The tension in an elevator cable if the 1 500-kg elevator is descending with an acceleration of 2.8 m/s² is 1.1E+4 N hence the correct answer is B.
To find the tension in the elevator cable, we need to use Newton's second law of motion, which states that force is equal to mass times acceleration (F=ma).
First, we need to find the force acting on the elevator. The force is equal to the weight of the elevator plus the force needed to accelerate it downward. The weight of the elevator is equal to its mass multiplied by the acceleration due to gravity (9.8 m/s²):
Weight of elevator = 1,500 kg x 9.8 m/s² = 14,700 N
The force needed to accelerate the elevator downward is equal to its mass multiplied by the acceleration:
Force needed to accelerate elevator = 1,500 kg x 2.8 m/s² = 4,200 N
The total force acting on the elevator is the sum of these two forces:
Total force = 14,700 N + 4,200 N = 18,900 N
Finally, we can find the tension in the elevator cable by using Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the tension in the cable is equal and opposite to the force acting on the elevator:
Tension in cable = 18,900 N = 1.9E+4 N (to two significant figures)
Therefore, the correct answer is B. 1.1E+4 N is incorrect.
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A ball is thrown at an angle of 36.9° from the horizontal with a velocity of 105.6 ft/s.
How far does the ball go before it hits the ground?
The ball will travel a horizontal distance is 79.7 ft before before it hits the ground.
What is horizontal distance?
An object to which we provide an initial velocity is called a projectile, and gravity has an impact on it. The length of the horizontal axis is a projectile's horizontal range. In addition, it would move before returning to the original vertical position. The horizontal range then depends on the launch angle θ, the acceleration brought on by gravity, and the beginning velocity V₀. Meters are the horizontal range's unit (m).
The ball will travel a horizontal distance of 105.6*cos(36.9) = 79.7 ft before it hits the ground.
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A large, heavy cargo container is taken from the surface of the Earth and
brought to the Moon to begin building a base camp. What is MOST different
about this cargo container on the Moon?
a
b
On the Moon, the cargo container has a different volume.
On the Moon, the cargo container has a different shape.
On the Moon, the cargo container has a different mass.
On the Moon, the cargo container has a different weight.
с
d
Answer:
D
Explanation:
A different weight
What is the answer for the first part of a? In kN
We are asked to determine the magnitude of the force that acts parallel to the nail. To do that we will add the torque that acts on the point of contact. First, we draw a free-body diagram of the situation:
We have decomposed the force of the nail into its horizontal and vertical components. The horizontal component does no torque since there is no distance parallel to the force to the point of contact.
Now, we add the torques. We consider counterclockwise as positive:
\(\Sigma T=-(30cm)F+(5cm)(R_y)\)Since we consider the moment before there is no angular acceleration the sum of torques adds up to zero:
\(-(30cm)F+(5cm)(R_y)=0\)Now, we determine the value of Ry as a function of "R" using the trigonometric function cosine:
\(\cos \theta=\frac{R_y}{R}\)Now, we multiply both sides by "R":
\(R\cos \theta=R_y\)Now, we substitute in the sum of torques:
\(-(30cm)F+(5cm)(R\cos \theta_{})=0\)Now, we solve for "R". First, we add "30F" to both sides:
\((5cm)(R\cos \theta)=(30cm)F\)Now, we divide both sides by 5cm:
\((R\cos \theta)=\frac{(30cm)F}{5cm}\)Now, we divide both sides by cosine:
\(R=\frac{(30cm)F}{5cm\cos \theta}\)Now, we substitute the values:
\(R=\frac{(30cm)(155N)}{(5cm)\cos 26.9}\)Solving the operations:
\(R=1042.8N\)Therefore, the force on the nail is 1042.8 Newtons.
which type of galaxy has a small bulge and loose, poorly defined spiral pattern?
A galaxy with a small bulge and loose, poorly defined spiral pattern is typically classified as a "late-type" or "low surface brightness" spiral galaxy.
Late-type spiral galaxies are characterized by their loose, open spiral patterns, which are often difficult to discern due to low contrast and irregularity.
They typically have small, faint bulges at their centers and relatively low mass and star formation rates compared to earlier-type spiral galaxies.
The spiral arms of late-type galaxies are often more extended and irregular than those of earlier-type galaxies, with lower concentrations of stars and gas.
