Find the value of log 1 2 462 to four decimal places. –8. 8517 –0. 1130 0. 1130 8. 8517.

Answers

Answer 1

Answer:

ten thousand is the place value of 12462 decimal palces


Related Questions

HELP PLSS
Write the correct postulate, theorem, property, or definition that justifies the statement below the
diagram.

HELP PLSS Write the correct postulate, theorem, property, or definition that justifies the statement

Answers

Answer:

Reflexive property of congruence

What is the solution to the equation? 3|x| − 1 = 8

Answers

Answer: x1= -3, x2=3

Step-by-step explanation:

3xlxl=8+1

3xlxl=9

lxl=3

x=3

=-3

solution

x1= -3, x2=3

Coolshirts.com sells T-shirts. It costs the company $2.50 to make a simple T-shirt. The company marks up the price by 300%. What is the selling price of a simple T-shirt from coolshirts.com?

Answers

Answer:

coolshirts.com will sell the t shirts for %7.5

Explaination:

the company pays 2.50 to make the shirt and has a 300% mark up.

300% as a decimal is 3 and then you just multiply 2.50 by 3 to get 7.5

30% as a decimal percent

mark has 5410 cups of sugar. he used 145 cups for a pie and 12 of a cup in his iced tea. how many cups of sugar does he have left?

Answers

Mark has 5253 cups of sugar left after using 145 cups for a pie and 12/1 cups for his iced tea.

Mark has 5410 cups of sugar, and he used 145 cups for a pie and 12 of a cup in his iced tea. To find out how many cups of sugar he has left, we need to subtract the amount of sugar he used from the total amount of sugar he had:

Total amount of sugar = 5410 cups

Amount of sugar used for pie = 145 cups

Amount of sugar used for iced tea = 12/1 cups (since 12 of a cup is the same as 12/1 cups)

Total amount of sugar used = 145 cups + 12/1 cups = 157 cups

Amount of sugar left = Total amount of sugar - Total amount of sugar used

Amount of sugar left = 5410 cups - 157 cups

Amount of sugar left = 5253 cups

Therefore, Mark has 5253 cups of sugar left after using 145 cups for a pie and 12/1 cups for his iced tea.

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(4) + (14 – 4i) =
Express your answer in the form (a + bi).

Answers

Answer:

I would recommend using photomath and math away for stuff like this :D

Step-by-step explanation:

use these apps save you lot of time

Help!! Thank you so much

Help!! Thank you so much

Answers

Answer:

336 cm²

Step-by-step explanation:

rectangle area:

b×h = 24×7,5=180 cm²

" " = 6,5×24=156 cm²

total area: 180+156=336 cm²

you spend $40 on 5 pounds of concrete. what is the unit rate in dollars per pound Someone please help me

Answers

Answer:

8

Step-by-step explanation:

5 pounds = 40$

1 pound = x$

x$= 1 ×40 /5

x$=8

Answer:

Step-by-step explanation:

you got 5 pounds for 40 dollars

so you'll divide 40 dollars by 5 pounds. it will give you dollars per pound price

40/5

=$8

When I divide both sides of an inequality by a negative number, I notice...

Answers

The sign is flipped, please brainiest me! :)
the sign is flipped !!

Which number is farther from zero,3/4 or-1 1/4

Answers

Answer:

-1 1/4

Step-by-step explanation:

Answer:

-1 1/4 ofc

Step-by-step explanation:

imagine -1 1/4 as 1 1/4, 1 1/4 > 3/4

2x + y = 7 3x -2y = -7 solve by substitution​

Answers

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(1, 5)

Equation Form:

x = 1, y = 5

Brainliest Please!!

2x + y = 7 3x -2y = -7 solve by substitution

The solution for the given equations: x = 1 , y = 5.

What is substitution method?

The substitution method is the algebraic method to solve simultaneous linear equations. As the word says, in this method, the value of one variable from one equation is substituted in the other equation.

Given, equations

2x + y = 7          -------(a)

3x -2y = -7          -------(b)

Taking equation (a)

2x + y =7

y = 7 - 2x        ------(c)

Substituting value of y in equation (b) from equation (c)

3x - 2(7 - 2x) = -7

3x - 14 + 4x = -7

7x = 7

x = 1

Putting value of x in equation (c)

y = 7 - 2 (1)

y = 5

Hence, x = 1 and y = 5 is the solution for the given equations 2x + y = 7 and 3x -2y = -7.

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Find the H.C.F. of 567 and 255 using Euclid’s division lemma.

