find the zeros
p(x)=5x3 −5x 2 −10x
and then place them on a graph

The measure of arc BC is 720 times the measure of angle BAC.

Given that AC is the diameter of the circle and AB is a chord with a length of 16 units, we need to find BC (the length of the other chord) and mBC (the measure of angle BAC).

To find BC, we can use the property of chords in a circle. If two chords intersect within a circle, the products of their segments are equal. In this case, since AB = BC = 16 units, the product of their segments will be:

AB * BC = AC * CE

16 * BC = 2 * r * CE (AC is the diameter, so its length is twice the radius)

Since the area of the circle is given as 289 square units, we can find the radius (r) using the formula for the area of a circle:

Area = π * r^2

289 = π * r^2

r^2 = 289 / π

r = √(289 / π)

Now, we can substitute the known values into the equation for the product of the segments:

16 * BC = 2 * √(289 / π) * CEBC = (√(289 / π) * CE) / 8

To find mBC, we can use the properties of angles in a circle. The angle subtended by an arc at the center of a circle is double the angle subtended by the same arc at any point on the circumference. Since AC is a diameter, angle BAC is a right angle. Therefore, mBC will be half the measure of the arc BC.

mBC = 0.5 * m(arc BC)

To find the measure of the arc BC, we need to find its length. The length of an arc is determined by the ratio of the arc angle to the total angle of the circle (360 degrees). Since mBC is half the arc angle, we can write:

arc BC = (mBC / 0.5) * 360

arc BC = 720 * mBC

Therefore, the length of the arc BC equals 720 times the length of the angle BAC.

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The task requires analyzing a list of departments and performing several tasks related to relationship codes, activity relationship diagrams, reason codes, a worksheet, and a dimensionless block diagram.

We need to consider the number of departments. Since we have 7 departments listed, the number of relationship codes can be calculated using the formula: (n * (n-1)) / 2, where n is the number of departments.

Substituting the value of n = 7, we get:

Relationship Codes = (7 * (7-1)) / 2

= (7 * 6) / 2

= 42 / 2

= 21

Therefore, there will be 21 relationship codes in the chart.

Create an activity relationship diagram:

An activity relationship diagram visually represents the relationships between departments. Here is a basic diagram representing the given departments:

Receiving --+

           +-- Assembly & Shipping -- Offices

Fabrication--+

           +-- Painting -- Stores

Restrooms & Lockers

Populate the diagram with codes for all the relationships:

To populate the diagram with codes, we can assign a unique code to each relationship. Here's an example of assigning codes to the relationships in the diagram:

Receiving (R) --+

               +-- Assembly & Shipping (AS) -- Offices (O)

Fabrication (F)--+

               +-- Painting (P) -- Stores (S)

Restrooms & Lockers (RL)

What is the percentage of codes in each category? Does it follow the standard percentages?

To determine the percentage of codes in each category, we need to count the number of codes in each category and calculate the percentage relative to the total number of codes (21).

In this case, we have the following categories and their respective codes:

Production: R, F, AS, P (4 codes)

Administration: O, S (2 codes)

Support: RL (1 code)

Percentage of Production codes = (4 / 21) * 100 ≈ 19.05%

Percentage of Administration codes = (2 / 21) * 100 ≈ 9.52%

Percentage of Support codes = (1 / 21) * 100 ≈ 4.76%

These percentages do not necessarily follow any standard percentages. The distribution of codes among categories can vary depending on the specific organization or context.

Provide at least 3 reason codes for the chart:

Reason codes are used to provide explanations or justifications for the relationships depicted in the chart. Here are three example reason codes for the given chart:

R01: Receiving department receives raw materials and supplies from external sources.

AS01: Assembly & Shipping department assembles products and prepares them for shipment.

O01: Offices department provides administrative support and management functions for the organization.

Create a worksheet to assist in the creation of the dimensionless block diagram:

Here's an example of a worksheet that can assist in creating the dimensionless block diagram:

Relationship Code From Department To Department

R Receiving Fabrication

F Fabrication Painting

AS Assembly & Shipping Offices

P Painting Stores

RL Restrooms & Lockers -

O Offices -

S Stores -

This worksheet lists the relationship codes along with the corresponding "From" and "To" departments.

