The value of c is 0.9, rounded to 2 decimal places. This is found by looking up the probability 0.8402 in the standard normal table.
A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. The standard normal table shows the probability that a standard normal variable will be less than a certain value. To find the value of c, we can look up the probability 0.8402 in the standard normal table. The table shows that the probability is 0.8402. This means that 84.02% of the values in a standard normal distribution will be less than c.
To find the actual value of c, we can round the probability to 0.9:
c = 1 - 0.1598 = 0.8402
This means that c is the value that 84.02% of the values in a standard normal distribution will be less than.
Rounded to 2 decimal places, the value of c is 0.9.
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Which of the following equations shows how substitution can be used to solve
the following system of equations?
Answer: Choice B)
2x+5(2x+3) = 3
============================================
Reasoning:
We start with the second equation 2x+5y = 3
Since y = 2x+3 from the first equation, we can replace every copy of y with (2x+3). This replacement is valid because y and 2x+3 are the same.
So that's how we go from 2x+5y = 3 to 2x+5(2x+3) = 3
This replacement is done to get rid of the y variable, and it allows us to solve for x later on.
ravelocity would like to test if the average roundtrip airfare between new york and london differs from $1,400. the correct hypothesis statement for this test would be
The "hypothesis of no change," "status quo," and "conventional wisdom" are all alternative names for the null hypothesis. Unless there is overwhelming evidence to the contrary, the null hypothesis is assumed to be correct.
H0: u = 1: u ≠ 1,400
When testing hypotheses with the P value, the null hypothesis is rejected if?
The evidence against the null hypothesis is stronger when the p-value is smaller (closer to 0).If the p-esteem is not exactly or equivalent to the predetermined importance level α, the invalid speculation is dismissed;The null hypothesis is not rejected otherwise.
A statement of expectation or prediction that will be tested by research is called a research hypothesis. Read up on the subject that interests you before coming up with your research hypothesis.
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What is the multiplicative rate of change for the exponential function f(x)= 3 (2/3)^-x
A. 0.4
B. 2.5
C. 0.6
D. 1.5
Answer:
C basta Yan ang sagot HAHAHA dko mapicturan solution ko e
Step-by-step explanation:
ano ba yan arte nyo sabing yan ang sagot eAnswer:
c 0.6
Step-by-step explanation:
lol
Solve the simultaneous equation.
7a+3b=46
4a+5b=69
Answer:
a=1 and b=13
do you need the working out?
Does anyone know what this could be ??
Answer:
The answer is f(-3)= -2(-3)+4
Step-by-step explanation:
you just switch x with -3 because you know the unknown variable now.
1. Let x ∈ Z. Prove that if 3 | 2x, then 3 | x.2. Let n ∈ Z. Prove that 3 | (2n 2 + 1) if and only if 3 - n.
Answer:
1.Suppose 3 | 2x. Then we can write 2x = 3k for some integer k. Rearranging, we have x = (3/2)k. Since k is an integer, (3/2)k is also an integer, which means that x is divisible by 3. Hence, 3 | x.
First, suppose 3 | (2n^2 + 1). Then we can write 2n^2 + 1 = 3k for some integer k. Rearranging, we have 2n^2 = 3k - 1. Since 3k - 1 is odd, we can write it as 2m + 1 for some integer m. Substituting, we have 2n^2 = 2m + 1, which implies that n^2 = m + (1/2). But since m is an integer, (1/2)m is not an integer, which means that n^2 is not an integer. This is a contradiction, so our assumption that 3 | (2n^2 + 1) must be false.
Now suppose 3 - n. Then we can write n = 3k - 1 for some integer k. Substituting, we have 2n^2 + 1 = 18k^2 - 12k + 3. Factoring out 3, we have 2n^2 + 1 = 3(6k^2 - 4k + 1). But 6k^2 - 4k + 1 is always an integer, so if 3 - n, then 3 | (2n^2 + 1).
give me thanks for more! your welcome!
Step-by-step explanation:
what is the drag force on a 1.6 m wide, 1.4 m high car traveling at 10 m/s (≈ 22 mph)?
141.472 N of drag force is applied in 1.6m wide and 1.4m high car travelling at 10m/s
What is drag force?Drag force is the net force in the direction of flow experienced by any item moving through a fluid and is caused by pressure and shear stress forces acting on the surface of the object.