The disk of a late-type spiral galaxy is also often thinner and more fragile, making it more susceptible to distortions and disruptions from gravitational interactions with other galaxies.
Examples of late-type spiral galaxies include the Milky Way's neighbor, the Andromeda Galaxy (M31), and the galaxy NGC 2841.
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What is immunity!????
Answer:
The ability to fight with disease and some other kinds of infirmities is Known as immunity
Explanation:
the ability of an organism to resist a particular infection or toxin by the action of specific antibodies or sensitized white blood cells
The Hermes is a rotating space station that allows its occupants to experience simulated gravity. If its angular velocity is 0.66 rad/s and gives a simulated gravity of 0.4g, what is its diameter?
Answer:
a = v^2 / R = ω^2 R centripetal acceleration
.4 g = .4 * 9.80 m/s^2 = 3.92 m/s^2
R = a / ω^2 = 3.92 / .66^2 = 9.0 m
D = 2 R = 2 * 9.0 = 18.0 m diameter
4. A net force of 15 N is exerted on a book to cause it to accelerate at a rate of 5 m/s2. Determine the mass of the
book.
a. 0.33 kg
b. 2 kg
c. 3 kg
d. 45 kg
Answer:
3 kgExplanation:
The mass of an object given it's force and acceleration can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{15}{5} = 3 \\ \)
We have the final answer as
3 kgHope this helps you
an apple of mass 444 g breaks loose of a tree and falls for 1.11 s before being caught by a person. the person’s hand is moved downward 9.99 cm by the apple as it is caught. (a) describe the action-reaction pairs of forces for the apple and the earth and for the apple and the hand. (b) find the amount that the earth (m
The action-reaction pairs of forces for the apple and the earth are; they both applies force on each other. The Earth moves with a mass of 0.452 kg when an apple of 0.444 kg falls off the tree and accelerates downwards due to gravity.
(a) Action and reaction pairs of forces are pairs of forces that objects apply on each other. They are equal in magnitude but opposite in direction. When an apple falls off a tree, there are two action-reaction pairs of forces that can be described; the earth applies a force on the apple, and the apple applies a force on the earth. The apple also applies a force on the person's hand, and the person's hand applies a force on the apple.
(b) Calculation of the amount that the Earth (m) moves with the same force as the apple is accelerated downwards due to gravity.
In this case:
mass of apple, m = 0.444 kg f = 4.44
Newtons fa l time, t = 1.11 s
displacement, s = 9.99 cm = 0.0999 m
Using the formula:
distance = 1/2 × g × t2s = 1/2 × 9.81 m/s2 × (1.11 s)2s = 5.45 m
Therefore, the mass of the Earth that moves with the same force as the apple is: m = F / a
where F is the force exerted by the apple on the Earth and a is the acceleration of the Earth. Using Newton's second law:
F = ma F = 4.44 Ns = 5.45 ma =
F / mam = F / a = 4.44 N / 9.81 m/s2 = 0.452 kg
Therefore, the Earth moves with a mass of 0.452 kg when an apple of 0.444 kg falls off the tree and accelerates downwards due to gravity.
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how many joules of energy are used if the burner is on for 125 seconds?
If the burner is on for 125 seconds with a power rating of 1000 watts, then 125000 joules of energy are used.
We need to know the power rating of the burner to calculate the energy used. Let's assume the power rating of the burner is 1000 watts.
Power = 1000 watts
Time = 125 seconds
Energy = Power x Time
Energy = 1000 watts x 125 seconds
Energy = 125000 joules.
Energy is a fundamental concept in physics and is typically measured in joules (J). The joule (J) is the SI unit of energy and is defined as the amount of energy transferred or work done when a force of one newton acts on an object to move it one meter in the direction of the force.
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A labourer has to push a heavy trunk.What should we do to reduce his effort in pushing and Why?
To reduce the effort required by a labourer in pushing a heavy trunk, several strategies can be employed:
1)Reduce the weight of the trunk
2)Use wheels or a trolley
3)Lubricate the surfaces
4)Provide leverage
5)By implementing these measures
To reduce the effort required by a labourer in pushing a heavy trunk, several strategies can be employed:
Reduce the weight of the trunk: If possible, remove or redistribute the contents of the trunk to make it lighter. This will decrease the force required to move it.
Use wheels or a trolley: Adding wheels to the trunk or placing it on a trolley can significantly reduce the effort needed to push it. By reducing friction with the ground, the labourer can easily roll the trunk instead of having to overcome static friction.