Create a dimensionless block diagram for your data B. Show the flow through the dimensionless block diagram:

A dimensionless block diagram represents the flow of activities or information between different departments. Here's an example of a dimensionless block diagram based on the given data:

Receiving --> Fabrication --> Painting --> Stores

                  |

                  v

        Assembly & Shipping --> Offices

                  |

                  v

       Restrooms & Lockers

The arrows indicate the flow of activities or information from one department to another.

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The ratio of the population of the second germ to the population of the first germ can be represented by option A, "R(x) = (2.6)^(3x-8), since 2.6 is the same as (1.3)^2". This can be solved by the concept of Ratio and Proportions.

The best function that represents the ratio of the population of the second germ to the population of the first germ is option A, R(x)=(2.6)^3x-8.

To find the ratio of the population of the second germ to the population of the first germ, we need to divide the second germ's population function by the first germ's population function.

R(x) = B(x)/A(x) = ((1.3)^4x+1)/((1.3)^x+9)

To simplify this expression, we can use the rule of exponents that states (a^m)/(a^n) = a^(m-n), and we get:

R(x) = (1.3)^(4x+1-x-9) = (1.3)^(3x-8)

Therefore, the ratio of the population of the second germ to the population of the first germ can be represented by option A, R(x) = (2.6)^(3x-8), since 2.6 is the same as (1.3)^2

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Answer:

A+c

Step-by-step explanation:

because common sense

Answer:3/8

Step-by-step explanation:

The equation that represent the relationship model that will reach $0 in the same number of days as the scenario gave is: y = -2x + 12

To solve this problem, we have to state the equation using the information of the problem.

Information about the problem:

Writing the equation according to the information gave, we have:

y = -2x + 12

Where:

So that (y) equals zero, the number of days (x) should be = 6

y = -2x + 12

0 = -2*6 + 12

0 = -12 + 12

0 = 0

The "y" variable is the dependent variable, because it will change according to the number of days passed (x).

The "x" variable is the independent variable, because it doesn't depend on any other value, just the number of days passed.

An equation is the equality between two algebraic expressions, which have at least one unknown or variable.

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Answer:

24,25,26

Step-by-step explanation:

Answer:

Step-by-step explanation:

25

There are 853,818,600 ways to award first, second, and third prizes in a contest with 950 contestants, assuming there are no ties.

To determine the number of ways to award first, second, and third prizes in a contest with 950 contestants, we can use the permutation formula:

P(n, r) = n! / (n - r)!

where n is the total number of contestants and r is the number of prizes to be awarded (in this case, 3).

Using this formula, we get:

P(950, 3) = 950! / (950 - 3)!

= 950! / 947!

= 950 × 949 × 948

= 853,818,600

Therefore, there are 853,818,600 ways to award first, second, and third prizes in a contest with 950 contestants, assuming there are no ties.

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Answer:

it Would be easier to answer with a picture but since these Question are normaly the same picture but it is Angle 3 and 7

Step-by-step explanation:

#NO ADDS

⇒For perpendicular lines when their gradients are multiplied they have to give -1, in this case we are given a line with gradient \(\frac{1}{2}\) meaning the gradient of the line perpendicular to it will be -2 since

\(-2*\frac{1}{2} =-1\)  this means that the gradient of the new line will be -2

⇒Now we have a point and  gradient.

⇒And we know that the general equation for a straight line is y=mx+c

\(3=-2(0)+c\\3=c\\c=3\)

The equation of the line perpendicular to the given one is

y=-2x+3

GOODLUCK!!

Answer:They are equal

Step-by-step explanation:

they will add up they are just token apart or in pieces

Three different figures are given. The area of the shaded region of all the figures is the same.

We need to determine the highest shaded area among all.

Now, the area of the square is common to all.

Thus,

\(\begin{aligned}\rm{Area\;of\;square}&=12^2\\&=144 \;\rm{units^2}\end{aligned}\)

1). Calculate the shaded area for figure A.

The diameter of the circle is 12 units, hence its radius is 6 units.