Formula of drag force is given by:
\(F_d = \frac{1}{2}C_dAPv^2\)
where
\(F_d\) = drag force (N)
\(C_d\) = drag coefficient (1.05 for moving car)
P = density of fluid (1.2 kg/m3 for air at NTP)
v = flow velocity (m/s)
A = characteristic frontal area of the body
A = height * width
=> 1.6*1.4
so A=2.24 \(m^2\)
and v=10 m/s
so \(F_d\) = 1/2* 1.05 * 2.24 *( 1.2 *10*10)
=> 0.5*1.05*2.24 *122
=> 143.472 N
so \(F_d\) = 143.472 N
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Required information Problem 1-35A (Algo) Recording events in a horizontal statements model LO 1-3, 1-4, 1-5, 1-6, 1-7, 1-8, 1-9, 1-10 [The following information applies to the questions displayed below.] Maben Company was started on January 1, Year 1, and experienced the following events during its first year of operation: 1. Acquired $38,000 cash from the issue of common stock. 2. Borrowed $32,000 cash from National Bank. 3. Earned cash revenues of $56,000 for performing services. 4. Paid cash expenses of $49,000. 5. Paid a $1,800 cash dividend to the stockholders. 6. Acquired an additional $28,000 cash from the issue of common stock. 7. Paid $8,000 cash to reduce the principal balance of the bank note. 8. Paid $61,000 cash to purchase land. 9. Determined that the market value of the land is $85,000. Problem 1-35A (Algo) Part g g. What is the balance in the Retained Earnings account immediately after Event 3 is recorded? Required information Problem 1-35A (Algo) Recording events in a horizontal statements model LO 1-3, 1-4, 1-5, 1-6, 1-7, 1-8, 1-9, 1-10 [The following information applies to the questions displayed below.] Maben Company was started on January 1, Year 1, and experienced the following events during its first year of operation: 1. Acquired $38,000 cash from the issue of common stock. 2. Borrowed $32,000 cash from National Bank. 3. Earned cash revenues of $56,000 for performing services. 4. Paid cash expenses of $49,000. 5. Paid a $1,800 cash dividend to the stockholders. 6. Acquired an additional $28,000 cash from the issue of common stock. 7. Paid $8,000 cash to reduce the principal balance of the bank note. 8. Paid $61,000 cash to purchase land. 9. Determined that the market value of the land is $85,000. Problem 1-35A (Algo) Part c c. Identify the asset source transactions and related amounts for Year 1.
In Year 1, Maben Company had several asset source transactions that increased the company's assets.
Asset source transactions refer to events or activities that result in an increase in a company's assets. In the given information for Maben Company, the following events can be identified as asset source transactions:
1. Acquired $38,000 cash from the issue of common stock: This transaction involves the issuance of common stock, which increases the company's cash balance.
2. Borrowed $32,000 cash from National Bank: This transaction involves obtaining a loan from the bank, resulting in an increase in the company's cash balance.
3. Earned cash revenues of $56,000 for performing services: This transaction represents the company's primary operations, where it generated revenue in exchange for services rendered. The revenue earned increases the company's cash balance.
6. Acquired an additional $28,000 cash from the issue of common stock: Similar to the first transaction, this event involves issuing common stock and receiving cash, leading to an increase in the company's cash balance.
The total amount of cash acquired through these asset source transactions can be calculated by summing the cash amounts from each transaction: $38,000 + $32,000 + $56,000 + $28,000 = $154,000.
In summary, the asset source transactions in Year 1 of Maben Company involve acquiring cash through the issuance of common stock, borrowing from a bank, and generating cash revenues from services rendered. These transactions resulted in a total cash inflow of $154,000.
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Pentagon TEXAS has vertices at T(1, 8), E(3, 8), X(6, 2), A(3, 2), and S(1, 4). What is the area of Pentagon TEXAS?
341.5 square units
18.5 square units
17 square units
19 square units
The area of the pentagon is 19 square units
The coordinates of the pentagon are given as:
\(T = (1, 8)\)
\(E =(3, 8)\)
\(X =(6, 2)\)
\(A=(3, 2)\)
\(S = (1, 4)\)
The area of the pentagon is then calculated using:
\(Area = \frac 12|(x_1y_2+x_2y_3+x_3y_4+x_4y_5+x_5y_1) -(y_1x_2+y_2x_3+y_3x_4+y_4x_5+y_5x_1)|\)
So, we have:
\(Area = \frac 12|(1 \times 8 +3 \times 2+6\times2+3 \times 4 + 1 \times 8) -(8\times3+8\times6+2\times3+2\times1+4\times1)|\)
Simplify the expressions in both brackets
\(Area = \frac 12|46 -84|\)
\(Area = \frac 12|-38|\)
Remove absolute bracket
\(Area = \frac 12 \times 38\)
\(Area = 19\)
Hence, the area of the pentagon is 19 square units
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You have
$
5.00
$5.00 and you need to make copies of a flyer at a store that charges
$
0.15
$0.15 per copy. Find the inequality that represents the number of copies you can make. Use
�
x as the variable.
