For a chemical reaction at equilibrium, which of the following will change the value of the equilibrium constant K?
I. Changing the temperature
II. Changing the total concentration of reactants and products
III. Changing the reaction coefficients
a. I only d. I and II only
b. II only e. I and III only
c. III only

Answers

Answer 1

The equilibrium constant K can be changed for a chemical reaction at equilibrium by changing the temperature and the total concentration of reactants and products.

The correct option is d. I and II only.

.A chemical reaction at equilibrium is the point at which the rates of the forward and reverse reactions are equal. At equilibrium, the concentrations of the reactants and products remain constant. The equilibrium constant, K, is a value that describes the relative amounts of products and reactants at equilibrium.

The value of K is a function of temperature only, so changing the temperature of the system will change the value of K. The equilibrium constant K also depends on the concentration of reactants and products. Therefore, changing the total concentration of reactants and products will change the value of K.

The equilibrium constant K also depends on the reaction coefficients, but changing the coefficients does not change the value of K. This is because the equilibrium concentrations of the reactants and products will adjust to compensate for the change in coefficients

. Therefore, option c. III alone is incorrect. Thus, the correct option is d. I and II only.

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Related Questions

An aerobatic airplane pilot experiences
weightlessness as she passes over the top of
a loop-the-loop maneuver.
The acceleration of gravity is 9.8 m/s^2.
If her speed is 450 m/s at this time, find the radius of the loop.
Answer in units of km.

Answers

To find the radius of the loop, we can use the relationship between the acceleration of gravity, the speed of the airplane, and the radius of the loop. This relationship is given by:

g = (v^2) / r

Where g is the acceleration due to gravity, v is the speed of the airplane, and r is the radius of the loop.

We know that the acceleration of gravity is 9.8 m/s^2, and the speed of the airplane is 450 m/s. We can substitute these values into the equation and solve for r:

9.8 = (450^2) / r

r = (450^2) / 9.8

r = (450 x 450) / 9.8

r = (202,500) / 9.8

r = 20,714.2857 m

To convert meters to kilometers, we divide the value by 1000.

r = 20.7142857 km

A person walks along a road 2 miles and rests. Then taking another road, he travels 3.000 miles; and switching to a dirt path, he walks 2.00 miles before arriving at his destination. Determine the total distance the person walks. 7.000 7 miles 7.00 miles 7.0 miles

Answers

Answer:

he walked 7 miles

Explanation:

2+3.000+2.00= 7

you can add with a calculator as well

Which of the following settings describes a displacement vs. time graph that
looks like this?
Displacement
Time
Check all that apply
O A. Constant velocity
OB. Increasing velocity
I C. Zero acceleration
O D. Decreasing acceleration
I NEED HELP ASAP

Which of the following settings describes a displacement vs. time graph thatlooks like this?DisplacementTimeCheck

Answers

Answer:

c and a

Explanation:

ape x

18. all of the following are units of power except (a) watts (b) joules per second (c) electron volts per second (d) newton meters per second (e) kilogram meters per second

Answers

joule is not the unit of power.

In physics, power measures the rate of transfer of electrical energy through a circuit per unit of time. It is denoted by P and is measured using the SI unit of power (watts or 1 joule/second). Electrical energy is usually supplied by batteries and produced by generators. Power refers to the rate per unit of time at which electrical energy is transferred through a circuit. When we talk about units of power, it is joules per second or joules per unit of time. A watt is a unit of electrical power equivalent to 1 ampere under 1 volt of pressure.

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1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)

Answers

The force diagram on the desk consists of normal reaction and weight of the pencil.

The net force on the desk in vertical direction is 1 N.

The net force on the desk in horizontal direction is 0.

The given parameters;

weight of the pencil, W = 1 N

The force diagram of the desk is sketched as follows;

                                             ↑ N

                                             ⊕

                                              ↓ W

Where;

N is the normal reaction on the deskW is the weight of the ball

The net force on the desk in vertical direction = 1 N

The net force on the desk in horizontal direction = 0

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ing Figure 8.9 Explain the following using F= ma a A racing car has a powerful engine and is made of e le strong but lightweight material. b A car with a small engine can still accelerate rapidly.​

Answers

The acceleration is inversely related to the mass of the engine.

