for each pair of functions, decide which one is taller.​

Answer:

y= -2x- \(\frac{2}{3}\)

Step-by-step explanation:

3y+2=-6x

3y=-6x-2

y= \(\frac{-6}{3}\)x - \(\frac{2}{3}\)

y= -2x - \(\frac{2}{3}\)

You isolate for y in this example by moving the 2 to the other side and then dividing the -6x and -2 by 3 to get the y by itself.

To determine the amount of wrapping paper needed to wrap a cylindrical gift with a diameter of 8 meters and a height three times the radius, we need to find the surface area of the cylinder.

The diameter is 8 meters, so the radius (r) is half of that, which is 4 meters. The height (h) is three times the radius, so it is 3 * 4 = 12 meters.

The surface area of a cylinder is given by the formula: A = 2πr(h + r)

Plugging in the values, we get: A = 2 * π * 4 * (12 + 4) = 2 * π * 4 * 16 = 128π square meters.

So, it would take approximately 128π square meters of wrapping paper to wrap the cylindrical gift.

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The solution to Laplace's equation with the given boundary conditions is: u(x,y) = (f(y)/2)x + (1/π)∑[n=1 to ∞] [(f(y)-f(0))(1-cos(nπx/2))/\(n^2\)cos(nπ/2)]

The Laplace's equation uxx + uyy = 0 is a partial differential equation that describes a steady-state temperature distribution or electrostatic potential in a 2D region. The given boundary conditions specify that u(0,y) = 0 and u(2,y) = f(y), where f(y) is a given function. These conditions indicate that the solution is a function of x and y, and that the value of u is fixed on the boundaries.

To find the solution, we use separation of variables and assume that u(x,y) = X(x)Y(y). This leads to the equation X''/X = -Y''/Y = λ, where λ is a constant. The boundary conditions imply that X(0) = 0 and X(2) = 1, and the general solution is X(x) = (1/π)∑[n=1 to ∞] \(sin(nx\pi /2)cos(n\pi /2)ex^{-n^{2}\pi ^{2}y/4 }\)).To determine Y(y), we use the boundary condition u(2,y) = f(y), which gives Y(y) = f(y)/(2X(2)). Substituting X(x) and Y(y) into the general solution for u(x,y), we obtain:

u(x,y) = (f(y)/2)x + (1/π)∑[n=1 to ∞] [(f(y)-f(0))(1-cos(nπx/2))/\(n^2\)cos(nπ/2)]

This is the final solution to Laplace's equation with the given boundary conditions. It describes the temperature or potential distribution in the 2D region, and depends on the function f(y) and the Fourier series coefficients of X(x). The solution satisfies the Laplace's equation and the boundary conditions, and is unique up to a constant.

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Answer:

The fourth answer choice: 10 + 1.50n < 50

I would appreciate Brainliest but no worries.

so,  -11-\(\sqrt{2}\)i and 3 + 4i are roots of polynomial function f(x) so 11 + \(\sqrt{2}\)i and

3 - 4i are roots of f(x)  

Therefore, option D is correct

Polynomial function:

A polynomial function, in general, is also stated as a polynomial or polynomial expression, defined by its degree. The degree of any polynomial is the highest power present in it.

given that

Patricia is studying a polynomial function f(x). three given roots of f(x) are

-11-\(\sqrt{2}\)i , 3 + 4i and 10 . Patricia concludes that f(x) must be a polynomial with degree 4.

so -11-\(\sqrt{2}\)i and 3 + 4i are roots of polynomial function f(x) so 11 + \(\sqrt{2}\)i and

3 - 4i are roots of f(x)  

Therefore, option D is correct

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Solution

The question would like us to evaluate the following expression

- We should deal with the modulus and bracket separately.

- After that, we can then perform the subtraction operation on the results of the modulus and bracket.

- This is done below:

Also,

Thus, combining both results, we have:

Final Answer

The answer is -6

Answer:

-6 hope it helps

thank you

The surface area of the rectangular prism is 88 square inches.

