For a 5-khz sine wave, how long does it take for 1/4 of a cycle?

This question can be solved using the concept of friction energy.

The thermal energy change is b "258.4 J".

The change in thermal energy will be equal to the friction energy produced during the motion of the box.

\(Change\ In\ Thermal\ Energy = E = Friction\ Energy\\\\E = \mu fd\)

where,

μ = coefficient of kinetic friction = 0.4

f = force applied = 38 N

d = distance traveled by the box = 17 m

Therefore,

\(E = (0.4)(38\ N)(17\ m)\)

E = 258.4 J

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Answer:

3920 N.

Explanation:

that's what the answer is..

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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Create three scripts: 'task1.m' to save variables, 'gcalculate.m' to calculate gravitational acceleration, and 'task3.m' to plot and analyze the variation of g with height for different planets, using stored variables from 'project_1.mat'.

Accomplish the given tasks, you need to create three MATLAB scripts: 'task1.m', 'gcalculate.m', and 'task3.m'.

In 'task1.m', you will define and save the required variables, such as the universal gravitational constant (G), masses, radii, and names of Earth, Moon, Mars, and Jupiter, as well as the heights of different strata of Earth's atmosphere. These values will be stored in the 'project_1.mat' workspace.

In 'gcalculate.m', you will create a function called 'gcalculate' that takes inputs G, M, and d to calculate and return the gravitational acceleration (g) using the given formula. This function will be used in the subsequent tasks.

In 'task2.mlx', you will load the stored variables from 'project_1.mat' and use the 'gcalculate' function in a loop to calculate and display the values of g at the surface of each planet and at different strata of Earth's atmosphere.

The script will also accept user input for the desired planet and distance to calculate and display the corresponding g value.

In 'task3.m', you will load the stored variables and define an implicit function to calculate g with respect to the variable x, representing the distance from the surface of the planet.

You will sample 1000 evenly distributed values for x, calculate the corresponding g values, and plot a graph showing the variation of g with height for different planets. The plot will be properly labeled and saved as 'task3_graph.fig'.

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Answer:

muscular force in relative to this

Answer:

a.  Frequency is 5.45 x 10^14 hz

b.   The period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Explanation:

The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).  

V = λ f     where,

V is the wave speed,

f is the wave frequency,

λ is the wavelength.

To find frequency, rearrange to:

f = V/ λ

Light travels at 3.00x10^8 m/sec.

λ is 5.50 x 10^-7 m

f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m)  meters cancels, secs is on the bottom]

f = (3.00/5.50)*(10^15)  [The base 10 exponent on the bottom ius subtracted from the one on top:  98-(-7)) = 15)  

f = 0.545 x 10^15 1/s or hz

f = 5.45 x 10^14 hz

b.  The period of a wave is the inverse of it's frequesncy.  It is the time it takes for 1 wave to pass.  Invert the frequency:

 Period = 1/f

  Period =  1/(0.545 x 10^15 1/s)

Period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Answer :

after this all u can write this

False. It is incorrect to consider a lightbulb as a kind of lever.

A lightbulb is not a kind of lever. A lever is a simple machine that consists of a rigid bar or plank that rotates around a fixed point called a fulcrum. Levers are used to transmit and amplify forces or to change the direction of applied forces. They work based on the principle of torque, where a force is applied at a certain distance from the fulcrum, creating rotational motion.

On the other hand, a lightbulb is an electrical device that produces light when an electric current passes through it. It consists of a filament or a gas-filled chamber enclosed in a glass bulb. The functioning of a lightbulb is based on the principles of electrical resistance and thermal radiation, rather than the mechanical principles of levers.

While levers and lightbulbs both exist as objects, they serve entirely different purposes and operate on different principles. Levers are used for mechanical advantage and force amplification, while lightbulbs are used for generating light through the conversion of electrical energy.

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(a) The signal xa(t) = 3sin(100πt) is a sinusoidal waveform with an amplitude of 3 and a frequency of 100 Hz. The sketch of xa(t) for 0 ≤ t ≤ 30 ms will depict a periodic waveform with 3 complete cycles.

(a) The signal xa(t) = 3sin(100πt) represents a sinusoidal waveform with an amplitude of 3 and a frequency of 100 Hz. Within the time interval of 0 ≤ t ≤ 30 ms, the waveform completes 3 full cycles. Therefore, when sketching xa(t) for this time range, we will observe three peaks of the sinusoidal waveform.