Answers

Step-by-step explanation:

To find the Highest Common Factor (H.C.F.) of 567 and 255 using Euclid's division lemma, we can follow these steps:

Step 1: Apply Euclid's division lemma:

Divide the larger number, 567, by the smaller number, 255, and find the remainder.

567 ÷ 255 = 2 remainder 57

Step 2: Apply Euclid's division lemma again:

Now, divide the previous divisor, 255, by the remainder, 57, and find the new remainder.

255 ÷ 57 = 4 remainder 27

Step 3: Repeat the process:

Next, divide the previous divisor, 57, by the remainder, 27, and find the new remainder.

57 ÷ 27 = 2 remainder 3

Step 4: Continue until we obtain a remainder of 0:

Now, divide the previous divisor, 27, by the remainder, 3, and find the new remainder.

27 ÷ 3 = 9 remainder 0

Since we have obtained a remainder of 0, the process ends here.

Step 5: The H.C.F. is the last non-zero remainder:

The H.C.F. of 567 and 255 is the last non-zero remainder obtained in the previous step, which is 3.

Therefore, the H.C.F. of 567 and 255 is 3.

What’s 5x-2=25x+14? (please explain)

Answers

Answer:

x = - \(\frac{4}{5}\)

Step-by-step explanation:

Given

5x - 2 = 25x + 14 ( subtract 25x from both sides )

- 20x - 2 = 14 ( add 2 to both sides )

- 20x = 16 ( divide both sides by - 20 )

x = \(\frac{16}{-20}\) = - \(\frac{4}{5}\)

list the three conditions that must be met in order to use a two-sample f-test.

Answers

(1)  The samples being compared should be independent of each other.

(2) The populations from which the samples are drawn should follow a normal distribution.

(3) The two samples being compared should have equal variances.

To use a two-sample f-test, three conditions must be met.

Firstly, the samples being compared should be independent of each other. Independence means that the observations in one sample do not influence or depend on the observations in the other sample. This condition is important to ensure that the variability between the samples is not confounded or biased by any relationship or dependence between the observations.

Secondly, the populations from which the samples are drawn should follow a normal distribution. The assumption of normality is required for the f-test to accurately assess the differences in means between the two groups. If the data deviates significantly from a normal distribution, alternative non-parametric tests may be more appropriate.

Finally, the two samples being compared should have equal variances. This assumption, known as the assumption of equal variances or homogeneity of variances, implies that the variability within each group is similar. Violation of this assumption can affect the accuracy of the f-test results. In cases where the variances are unequal, modified versions of the f-test, such as the Welch's t-test, can be used.

In summary, the three conditions for using a two-sample f-test are independence between samples, normality of the populations, and equality of variances. These conditions ensure that the f-test accurately evaluates the differences in means between the two groups being compared.

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Y
2
0
A
с
B
o'
D
Which point is located at
(11.2)

Answers

The point that is located at the ordered pair (4, -2) is given as follows:

Point B.

How to define the ordered pair?

The general format of an ordered pair is given as follows:

(x,y).

In which the coordinates are given as follows:

x is the x-coordinate.y is the y-coordinate.

On the coordinate plane, we have that:

x is the horizontal coordinate.y is the vertical coordinate.

Hence the coordinates for this problem are given as follows:

A(-2, 4), B(4, -2), C(-4, 2) and D(2, -4).

Missing Information

The graph is given by the image presented at the end of the answer.

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Y20ABo'DWhich point is located at(11.2)

Frank Pianki, the manager of an organic yogurt processing plant desires a quality specification with a mean of 16.0 ounces, an upper specification limit of 16.5 ounces, and a lower specification limit of 15.5 ounces. The process has a mean of 16.0 ounces and a standard deviation of 1 ounce. The process capability index (C
pk

)= (round your response to three decimal places).

Answers

Answer:

To three decimal places, The process capability index is 0.167

Step-by-step explanation:

We have to find the process capability index,

Upper specification = 16.5 ounces,

Lowe specification = 15.5 ounces

Mean = 16.0 ounces

Standard Deviation = S = 1 ounce

process capability index = (upper specification - lower specification)/6S

process capability index = (16.5 - 15.5)/6(1)

= 1/6

Process capability index = 1/6 = 0.16666667

To 3 decimal places, we get,

Process capability index = 0.167

Similar triangles really need help quick

Similar triangles really need help quick

Answers

Is this an open response or multiple choice question?

Answer:

SAS

i think! hope it helps.

