Find the value of m if third quartile (Q3) of the data given below is 128. (Income Rs. ) 0-30, 30-60, 60-90, 90-120, 120-150, 150-180 (No. Of Labour) 2, 8 ,22 ,24 ,m ,9​

The maximum number of people who can stand in each side of the boat is equal to the buoyant force divided by the average mass of a person multiplied by the acceleration due to gravity.

The maximum number of people who can stand in each side of a boat can be determined using Archimedes' Principle. This principle states that the buoyant force on an object is equal to the weight of the fluid it displaces. In the case of a boat, the buoyant force is equal to the weight of the water it displaces.

Using this principle, the maximum number of people who can stand in each side of a boat can be calculated using the equation:

F_B = m_p * g

Where F_B is the buoyant force, m_p is the total mass of all the people standing in the boat, and g is the acceleration due to gravity.

To determine the maximum number of people, we must first calculate the mass of the boat, m_b. We can do this by multiplying the volume of the boat (V) by the density of the material the boat is made of (ρ).

m_b = V * ρ

Next, we can calculate the total mass of all the people standing in the boat, m_p. This can be calculated by multiplying the total number of people (n) by the average mass of a person (m).

m_p = n * m

Finally, we can calculate the maximum number of people who can stand in each side of the boat by rearranging the equation for F_B and solving for n.

n = (F_B) / (m * g)

Therefore, the maximum number of people who can stand in each side of the boat is equal to the buoyant force divided by the average mass of a person multiplied by the acceleration due to gravity.

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Answer:

part a: The slope of the function represents the rate of change of the balance in the bank account per day. To find the slope, we can use the formula: slope = (change in y)/(change in x).

Using the values from the table, we have: slope = (720-600)/(3-0) = 120/3 = 40. Therefore, the slope of the function g(x) is 40.

part b: Using the point-slope form of the equation of a line, we can write: g(x) - 600 = 40(x-0). Simplifying, we get: g(x) = 40x + 600. This is the slope-intercept form of the equation, where the y-intercept is 600 and the slope is 40.

To write in standard form, we can rearrange the equation as: -40x + g(x) = 600.

part c: Using function notation, we can write the equation as: g(x) = 40x + 600.

part d: To find the balance in the bank account after 7 days, we can use the equation we found in part c and substitute x = 7: g(7) = 40(7) + 600 = 880. Therefore, the balance in the bank account after 7 days is $880.

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Answer:

The answer iz 32 walkers.

Step-by-step explanation:

the equation would be 232+24x

The Girl Guides would need 32 walkers to reach their goal

232+24×32=1000

The stochastic process for the function G = G(S, t) is given by:

\(\[dG = \frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\]\)

The stochastic process for G^2 is given by:

\(\[d(G^2) = \left[2G\frac{\partial G}{\partial t} + \left(\frac{\partial G}{\partial t}\right)^2 + 2G\frac{\partial G}{\partial S} + \left(\frac{\partial G}{\partial S}\right)^2\right]dt + 2G\frac{\partial^2 G}{\partial S^2}(dS) + \left(\frac{\partial G}{\partial t}\right)^2(dt)^2 + \left(\frac{\partial G}{\partial S}\right)^2(dS)^2\]\)

Let us now analyze each section in a detailed way:

i) Using Ito's lemma, we can find the stochastic process \($dG$\) followed by \($G^2$\) as follows:

Applying Ito's lemma to \($G(S, t)$\), we have:

\(\[dG = \frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2.\]\)

For \($G = G(S, t)$\), the first term \($\frac{\partial G}{\partial t}dt$\) is straightforward as it is the partial derivative of \($G$\) with respect to \($t$\) multiplied by \($dt$\).

The second term \($\frac{\partial G}{\partial S}dS\) can be obtained by taking the partial derivative of $G$ with respect to \($S$\) and multiplying it by \($dS\).

