Find value of x. Leave in simplest radical form ​

Answer:

20% of 200 is 40

Step-by-step explanation:

multiply 20 and 200 then divide by 100 to get your answer (20*200)/100=40

Providing one example when the statement holds is sufficient to prove an existential statement. This statement is False.

An existential statement implies that at least one object exists such that it satisfies the statement. It's difficult to prove an existential statement by simply presenting an instance. No matter how many cases you provide, you still can't prove the statement true. Consider the following existential statement: "There is a white swan." One may show a white swan as proof that the statement is accurate. It is, however, feasible that a white swan will not be present if we visit a different pond. As a result, providing one example when the statement holds is insufficient to prove an existential statement. It is required to provide logical proof in order to show the truth of an existential statement.

In addition, the set (BC) U 0 is equivalent to OB. (BC) represents the union of set B and set C, but since set C is undefined, the union is the same as set B. OBnc represents the union of sets B and the complement of C. Since C is not defined, we assume that the complement of C, which is everything outside of C, is the universal set U. Thus, the union of set B and the complement of C is equal to the union of set B and U, which is U. Therefore, (BC) U 0 is equivalent to OB. Lastly, A × B is the set of all possible ordered pairs where the first element comes from set A and the second element comes from set B. Therefore, the product of A and B is not infinite, but rather has a cardinality of 6.

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Answer:

Step-by-step explanation:

Answer:

X=4

Step-by-step explanation:

Let's make an equation,

7/4 ÷ 14 = x ÷ 3

We can cross multiply

7/4 * 32 = x * 14

Now we have 56 = 14x

Divide both sides by 14

56 ÷ 14 = 4, 14x ÷ 14 = x

4 = x

x = 4

The derivative \(\( y' \)\) of the implicit function \(\( y^2 - xy = -2 \)\) is 0, indicating a constant slope with no change in relation to \(\( x \)\).

To find \(\( y' \)\)for the implicit function \(\( y^2 - xy = -2 \)\), we can differentiate both sides of the equation with respect to \(\( x \)\) using the chain rule. Let's go step by step:

Differentiating \(\( y^2 \)\) with respect to \(\( x \)\) using the chain rule:

\(\[\frac{d}{dx}(y^2) = 2y \cdot \frac{dy}{dx}\]\)

Differentiating \(\( xy \)\) with respect to \(\( x \)\) using the product rule:

\(\[\frac{d}{dx}(xy) = x \cdot \frac{dy}{dx} + y \cdot \frac{dx}{dx} = x \cdot \frac{dy}{dx} + y\]\)

Differentiating the constant term (-2) with respect to \(\( x \)\) gives us zero since it's a constant.

So, the differentiation of the entire equation is:

\(\[2y \cdot \frac{dy}{dx} - (x \cdot \frac{dy}{dx} + y) = 0\]\)

Now, let's rearrange the terms:

\(\[(2y - y) \cdot \frac{dy}{dx} - x \cdot \frac{dy}{dx} = 0\]\)

Simplifying further:

\(\[y \cdot \frac{dy}{dx}\) \(- x \cdot \frac{dy}{dx} = 0\]\)

Factoring out:

\(\[(\frac{dy}{dx})(y - x) = 0 \]\)

Finally, solving:

\(\[\frac{dy}{dx} = \frac{0}{y - x} = 0\]\)

Therefore, the derivative \(\( y' \)\) of the given implicit function is 0.

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If A and B are square matrices, then they satisfy the following properties: a) tr(A + B) = tr(A) + tr(B) (b) tr(kA) = ktr(A) where k is a scalar

a) Proof: Let A and B be two n x n matrices. Then,

tr(A + B) = Σi=1nAii + Σi=1nBii  = Σi=1n(Aii + Bii)

 = Σi=1nAii + Σi=1nBii

 = tr(A) + tr(B)  



b) Proof: Let A be an n x n matrix. Then,

tr(kA) = Σi=1n(kA)ii = Σi=1nk(Aii) = kΣi=1nAii = ktr(A)

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Answer:

5.02 pounds

Step-by-step explanation:

y = k*x

Where,

y = weight of a object on Jupiter

x = weight of the object on earth

k = constant of proportionality

An object that weighs 150 ponds on earth would weigh 378.2 ponds on Jupiter.

