find the solution of the differential equation that satisfies the given initial condition. dy dx = x y , y(0) = −5

Pensacola Beach should be chosen by Amy for her vacation as it has the highest typical temperature (median of 85 degrees) and the least temperature variability, with a range from 83 to 87 degrees. The correct option is D).

To determine which beach in Florida has the highest typical temperature and the least variability, we need to analyze the box plots for each beach. The correct answer is Pensacola Beach, we can evaluate based on that information.

Look at the box plot for Pensacola Beach. Identify the range of temperatures, which is given as 83 to 87 degrees. Locate the median temperature on the box plot, which is stated as 85 degrees.

Assess the variability by considering the spread of the box plot. If the box is narrow and the whiskers are short, it indicates less variability.

Based on the above information, we can conclude that:

The range of temperatures at Pensacola Beach is 83 to 87 degrees. The median temperature at Pensacola Beach is 85 degrees. The box plot suggests a relatively small range and less variability in temperatures at Pensacola Beach.

Therefore, based on these calculations, Pensacola Beach would be the best choice for Amy, as it has the highest typical temperature and the least variability among the four Florida beaches mentioned. The correct answer is D).

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--The given question is incomplete, the complete question is given below " amy is considering a vacation at a beach in florida. the high temperatures for may at four florida beaches are shown using box plots. amy loves warm weather, so she would prefer to go to the beach with the highest typical temperature and the least variability. which beach should she choose to visit? "--

Answer:

x = -1

Step-by-step explanation:

Now we have to,

→ Find the required value of x.

The equation is,

→ x - 3x = 2

Then the value of x will be,

→ x - 3x = 2

→ -2x = 2

→ 2x = -2

→ x = -2 ÷ 2

→ [ x = -1 ]

Hence, the value of x is -1.

Answer: it is upside down

Step-by-step explanation:

cant see the problem

A spreadsheet for rainfall is given below:

Here, we have,

a sample spreadsheet for rainfall data:

|   A    |     B    |

|--------|----------|

| Month  | Rainfall |

|--------|----------|

| Jan    |          |

| Jan    |    5     |

| Jan    |    9     |

| Feb    |          |

| Feb    |    3     |

| Mar    |          |

| Mar    |    11    |

| Mar    |    6     |

| Mar    |    1     |

| Apr    |          |

| Apr    |    5     |

| Apr    |    15    |

| Apr    |    9     |

| Apr    |    1     |

| Apr    |    2     |

| May    |          |

| May    |    4     |

| May    |    2     |

| May    |    1     |

| May    |    8     |

| May    |    15    |

| May    |    12    |

| May    |    5     |

| May    |    1     |

| May    |    1     |

| Jun    |          |

| Jun    |    2     |

| Jun    |    7     |

| Jun    |    25    |

| Jun    |    1     |

| Jun    |    14    |

| Jun    |    6     |

| Jun    |    8     |

| Jun    |    1     |

| Jun    |    1     |

| Jun    |    6     |

| Jun    |    32    |

| Jun    |    25    |

| Jun    |    5     |

| Jul    |          |

| Jul    |    17    |

| Jul    |    25    |

| Jul    |    23    |

| Jul    |    18    |

| Jul    |    1     |

| Jul    |    3     |

| Jul    |    4     |

| Jul    |    9     |

| Jul    |    18    |

| Jul    |    11    |

| Jul    |    3     |

| Aug    |          |

| Aug    |    1     |

| Aug    |    1     |

| Aug    |    5     |

| Aug    |    6     |

| Aug    |    35    |

| Aug    |    12    |

| Aug    |    1     |

| Aug    |    9     |

| Aug    |    5     |

| Aug    |    4     |

| Aug    |    11    |

| Aug    |    7     |

| Aug    |    15    |

| Aug    |    2     |

| Aug    |    3     |

| Aug    |    8     |

| Sep    |          |

| Sep    |    6     |

| Sep    |    5     |

| Sep    |    9     |

| Sep    |    17    |

| Sep    |    22    |

| Sep    |    3     |

| Sep    |    6     |

| Sep    |    1     |

| Sep    |    5     |

| Sep    |    4     |

| Sep    |    1     |

| Sep    |    6     |

| Oct    |          |

| Oct    |    5     |

| Oct    |    17    |

| Oct    |    8     |

| Oct    |    2     |

| Oct    |    5     |

| Oct    |    1     |

| Oct    |    1     |

| Oct    |    9     |

| Oct    |    16    |

| Oct    |    2     |

| Oct    |    8     |

| Oct    |    1     |

| Nov    |          |

| Nov    |    12    |

| Nov    |    6     |

| Nov    |    4     |

| Nov    |    1     |

| Nov    |    1     |

| Nov    |    3     |

| Nov    |    2     |

| Nov    |    9     |

| Nov    |    1     |

| Dec    |          |

| Dec    |    6     |

| Dec    |    1     |

| Dec    |    3     |

| Dec    |    1     |

| Dec    |    4     |

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Answer:

f(x) = (1/5)x - (2/5)

Step-by-step explanation:

The linear function can be written in the form of f(x) = mx + b, where m is the slope and b is the y-intercept.

To find the rule for the linear function when x=-10, y=-1, when x=0, y=1 and when x=10, y=3, we can use the two points method.

We can start by finding the slope (m) of the function using the following formula:

m = (y2 - y1) / (x2 - x1)

Where (x1, y1) and (x2, y2) are two points on the line.

Using the point (-10, -1) and (10, 3) we get:

m = (3 - (-1)) / (10 - (-10)) = 4/20 = 1/5

Now that we know the slope, we can use the point-slope form of the equation of a line to find the equation of the line:

y - y1 = m(x - x1)

Plug in one of the points and the slope that we found:

y - (-1) = (1/5)(x - (-10))

y = (1/5)x - (2/5)

So the equation of the linear function is f(x) = (1/5)x - (2/5)

This is the rule of the linear function when x=-10, y=-1, when x=0, y=1 and when x=10, y=3.

Answer:

Number of stamp Amanda has = 112

Step-by-step explanation:

Given:

Total number of stamp = 364

Number of stamp Lyle has = x

Number of stamp Shaquille has = [1/2]x

Number of stamp Amanda has = [2/3]x

Find:

Number of stamp Amanda has

Computation:

Total number of stamp = Number of stamp Lyle has + Number of stamp Shaquille has + Number of stamp Amanda has

Total number of stamp = x + [1/2]x + [2/3]x

364 = 13x / 6

x = 168

So,

Number of stamp Amanda has = [2/3]168

Number of stamp Amanda has = 112

Answer:

C.112

Step-by-step explanation:

edge 2020

Answer:

5

Step-by-step explanation:

5

The excluded value for the expression (3u-2)/(3u-9) is u = 3

In this expression, the denominator is 3u-9. To avoid division by zero, we need to find the values of "u" that make the denominator equal to zero.

To do this, we can set the denominator equal to zero and solve for "u":

3u-9 = 0

Adding 9 to both sides, we get:

3u = 9

Dividing both sides by 3, we find:

u = 3

So, the value of "u" that makes the expression undefined is 3.

The excluded value for the expression (3u-2)/(3u-9) is u = 3. This means that when "u" is equal to 3, the expression is undefined. For any other value of "u", the expression will have a valid numerical result.

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The value of the angle y is 42 degrees

Using the angle sum theorem which states that the sum of the interior angles of a triangle is equivalent to 180 degrees

From the information given, we have the angles as;

Now, equate the angles to the sum, we have;

y + 48 + 90 = 180

add the values

y + 138 = 180

collect the like terms

y = 180 -138

subtract the values, we get;

y = 42 degrees

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\(xy^2+8xy+15x=x(y^2+8y+15) = x(y+5)(y+3)\)

Hope that helps!