Why does the small engine car accelerate rapidly?

We have to note that we must look at the law that have been stated by Newton for the motion of an object. That law states that the relationship between the force that is acting on the object and the acceleration of the object can be given by the formula; F = ma

F = force of the object

m = mass of the object

a= acceleration of the object

It then follows that;

a = F/m

The larger the mass, the lesser the object would accelerate.

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A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.80 m/s. If the roof is pitched at 38.0° below the horizon and the roof edge is 3.30 m above the ground, find the time the baseball spends in the air and the horizontal distance from the roof edge to the point where the baseball lands on the ground. HINT

Answers

Answer:

a) The baseball spends 0.674 seconds in the air

b) The horizontal distance from the roof edge to the point where the baseball lands on the ground = 2.02 m

Explanation:

The ball's initial speed, u = 3.8 m/s

θ = 38°

The edge of the roof has a height, H = 3.30 m

The vertical motion of the baseball can be given by the equation:

\(H = U_{y} t + 0.5a_{y} t^{2}\).........(1)

Vertical acceleration of the baseball, \(a_y = 9.8 m/s^2\)

The vertical component of the initial speed can be calculated by:

\(U_y = Usin \theta\\U_y = 3.8 sin 38\\U_y = 2.34 m/s\)

Substituting the appropriate values into equation (1):

\(3.8 = 2.34 t + 0.5(9.8)} t^{2}\\4.9t^2 + 2.34t - 3.8 = 0\)

Solving for t in the quadratic equation above:

t = 0.674 s

To calculate the horizontal distance, S, use the formula below:

\(S = U_xt + 0.5a_xt^2\)

Horizontal acceleration of the baseball, \(a_x = 0 m/s^2\)

The horizontal component of the initial speed can be calculated as:

\(U_x = Ucos \theta\\U_x = 3.8 cos 38\\ U_x = 2.99 m/s\)

S = 2.99(0.674) + 0.5(0)

S = 2.02 m

A long straight conductor carries a current of 100 A. At what distance from the axis is the magnetic field caused by the current equal in magnitude to earth's magnetic field which is 0.5 E-4 T
A) 0.4 m
B) 25 m
C) 2.5 m
D) 4.0 m

Answers

The correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

To find the distance from the conductor at which the magnetic field caused by the current is equal to the Earth's magnetic field, we'll use the formula for the magnetic field around a long straight conductor:

\(B = (de * I) / (2 * \pi  * r)\)

Where B is the magnetic field, μ₀ is the permeability of free space (\(4\pi  * 10^-7 Tm/A\)), I is the current, and r is the distance from the conductor. We want to find the value of r when B equals Earth's magnetic field (0.5 x 10⁻⁴ T).

\(0.5 * 10^-4 T = (4\pi  * 10^-7 Tm/A * 100 A) / (2 * \pi  * r)\)
To solve for r, we can first simplify the equation by cancelling the π terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm/A * 100 A) / (2 * r)\)

Now, cancel out the A (Amperes) terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm) / (2 * r)\)

Divide both sides by 4 x 10⁻⁷ T:

\(r = (0.5 * 10^-4 T) / (4 * 10^-7 T)\)

Simplify the equation:

r = \(0.5 * 10^3 m / 4\)
r = 500 / 4
r = 125

So, the correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

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TRUE OR FALSE!!!!!

PLEASE HELP


Igneous rock is formed by volcanoes releasing magma from the mantle, the rock cools and piles up forming a mountain. Rivers direct water to cool magma underground forming metamorphic rock under lake beds.

Answers

Answer:

true

Explanation:

this is true, igneous rocks are formed from molten lava when it cools

Answer: True

Explanation:

An Olympic swimming pool is 50 meters long. You swam from one end
to the other four times.
a. How many meters did you swim?

Answers

Answer:

200 meters

Explanation:

50 meters × 4 times = 200 meters

The total number of meters you swim is 200 meters if the Olympic swimming pool is 50 meters long.

What is the distance?

Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.

It is given that:

An Olympic swimming pool is 50 meters long. You swam from one end to the other four times.

