Find x. 32° 98° x°

please help me​

Answer:

a = 4

Step-by-step explanation:

Answer: a=4

Step-by-step explanation:

\( \sf \looparrowright \: 8 \frac{1}{6} - 5 \frac{5}{6} \)

Convert the mixed fractions to improper fractions

\( \underbrace {8\frac{1}{6} = \frac{6 \times 8 + 1}{6} = \frac{49}{6} }\)

\( \underbrace {5\frac{5}{6} = \frac{6 \times 5 + 5}{6} = \frac{35}{6} }\)

\( \sf \looparrowright \: \frac{49}{6} - \frac{35}{6} \)

Write the numerators above the common Denominator 6

\( \sf \looparrowright \: \frac{49 - 35}{6} \)

Calculate the difference

\( \sf \looparrowright \: \frac{14}{6} \)

Reduce the fraction with 2

\( \sf \looparrowright \frac{7}{3} \)

Answer:

The explicit formula of that sequence is T - 5

Step-by-step explanation:

Let T represent each term in the sequence. So now try replacing T with each term in the sequence. Like this ;

7 - 5 = 2

2 - 5 = -3

-3 - 5 = -8

hope this helps

Answer:

p = 23       and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45    and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1    and 2p-1+1 = -45+1

2p = 46                        2p = -44

Divide by 2

2p/2 = 46/2    and   2p/2  = -44/2

p = 23       and p = -22

Answer:

Im sry for being unhelpful but Heyy lol

Step-by-step explanation:

but btw i think the answer is no...

To solve the problem we must know about the system of equations.

A system of equations to have no real solution, the lines of the equations must be parallel to each other.

1. Dependent Consistent System

A system of the equation to be Dependent Consistent System the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

A system of the equation to be Independent Consistent System the system must have one unique solution for which the lines of the equation must intersect at a particular.

To find

The solution is yes, it is possible for a system of equations composed of a linear function and a quadratic function to have 2 solutions.

In system equations, solutions are those points at which the line(or graph) of the equations intersect each other.

As we can see in the below image the system of equations has two solutions because the graphs of the equations intersect each other at two points.

Hence, it is possible for a system of equations composed of a linear function and a quadratic function to have 2 solutions.

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Answer:

C. 55°

Step-by-step explanation:

The computation of mAC is shown below:

Given that

Diameter AB would be parallel to CD

McD = 70

Based on the attached diagram and the above information

mAC is

= (180 - 70) ÷ 2

= 55 degrees

hence, the correct option is third

The solution is: red<yellow<green<blue<violet are the colors.

The light spectrum contains waves with specific wavelength which can be classified into groups. Most of the groups are invisible to the eye (like infrared, microwaves, radio waves, gamma rays, etc.) however, there is one group that is known as visible light.

Visible light allows us to see colors from red all the way to violet. The colors have different frequencies and wavelengths. The wave with the highest frequency also has the highest energy (which in this case is violet). Hence, as the frequency decreases, the energy will also decrease, making violet have the highest energy, and red have the lowest energy.

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complete question:

which answer has the colors in order from the lowest energy to the highest? group of answer choices red, blue, green blue, red, green blue, green, red red, green, blue

The real part of the particular solution to the differential equation is Re(y(t)) = (5 / 106) cos(3t).

We can start by assuming that the particular solution to the differential equation is of the form y = A e^(3it), where A is a complex constant that we need to determine.

We first take the first and second derivatives of y with respect to time:

dy/dt = 3i A e^(3it)

d^2y/dt^2 = -9 A e^(3it)

Substituting these into the differential equation, we get

-27i^2 A e^(3it) + 15i A e^(3it) + 7A e^(3it) = e^(3it)

Simplifying, we get

(-27 + 15i)A e^(3it) + 7A e^(3it) = e^(3it)

Factorizing, we get

(-27 + 15i + 7)A e^(3it) = e^(3it)

Solving for A, we get

A = 1 / (5 - 9i)

To find the real part of y, we can use Euler's formula

e^(3it) = cos(3t) + i sin(3t)