Therefore,

\(\begin{aligned}\rm{Area\;of\;circle}&=\pi \times 6^2\\&=36 \pi \;\rm{units^2}\end{aligned}\)

\(\begin{aligned} \rm{Shaded\; area} &= \rm{Area\; of\; the\; square - Area\; of\; the\; circle}\\&=144-36 \pi \end{aligned}\)

Thus, the area of the shaded region for figure 1 is \(114-36 \pi\).

2). Calculate the shaded area for the figure B.

The diameter of the circle is 6 units, hence its radius is 3 units.

Therefore,

\(\begin{aligned}\rm{Area\;of\;circle}&=\pi \times 3^2\\&=9 \pi \;\rm{units^2}\end{aligned}\)

\(\begin{aligned} \rm{Shaded\; area} &= \rm{Area\; of\; the\; square - 4 \times Area\; of\; the\; circle}\\&=144-36 \pi \end{aligned}\)

Thus, the area of the shaded region for figure 2 is \(114-36 \pi\).

3). Calculate the shaded area for figure C.

The diameter of the circle is 4 units, hence its radius is 2 units.

Therefore,

\(\begin{aligned}\rm{Area\;of\;circle}&=\pi \times 2^2\\&=4 \pi \;\rm{units^2}\end{aligned}\)

\(\begin{aligned} \rm{Shaded\; area} &= \rm{Area\; of\; the\; square - Area\; of\; the\; circle}\\&=144-36 \pi \end{aligned}\)

Thus, the area of the shaded region for figure 3 is \(114-36 \pi\).

Therefore, the area of the shaded region of all the figures is the same.

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Answer:

18.41

Step-by-step explanation:

31.56/12 = 2.63

2.63 X 7 = 18.41

Have a great day!

Please rate and give brainliest!

Step-by-step explanation:

(f + g)(-1) = f(-1) + g(-1)

f(-1) = -1 -2 = -3

g(-1) = (-1)² + (-1) -6 = -6

(f+g)(-1) = -9

Answer:

(f + g)(- 1) = - 9

Step-by-step explanation:

note (f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x - 2 + x² + x - 6 ← collect like terms

= x² + 2x - 8

To evaluate (f + g)(- 1) substitute x = - 1 into (f + g)(x), that is

(f + g)(- 1)

= (- 1)² + 2(- 1) - 8 = 1 - 2 - 8 = - 9

Answer:

A because when you subtract x will be less than the unknown number

It seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.

To compute the flux of the vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ through the surface S given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0, oriented toward the xz-plane, we can use the surface integral.

The surface integral of a vector field F⃗ over a surface S is given by the formula:

∬S F⃗ · dS = ∬S F⃗ · (n⃗ dS)

where F⃗ is the vector field, dS is the differential area vector, and n⃗ is the unit normal vector to the surface.

In this case, the surface S is given by y=x^2+z^2, with 0≤y≤16, x≥0, z≥0. We can parameterize this surface as:

r(x, z) = xi⃗ + yj⃗ + zk⃗ = xi⃗ + (x^2+z^2)j⃗ + zk⃗

To find the normal vector n⃗ to the surface, we can take the cross product of the partial derivatives of r(x, z) with respect to x and z:

n⃗ = ∂r/∂x × ∂r/∂z

= (1i⃗ + 2xj⃗) × (0i⃗ + 2zj⃗)

= -2xz i⃗ + 2zj⃗ + 2xk⃗

Now, we can calculate the flux:

∬S F⃗ · (n⃗ dS) = ∬S (3(x+z)i⃗ + 2j⃗ + 3zk⃗) · (-2xz i⃗ + 2zj⃗ + 2xk⃗) dS

= ∬S (-6x^2z - 4xz + 6xz^2 + 6xz) dS

= ∬S (-6x^2z + 2xz + 6xz^2) dS

To evaluate this integral, we need to determine the limits of integration for x, y, and z.

Since the surface is defined by 0≤y≤16, x≥0, z≥0, we have:

0 ≤ y = x^2 + z^2 ≤ 16

Simplifying the inequality, we get:

0 ≤ x^2 + z^2 ≤ 16

From this, we can see that x and z both range from 0 to 4.