-
What is the maximum number of copies you can afford to make?
The inequality is 0.15x ≤ 5.00. If copies of a flyer at a store that charges $0.15 per copy, the maximum number of copies you can afford to make is 33.
The inequality that represents the number of copies you can make is:
0.15x ≤ 5.00
Here, x represents the number of copies you can make, and 0.15 is the cost per copy in dollars. The inequality states that the total cost of copies must be less than or equal to the amount of money you have.
To find the maximum number of copies you can afford to make, we need to solve for x:
0.15x ≤ 5.00
x ≤ 5.00/0.15
x ≤ 33.33
Since you cannot make a fraction of a copy, the actual number of copies you can make is 33 or less.
In conclusion, the inequality that represents the number of copies you can make is 0.15x ≤ 5.00, and the maximum number of copies you can afford to make is 33.
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You have $5.00 and you need to make copies of a flyer at a store that charges $0.15 per copy. Find the inequality that represents the number of copies you can make. Use x as the variable. What is the maximum number of copies you can afford to make?
Your hospital has just reset the safety stock level for sleeping pills to be 220 pills.
If your hospital consumes an average of 1,155 per day with a standard deviation of 81 pills, what is the chance that your hospital will run out of sleeping pills on any day? (Keep four decimal places in your answer, which should be a number not a percentage)
The chance that the hospital will run out of sleeping pills on any given day is 0.5000 (or 0.5000 with four decimal places).
To calculate the chance that the hospital will run out of sleeping pills on any given day, we can use the normal distribution and Z-score.
First, let's calculate the Z-score using the formula:
Z = (X - μ) / σ
Where:
X = consumption rate per day (1,155 pills)
μ = average consumption rate per day (1,155 pills)
σ = standard deviation (81 pills)
Z = (1,155 - 1,155) / 81
Z = 0
Now, we need to find the probability associated with this Z-score. However, since the demand for sleeping pills can be considered continuous and not discrete, we need to calculate the area under the curve from negative infinity up to the Z-score. This represents the probability of not running out of sleeping pills.
We discover that the region to the left of a Z-score of 0 is 0.5000 using a basic normal distribution table or statistical software.
To find the probability of running out of sleeping pills, we subtract this probability from 1:
Probability of running out of sleeping pills = 1 - 0.5000
Probability of running out of sleeping pills = 0.5000
Therefore, on any given day, the hospital has a 0.5000 (or 0.5000 with four decimal places) chance of running out of sleeping tablets.
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Can anyone help me with this?
Answer:
a. x=4 or x=−10
b. x= 3/2 or x= −8
Step-by-step explanation:
(FOR LETTER A)
Step 1: Factor left side of equation.
(x−4)(x+10)=0
Step 2: Set factors equal to 0.
x−4=0 or x+10=0
x=4 or x=−10
(FOR LETTER B)
Step 1: Factor left side of equation.
(2x−3)(x+8)=0
Step 2: Set factors equal to 0.
2x−3=0 or x+8=0
x= 3/2
or x= −8
A nurse provides a back massage as a palliative care measure to a client who is unconscious, grimacing, and restless. Which of the following findings should the nurse identify as indicating a therapeutic response? (Select all that apply.)
A. the shoulders droop
B. the facial muscles relax
C. the RR increases
D. the pulse is within the expected range
E. the client draws his legs into a fetal position
A nurse provides a back massage as a palliative care measure to a client who is unconscious, grimacing, and restless.
The therapeutic response that the nurse should identify in the client after a back massage includes relaxing of facial muscles and the pulse remaining within the expected range.
Massage is a fundamental nursing measure that is often utilized as part of palliative care for patients. The purpose of back massage is to promote relaxation, improve blood circulation, reduce muscle tension, and alleviate pain, stress, and anxiety. The nursing assessment of the patient before and after the massage is essential to determine its effectiveness as a therapeutic intervention for the patient.