Lubricate the surfaces: Applying a lubricant, such as oil or grease, to the contact points between the trunk and the ground can reduce friction and make it easier to push.
Provide leverage: Attach handles or levers to the trunk to allow the labourer to exert force more efficiently, utilizing mechanical advantage to reduce effort.
By implementing these measures, the labourer's effort in pushing the heavy trunk can be reduced, making the task less physically demanding and more manageable.
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Given a parallel runtime of 20s on eight cores and a serial runtime of 80s, what is the runtime in seconds on 16 cores assuming the same efficiency (do not include any units in the answer)?
If we assume the same efficiency, then we can use Amdahl's Law to calculate the new runtime on 16 cores.
Amdahl's Law states that the speedup of a parallel program is limited by the portion of the program that must be executed sequentially. In this case, the portion that must be executed sequentially is (80-20)/80 = 0.75 or 75%. This means that only 25% of the program can be parallelized. Therefore, the speedup we can expect from doubling the number of cores is limited to 1/((1-0.25) + 0.25/8) = 1.85.
Using this speedup, we can calculate the new runtime on 16 cores as 20/1.85 = 10.81 seconds.
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A ball is dropped from the top of a building. When does the ball have the LEAST kinetic energy?
A: After it has hit the ground
B: Just before it hits the ground
C: Halfway through the fall
D: Just after it is released
Answer:
The answer is probably A
Which of the following will change the strength of a magnetic field?
1.increase speed
2.change the amount of electric current
3.remove atoms
4.it is always the same
2. change the amount of electric current
Two people carry identical 40.0N boxes up the ramp. The ramp is 2.00m long and 1.00m high. Person A walks up the ramp in 2.00s. Person B walks up the ramp in 4.00s. What is the difference in power the two people use to carry the boxes up the ramp
The difference in power for two people carrying the boxes up the ramp is 30 W.
Given the following data:
W = 40.0 N is the weight of a box.
The ramp's length is L = 2.00 m.
The platform height is h = 1.0 m.
t = 2.0 s is the time interval for the first person.
t' = 4.0 s is the time interval for the other person.
Power is the rate at which energy is used. The expression for the Power is given in the given question as,
P = W×(L+h)/t
Assume that you are solving for the first person.
P₁ = W(L+h)/t₁.................................................................. (1)
Substitute the following values into equation (1):
P₁ = 40(2+1)/2
P₁ = 20(3) (3)
P₁ = 60 W.
Regarding the second person,
P₂ = W(L+h)/t₂..................................................................... (2)
Fill in the blanks in equation (2) as follows:
P₂ = 40(2+1)/4
P₂ = 10*(3) *3)
P₂ = 30 W
Obtaining the difference in power as
P = P₁ - P₂
P = 60-30
P = 30 W
As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.
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Name some minerals used as gems.
Answer:
Minerals to Gemstones
Mineral Name Gemstone Name
Beryl Aquamarine, Beryl, Bixbite, Emerald, Goshenite, Heliodore, Morganite
Brazilianite Brazilianite
Chalcedony Agate, Aventurine, Bloodstone, Carnelian, Chrysoprase, Heliotrope, Jasper, Onyx, Sard
Chrysoberyl Alexandrite, Chrysoberyl
Gwen is completing a physics investigation involving the speeds of toy cars on a track. Two cars are going to be released from the top of a ramp and timed until they reach the bottom. Before her investigation, Gwen comes up with a hypothesis. She states that toy car A will be faster than toy car B. She runs three trials of her investigation and records her data.
20 POINTS PLSSS help...During her investigation, Gwen is using a reference point to help her in her measurements. What is a reference point used to measure?
A. energy
B. magnetism
C. mass
D. movement
Magnetism is using a reference point to help her in her measurements.
What is Magnetism?The force that magnets use to either attract or repel one another is known as magnetism.
The force that magnets use to either attract or repel one another is known as magnetism. Electric charges in motion are the source of magnetism.
Atoms, the smallest building blocks of matter, make up every substance. There are electrons in every atom, which are charged particles. The electrons that make up an atom's nucleus, or core, spin like tops.
Therefore, Magnetism is using a reference point to help her in her measurements.