Let x be the total number of meters you swim.

x can be found using:

x = 50 + 50 + 50 + 50

x = 50×4

x = 200 meters

Thus, the total number of meters you swim is 200 meters if the Olympic swimming pool is 50 meters long.

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two events occur in an inertial system k at the same time but 7 km apart. what is the time difference (in s) measured in a system k' moving parallel to these two events when the distance separation of the events is measured to be 17 km in k' ?

Answers

This is a problem in special relativity that involves the concept of time dilation and length contraction.

We can use the Lorentz transformation equations to find the time difference between the two events in the moving system k'.

Let t1 and t2 be the times at which the two events occur in system k, and let x1 and x2 be their positions along the x-axis of k.

We are given that the events occur at the same time in k, so t1 = t2. We are also given that the distance between the events in k is 7 km, so x2 - x1 = 7 km.

Let's assume that k' is moving to the right with a speed v relative to k. Then, the position and time coordinates of the events in k' can be found using the following Lorentz transformation equations:

\(x' = \gamma(x - vt)\)

\(t' =\gamma(t - vx/c^2)\)

where \(\gamma= 1/√(1 - v^2/c^2)\) is the Lorentz factor.

To find the time difference between the events in k', we need to find the difference between their time coordinates in k'. Using the Lorentz transformation equations, we can express the positions and times of the events in k' as:

\(x1' = \gamma(x1 - vt)\)

\(x2' = \gamma(x2 - vt)\)

\(t1' = \gamma(t1 - vx1/c^2)\)

\(t2' = \gamma(t2 - vx2/c^2)\)

Since t1 = t2, we can simplify the expressions for t1' and t2' as:

\(t1' = \gamma(t1 - vx1/c^2) = \gamma(t2 - vx1/c^2)\)

t2' = γ(t2 - vx2/c^2) = γ(t1 - vx2/c^2)

Subtracting these two equations, we get:

\(t2' - t1' = \gamma(v/c^2)(x2 - x1)\)

Substituting the values given in the problem, we get:

\(t2' - t1' = \gamma(v/c^2)(7 km)\)

We also know that the distance between the events in k' is 17 km. Using the Lorentz transformation equation for length contraction, we can express this distance as:

\(x2' - x1' = \gamma(x2 - x1) = γ(7 km)\)

Substituting the value of γ from this equation into the expression for t2' - t1', we get:

\(t2' - t1' = (17 km/c) (v/c)\)

Simplifying this expression, we get:

\(t2' - t1' = (17/c) (v/c) s\)

So, the time difference between the two events in system k' is proportional to the speed v of k' relative to k, and is given by the formula above in seconds.

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If a baseball lands with a speed of 80 miles/hr after traveling with an acceleration of -6 miles/hr/sec for 5seconds, what was the initial speed at which the ball was hit?

Answers

We are given that an object falls with an acceleration of -6 miles/h/s. To determine the initial velocity we will use the following motion:

\(v_f=v_0+at\)

Where:

\(\begin{gathered} v_f,v_0=\text{ final and initial velocity} \\ a=\text{ acceleration} \\ t=\text{ time} \end{gathered}\)

Now, we solve for the initial velocity by subtracting "at" from both sides:

\(v_f-at=v_0\)

Now, we plug in the values:

\(80\frac{mi}{h}-(6\frac{mi}{hs})(5s)=v_0\)

Now, we solve the operations:

\(50\frac{mi}{h}=v_0\)

Therefore, the initial velocity is 50 mi/h.

If a solenoid were suspended by a string so that it could rotate freely, could it be used as a compass when it carried a direct current? Could it also be used if the current were alternating in direction?

Answers

Yes, a solenoid suspended by a string can be used as a compass when it carries a direct current. This is because the solenoid creates a magnetic field when current flows through it.                                                                                                                    

The magnetic field aligns with the Earth's magnetic field, causing the solenoid to point in the direction of magnetic north. However, if the current were alternating in direction, the solenoid would constantly change its orientation and would not be reliable as a compass.
This magnetic field interacts with Earth's magnetic field, causing the solenoid to align itself with the magnetic north and south poles, acting as a compass.
Consequently, a solenoid with an alternating current would not function effectively as a compass.

