The expression of v in terms of m1, m2, and the cars' initial speeds v1 and v2 during a collision would be (m1*v1 + m2*v2) / (m1 + m2).
Determining the magnitude of speed:
To find the speed of the two-car unit after the collision, we need to use the conservation of momentum principle, which states that the total momentum of the system remains constant before and after the collision.
Let m1 and m2 be the masses of the two cars, and v1 and v2 be their initial speeds before the collision. Let v be the speed of the two-car unit after the collision.
The initial momentum of the system is:
p_initial = m1*v1 + m2*v2
After the collision, the two cars stick together, so they move as one unit. The final momentum of the system is:
p_final = (m1 + m2) * v
According to the conservation of momentum principle, these two momenta are equal:
p_initial = p_final
m1*v1 + m2*v2 = (m1 + m2) * v
Solving for v, we get:
v = (m1*v1 + m2*v2) / (m1 + m2)
Therefore, the magnitude of v is given by the above equation. It depends on the masses of the two cars and their initial speeds before the collision.
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a student uses a string to pull her 2.0 kg physics book, starting from rest, across a 2.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string? a student uses a string to pull her 4.0 kg physics book, starting from rest, across a 2.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string? a student uses a string to pull her 4.0 kg physics book, starting from rest, across a 4.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 8.0 m/s , what is the tension in the string? a student uses a string to pull her 2.0 kg physics book, starting from rest, across a 4.0- m -long lab bench. the coefficient of kinetic friction between the book and the lab bench is 0.15. if the book's final speed is 4.0 m/s , what is the tension in the string?
The calculated tension is 500 N. The direction of pulling is pull and is named tension. Therefore, tension points away from the mass in the direction of the cord/rope.
In hanging weights, the string/rope exerts an upward force on the weight as the string pulls the weight upwards. This is the force generated when a load is applied to the edge of an object, usually its cross section. Also called tensile force, tension, or tension. This type of force is only applied when the cable and object are in contact. Tension also allows power to be transmitted over relatively long distances.
mg= 50 *10
=500 N
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what is a similarity between magnetic force and gravitational force
Both magnetic force and gravitational force are fundamental forces that operate at a distance. Both forces obey an inverse square law in terms of distance, which means that the force becomes weaker as the distance between the two objects increases.
Magnetic force and gravitational force are two distinct forces, however, they do have a common similarity. They are both basic forces that operate at a distance. Both forces obey an inverse square law in terms of distance, which means that the force becomes weaker as the distance between the two objects increases.
Magnetic force is generated by the motion of electric charges, while gravitational force is generated by the mass of an object. The interaction between two objects is given by the product of their masses and the inverse square of the distance between them in the case of gravitational force.
The interaction between two magnetic objects, on the other hand, is determined by the distance between them, the magnitude of their magnetic field, and their magnetic moment, which is a measure of the strength of the magnetic field.
The force between two magnetic objects is proportional to the product of their magnetic moments and the inverse square of the distance between them. Because both magnetic force and gravitational force obey an inverse square law, they both result in an attractive force between two objects. The strength of the force varies as the distance between the objects changes.
In conclusion, the similarity between magnetic force and gravitational force is that they are both fundamental forces that operate at a distance and obey an inverse square law in terms of distance.
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A 0. 40-kg mass is attached to a spring with a force constant of
k = 247 N/m,
and the mass–spring system is set into oscillation with an amplitude of
A = 3. 0 cm. Determine the following. (a) mechanical energy of the system
The mechanical energy of the system is 0.03 J. the mechanical energy of an oscillating system is the sum of its kinetic energy and potential energy. At the maximum displacement (amplitude), all the energy is potential energy, and at the equilibrium position, all the energy is kinetic energy.
Given:
Mass (m) = 0.40 kg
Force constant (k) = 247 N/m
Amplitude (A) = 3.0 cm = 0.03 m (converted to meters)
At the maximum displacement, the potential energy (PE) is maximum, and the kinetic energy (KE) is zero. The potential energy can be calculated using the formula PE = (1/2)kA^2.
PE = (1/2)(247 N/m)(0.03 m)^2
= 0.0369 J
At the equilibrium position, the potential energy is zero, and the kinetic energy is maximum. The kinetic energy can be calculated using the formula KE = (1/2)mv^2, where v is the velocity at the equilibrium position.
Since the mass-spring system is in simple harmonic motion, the maximum velocity (v) is given by the formula v = ωA, where ω is the angular frequency. The angular frequency can be calculated using the formula ω = √(k/m).