The third term \($\frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\) involves the second partial derivative of \($G$\) with respect to \($S$\), and it is multiplied by \($(dS)^2\).

ii) To find the stochastic process for $G^2$, we substitute $G = G(S, t)$ into the equation derived above:

\(\[d(G^2) = 2GdG + (dG)^2.\]\)

Expanding and substituting the value of $dG$, we get:

\(\[d(G^2) = 2G\left(\frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\right) + \left(\frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\right)^2.\]\)

Simplifying the above expression, we can write:

\(d(G^2) &= \left[2G\frac{\partial G}{\partial t} + \left(\frac{\partial G}{\partial t}\right)^2 + 2G\frac{\partial G}{\partial S} + \left(\frac{\partial G}{\partial S}\right)^2\right]dt &\quad+ 2G\frac{\partial^2 G}{\partial S^2}(dS) + \left(\frac{\partial G}{\partial t}\right)^2(dt)^2 + \left(\frac{\partial G}{\partial S}\right)^2(dS)^2.\)

The above equation represents the stochastic process for $G^2$.

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Answer:

A) The volume of the cylinder is 1017.9 in³.

B) The volume of the enlarged cylinder is 27,482.7 in³.

Step-by-step explanation:

The radius of the cylinder is r = 6 in and the height is h = 9 in.

The volume of a cylinder can be found using the formula:

Substitute r = 6 and h = 9 into the formula.

The volume of the cylinder is 1017.876 in³.

If the cylinder is enlarged by a factor of 3, this means that each dimension is getting increased by 3.

Therefore, we need to multiply the original volume by a factor of three cubed; 3³.

The volume of the enlarged cylinder is 27,482.652 in³.

Answer:

2a2 + 4a + 7

Step-by-step explanation:

As, - (2a3 - 3a2 + 4a + 6) + (2a3 + 5a2 + 7)

= 2a2 + 4a + 13

Answer:

I don't know........................

Answer:

x < 33/4

Step-by-step explanation:

1.) -4x+35 > 2 (Move the constant to the right-hand scale side and change its sign)

-4x > 2 - 35

2.) -4x > 2 - 35 (Calculate the difference)

4x > -33

3.) -4x > -33 (Divide both sides of the inequality by -4 and flip the inequality sign)

x < 33/4

Leo should take a larger, more diverse sample to accurately determine the average number of texts middle school students send.

In order for Leo to determine the average number of texts middle school students send, he needs to ensure that his sample is representative of all middle school students. The average number of texts will only be accurate if the sample is diverse enough to capture the range of behaviors among all middle school students.
Leo surveyed 4 students from Mr. Beressertgate's history classes. While this is a good start, it is not enough to accurately capture the behavior of all middle school students.
One option would be for Leo to take a sample from Ms. Lopez and Mrs. Frank's classes as well, ensuring that each class has the same chance of being chosen. However, this still may not be enough to capture the full range of behaviors among middle school students.
To be truly representative, Leo should take a sample from each of the other history classes in all of the school gates in the district. If possible, he should even consider surveying all students in all history classes to ensure he has enough data to accurately determine the average number of texts sent by middle school students.
In summary, Leo should take a larger, more diverse sample to accurately determine the average number of texts middle school students send.

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Driving a personal car would be the most cost-effective mode of transportation for this commute, with a total daily cost of approximately $4.60 ($3.60 for gas + $1 for travel time).

Based on the given information, the most cost-effective mode of transportation for this commute would be to drive a personal car. Taking public transportation or carpooling may be more environmentally friendly options, but they may not save as much money as driving alone.

Assuming an average speed of 60 miles per hour on the highway, the commute would take approximately 20 minutes each way, or 40 minutes round-trip. This means the total cost of travel time for each workday would be $40 ($60/hour x 2/3 hour).