y = k*x

378.2 = k*150

378.2 = 150k

k = 378.2/150

= 2.5213

Approximately k = 2.52

determine how Much a rock that weigh 12.64 on Jupiter would weigh on earth

y = k*x

12.64 = 2.52*x

12.64 = 2.52x

x = 12.64 / 2.52

= 5.0159

Approximately x = 5.02 pounds

Answer:

36 prices

Step-by-step explanation:

Given the following :

Dentist bought 9 bags of prizes for his patients

Each bag had 12 prizes, and prices were divided equally among three boxes: The each box will. Have :

Total number of prices :

Number of bags × number of prices per bag

9 × 12 = 108 prices

Number of boxes in which prices were equally distributed = 3

Hence, each box will have :

Total prices / number of boxes

= 108 / 3

= 36 prices per box

Answer: C I think

Step-by-step explanation:

Answer:

The answer is C on edg

Step-by-step explanation:

Answer:

Step-by-step explanation:

   9² + 10² + 11² + ......... 20² =

= 9² + 10² + 11² + 12² + 13² + 14² + 15² + 16² + 17² + 18² + 19² + 20² =

= 81 +100 +121 +144 +169 +196 +225 +256 +289 +324 +361 +400 =

= 2666

First, we want to note two things:

We can describe this with an inequality:  x ≥ -10
Be sure you use ≥ and not >, since -10 is included.

We can describe this with interval notation: [ -10, infty )
Be sure you use [ and not ( on -10, since -10 is included.

You can also use set-builder notation: { x | x ≥ -10 }

PART A:

In the expression -7 - (-9), we can combine both negative signals and create a positive signal, so the expression will be -7 + 9.

That means in the number line we start at the number -7 and go 9 units to the right.

So Karissa is not correct, because she said a different starting point and a different direction to add the 9 units.

PART B:

Let's solve the equation:

We can see that the equation is not true, since the final statement is false. So Hugo is not correct, because the final values of each side of the equation didn't match.

The line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1, 1), and the line segment from (1,1) to (0,1) is equal to 2/5.

What is integral?

The value obtained after integrating or adding the terms of a function that is divided into an infinite number of terms is generally referred to as an integral value.

To evaluate the line integral using Green's theorem, we need to find a vector field F = (P, Q) such that ∇ × F = Qₓ - Pᵧ, where Qₓ represents the partial derivative of Q with respect to x, and Pᵧ represents the partial derivative of P with respect to y.

Let's consider F = (P, Q) = (x²y², xy).

Now, let's calculate the partial derivatives:

Qₓ = ∂Q/∂x = ∂(xy)/∂x = y

Pᵧ = ∂P/∂y = ∂(x²y²)/∂y = 2x²y

The curl of F is given by ∇ × F = Qₓ - Pᵧ = y - 2x²y = (1 - 2x²)y.

Now, let's find the line integral using Green's theorem:

∫[C] (Pdx + Qdy) = ∫∫[R] (1 - 2x²)y dA,

where [R] represents the region enclosed by the curve C.

To evaluate the line integral, we need to parameterize the curve C.

The arc of the parabola y = x² from (0, 0) to (1, 1) can be parameterized as r(t) = (t, t²) for t ∈ [0, 1].

The line segment from (1, 1) to (0, 1) can be parameterized as r(t) = (1 - t, 1) for t ∈ [0, 1].

Using these parameterizations, the region R is bounded by the curves r(t) = (t, t²) and r(t) = (1 - t, 1).

Now, let's calculate the line integral:

∫∫[R] (1 - 2x²)y dA = ∫[0,1] ∫[t²,1] (1 - 2t²)y dy dx + ∫[0,1] ∫[0,t²] (1 - 2t²)y dy dx.

Integrating with respect to y first:

∫[0,1] [(1 - 2t²)(1 - t²) - (1 - 2t²)t²] dt.

Simplifying:

∫[0,1] [1 - 3t² + 2t⁴] dt.

Integrating with respect to t:

[t - t³ + (2/5)t⁵]_[0,1] = 1 - 1 + (2/5) = 2/5.

Therefore, the line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1,1), and the line segment from (1,1) to (0,1) is equal to 2/5.

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Based on the characteristics of the distribution, the probability that the first goal is scored in less than 4 minutes is 0.