ω = √(247 N/m / 0.40 kg)
= √(617.5 rad/s^2)
≈ 24.84 rad/s
v = (24.84 rad/s)(0.03 m)
= 0.7452 m/s
KE = (1/2)(0.40 kg)(0.7452 m/s)^2
≈ 0.0556 J
The total mechanical energy of the system is the sum of the potential energy and kinetic energy:
Mechanical Energy = PE + KE
= 0.0369 J + 0.0556 J
≈ 0.0925 J
≈ 0.03 J (rounded to two decimal places)
Therefore, the mechanical energy of the system is approximately 0.03 J.
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If a bus travel 200 km in 45 minutes calculate the speed kilometer per second
Answer:
0.07km/s
Explanation:
The question asks you to find the speed in kilometres per second.
Since your time given is in minutes, convert it to seconds first.
Min to sec = min × 60
use the formula
\(s = \frac{d}{t} \)
speed equals distance over time, using the value for time in seconds.
\(s = \frac{200}{2700} \)
That equates to the answer above.
Crate is being pushed a constant velocity. What forces are being used?
The earth attracts an apple with a force of 15 Newton. taking this as an action force, how much is reaction force? who accepts the reaction force? on which body does a reaction force act?
Answer:
action = reaction
land accepts
reaction force acts on the apple
Answer:
15 Newton
Explanation:
According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)
So,
Action Force = Reaction Force
Reaction Force = 15 N
The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.
17. For how long should a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s?
a. 0.031 s
b. 0.065 s
c. 15.4 s
d. 40 s
Answer:
c. 15.4 s
Explanation:
Given the following data;
Mass, m = 50kg
Force, F = 130N
Initial velocity, u = 20m/s
Final velocity, v = 60m/s
To find the time;
First of all, we would solve for acceleration using the formula below;
Force = mass * acceleration
130 = 50*acceleration
Acceleration = 130/50
Acceleration = 2.6m/s²
Now, we would use the first equation of motion to find the time.
V = U + at
60 = 20 + 2.6t
2.6t = 60 - 20
2.6t = 40
t = 40/2.6
Time, t = 15.39 ≈ 15.4 seconds.
The time taken will be 15.4 seconds approximately. The correct answer is option c
NEWTON SECOND LAW
Newton's second law state that, the rate of change of momentum is proportional to the force applied.
Given that a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s. The given parameters are;
Force F = 130 Nmass m = 50 kgInitial velocity u = 20 m/sFinal velocity V = 60 m/sfrom Newton's second law,
Ft = m(v - u)
Substitute all the parameters into the formula
130t = 50 (60 - 20)
130t = 50 x 40
130t = 2000
t = 2000/130
t = 15.38 seconds
Therefore, the time taken will be 15.4 seconds approximately. The correct answer is option c
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A rocket burns fuel as it shoots into the sky. What happens to the mass and volume of the rocket?
Answer:
mass goes down volume remains the same
why is graffiti important to our community
Answer:Graffiti and street art embody cultural significance through its individualistic nature, though its ability to beautify and enhance public spaces, when you see graffiti you might think to yourself, "dang that looks cool"
Explanation:
a 40 kg child at a playground is swinging back and forth, through a semi-circular trajectory of radius 3 m. how much work (in joules) is being done on the child by the swing/rope?
Work (in joules) is being done on the child by the swing/rope4.85 jouls playground is swinging back and forth.
T=mg + mv2 / R = 40 * 9.8 + 40 * (2*2) / 2.40 T=392 + 66.67 = 458.67N at the lowest point.
b) At the top, mv2 / R =mg v=root of Rg =2.4*4.8 =4.85m/s
At the end of a 6.0 m rope, a ball weighing 60 N is swinging like a pendulum. The ball is moving at 5.0 m/s when it swings past its lowest point. What degree of tension does the rope currently have?
Like a pendulum, the ball is swinging in a particular way.
The mean position of a pendulum is its lowest point of swing, its zero gravitational potential, and its highest kinetic energy.
At this moment, the rope becomes vertically straight.
Hence, the tension of the rope balances the weight of the object at its lightest point.
Therefore,
As a result, in this scenario, while the ball is swinging like a pendulum trough its lowest point, the strain in the rope will be equal to the weight of the ball.
Tension times weight equals 60 N.
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234 oz to tons using the table method (US)
Answer:
234 oz = 0.0066339 t.