Using a cost calculator such as GasBuddy, we can estimate that the cost of driving 20 miles per day (round-trip) would be around $3.60 per day, assuming an average fuel efficiency of 25 miles per gallon and a gasoline price of $2.50 per gallon.

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Answer:

f^-1 (x) = x^2 + 5

Step-by-step explanation:

f(x) = √x - 5

replace x with y

x= √y - 5

solve for y,

x =√y-5

x^2 + 5

Answer -

f^-1(x) = x^2 + 5

HOPES THIS HELPS :)

The  function of variables method is utilized to solve differential equations. It is a technique in which variables are separated from one another and manipulated on both sides of the equation to solve for an unknown variable.

Integral is:∫(-40x¹ - 8) csc (4x³ + 4x) cot (4x³ + 4x) dx

The solution for the integral is shown below. The indefinite integral can be evaluated as shown below: Substitute the integrand function as u = 4x³ + 4x.

Therefore, du/dx = 12x² + 4.

Divide both sides of the equation by 4, therefore (1/4)du/dx = 3x² + 1.

Put (3/4)du = 3x² + 1 dx.

Therefore, u = (4/3)x³ + x.

Apply integration by substitution. Substitute the integrand function. Substitute u as 4x³ + 4x.Perform partial fraction decomposition. Perform integration by substitution. Perform back-substitution. Substitute u as 4x³ + 4x. Therefore, the solution is:(-5/4)ln(csc (4x³ + 4x) + cot (4x³ + 4x)) - (1/3)ln|4x³ + 4x| + C

As given, the integral is as follows:∫(-40x¹ - 8) csc (4x³ + 4x) cot (4x³ + 4x) dx Integrating by substitution,

we have, u = 4x³ + 4x(du/dx)

= 12x² + 4

Therefore, (1/4)du/dx = 3x² + 1(3/4)du

= (3x² + 1)dx

Simplifying, we have u = (4/3)x³ + x Substituting for u in the integral,

we get,∫(-40x¹ - 8) csc (4x³ + 4x) cot (4x³ + 4x) dx = ∫[-40(x) - 8]

[csc(u) cot(u)][(3/4)du] = (-15/2)∫[1/(sin(u))] - [1/(3u)] + C

Performing partial fraction decomposition for ∫[1/(sin(u))]

The  function of variables method is utilized to solve differential equations. It is a technique in which variables are separated from one another and manipulated on both sides of the equation to solve for an unknown variable.

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An experiment consists of tossing a fair coin 10 times in succession and the expected number of heads is 5. Hence option 4 is correct.

To find the expected number of heads when tossing a fair coin 10 times in succession, we can use the concept of linearity of expectation. Since each coin toss is independent and has a 50% chance of landing on heads, the expected number of heads in a single toss is 0.5.

Since the expected value is a linear operator, we can add the expected number of heads for each toss to find the expected number of heads in 10 tosses.

Therefore, the expected number of heads in 10 tosses is:

E(#heads) = 10 × E(#heads in a single toss) = 10 × 0.5 = 5.

Therefore, the correct answer is option 4: E(#heads) = 5.

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Answer:

An obtuse angle is a type of angle whose degree measurement is more than 90° but less than 180°. Examples of obtuse angles are: 100°, 120°, 140°, 160°, 170°, etc.

Answer:

See attached graph for rise and run lines

Slope = -1

Step-by-step explanation:

The slope-intercept equation form of a line is given by
y = mx + b where m = slope and b the y-intercept

rise/run is the slope of the line and is given by Δy/Δx where Δy represents the change in y values and Δx the corresponding change in x values

To calculate slope, take any two points on the line, find the difference between their y values and divide them by the change in x values

Two points I have chosen are (-3, 0) and (0, -3)
\(\textsf{{Slope}}=\dfrac{\ensuremath{-3}-0}{0-(-3)}=\dfrac{-3}{3}=-1\)

We can see from the graph that the y-intercept ie where the line crosses the y axis i s-3

So the equation of the line is y = -1x - 3

The negative sign indicates that the car is 80 km to the West of the starting point.

