Fiona must find the length indicated by the dotted line for the tiles she is installing. She knows that each polygon is a regular hexagon with a perimeter of 7. 5 in. 3 regular hexagons are connected at their sides. A dotted line is drawn through the middle of the 3 hexagons. The top image is a reflection of the bottom image. The dotted line is the length of one side and the distance from one point of the hexagon to the opposite point. What is the length of the dotted line? Round to the nearest hundredth. 2. 50 in. 3. 75 in. 5. 00 in. 6. 25 in.

Answer:

9:02

Step-by-step explanation:

If she wakes up at 9:02 then she can get ready by 9:10 and be at work by 9:33 since it takes her 23 minutes to drive to work.

The decision-making process involved in Mikaela's decision to attend a Zumba class on Tuesday and Thursday afternoons and make it her regular exercise routine is "escalation."

In the scenario described, Mikaela initially started attending the Zumba class on Tuesday and Thursday afternoons. She found that it gave her a good workout and was satisfied with the results. As a result, she continued attending the class on those days and made it her regular exercise routine. This decision to stick to the same schedule without considering other options or making changes over time is an example of escalation.

Escalation in decision-making refers to the tendency to persist with a chosen course of action even if it may not be the most optimal or efficient choice. It occurs when individuals continue to invest time, effort, and resources into a decision or course of action, even if there may be better alternatives available. In this case, Mikaela has decided to stick with the Zumba class on Tuesday and Thursday afternoons because she found it effective and enjoyable, and she hasn't explored other exercise options since then.

It's important to note that escalation may not always be the best approach in decision-making. It's always a good idea to periodically reassess and evaluate the choices we make to ensure they still align with our goals and needs. Mikaela might benefit from periodically evaluating her exercise routine to see if it still meets her fitness goals and if there are other options she could explore for variety or improved results.

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Given,

the coordinates of the point is P(-4, -1) and N(1, -8).

Required

The distance between the point P and N.

The distance between the point P and N.

Hence, the distance between the points is sqrt(74).

Answer:

x=14

Step-by-step explanation:

This is asking for the ratio of A to B.

The x-10 is 1.

The 28 is 7.

Find the scale factor by executing 28/7=4.

So, you would want polygon A to be 4 in order to be proportional to polygon B.

Now, you can just guess and check that 14-10=4

Or, you can set up the equation as follows: x-10    =    4

                                                                         +10        +10

                                                                           x      =   14 is your answer.

Answer:

try 3 i need 20 more letters

Answer:

f(x) = 2x^2 + 12x +10

Step by step solution:

x = 1 x = 5 y = 10

f(x) = a(x+1)(x+5)

f(0) = a(1)(5) = 10

5a = 10

Divide by 5

a = 2

f(x)= 2(x+1)(x+5)

f(x) = 2(x^2 +6x +5)

f(x) = 2x^2 + 12x +10

brainliest much appreciated!

Answer:

I think The answer would be 0.3

Answer:

-3/10

Step-by-step explanation:

3/2 is equivalent to 15/10. Or 1 5/10. And 6/5 is equivalent to 18/10s or 1 8/10. Therefore 1 1/5 + (-1 8/10) = -3/10

Answer:

-3/5x

Step-by-step explanation:

It is a negative slope and use rise over run

The equation in slope-intercept form that represents Sam's savings account growth is y = 20x + 300, where y represents the amount of money in the account and x represents the number of weeks that have passed.

To find the equation in slope-intercept form, we need to determine the slope and the y-intercept based on the given information. We know that after 5 weeks, Sam had $350 in his account, and after 10 weeks, he had $400.

Using these data points, we can calculate the slope (m) of the line. The change in the y-values (350 - 300 = 50) divided by the change in the x-values (5 - 0 = 5) gives us the slope: m = 50/5 = 10.

Next, we need to find the y-intercept (b) by substituting one of the data points into the equation. We can choose the point (5, 350). Plugging in these values, we have: 350 = 10(5) + b. Solving for b, we get: b = 300.