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A 5.00-kg sphere is moving at a speed of 4.00 m/s. An identical sphere is at rest. The two spheres collide. The first sphere moves off at a 60.0° angle to the left of its original path. The second sphere moves off in a direction 90.0° to the right of the first sphere’s final path. Assuming no friction, what are the speeds of the two spheres as they separate?

Answers

The final speeds of the spheres are 3.47 m/s and 3.08 m/s.

We can use conservation of momentum to solve this problem since there are no external forces acting on the system.

The initial momentum of the system is:

p_initial = m₁ * v₁ + m₂ * v₂

where m₁ and m₂ are the masses of the spheres, and v₁ and v₂ are their initial velocities (4.00 m/s and 0 m/s, respectively).

After the collision, the momentum of the system is:

p_final = m₁ * v1' + m₂ * v₂'

where v₁' and v₂' are the final velocities of the spheres. We also know that the angle between the first sphere's final path and its initial path is 60 degrees, which means that the angle between the two spheres after the collision is 150 degrees (90 + 60).

Using conservation of momentum, we can set the initial and final momenta equal to each other:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' + m₂ * v₂'

We can also break down the final velocities into their x and y components using trigonometry. Let's define the angle between the first sphere's final path and the x-axis as theta. Now we can use conservation of momentum to solve for the final velocities:

m₁ * v₁ + m₂ * v₂ = m₁ * v₁' * cos(theta) + m₂ * v₂' * cos(150 degrees)

0 = m₁ * v₁' * sin(theta) + m₂ * v₂' * sin(150 degrees)

Solving the first equation for v₂', we get:

v₂' = (m₁ * v₁ + m₂ * v₂ - m₁ * v₁' * cos(theta)) / (m₂ * cos(150 degrees))

Substituting this expression into the second equation and solving for v₁', we get:

v₁' = (m₂ * sin(150 degrees) * v₁ + m₂ * sin(150 degrees) * v₂ + m₁ * sin(theta) * v₁' - m₁ * sin(theta) * m₂ * v₁ * cos(theta) / cos(150 degrees)) / (m₁ * sin(theta))

Plugging in the given values and solving, we get:

v₁' = 3.47 m/s

v₂' = 3.08 m/s

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The function sequalsnegative t cubed plus 6 t squared minus 12 t​, 0 less than or equals t less than or equals 4​, gives the position of a body moving on a coordinate​ line, with s in meters and t in seconds. a. Find the​ body's displacement and average velocity for the given time interval. b. Find the​ body's speed and acceleration at the endpoints of the interval. c.​ When, if​ ever, during the interval does the body change​ direction?

Answers

Answer:

Explanation:

Given the position of a body modeled by the equation

S = t³+6t²-12t for 0≤t≤4 where s is in metres and t in seconds

Displacement during the interval is expressed as;

ΔS = S(4)-S(0)

s(4) = 4³+6(4)²-12(4)

S(4) = 64+96-48

S(4) = 112m

at t = 0

S(0) = 0³+6(0)²-12(0)

S(0) = 0m

The displacement of the body = 112 - 0 = 112m

average velocity is the rate of change of displacement with respect to time.

average velocity = diaplacement/time

average velocity = 112/4

average velocity = 28m/s

b) speed v = dS/dt

v(t) =  3t²+12t-12

at endpoint t = 4s

v(4) = 3(4)²+12(4)-12

v(4) = 48+48-12

v(4) = 84m/s

at t = 0

v(0) =  3(0)²+12(0)-12

v(0) = -12m/s

|v(0)| = 12m/s

acceleration = dv/dt

a(t) = 6t+12

at endpoint t = 4s

a(4) = 6(4)+12

a(4) = 24+12

a(4) = 36m/s

at t = 0

a(0) =  6(0)+12

a(0) = 0+12

a(0) = 12m/s

3) The direction of the bod is determined by the value of its velocity whether it is a negative or a positive value. A positive value shows that the object moves in the positive direction while a negative value shows that the body moves in the negative direction.