Given that:

Length, L = 6 inches

Width, W = 2 inches

Height, H = 4 inches

Let the prism with a length of L, a width of W, and a height of H. Then the surface area of the prism is given as

SA = 2(LW + WH + HL)

SA = 2(6 x 2 + 2 x 4 + 4 x 6)

SA = 2 (12 + 8 + 24)

SA = 2 x 44

SA = 88 square inches

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Answer:

.309

.34

.4

.46

.97

.98

Step-by-step explanation:

Hope this helped. Do not be shy to give Brainlist.

Answer:

0.4, 0.309, 0.34, 0.46, 0.97, 0.98

Step-by-step explanation:

Therefore, the gradient field is: ∇g(x,y,z) = ⟨ -2x/(x^2+y^2), -2y/(x^2+y^2), e^z ⟩.

The gradient of the function g(x,y,z)=ez−ln(x2+y2) is given by:

∇g(x,y,z) = ⟨ ∂g/∂x, ∂g/∂y, ∂g/∂z ⟩

Taking partial derivatives:

∂g/∂x = -2x/(x^2+y^2)

∂g/∂y = -2y/(x^2+y^2)

∂g/∂z = e^z

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Answer:

3

Step-by-step explanation:

The 3 is in the tens place representing the number 30.

~theLocoCoco

Answer:

The answer is C.

There is a horizontal line test but the question asks to use the vertical line test. Using the horizontal line test you would get that the function is not one to one but using the vertical line test you would get its one to one.

The probability that a sample of 130 steady smokers spend between $19 and $21 by using normal probability distribution is 0.897.

The probability distribution that would be symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean.

The formula for normal probability distribution is-

z = (x - μ)/σ

where is the z is the standard normal variate or z-score.

x is the range of the values. ( = 19 to 21)

μ is the mean. (=20)

σ is the standard deviation. (=7)

n is sample size = 130

How likely it is that a sample of 130 regular smokers will spend within $19 and $21?

This is the result of subtracting the pvalue of Z when X = 19 from of the p-value for Z when X = 21.

By central limit theorem;

s = σ/√n

s = 7/√130

s = 0.61

So,

When x = 21

z = (21 - 20)/0.61

z = 1.63  ( p-value of 0.948 taken from z-table)

when x = 19

z = (19 - 20)/ 0.61

z = -1.63 ( p-value of 0.051 taken from z-table)

The probability is 0.948 -  0.051

Probability = 0.897

Therefore, the probability that a sample of 130 steady smokers spend between $19 and $21 is 0.897.

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Answer: X- 4y - 12=0

step by step explanation:

First, move the constant to the left by adding its opposite to both sides

x-4y -12 = 12-12 =

X-4y-12 =  0

So the answer is X- 4y - 12=0

A and B are two events for which P(A)=0.28,P(B)=0.63, and P(B∣A)=0.47. a) The probability of both events A and B occurring (A∩B) is 0.1316. b) The probability of either event A or event B occurring (A∪B) is 0.7784. c) The conditional probability of event A occurring given that event B has occurred (A∣B) is approximately 0.2092.

a) To find P(A∩B), we can use the formula P(A∩B) = P(B∣A) * P(A). Given that P(B∣A) = 0.47 and P(A) = 0.28, we can calculate:

P(A∩B) = 0.47 * 0.28 = 0.1316

b) To find P(A∪B), we can use the formula P(A∪B) = P(A) + P(B) - P(A∩B). Given that P(A) = 0.28, P(B) = 0.63, and we just calculated P(A∩B) = 0.1316, we can substitute these values into the formula:

P(A∪B) = 0.28 + 0.63 - 0.1316 = 0.7784

c) To find P(A∣B), we can use the formula P(A∣B) = P(A∩B) / P(B). Given that we know P(A∩B) = 0.1316 and P(B) = 0.63, we can substitute these values into the formula:

P(A∣B) = 0.1316 / 0.63 ≈ 0.2092

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Answer:

B. 2.2π m² : 3.2π m²

Step-by-step explanation:

Given:

Slant height (l) = 2.2 m

Diameter (d) = 2 m

Radius (r) = ½(2) = 1 m

Required:

Lateral area and surface area

Solution:

✔️Formula for lateral area of a cone = πrl

Plug in the values

Lateral area of the cone = π*1*2.2

Lateral area = 2.2π m²

✔️ Formula for surface area of a cone = πr(l + r)

Plug in the values

Surface area of the cone = π*1(2.2 + 1)

Surface area = π(3.2)

Surface area = 3.2π m²

The answer would therefore be:

2.2π m² : 3.2π m²

Answer:

i didnt understand can you plz explain

After solving the system of equations using Gaussian elimination we get the values as x = 5 , y = -11 and z=3

Given we have the system of equations as follows:

2x - y + 4z = 33

x + 2y - 3z = -26

-5 x - 3y +5z = 23

Rewrite the system in matrix form and solve it by Gaussian elimination.

[ 2  -1  4     [ 33

 1  2  -3   =  -26

-5  -3  5 ]      23 ]

Now divide row 1 by row 2.

[ 1  -0.5  2        [ 16.5

 1     2   -3    =  -26

-5    -3  5 ]         23 ]

Now R₂ - 1R₁ → R₂

and R₃ + 5R₁ → R₃

[ 1  -0.5  2        [ 16.5

 0   2.5  -5    =  -42.5

 0  -5.5 15 ]       105.5 ]

Divide row 2 by 2.5.

[ 1  -0.5  2        [ 16.5

 0     1   -2    =  -17

 0  -5.5 15 ]       105.5]

R₁+0.5R₂ → R₁

R₃ + 5.5R₂ → R₃

[ 1   0  1          [ 8

 0   1   -2    =  -17

 0    0   4 ]        12 ]

Divide R₃ by 4

[ 1   0  1          [ 8

 0   1   -2    =  -17

 0    0   1 ]         3 ]

Therefore, R₁-1R₃→R₁

R₂ + 2R₃ → R₂

[ 1   0  1          [ 5

 0   1   0    =    -11

 0    0   1 ]        3 ]

therefore x = 5, y=-11 and z = 3.

Hence we solved the system of equations using Gaussian elimination.

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Answer:4/15

Step-by-step explanation:

Let the total pocket money be 1 (since she spent fractions of her money)

Total spent = 3/5 + 2/15 = 11/15

Thus, fraction of money left = 1-(11/15)= 4/15.

Hope this helps! :)

If the cost of advertising was $100,000 and the reach or circulation was 10,000,000 people, then the CPM is $10.

Cost per thousand (CPM), which is also called cost per mille, is a marketing word used to denote the price of 1,000 advertisement prints on one web page. If a publisher of a website charges $2.00 CPM, that means an advertiser must pay $2.00 for every 1,000 prints of its ad.

The CPM is calculated by dividing the cost of the advertisement by the number of people reached and then multiplying by 1000.

Given that the cost of advertising was $100,000 and the reach was 10,000,000 people, the CPM can be calculated as follows:

CPM = ($100,000 / 10,000,000) × 1000 = $10.

So, the CPM is $10.

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The random variable x has a normal distribution with standard deviation. It is known that the probability that x exceeds is. 90. Therefore, mean  of the probability distribution is 133.09.

We are given that the random variable x has a normal distribution with standard deviation 21,i.e;

X ~ N( u, σ=21)

The Z probability is given by;

             Z = X- u/σ ~ (0,1)

Also, it is known that the probability that x exceeds 160 is 0.90 ,i.e;

P(X > 160) = 0.90

P( X-u/σ > 160-u /21  ) = 0.90

From the z% table we find that at value of x = -1.2816, the value of

P(X > 160) is 90%

which means;   160-u /21   = -1.2816

                          160 -  = 21*(-1.2816)

                             = 160 - 26.914 = 133.09

Therefore, mean  of the probability distribution is 133.09.

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The sample that is most likely to yield a representative sample for the poll is "twenty names from each grade pulled blindly from a container filled with the names of the entire student body written on slips of paper."

A representative sample is one that accurately reflects the characteristics of the population from which it is drawn. In this case, Miranda wants to determine how many students would attend a students-only school dance. To achieve this, she needs a sample that represents the entire student body.