Answer:

6 * 10^2

Step-by-step explanation:

Simplify : (4.2×10^7)÷(7×10^4)

(4.2 × 10^7) / (7 × 10^4)

From indices : 10^a ÷ 10^b = 10^(a - b)

(4.2 / 7) * 10^(7-4)

0.6 * 10^3

= 6 * 10^2

Hence, (4.2×10^7)÷(7×10^4) = 6 * 10^2

Answer:

\(P(Not\ Star) =\frac{2}{3}\)

Step-by-step explanation:

Given

See attachment

Required

Theoretical probability that a roll will not land on a star

From the attachment, we have:

\(n = 12\) --- Total space

\(Star = 4\)

So, the theoretical probability that a roll will land on a star is:

\(P(Star) = \frac{n(Star)}{n}\)

\(P(Star) = \frac{4}{12}\)

\(P(Star) = \frac{1}{3}\)

Using the complement rule, the probability that it will not land on a star is:

\(P(Not\ Star) = 1 - P(Star)\)

\(P(Not\ Star) = 1 - \frac{1}{3}\)

Take LCM

\(P(Not\ Star) =\frac{3-1}{3}\)

\(P(Not\ Star) =\frac{2}{3}\)

Answer:

Look at the photo below

Step-by-step explanation:

Answer:

6,205 hours you are awake in a year

Step-by-step explanation:

A roster of twenty-four players divided into four teams can be represented by the expression 24/4.

Given

24 players total

(4) teams total.

This can be expression as = 24 / 4.

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Answer:

2 teaspoons of sugar

Step-by-step explanation:

So if jennilsa is using 1 cup of milk for the recipe she would need 2 teaspoons of sugar.

The domain of the function is defined as 0 ≤  x ≤ 4.

option A is the correct answer.

A domain of a function refers to "all the values" that can go into a function without resulting in undefined values.

So the domain of a function is the set of x values, while the range of a function is the set of y values.

From the given statement, the range of the function is defined as;

y = vt

where;

y = 60 mph x 4 hr

y = 240 miles

From the given statement, the domain of the function is defined as;

0 ≤  x ≤ 4

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Given  a full subtractor with inputs X and Y , what is X "minus" Y, given that X = 1, Y = 0 and Yout = 1. The correct answer is indeed: b. 1

In a full subtractor circuit, the inputs X and Y represent the minuend and subtrahend, respectively, and the output Yout represents the borrow. The operation "X minus Y" is performed by subtracting the subtrahend (Y) from the minuend (X), taking into account any borrow (Yout) from the previous subtractor stage.

In the given truth table, when X = 1, Y = 0, and Yout = 1, we can see that the result of "X minus Y" is 1. This means that when subtracting 0 from 1, the result is 1.

The borrow (Yout) being 1 indicates that there was a borrow from the previous subtractor stage, which is important when performing subtraction with multiple bits. However, in this case, since we are only considering a single subtractor, we can focus on the X and Y inputs and the resulting output, which is 1.

Therefore, the correct answer is indeed:

b. 1

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Answer:

it is voa

Step-by-step explanation:

45= 6r-3

45+3=6r

48=6r

r=8

Answer:

\(45 = (6r - 3) \\ 6r = 45 + 3 \\ 6r = 48 \\ r = 48 \div 6 = 8\)

If the radius of the sphere is 3.5 inches , then the volume is 130.85 inches³  and the surface area is 153.86 inches²  .

In the question,

it is given that , the shape of the exercise ball is a sphere ,

the radius of the sphere is = 3.5 inches ,

the volume of sphere is gives as

Volume = (4/3)πr³

= (4/3)π(3.5)³              ....using π = 3.14

= 130.85 inches³

and Surface Area of the Sphere is = 4πr²

= 4π(3.5)²               ....using π = 3.14

= 153.86 inches²

Therefore , If the radius of the sphere is 3.5 inches , then the volume is 130.85 inches³  and the surface area is 153.86 inches²  .

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Answer:

the answer is c

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

a) The percentage of flashlights that have a life of 55 to 65 is about 36%

b) The percentage of the batteries that have a life of 52 to 68 hours is about 75%.

