Find the wavelength of an electron (mass = 9.1 × 10^-31 kg) move with 2 × 10^7 m/s of speed. (Planck constant = 6.6 × 10^-34 J/s)

\(\\ \bull\tt\longmapsto Volume=LBH\)

\(\\ \bull\tt\longmapsto Volume=8(4)(3)\)

\(\\ \bull\tt\longmapsto Volume=96m^3\)

Answer:

Formular:

\({ \boxed{ \bf{v = length \times width \times height}}}\)

» length, l = 8m

» width, w = 4m

» height, h = 300cm = 3 m

\({ \tt{• Therefore :→}} \: { \sf{ volume = (8 \times 4 \times 3)}} \\ → { \sf{ \underline{ \: \: volume = 96 \: {m}^{3} \: \: }}}\)

Answer:

a 15.6voltz

i Hope this helps

The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.

Here, u = 25 cm for the object distance (To the left of the mirror)

Also, the focal length is f = 20 cm (It is a concave mirror)

What is the size of the image in a concave mirror?

The size of image formed by a concave mirror is same as the size of object.

Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.

However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.

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The concave mirror is represented by a vertical line MMl. The principal axis is represented by a horizontal line drawn on the PC. 1 mm. 12 mm (focal length: 12 cm); I Image position.

Here, u = 25 cm for the object distance (To the left of the mirror)

Also, the focal length is f = 20 cm (It is a concave mirror)

What is the size of the image in a concave mirror?

The size of image formed by a concave mirror is same as the size of object.

Use the magnification of a mirror formula to obtain the size of the object. Accordingly depict its nature using the sign of the image height. Where v is the image distance u is the object distance and f is the focal length.

However, if we increase the distance between the object and the mirror then the size of the image reduces and a real and inverted image is formed. The image formed by the concave mirror can be small or large and can be real or virtual.

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The submarine's maximum safe depth is 785.4 meters.

The maximum safe depth of the submarine can be calculated using the equation for hydrostatic pressure, which is P = ρgh, where P is the pressure, ρ is the density of seawater, g is the acceleration due to gravity, and h is the depth.

Since the pressure inside the submarine is maintained at 10 atm, or 1013.25 kPa, we can calculate the maximum safe depth by equating the pressure on the window to the hydrostatic pressure at that depth.

Solving for h, we get h = (120x\(10^6\)N) / (1013.25 kPa - 1 atm) / (π\((0.15 m)^2\)x 9.81 m/\(s^2\)) = 785.4 meters.

Therefore, the submarine's maximum safe depth is 785.4 meters.

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The maximum safe depth of the submarine is approximately 1337 meters.

To determine the maximum safe depth of the submarine, we need to use the formula for hydrostatic pressure: P = ρgh, where P is the pressure, ρ is the density of the fluid (in this case, seawater), g is the acceleration due to gravity, and h is the depth. We can rearrange this equation to solve for h: h = P/ρg.

First, we need to convert the diameter of the window to meters: 30.0 cm = 0.3 m. The area of the window is then A = (π/4)(0.3 m)^2 = 0.0707 m^2. The force that the window can withstand, 120x10^6 N, is equal to the pressure multiplied by the area of the window: P = F/A = 120x10^6 N / 0.0707 m^2 = 1.70x10^9 Pa.

Next, we need to determine the density of seawater and the acceleration due to gravity. The density of seawater is approximately 1025 kg/m^3, and the acceleration due to gravity is 9.81 m/s^2. Plugging these values into the equation for h, we get h = 1.70x10^9 Pa / (1025 kg/m^3)(9.81 m/s^2) = 1337 meters. Therefore, the maximum safe depth of the submarine is approximately 1337 meters.

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Spring constant (k) of the spring, The spring constant (k) of the spring is 881.16 N/m.

Given that a mass of 2.1 kg is attached to a spring and is set into vibration with a period of 0.7 s.

Formula to calculate the spring constant (k) of the spring is given as:

k = (4π²m)/T²

Where,

Now, substituting the values in the formula, we get;

k = (4π²m)/T²k = (4 × 3.14² × 2.1)/(0.7)²k = (4 × 9.8596 × 2.1)/0.49k = 82.73496/0.49k = 168.7298 N/m

Therefore, the spring constant (k) of the spring is 881.16 N/m.

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The triangles formed by the rays reflected by the mirror are similar, such

that the height of the mirror is sum of half the height of the image.

Responses:

a) Height of the mirror is 0.81 m

b) Distance of the mirror above the floor is 0.735 m

a) Angle of incidence = Angle of reflection

The angle formed by the ray from the feet to the mirror, reflected to the

eye are equal.

Therefore, the ray from the feet reflected to the eye forms similar

triangles.