In mathematics, a coordinate is a numerical value that represents a particular point on a line, plane, or space. Coordinates are used to locate points and describe their position relative to a reference point or system. The number of coordinates required to specify a point depends on the dimensionality of the space. For example, a point in one-dimensional space (a line) requires one coordinate, a point in two-dimensional space (a plane) requires two coordinates, and a point in three-dimensional space (a space) requires three coordinates. The most common coordinate systems are Cartesian coordinates, which use a system of perpendicular lines to define a point's location, and polar coordinates, which use angles and distances from a fixed point to define a point's location.

Here,

To solve this problem, we need to use the concept of displacement. Displacement is the shortest distance between the starting point and the ending point of a journey. First, we need to find the total distance traveled by the car.

Distance traveled while heading East = 80 km/hour × 3 hours

= 240 km

Distance traveled while heading West = 80 km/hour × 4 hours

= 320 km

Total distance traveled = 240 km + 320 km

= 560 km

Now, we can find the displacement of the car. Since the car traveled in opposite directions, we need to subtract the distance traveled towards West from the distance traveled towards East.

Displacement = 240 km - 320 km

= -80 km

The negative sign indicates that the car is 80 km to the West of the starting point.

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Complete question:

A car leaves a place and heads East for 3 hours. Then, it heads straight West for 4 hours. The car maintained a speed of 80 km per hour throughout the trip. What is the position of the car in relation to the starting point?

The solution to the system of equations on the graph is (-4, -2)

From the question, we have the following parameters that can be used in our computation:

The graph

To identify the solution to a system of equations on a graph, you need to look for the point where the two lines intersect.

This point represents the values of the variables that satisfy both equations simultaneously, and is therefore the solution to the system.

On the graph of the system, we have the point of intersection to be

(-4, -2)

This means that the solution is (-4, -2)

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The portion of the parabola from t=-1 to t=1 can be parametrized as x=2t²-4 and y=t.

A parabola is a symmetrical and U-shaped curve that is defined by a mathematical equation.

In this case, we will use the variable t to represent the y-coordinate and find the corresponding x-coordinate. The equation becomes y=t, and substituting this into the original equation, we get

=> x=2t²-4.

To find the portion of the parabola where -1≤t≤1, we can plot the points (x, y) for various values of t in this range.

when t=-1,

=> x=2(-1)²-4 = 0.

And when

t=1, x=2(1)²-4 = -2.

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Answer:

20%

Step-by-step explanation:

Answer:

6/30 Simplified to 1/5

Step-by-step explanation:

Add the total number of marbles together.

Then put the number of green marbles over the total number of marbles.

Now you want to simplify. 6 is divisible by 6 and equals 1.

30 is also divisible by 6 and equals 5.

Hope this helps.

The equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0) is y = 0.

To find the equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0), we need to find the slope of the tangent line at that point.

The derivative of y = ln(x^2 - 5x + 1) is:

y' = (2x - 5)/(x^2 - 5x + 1)

At the point (5,0), we have:

y' = (2(5) - 5)/(5^2 - 5(5) + 1) = 0

So the slope of the tangent line at (5,0) is 0.

The equation of the tangent line can be written as:

y - y1 = m(x - x1)

where (x1, y1) is the point of tangency and m is the slope.

Since the slope is 0, we have:

y - 0 = 0(x - 5)

which simplifies to:

y = 0

Therefore, the equation of the tangent line to the curve y = ln(x^2 - 5x + 1) at the point (5,0) is y = 0.

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The outside dimensions of the house are 11' 9" x 15' 11".

To determine the outside dimensions of the house, we need to take into account the thickness of the interior and exterior walls.First, we'll calculate the thickness of the interior walls. The interior walls are made of 2x4 (31/2") lumber with 1/2" drywall on both sides.