HELP ASAP I WILL MARK YOU BRAINLEAST

You roll a die ten times and get a six four of those times. What is the experimental probability of rolling a six?

PLS ANSWER CORRECTLY

Answers

The experimental probability of rolling a six is 0.4.

Answer:

1/3 is the experimental probability of rolling 6

Explanation:

Given, a die roll 10 times in which we get 6 three times. Total no. of  possible outcomes = 10 and number of favorable outcomes = 3

Therefore, the probability of getting 6 =  1/3.

Given the interest rate as \( 29 \% \) per two months, compounded every two months, the equivalent effective rate per year is: Enter the answers as a decimal number with 4 decimals (Exp 0.4563)

Answers

Therefore, the equivalent effective rate per year, rounded to 4 decimal places, is 0.6892.

To find the equivalent effective rate per year, we need to convert the given interest rate per two months to an annual rate.

Let's denote the interest rate per two months as r. From the given information, r = 29%.

To find the equivalent annual rate, we can use the formula:

\((1 + r)^6 - 1\)

where r is the interest rate per two months, and we raise it to the power of the number of two-month periods in a year, which is 6 since there are 12 months in a year and each two-month period is counted as one.

Let's calculate the equivalent effective rate per year:

\((1 + 0.29)^6 - 1 = 0.6892\)

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Use the formula slope = yz-Yi to find the slope an then describe the slant of theXz-X1

line that connects the points:

Answers

we can describe the slant of the line as a steep and downward sloping line from left to right.

The formula for slope of a line passing through two points (x1, y1, z1) and (x2, y2, z2) is given by the following formula;Slope = (z2-z1)/(x2-x1).

We are supposed to use this formula to find the slope and then describe the slant of the line that connects the points.

Let's solve it accordingly;Given;Point 1 (x1, y1, z1) = (2, -1, 5) Point 2 (x2, y2, z2) = (-1, 4, 7)Slope = (z2-z1)/(x2-x1) = (7-5)/(-1-2) = 2/-3

Now, we are supposed to describe the slant of the line.

The slope of the line represents how steep or slant the line is.

For a slope of 2/-3, we can say that the line is steep and goes downwards from left to right side of the graph as it has a negative slope.

A slope of 1/2 would represent a shallow or gradual slope, while a slope of -2/3 would represent a steeper decline.

Therefore, we can describe the slant of the line as a steep and downward sloping line from left to right.

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The number of yeast cells in a laboratory culture increases rapidly initially but levels off eventually. The population is modeled by the function n=f(t)=a/1+be^-0.7t where t is measured in hours. At time t = 0 the population is 20 cells and is increasing at a rate of 12 cells/hour. Find the values of a and b. According to this model, what happens to the yeast population in the long run?

Answers

Answer:

Step-by-step explanation:

Given the population of yeast modelled by the function f(t)=a/1+be^-0.7t where t is measured in hours.

If at time t = 0 the population is 20 cells, then the equation becomes:

20 = a/1+be^-0.7t

20 = a/1+be^-0.7(0)

20 = a/1+be^-0

20 = a/1+b(1)

a/1+b = 20

a = 20(1+b) ........ equation 1

Also if the population is increasing at a rate of 12 cells/hour, then d(f(t)/dt = 12

Differentiate the expression with respect to time

f(t)=a(1+be^-0.7t)^-1

d(f(t)/dt =

a{-(1+be^-0.7t)^-2×(-0.7be^-0.7t)

a{-(1+be^-0.7t)^-2×(-0.7be^-0.7t) = 12

0.7abe^-0.7t/(1+be^-0.7t)² = 12 ..... equation 2

at t = 0, the equation becomes

0.7abe^-0/(1+be^-0)² = 12

0.7ab/(1+b)²= 12

0.7ab = 12(1+b)²

Substitute 1 into 2

0.7×20(1+b)b = 12(1+b)²

14(1+b)b = 12(1+b)²

Divide both sides by 1+b

14b = 12(1+b)

14b = 12+12b

14b-12b = 12

2b = 12

b = 6

Substitute b= 6 into the equation a = 20(1+b) to get a.

a = 20(1+6)

a = 20×7

a = 140

For us to be able to determine what happens to the yeast population in the long run. we will take the limit of f(t) as t approaches infinity.

Lim t -->/infty a/1+be^-0.7t

= a/1+be^-(infty)

= a/1+b(0)

= a

Since a = 140, hence the population of the yeast tends to 140 on the long run

Find the distance between (-2, 3) & (-7, -7). Round to the nearest tenth.