For us to be able to calculate the probability that the first goal is scored in less than 4 minutes, the distribution needs to satisfy the requirements of the Central Limit Theorem(CLT).

Based on the fact that the distribution here is extremely right skewed, then it does not satisfy the requirements of CLT so the probability is 0.

First part of question:

The distribution of the time it takes for the first goal to be scored in a hockey game is known to be extremely right skewed with population mean 12 minutes and population standard deviation 8 minutes.

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Answer:

bd=12

Step-by-step explanation:

Answer:

x=18 if u are solving and bd=12

Step-by-step explanation:

Answer:b

Step-by-step explanation:

Answer:

can you please send the diagram for it to be clear

Jenna and Mia arrived at the same answer because both the methods they have adopted are correct.

Given solution of a question done by two people.

Jenna's method

5(30+4)

(5)(30)+(5)(4)

150+20=170

Mia's method

5(30+4)

5(34)=170

We are required to find why they have achieved at the same answer.

Jenna and Mia have achieved at the same answer because they both have adopted the right method.Jenna's method is the equation in its simplest form. Addition of that is easily understood. While Mia's method is just valid as Jenna's some people may have trouble remembering the steps of multiplication within parantheses as well as being able to look at large multiplication problem and automatically knowing the answer or being able to get the answer as fast as simple addition.

Hence Jenna and Mia arrived at the same answer because both the methods they have adopted are correct.

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The rate of change of the side of the square is 1.5 centimeters per second when the area is 3 square centimeters.

Let's denote the side length of the square as s, and the area of the square as A. Then we know that \(A = s^2\). We are given that \(dA/dt = 30 cm^2/s\), which means that the area of the square is increasing at a rate of \(30 cm^2/s\). We want to find ds/dt, the rate of change of the side of the square.

Using the chain rule, we have:

\(dA/dt = d/dt (s^2) = 2s ds/dt\)

Solving for ds/dt, we get:

\(ds/dt = (1/2s) dA/dt\)

When the area is \(3 cm^2\), the side length is \(s = \sqrt{3} cm\). Plugging in dA/dt = 30 cm^2/s and s = sqrt(3) cm, we get:

\(ds/dt = (1/2(\sqrt{3})) (30) = 1.5 cm/s\)

Therefore, the rate of change of the side of the square is 1.5 cm/s when the area is 3 cm^2.

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a) The forecast is approximately miles. b) the Mean Absolute Deviation (MAD) based on the forecast is approximately miles. c) The forecast for year 6 is approximately miles. d) the last forecast is 3,468 miles.

a) To calculate the forecast for year 6 using a 2-year moving average, we take the average of the mileage for years 5 and 4. This provides us with the forecasted value for year 6.

b) The Mean Absolute Deviation (MAD) for the 2-year moving average forecast is calculated by taking the absolute difference between the actual mileage for year 6 and the forecasted value and then finding the average of these differences.

c) When using a weighted 2-year moving average, we assign weights to the most recent and previous periods. The forecast for year 6 is calculated by multiplying the mileage for year 5 by 0.40 and the mileage for year 4 by 0.60, and summing these weighted values.

The MAD for the weighted 2-year moving average forecast is calculated in the same way as in part b, by taking the absolute difference between the actual mileage for year 6 and the weighted forecasted value and finding the average of these differences.

d) Exponential smoothing involves assigning a weight (α) to the most recent forecasted value and adjusting it with the previous actual value. The forecast for year 6 is calculated by adding α times the difference between the actual mileage for year 5 and the previous forecasted value, to the previous forecasted value.

In this case, with α=0.20 and a forecast of 3,100 miles for year 1, we perform this exponential smoothing calculation iteratively for each year until we reach year 6, resulting in the forecasted value of approximately 3,468 miles.

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Answer:

\(Speed = \frac{Distance}{Time } = \frac{120}{3} = 40mph\)

T = 75minutes = (75/60) hours

\(Distance = Speed \times Time = 40 \times \frac{75}{60} =\frac{40\times 75}{60} = 50miles\)

option A

Answer:

B. 60 miles

Step-by-step explanation:

Answer:

it's A

Step-by-step explanation:

just did it made 80

Answer:

heyy hello how r u? I hope u r fine

The size of the angle x which is the missing angle of the lines is:  224°

We know that supplementary angles are angles that sum up to 180 degrees. Thus, the supplementary angle to 61 degrees is : 180 - 61 = 119 degrees

Now, we know that opposite angles are the angles that are directly opposite each other where two lines cross.