When providing back massage as a palliative care measure to an unconscious, grimacing, and restless client, the nurse should identify several therapeutic responses as follows;
The shoulders droop: The nurse should expect the shoulders of the client to relax during massage therapy. If this occurs, it is a sign that the patient is experiencing relaxation and tension relief.
The facial muscles relax: Relaxation of the facial muscles is a common therapeutic response during back massage. The nurse should observe the patient's face for any signs of relaxation, which may include softening of facial lines, eyelids drooping, or a general expression of peacefulness.
The respiratory rate (RR) decreases: The nurse should expect the client's respiratory rate to decrease during a back massage. This is because relaxation stimulates the parasympathetic nervous system, resulting in decreased respiratory rate, heart rate, and blood pressure.
The pulse is within the expected range: The nurse should expect the client's pulse to remain within the expected range during a back massage. A normal pulse rate is between 60-100 beats per minute for adults. If the pulse remains within this range, it is a sign that the patient is responding positively to the massage therapy.
In conclusion, providing back massage as a palliative care measure to an unconscious, grimacing, and restless client can help to promote relaxation, improve blood circulation, reduce muscle tension, and alleviate pain, stress, and anxiety. The nurse should identify therapeutic responses in the patient during the massage therapy, which may include relaxation of the shoulders, facial muscles, decreased respiratory rate, and pulse remaining within the expected range.
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me the investment company institute sampled 300 american families to estimate that the percent owning stocks or stock funds is 46% this year. what is the p value for your hypothesis test? if required, round your answer to four decimal places. do not round your intermediate calculations.
The p value for your hypothesis test is 0.0832.
To calculate the p-value for a hypothesis test, we need to know the null hypothesis, the alternative hypothesis, the test statistic, and the level of significance (alpha). Let's assume that the null hypothesis is that the percentage of American families owning stocks or stock funds is equal to 50%, and the alternative hypothesis is that it is not equal to 50%.
The test statistic for a hypothesis test of a proportion is given by:
z = \(\frac{p-P}{\sqrt{\frac{P(1-P)}{n} } }\)
where p is the sample proportion (0.46), P is the hypothesized population proportion under the null hypothesis (0.5), n is the sample size (300), and sqrt denotes the square root function.
Plugging in the values, we get:
z = \(\frac{0.46-0.5}{\sqrt{\frac{0.5*0.5}{300} } }\) = -1.732
To find the p-value, we need to find the area under the standard normal curve to the left and right of the test statistic (since this is a two-tailed test). Using a standard normal table or calculator, we find that the area to the left of -1.732 is 0.0416, and the area to the right is also 0.0416 (since the standard normal curve is symmetric).
Therefore, the p-value for this hypothesis test is the sum of the areas in both tails:
p-value = 0.0416 + 0.0416 = 0.0832
Rounding to four decimal places, the p-value is 0.0832.
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Must solve this problem using the method elimination
6x-7y = 25/ 3x = 9y = 0
The solution to the system of equations is x = 75/11 and y = 25/11.
To solve the given problem using the method of elimination, we can eliminate one variable by manipulating the equations. Let's start with the given equations:
Equation 1: 6x - 7y = 25
Equation 2: 3x = 9y
To eliminate one variable, we can multiply Equation 2 by 2 to make the coefficients of x in both equations equal:
2 * (3x) = 2 * (9y)
6x = 18y
Now, we have two equations with the same coefficient for x:
Equation 1: 6x - 7y = 25
Equation 3: 6x = 18y
Next, we can subtract Equation 3 from Equation 1 to eliminate x:
(6x - 7y) - (6x) = 25 - (18y)
-7y = -18y + 25
11y = 25
Finally, we can solve for y by dividing both sides of the equation by 11:
y = 25/11
Now that we have the value of y, we can substitute it back into Equation 2 to solve for x:
3x = 9 * (25/11)
3x = 225/11
x = (225/11) * (1/3)
Thus, x = 75/11 and y = 25/11.
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For three consecutive plays, the Patriots gained
12 yards per play. On the next play, they lost 5
yards. What is the change in field position for
these four plays?
Answer:
The overall change in field position is 7yds, 0 - 5 + 12 = 7, if that isn't a "sum of integers" I apologize.
Step-by-step explanation:
Match the standard deviations on the left to their corresponding varlance on the right.