Explanation:
Boom Logic...
true or false: the resistances measured in this experiment are very small. the values of resistance will be less than 1 ω.
False. The statement that the resistances measured in the experiment are very small and less than 1 Ω cannot be determined solely based on the information provided.
The values of resistance in an experiment can vary widely depending on the specific setup and components used.
Resistances can range from very small values (less than 1 Ω) to extremely large values, depending on the context and purpose of the experiment. Additional information about the specific experiment and its components would be needed to make a definitive statement about the resistances being measured.
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estimate the energy density of nuclear fuels (in terawatt/kilogram, 1 terawatt = 1e12 watt).
Answer: The energy density of nuclear fuels is between 1 x 1014 to 2 x 1014 terawatt/kg.
Here's an explanation: The energy density of nuclear fuels in terawatt/kilogram is estimated as: Energy density (in terawatt/kilogram) = (Energy released per kg) / (time taken to release energy) 1 terawatt = 1 x 1012 watts. Therefore, the energy density of nuclear fuels is given as: Energy density = (Energy released per kg) / (time taken to release energy) = (Mass defect x c²) / (time taken to release energy) Where Mass defect = (Initial mass - Final mass), and c is the speed of light.
The energy density of nuclear fuels is between 1 x 1014 to 2 x 1014 terawatt/kg.
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How much pressure does a box whose sides are 1.44 m long each exert on the ground due to gravity?Assume that the box has a mass of 17.3 kg. HINT: Look at the definition of pressure - what force is doing the "pushing?" What's the area?
Pressure = Force / area
m= mass = 17.3 kg
g= gravity = 9.8 m/s^2
Force = m * g = 17.3 kg * 9.8 m/s^2 = 169.54 N
P = F / A
A = area = 1.44^2 = 2.0736 m^2
P = 169.54 N/ 2.0736 m^2 = 81.76 Pa
True or False: The variables in the equation 4x-(5y)2=64x-(5y)2=6 are 4, 5, and 6
Answer:
true
Explanation:
Answer:
true
Explanation:
what is the common name of potassium nirate (KNO3)?
The common name of potassium nitrate (KNO3) is saltpeter or saltpetre.
Potassium nitrate (KNO3), also known as saltpeter, is a chemical compound made up of potassium, nitrogen, and oxygen. It is commonly used in the manufacture of fertilizers, explosives, and fireworks.
In the agriculture industry, potassium nitrate is used as a source of nitrogen and potassium, which are essential nutrients for plant growth. It is also used in the preservation of meats as a curing agent, as it helps prevent bacterial growth.
Potassium nitrate has been used historically in the production of gunpowder and fireworks due to its oxidizing properties. It is also used in the production of other explosives, such as rocket propellants.
In addition to its industrial uses, potassium nitrate has also been used in traditional medicine for its diuretic and laxative properties. However, it can be toxic if consumed in large amounts and should only be used under the guidance of a healthcare professional.
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A student pulls a block 3.0 meters along a horizontal surface at constant velocity. The diagram below shows the components of the force exerted on the block by the student. String ck8.0N Horizonta apaaaaaaaSurface 3.0 m How much work is done against friction? 1) 6J 2) 18 J 3) 24 J 4) 30 J 5) 42 J
The work done by student when he apply a force of 8 N on a string is 24 J.
What is work done?Work is said to be done when ever a force moves a body through a certain distance.
To calculate the work done by the student, we use the formula below
Formula:
W = Fd.................... Equation 1Where:
W = Work doneF = Forced = DistanceFrom the question,
Given:
F = 8 Nd = 3 mSubstitute these values into equation 1
W = 8×3W = 24 JHence, the work done by student is 24 J.
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in a pendulum, how does each component swing?
Answer:
Function. The Earth's gravity attracts the pendulum. This swinging-back-and-forth force continues until the force that started the movement is not stronger than gravity, and then the pendulum is at rest again.
Explanation:
back and forth under the action of gravity. And the swing continues moving back and forth without any extra outside help until friction (between the air and the swing and between the chains and the attachment points) slows it down and eventually stops it.
Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above
Answer:
Explanation:
Hell im good dude
A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to take a break. Which of the following is true?
A) the distance driven is more than the displacement.
B) the displacement is more than the distance driven.
C) the distance driven and the displacement are the same.
Answer:
A
Explanation:
They drove 30km north. The displacement adds up to 25km therefore making the distance greater
Hope this helps!