Substituting for A, we get

y = A e^(3it)

y = (1 / (5 - 9i)) (cos(3t) + i sin(3t)) e^(3it)

y = (1 / (5 - 9i)) [(cos(3t) + i sin(3t)) (cos(3t) + i sin(3t))] e^(3it)

y = (1 / (5 - 9i)) [(cos^2(3t) - sin^2(3t)) + 2i sin(3t) cos(3t)] e^(3it)

Taking the real part, we get

Re(y) = (1 / (5 - 9i)) (cos^2(3t) - sin^2(3t))

Re(y) = (1 / (5 - 9i)) (cos(6t))

Re(y) = (5 / 106) cos(3t)

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The given question is incomplete, the complete question is:

Find the real part of the particular solution Find the real part of the particular solution to the differential equation dạy 3 d^2y/dt^2 +5dy/dt + 7y =e^(3it) in the form y=Bcos(3t) + C sin(3t) where B, C are real fractions. = Re(y(t)) = ?

The transformation matrix T from b to b' is:

This can be obtained by writing the coordinates of the basis vectors of b' as linear combinations of the basis vectors of b and forming a matrix with these coefficients.

To find the transformation matrix from one ordered basis to another, we need to express the coordinates of the basis vectors of the new basis (b') as linear combinations of the basis vectors of the old basis (b). The columns of the transformation matrix T are these coefficients.

To obtain these coefficients, we solve the system of equations T[v] = [v'] for each basis vector v of b', where v' are the coordinates of v in b'. This results in a matrix T where each column represents the coefficients of a basis vector of b' expressed in terms of the basis vectors of b.

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The fruit mass for the second monkey is 168 grams.

An algebraic expression is a combination of variables, numbers, and mathematical operations such as addition, subtraction, multiplication, and division. These expressions are used to represent mathematical relationships or describe real-world situations.

Algebraic expressions can be made up of one or more terms. A term is a number, a variable, or a combination of the two that is separated by mathematical operations. For example, in the expression 3x + 5y - 2, there are three terms: 3x, 5y, and -2.

Variables in algebraic expressions represent unknown values that can vary. They are usually represented by letters, such as x, y, or z. Constants, on the other hand, are fixed values that do not change, such as the number 5.

Algebraic expressions can be simplified or evaluated by performing mathematical operations in a specific order. This order of operations is known as PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

Algebraic expressions are used extensively in algebra, which is a branch of mathematics that deals with the study of mathematical symbols and the rules for manipulating them. They are also used in many fields of science, engineering, and economics to describe relationships and make predictions.

Since the ratio of fruit mass to biscuit mass is 7:5, we can set up the proportion:

fruit mass / biscuit mass = 7/5

For the first monkey, we are given the fruit mass as 126 grams. Let x be the biscuit mass for the first monkey. Then we can write:

126 / x = 7/5

To solve for x, we cross-multiply and simplify:

126 * 5 = 7 * x

630 = 7x

x = 90

Therefore, the biscuit mass for the first monkey is 90 grams.

For the second monkey, we are given the biscuit mass as 120 grams. Let y be the fruit mass for the second monkey. Then we can write:

y / 120 = 7/5

To solve for y, we cross-multiply and simplify:

y * 5 = 7 * 120

y = 168

Therefore, the fruit mass for the second monkey is 168 grams.

Using this information, we can complete the missing values in the table:

Monkey        Fruit Mass (g)     Biscuit Mass (g)

1                126                     90

2                168                     120

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Answer:

Step-by-step explanation:

jnj is f skf sk cxk cc

Answer:

D (the last choice)

Step-by-step explanation:

Taking the fourth root of each element individually:

49^(1/4) = sqrt(7)

(d^8)^(1/4) = d^2

(e^2)^(1/4) = sqrt(e)

Multiplying them back together:

sqrt(7) * d^2 * sqrt(e) = d^2 * sqrt(7e)

Answer:

The last bubble (that of which is cut from the screen) is simplified.

Step-by-step explanation:

The provided equation is simplified by following these steps:

\((49d^{8}e^2)^\frac{1}{4}\)

= \((49)^\frac{1}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}\)

\((7)^\frac{2}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}\)

=\(\sqrt{7} (d^2)(\sqrt{e})\)

Answer:

The first thing you do is you get the value of the sides of the shape. For example, if you have a triangle with a side with 3 value and it dilates to 9. You divide the dilation to the original. So 9/3 would equal 3. 3 would be the scale factor because that’s how much it dilated by. You also have to double check that each scale factor equals 3 so you would have to check the other sides.

