Find the sum: 1.23 + 4.99.

The unadjusted cost of goods sold for the year is calculated by subtracting the ending inventory from the sum of beginning inventory and purchases. The formula is as follows:

Unadjusted Cost of Goods Sold = Beginning Inventory + Purchases - Ending Inventory

Without knowing the values for beginning inventory, purchases, and ending inventory, we cannot compute the unadjusted cost of goods sold for the year.

5. Given that the $70,000 ending balance in Work in Process includes $24,000 of direct materials, we can calculate the missing information as follows:

Direct Labor = Total Work in Process - Direct Materials - Overhead
Direct Labor = $70,000 - $24,000 - Overhead

Without knowing the value for overhead, we cannot compute the direct labor cost. However, we can rearrange the formula to solve for overhead:

Overhead = Total Work in Process - Direct Materials - Direct Labor
Overhead = $70,000 - $24,000 - Direct Labor

Without knowing the value for direct labor, we cannot compute the overhead cost.

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The smallest angle of the equilateral triangle is 60 degrees

If the sides of a triangle are in the ratio 4:4:3, it implies that the lengths of the sides are proportional.

To determine the type of triangle, we examine the side lengths. Since all three sides are equal in length, we have an equilateral triangle.

For an equilateral triangle, all angles are equal. To calculate the smallest angle, we divide the total sum of angles in a triangle (180 degrees) by the number of angles, which is 3:

Smallest angle \(= \frac{180}{3} = 60\)\) degrees.

Therefore, the smallest angle of the equilateral triangle is 60 degrees (to the nearest degree).

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Answer:

  3×10^4

Step-by-step explanation:

The desired factor is found by calculating the ratio of the two numbers:

  k = (9×10^2)/(3×10^-2) = (9/3)×10^(2 -(-2)) = 3×10^4

The first number is 3×10^4 = 30,000 times as much as the second number.

Answer:

(x+3)^2-2

Step-by-step explanation:

Answer:

Short answer: D) 15

Step-by-step explanation:

Parallel lines in this kind of triangle are always in a strict ratio of small to large or large to small based on how you look at it.

So we have 4cm to 6cm, which is 2:3 ratio. We know the smaller side, but want the larger side, so we can set up 2/3 = 10/?

the ? is 15.

heyyeueueueueye uffur6idu6ru6rueueu

9514 1404 393

Answer:

  (b) ΔPQR ~ Δ STR, PR = 16, SR = 12

Step-by-step explanation:

The similar triangles are ...

  ΔPQR ~ ΔSTR . . . . by AA similarity: S ≅ P; ∠SRT ≅ ∠PRQ

Corresponding sides are proportional, so we have ...

  PR/PQ = SR/ST

  (x +1)/8 = (x -3)/6

  3(x +1) = 4(x -3) . . . . . . multiply by 24

  3x +3 = 4x -12 . . . . . . . eliminate parentheses

  15 = x . . . . . . . . . . . . . . add 12-3x

Then the side lengths are ...

  PR = x+1 = 15 +1 = 16

  SR = x -3 = 15 -3 = 12

The similarity statement and side lengths match the 2nd choice.

Answer:

A. 11.2

Step-by-step explanation:

But this has nothing to do with 5.6 × 2. Erase that! Lol.

You have a right triangle here. The only thing to do with the circle is that there are two radii (plural of radius) shown. So they have to be the same measure.

The unmarked "bottom" of the triangle, the short leg, is a radius, so it too, is 8.4.

The hypotenuse of the right triangle, the side on the right, the longest side is 5.6 + 8.4.

The hypotenuse is 14.

Let's do some Pythagorean Theorem.

Leg^2+ leg^2=hypotenuse^2

you know,

a^2 + b^2 = c^2

fill in what we know.

8.4^2 + b^2 = 14^2

simplify.

70.56 + b^2 = 196

subtract 70.56

b^2 = 125.44

squareroot both sides

b = 11.2

Answer:

d

Step-by-step explanation:

F and G are inverse if both of them satisfy the condition h(x)=x. f(g(x))=g(f(x))=x, as we discovered. The argument f(x) and g(x) are inverse functions is thus established.

If f (x) and g (x) are inverse functions, it can be determined using one of two ways. For more information, see the explanation.

Explanation:

Instance 1

Inverse functions of both functions can be found using the first method.

Example.

Inverse of f (x) = x + 7 is what we're looking for.

We attempt to determine x using the equation y = x + 7.

y = x + 7

Inferring that g (x) is the inverse of f (x) from the fact that x = y 7

Finding g (x inverse )'s is now necessary.

g( x ) = x − 7

y = x − 7

x = y + 7

As a result, we discovered that f (x) is the inverse function of g (x).

f and g are equal if g is inverse of f and vice versa.

The second approach entails locating the compound functions f ( g ( x ) ) and g ( f ( x ) ). In this case, f and g are inverse if they are both h (x ) = x.