Answers

Answer:

11.2 units

Step-by-step explanation:

From (-7, -7) to (-2, 3) is 5 units horizontally  and  10 units vertically.  Thus we have a right triangle with sides 5 and 10 respectively.  The length of the hypotenuse of this triangle is the distance between (-2, 3) & (-7, -7):

d = √(5² + 10²) = √(25 + 100) = √125 = √25√5, or 5√5.

This is approximately 11.2 units

\({ \sf{find \: the \: distance \: between \: ( - 2,3)and \: ( - 7, - 7).}} \\ { \sf{round \: to \: the \: nearest \: tenth}}\)

\({ \sf{ \red{distance = \sqrt{( {x2 - x1})^{2} + ( {y2 - y1})^{2} } }}} \\ \\ { \sf{x1 = - 2}} \\ { \sf{x2 = - 7}} \\ { \sf{y1 = 3}} \\ { \sf{ y2 = - 7}}\)

\({ \sf{ \green{ distance = \sqrt{ {( - 7 - ( - 2)})^{2} + {( - 7 - 3)}^{2}}}} } \\ \\ { : {\implies{ \green{ \sf{distance = \sqrt{ {( - 5)}^{2} + {( - 10)}^{2} } }}}}} \\ \\ { : { \implies{ \green{ \sf{distance = \sqrt{25 + 100}}}}}} \)

\({ : { \implies{ \sf{ \green{distance = \sqrt{125}}}}}} \\ \\ { : { \implies{ \green{ \sf{distance = 5 \sqrt{5}}}}}} \\ \\ { : { \implies{ \green{ \sf{distance = 5 \times 2.236}}}}}\)

\({ : { \implies{ \underline{ \green { \sf{distance = 11.18= 11.2}}}}}}\)

the years of education for self-employed individuals is normally distributed with a mean of 7.4 years and a standard deviation of 3.4 years. if 36 self-employed individuals are polled, what is the probability that the mean years of education of this sample is at most 7.6 years? round your answer to at least three decimals.

Answers

The probability that the mean years of education of this sample is at most 7.6 years is 0.841.

Let X be the mean years of education of this sample. Then X follows a Normal Distribution, N(7.4, 3.4).

We want to find P(X <= 7.6).

Using the Z-Score Table, we find that P(X <= 7.6) = 0.8413.

So, the probability that the mean years of education of this sample is at most 7.6 years is 0.841.

To calculate this, we first find the Z-Score of 7.6

Z = (x - mean) / sd

Z = (7.6 - 7.4) / 3.4

Z = 0.5882

Then, we look up the Z-Score of 0.5882 in the Z-Score Table and find the probability associated with it.

P(X <= 7.6) = 0.8413

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Last week, Colton sold 14 magazine subscriptions and 36 raffle tickets for a fundraiser. This week, he sold 18 magazine subscriptions and 26 raffle tickets. If Colton charged $10.25 for each magazine subscription and $0.50 for each raffle ticket, how much money did he earn for the fundraiser over these two weeks?

Answers

If in Last week, Colton sold 14 magazine subscriptions and 36 raffle tickets for a fundraiser. This week, he sold 18 magazine subscriptions and 26 raffle tickets. If Colton charged $10.25 for each magazine subscription and $0.50 for each raffle ticket, Then $359 money he earned for the fundraiser over these two weeks

What is Equation?

Two or more expressions with an Equal sign is called as Equation

Given,

10.25 for each magazine subscription and $0.50 for each raffle ticket,

M=10.25 and T=0.50

Last week:

14 magazine subscriptions and 36 raffle tickets for a fundraiser.

14M+36T

Now substitute M and T values

14(10.25)+36(0.50)

143.5+18

161.5

Current week:

18 magazine subscriptions and 26 raffle tickets.

18M+26T

Now substitute M and T values

18(10.25)+26(0.50)

184.5+13

197.5

So total money he earned for two weeks is 161.5+197.5

$359

Hence $359 money did he earn for the fundraiser over these two weeks

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What is the value of this expression

What is the value of this expression

Answers

Answer:

+0.125 is the answer

The answer is 0.125….
What is the value of this expression

3. Evaluate each limit, if it exists. If the limit does not exist, explain why not. [12] x? - 8x +16 2x2 – 3x-5 lim lim a) x2 -16 x+3 x2 - 2x-3 X c) ਗਤ lim 1 2 x-1/x+3 3x + 5 x-5 lim ** VX-1-2 b

Answers

The limits in (a) and (c) do not exist due to zero denominators, while the limit in (b) does exist and equals -1.