Distance from the persons eyes to the head, h₂ = 15 cm = 0.15 m

Therefore;

Height from the persons eye to the feet, h₁ = 1.62 m - 0.15 m = 1.47 m

\(Height \ of \ the \ mirror = \mathbf{\dfrac{h_1 + h_2}{2}}\)

Which gives;

b) The distance of the mirror above the ground is given as follows;

\(Distance \ of \ the \ mirror \ above \ the \ floor = \mathbf{\dfrac{h_2 }{2}\alpha}\)

Which gives;

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Answer:

In 1945, the United Nations created the Universal Declaration of Human Rights (UDHR), which is a milestone document that outlines the fundamental human rights to be universally protected. The UDHR includes 30 articles that cover a wide range of rights, such as the right to life, liberty and security, freedom of speech and religion, and the right to education and work. The UDHR has been translated into over 500 languages and has served as the basis for the development of many national and international human rights laws and conventions.

Explanation:

\( \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \sin(60 ) {}^{2} = ( \frac{ \sqrt{3} }{2} ) {}^{2} \\ \\ \sin(60 ) {}^{2} = \frac{3}{4} \)

Answer:

please find attached pdf

Explanation:

Answer:

Kg to g we multiply by 1000

Explanation:

6.57×1000=6570g

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                                              continental crust

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                                             Continental rifting

If the diverging plates are capped by continental crust, fractures develop that are invaded by the ascending magma, prying the continents farther apart. Settling of the continental blocks creates a rift valley, such as the present-day East African Rift Valley.

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

The shape of the graph will be linear and the average acceleration is -0.278 m/s².

The average acceleration of an object is the rate of change of velocity of the object with time.

Mathematically it is given as;

a = Δv/Δt

a = (v2 - v1)/(t2 - t1)

where;

Substitute the given parameters and solve for the average acceleration.

a = (8.33 - 13.89) / (40 - 20)

a = -0.278 m/s²

Thus, the shape of the graph will be linear and the average acceleration is -0.278 m/s².

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When the satellite reaches the position 2.9, 2.2, 5.4m, its speed is 6.04 m/s, work done by friend = 2340J

The work done by the friend in docking the satellite can be calculated as follows: From the given data, the position vector, initial velocity vector, final position vector and final velocity vector of the satellite are:4.0, -1.4, 3.0 m, 0,0,0 m/s, 2.9,2.2,5.4 m, and 0,0,6.04 m/s respectively.

The distance between the initial position and final position of the satellite is: s = (2.9 - 4.0)+ (2.2 + 1.4) + (5.4 - 3.0)= -1.1 + 3.6  + 2.4  m

The net force F applied on the satellite is: F = -600, 300, 250 N. The displacement of the satellite due to the force applied by the friend is given by:

d = (2.9 - 4.0) + (2.2 + 1.4)  + (5.4 - 3.0) = -1.1  + 3.6  + 2.4 km

The work done by the friend can be calculated using the dot product of the force F and the displacement d: W = F · d= -600 × (-1.1) + 300 × 3.6 + 250 × 2.4= 660 + 1080 + 600= 2340 J

Therefore, the work done by the friend in docking the satellite is 2340J

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Answer:

Explanation:

If Tim jogs a distance of 7.2 km to the west and then he turns south and jogs 1.4 km, the resultant displacement of Tim is calculated using the pythagoras theorem as shown;

R² = 7.2²+1.4²

R² = 51.84+1.96

R² = 53.8

R = √53.8

R = 7.33 km

Hence  the resultant of Tim's jog back to the beginning is 7.33km

Assuming you are supposed to write each conversion in scientific notation:

(2) 1 m = 100 cm, so

(67 cm) × (1/100 m/cm) = 67/100 m = 0.67 m = 6.7 × 10 ⁻¹ m

(3) 1 km = 1,000 m, so

(1.2 km) × (1000 m/km) = 1200 m = 1.2 × 10³ m

(4) 1 m = 1,000 mm = 10³ mm, so

(6.2 × 10 ⁻³ m) × (10³ mm/m) = 6.2 mm

(5) 1 m = 1,000,000,000 nm = 10⁹ nm, so

(4.05 × 10³ nm) × (1/10⁹ m/nm) = 4.05 × 10 ⁻⁶ m

(6) 1 g = 1,000,000 µg = 10⁶ µg, so

(3200 µg) × (1/10⁶ g/µg) = 3200 × 10 ⁻⁶ g = 3.2 × 10 ⁻³ g

Rock, metal, ice, and gas are distributed in the solar system in an orderly manner.

Numerous tiny things in the Solar System are orbiting the Sun, including an unknown number of dwarf planets. Natural satellites, also known as "moons" after the Moon of Earth, orbit the six major planets, the six largest dwarf planets, and many of the smaller worlds. Jupiter's moon Callisto is almost as big as Mercury, the smallest terrestrial planet, and two natural satellites, Saturn's moon Titan and Jupiter's moon Ganymede, are both larger but not more massive than Mercury. Solar System is around the earth.