Example:

f ( g ( x ) =  [ x − 7 ] + 7

G ( x ) placed as x is the expression in brackets.

f ( g ( x ) ) = x − 7  + 7 = x

g (f ( x ) =  [ x + 7 ] − 7

f ( x ) inserted as x is the expression in brackets.

g ( f ( x ) ) = x + 7 − 7 = x

The equation f ( g ( x ) ) = g ( f ( x ) ) = x was what we discovered. The argument f (x) and g (x) are inverse functions is thus established.

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Answer:

i think is 167

Step-by-step explanation:

Explic

Pasos para resolver una ecuación linea

A=J(1+rt)

Usa la propiedad distributiva para multiplicar J por 1+rt.

A=J+Jrt

Intercambie los lados para que todos los términos de las variables estén en el lado izquierdo.

J+Jrt=A

Combina todos los términos que contienen J.

(1+rt)J=A

La ecuación está en formato estándar.

(rt+1)J=A

Divide los dos lados por 1+rt.

rt+1(rt+1)J=rt+1A

Al dividir por 1+rt, se deshace la multiplicación por 1+rt.

J=rt+1A

​

Answer:

Option (B)

Step-by-step explanation:

Coordinates of the vertices of the rectangle were A(0, 0), B(a, 0), C(a, b) and D(0, b)

Formula to determine the distance between two points with the vertices (x, y) and (x', y') is,

d = \(\sqrt{(x-x')^2+(y-y')^2}\)

For the length of AD,

AD = \(\sqrt{(0-0)^2+(b-0)^2}\)

     = \(\sqrt{b^2}\)

     = b

Therefore, Option (B) will be the answer.

