Which of the following is/are true about magnetic field lines? *
Points away from the south pole and toward the north pole
Uniformly intersect other magnetic field lines
They present the direction and not the force of the magnetic field
They represent the strength of the magnetic field
All of the above
None of the above
Answer:
Explanation:
Interest to
Answer:
Points away from the south pole and toward the north pole
Explanation:
They're magnets fam
idling gas-powered vehicles after starting and before driving away is select one: a. is illegal in maryland if the vehicle is unattended and is not necessary. b. recommended because it allows the vehicle to come to operating temperature before driving away. c. recommended to make sure the vehicle is ready to drive. d. not recommended because it may cause the car to overheat.
If the car is unattended and it is not necessary, it is illegal in Maryland to leave a gas-powered vehicle idling after starting it and before leaving.
While turning, a motorist should be sure to stay in the same lane and keep an eye out for other vehicles. Remember to turn off the signal and let the steering wheel return to center after making the turn. Turning it off can help you conserve gasoline and cut down on carbon dioxide emissions, unless you drive a classic automobile with a carburetor. Our research has shown that drivers can save fuel and cut pollutants by shutting down for periods as little as 10 seconds. Some drivers believe that idling burns less fuel than resuming. and cut pollutants by shutting down for periods as little as 10 seconds. Some drivers believe that idling burns less fuel than resuming.
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Which of the following statements does NOT describe force?
A.Force causes objects to change direction.
B.Force causes objects to start moving.
C.Force causes objects to stop moving.
D.Force causes objects at rest to remain stationary.
Answer: D
Explanation: Force can do everything else.
Answer:
D. Force causes objects at rest to remain stationary.
Explanation:
what units is time measured in
Answer:
The base unit for time is the second (the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance). The second can be abbreviated as s or sec.
Explanation:
a service main at the end of a street decreases in diameter from 12 to 4 inches. if the flow rate is 4 ft/s and the pressure at point 1 is 50 psi
The amount of fluid that moves past a point in area A per unit of time is known as the flow rate.
How do you find average velocity from flow rate?The amount of fluid that moves past a point in area A per unit of time is known as the flow rate. Here, a uniform pipe carrying the shaded fluid cylinder passes point P in time t. The cylinder's capacity is Ad, its average velocity is v=d/t, and its flow rate is Q=Ad/t=Av.The average fluid velocity for laminar flow through a pipe is equal to half of the fluid's greatest velocity at the pipe's center. The Hagen-Poiseuille equation is shown above. Since there is no acceleration in a steady and uniform flow, there is no force acting in the direction of the flow.To learn more about fluid velocity refer,
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What happens if we nuke a city?
Answer:
Those who survived the bomb may become deaf or blind, as well as suffer catastrophic burns and injuries. Even people who were not seriously injured could become trapped within a structure or unable to navigate through the wreckage.
Explanation:
An object has a mass of 10 kilograms and is accelerating at 5 m/s/s, what force pushed the object?
Answer:
hope helps
Explanation:
In a weightless environment a force of 5 Newtons is applied horizontally to the right on a rock with a mass of 1 kg and to a pebble with a mass of 0.1 kg.
Answer: 2km/m/s/s
Explanation:
10km divided by 5m/s/s = 2km/m/s/s
HELP HW!!!!! IF U CAN SOLVE ONE AT LEAST I WILL CROWN U BRAINLIEST ( I’m so bad at this plz helppp)
Answer:
Q = I * t = 2 Coulomb / sec * 1000 sec = 2000 Coulombs transferred
E (energy) = V * Q = I * t * 240 V
E = 240 J / Coul * 2000 Coul = 480,000 Joules
Next question:
Total voltage drop in circuit = 6.5 V + 4.5 V = 11 V
So the power supply must supply 11 V
I need help please help
Answer:
29 Joules
Explanation:
58N * 0.5m =
58 * 0.5 =
58 * 5/10 =
290/10 = 29 Joules
What does Newton's law all about?