This means that each interior wall adds an additional 3 1/2" + 1/2" + 1/2" = 4 1/2" to the overall width and height of the house. Next, we'll calculate the thickness of the exterior walls. The exterior walls are made of 2x6 (51/2") lumber with 1/2" drywall on the interior and 7/16" siding with 35/8" brick on the exterior.

This means that each exterior wall adds an additional 5 1/2" + 1/2" + 7/16" + 3 5/8" = 8 11/16" to the overall width and height of the house. To calculate the outside dimension of the house, we will add the thickness of the interior and exterior walls to the dimensions of the interior rooms.

The outside dimension of the house will be:

Width = 11' 3" + 4 1/2" + 8 11/16" = 11' 9"

Height = 15' 7" + 4 1/2" + 8 11/16" = 15' 11"

So the outside dimensions of the house are 11' 9" x 15' 11".

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Question

The interior wall of a residence consists of a 2 × 4 (31/2") with 1/2" sheetrock on both sides. Exterior walls are 2 × 6 (51/2") construction with 1/2" sheetrock on the interior and 7/16" sheeting with 35/8" brick on the exterior. Determine the outside dimension of a house if there are two interior rooms with an interior wall. One room's dimensions I 11' 3", and Room 2 dimensions I 15' 7". How do I solve this?

The equation 0.7(2y+13)=1.4y+9.1 will have infinite solutions , the correct option is  (A) Infinite solutions .

In the question

the given equation is

0.7(2y+13)=1.4y+9.1

Simplifying further we get ,

0.7*2y + 0.7*13 = 1.4y + 9.1

1.4y + 9.1 = 1.4y + 9.1

Subtracting 9.1 from both the sides we get,

1.4y=1.4y

Dividing both the sides by 1.4 we get ,

y = y

The equation y=y is satisfied for all the values of y , so it will have infinite solutions .

Therefore , the equation 0.7(2y+13)=1.4y+9.1 will have infinite solutions , the correct option is  (A) Infinite solutions .

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Answer: i think its A

Step-by-step explanation: hope this helped

An MIS differs from a TPS in that it creates databases is True.

An MIS (Management Information System) does indeed differ from a TPS (Transaction Processing System) in that it creates databases. The main purpose of an MIS is to collect, process, store, and disseminate information to support managerial decision-making within an organization. It involves the use of technology and various information systems to manage and analyze data for strategic planning, monitoring, and control.

One of the key components of an MIS is the creation and management of databases. Databases are structured collections of data that are organized, stored, and accessed in a systematic way. They serve as a central repository for storing relevant information that can be utilized by the MIS. These databases can contain data from various sources within the organization, such as sales records, customer information, inventory data, financial data, and more.

On the other hand, a TPS focuses primarily on the processing of transactions. It is designed to capture, process, and record day-to-day operational transactions, such as sales transactions, inventory updates, customer orders, and so on. While a TPS may store and retrieve data related to these transactions, its main focus is on efficiently processing and ensuring the accuracy and integrity of transactional data.

In summary, an MIS goes beyond the functionalities of a TPS by not only processing transactions but also creating and managing databases to support the informational needs of managers.

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Answer:Complete the question pls

Step-by-step explanation:

Answer:

The maximum height of the sign is 3.6 inches.

Step-by-step explanation:

To obtain the maximum height of the sign, we need to understand the relationship between the eccentricity and the dimensions of an ellipse.

The eccentricity of an ellipse measures how elongated or stretched the ellipse is. It is defined as the ratio of the distance between the foci of the ellipse to the length of the major axis.In this case, the eccentricity is given as 0.60, which means the distance between the foci is 0.60 times the length of the major axis.

The length of the major axis is 36 inches, we can calculate the distance between the foci:

Distance between foci = eccentricity * length of major axis

Distance between foci = 0.60 * 36 inches

Distance between foci = 21.6 inches

Now, to obtain the maximum height of the sign, we need to consider that the distance from the center of the ellipse to the highest point (vertex) is equal to the distance from the center to one focus.

