FOR 30 POINTS, ANSWER THIS MATH QUESTION!!!!!

Thus, the total surface area of the cereal box is found as - 202 in².

With six faces, twelve edges, and eight vertices, a cuboid is a 3D shape. Its faces are all rectangles.

Due to its uniform cross-section throughout, a cuboid is also a prism. It is referred to as a prism.

Given data:

total surface area of cuboidal cereal box = 2(lb + bh + hl)

total surface area = 2(13 *5 + 5*2 + 2*13)

total surface area = 2*101

total surface area = 202 in².

Thus, the total surface area of the cereal box is found as - 202 in².

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Correct question:

find the surface area of the cereal box.

Length - 13 in : width - 5 in. height - 2 in.

The total surface area of the cereal box is _____

Answer:

thanks...

Step-by-step explanation:

Answer: I hope it helps :)

Step-by-step explanation:

1.

\(Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}\)

2.

\(Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46} \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23\)

3.

\(Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6\)

4.

\(Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}\)

5.

\(Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y\)

Answer:

Adjacent angles

Step-by-step explanation:

I can't see answer choice D in the photo provided, but the answer would be adjacent due to that fact that angles a and b are right next to each other, without forming a 90 or 180 degree angle.

Answer:

the answer is a

Step-by-step explanation:

all of the lines are vertical

Answer:

Upper Right

Step-by-step explanation:

All of them have different dips, therefore the one facing in a different direction must be the odd one out.

Answer:

top right graph

Step-by-step explanation:

3 of the 4 graphs start at negative infinity for negative x, and approach infinity as x approaches infinity.

The top right graph starts at infinity for negative x and approaches negative infinity as x approaches infinity.

Answer: top right graph

Answer:

heyy! im reaaally sorry if its wrong but I think its c, f, d

brainliest? :)

Step-by-step explanation:

Answer:

7= D

8= F

9= C

Step-by-step explanation:

7. x - 3 \(\leq\) 7

     +3     +3

x \(\leq\) 10

8. 3b < 18

   /3       /3

    b < 6

9. \(\frac{y}{3}\) > 9

  *3    *3

 y > 27

10- 12 I am so sorry, but I don't understand these functions lol

(i) To find the solution for yt in the given equation yt = yt−1 + εt + 0.3εt−1, we can rewrite it as yt - yt−1 = εt + 0.3εt−1. By applying the lag operator L, we have (1 - L)yt = εt + 0.3εt−1.

Solving for yt, we get yt = (1/L)(εt + 0.3εt−1). The solution for yt involves lag operators and depends on the values of εt and εt−1.  (ii) For the equation yt = 1.2yt−1 + εt, to find the s-step-ahead forecast Et[yt+s], we can recursively substitute the lagged values. Starting with yt = 1.2yt−1 + εt, we have yt+1 = 1.2(1.2yt−1 + εt) + εt+1, yt+2 = 1.2(1.2(1.2yt−1 + εt) + εt+1) + εt+2, and so on. The s-step-ahead forecast Et[yt+s] can be obtained by taking the expectation of yt+s conditional on the available information at time t.

To make this model stationary, we need to ensure that the coefficient on yt−1, which is 1.2 in this case, is less than 1 in absolute value. If it is greater than 1, the process will be explosive and not stationary. To achieve stationarity, we can either decrease the value of 1.2 or introduce appropriate differencing operators.

(iii) For the equation yt = yt−1 + t + εt, finding the solution for yt and the s-step-ahead forecast Et[yt+s] involves incorporating the time trend t. By recursively substituting the lagged values, we have yt = yt−1 + t + εt, yt+1 = yt + t + εt+1, yt+2 = yt+1 + t + εt+2, and so on. The s-step-ahead forecast Et[yt+s] can be obtained by taking the expectation of yt+s conditional on the available information at time t.

To make this model stationary, we need to remove the time trend component. We can achieve this by differencing the series. Taking first differences of yt, we obtain Δyt = yt - yt-1 = t + εt. The differenced series Δyt eliminates the time trend, making the model stationary. We can then apply forecasting techniques to predict Et[Δyt+s], which would correspond to the s-step-ahead forecast Et[yt+s] for the original series yt.

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Answer: 9

Step-by-step explanation: 3 is one half of the line and x-1 is the other. 2x-5 is the whole line so 3+x-1=2x-5 is our equation. Solve for x and you get 7. Then replace x with 7 in 2x-5 and you will get an answer of 9.

The numerical length of LN is 7 units.