Thus, the opposite angle to 61 degrees inside the triangle is 61 degrees.

The supplementary angle to 136 degrees is: 180 - 136 = 44 degrees

Thus, angle at the apex inside the triangle is:

180 - (44 + 61)

= 180 - 105

= 75 degrees

The alternate angle to 61 degrees inside the triangle is 61 degrees.

Angle at a point is 360 degrees. Thus:

x = 360 - (61 + 75)

x = 360 - 136

x = 224°

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Answer:

Step-by-step explanation:

To find the size of angle x, we can use the fact that the sum of angles in a triangle is always 180 degrees.

In this case, we have two angles given: 61 degrees and 136 degrees.

To find angle x, we can subtract the sum of these two angles from 180 degrees.

180 degrees - (61 degrees + 136 degrees) = 180 degrees - 197 degrees = -17 degrees.

However, since angles cannot have negative values, we can conclude that angle x has no meaningful measurement in this case.

Therefore, the size of angle x cannot be determined based on the given information.

Answer:

–1  

✔ <

Negative one-half

0  

✔ >

–1.5

Step-by-step explanation:

\(\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=65\pi \end{cases}\implies 65\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3}{4\pi}\cdot 65\pi =r^3 \\\\\\ \cfrac{195}{4}=r^3\implies \sqrt[3]{\cfrac{195}{4}}=r\implies 3.65\approx r\)

The coordinate vector of p(t) in basis B is a' = [1/2(a - c)  1/2(a + b)  1/2(b - c)].

In linear algebra, a coordinate vector is a representation of a vector in terms of its components with respect to a specific coordinate system or basis. It provides a way to express a vector as a tuple of numbers.

Given the following ordered bases

B = {1,1-t, t-t²} and

C = {1, t, t²} for P₂.

Let p(t) = ax² + bx + c be a polynomial in P₂.

We have to find:

(a) The change of coordinates matrix from C to B.

(b) The coordinate vector of p(t).SOLUTION

(a) The change of coordinates matrix from C to B.

The matrix is formed as:

[B]C = [C to B] =  [1  -1  1] [1  0  0][0  1  0] [-1  1  -1][0  0  1] [0  -1  1]

Therefore, the matrix is [B]C = [1  0  -1][1  1  0][-1  1  1]

(b) The coordinate vector of p(t).In order to find the coordinate vector of p(t) in basis B,

we have to use the change of coordinates matrix [B]C which is:

[1  0  -1][1  1  0][-1  1  1][a'] = [B]C [a]

To solve for the coordinate vector a', we multiply both sides of the equation by the inverse of [B]C which is:

[1/2   -1/2   1/2][1/2    1/2   0][-1/2   1/2   1/2][a'] = [1  0  -1][1  1  0][-1  1  1][a][a'] = [1/2(a - c)     1/2(a + b)][1/2(a + b)     b][1/2(a - c)     1/2(b - c)]

Therefore, the coordinate vector of p(t) in basis B is a' = [1/2(a - c)  1/2(a + b)  1/2(b - c)].

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Answer:

10

Step-by-step explanation:

(12 + x0.5) <= 17

Answer: A monomial representation is a way to express a polynomial as a product of powers of its variables, where each power is a non-negative integer. For example, the polynomial 2x^3 + 4x^2 - 6x + 8 can be represented as a monomial representation of (2x^3)(x^2)(-6x)(8).

Symmetric polynomials are polynomials that are invariant under permutation of their variables. A symmetric presentation is a way of expressing a symmetric polynomial as a sum of elementary symmetric polynomials, which are defined as the sum of all possible products of variables taken i at a time, where i ranges from 1 to the number of variables. For example, the symmetric polynomial x^3 + y^3 + z^3 can be expressed as a symmetric presentation of x + y + z.

Step-by-step explanation:

Answer:

bro this is answer or questions

Step-by-step explanation:

can u repeat at short

Answer:

I think it would be B

Step-by-step explanation:

EFG is congruent to HJK, then HJK is congruent to EFG.