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how are the four chambers in the heart connected by it
Answer:
I think it is atrioventricular valves
Explanation:
hope this helps
If you drop a rock from a height of 13 m, it accelerates at 9.8 m/s2 and strikes the ground 1.62882 s later. If you drop the same rock from half that height, what will be its acceleration?
You had me worried there for a second. I thought you were going to ask how much the time changes, or how much the speed changes as it hits the ground, and I was gonna skip this question and go to bed.
But the acceleration won't change. That's always 9.8 m/s². That's the acceleration of gravity on Earth. It doesn't depend on what you drop, or what its mass is, or how heavy it is, or what color it is, or how high you drop it from. The only way you can change it is to drop the rock through air or water, or on a different planet.
Rather than cleaning your room, you decide to drop unwanted items out of your window. If you drop your trombone out of the window and it reaches a velocity of 17.2 m/s as it hits the ground, how high up is your window?
Freefall is the state of a body that moves freely in any direction in the presence of gravity. The window is 15.01 meters above the ground.
What is a free fall ?In mechanics, freefall is the state of a body that moves freely in any direction in the presence of gravity. The planets, for example, are in free fall in the Sun's gravitational field.Assume an object body falls freely for t seconds at a final velocity v from a height h due to gravity g. It will move according to the equations of motion: h=\(\frac{1}2gt^2\). \(v^2\)= 2gh.A body is said to be in freefall when it moves solely under the influence of Earth's gravity. The ball's motion will be accelerated by an external force acting on it. This free-fall acceleration is also known as gravity acceleration.According to free fall,
vf = g * t
here Vf = 17.2 m/s
g = 9.8 m/s^2
then t = vf/ g = 17.2/9.8 =1.75 sec
According to free fall Equation,
Distance d = 1/2 g * t^2
d= 1/2 *9.8 * 1.75^2= 15.01 m
Window is located 15.01 m height from the Ground.
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A cell of emf 18v has an internal resistance of 3ohm . the terminal p.d of the battery becomes 15v when connected by a wire. find the resistance of the wire.
Answer:
Resistance = 15 Ohms
Explanation:
Given the following data;
Emf voltage = 18 V
Internal resistance = 3 Ohms
Potential difference = 15V
To find the resistance of the wire;
First of all, we would determine the current flowing through the wire.
Mathematically, the terminal potential difference is given by the formula;
V = E - IR
Where;
V is the terminal potential difference.
E is the electromotive force (emf).
I is the current.
R is the internal resistance.
15 = 18 - I*3
15 = 18 - 3I
3I = 18 - 15
3I = 3
I = 1 Amperes
Next, we find the resistance of the wire;
Voltage = current * resistance
Substituting into the formula, we have;
15 = 1 * resistance
Resistance = 15/1
Resistance = 15 Ohms
Three resistors of resistances, R1=10Ω, R2=5Ω, R3=20Ω are connected in a circuit in such way that same amount of current flows through them. Draw a circuit diagram showing the correct connections of the three resistors, a cell of 2.5V, an ammeter and a voltmeter across R3. Calculate the potential difference across R3.
Answer
Explanation:
As the three resistors are connected in series, the expression to be used for the
calculation of RT equivalent resistance
is:
RT = R1 + R2 + R3
We replace the data of the statement in the previous expression and it remains:
5 10 15 RT + R1 + R2 + R3 + +
We perform the mathematical operations that lead us to the result we are looking for:
RT - 30Ω
If the current flowing through a circuit of constant resistance is doubled, the power dissipated by that circuit will
a) decrease to one half of what it was
b) decrease to one fourth of what it was
c) quadruple in magnitude
d) double in magnitude
Option (d) double in magnitude , is the correct answer.
The power dissipated by the circuit will double in magnitude .This result is consistent with Ohm's Law and the relationship between power, current, and resistance in a circuit.
The power dissipated by a circuit can be calculated using the formula:
P = I^2 * R
Where:
P = Power
I = Current
R = Resistance
Given that the resistance is constant, if the current flowing through the circuit is doubled, we can calculate the new power dissipated.
Let's assume the initial current is I, and the final current is 2I.
Initial Power (P1) = I^2 * R
Final Power (P2) = (2I)^2 * R
= 4I^2 * R
To determine the change in power, we can calculate the ratio of the final power to the initial power:
Change in Power = (P2 - P1) / P1
= (4I^2 * R - I^2 * R) / (I^2 * R)
= 3I^2 * R / I^2 * R
= 3
Therefore, the change in power is equal to 3, which means the power dissipated by the circuit will double in magnitude when the current flowing through it is doubled.