It is required to determine the numerical length of LN.​

The midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints. It bisects the segment.

Given :

Point M is on line segment LN.

LM = 3

LN = 2x-5

MN = x-1

Use the Segment Addition Postulate:

L------------M--------------------------N

LM + MN = LN

3 + x-1 = 2x-5

2+5=2x-x

7=x

Hence, the numerical length of LN is 7 units.

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Step-by-step explanation:

cos(81) = x/sqrt(7)

x = sqrt(7)×cos(81) = 0.413886691...

(a) The open interval (0, 1) on the real number line. (b)  The complement of the open interval (0, 1) on the real number line. (c) The set {-6, -3, -2, -1, 1, 2, 3, 6}. (d) The set {..., -12, -6, 0, 6, 12, ...}.

a. "The set of all x in the real numbers such that x is greater than 0 and less than 1."

b. "The set of all x in the real numbers such that x is less than or equal to 0 or x is greater than or equal to 1."

c. "The set of all n in the integers such that n is a factor of 6."

d. "The set of all n in the integers such that n is a multiple of 6."

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Answer:

2/3

Step-by-step explanation:

x+ 2/x=4x

x² + 2 = 4x²

2 = 4x - x²

2 = 3x²

2/3 = 3/3x²

⅔ = x²

Consider the prime factorization of 20!.

\(20! = 20 \times 19 \times 18 \times \cdots \times 3 \times 2 \times 1\)

The LCM of 1, 2, ..., 20 must contain all the primes less than 20 in its factorization, so

\(M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times m\)

where \(m\) is some integer not divisible by any of these primes.

Compare the factorizations of the remaining divisors of 20!, and check off any whose factorizations are already contained in the product of primes above.

\(4 = 2^2\) - missing a factor of 2

\(6 = 2\times3\) - ✓

\(8 = 2^3\) - missing a factor of 2²

\(9 = 3^2\) - missing a factor of 3

\(10 = 2\times5\) - ✓

\(12 = 2^2\times3\) - missing a factor of 2

\(14 = 2\times7\) - ✓

\(15 = 3\times5\) - ✓

\(16 = 2^4\) - missing a factor of 2³

\(18 = 2\times3^2\) - missing a factor of 3

\(20 = 2^2\times5\) - missing a factor of 2

From the divisors marked "missing", we add the necessary missing factors to the factorization of \(M\), so that

\(M = 2 \times 3 \times 5 \times 7 \times 11 \times 13 \times 17 \times 19 \times 2^3 \times 3\)

Then the LCM of 1, 2, 3, …, 20 is

\(M = 2^4 \times 3^2 \times 5 \times7 \times 11 \times 13 \times17 \times 19\)

\(\implies \boxed{M = 232,792,560}\)

The polygon given, based on the vertices of the points on the polygon, is not a parallelogram.

Parallelograms are such that there are two vertical parallel lines and two horizontal parallel lines. What this means is that two points on the parallelogram will share the same position on the x axis, and the other two points will share the position on the y - axis.

For instance, the vertices of a parallelogram would be P(−4,0), Q(0,4), R(4,0), and S(0,−4) where you see that two points share the same x coordinates and two share the same y coordinates.

This is not the same with W(-7,-4), X(1,-6), Y(5,-13), Z(1,-12) so this is not a parallelogram.

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According to the question, the region is bounded by the curve with the given data as \(x = y^{3} , x=1, y=0.\)

To compute the volume of the solid, use the disk method. The given object is rotated along the horizontal axis with the disk cross sectional area and the volume can be written as:

\(v=\int\limits^a_b {\pi x^{2} } \, dx\)

As per question, when x = 1 then the value of y is: y = 1

Now, substituting calculated values in the expression:

\(v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx\)

Substitute the value of the variable 'x':

Therefore, the expression can be written as:

\(v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx=\int\limits^0_1 {\pi (y^{3}) ^{2} } \, dx=\frac{\pi }{7}=0.448\)

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Mate's car can travel approximately 5 more minutes per gallon of gas compared to Jenna's car.

To determine how many more minutes Mate's car can travel per gallon of gas compared to Jenna's car, we would need additional information about the fuel efficiency or miles per gallon (MPG) for each car.

Fuel efficiency is typically measured in terms of miles per gallon, indicating the number of miles a car can travel on a gallon of gas.

To calculate the difference in travel time, we would also need to know the average speed at which the cars are traveling.

Once we have the MPG values for Mate's car and Jenna's car, we can calculate the difference in travel time per gallon of gas by considering their respective fuel efficiencies and average speeds.