In a Young's double-slit experiment, a set of parallel slits with a separation of 0.102 mm is illuminated by light having a wavelength of 575 nm and the interference pattern observed on a screen 3.50 m from the slits.(a) What is the difference in path lengths from the two slits to the location of a second order bright fringe on the screen?(b) What is the difference in path lengths from the two slits to the location of the second dark fringe on the screen, away from the center of the pattern?
Answer:
Rounded to three significant figures:
(a) \(2 \times 575\; \rm nm = 1150\; \rm nm = 1.15\times 10^{-6}\; \rm m\).
(b) \(\displaystyle \left(1 + \frac{1}{2}\right) \times (575\;\rm nm) \approx 863\; \rm nm = 8.63\times 10^{-7}\; \rm m\).
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let \(k\) denote a natural number (\(k \in \left\lbrace0,\, 1,\, 2,\, \dots\right\rbrace\).) In a double-split experiment of a monochromatic light:
A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: \(\text{Path difference} = k\, \lambda\).Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: \(\displaystyle \text{Path difference} = \left(k + \frac{1}{2}\right)\cdot \lambda\).MaximaThe path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where \(k = 0\) in \(\text{Path difference} = 0\).
The path difference increases while moving on the screen away from the center. The first order maximum is at \(k = 1\) where \(\text{Path difference} = \lambda\).
Similarly, the second order maximum is at \(k = 2\) where \(\text{Path difference} = 2\, \lambda\). For the light in this question, at the second order maximum: \(\text{Path difference} = 2\, \lambda = 2 \times 575\; \rm nm = 1.15\times 10^{-6}\; \rm m\).
Central maximum: \(k = 0\), such that \(\text{Path difference} = 0\).First maximum: \(k = 1\), such that \(\text{Path difference} = \lambda\).Second maximum: \(k = 2\), such that \(\text{Path difference} = 2\, \lambda\).MinimaThe dark fringe closest to the center of the screen is the first minimum. \(\displaystyle \text{Path difference} = \left(0 + \frac{1}{2}\right)\cdot \lambda = \frac{1}{2}\, \lambda\) at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda\) at that point.
First minimum: \(k =0\), such that \(\displaystyle \text{Path difference} = \frac{1}{2}\, \lambda\).Second minimum: \(k =1\), such that \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda\).For the light in this question, at the second order minimum: \(\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda = \left(1 + \frac{1}{2}\right)\times (575\; \rm nm) \approx 8.63\times 10^{-7}\; \rm m\).
An LC circuit oscillates at a frequency of 10.4kHz. (a) If the capacitance is 340μF, what is the inductance? (b) If the maximum current is 7.20mA, what is the total energy in the circuit? (c) What is the maximum charge on the capacitor?
(a) The resonant frequency of an LC circuit is given by the equation:
f = 1 / (2π√(LC))
Where f is the frequency, L is the inductance, and C is the capacitance.
We can rearrange this equation to solve for L:
L = 1 / (4π²f²C)
Plugging in the given values, we get:
L = 1 / (4π² * (10.4kHz)² * 340μF) = 0.115H
Therefore, the inductance of the circuit is 0.115H.
(b) The total energy in an LC circuit is given by the equation:
E = 1/2 * L *\(I_{max}\)²
Where E is the total energy, L is the inductance, and \(I_{max}\) is the maximum current.
Plugging in the given values, we get:
E = 1/2 * 0.115H * (7.20mA)² = 0.032J
Therefore, the total energy in the circuit is 0.032J.
(c) The maximum charge on the capacitor is given by the equation:
\(Q_{max}\)= C *\(V_{max}\)
Where \(Q_{max}\) is the maximum charge, C is the capacitance, and \(V_{max}\) is the maximum voltage.
At resonance, the maximum voltage across the capacitor and inductor are equal and given by:
\(V_{max}\) = \(I_{max}\) / (2πfC)
Plugging in the given values, we get:
\(V_{max}\) = 7.20mA / (2π * 10.4kHz * 340μF) = 0.060V
Therefore, the maximum charge on the capacitor is:
\(Q_{max}\) = 340μF * 0.060V = 20.4μC
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a harmonic oscillator absorbs a photon of wavelength 6.20×10−6 m when it undergoes a transition from the ground state to the first excited state.
The absorbed photon transfers its energy to the harmonic oscillator, causing it to transition from the ground state to the first excited state.
