find the retio of acceleration due to gravity at the position of a satelite located 320 km BOVE THE EARTHS SURFACE TO THE FREE FALL ACCELERATION AT THE SURFACE OF THE EARTH?

Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

  1.148×10^6 N

Explanation:

The kinetic energy of the train is ...

  KE = (1/2)mv^2 = (1/2)(3.6×10^5 kg)(115 km/h × (1000 m/km)/(3600 s/h))^2

  ≈ 1.83681×10^8 J

This is the work required to stop the train, so is ...

  F·d = KE

  F = KE/d = (1.83681×10^8 J)/(160 m) = 1.148×10^6 N

The force required to stop the train is 1.148×10^6 newtons.

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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We can use the following data to get the values of acceleration and the distance covered at top speed:

Maximum speed is 20 m/s (v_max).

Time (t) = 21 seconds

(d) = 270 m is the total distance travelled.

Find the acceleration (A) first:

Applying the equation v = u + at

where an is the acceleration, t is the elapsed time, u is the beginning velocity, and v is the end velocity.

Given: The bus will begin at rest with an initial velocity of 0 metres per second (u).

The formula can be rearranged as follows:

a = (v - u) / t

a = (20 m/s - 0 m/s) / 21 seconds

0.952 m/s2 a = 20 m/s / 21 sec

Therefore, the acceleration of the bus is approximately 0.952 m/s².

Next, let's find the distance traveled at maximum speed (B):

Since the bus starts from rest, it takes time to accelerate to its maximum speed and then decelerate to stop. The distance traveled at maximum speed can be found by subtracting the distances covered during acceleration and deceleration from the total distance.

Distance during acceleration = (1/2) * a * t^2

Distance during deceleration = (1/2) * a * t^2

Distance traveled at maximum speed = Total distance - (Distance during acceleration + Distance during deceleration)

B = d - (0.5 * a * t^2 + 0.5 * a * t^2)

B = 270 m - (0.5 * 0.952 m/s² * (21 sec)^2 + 0.5 * 0.952 m/s² * (21 sec)^2)

B = 270 m - (0.952 m/s² * (21 sec)^2)

B = 270 m - 220.392 m

B ≈ 49.608 m

Therefore, the distance traveled at maximum speed is approximately 49.608 m

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Based on the observations during the experiment, the car's velocity can be described as follows. .

The car had a   constant speed of approximately 60 km/h throughout the experiment,indicating a consistent rate of motion.

In terms of   direction, the car initially traveledin a straight line towards the east.

However, after a certain point,   it made a sharp turn towards the north, changing its direction but maintaining thesame speed.

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Answer:

1) Δx  = 0.16 m / s² ,   Δx = 9.72-9.8 = 0.08 m / s²

2)  e% = 1.63% , ,   e% = 0.816%

3)           1e% = 0.04

Explanation:

The fractional error in a quantity is the absolute error between the accepted value of the quantity and the percentage error is the fractional error per 100

In this case, it is not indicated which is the measured experimental value of pi, suppose that a value of 3.142 is measured

fractional error

                 e = (ax - ax_average) / x_average

                 e = (3.142 - 3.1416) / 3.1416

                 e = 1.27 10⁻⁴

the percentage error is

                 % = e 100

                 % = 1.27 10-4 100

                 % = 1.27 10⁻²%

1) Δx = 9.96-9.8 = 0.16 m / s²

            Δx = 9.72-9.8 = 0.08 m / s²

2) the percentage difference

 x = 9.96 m / s2

             e% = (9.96 - 9.80) / 9.80 100

             e% = 1.63%

x = 9.72 m / s2

             e% = (9.72 -9.80) / 9.80 100

              e% = 0.816%

3) the mean value is

                x_average = (x1 + x2) / 2

               x_average = (9.96 + 9.72) / 2

               x_average = 9.84 m / s2

               e% = (9.84 - 9.80) / 9.80 100

             1e% = 0.04

if 3kg moves at 4.50 so 50 is 225

Explanation:

So if two magnets are pointing with unlike-poles together (north pole to a south pole), then bringing them closer together decreases the energy stored up in the magnetic field. They will be pushed in the direction that decreases the amount of stored-up energy.