A cyclist covers 950 m in 5 minutes. Find his speed in km/ hour
The speed of the cyclist is = 11.4km/hr
From the cross ab/ab x ab/ab, what is the recombination frequency if the progeny numbers are 72 ab/ab, 68 ab/ab, 17 ab/ab, and 21 ab/ab?.
To calculate the recombination frequency, we need to determine the number of recombinant progeny (ab/ab) divided by the total number of progeny. Therefore, the recombination frequency in this case is 100%.
Given:
Number of progeny with ab/ab genotype = 72 + 68 + 17 + 21 = 178
Total number of progeny = 72 + 68 + 17 + 21 = 178
Recombination frequency = (Number of recombinant progeny / Total number of progeny) × 100%
Recombination frequency = (178 / 178) × 100%
Recombination frequency = 100%
Therefore, the recombination frequency in this case is 100%.
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Help please! Will give brainliest to first correct answer!
Answer:
1) Addition of a catalyst
2) To change the reaction rate of slope B to look like slope A, simply add a catalyst to speed up the rate of reaction, giving you a higher amount of products in a shorter amount of time (line A)
Explanation:
1 and 2)Two things can alter the rate of a reaction, either the addition of a catylist which will not alter the composition of the products or reactants, but will accelerate the reaction time, or an increase in temperature will also increase the rate at which a reaction will occur.
You could choose temperature also and have the same result, it's your choice both are correct, but catalyst is the easiest.
if tou were to become a scientist what will be your contribution to the society? why?
when an object is located 36 cm to the left of a lens, the image is formed 22 cm to the right of the lens. part a what is the focal length of the lens?
The focal length of the lens when the object is at 36 cm from the lens on the left and the image is at 22cm towards the right is 13.6 cm.
In optics, the relationship between the distance of the image (v), the distance of the object (u), and the focal length (f) of the lens are given by the formula known as the Lens formula. The Lens formula is applicable for convex as well as concave lenses. These lenses have negligible thickness.
The position of the object,u= 36cm to the left of the lens.
The position of the image, v= 22 cm to the right of the lens.
According to the sign convention, if we take the direction in which the ray of light goes as the positive direction. Then u=-36cm and v=+22cm.
Now from the lens formula, 1/f=1/v-1/u, 1/f= 1/22-(-1/36), 1/f= 1/22+1/36=(36+22)/36×22 =58/792. f= 792/58 = 13.6 cm.
The focal length of the lens is 13.6cm.
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A Eureka can of mass 60g and cross sectional area of 60 square centimeters is fillied with water of density 1g/ cubic centimeters. A piece of steel of mass 20g and density 8g/ cubic centimeters is lowered carefully into the can.
(a) Calculate the total mass of water and the Eureka Can before the metal was lowered.
(b) Calculate the volume of the water that overflowed.
(c) Calculate the final mass of the Eureka Can and its contents.
a.600 cm³
b. 2.5 g/cm³
c. 2.0775 kg
What is Eureka moment?
In Physics, this Archimedes' Eureka moment is called the Archimedes Principle, which states that when a body is immersed in a liquid, it experiences an upward buoyant force, which is equal to the weight of the liquid displaced by the body.
According to the question
Mass of Eureka is 60g
Cross sectional area is 60 square centimeters
Mass of steel piece is 20g
Density = 8g /cubic centimeter
a)The total mass of the can before the metal was lowered we need to add the mass of the eureka can and the mass of the water in the can.
To find the mass of the water but we can easily find if we know the volume of the can.
In order to calculate the volume we would have to multiply the area of the cross section by the height.
Here,
60cm² x 10cm = 600 cm³
To find the mass that water has in this case we have to multiply the water's density by the volume,
so we get....
\(\frac{1g}{cm^3}\) x 1000 = 1000g or 1kg
Now can calculate the total mass of the can before the metal was lowered, by adding the mass of the water to the mass of the can.
So we get....