Therefore, the equation in slope-intercept form that represents Sam's savings account growth is y = 10x + 300, where y is the amount of money in the account and x is the number of weeks that have passed.

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Answer:

x=42

Your welcome!

Answer:

x=42

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4/7*x+5/14*x-(39)=0

Simplify 5/14

((4/7• x) +  (5/14 • x)) -  39  = 0

Simplify 4/7

  4         5x    

 ((— • x) +  ——) -  39  = 0

   7         14    

Find the Least Common Multiple

     The left denominator is :       7

     The right denominator is :       14

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

7 1 1 1

2 0 1 1

Product of all

Prime Factors  7 14 14

     Least Common Multiple:

     14

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 2

  Right_M = L.C.M / R_Deno = 1

Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4x • 2

  ——————————————————  =   ——————

        L.C.M               14  

  R. Mult. • R. Num.      5x

  ——————————————————  =   ——

        L.C.M             14

Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

4x • 2 + 5x     13x

———————————  =  ———

    14          14

 13x    

 ——— -  39  = 0

 14    

 Subtracting a whole from a fraction

Rewrite the whole as a fraction using  14  as the denominator :

         39     39 • 14

   39 =  ——  =  ———————

         1        14  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding up the two equivalent fractions

13x - (39 • 14)     13x - 546

———————————————  =  —————————

      14               14    

 Pull out like factors :

  13x - 546  =   13 • (x - 42)

13 • (x - 42)

 —————————————  = 0

      14  

 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 13•(x-42)

 ————————— • 14 = 0 • 14

    14    

Now, on the left hand side, the  14  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  13  •  (x-42)  = 0

Solve :    13   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solve  :    x-42 = 0

Add  42  to both sides of the equation :

                     x = 42

Please Give me Brainliest

in our bstnode class the variables left and right, that represent the links of a node, are of class comparable is FALSE.

The variables left and right in the bstnode class represent the links to the left and right subtrees of a node in a binary search tree. These variables are typically of the same type as the bstnode class itself, since they also represent nodes in the tree. They do not need to be of the class Comparable, as that interface is used for objects that can be compared to each other for the purposes of sorting. The bstnode class may contain an instance variable of a comparable type if the nodes are being sorted based on their values, but this is separate from the left and right variables. Conclusion: The variables left and right in the bstnode class are not of class Comparable.

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Kara erred when she answered the equation 2x + 6 = -8. Instead, she should have solved the equation 2x + 6 = 8 because it relates to the second situation (where -2x + 6 + 10 is smaller than 0).

Kara made a mistake when solving the equation |- 2x + 6 + 10| = 2. The correct steps to solve this equation are as follows:

First, we need to find the value of -2x + 6 + 10. To do this, we need to remove the absolute value bars by considering two cases:

a. If -2x + 6 + 10 is greater than or equal to 0, then the absolute value is equal to -2x + 6 + 10.

b. If -2x + 6 + 10 is less than 0, then the absolute value is equal to the negative of -2x + 6 + 10.

In the first case, we have -2x + 6 + 10 = 2. Solving this equation gives us x = -1.

In the second case, we have -(-2x + 6 + 10) = 2. Solving this equation gives us x = 7.

Therefore, the solution to the equation |- 2x + 6 + 10| = 2 is x = {7, -1}.

She made a mistake when she solved the equation 2x + 6 = -8. She should have solved the equation 2x + 6 = 8 instead, because this is the equation that corresponds to the second case (where -2x + 6 + 10 is less than 0).

As a result, Kara got the wrong value for x and included the incorrect solution {7, -1} in her final answer.

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The sample is a stratified sample.

A stratified sample is a sampling method in which a population is separated into distinct, non-overlapping subpopulations, or strata, and a random sample is taken from each stratum.

This is frequently utilized when the population contains subpopulations with distinct characteristics, and the researcher wants to guarantee that these subpopulations are adequately represented in the sample.