(b) Sampling the continuous-time signal xa(t) with a sampling rate Fs yields the discrete-time signal x(n) = xa(nT), where T = 1/Fs is the sampling period. The frequency of the discrete-time signal is determined by the sampling period T. In this case, since the original signal has a frequency of 100 Hz, the sampling period T will result in a discrete-time signal x(n) that is also periodic with the same frequency of 100 Hz.

(c) To compute the sample values in one period of x(n), we need to determine the number of samples within one period. Since the period of the discrete-time signal is the reciprocal of its frequency, the period of x(n) can be calculated as 1/100 Hz, which is equivalent to 10 ms. On the same diagram as xa(t), we can plot the sample values of x(n) within one period, which will consist of multiple discrete points representing the discrete-time approximation of the continuous signal.

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Answer:

Well Astronomy is study of stars or planets and chemistry is like potions

Explanation:

Providing you with the general process of evaluating the formula. To round the result to two decimal places, apply rounding rules after obtaining the final value.

To evaluate the formula z = p×g^125, we need to substitute the given values of p, g, and n.

Given:

p = 0.25

g = 125

n = 410

First, we need to calculate q× (1-p):

q = 1 - p = 1 - 0.25 = 0.75

Now we can substitute the values into the formula:

z = p × g^125

z = 0.25 × 125^125

Calculating 125^125 would result in an extremely large number that is beyond the capability of this text-based interface. However, providing you with the general process of evaluating the formula:

Calculate p ×g, which in this case would be 0.25 × 125.

Take the result of step 1 and raise it to the power of 125, which represents g^125.

Multiply the value obtained in step 2 by p to find z.

To round the result to two decimal places, apply rounding rules after obtaining the final value.

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Given:

Thermal energy is denoted by W

Chemical energy is denoted by X

Electrical energy is denoted by Y

Kinetic energy is denoted by Z

To find the order of energy while converting bagasse to electricity.

Explanation:

The bagasse has chemical energy stored in it.

The bagasse is burned, so chemical energy gets converted into thermal energy.

The thermal energy gets converted into kinetic energy.

The kinetic results in the motion of electrons.

Thus, producing electrical energy.

Hence, the conversion order is XWZY

The instrument commonly used to measure the mass of an object is a scale or a balance.

Mass is the measure of the amount of matter an object contains. This amount of matter in an object is typically measured in grams (g), kilograms (kg), ounces (oz), or pounds (lbs). The mass of an object is different from its weight, which is the force of gravity acting on an object with mass. Mass is a fundamental property of matter. It is a scalar quantity that describes the amount of matter in an object. The SI unit for mass is the kilogram (kg).

Mass can be measured using a variety of instruments including balances, scales, and mass spectrometers. A balance is an instrument that compares the mass of an object with a known mass, usually calibrated in grams or kilograms. A scale is an instrument that measures weight or mass by means of a spring or a set of calibrated weights. Mass spectrometry is a technique that is used to measure the mass of molecules or atoms by measuring the mass-to-charge ratio of ions. The mass spectrometer is an instrument that is used to perform mass spectrometry. Thus, the instrument used to measure the mass of an object is a scale.

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Higher mass stars tend to have higher temperatures, smaller radii, and bluer colors compared to low mass stars.

The temperature of a star is directly related to its mass. Higher mass stars have more gravitational potential energy, resulting in greater compression and higher core temperatures. These high core temperatures lead to more intense nuclear fusion reactions, releasing a larger amount of energy. Consequently, higher mass stars exhibit higher surface temperatures.

The size or radius of a star is also influenced by its mass. Higher mass stars have stronger gravitational forces, which counteract the outward pressure from nuclear fusion. This equilibrium results in a balance between gravity and pressure, causing the star to be more compact and have a smaller radius compared to low mass stars.

The color of a star is directly linked to its surface temperature. Higher temperature stars emit more energy at shorter wavelengths, including the blue and ultraviolet regions of the electromagnetic spectrum. Hence, higher mass stars with their higher temperatures tend to have bluer colors, while lower mass stars appear redder.

In summary, higher mass stars have higher temperatures, smaller radii, and bluer colors compared to low mass stars due to the interplay of mass, temperature, and stellar structure.

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Answer:

POGGGGGGGGGGGGGGG

Explanation:

Answer:

hsnzbssj

Explanation:

Answer:

4.44 m/s

Explanation:

Since we want the unit to be in m/s (meter per second), we will be converting from 4 kilometers to meter unit and 15 minutes to second unit.

