To find the steady-state response of a cantilever beam that is subjected to a suddenly applied step bending moment of magnitude m0 at its free end, we need to use the principles of structural analysis.
The cantilever beam is a type of beam that is fixed at one end and free at the other end, and it can be modeled using the Euler-Bernoulli beam theory.
The steady-state response of the cantilever beam can be calculated by solving the differential equation of motion, which relates the bending moment and deflection of the beam. The solution to this differential equation depends on the boundary conditions and the load applied to the beam.
In the case of a suddenly applied step bending moment of magnitude m0 at the free end of the beam, the steady-state response of the beam can be determined by finding the deflection of the beam at the free end. This deflection can be calculated using the equations of the Euler-Bernoulli beam theory, which relates the bending moment, deflection, and stiffness of the beam.
The magnitude of the deflection of the cantilever beam will depend on the magnitude of the step bending moment, the length and stiffness of the beam, and the boundary conditions. In general, the deflection of the cantilever beam will increase with the magnitude of the step bending moment and decrease with the stiffness of the beam.
In conclusion, to find the steady-state response of a cantilever beam that is subjected to a suddenly applied step bending moment of magnitude m0 at its free end, we need to use the principles of structural analysis and the Euler-Bernoulli beam theory. The magnitude of the deflection will depend on the magnitude of the step bending moment, the length and stiffness of the beam, and the boundary conditions.
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Rearrange the equation for kinetic energy so that you are solving for mass :)
Answer: Half of an object's mass (1/2*m) multiplied by the velocity squared
Explanation:
In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.
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an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electric filed at P *
Identify three pieces of evidence that indicate the continents were once closer than they are today
Answer:
fit of the continents, paleoclimate indicators, truncated geologic features, and fossils.
Explanation:
If there is straight line on speed time graph, which of the following statements best describes A)the body is travelling at a constant speed. B) the body is slowing down. C)the body is accelerating. D) the body is stopped
Answer:
Option A
Explanation:
If the graph plotted against Distance and Time and the graph is a linear straight line then the body is IN CONSTANT VELOCITY.And Acceleration is 0
An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of the plane? Round your answer to the nearest whole number
Answer:
433 mph
Explanation:
We know that
\(Velocity =\frac{Distance}{Time }\)...Eq(1)
Here,
Distance =1,592 miles
Time=3.68 hours
Putting the value of distance and Time in the Eq(1) We get
Velocity =\(\frac{1592\ miles}{3.68\ hours}\)
\(Velocity = 432.608\ mph\\Velocity = 433 mph\)
therefore Average velocity is 433 mph
Wan and Nurul sat on a see-saw. The see-saw is imbalanced because Wan’s mass is 45 kg while Nurul’s mass is only 30 kg. Suggest how Nurul can balance the see-saw.
We have that the see-saw will be balance if a weight of \(x=15kg\) is added to Nural's side of the see-saw
\(x=15kg\)
From the Question we are told that
Wan’s mass is \(M_w=45 kg\)
Nurul’s mass is \(M_n= 30 kg.\)
Generally
The Will be balance when the weight on both sides of the see-saw are equal
\(M_w=M_n+x\)
\(45=30+x\)
\(x=45-30\)
\(x=15kg\)
In conclusion
The see-saw will be balance if a weight of \(x=15kg\) is added to Nural's side of the see-saw
\(x=15kg\)
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How can you use the position-time graphs for two in-line skaters to determine if and when one in-line skater will pass the other one?
Explanation:
Position-time graphs measure/express the position of a skater over time relative to the start or finish of the race (depends on how it is used). Note: are the skaters in line vertically or horizontally? Like is one directly behind the other or are they next to each other?
If the two skaters are in line horizontally with each other, then their position will be the same relative to the start or finish of the race. This means if one passes the other one, the position would be different for all times after they pass. On the graph, it would look like one single line at the start (as position is same) which splits into 2 (representing the new difference in position due to 1 passing the other.
If the two skaters are in line vertically, their lines on the graph will appear parallel to each other (assuming they are going same speed) because the position is changing at the same rate, one is just reaching the same point after the other. If the skater behind overtakes the one in front. The lines on the graph will cross and continue either in parallel but with the other line on top to represent the moment where their position is the same right before they pass and after, where the second skater is now in front.
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if jake paul and logan paul fought to the death who do you think would win?
Answer:
Hehe :) Fun question, Ig Logan Paul?? XD
Plz help me with these :)
Which of the following acts on an object causing either a change in its velocity or direction of motion?"
Answer:
force
Explanation:
a satellite is orbiting planet earth with a linear speed of 4,037 m/s. the orbital radius of the satellite in km is:
The orbital radius of the satellite is approximately 6,875 km.