1000g + 60g = 1060g or 1.06kg
b)The volume of the water that over flowed will be equal to the volume of the metal piece since, when we add the metal piece, the metal piece will force out the same volume of water as itself, to understand this more deeply you can read the about "Archimedes principle".
Knowing this we just have to calculate the volume of the metal piece an that will be the answer.
So this time in order to find volume we will have to divide the total mass of the metal piece by its density.
So we get
20g ÷ \(\frac{8}{cm^3}\) = 2.5 g/cm³
c)Now to find out the total mass of the can after the metal piece was lowered we would have to add the mass of the can itself, mass of the water inside the can, and the mass of the metal piece.
We know the mass of the can, and the metal piece but we don't know the mass of the water because when we lowered the metal piece some of the water overflowed, and as a result the mass of the water changed. So now we just have to find the mass of the water in the can keeping in mind the fact that 2.5 overflowed.
So now we the same process as in number a) just with a few adjustments.
\(\frac{1g}{cm^3}\) x (1000 - 2.5) = 997.5g
So now that we know the mass of the water in the can after we added the metal piece we can add all the three masses together (the mass of the can.
The mass of the water, and the mass of the metal piece.
Hence,
1060g + 997.5g + 20g = 2077.5 g or 2.0775 kg
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A satellite is in circular orbit about the Earth at an altitude at which air resistance is negligible. Which of the following statements is true?
a. There is only one force acting on the satellite.
b. There are two forces acting on the satellite, and their resultant is zero.
c. There are two forces acting on the satellite, and their resultant is not zero.
d. There are three forces acting on the satellite.
e. None of the preceding statements are correct.
Answer:
the correct statement is: "There is only one force acting on the satellite."
The true statement is There are two forces acting on the satellite, and their resultant is not zero.(C)
In a circular orbit with negligible air resistance, there are two forces acting on the satellite: gravitational force and centripetal force.
Gravitational force pulls the satellite towards the Earth, while centripetal force keeps it moving in a circular path. These forces are not equal and opposite, so their resultant is not zero.
The gravitational force provides the necessary centripetal force for the satellite to remain in orbit, maintaining a balance between these forces.(C)
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what is the volume of water in a 250 cylinder at 0.9999 density
The volume of water in the 250 mL cylinder is approximately 249.975 mL.
To calculate the volume of water, we multiply the density of water by the volume of the cylinder.
Given:
Density of water = 0.9999 g/mL
Volume of the cylinder = 250 mL
The formula for calculating the volume of a substance is:
Volume = Mass / Density
Since we are given the density and we want to find the volume, we rearrange the formula as:
Volume = Mass / Density
The mass can be obtained by multiplying the density by the volume:
Mass = Density * Volume
Substituting the given values:
Mass = 0.9999 g/mL * 250 mL
Simplifying, we get:
Mass = 249.975 g
Therefore, the volume of water in the 250 mL cylinder is approximately 249.975 mL.
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A basketball and a bowling ball are relatively the same size or volume. Explain which ball is denser and why.
Answer:
The Bowling Ball is Denser.
Explanation:
If we consider both balls in terms of mass they are very different. Size and volume can be the same though.
What makes the mass? Think of what fills each of the balls.
A Basketball is filled with air, which weighs very little.
Meanwhile, a bowling ball is filled with coverstock, made up of plastic, urethane and resin. These materials weigh considerably more than air!
Why is light wave not considered a mechanical wav?
A.A light wave is visible to humans.
B.A light wave moves faster than most waves.
C.A light wave does not have a wavelength.
D.A light wave travels through the vacuum of space.
The correct option is D)A light wave travels through the vacuum of space.
Light waves don't require a medium for their propagation. It can travel through a vacuum such as the empty parts of external space. But unlike sound waves or water waves, it does not need any matter or material to carry its energy along its transmission. Hence, it is a non-mechanical wave.
Light contains packets of energy and transfers via electromagnetic waves. Unlike mechanical waves, which require matter and medium, electromagnetic waves can travel through empty spaces and liquids, solids, and gases. Another familiar wave as light is a sound wave which is a mechanical wave as it requires the mode of transmission.