(a) The limit of (x^2 - 16) / (x + 3) as x approaches -3 can be evaluated by substituting -3 into the expression. However, this results in a zero denominator, which leads to an undefined value. Therefore, the limit does not exist.

(b) The limit of √(x - 1) - 2 as x approaches 2 can be evaluated by substituting 2 into the expression. This results in √(2 - 1) - 2 = 1 - 2 = -1. Therefore, the limit exists and equals -1.

(c) The limit of (3x + 5) / (x - 5) as x approaches 5 can be evaluated by substituting 5 into the expression. However, this also results in a zero denominator, leading to an undefined value. Therefore, the limit does not exist.

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What are the domain and range of this relation? {(3, -9), (11,21), (121,34), (34,1), (23,45)}

Answers

Answer:

domain = ( 3, 11, 121, 34, 23)

range = ( 21, 34, 1, 23)

In an A.P the term is -10 and the 15th term is 11 and the last term is 41. Find the sum of all terms in this progression.​

Answers

Answer:  542.5

This is equivalent to the fraction 1085/2

===============================================================

Explanation:

AP stands for "arithmetic progression", which is another name for "arithmetic sequence"

a1 = -10 is the first term

the 15th term happens when n = 15, so

an = a1 + d*(n-1)

a15 = -10 + d(15-1)

a15 = 14d-10

Set this equal to 11 (the stated 15th term) and solve for d

a15 = 11

14d-10 = 11

14d = 11+10

14d = 21

d = 21/14

d = 3/2

d = 1.5 is the common difference

Let's find the nth term

an = a1 + d(n-1)

an = -10 + 1.5(n-1)

an = -10 + 1.5n - 1.5

an = 1.5n - 11.5

-------------------------------

The last term is 41, so we'll replace the 'an' with that and solve for n

an = 1.5n - 11.5

41 = 1.5n - 11.5

41+11.5 = 1.5n

52.5 = 1.5n

1.5n = 52.5

n = (52.5)/(1.5)

n = 35

So the 35th term is 41.

-------------------------------

We're summing n = 35 terms from a1 = -10 to an = 41

S = sum of the first n terms of arithmetic progression

S = (n/2)*(a1 + an)

S = (35/2)*(-10+41)

S = 542.5

The 35 terms add up to 542.5 which is the final answer

As an improper fraction, this converts to 1085/2

Jim is paid for overtime when he works more than 40 hours per week.Enter an expression for the number of hours he works overtime when he works h hours.

Answers

Answer:

Overtime hours = [h - 40] hours

Step-by-step explanation:

Given:

Weekly hour work = 40 hours per week

Total hour work = h hours

Find:

Overtime hours

Computation:

Overtime hours = Total hour work - Weekly hour work

Overtime hours = [h - 40] hours

A parallelogram has a base of 100, a side length of 36, and interior angle of 60, what is the height

A parallelogram has a base of 100, a side length of 36, and interior angle of 60, what is the height

Answers

Answer:

\(18\sqrt{3}\)

Step-by-step explanation:

Please see the attached image

I'm assuming you've already learned the special properties of a 30-60-90 triangle.

By drawing a 30-60-90 triangle by constructing line BC, and using the special proportions that come from it, we can find that

AB=AC/2=36/2=18

and

BC=AB*\(\sqrt{3}\)=\(18\sqrt{3}\)

A parallelogram has a base of 100, a side length of 36, and interior angle of 60, what is the height

The weights of a pack of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation of 2.4 grams. what is the weight of a randomly selected pack of gum that has a z-score of 3.11? a. 39.6 grams b. 44.7 grams c. 49.5 grams d. 54.6 grams

Answers

Answer:

Step 1: Obtain the mean and standard deviation of the weights of packs of chewing gum. The weights of packs of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation 2.- grams. Step 2: Obtain the z-score of the randomly selected pack of gum. The z-score of the randomly selected pack of gum is 3.11. Step 3: Determine which of the following statements is true: The weight of this pack of gum is lighter than the mean weight by 3.11 standard deviations The weight of this pack Of gum is heavier than the mean weight by 3.11 standard deviations The weight of this pack Of gum is lighter than the mean weight by 2.4 standard deviations The weight of this pack Of gum is heavier than the mean weight by 2.4 standard deviations

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The weights of a pack of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation
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