Standard normal distribution is a type of continuous distribution with a mean of zero and standard deviation of one. The random variables are standardized into z scores using z score formula.

a) The Chebyshev's theorem states that; for sample or population, percentage (p) of values are contained within two, three or more standard deviations within the mean, provided that the values of k is greater than 1:

P(%) = \(1-\frac{1}{k^2}\)

Calculate the value of k:

\(k =\frac{65-60}{4}=1.25\)

The percentage is calculated as;

p(%) = \(1-\frac{1}{1.25^2}\) = 36%

The percentage of flashlights that have a life of 55 to 65 is about 36%

b) k = \(\frac{68-60}{4}=2\)

p(%) = \(1-\frac{1}{2^2}\) = 75%

The percentage of the batteries that have a life of 52 to 68 hours is about 75%.

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Answer:

\(x^{6}\) - 6x³

Step-by-step explanation:

To evaluate (f ￮ g)(x) substitute x = g(x) into f(x) , that is

f(x³ ) = (x³ )² - 6(x³ ) = \(x^{6}\) - 6x³

True. A recursive function can have two base cases, such as n == 0 returning 0, and n == 1 returning 1.

Having multiple base cases in a recursive function allows for handling different scenarios and terminating the recursion based on those specific conditions.

In the case you mentioned, where the first base case is n == 0 returning 0, and the second base case is n == 1 returning 1:

When the input value of n is 0, the recursive function reaches the first base case (n == 0) and returns the value 0. This provides a stopping condition to prevent further recursive calls and allows the function to unwind back through the call stack.

When the input value of n is 1, the recursive function does not match the first base case (n != 0), but it matches the second base case (n == 1), which returns the value 1. Again, this terminates the recursion and allows the function to exit.

Having multiple base cases is useful when the recursive problem has different possible outcomes or when there are specific values that need to be handled separately. Each base case defines a condition under which the recursion should stop and allows the function to return a specific value.

If none of the base cases match for a given input, the recursive function will continue making recursive calls until a base case is reached and the recursion can be terminated.

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The correct matching of the confidence level with the confidence interval for μ is as follows:

x ± 1.96 --> A. 95%

x ± 2.575 --> B. 99%

x ± 1.645 --> C. 90%

A confidence level of 95% corresponds to a critical value of 1.96. This means that if we construct a confidence interval by taking the sample mean (x) and adding or subtracting 1.96 times the standard error, we can be 95% confident that the true population mean (μ) falls within this interval.

A confidence level of 99% corresponds to a critical value of 2.575. Similarly, constructing a confidence interval using the sample mean and adding or subtracting 2.575 times the standard error will give us a wider interval within which we can be 99% confident that the true population mean falls.

A confidence level of 90% corresponds to a critical value of 1.645. Constructing a confidence interval using the sample mean and adding or subtracting 1.645 times the standard error will give us a narrower interval within which we can be 90% confident that the true population mean lies.

These critical values are based on the standard normal distribution and are chosen to achieve the desired level of confidence.

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Answer:

No (unless it happens to have a vinculum on top of any digit image attached is an example of a vinculum)

Step-by-step explanation:

0.63 just stops at 0.63

Given:

To simplify 3(5y+6)-4

Hence the simplified value os 15y+14.

The Wronskian of two functions f(t) and g(t) is defined as the determinant of the following matrix:
[f(t), g(t)]
[f'(t), g'(t)]
The Wronskian of the functions f(t) = e^2t and g(t) = e^3t is 6e^5t - 2e^4t, which indicates linear independence.

For the given functions f(t) = e^2t and g(t) = e^3t, the Wronskian is the determinant of the following matrix:
[e^2t, e^3t]
[2e^2t, 3e^3t]
The determinant is equal to 6e^5t - 2e^4t, which is the Wronskian of the given functions.
The Wronskian can be used to determine whether two functions are linearly independent. A Wronskian equal to 0 indicates linear dependence and a Wronskian unequal to 0 indicates linear independence. In the case of the given functions, the Wronskian is not equal to 0 and therefore the functions are linearly independent.

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