Therefore light is an electromagnetic wave.
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a 10-mev y-ray enters a volume v and undergoes pair production, thereby disappearing and giving rise to an electron and positron of equal energies. the
When a 10 MeV gamma-ray undergoes pair production in a given volume V, it results in the creation of an electron and a positron, both having equal energies of approximately 10 MeV.
Given that a 10 MeV gamma-ray undergoes pair production in volume V, it results in the creation of an electron and a positron with equal energies.
Pair production is a phenomenon where a gamma-ray photon, which is a high-energy photon, interacts with an atomic nucleus or an electron and converts its energy into the mass of an electron-positron pair. This process requires a minimum threshold energy, typically around 1.02 MeV, to produce an electron-positron pair.
In this case, the 10 MeV gamma-ray exceeds the threshold energy required for pair production. As a result, the gamma ray disappears and is transformed into an electron and a positron, both having equal energies. The energy of each particle will be approximately 10 MeV, as the total energy of the gamma-ray is conserved in the process.
It's important to note that pair production requires an atomic nucleus or an electron to interact with the gamma ray. The volume V mentioned in the question could refer to the specific region or medium where this interaction occurs, such as a target material or a radiation detector.
Overall, when a 10 MeV gamma-ray undergoes pair production in a given volume V, it results in the creation of an electron and a positron, both having equal energies of approximately 10 MeV.
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A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the box on the plank and gradually raises one end of the plank. When the angle of inclination with the horizontal reaches 31o, the box starts to slip, and it then slides 3.7 m down the plank in 2.5 s at constant acceleration. What are (a) the coefficient of static friction and (b) the coefficient of kinetic friction between the box and the plank
a) The coefficient of static friction is 0.6
b) The coefficient of kinetic friction between the box and the plank is 0.45.
Given information,
Angle of inclination = 31⁰
Distance, d = 3.7 m
time, t = 2.5 s
a) To calculate the coefficient of static friction
The force acting on an object at rest is known as static friction. When we attempt to move an object that is at rest, we must apply force in order to remove static friction and allow the object to move.
μ = tanθ
μ = tan(31⁰)
μₐ = 0.6.
the coefficient of static friction is 0.6.
b) Kinetic friction is the force that acts between two moving surfaces.
From Newton's second law of motion,
μ = gsinθ - (2d/t²)/gcosθ
μ = (9.8×0.515-1.184)/8.4
μ = 0.45
The coefficient of kinetic friction between the box and the plank is 0.45.
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For a parallel-plate capacitor the energy density is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?.
No. this is not true for a spherical capacitor.
A spherical capacitor can be thought of as what is shown in the attached figure.That phenomenon for the parallel plate capacitor occurs because of the sudden change in the electric field intensity. Between the plates, the electric field intensity is constant and uniform and that uniformity changes at the edges.Such a uniform field intensity is not found in a spherical capacitor.The field at a given distance from the sphere is a function of that distance so it changes from place to place.So the energy density is not uniform in a region between 2 spherical surfaces.Therefore, what is true for spherical capacitors is that the energy density is like that at the edges of a parallel plate capacitor.#SPJ4
Imagine you are making a Greek salad with cucumbers, tomatoes, olives, feta, and lettuce. What kind of cut would you use for each of these ingredients? Why?
To prepare a Greek salad, different types of cut must be used to cut these ingredients depending on the ingredient.
In culinary there are different types of cuts depending on the cooking or the presentation that you want to give the dish. For example, in the case of Greek salad, all the ingredients are required to be cut in such a way that the bites are suitable for the size of the mouth.
Therefore, the cutting technique for each ingredient is:
Cucumbers - Julienne (thin and long strips)Tomatoes - Brunoise or chopped (small squares)Olives - chopped (split in half)Feta cheese - Brunoise or minced (small squares)Lettuce - Chiffonade (flat and elongated strips)the Greek salad looks like the image below:
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The distance is 10 meters. What is the variable?
you are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. you instantly start running toward the still-open door at 5.7 m/s.
a) It takes you 1.893s to reach the opened door and jump in.
b) The maximum time that you can wait before starting to run and still catch the bus is 1.27s
The time which the passenger can delay and still catch the bus must be less than this.