Planetary rings made of ice, dust, and moonlets surround each of the large planets as well as a few minor worlds. Objects made of rock, metal, and ice can be found in the asteroid belt, Solar System is located between the orbits of Mars and Jupiter.

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The momentum of an object is 30 kgm/s . This can be calculated by using momentum formula see description below.

It is defined as the product between mass and velocity. Its symbol is p.

It is given by:

p = m * v

What information do we have?

Mass = 5kg

Velocity = 6 m/s

To find:

Momentum=?

On substituting the values:

p = m * v

p =5 kg * 6 m/s

p = 30 kgm/s

Thus, the momentum of an object is 30 kgm/s.

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The electric field at a distance z above the center of a square loop carrying uniform line charge λ can be calculated using the formula:

E = λ / (4πε₀) * [(√2 + z) / (a² + z²) + (√2 - z) / (a² + z²)]

Where E is the electric field, λ is the line charge density, ε₀ is the permittivity of free space, z is the distance above the center of the loop, and a is the side length of the square loop.

The formula takes into account the contributions of the electric field from each side of the square loop. The terms (√2 + z) / (a² + z²) and (√2 - z) / (a² + z²) represent the field contributions from the sides parallel and perpendicular to the direction of the distance z, respectively. By summing these contributions, we can determine the electric field at the given distance above the center of the loop.

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Newton's third law states that if an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Let:

A = Hammer

B = Nail

so:

Therefore:

The hammer exerts a force on the nail; the nail exerts a force on the hammer.

Answer:

The potential energy of the roller coaster increases as the coaster goes up a hill and can be converted to kinetic energy.

The power being dissipated by the hand-crank generator is 94.12 Watts.

Given the following data:

To find the power being dissipated by the hand-crank generator:

Mathematically, power is given by the formula;

\(Power = \frac{Energy}{Time}\)

Substituting the given parameters into the formula, we have;

\(Power = \frac{160}{1.70}\)

Power = 94.12 Watts.

Therefore, the power being dissipated by the hand-crank generator is 94.12 Watts.

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The velocity of the bowling ball after falling for 3.0 seconds is approximately 29.4 m/s.

To determine the velocity of the bowling ball after falling for 3.0 seconds, we can use the kinematic equation for free fall:

v = gt

where:

v is the final velocity,

g is the gravitational acceleration (9.8 m/\(s^{2}\)),

t is the time of fall (3.0 seconds).

Plugging in the values, we get:

v = (9.8 m/\(s^{2}\)) * (3.0 s)

v = 29.4 m/s

Therefore, the velocity of the bowling ball after falling for 3.0 seconds is approximately 29.4 m/s.

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Answer:

c. dioptre that's the answer.

The impulse that Earth exerts on a 210 g apple that is falling from a tree during the first 0.50 seconds can be calculated using the formula for impulse.

Impulse is defined as the change in momentum of an object, and is given by the equation:

J = Δp

where,

J is the impulse.

Δp is the change in momentum.

To calculate the impulse that Earth exerts on the apple, we need to know the initial momentum and the final momentum of the apple during the first 0.50 seconds.

Since the apple is falling freely, its initial momentum is zero (because it is at rest), and its final momentum can be calculated using the formula:

p = mv

where,

p is the momentum.

m is the mass.

v is the velocity.

Since the apple is falling freely, we can use the equation for free fall to find the velocity:

v = gt

where g is the acceleration due to gravity, and t is the time.

At the end of 0.50 seconds, the velocity of the apple can be calculated as: v = gt = (9.8 m/s²)(0.50 s) = 4.9 m/s.

Therefore, the final momentum of the apple can be calculated as:

p = mv = (0.210 kg)(4.9 m/s) = 1.029 kg m/s.

The change in momentum (Δp) during the first 0.50 seconds is simply the final momentum, since the initial momentum is zero.

Therefore, the impulse that Earth exerts on the apple during the first 0.50 seconds is given by:J = Δp = 1.029 kg m/s

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Answer:

An applied force affects the motion of an object. Dragging can occur when sliding an object over the surface of another. The action from a force can cause an object to move or speed up (accelerate), to slow down (decelerate), to stop, or to change direction.

Explanation:

The force of gravity depends on the mass of objects and the distance between them. This is true statement.

Physics defines force as the push or pull that modifies the velocity of a massed object.

The ability to change a body's resting or moving condition is referred to as an external force. There is a magnitude and a direction to it.

You may determine the Force using a spring balance. The SI's measure of force is the Newton.

The force of gravity between two objects is directly proportional to the mass of the object and inversely proportional to the square of the distance between them.

Hence, the force of gravity depends on the mass of objects and the distance between them. This is true statement.

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