When a harmonic oscillator absorbs a photon of wavelength 6.20×10−6 m, it undergoes a transition from the ground state to the first excited state. This transition occurs because the energy of the photon is equal to the energy difference between these two states. The energy of the photon can be calculated using the equation E=hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. The energy difference between the ground state and the first excited state can be calculated using the equation ΔE = E1 - E0, where ΔE is the energy difference, E1 is the energy of the first excited state, and E0 is the energy of the ground state. The absorbed photon transfers its energy to the harmonic oscillator, causing it to transition from the ground state to the first excited state.
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a. what is the normal force, and why is it used instead ofthe load?b. why is it importantto have the string parallel to the horizontal surface in theprocedures where suspended weights are used?
a. The normal force is the force exerted by a surface perpendicular to the object in contact with it. It is used instead of the load because it counterbalances the force applied by the object due to gravity.
The normal force ensures that the object remains in equilibrium and prevents it from sinking into or penetrating the surface.
How the string parallel to the horizontal surface?b. It is important to have the string parallel to the horizontal surface in procedures where suspended weights are used to ensure that the tension in the string is solely vertical. When the string is parallel to the horizontal surface, the tension in the string acts vertically upwards, balancing the downward force due to gravity on the suspended weight.
If the string is not parallel to the horizontal surface, there would be a horizontal component of tension that could introduce an additional force acting on the system, leading to an inaccurate measurement of the weight or affecting the equilibrium of the system.
Therefore, keeping the string parallel to the horizontal surface ensures that the tension in the string is solely responsible for balancing the weight of the object.
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If you want to calculate the acceleration of a car, you should _____ the change in velocity of the car by the time interval.
A. Multiply
B. Increase
C. Divide
D. Decrease
Answer:
Your awnser is B. Increase
Explanation:
Answer:
divide
Explanation:
u should divide the velocity by time interval because a=vf-vi/t
a longitudinal wave is observed. Exactly 6 crests are observed to move past a given point in 9.1 s. Its wavelength is 2.4 m and its frequency is 0.66 HZ. What is the speed of the wave.
The speed of the longitudinal wave is 1.584 or approximately 1.6 meters per second.
What is a longitudinal wave?Longitudinal waves are waves in which the medium's vibration is parallel to the wave's travel direction and the medium's displacement is in the same direction as the wave's propagation.
Sound waves are one example of longitudinal waves. Waves of ultrasound P-waves from earthquakes
A longitudinal wave's key features include compression, rarefaction, wavelength, amplitude, period, and frequency.
To calculate the above answer multiply wavelength by frequency to get the speed of a wave.
That is:
2.4 x 0.66
= 1.584
Where the frequency is not given beforehand, you can divide 6 crests by 9.1 seconds to determine the frequency.
Hence, the speed of the longitudinal wave is 1.584 which is approximately 1.6.
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A hockey ball accelerates from 0 m/s to 25 m/s in 0.05 seconds. What is the acceleration of the ball?
Answer:
500
Explanation:
25/0.05
A baseball player hits a 0. 15 kg 0. 15kg0, point, 15, start text, k, g, end text baseball that is initially at rest, changing its momentum by 11 kg ⋅ m s 11 s kg⋅m 11, start fraction, start text, k, g, end text, dot, start text, m, end text, divided by, start text, s, end text, end fraction
The velocity of baseball that was initially at restand changing momentum by 11 kgm/s is 73.3m/s.
How to calculate velocity?We can find the velocity of the player.
Momentum = mass * velocity
Given
Mass = 0.15kg
Momentum = 11kgm/s
Get the velocity
Velocity = Momentum/Mass
Velocity = 11/0.15
Velocity = 73.3m/s
Hence the velocity of the player is 73.3m/s
What is velocity?The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.For more information on momentum kindly visit to
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What data will you collect in order to calculate the balloon car’s velocity?
Answer:
To calculate speed, all you have to do is divide distance by time.
Explanation:
Velocity is just speed in a particular direction. For example, if in 3 hours you ran 6 kilometers west, your velocity was 6 km/3 hours = 2 km/hour west.
Buildings are more dense than the surrounding air. This means that they have more _____ per volume than the air and will stay on the ground instead of floating up into the atmosphere.
Answer:
mass
Explanation:
Density is the measure of how much mass of a substance is squeezed into a given volume of that substance. It is the mass per unit volume, and substances with lesser density will float in materials with denser density. Buildings are generally more obviously denser that air, if not we'll see then float upwards into the atmosphere, but that is not the case. Different liquids too can separate and form layers on one another due to their differences in volume.