From the question:
Distance between the passenger and the door of the bus d = 9
Acceleration of the bus a¹ = 1.0m/s²
Speed of the passenger v = 5.7m/s
Time taken for you to catch up with the bus must occur at the exact position with the bus,
Let the position = y
The time taken for you to reach the point:
t = total speed/distance
t = y + 9/5.7 ..................... eqn 1
The time taken for the bus to reach the same point;
y = vt + 1/2at²
Initial velocity of the bus is zero
y = 0.5*(1)t²
y = t²/2
t = √2y .......................eqn 2
We solve eqn (1) and (2) together:
9 + y = 5.7 * √2y
81 + y² + 18y = 64.98y
y² - 46.98y + 81 = 0
y = 45.187m or 1.792m
Now we take the smallest distance: x=1.792 m
Time taken for both to reach this point: (put x in eq. (1))
t = 1.792+9/5.7
t = 1.893s
For the maximum waiting time we find have:
Relative acceleration, ar = -1m/s⁻²since the bus is moving away from the intended
The final relative velocity for the passenger to catch it, vr = 0m/s⁻¹
Using equation of motion:
s = 9 + 1/2 * (-1)t²
also the initial relative velocity:
vr = ur + ar.t
ur = 5.7 - t
and
vr² = ur² + 2ar.s
0² = (5.7 - 1)² - 2 * 1 * (9 - 0.5t²)
t = 1.27s
Here's the complete question:
You are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. You instantly start running toward the still-open door at 5.7 m/s.
How long does it take for you to reach the open door and jump in?
What is the maximum time you can wait before starting to run and still catch the bus?
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A 2.0 kg 2.0kg2, point, 0, start text, k, g, end text cart moving right at 5.0 m s 5.0 s m 5, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction on a frictionless track collides with a 3.0 kg 3.0kg3, point, 0, start text, k, g, end text cart initially at rest. The 2.0 kg 2.0kg2, point, 0, start text, k, g, end text cart has a final speed of 1.0 m s 1.0 s m 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction to the left. What is the final speed of the 3.0 kg 3.0kg3, point, 0, start text, k, g, end text cart?
The final speed of the 3.0 kg cart is 4 m/s.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
The external force is not acting here, so the initial momentum is equal to the final momentum. For elastic collision, final velocities is different for both the bodies.
m₁u₁ +m₂u₂ = m₁v₁ +m₂v₂
A 2.0 kg cart moving right at 5.0 m/s on a frictionless track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 m/s to the left.
Substitute the values for m₁ = 2kg, m₂ =3kg, u₁ =5 m/s and u₂ =0 m/s, then the final velocity will be
3x0 +2x5 = -2x1 + 3v₂
v₂ = 4 m/s
Thus, the the final velocity 3.0 kg cart is 4 m/s.
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Need help ASAP please and thank you
Answer:
253
Explanation:
He stands at 50 so you keep counting by 50 until you get it to add three.
Calculate the value of C2 in the circuit below, if C1 = 33 F and Ctotal = 58 F.
The value of capacitor C2 in the given parallel circuit arrangement of the capacitors is 25 F.
Capacitance of the circuit
The capacitance of the circuit is calculated as follows.
Assuming a parallel circuit arrangement for the capacitors;
C(total) = C1 + C2
58 F = 33 F + C2
C2 = 58 F - 33 F
C2 = 25 F
Thus, the value of capacitor C2 in the given parallel circuit arrangement of the capacitors is 25 F.
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7. Navy use SONAR method to locate the position of submarine under water. The waves used in SONAR are A transverse waves. B electromagnetic waves. C. audible to human ear. D.audible to navy only.
Answer:
A. transverse waves
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