Likewise, in the provided scenario of the electronics store, the store will first separate the customers who purchased a computer over the past two years and then take 100 receipts through a random number generator to question customers about high-speed Internet rates.

This way, it can ensure that all customers are adequately represented in the sample and the information it receives is not biased.

A stratified sample is a sampling technique used in statistics and research to ensure that the sample accurately represents the different subgroups or strata within a population. It involves dividing the population into distinct subgroups or strata based on certain characteristics or variables and then selecting a sample from each stratum.

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One strategy that may help Emilio write more fluently is practicing speed writing or shorthand techniques.

Practicing speed writing or shorthand techniques can help Emilio increase his writing speed without sacrificing legibility. Speed writing involves using abbreviations, symbols, and shortcuts to represent words or phrases, allowing for faster transcription of thoughts onto paper.

Shorthand systems, such as Gregg shorthand or Pitman shorthand, provide structured methods for condensing words and phrases into simplified symbols.

By learning and practicing speed writing or shorthand techniques, Emilio can improve his writing efficiency and reduce the time it takes to write a few sentences. This strategy allows him to maintain neatness while increasing his writing speed, enabling him to express his thoughts more fluently.

With regular practice and familiarity, Emilio will become more comfortable with the shorthand system and experience a significant improvement in his writing speed and fluency.

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Answer: are diagrams that depict the direction and relative magnitude of a vector quantity by a vector arrow. Vector diagrams can be used to describe the velocity of a moving object during its motion. For example, a vector diagram could be used to represent the motion of a car moving down the road.

Step-by-step explanation:

The electric field (E-field) associated with the given potential function V(x, z) = 4bx^2 + 4az^3 - 3cz^3 is E = -8bx i - (12az^2 - 9cz^2)j.

To find the electric field (E-field) associated with the given potential function, we need to calculate the negative gradient of the potential. The E-field is given by the following formula:

E = -∇V

Where ∇ is the gradient operator. In this case, the potential function V(x, z) is defined as:

V(x, z) = 4bx^2 + 4az^3 - 3cz^3

To calculate the E-field, we need to take the partial derivatives of V with respect to x and z and then apply the negative sign. Let's calculate each component separately:

Partial derivative with respect to x (dV/dx):

dV/dx = 8bx

Partial derivative with respect to z (dV/dz):

dV/dz = 12az^2 - 9cz^2

Now, we can write the E-field vector as:

E = -∇V = -(dV/dx)i - (dV/dz)j

Substituting the calculated partial derivatives, we have:

E = -8bx i - (12az^2 - 9cz^2)j

Therefore, the electric field (E-field) associated with the given potential function V(x, z) = 4bx^2 + 4az^3 - 3cz^3 is:

E = -8bx i - (12az^2 - 9cz^2)j

Note that the positive constants b and c are included in the E-field expression.

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Answer:

$31.20

Step-by-step explanation:

Use proportions:

10/6.50 = 48/x

Cross multiply:

6.50*48 = 312

312/10 = 31.20

1a) The number of whole servings Susan can make from 4.25 pounds of flour if one serving uses ²/₃ is 6.

1b) The quantity of flour Susan has after making 6 servings is ¹/₄ pounds.

2) Garrison can drink ⁷/₈ gallons of lemonade each of the next six days.

3) The student council sold 122 bags of chips.

4) If a container can hold 3¹/₃ ounces of peanuts, 5 containers will hold 16²/₃ ounces.

5) The number of people at the football game (400) last night who were not wearing orange and black is 240.

6) The number of long sleeves in Jordan's outfits is 45.

The numbers and values can be determined using suitable mathematical operations.

The basic mathematical operations used include division, subtraction, and multiplication.

1) The total quantity of flour available = 4.25 pounds

The amount of flour required per serving = ²/₃ pounds

The number of servings from 4.25 pounds = 6³/₈ servings (4.25 ÷ ²/₃)

= 6 servings.