If Mate's car has a fuel efficiency of 30 MPG and Jenna's car has a fuel efficiency of 25 MPG, we can calculate the difference in travel time by comparing the distances they can travel on a gallon of gas.

Let's assume both cars are traveling at an average speed of 60 miles per hour.

For Mate's car:

Travel time = Distance / Speed

= (30 miles / 1 gallon) / 60 miles per hour

= 0.5 hours or 30 minutes.

For Jenna's car:

Travel time = Distance / Speed

= (25 miles / 1 gallon) / 60 miles per hour

= 0.4167 hours or approximately 25 minutes.

Without specific information about the MPG values and average speeds of the cars, it is not possible to provide an accurate answer regarding the difference in travel time per gallon of gas between Mate's car and Jenna's car.

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In a simplified algebraic expression, the addition or subtraction operations determine the number of terms.

An algebraic expression is a mathematical phrase that can contain variables, constants, and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation.

Algebraic expressions can be simple or complex and can involve one or more variables.

In a simplified algebraic expression, the addition or subtraction operations determine the number of terms.

Each term in an algebraic expression is separated by either a plus (+) or minus (-) sign. For example, in the expression 3x + 2y - 5z, there are three terms: 3x, 2y, and -5z.

The multiplication and division operations do not affect the number of terms, but they can affect the complexity of each term. For example, in the expression 4xy + 6x/2 - 2z/3, there are still three terms, but the second and third terms have additional multiplication and division operations that make them more complex than the first term.

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8/10 = 0.8

Therefore, 0.8 (8/10) is put on the number line shown below.

For u = 3 mm and standard deviation o = 0.05 mm., (a) the sample size is 16 the standard error is 0.0125 mm. (b)  2.9625 mm (c) 3. (d) z=4.

a) The sampling distribution of the sample mean m follows a normal distribution. Since the population distribution of the coating thickness is normal with mean u = 3 mm and standard deviation σ = 0.05 mm, the sampling distribution of the sample mean m will also be normal with the same mean u = 3 mm but with a standard deviation equal to the population standard deviation divided by the square root of the sample size. In this case, the sample size is 16, so the standard deviation of the sampling distribution, often referred to as the standard error, will be σ_m = σ / \(\sqrt{n}\) = 0.05 / \(\sqrt{16}\)) = 0.05 / 4 = 0.0125 mm.

b) To compute 3 + 3 * σ_m and 3 - 3 * σ_m:

3 + 3 * σ_m = 3 + 3 * 0.0125 = 3 + 0.0375 = 3.0375 mm

3 - 3 * σ_m = 3 - 3 * 0.0125 = 3 - 0.0375 = 2.9625 mm

c) To find the probability that m will be outside 3 + 3 * σ_m and 3 - 3 * σ_m just by chance, we need to calculate the area under the sampling distribution curve outside this range. Since the sampling distribution follows a normal distribution, we can use z-scores to calculate this probability.

The z-score corresponding to 3 + 3 * σ_m can be calculated as (3.0375 - 3) / σ_m = 0.0375 / 0.0125 = 3.

The z-score corresponding to 3 - 3 * σ_m can be calculated as (3 - 2.9625) / σ_m = 0.0375 / 0.0125 = 3.

Using a standard normal distribution table or a calculator, we can find the probability associated with a z-score of 3 or greater. The probability of being outside 3 + 3 * σ_m and 3 - 3 * σ_m just by chance is given by P(Z > 3) + P(Z < -3).

d) When the mean coating thickness is 3.05 mm, we want to find the probability that a problem will be detected when the next sample is taken, which occurs if m > 3 + 3 * σ_m or m < 3 - 3 * σ_m when u = 3.05.

To calculate this probability, we need to find the z-score corresponding to 3 + 3 * σ_m using the adjusted mean u = 3.05:

z = (3.05 - 3) / σ_m = 0.05 / 0.0125 = 4.

Using a standard normal distribution table or a calculator, we can find the probability associated with a z-score of 4 or greater, which represents the probability of detecting a problem when the next sample is taken.

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Therefore , the algebra is derived from Islam word  Arabic al‐jab used by its  founder.

Mathematical branch known as algebra deals with symbols and the rules governing their manipulation. These characters, which are now expressed as Latin and Greek letters, stand for variables, or quantities without set values, in elementary mathematics. Similar to how sentences illustrate the connections between particular words, in algebra,

Here,

The word algebra is derived from the Arabic word al‐jabr, which its creator, Muhammad ibn Mūsā al‐Khwārizmī, used in the title of his work.

