane
F - Wₓ = 0
F = Wₓ
with trigonometry let's decompose the weight
sin θ = Wₓ / W
Wₓ = W sin θ
F = W sin 15
F = 2800 sin 15
F = 724.7 lb
we look for the speed, as it rises with constant speed we can use the relations of uniform motion
v = x / t
v = 1160/12
v = 96.67 ft / s
we calculate the power
P = 724.7 96.67
P = 70054.3 W
b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy
W = ΔK
W = ½ m v_f² - ½ m v₀²
let's reduce to the SI system
v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s
v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s
mass : m = w / g
W = ½ 2800/32 (73.33² - 14.67²)
W = 225841 J
we calculate the average power
P = W / t
P = 225841/12
P = 18820 W
c) we repeat the previous procedure
v₀ = 45 mph = 66 ft / s
v_f = 15 mph = 22 ft / s
W = ½ 2800/32 (22² - 66²)
W = -169400 J
P = W / t
P = 169400/12
P = 14116.7 W
What can result if. An earthquake cause sudden vertical change in the sea floor?
Answer:
A Tsunami would occur.