Quantity of flour left = ¹/₄ pounds [4 - 6(²/₃)]

2) The number of lemonades available = 5.5 gallons

The quantity Garrison took on Monday = ¹/₄ gallons (0.25)

The remaining number of gallons = 5.25 gallons (5.5 - 0.25)

The gallons for the remaining 6 days = ⁷/₈ gallons (5¹/₄ ÷ 6)

3) The total amount realized from sales = $73.20

The unit price per bag of chips = $0.60

The units sold = 122 ($73.20 ÷ $0.60)

4) The ounces of peanuts per container = 3¹/₃

The number of containers = 5

The ounces of peanuts for 5 containers = 16²/₃ ounces (3¹/₃ x 5)

5) The total number of people at the game = 400

The proportion of people wearing orange and black = ²/₅

The proportion of people not wearing orange and black = ³/₅ (1 - ²/₅)

The number of people not wearing orange and black = 240 (400 x ³/₅)

6) The total number of outfits in Jordan's closet = 200

The proportion of shirts = ³/₄

The proportion of long sleeve shirts = ³/₁₀

The number of long sleeve shirts = 45 (200 x ³/₄ x ³/₁₀)

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Answer:

The answer is V = 31 1/2 in^3

Answer:

Step-by-step explanation:

B

Hi,

12(3 + 5) = 12*3 + 12*5 = 36 + 60 = 96

I hope it helped.✅

Answer:

\(12(3 + 5) = 12 \times 3 + 12 \times 5 \\ = 36 + 60 \\ = 96\)

This can be derived using Chebyshev's inequality, as Chebyshev's inequality and the law of large numbers are different in nature.

Let M_n be the maximum of n independent U(0, 1) random variables.

To derive the exact expression for P(|M_n − 1| > ε), we need to follow the below steps:

First, we determine P(M_n ≤ 1-ε). The probability that all of the n variables are less than 1-ε is (1-ε)^n

So, P(M_n ≤ 1-ε) = (1-ε)^n

Similarly, we determine P(M_n ≥ 1+ε), which is equal to the probability that all the n variables are greater than 1+\epsilon

Hence, P(M_n ≥ 1+ε) = (1-ε)^n

Now we can write P(|M_n-1|>ε)=1-P(M_n≤1-ε)-P(M_n≥1+ε)

P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n.

Thus we have derived the exact expression for P(|M_n − 1| > ε) as P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n

Now, to show that $lim_{n\to\∞}$ P(|M_n - 1| > ε) = 0 , we can use Chebyshev's inequality which states that P(|X-\mu|>ε)≤{Var(X)/ε^2}

Chebyshev's inequality and the law of large numbers are different in nature as Chebyshev's inequality gives the upper bound for the probability of deviation of a random variable from its expected value. On the other hand, the law of large numbers provides information about how the sample mean approaches the population mean as the sample size increases.

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Step-by-step explanation:

= 3/5 × 1/6

= (3 × 1)/(5 × 6)

= 3/30

= 1/10

Answer:

\( \sf \frac{1}{10} \)

Step-by-step explanation:

\( \sf = \frac{3}{5} \times \frac{1}{6} \)

\( \sf = \frac{3 \times 1}{5 \times 6} \)

\( \sf = \frac{1 \times 1}{5 \times 2} \)

\( \sf = \frac{1}{10} \)

Answer: x=16 kg.

Step-by-step explanation:

\(\displaystyle\\x+x+\frac{1}{2}x=40\\\\ 2\frac{1}{2}x=40\\\\\frac{(2*2+1)}{2}x=40\\\\ \frac{5}{2} x=40\\\\Multiply\ both\ sides\ of\ the\ equation\ by\ 2:\\\\\frac{5}{2}x*2 =40*2\\\\5x=80\\\\Divide\ both\ sides\ of\ the\ equation\ by\ 5:\\\\x=16\ kg.\)

If you can earn 8 percent on your money, the prize worth to you is: $76,812.50. To calculate the present value of the prize, we need to determine the current worth of receiving $1000 per month for 9 years, given an 8 percent annual interest rate.