Now, we can evaluate the flux:

∬S (-6x^2z + 2xz + 6xz^2) dS = ∫∫ (-6x^2z + 2xz + 6xz^2) dA

where dA is the differential area.

Integrating over the limits 0 ≤ x ≤ 4 and 0 ≤ z ≤ 4, we can calculate the flux.

However, it seems there is an error in the given vector field F⃗ = 3(x+z)i⃗ + 2j⃗ + 3zk⃗ as it does not have a component along the y-axis. Please double-check the vector field or provide the correct vector field to proceed with the calculation.

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Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.

Explanation: Metric length is a measurement system that uses the metric unit. The metric unit is more common than the customary unit system in the United States. To convert customary unit lengths to metric lengths, a conversion factor is used.3 inches is the measurement of the scar in customary units. To convert 3 inches to metric units, multiply it by the conversion factor. There are 2.54 centimeters in one inch, which is the conversion factor. To find the equivalent metric length of a 3-inch scar, multiply 3 by 2.54. Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.  The equivalent metric length of a 3-inch scar would be 7.62 centimeters. Metric length is a measurement system that uses the metric unit. The metric unit is more common than the customary unit system in the United States. To convert customary unit lengths to metric lengths, a conversion factor is used. There are 2.54 centimeters in one inch, which is the conversion factor.

Therefore, the equivalent metric length of a 3-inch scar would be 7.62 centimeters.

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The appropriate statistical test to use is the two-sample t-test. This test compares the means of two independent samples and determines if there is a significant difference between them.

In this scenario, the goal is to compare the mean amount of money spent on food for two groups: students who live on campus and students who live off campus. Since the two groups are independent of each other, the two-sample t-test is the appropriate choice.

The two-sample t-test compares the means of the two groups and calculates a t-statistic and a p-value. The t-statistic measures the difference between the means relative to the variability within each group, while the p-value indicates the probability of observing such a difference by chance alone.

By conducting a two-sample t-test on the collected data from the random samples of 40 students from each group, we can determine if there is evidence of a significant difference in the mean amount of money spent on food between the two groups. The null hypothesis assumes that there is no difference between the means, while the alternative hypothesis suggests that there is a significant difference. The p-value obtained from the test will determine if there is sufficient evidence to reject the null hypothesis and conclude that there is a difference in the mean amount spent on food between the two groups.

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Answer:

3.7feet

Step-by-step explanations

Using the sin rule

A/sin a = B/sin b

Let A = PQ = 8.5feet

B = QR = x feet

a = R = 90°

b = P = 26°

Substitute the values into the Sin rule

8.5/sin90 = x/sin26

8.5×sin 26 = x × sin 90

8.5×0.4383 = x× 1

3.7255 = x

Hence the length of QR to the nearest tenth 3.7feet

Answer:

i think 200 paws

Step-by-step explanation

120 dogs paws

80 cats paws

200 paws

Answer:

200

______________________________________________________

Step-by-step explanation:

well, lets start w dogs.

dogs and cats both have four paws each.

30 x 4 = 120

cats now.

20 x 4 = 80

80 + 120 = 200

Answer:

A = 48 square units

Step-by-step explanation:

The dimensions between two markings on the coordinate plane = 2 unit

The trapezoid is located sideways

The area of a trapezoid, A = ((a + b)/2) × h

Where;

a = The long base side

b = The short base side

h = The height

The long base side length AT = 4 space between markings = 4 × 2 units = 8 units

The short base side length SR = 2 space between markings = 2 × 2 units = 4 units

The height, h = 4 space between markings = 4 × 2 units = 8 units

The area of the trapezoid, A = ((4 unit + 8 unit)/2) × 8 unit = 48 square units.

To find the derivative f'(x) of the function f(x) = 5x using the definition of a derivative, we use the following formula:

f '(x) = lim(h -> 0) [f(x + h) - f(x)] / h

Substituting f(x) = 5x, we get:

f '(x) = lim(h -> 0) [f(x + h) - f(x)] / h

f '(x) = lim(h -> 0) [5(x + h) - 5x] / h

f '(x) = lim(h -> 0) (5h / h)

f '(x) = lim(h -> 0) 5

f '(x) = 5

Therefore, the derivative of f(x) = 5x is f '(x) = 5.