1. 1.4978
2. 1.5604
3. 1.3965
4. 1.5109
a. ≈2.2434
b. ≈1.9502
c. ≈ 2.2828
d.≈ 2.4348
The matches between the standard deviations on the left and their corresponding variances on the right are:
Standard deviation 1.4978 matches with variance ≈2.2434 (a).
Standard deviation 1.5604 matches with variance ≈2.4348 (d).
Standard deviation 1.3965 matches with variance ≈1.9502 (b).
Standard deviation 1.5109 matches with variance ≈2.2828 (c).
To match the standard deviations on the left to their corresponding variances on the right, we need to understand the relationship between standard deviation and variance.
The variance is the square of the standard deviation.
Given the options:
Standard deviation: 1.4978
Variance: ≈2.2434 (option a)
Standard deviation: 1.5604
Variance: ≈2.4348 (option d)
Standard deviation: 1.3965
Variance: ≈1.9502 (option b)
Standard deviation: 1.5109
Variance: ≈2.2828 (option c)
To verify the matches, we can calculate the variances by squaring the corresponding standard deviations:
\(1.4978^2\) ≈ 2.2434
\(1.5604^2\) ≈ 2.4348
\(1.3965^2\) ≈ 1.9502
\(1.5109^2\) ≈ 2.2828
Therefore, the correct matches are:
Standard deviation: 1.4978, Variance: ≈2.2434 (option a)
Standard deviation: 1.5604, Variance: ≈2.4348 (option d)
Standard deviation: 1.3965, Variance: ≈1.9502 (option b)
Standard deviation: 1.5109, Variance: ≈2.2828 (option c)
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W = {(*1, 12.12 - 1), 12 € R} and W, = {(91 +92:54, 291) | 1,92 € R} be subspaces of R' (a) Show that R= W + W. (b) Is the sum Wi+W, a direct sum?
(a) To show that R^2 = W + W', we need to prove two things: (i) any vector in R^2 can be expressed as the sum of two vectors, one from W and one from W', and (ii) W and W' intersect only at the zero vector.
(i) Let (a, b) be any vector in R^2. We can express (a, b) as (a, 0) + (0, b), where (a, 0) is in W and (0, b) is in W'. Therefore, any vector in R^2 can be expressed as the sum of a vector from W and a vector from W'.
(ii) The intersection of W and W' is the zero vector (0, 0). This is because (0, 0) is the only vector that satisfies both conditions: (0, 0) ∈ W and (0, 0) ∈ W'.
Since both conditions hold, we can conclude that R^2 = W + W'.
(b) The sum W + W' is not a direct sum because W and W' are not disjoint. They intersect at the zero vector (0, 0). In a direct sum, the only vector that can be expressed as the sum of a vector from W and a vector from W' is the zero vector. Since there exist other vectors in W + W', the sum W + W' is not a direct sum.
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Given that line k bisects BD at point C and that BC=9x−13 and BD=118, find CD.
Applying the definition of a segment bisector, the length of CD is: 59 units.
What is a Segment Bisector?A line segment that bisects a line segment is known as a segment bisector. It divides the line segment into two smaller segments that are equal in length to each other.
Since line k bisects BD at point C, therefore, based on the definition of a segment bisector, we have the following equation:
2(BC) = BD
BC = 9x - 13
BD = 118
Substitute the values
2(9x - 13) = 118
18x - 26 = 118
18x = 118 + 26
18x = 144
18x/18 = 144/18
x = 8
CD = BC = 9x - 13
CD = 9x - 13 = 9(8) - 13
CD = 59 units
Therefore, applying the definition of a segment bisector, the length of CD is: 59 units.
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hi I'm Danica and it's sixth grade I would really like if you look over this problem and tell me the answer(sending it rn)!!!!!!!!!!!!!!!!!hiii!!!!!!!!!!!!!!(no important info cutted off
Answer:
The answer is the third one
Step-by-step explanation:
I was in 6th grade last year and our teacher made sure we new the answer always so i got good at it and yeah the answer is the third one hope this helps!!!!!!!
Answer: (x,y) (x,y+4)
Step-by-step explanation:
Sami opened an account with a deposit of $4,000. The bank pays 3.5% annual simple interest on this account Sami did not make any additional deposits or withdrawals. How long will it take for Sami to earn $2,100 in interest on this account?