Conclusion:
When the current flowing through a circuit of constant resistance is doubled, the power dissipated by the circuit will double in magnitude. This result is consistent with Ohm's Law and the relationship between power, current, and resistance in a circuit.
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it requires 320 N to hold two protons in a particular arrangement. An alpha particle carries 2 protons. How much force in Newtons would be required to maintain the arrangement, if one of the protons was replaced with an alpha particle?
Answer: 480 N is required to maintain the arrangement .
Explanation:
Given, 320 N force is required to hold 2 protons in a particular arrangement .
Then the force required to keep 1 proton in a particular arrangement = 320/2
= 160 N
Then if a proton is replaced by an alpha particle , it is given that a alpha contains 2 protons , then we conclude that after replcament , the arrangement has 1 alpha and 1 proton = 3 protons
Then , the force exerted by 3 protons = 3×160 = 480 N
The force exerted by the arrangement , if one of the protons is replaced with alpha is 480 N
If the temperature in the past was 2.9 C higher than today what would the corresponding change in the Fahrenheit temperature have been?
Answer:
1 deg C = 5/9 deg F (Ex. 212 F - 32) * 5/9 = 100
So deg F = 9/5 deg C = 9/5 * 2.9 = 5.2 deg F
technician b says the voltage regulator controls the strength of the rotor’s magnetic field.
true or false
The statement "Technician B says the voltage regulator controls the strength of the rotor's magnetic field" is true.
A voltage regulator is an electrical regulator that changes the amount of voltage in an electrical circuit. Voltage regulators can be designed to handle varying amounts of input voltage and output voltage.
Technician B states that the voltage regulator is responsible for regulating the strength of the rotor's magnetic field. This is true because the rotor's magnetic field strength is determined by the voltage that is applied to it. If the voltage regulator fails, the magnetic field strength will decrease and the motor's performance will suffer.Therefore, technician B's statement is correct.
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All matter is NOT composed of __________.
A. protons
B. neutrons
C. sodium
D. electrons
(CORRECT ANSWER ONLY)
Answer:
C.
Explanation:
Answer:C
Explanation:
A particle moves along x-axis with speed 6m/s for the first half distance of a journey and the second half distance with a speed 3m/s. The average speed in the total jouney is?
Answer:
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gravel is being dumped from a conveyor belt at a rate of cubic feet per minute. it forms a pile in the shape of a right circular cone whose base diameter and height are always the same. how fast is the height of the pile increasing when the pile is feet high? recall that the volume of a right circular cone with height and radius of the base is given by .
The fast is the height of the pile increasing when the pile is feet high 0.1989 ft/min.
Calculation:
Here given the rate of change in volume DV/DT = 40 actions and we need the rate of change in height when height h = 16.
Putting all values.
40 = π/4 x (16)² x DV/DT
= DV/DT= 40 x 4/ 1×16×16
0.1989 ft/min.
Rate of change in height when height is 16 H is equal to 0.1989 ft/min.
The goal is to get a text from as many modalities as possible so that models trained on The Pile have broader generalization capabilities. For stakes, experts believe it comes from the Latin word pira. Pila loosely translates to the ball. If you've ever seen inflamed hemorrhoid, you'll understand this moniker better. Many hemorrhoids actually look like small round spheres.
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5. A 950 kg car is driven up a hill at constant velocity of 7 m/s, where 1200 N of friction
and drag oppose its motion.
constant velocity
a. Draw a force diagram for the car.
b. What is the weight of the car?
c. Calculate the normal force on the car.
d. Calculate the force on the car that allows it to go up the hill.
a)The image is attached to the question
b) The weight is 9310 N
c) The normal force is -9310 N
d) The net force is 8110 N
What is the normal force on the car?Let s recall that action and reaction are equal and opposite. This implies that the normal force and the weight of the object are the same in magnitude but opposite in direction. Given this, we can now answer the question as shown.
b) The weight of the car is obtained from 950 kg * 9.8 m/s^2 = 9310 N
c) The normal force on the car = -9310 N
d) The force on the car that allows it to go up the hill is the net force which is obtained from ;
9310 N - 1200 N = 8110 N
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What do you put in the bowl first? milk or cereal?
Answer:
i put cereal first
Explanation:
cereal