To find the orbital radius of the satellite, we can use the formula for centripetal force:
F = (\(mv^2\))/r
where F is the gravitational force, m is the mass of the satellite, v is the linear speed of the satellite, and r is the orbital radius.
We can rearrange this formula to solve for r:
r = (\(mv^2\))/F
The gravitational force can be calculated using Newton's law of gravitation:
F = \((GmM)/r^2\)
where G is the gravitational constant, M is the mass of the planet (in this case, Earth), and r is the distance between the satellite and Earth's center.
Substituting the expression for F into the equation for r, we get:
r = \((mv^2)/(GmM/r^2)\)
Simplifying, we get:
\(r^3 = GM/(v^2/G)\)
Finally, we can solve for r by taking the cube root of both sides:
\(r = (GM/(v^2/G))^{(1/3)\)
Substituting the given values, we get the orbital radius as:
\(r = [(6.67*10^{-11} Nm^2/kg^2)(5.97*10^{24} kg)/((4037 m/s)^2)]^{(1/3)\)
r = 6,875 km (rounded to the nearest km)
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the shear stress is a maximum where the velocity is
The shear stress is a maximum where the velocity gradient is maximum. This is referred to as the “wall effect”.The concept of shear stress in fluid mechanics refers to the frictional forces that oppose the motion of fluids when they are in contact with surfaces.
Shear stress is defined as the ratio of the force applied to an area to the area it is applied to. The formula for calculating shear stress is given as τ = F / A, where τ represents shear stress, F represents the applied force, and A represents the surface area. The unit of shear stress is N/m² or Pa. The maximum shear stress is found where the velocity gradient is the highest. As the velocity increases, the distance between layers decreases, resulting in a higher velocity gradient. The velocity gradient is highest at the wall of the container, where the fluid is in contact with a stationary surface. As a result, the shear stress is at its highest at the wall.
In fluid mechanics, shear stress is a concept that refers to frictional forces that oppose the motion of fluids. Shear stress is the ratio of the force applied to an area to the area it is applied to. The maximum shear stress is found where the velocity gradient is the highest. This is referred to as the “wall effect”.
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a truck with 0.335 m radius tires travels at 45.0 m/s. at how many radians per second are the tires rotating?
The tires of the truck are rotating at approximately 21.4 Radians per second.
To determine the radian per second at which the tires of the truck are rotating, we first need to calculate the angular velocity of the tires. We know that the linear velocity of the truck is 45.0 m/s, and since the tires are in contact with the ground, their linear velocity must be the same. Therefore, the circumference of the tire can be calculated as 2πr, where r is the radius of the tire (0.335 m in this case).
Circumference of tire = 2πr = 2π(0.335) = 2.104 m
Now, we can calculate the angular velocity using the formula:
Angular velocity = Linear velocity / Circumference of tire
Angular velocity = 45.0 / 2.104
Angular velocity ≈ 21.4 radians per second
Therefore, the tires of the truck are rotating at approximately 21.4 radians per second.
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a water break at the entrance to a harbor consists of a rock barrier with a 50.0-m-wide opening. ocean waves of 30.0-m wavelength approach the opening straight on. at what angle to the incident direction are the boats inside the harbor most protected against wave action?
The boats inside the harbor are most protected against wave action when the incident waves create a diffraction pattern with a minimum at the harbor, at an angle of approximately 19.5 degrees.
When ocean waves approach an opening in a breakwater, they will diffract or bend around the opening. The amount of diffraction depends on the wavelength of the waves and the size of the opening. The waves will diffract most when the opening is approximately the same size as the wavelength. In this scenario, the wavelength of the ocean waves is 30.0 meters and the width of the opening is 50.0 meters. Therefore, the waves will diffract most when they approach the opening at an angle of approximately 53 degrees to the incident direction. At this angle, the waves will bend around the opening and produce the smallest waves inside the harbor.
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Why is there no such thing as an ideal machine? A. Machines never have friction. B. Machines are always breaking. C. No machine is 100% efficient. D. The work input always equals the work output.
There is no such thing as an ideal machine because no machine is 100 % efficient.
Hence option D is the correct option.
For a machine to be ideal, machine should follow many criteria the machine should be frictionless and the work input must always be equal to the work output.
In reality, no machine is an ideal machine as every machine involves friction. There is no machine without friction. Friction is a necessity in our life. Without friction, we can not survive. Friction helps us to walk and even stop. Friction is like oxygen, it has vital importance in our life. Hence no machine is friction-free and friction causes wear and tear in machines. Similarly, no machine is 100 % efficient. There is always some energy loss in the process, so work input is never equal to the work output.