Answer: 15 months
Step-by-step explanation:
HELP ASAP
i need too know these
Answer:
3. y = 4
4. y = 40
Step-by-step explanation:
3. To find y, input the value of 2 for x in the equation y = 3x - 2.
y = 3(2) - 2
y = 6 - 2
y = 4
y is 4 when x is 2.
4. To find the answer we first have to make an equation in y=mx + b form, where b is the y-intercept and m is the slope. We know that the y-intercept is -5 because the table tells us that when x is zero, y is -5. So, we can use the y-intercept and a point In this example I will use point (6, 13)) to find the slope:
Input the values you know into the equation:
13 = 6m - 5
Add 5 to both sides to isolate the 6m:
18 = 6m
Divide both sides by 6 to isolate the m:
3 = m
Our slope is 3. Now that we know the slope and y-intercept, we can make our equation:
y = 3x - 5
We can use this equation to find y when x is 15:
Input 15 in place of x:
y = 3(15) - 5
Solve:
y = 45 -5
y = 40
When x is 15, y is 40.
Hope this helps :)
a fish is 12 meters below the surface of the ocean. A sea bird is 28 meters above the surface. how far apart are they?
answer is 40
Step-by-step explanation:
A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen from the deck at random. What is the probability of choosing one club and one spade?
Answer:
Probability of choosing one club and one spade = 0.6025
Step-by-step explanation:
Total number of cards= 52 cards
For the first event
Probability of choosing a club
Toatal club = 13 cards
Probability of choosing a club
= 13/52
Probability of choosing a club
= 1/4
Probability of choosing a club
=0.25
For the second event
Probability of choosing a spade
Toatal spade = 13 cards
Probability of choosing a spade
= 13/52
Probability of choosing spadep
= 1/4
Probability of choosing a spade = 0.25
Probability of both = 0.25*0.25
Probability of both = 0.6025
Answer:
D. 0.1275
Step-by-step explanation:
Justo took the Pre-Test on Edg (2020-2021)!!
Lisa set a weekly goal of jogging 18 miles. In each of the first 3 days, he jogged 2 2/3 miles. How many more miles must he run to reach his goal?
Answer:
Step-by-step explanation:
3(2+(2/3))+x=18
3(8/3)+x=18
(24/3)+x=18
8+x=18
x=10
He must run another ten miles.
Answer:
10.88
Step-by-step explanation:
3 * 2 3/8 = 6 9/8 = 7 1/8 miles
Plz help with math u will get Brainliest
Answer:
Volume = 315 cm³
Step-by-step explanation:
Volume = Length × Width × Height
→ Substitute in the values
Volume = 6 cm × 3.5 cm × 15 cm
→ Simplify
Volume = 315 cm³
HELLPPP
Solve the system by substitution.
-9x-10y=12
−3x+3=y
Answer:
\(x=2\\y=-3\)
Step-by-step explanation:
We have:
\(-9x-10y=12\\-3x+3=y\)
Since we already have a variable value (\(y\)) in the second equation, it would be easiest to substitute the value for \(y\) in the first equation:
\(-9x-10(-3x+3)=12\)
Distribute \(-10\) into \((-3x+3)\):
\(-9x+30x-30=12\)
Combine like terms:
\(21x-30=12\)
Add \(30\) to both sides of the equation:
\(21x=42\)
Divide by the coefficient of \(x\), which is \(21\):
\(x=2\)
_
Now that we have our \(x\) value, we can substitute that in to the second equation to find our \(y\) value:
\(-3(2)+3=y\)
Multiply:
\(-6+3=y\)
Combine like terms:
\(-3=y\)
N/A
N/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/AN/A
Answer:
why is there an N not paired up with A at the beginning, and an A without an N at the end? oh my gosh dude pair them up theyre lonely
Step-by-step explanation:
Someone plz help me with this 2 questions I will give brainliest
(Look at the pictures)
Answer:
61 ounces
Step-by-step explanation:
1 pound = 16 ounces
8 pound 3 ounces = 8*16 + 3 = 128 +3 = 131 ounces
No Jesse's weight = 12 pounds = 12*16 = 192 ounces
Weight gained = 192 - 131 = 61 ounces
6- Karen is making a frame for a square picture with an area of 169 square inches. How
many inches of framing are needed?
a) 13
b) 14
c) 15
d) 16
PLEASE HURRY! I WILL MARK YOU BRAINLIST OR WHATEVER... IF YOU DO IT PLEASE
Answer: a
Step-by-step explanation:
Tell me if it is correct