The option of selecting twenty names from each grade ensures that the sample includes students from all grades, which is important to capture the diversity of the student body.

By pulling the names blindly from a container filled with the names of the entire student body, the selection process is unbiased and random, minimizing any potential biases that could arise from alternative methods.

The other options have certain limitations that may result in a non-representative sample. For example, selecting every tenth person walking down Main Street may introduce a bias towards students who live or frequent that particular area.

Students who write into the school newspaper may have different interests or characteristics compared to the general student body, leading to a biased sample. Similarly, selecting all the students from Miranda's classes would not represent the entire student body, as it would only include students from those specific classes.

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Applying the definition of midpoint, the measure of angle GIH in the triangle shown is: 59°.

The corresponding angles of two similar triangles are always congruent to each other.

Given that H is the midpoint of Eg and I is the midpoint of FG, two similar triangles are created, where angles GFE and GIH are corresponding angles.

Given:

m∠GFE = 87 - 7x

m∠GIH = 51 + 2x

m∠GFE = m∠GIH [corresponding angles are congruent]

Substitute

87 - 7x = 51 + 2x

Solve for x

-2x - 7x = 51 - 87

-9x = -36

Divide both sides by -9:

-9x/-9 = -36/-9

x = 4

m∠GIH = 51 + 2x = 51 + 2(4)

m∠GIH = 59°

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The function which represents a quadratic function is f(x) = three-quarters x^2 + 2x - 5 as it has a degree of 2 which is highest exponent.  The correct answer is A).

The quadratic function is f(x) = three-quarters x^2 + 2x - 5.

We can identify a quadratic function by its degree, which is 2. The degree of a polynomial is the highest exponent in the expression.

In the given options, f(x) = three-quarters x^2 + 2x - 5 has a degree of 2, with the x^2 term being the highest exponent. The other options have either a degree of 3 (f(x) = -8x^3 - 16x^2 - 4x) or 0 (f(x) = 0x^2 - 9x + 7), or are not even functions (f(x) = 4/x^2 - 2/x + 1). so, the correct option is A).

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Answer:

100

Step-by-step explanation:

Answer:

23.39

Step-by-step explanation:

To calculate the percentage of underclassmen interested in taking a Mandarin course next year, find the marginal frequency for the total number of underclassmen who showed interest in Mandarin. There are 145 underclassmen who showed interest in Mandarin courses.

Find the total number of underclassmen who were polled. This number is located at the intersection of the marginal frequency row and marginal frequency column. There are 620 underclassmen who were polled in the survey.

Calculate the approximate percentage of underclassmen interested in taking a Mandarin course next year.

I took the test and got it right trust me.

In this game, the pure best response equilibria (BNE) are when Anna bids 200 and Brian bids 100, or when Anna bids 100 and Brian bids 200. These equilibria occur because both players are playing their best response to the other player's strategy, resulting in a Nash equilibrium.

(a) The normal form of the game can be represented in a payoff matrix where the rows represent Anna's strategies (bids) and the columns represent Brian's strategies (bids):

scss

Copy code

            Brian

         |   100   |   200   |

-------------------------------

 100 |  (300, 0) | (300, 0) |

-------------------------------

 200 | (0, 100)  | (0, 200) |

-------------------------------

In each cell, the first number represents Anna's payoff, and the second number represents Brian's payoff.

(b) To find all pure best response equilibria (BNE), we need to examine each player's strategy and determine if they have a best response to the other player's strategy.

For Anna:

If Brian bids 100, Anna's best response is to bid 200, as this guarantees a higher payoff of 300.

If Brian bids 200, Anna's best response is to bid 100, as this guarantees a higher payoff of 300.

For Brian:

If Anna bids 100, Brian's best response is to bid 200, as this guarantees a higher payoff of 0.

If Anna bids 200, Brian's best response is to bid 100, as this guarantees a higher payoff of 0.

Therefore, the pure best response equilibria (BNE) of this game are:

(Anna: 200, Brian: 100)

(Anna: 100, Brian: 200)

In both cases, both players are playing their best response to the other player's strategy, resulting in a Nash equilibrium.

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