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The map below shows the average annual snowfall, in inches, for western New York State .According to the map, which of these cities receives the greatest average annual snowfall?
1. Buffalo
2. JamesTown
3. Niagara Falls
4. Elmira
Answer:
Jamestown nearly 200 inches of snowfall
Explanation:
The area of Buffalo and Jamestown have extreme weather. Snowfall is between 100 and 200 inches. Niagara has average snowfall around 100 inches and Elmira has around 80 inches snowfall from the map.
According to the map the greatest snowfall is around 200 inches which is shown in the area of Jamestown. Then comes the Buffalo a little less than Jamestown . Then the Niagara Falls and the least amount of snow is received by Elmira.
According to the map, Jamestown has nearly 200 inches of snowfall receives the greatest average annual snowfall.
What is the area with Highest average snowfall?
The area of Buffalo and Jamestown have excessive weather. Snowfall is between 100 and 200 inches.
Niagara has an average snowfall of around 100 inches and Elmira has about 80 inches of snowfall from the map.
According to the map, the greatest snowfall is around 200 inches which are shown in the area of Jamestown.
Then comes the Buffalo a little less than Jamestown. Then the Niagara Falls and the least amount of snow is received by Elmira.
Thus, Jamestown has nearly 200 inches of snowfall receives the greatest average annual snowfall.
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A graph showing the kinetic energy of a 10 kg object at different
speeds is provided:
Answer:
20 Joules
Explanation:
by seeing the Graph, we know that the graph will be curved. Then we can assume that the KE at speed 2 m/s is 20 Joules. But lets count it:
KE = ½ x m x v²
KE = ½ x 10 x 2²
KE = 5 x 4 = 20 Joules
How do I find out where two cars intersect when I am given velocity for the red car 14.41cm/s and the starting point for the red car 0.6m. I am also given velocity for the blue car 41.32cm/s and the starting point at 0m.
Explanation:
Write equations for the position of each car as a function of time. (Make sure to convert units if they're different.)
The red car's position x at time t is:
x = (14.41 cm/s) t + 60 cm
The blue car's position x at time t is:
x = (41.32 cm/s) t
To find when they meet, set the equations equal to each other.
(14.41 cm/s) t + 60 cm = (41.32 cm/s) t
60 cm = (26.91 cm/s) t
t = 2.230 s
Calculate the Kinetic energy of an object with a mass of 15kg while sitting on a shelf that is 20m high.
Kinetic energy is energy of motion. If the object is sitting still, then it has no kinetic energy. It doesn't matter what its mass is, or how high the shelf is.
KE = 0
which of these galaxies is most likely to be the oldest? (a) a galaxy in the local group (b) a galaxy observed at a distance of 5 billion light-years (c) a galaxy observed at a distance of 10 billion light-years
A galaxy in the local group is most likely to be the oldest.
How many light years old is the cosmos?As a result, the cosmos is estimated to be around 25 billion light years across. In 1958, Alan Sandage reduced the Hubble's constant value once more, but he still came up with an age range for the universe between 15 and 25 billion years.It is exactly because of the expanding cosmos that we can see things that are up to 46.1 billion light-years away. There will always be restrictions on the items we can view and the objects we might be able to access, regardless of how much time passes.Our own Milky Way galaxy, according to astronomers, is 13.6 billion years old. The most recent galaxy that we are aware of originated about 500 million years ago.To learn more about galaxy refer to:
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Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes .
Complete question :
Tony drives his car . He drives the first 13 miles in 13 minutes. He then drives at an average speed of 68mph for 1 hour 24 minutes . Find how much petrol he uses using the information in the table.
Requires table to answer question is attached below
Answer:
2.64 gallons
Explanation:
Given that:
First 13 miles takes 13 minutes
Average rate = 13 miles / 13 minutes = 1mile/minute ; Average rate per hour = (1 mile /minute * 60) = 60 miles /hour
If average speed = 65mph or less ; 50 miles per gallon (it uses 1 gallon for 50 miles)
Hence, since first phase rate is 60 mph,; then miles per gallon is 50 miles
Therefore,gallon of petrol used for 13 miles will be :
13 miles / 50 mpg = 0.26 gallons
2nd phase:
Average rate of 68 mph for 1 hour 24 minutes (1.4 hours)
Here, miles per gallon = 40 (that is; 40 miles for 1 gallon).