For us to determine when the body will change direction, we wil have to find the value of t at when v(t) =0

v(t) =  3t²+12t-12

3t²+12t-12 = 0

t²+4t-4 = 0

t = -4±√16-4(-4)/2

t = (-4±√32)/2

t = (-4±4√2)/2

t = -2+2√2 and -2-2√2

t = -2+2.83 and -2-2.83

t = 0.83secs and -4.83 secs

Hence the body changes velocity at t = 0.83s and -4.83secs

Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the heat added. In this situation,

Answers

Answer:

The Internal energy of the gas did not change

Explanation:

In this situation the Internal energy of the gas did not change and this is because according the the first law of thermodynamics

Δ U = Q - W  ------ ( 1 )

Δ U  = change in internal energy

Q = heat added

W = work done

since Q = W.  the value of ΔU  will be = zero   i.e. No change

3. Four projectiles, A, B, C, and D, were launched from, and returned to, level ground.
The data table below shows the initial horizontal speed, initial vertical speed, and
time of flight for each projectile.
Data Table
Projectile Initial Horizontal Speed (m/s) Initial Vertical Speed (m/s) Time of Flight (s)
A
40.0
29.4
6.00
B
60.0
19.6
4.00
С
50.0
24.5
5.00
D
80.0
19.6
4.00
Which projectile traveled the greatest horizontal distance? [Neglect friction.]

Answers

Answer is D

Taking the test rn and found out the answer

The projectile D traveled the greatest horizontal distance.

What is projectile motion?

Projectile motion is a form of motion experienced by an object or particle that is projected near the Earth's surface and moves along a curved path under the action of gravity only.

What is projectile horizontal distance?

Horizontal range of a projectile is the horizontal distance travelled by the projectile between launch and the landing points.

The projectile horizontal distance is depend on horizontal speed and time in air.

In all these four projectile, projectile D has maximum horizontal speed and time in air.

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What is mass formula?

Answers

Answer:

The mass formula is given as

Mass = ρ × v

Where,

ρ = density and

v = the volume

The weight mass formula is given as

m = w / g

Where,

w= weight

m = mass

g = gravity

The mass formula is also given as

m = F / a

If acceleration itself is the gravity, then

M = F / g

Where,

F = force

G = gravity

According to Einstein’s mass-energy relation

m = (E / c2)

Where,

m = mass

E = energy

c = speed of light (3×108 m/s)

The kinetic energy mass formula is given as

K.E = ½ mv2

Where,

m = mass,

v = velocity.

Explanation:

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Featured snippet from the web
The molar mass (M) is a physical property and it is defined as the mass of one mole of the chemical substance or it is a ratio of the mass of a chemical compound to its amount of chemical substance. The unit of molar mass is kg/mol. The mass formula is given as. Mass = ρ × v.

if the force moving an object points at least partially in the positive direction of the objects motion the work is considered to be

Answers

Answer:

the work done can be positive or negative  

Explanation:

Give 3 examples of momentum used in everyday life.

Answers

Answer:

waking up,eat,sleep

Explanation:

notice how i didn't say math :)

2. Which is NOT a unit of speed?
A. kilometer/hour
B. meter/second
C. miles/hour
D. second/meter​

Answers

The answer is D) second/meter

Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3

Answers

Answer:

2,3,1

Explanation:

There are 3 laws of Kepler.

First law = The path of each planet around the sun is an ellipse with the sun at one focus.

Second law =  As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.

Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.

Hence, the correct order for Kepler's law is: 2,3,1

Que fuerza será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s²

Answers

Answer:

La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.

Explanation:

La segunda ley de Newton, llamada ley fundamental o principio fundamental de la dinámica, plantea que un cuerpo se acelera si se le aplica una fuerza.

De esta manera, esta ley establece que las aceleraciones que experimenta un cuerpo son proporcionales a las fuerzas que recibe. Dicho de otra forma, la aceleración de un cuerpo es proporcional a la fuerza neta que se le aplica. Cuanto mayor es la fuerza que se le aplica a  un objeto con una masa dada, mayor será su aceleración.

La segunda Ley de Newton se expresa matemáticamente como:

F = m*a

Donde:

F es la fuerza neta. Se expresa en Newton (N) m es la masa del cuerpo. Se expresa en kilogramos (Kg.). a es la aceleración que adquiere el cuerpo. Se expresa en metros sobre segundo al cuadrado (m/s²).