This situation can be evaluated using the concept of the present value of an annuity. The present value of an annuity formula is used to find the current value of a series of future cash flows. In this case, the future cash flows are the $1000 monthly payments for 9 years. By applying the formula, which involves discounting each cash flow back to its present value using the interest rate, we find that the present value of the prize is $76,812.50.

This means that if you were to receive $1000 per month for 9 years and could earn an 8 percent return on your money, the equivalent present value of that prize, received upfront, would be $76,812.50.

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At great axial distances x from a current-carrying loop, the magnetic field varies as:

b. x^-3

Here's the step-by-step explanation:

1. The magnetic field B at a point on the axis of a current-carrying loop can be given by the formula: B = (μ₀Ia²) / (2(a² + x²)^(3/2))

2. In this formula, μ₀ is the permeability of free space, I is current, a is the radius of the loop, and x is the axial distance from the loop.

3. When the axial distance x is much greater than the radius a (i.e., x >> a), the term a² in the denominator becomes negligible compared to x².

4. Therefore, the formula simplifies to: B ≈ (μ₀I) / (2x³)

As you can see, the magnetic field B varies as x^-3 at great axial distances from the current-carrying loop.

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Answer:

1 solution! X = 0

Then an appropriate domain for the situation is composed by all integer values.

The function in this problem is defined as follows:

f(x) = 0.04(|7x| + 4x).

In which:

Then the numeric values are obtained replacing x by the number of steps run, as follows:

f(-20) = 0.04(|7(-20)| + 4(-20)) = 2.4 calories.

The number of stairs is a countable amount, meaning that it cannot assume decimal values, and thus f(17.5) does not make sense in the context of this problem, and an appropriate domain is given by all integer values.

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The probability of a patient scoring above 192 on the endurance test is approximately 40.90%. A patient at the 80th percentile receives a score of approximately 208.2.

a. To find the probability that a patient will score above 192, we need to use the Z-score formula. The Z-score measures the number of standard deviations a data point is from the mean. In this case, the formula is Z = (X - μ) / σ, where X is the score, μ is the mean, and σ is the standard deviation.

First, calculate the Z-score: Z = (192 - 185) / 30 = 7/30 ≈ 0.23.

Next, we need to find the probability of scoring above this Z-score. Using a Z-table or a calculator, we find that the probability is approximately 0.4090, or 40.90%.

b. To find the score that corresponds to the 80th percentile, we need to find the Z-score that has an area of 0.80 to the left. Using the Z-table or a calculator, we find that the Z-score is approximately 0.84.

Now, we can use the Z-score formula to find the corresponding score: X = Z * σ + μ. Plugging in the values, we get X = 0.84 * 30 + 185 = 208.2.

Therefore, a patient at the 80th percentile receives a score of approximately 208.2.

a. To find the probability of a patient scoring above 192 on the endurance test, we first calculate the Z-score. This allows us to standardize the score by measuring how many standard deviations it is from the mean. We then use a Z-table or calculator to find the probability corresponding to this Z-score, which is approximately 0.4090 or 40.90%.

b. To find the score at the 80th percentile, we first need to find the Z-score that corresponds to an area of 0.80 to the left. Using a Z-table or calculator, we find this Z-score to be approximately 0.84. We then use the Z-score formula to find the corresponding score, which is approximately 208.2.

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The forecast for demand of chip sales for week 4 is 13.2. So, the answer is option 4) 13.2.

This forecast assumes a linear relationship between the demand for chips sale and time. To use the equation Y=2.8X+2 for forecasting the demand of chips sale, we need to plug in the value of X, which is the week for which we want to create the forecast. Here, we want to forecast for week 4, so X=4.

Substituting the value of X=4 in the equation, we get:

Y=2.8(4)+2

Y=11.2+2

Y=13.2

Therefore, the forecast for week 4 using the given equation is 13.2. The correct answer is option (4) that is 13.2.

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