Total distance covered = 68 * 1.4 = 95.2 miles
Petrol used = 95.2 miles / 40 mpg = 2.38 gallons
Hence,
Total petrol used : (0.26 + 2.38) = 2.64 gallons
Calcule how long it takes a sound wave to travel trough 1.0km of water at 0C
Answer:
Explanation:
25.0 m/s
you are somewhere in the solar system. it's much colder than earth, and you are airborne in the planet's atmosphere, with blue skies around you. and while you can tell that your planet is rotating fairly rapidly, it is remaining daylight at all times, indicating a very large axis tilt (much larger than earth's). where are you?
Answer:
Neptune or Uranus.
Explanation:
The blue skies and rapid tilt
The ratio of the magnitude of the frictional force to the magnitude of the force
holding two surfaces together is called the and its UNIT is
Answer: the coefficient of friction
Explanation:
The coefficient of friction (μ (mu)) has no unit because it is a ratio of forces so the units of N (newtons, which are the units of force) cancel out.The magnitude of frictional force is \(\mu\)N and the magnitude of the force is N. So if we take the ratio of it we will get \(\mu\) In result.
What is the Coefficient of friction?The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them. Typically, the Greek letter is used to symbolize it, i.e., \(\mu\). In mathematical terms, is equal to F/N, where F represents frictional force and N represents normal force. Since both F and N are measured in units of force, the coefficient of friction is a dimensional less quantity (such as newtons or pounds).
For both static and kinetic friction, the coefficient of friction has a range of values. When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. In kinetic friction, the frictional force resists the motion of the object.
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7. A diver steps off a diving board and hits the surface of the water in the swimming pool 1.5 s later. If the instant they enter the water, the diver starts to decelerate at 16 m/s
2
, how deep do they go into the water before stopping? Ignore air resistance. Hint: Stepping off the diving board means that they will start with zero velocity and go straight down into the water. (All options are given as negative because they are how far below the surface of the water.) x
2
−4.05m x
2
=−6.75m x
2
=−11m x
2
=−14.7m x
2
=−18m
The diver goes 12 meters below the surface of the water before coming to a stop.
To solve this problem, we can use the equations of motion for uniformly decelerated motion. We know that the initial velocity (u) is zero because the diver starts with zero velocity when stepping off the diving board. The acceleration (a) is -16 m/s² because the diver decelerates at a constant rate of 16 m/s². We need to find the displacement (x) of the diver when they come to a stop.
The equation for displacement in uniformly decelerated motion is given by:
x = ut + (1/2)at²
Since the initial velocity (u) is zero, the equation simplifies to:
x = (1/2)at²
Plugging in the values:
x = (1/2)(-16 m/s²)(1.5 s)²
x = -12 m
Therefore, the diver goes 12 meters below the surface of the water before coming to a stop.
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Why is it important to specify both magnitude and direction with some measurements and not others?
Answer:
Other measurements have modulus, but also have a direction and sense, for example: position, speed, these quantities are called vectors.
Explanation:
Some magnitudes have only module for example: time, energy. These quantities are called scalars
Other measurements have modulus, but also have a direction and sense, for example: position, speed, these quantities are called vectors.
For these vector magnitudes, both the magnitude and the direction and the point of application must be given, to have complete information about them
What acceleration would be achieved by a 5N thrust motor in a 0.30kg
Answer:
F=ma
5N=0.3a
a=5/0.3=16.66m/s²
PLEASE GIVE BRAINLIEST
Answer:
16.7
Explanation:
acceleration=force/mass
How much will an object weigh on the moon if it weighs 60 lbs on the earth?
Answer:
10lbs on the moon
Explanation:
A fish is 50.0 cm below the surface of a pond (index of refraction for water is 1.33). For a viewer directly above the fish, the fish appears to be placed
O 37.6 cm below the surface of the pond.
O 50.0 cm below the surface of the pond.
O 66.5 cm below the surface of the pond.
O None of the above is correct
The fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.The correct answer is: O 37.6 cm below the surface of the pond.
This is because when light travels from water (with an index of refraction of 1.33) to air (with an index of refraction of 1.00), it undergoes refraction. This means that the light bends as it passes through the surface, which causes objects to appear shifted from their actual position.
In this case, the fish is actually located 50.0 cm below the surface of the pond. However, when the light from the fish enters the air above the pond, it bends away from the normal (a line perpendicular to the surface of the water), causing the fish to appear higher up than it actually is. Using the formula for calculating the apparent depth of an object underwater:
apparent depth = real depth / index of refraction
We can calculate the apparent depth of the fish:
apparent depth = 50.0 cm / 1.33 = 37.6 cm
Therefore, the fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.
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What is your velocity if you run 100 meters away from your house and it takes you 5 seconds to run that far?
Answer:
velocity = displacement / time taken
velocity = 100/5
velocity = 20m/s