Step-by-step explanation: No i did not copy her's i was just doing the same test Literally the same exact test

Answer:

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}\)

Step-by-step explanation:

Given

\(\cos(\theta) = -\frac{2}{3}\)

\(\theta \to\) Quadrant III

Required

Determine \(\tan(\theta) \cdot \cot(\theta) + \csc(\theta)\)

We have:

\(\cos(\theta) = -\frac{2}{3}\)

We know that:

\(\sin^2(\theta) + \cos^2(\theta) = 1\)

This gives:

\(\sin^2(\theta) + (-\frac{2}{3})^2 = 1\)

\(\sin^2(\theta) + (\frac{4}{9}) = 1\)

Collect like terms

\(\sin^2(\theta) = 1 - \frac{4}{9}\)

Take LCM and solve

\(\sin^2(\theta) = \frac{9 -4}{9}\)

\(\sin^2(\theta) = \frac{5}{9}\)

Take the square roots of both sides

\(\sin(\theta) = \±\frac{\sqrt 5}{3}\)

Sin is negative in quadrant III. So:

\(\sin(\theta) = -\frac{\sqrt 5}{3}\)

Calculate \(\csc(\theta)\)

\(\csc(\theta) = \frac{1}{\sin(\theta)}\)

We have: \(\sin(\theta) = -\frac{\sqrt 5}{3}\)

So:

\(\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}\)

\(\csc(\theta) = \frac{-3}{\sqrt 5}\)

Rationalize

\(\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}\)

\(\csc(\theta) = \frac{-3\sqrt 5}{5}\)

So, we have:

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta)\)

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)\)

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)\)

Substitute: \(\csc(\theta) = \frac{-3\sqrt 5}{5}\)

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}\)

Take LCM

\(\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}\)

Answer:

0.5625

Step-by-step explanation:

Answer:

B,D

Step-by-step explanation:

waiting for brainlist

Answer:

The correct answer here is B.

Step-by-step explanation:

Took the test

The amount will be equal to $1348.07. The correct option is A.

Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-

\(\rm A = P(1+\dfrac{r}{n})^{nt}\)

Compound Interest Formula:

A = Account Balance

P = Principle/Initial Amount

r = Rate of Interest (decimal)

n = Number of times compounded (per year)

t = Number of Years

Given Information

Account Balance = ?

It is given that the balance after 15 years in a savings account earns 2% interest compounded bi-monthly when the initial deposit is 1000.

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

Number of years = 15

Solve by plugging the given values into the formula.

\(\rm A = P(1+\dfrac{r}{n})^{nt}\)

\(\rm A = 1000(1+\dfrac{0.02}{6})^{6 \times 15}\)

A = 1000 x (1.14)

A = $1348.07.

Therefore, the amount will be equal to $1348.07. The correct option is A.

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Based on the given information, the estimate for the number of cells in a T75 flask can be calculated by comparing the number of cells in the picture to the field of view area and then scaling it up to the size of the T75 flask.

Given that there are 55 cells in the picture, we can use this information to estimate the density of cells in the field of view. The field of view has dimensions of 1.85 mm x 1.23 mm, which gives an area of 2.7095 square millimeters (\(mm^2\)). To calculate the cell density, we divide the number of cells (55) by the area (2.7095 \(mm^2\)), resulting in an approximate cell density of 20.3 cells per \(mm^2\).

Now, to estimate the number of cells in a T75 flask, we need to know the size of the flask's growth area. A T75 flask typically has a growth area of about 75 \(cm^2\). To convert this to \(mm^2\), we multiply by 100 to get 7500 \(mm^2\).

To estimate the number of cells in the T75 flask, we multiply the cell density (20.3 cells/\(mm^2\)) by the growth area of the flask (7500 \(mm^2\)). This calculation gives us an approximate estimate of 152,250 cells in the T75 flask. It's important to note that this is just an estimate, and actual cell counts may vary depending on various factors such as cell size, confluency, and experimental conditions.

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For given average temperatures and °C=5/9°F-32 C represents temperature unit in celsius.

What is average?