We know that a kilometer equals to 1000 meters. Multiply both sides by 4:

\(\displaystyle{4 \cdot 1 \ \, \sf{km} = 1000 \ \, \sf {m} \cdot 4 }\\\\\displaystyle{4 \ \, \sf{km} = 4000 \ \, \sf {m}}\)

Therefore, 4 kilometers will equal to 4000 meters.

Next, we also know that a minute equals to 60 seconds. Multiply both sides by 15:

\(\displaystyle{15 \cdot 1 \ \, \sf{minute} = 60 \ \, \sf {seconds} \cdot 15 }\\\\\displaystyle{15 \ \, \sf{minute} = 900 \ \, \sf {seconds} }\)

Therefore, 15 minutes will equal to 900 seconds.

Now we have the units in meter and second. We will use the formula of speed to find the rate of change in meter/second. The formula of speed is:

\(\displaystyle{v = \dfrac{s}{t}}\)

where v is speed, s is distance and t is time. We know that distance is 4000 meters and time is 900 seconds. Substitute in the formula:

\(\displaystyle{v = \dfrac{4000 \ \, \sf{meters}}{900 \ \, \sf{seconds}}}\\\\\displaystyle{v = 4.44 \ \, \sf{m/s}}\)

Therefore, her speed is 4.44 m/s

Answer:

Different ions of an element

Explanation:

From the options given, it is only the different ions of an element that can have different electrons.

This is because ions carry charge which could be positive or negative due to a deficit or excess of electrons.

A cation would be formed if there is a deficit of electrons and the atom becomes positively charged, and an anion would be formed if there is an excess of electrons and the atom becomes negatively charged.

For different ions of the same element, the electron number would vary and this would thus lead to each different ion carrying a greater or lesser charge than the other ions of the same element.

Different numbers of electrons occurs in different ions of an element.

Different isotopes of an element have the same number of number of protons and electrons but different number of neutrons.

Different ions of an element have different number of electrons.

For cations, such as;

Thus, we can conclude that different numbers of electrons occurs in different ions of an element.

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Answer:

The answers is A lol

Explanation:

This type of system is a third class lever. FEL where fulcrum, effort and load comes in an arrangement.

Lever  is a simple machine in which the fixed arms are arranged at a fixed point known as fulcrum. There are three types of lever system: first class Lever system, second class lever system and third class lever system. In the first class lever system there is an arrangement like the see saw. In this arrangement the fulcrum is in center and both the arms are like a seesaw. In the second class lever system, output force was between input force and fulcrum. In the third class lever system input force is between output force and fulcrum. 

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In a perfectly elastic collision between a 400g ball moving east at 3.0 m/s and a 300g ball at rest, the first ball's velocity remains 3.0 m/s east, while the second ball's velocity becomes -4.0 m/s west. Kinetic energy is conserved in the collision.

a) In a perfectly elastic collision, both momentum and kinetic energy are conserved. To determine the velocity of the first ball just after the collision, we can use the conservation of momentum:

Initial momentum = Final momentum

(mass of ball 1) × (velocity of ball 1) + (mass of ball 2) × (velocity of ball 2) = (mass of ball 1) × (velocity of ball 1, final) + (mass of ball 2) × (velocity of ball 2, final)

(400 g) × (3.0 m/s) + (300 g) × (0 m/s) = (400 g) × (v1) + (300 g) × (v2)

1200 g·m/s = 400 g × v1

v1 = 3.0 m/s

Therefore, the velocity of the first ball just after the collision is 3.0 m/s toward the east.

b) Similarly, for the second ball, since it was initially at rest, the conservation of momentum equation simplifies to:

(mass of ball 1) × (velocity of ball 1) = (mass of ball 1) × (velocity of ball 1, final) + (mass of ball 2) × (velocity of ball 2, final)

(400 g) × (3.0 m/s) = (400 g) × (v1) + (300 g) × (v2)

1200 g·m/s = 400 g × v1 + 300 g × v2

Since the collision is head-on, the velocity of the second ball will be in the opposite direction to the first ball:

v2 = -4.0 m/s

Therefore, the velocity of the second ball just after the collision is -4.0 m/s (moving toward the west).

c) Yes, kinetic energy is conserved in this collision. In a perfectly elastic collision, both momentum and kinetic energy are conserved. We can calculate the initial kinetic energy and the final kinetic energy to verify if they are equal.