En este caso:

m= 20 kga= 4 m/s²

Reemplazando:

F= 20 kg* 4 m/s²

Resolviendo:

F= 80 N

La fuerza que será necesaria aplicar a un cuerpo de 20kg de masa para imprimirle una aceleración a=4m/s² es 80 N.

Compare the direction that a transverse wave travels with the direction that matter in the wave vibrates

Answers

In a transverse wave, matter vibrates in a direction that is parallel to the wave motion, whereas the direction of energy transfer is perpendicular to the wave's direction of motion.

How can the direction that a transverse wave moves be compared to the direction that the wave's constituent matter vibrates?

A transverse wave transfers energy in a direction that is perpendicular to the way that the wave's constituent matter vibrates. For instance, when a rope is shaken back and forth to produce a wave, the energy moves perpendicular to the rope's motion from one end to the other.

In contrast, the path of energy transfer in a longitudinal wave is parallel to the direction in which the wave's constituent matter vibrates. For instance, as sound waves pass through air, the molecules in the air oscillate back and forth parallel to the wave's motion.

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Give reason: Acceleration is positive when its value increases​

Answers

Answer:

The acceleration of an object that is speeding up is always positive. The acceleration of an object that is slowing down is always negative. The airplane is speeding up as it goes down the runway. The final speed is greater than the initial speed.

Explanation:

The force of gravity causes objects to accelerate back to earth at:_______

Answers

The force of gravity causes objects to accelerate back to earth at a rate of  9.8 m/s^2

Gravity is the force of attraction between any two objects with mass. The strength of this force depends on the masses of the two objects and the distance between them. The larger the masses of the objects, the stronger the gravitational force between them will be. Similarly, the closer two objects are to each other, the stronger their gravitational attraction will be.

When an object is dropped or thrown, the force of gravity immediately begins to pull it back towards the earth. This force causes the object to accelerate downwards, meaning that its velocity (speed and direction of motion) increases over time. The rate at which this acceleration occurs is constant and is equal to approximately 9.8 m/s^2

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a car having a mass of 10kg accelerates from 10m/s square to 16 m/s square in t seconds? What is the force exerted by the car?​

Answers


using F=ma (force = mass * acceleration), the force needed would be 10 kg * 16

10 * 16 = 160, so the force would be 160N.

Answer:

The answer is 160 N

Explanation:

I did the test

Hope this helps :)

How to calculate mass

Answers

Answer:

The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.

Answer:

\(vd=m\) - volume times density

Explanation:

d = density

v = volume

m = mass

density = mass divided by volume.

multiply both sides by volume to find mass.

An eccentric inventor attempts to levitate by first placing a large negative charge on himself and then putting a large positive charge on the ceiling of his workshop. Instead, while attempting to place a large negative charge on himself, his clothes fly off. Explain.

Answers

Answer:

shirt is little attached to the body, it can come off and fly away

Explanation:

In electrostatics, charges of different signs attract and charges of the same sign repel.

In this case, when a negative charge is placed on it, both the inventor and the shirt are charged, therefore there is a repulsive force, also there is an attraction between the positive charge of the roof attracts the negative charge, such as the shirt. of weak the two forces not greater than the resistance of the walk.

As the shirt is little attached to the body, it can come off and fly away

if your weight is 600 Newton on the earth how far should you go from the centre of the earth so that it will be 300 Newton​

Answers

Given :

Our weight is 600 Newton on the earth.

To Find :

How far should you go from the center of the earth so that it will be 300 Newton​.

Solution :

Acceleration due to gravity at depth d is given by :

\(g' = g( 1 - \dfrac{d}{R_e})\)

At earth surface, mg = 600 N   ...1)

At depth d, mg' = 300 N            ...2)

Dividing 1) and 2), we get :

\(\dfrac{g}{g'} = \dfrac{600}{300}\\\\\dfrac{g}{g'} = 2\\\\g = 2g'\\\\g = 2\times g\times ( 1 - \dfrac{d}{R_e} )\\\\1 - \dfrac{d}{R_e} = \dfrac{1}{2} \\\\d = \dfrac{R_e}{2}\)

Therefore, we should go in the depth of distance half the radius of earth.

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