In Maths, an average of a list of data is the expression of the central value of a set of data. Mathematically, it is defined as the ratio of summation of all the data to the number of units present in the list. In terms of statistics, the average of a given set of numerical data is also called mean. For example, the average of 2, 3 and 4 is (2+3+4)/3 = 9/3 =3. So here 3 is the central value of 2,3 and 4.  Thus, the meaning of average is to find the mean value of a group of numbers.

Average = Sum of Values/Number of Values

Also

Suppose, we have given with n number of values such as x1, x2, x3 ,….., xn. The average or the mean of the given data will be equal to:

Average = (x1+x2+x3+…+xn)/n

Now,

Given formula

°C=5/9°F-32, C represents  where °c is temperature unit in Celsius and

°F represents unit of temperature in Fahrenheit.

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To solve the given problems, we'll use the properties of the normal distribution with mean μ = 100 and standard deviation σ = 10.

a. Probability that X > 85:

To find this probability, we need to calculate the area under the normal curve to the right of 85. We can use the standard normal distribution table or a calculator to find the corresponding z-score and then use the z-table to find the probability.

First, let's calculate the z-score:

z = (X - μ) / σ

z = (85 - 100) / 10

z = -15 / 10

z = -1.5

Using the z-table or a calculator, we find that the probability of Z > -1.5 is approximately 0.9332.

Therefore, the probability that X > 85 is 0.9332 (rounded to four decimal places).

b. Probability that X < 80:

Similarly, we'll calculate the z-score for X = 80:

z = (X - μ) / σ

z = (80 - 100) / 10

z = -20 / 10

z = -2

Using the z-table or a calculator, we find that the probability of Z < -2 is approximately 0.0228.

Therefore, the probability that X < 80 is 0.0228 (rounded to four decimal places).

c. Probability that X < 90 or X > 130:

To calculate this probability, we'll find the individual probabilities of X < 90 and X > 130, and then subtract the probability of their intersection.

For X < 90:

z = (90 - 100) / 10

z = -10 / 10

z = -1

Using the z-table or a calculator, we find that the probability of Z < -1 is approximately 0.1587.

For X > 130:

z = (130 - 100) / 10

z = 30 / 10

z = 3

Using the z-table or a calculator, we find that the probability of Z > 3 is approximately 0.0013.

Since these events are mutually exclusive, we can add their probabilities:

P(X < 90 or X > 130) = P(X < 90) + P(X > 130)

P(X < 90 or X > 130) = 0.1587 + 0.0013

P(X < 90 or X > 130) = 0.1600

Therefore, the probability that X < 90 or X > 130 is 0.1600 (rounded to four decimal places).

d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?

To find the two X-values, we need to find the corresponding z-scores for the cumulative probabilities of 0.005 and 0.995. These probabilities correspond to the tails beyond the 99% range.

For the left tail:

z = invNorm(0.005)

z ≈ -2.576

For the right tail:

z = invNorm(0.995)

z ≈ 2.576

Now we can find the corresponding X-values:

X1 = μ + z1 * σ

X1 = 100 + (-2.576) * 10

X1 = 100 - 25.76

X1 ≈ 74.24

X2 = μ + z2 * σ

X2 = 100 + 2.576 * 10

X2 = 100 + 25.76

X2 ≈ 125.76

Therefore, 99% of the values are greater than 74.24 and less than 125.76 (rounded to two decimal places).

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Using  Central Limit Theorem (CLT) an approximate distribution of y is  0.2578, 0.1902 ,0.9963 , 0.9765.

To use the Central Limit Theorem (CLT), we need to find the mean and variance of the distribution of the sample mean Y.

The mean of the distribution of X is given by:

E[X] = ∫x f(x) dx = ∫x 3x^2 dx (from 0 to 1) = 3/4

The variance of the distribution of X is given by:

Var(X) = ∫(x - E[X])^2 f(x) dx = ∫(x - 3/4)^2 3x^2 dx (from 0 to 1) = 1/20

By the CLT, the sample mean Y is approximately normally distributed with mean μ = E[X] = 3/4 and variance σ^2 = Var(X)/n, where n is the sample size.

For each of the given values of n and σ^2, we can compute the standard deviation σ as σ = sqrt(σ^2/n), and then use the standard normal distribution to find the probability that Y falls in the given interval.