To find the second derivative f''(x), we differentiate f'(x) with respect to x:

f ''(x) = d/dx [f '(x)]

f ''(x) = d/dx [5]

f ''(x) = 0

Therefore, the second derivative of f(x) = 5x is f ''(x) = 0.

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The first Option is the correct option

Answer:

1/2 cup of carrot juice for each cup of apple juice.

Step-by-step explanation:

The ratio of carrot juice to apple juice is 3:6

Also written as 1:2

1/2 cup of carrot juice per 1 cup of apple juice

(a) Expected number of repairs per year is 0.33 (b) Standard deviation of number of repairs per year is 0.749, (c) The mean and standard deviation of annual expense are $136.55 and $26.217 respectively.

Standard deviation is a measure in statistics which measures the amount of deviation a set of data has with respect to their mean.

(a) Expected number of repairs for the freezer per year is the sum of the product of number of repairs to their probability.

E(Repairs) = (0 × 0.80) + (1 × 0.11) + (2 × 0.05) + (3 × 0.04)

                 = 0.33

(b) Standard deviation of number of repairs per year can be calculated as,

SD(Repairs) = \(\sqrt{[(0 - 0.33)^{2}(0.8)]+[(1-0.33)^{2}(0.11)] + [(2-0.33)^{2}(0.05)]+[(3-0.33)^{2}(0.04)] }\)

= √ (0.5611)

= 0.749

(c) Mean of the restaurant's annual expense with service contract is,

Mean = Expected cost = $125 + ($35 × 0.33) = $136.55

Standard deviation of the restaurant's annual expense with service contract is,

SD = \(\sqrt{35^{2}(0.5611) }\) = 35 × 0.759 = 26.217

Hence the expected number of repairs is 0.33, standard deviation of number of repairs is 0.749, mean and standard deviation of annual expense is $136.55 and $26.217 respectively.

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Answer:

there are 2,730 different ways to choose a president, vice president, and treasurer from the student club consisting of 10 computer science majors and 5 mathematics majors.

Step-by-step explanation:

To choose three different members from the club to be president, vice president, and treasurer, you can follow these steps:

Step 1: Calculate the number of ways to choose the president:

Since there are 15 club members in total, the number of ways to choose the president is 15.

Step 2: Calculate the number of ways to choose the vice president:

After selecting the president, there are 14 remaining members. The number of ways to choose the vice president from these 14 members is 14.

Step 3: Calculate the number of ways to choose the treasurer:

After selecting the president and vice president, there are 13 remaining members. The number of ways to choose the treasurer from these 13 members is 13.

Step 4: Calculate the total number of ways to choose the president, vice president, and treasurer:

Since each step is independent, you can multiply the number of choices at each step: 15 * 14 * 13 = 2,730.

Therefore, there are 2,730 different ways to choose a president, vice president, and treasurer from the student club consisting of 10 computer science majors and 5 mathematics majors.

Answer:

See below.

Step-by-step explanation:

Vertical angles can be found by adding the two degrees, and if they equal 180, they are vertical.

94 and 86

119 and 61

-hope it helps

The box and whisker plot of the prices of some DVDs:

Minimum: 9.99

First Quartile: 12.99

Median: 15.99

Third Quartile: 19.99

Maximum: 26.99

The box and whisker plot shows that the median price of a DVD is $15.99. The prices range from $9.99 to $26.99. There are two outliers, one at $9.99 and one at $26.99.

The box and whisker plot can be used to identify the distribution of the data. In this case, the data is slightly skewed to the right, meaning that there are more DVDs priced at the lower end of the range than at the higher end.

The box and whisker plot can also be used to compare different sets of data. For example, we could compare the prices of DVDs from different stores or from different years.

Overall, the box and whisker plot is a useful tool for visualizing and summarizing data.

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Answer:

24 or 10

Step-by-step explanation:

unluckily, when you copied the text you did not paste well the value of x, but I assume it is 1.2 or 1/2

for the first value, the K (costant of variation) is 24, while for the second is 10, as the photo explains