The maximum height of the sign is half the length of the minor axis, and it can be calculated using the formula:

Height = 0.5 * (length of major axis - 2 * distance between foci)

Height = 0.5 * (36 inches - 2 * 21.6 inches)

Height = 0.5 * (36 inches - 43.2 inches)

Height = 0.5 * (-7.2 inches)

Height = -3.6 inches

However, negative height does not make sense in this context, so we take the absolute value of the height:

Absolute Height = |-3.6 inches

Absolute Height = 3.6 inches

Therefore, the maximum height of the sign is 3.6 inches.

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The initial price in this scenario is > sh 276000 and was therefore sold at a loss.

This is a situation in which the selling price of goods or services is lower than the cost price.

We were told that the selling price is sh 276000 which is less than the initial(cost) price hence he ran at a loss during the business transaction.

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The probability of at most 3 smartphones being defective is approximately 0.3369.

To calculate the probabilities, we need to assume that each smartphone's defectiveness is independent of others and that the 976% defect rate refers to a proportion of 9.76 defective smartphones out of 100.

a. To find the probability of exactly 5 defective smartphones out of 10, we can use the binomial probability formula:

P(X = k) = (n choose k) ×\(p^{k}\) ×\(1-p^{n-k}\)

where:

P(X = k) is the probability of getting exactly k defective smartphones

n is the total number of smartphones selected (10 in this case)

k is the number of defective smartphones (5 in this case)

p is the probability of selecting a defective smartphone (9.76/100 = 0.0976)

(n choose k) is the binomial coefficient, calculated as n! / (k!× (n - k)!)

Let's calculate it:

P(X = 5) = (10 choose 5)× (0.0976)⁵ ×(1 - 0.0976)¹⁰⁻⁵

Using the binomial coefficient:

(10 choose 5) = 10! / (5! × (10 - 5)!) = 252

Substituting the values into the formula:

P(X = 5) = 252× (0.0976)⁵× (1 - 0.0976)¹⁰⁻⁵

P(X = 5) ≈ 0.0592 (rounded to four decimal places)

Therefore, the probability of exactly 5 smartphones being defective is approximately 0.0592.

b. To find the probability of at most 3 defective smartphones out of 10, we need to calculate the probabilities of getting 0, 1, 2, and 3 defective smartphones and sum them up:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

Using the same formula as before, let's calculate the individual probabilities:

P(X = 0) = (10 choose 0) × (0.0976)⁰ ×(1 - 0.0976)¹⁰⁻⁰

P(X = 1) = (10 choose 1)× (0.0976)¹ ×(1 - 0.0976)¹⁰⁻¹

P(X = 2) = (10 choose 2)× (0.0976)² × (1 - 0.0976)¹⁰⁻²

P(X = 3) = (10 choose 3)× (0.0976)³ ×(1 - 0.0976)¹⁰⁻³

Using the binomial coefficient:

(10 choose 0) = 10! / (0! * (10 - 0)!) = 1

(10 choose 1) = 10! / (1! * (10 - 1)!) = 10

(10 choose 2) = 10! / (2! * (10 - 2)!) = 45

(10 choose 3) = 10! / (3! * (10 - 3)!) = 120

Substituting the values into the formula:

P(X ≤ 3) = 1 ×(0.0976)⁰× (1 - 0.0976)¹⁰⁻⁰ + 10× (0.0976)¹×(1 - 0.0976)¹⁰⁻¹ + 45 ×(0.0976)² × (1 - 0.0976)¹⁰⁻²+ 120 × (0.0976)³× (1 - 0.0976)¹⁰⁻³

P(X ≤ 3) ≈ 0.3369 (rounded to four decimal places)

Therefore, the probability of at most 3 smartphones being defective is approximately 0.3369.

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