Initial kinetic energy = (1/2) × (mass of ball 1) × (velocity of ball 1)^2 + (1/2) × (mass of ball 2) × (velocity of ball 2)^2

Initial kinetic energy =\((1/2) × (400 g) × (3.0 m/s)^2 + (1/2) × (300 g) × (0 m/s)^2\)

Initial kinetic energy =\(1800 g·m^2/s^2\)

Final kinetic energy = (1/2) × (mass of ball 1) × (velocity of ball 1, final)^2 + (1/2) × (mass of ball 2) × (velocity of ball 2, final)^2

Final kinetic energy =\((1/2) × (400 g) × (3.0 m/s)^2 + (1/2) × (300 g) × (-4.0 m/s)^2\)

Final kinetic energy = \(1800 g·m^2/s^2\)

The initial and final kinetic energies are equal, indicating that kinetic energy is conserved in this collision.

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In the analysis by mass spectrometry, aldehydes, and ketones prefer to fragment by ∝-cleavage, which produces a resonance-stabilized acylium ion.

Aldehydes and ketones are known to experience ∝-cleavage fragmentation during mass spectrometry analysis. A resonance-stabilized acylium ion is created as a result of this fragmentation process, which entails the breaking of a bond close to the carbonyl group (C=O). The stability attained by resonance effects leads to ∝-cleavage fragmentation. The carbonyl group's oxygen atom has a single pair of electrons that can delocalize into the nearby carbon-carbon (C-C) bond. The positively charged acylium ion is created as a result of this resonance stabilization.

The acylium ion produced by ∝-cleavage fragmentation can go through a number of further processes in the mass spectrometer, including rearrangements, eliminations, or more fragmentation, producing recognizable fragment ions. The original aldehyde or ketone component is then recognized from these fragment ions by detection and analysis.

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Answer:

C.

3.4 joules

Explanation:

Answer for Plato and edmentum

Answer:

A) but be sure and read the answer.

Explanation:

If the object does not move at all, (that's an important restriction) the net force = 0. That being so, the acceleration must be 0 as well. But there is no law saying that there cannot be a constant motion and that's why the restriction is important.

The mean free path in the gas is given by the formula: mean free path = (k * T) / (sqrt(2) * pi * d^2 * P), where k is Boltzmann's constant, T is the temperature in Kelvin, d is the diameter of a helium atom.

P is the pressure in atm. The diameter of a helium atom is approximately 2.4 Ångstroms.

The rms speed of the atoms is given by the formula: rms speed = sqrt((3 * k * T) / (m)), where k is Boltzmann's constant, T is the temperature in Kelvin, and m is the mass of a helium atom.

The average energy per atom is given by the formula: average energy per atom = (3/2) * k * T, where k is Boltzmann's constant and T is the temperature in Kelvin.

The mean free path is the average distance an atom travels between collisions. It depends on the temperature, pressure, and size of the atoms.

The rms speed is the square root of the average of the squared speeds of the atoms. It gives an indication of the magnitude of the velocities of the atoms.

The average energy per atom is the average kinetic energy of the atoms in the gas. It depends only on the temperature and is proportional to the absolute temperature.

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Answer:

7.5 m/s2

Explanation:

F = ma

300 = 40 kg (a)

divide both sides by 40 to single out the variable a (acceleration)

300/40 = 7.5 m/s2

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) .

Acceleration is the rate of change of velocity with respect to time.

Mass of the car = 711 kg

Force exerted by the Student 1 = \(F_1\) =  638 N

Force exerted by the Student 2 = \(F_2\) =  573 N

Total force exerted on the car = F  = \(F_1\) + \(F_2\)

F = 638 + 573

F = 1,211 N

As we know that, Force is the product of mass and acceleration i.e.

F = m * a

\(a = \frac{F}{m}\)

a = \(\frac{1211}{711}\)

a = 1.70 \(m/s^{2}\)

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) to push it to a car mechanic.

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Answer:

it is Newtown's third law

Answer:This is Newton's third law of motion

Explanation:

When two surfaces glide past one another, a force known as friction is created.Friction forces that oppose the motion of moving objects cause them to expend energy and slow down.

An object rolls on a surface, creating rolling friction. When two surfaces rub against one another, sliding friction occurs. The deformation of surfaces causes rolling friction. Because tiny surfaces connect, sliding friction occurs.

Therefore, When the child pushes themselves down the slides. As the child is in motion as they are sliding down.

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Answer:When the child pushes themselves down the slides.

Explanation: i think im not sure