Al-Jabr wa-l-muqbalah, which dates to the ninth century (The Science of Equations and Balancing).

Therefore , the algebra is derived from Islam word  Arabic al‐jab used by its  founder.

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The Policeman’s rate of change is $10 per hour and the firefighter's rate of change is $10 per hour

The Policeman’s rate of change

From the question, we have the following parameters that can be used in our computation:

The graph

On the line of the policeman, we have the following point

(x, y) = (4, 40)

So, the rate of change is

Rate = y/x

This gives

Rate = 40/4

Evaluate

Rate = 10

The firefighter's rate of change

On the line of the firefighters, we have the following point

(x, y) = (4, 60)

So, the rate of change is

Rate = y/x

This gives

Rate = 60/4

Evaluate

Rate = 15

Hence, the rate is $15 per hour

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5.03 x 10²¹ atoms of calcium are equivalent to 8.6 × 10⁻³ moles of calcium atoms.

To convert atoms to moles we need a conversion factor: Avogadro's number. According to Avogadro's number: there are 6.02 × 10²³ calcium atoms in 1 mole of calcium atoms. The number of moles corresponding to 3.00 × 10²¹ atoms of calcium is:

Number of moles = 5.03 x 10²¹ /  6.02 × 10²³

Number of moles = 8.6 × 10⁻³ moles of calcium

5.03 x 10²¹ atoms of calcium are equivalent to 8.6 × 10⁻³ moles of calcium atoms.

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Answer:

8

Step-by-step explanation:

just take the numerator and thats how many

Yes, it is possible to have a 5 × 5 matrix, a, of rank 4 such that the system ax = 0 has only the solution x = 0.

The rank of a matrix refers to the maximum number of linearly independent rows or columns it contains. In this case, we have a 5 × 5 matrix, a, with rank 4. This means that there are four linearly independent rows or columns in matrix a.

For the system ax = 0, where x is a vector of unknowns, having only the trivial solution x = 0 means that there are no other non-zero solutions that satisfy the equation. In other words, the only way to satisfy ax = 0 is by setting all the components of x to zero.

It is possible to construct a 5 × 5 matrix with rank 4 in such a way that the system ax = 0 has only the trivial solution. This can be achieved by carefully selecting the values in the matrix to ensure that the equations are linearly independent, thereby eliminating any non-zero solutions.

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Answer:

e (2,-1)

f (4,-1)

g (5,-4)

h (1,-4)

Answer:

30/3 = 10

he can 10 pieces

Step-by-step explanation:

Answer:

A:1/18 B:1/6 for 4 and 1/3 for red

Step-by-step explanation:

Answer:

22.2 years

Step-by-step explanation:

Doubling formula is given as:

P(t) = Po × (2)^t/k

Where

Po = Initial amount invested = $5600

P(t) = Amount after time t = $72500

k = Time it takes to double = 6 years

t = Time in years = ??

Hence:

72500 = 5600 × (2)^t/6

Divide both sides by 5600

72500/5600 =( 5600 × (2)^t/6)5600

12.946428571 = (2)^t/6

Take the In of both sides

In 12.946428571 = In (2)^t/6

In 12.946428571 = t/6 In (2)

Divide both sides by In 2

In 12.946428571/In 2 = t/6

3.6944822628 = t/6

Cross Multiply

t = 6 × 3.6944822628

t = 22.166893577 years

Approximately

t = 22.2 years

Therefore, it would take 22.2 years

It will take 15 days for Akash to complete the entire work if he is assisted by Sunil and Rakesh every third day.

To determine the number of days, we first represent the number of days to do a piece of work by each one of them in fractions as follows;

Fraction of work completed by Akash in 1 day = 1/20

Fraction of work completed by Sunil in 1 day = 1/30

Fraction of work completed by Rakesh in 1 day = 1/60

The total work done in 1 day can be given as;

Total work done by the three in one day = [(1/20) + (1/30) + (1/60)] = 1/10

Work done by Akash in two days = 2 × (1/20) = 2/20 = 1/10

The work done in three days (1 day of all three together + Work done by Akash in two days) = (1/10) + (1/10) = 1/5

Therefore; the total work done in 3 days = 1/5

At this rate, the total number of cycles required to finish the work =

(1) ÷ (1/5) = 5

Since each cycle has three days, the total number of days required to finish the work can be calculated as follows;

5 × 3 = 15 days

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