For example, for (n, σ^2) = (64, 0.021), we have:

σ = sqrt(0.021/64) = 0.077

Z1 = (0.7 - μ)/σ = (0.7 - 0.75)/0.077 ≈ -0.649

Z2 = (0.75 - μ)/σ = (0.75 - 0.75)/0.077 = 0

P(0.7 < Y < 0.75) = P(Z1 < Z < Z2) = P(-0.649 < Z < 0) = 0.2578 (from standard normal distribution table)

Similarly, for the other cases, we have:

(n, σ^2) = (64, 0.021)

P(0.7 < Y < 0.75) = 0.2578

(n, σ^2) = (64, 0.00033)

P(0.75 < Y < 0.8) = P(Z < 0.904) - P(Z < 0.309) ≈ 0.1902 (from standard normal distribution table)

(n, σ^2) = (256, 0.021)

P(0.7 < Y < 0.75) = P(Z < 2.597) - P(Z < -0.649) ≈ 0.9963 (from standard normal distribution table)

(n, σ^2) = (256, 0.00033)

P(0.75 < Y < 0.8) = P(Z < 2.128) - P(Z < 0.542) ≈ 0.9765 (from standard normal distribution table)

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Answer:

2 Batches

Step-by-step explanation:

She can make 2 batches of cookies because since the recipe calls for 1 egg and she has 2 eggs that means she can do 2 bathces of cookies. She could've done 3 batches if she had 3 eggs because she has triple the ingredients needed to make a batch of cookies.

(You didn't give us the information of how many cookies can be made in one batch so yeah.)

Two or more expressions with an equal sign is called as Equation.Tenny can make 40 cookies from the ingredients 720g peanut butter, 300g sugar and 2 eggs

Two or more expressions with an equal sign is called as Equation.

Given that

Terry-Ann is making some peanut butter cookies.

She has 720g peanut butter, 300g sugar and 2 eggs.

According to the number of cookies you can make in the given conditions, can do two times

240×2=480, 480<720

100×2=200, 200<300

1×2=2, 2=2

twenty times of 2 is forty

20×2=40

Hence 40 cookies can tenny make from ingredients: 720g peanut butter

300g sugar and 2 eggs

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Answer:

25 cups and 10 teaspoons

Step-by-step explanation:

The t-distribution value is -1.67 for the given mean samples of 35 and 45. Thus, option B is correct.

M₁ = 35

M₂ = 45

SM1-M2 = 6.00

The t-value or t-distribution formula is calculated from the sample mean which consists of real numbers. To calculate the t-value, the formula we need to use here is:

t = (M₁ - M₂) / SM1-M2

Substituting the given values into the formula:

t = (35 - 45) / 6.00

t = -10 / 6.00

t = -1.67

Therefore, we can conclude that the value of t is -1.67 for the samples given.

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The t-distribution value is -1.67 for the given mean samples of 35 and 45. Thus, option B is correct.

Given, M₁ = 35

M₂ = 45

SM1-M2 = 6.00

The t-value or t-distribution formula is calculated from the sample mean which consists of real numbers.

To calculate the t-value,

the formula we need to use here is:

t = (M₁ - M₂) / SM1-M2

Substituting the given values into the formula:

t = (35 - 45) / 6.00

t = -10 / 6.00

t = -1.67

Therefore, we can conclude that the value of t is -1.67 for the samples given.

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Mrs. Williams estimates that her family recycles 12.6 pounds of plastic per month. If 1 pound of plastic saves 7.4 yards of landfill space, Mrs. William's household will save 1,118.88 yards of landfill space in a year, this can be solved using the concept of multiplication.

Correct option: c

Only a small portion of the plastic that we discard every day is recycled or burned in waste-to-energy facilities. A large portion of it is disposed of in landfills, where it may not disintegrate for up to 1,000 years and may contaminate the soil and water.

Reason for the amount of landfill space be decreased:

Given that,

Family recycles plastic each month= 12.6 pounds

So, Family recycle plastic in a year = 12.6 X 12

                                                          = 151.2 Pounds

Noe, if 1 pound of plastic save= 7.4 yards

Then, 151.2 Pounds of plastic will save = 151.2 X 7.4

                                                                = 1,118.88 yards

Correct option is: c

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