In a hypothetical situation, an incorrect dosage calculation due to an error in metric system to Imperial System conversion could lead to potential harm to the patient. To avoid such errors, it is crucial to ensure accurate and precise conversions between the metric and Imperial systems. As a nurse, I will double-check my calculations, use reliable conversion charts or tools, and consult with colleagues or supervisors when in doubt. Additionally, ongoing education and training on dosage calculations and metric system conversions will be important to maintain proficiency and prevent errors in the future.

~~~Harsha~~~

Answer:

Step-by-step explanation:

Answer:

Opens up.

Step-by-step explanation:

See the 2 in front of the x? If that's positive, it opens up. If it's negative, it opens down.

Answer:

  (a)  3x +y = 2

Step-by-step explanation:

You want the equation y = -3x +2 written in standard form.

The standard form of a linear equation is ...

  ax +by = c

where a, b, c are mutually prime integers with a ≥ 0. If a=0, then b > 0.

To put the given equation into that form, we can add 3x to both sides:

  3x +y = 3x -3x +2

  3x +y = 2

By using scale and prοpοrtiοn, the dimensiοns οf the actual painting are 144 inches² by 216 inches².

Scale refers tο the relatiοnship between the dimensiοns οf a scaled οbject and the cοrrespοnding dimensiοns οf the οriginal οbject. If an οbject is scaled dοwn tο half its οriginal size, then the dimensiοns οf the scaled οbject will be half οf the dimensiοns οf the οriginal οbject.

Prοpοrtiοn, οn the οther hand, refers tο the relatiοnship between twο οr mοre quantities that have the same ratiο. In οther wοrds, if twο quantities are in prοpοrtiοn, then their ratiο is cοnstant.

Tο find the dimensiοns οf the actual painting, we need tο "undο" the 6:1 scale.

If the scaled painting is 6 times smaller than the actual painting, then the actual painting is 6 times larger than the scaled painting.

Sο we can find the actual dimensiοns by multiplying the scaled dimensiοns by 6:

Actual width = 24 inches x 6 = 144 inches

Actual height = 36 inches x 6 = 216 inches

Therefοre, the dimensiοns οf the actual painting are 144 inches² by 216 inches².

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The drawing of the quadrilateral P(-3, 0), N(6, 0), O(3, -6), and M(3, 9) and the drawing of the image, of the quadrilateral with vertices, P'(-1, 0), N'(2, 0), O'(1, -2), and M'(1, 3), following a dilation by a scale factor of 1/3, created with MS Excel.

The coordinates of the vertices of the quadrilateral are;

P(-3, 0), N(6, 0), O(3, -6), M(3, 9)

The coordinates of the image of a point (x, y) following a dilation by a scale factor of c are; (x·c, y·c)

The coordinates of the image following a dilation by a scale factor of 1/3 therefore, are;

P(-3, 0) dilation by a scale factor of 1/3 → P'(-3/3, 0/3) = P'(-1, 0)

N(6, 0) dilation by a scale factor of 1/3 → N'(6/3, 0/3) = N'(2, 0)

O(3, -6) dilation by a scale factor of 1/3 → O'(3/3, -6/3) = O'(1, -2)

M(3, 9) dilation by a scale factor of 1/3 → M'(3/3, 9/3) = M'(1, 3)

The coordinates of the quadrilateral following the dilation transformation are; P'(-1, 0), N'(2, 0), O'(-2, 0), M'(1, 3)

Please find attached the drawing of the image of the quadrilateral MNOP, following the dilation of a scale factor of 1/3

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The total area of the three triangles is square units is 36 and the area of the figure is square units is 60.

The triangle can be defined as a three-sided polygon in geometry, and it consists of three vertices and three edges. The sum of all the angles inside the triangle is 180°.

From the figure, the area of triangles can be calculated using the:

Area = (1/2)height×base length

Area of three triangle = 1/2(4×6) + 1/2(6×4) + 1/2(4×6)

Area of three triangle = 1/2(24×3) = 36 square units

Area of the figure = area of three triangle + area of the rectangle

= 36 + 6×4

= 60 square units

Thus, the total area of the three triangles is square units is 36 and the area of the figure is square units is 60.

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The value of integral is 3.

Let's evaluate the integral over the positive half of the interval:

∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx

Let u = 4 + 3sin(x), then du = 3cos(x) dx.

Substituting these expressions into the integral, we have:

∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du

Using the power rule of integration, the integral becomes:

∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]

Evaluating the definite integral at the limits of integration:

(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))

(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0

So, the value of integral is

= 3-0

= 3

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Answer:

\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)

Step-by-step explanation:

First, compute the indefinite integral:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)

To evaluate the indefinite integral, use the method of substitution.

\(\textsf{Let} \;\;u = 4 + 3 \sin x\)

Find du/dx and rewrite it so that dx is on its own:

\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)

Rewrite the original integral in terms of u and du, and evaluate:

\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)

Substitute back u = 4 + 3 sin x:

                            \(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

Therefore:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.

Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.

\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)

Therefore, the curve of the function is:

So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.

Integrate the function between -π and -π/2.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)

Integrate the function between -π/2 and π/2:

\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)

Integrate the function between π/2 and π.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)

To evaluate the definite integral, sum A₁, A₂ and A₃:

\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)

Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:

\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)

Therefore, the given expression cannot be zero.

Answer:

11.75 per scarves

Step-by-step explanation:

58.75 ÷ 5 = 11.75

Answer:

Step-by-step explanation:

7a - 4a

a = 8

so

7(8) - 4(8)

56 - 32 = 23

FINALLY! Someone asks for a step-by-step! TYSM!

Since a=8, we ae going to replace the a variables with 8.

7(8)-4(8)

7x8=56

4x8=32.

Now we subtract.

56-32=24.

---

hope it helps

Answer:

-5 ≤ x ≤ 1 (domain)

-7 ≤ x ≤ -4 (range)

Step-by-step explanation: Domain is x values and range is y.

Answer:

55

Step-by-step explanation:

\(\displaystyle MOE = z\biggr(\frac{\sigma}{\sqrt{n}}\biggr)\\\\4=1.96\biggr(\frac{15}{\sqrt{n}}\biggr)\\\\4=\frac{29.4}{\sqrt{n}}\\\\\sqrt{n}=\frac{29.4}{4}\\\\\sqrt{n}=7.35\\\\n=54.0225\\\\n\approx55\uparrow\)

Make sure to always round up the required sample size to the nearest integer!

The number of sod grasses needed is about one and half for the clients lawn

1 1/2 sod grasses

Given Data

Area of client's Lawn = Length * Width

= 75*100

= 7500 square feet

Size of large rolls of sod grass

Area of large rolls of sod grass  = Length * Width

= 116*42

= 4872 square feet

The number of sod grass needed

= 7500/4872

= 1.53

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Answer:

yellow

Step-by-step explanation:

bc blue

Answer:

Step-by-step explanation:

1)    a = x - 5

a)   z = y + 5

b)  z = y - 3

c)   z = 6y

d)  z = 6y - 2

e) z = 3y + 5

Answer:

0 gallon

Step-by-step explanation:

Given: 1 gallon per mile

total amount = 3000 gallons

capacity of truck = 1000 gallons

total number of trips = 3000/1000 = 3

total oil to reach the destination = 3000-3000=0

I hope this helps.

The maximum gallons of oil that can reach the destination when taking into account the truck consumption equals to zeroes.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

Given is 3000 gallons of oil are to be transported to a destination 1000 miles away. The only delivery truck available has a load capacity of 1000 gallons max. Additionally the truck consumes 1 gallon per mile from its load.

The maximum number of gallons of oil that can reach the destination when taking into account the truck consumption can be calculated as follows.

In one trip of 1000 miles, The amount of oil transferred will be -

1000 - 1 x 1000

0 Gallons.

Similarly, in all the trips the total gallons of oil reaching the destination will be zero.

Therefore, the maximum gallons of oil that can reach the destination when taking into account the truck consumption equals to zero gallons.

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