Explanation:

depending on the polarity they'll increasingly repel or attract

Answer:

at a rate of deceleration of -15 kilometers per second

Explanation:

90/6=15

The rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².

The rate of deceleration can be calculated by using the following formula:

d = v - u/t

Where;

d = 25 - 0/6

d = 4.16m/s²

Therefore, the rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².

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Explanation:

\({ \rm{force = \frac{q _{1}q _{2} }{4\pi \phi \: {r}^{2} } }} \\ \)

\({ \rm{force = \frac{1 \times 1 \times 9 \times {10}^{9} }{ {1}^{2} } }} \\ \\ { \boxed{ \rm{force = 9 \times {10}^{9} \: newtons }}}\)

tbm queria saber essa pergunta!!

The final velocity of the of the object is 60 m/s.

Velocity is the rate of change of displacement.

To calculate the speed of the object, we use the formula below

Formula:

Where:

Substitute these values into equation 1

Hence, the right option is b. 60 m/s.

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Answer:

pictures please

Explanation:

I need a picture so I can tell you

An elastic collision is an come across between two bodies wherein the overall kinetic electricity of the two bodies stays the same.

In a super, perfectly elastic collision, there's no internet conversion of kinetic strength into other kinds inclusive of heat, noise, or capacity strength.  An elastic collision is a collision wherein there is no internet loss in kinetic strength within the gadget due to the collision. each momentum and kinetic energy are conserved portions in elastic collisions.

An elastic collision is a collision wherein there is no internet loss in kinetic electricity in the gadget because of the collision.  In the elastic collision, in which the kinetic energy is conserved, the kinetic electricity in an inelastic collision isn't always conserved. In an inelastic collision, the kinetic energy among the colliding bodies is exceptional at the start and the quit of the collision.

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\(\textbf{A}\cdot\textbf{B} = 11.5\)

Explanation:

The dot product between two vectors \(\textbf{A}\) and \(\textbf{B}\) is defined as

\(\textbf{A}\cdot\textbf{B} = AB\cos{\theta}\)

where A and B are the magnitudes of the vectors \(\textbf{A}\) and \(\textbf{B},\) respectively and \(\theta\) is the angle between the two. Since A = 3, B = 5 and \(\theta = 40°,\) the dot product \(\textbf{A}\cdot\textbf{B}\) is

\(\textbf{A}\cdot\textbf{B} = (3)(5)(0.766) = 11.5\)

Answer:

\(\mu=0.75\)

Explanation:

Given that,

Force acting on an object, F = 30 N

Mass of the object, m = 4 kg

It is moving with a constant velocity of 2 m/s across a level surface.

We need to find the coefficient of friction  between the object and the surface. Let it is μ. Force in terms of coefficient of friction  is given by :

F = μ N, Where N is normal force, N = mg

\(\mu=\dfrac{F}{mg}\\\\\mu=\dfrac{30}{4\times 10}\\\\\mu=0.75\)

So, the coefficient of friction  between the object and the surface is 0.75.

a) The image is attached to this answer

b) The kinetic friction force affects the forward force of the ball.

The force that opposes a rolling ball's motion is called rolling friction. It slows the ball down by acting in the opposite direction to that of the ball's motion. The weight of the ball and the type of the surface are two variables that affect rolling friction.

The force that a surface uses to maintain the weight of an object that is resting on it is known as the normal force. When a ball is rolling, the normal force exerts itself perpendicular to the surface the ball is moving on. It maintains the ball's weight balance and offers the required reaction force for rolling motion.

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The frequency of light with a wavelength of 655 nm is\(4.57 x 10^14 Hz\) and 515 nm is \(5.82 x 10^14\) Hz and  475 nm is\(6.31 x 10^14 Hz\)

The equation that links the speed of light to wavelength and frequency is

c = λν

Where, c = speed of lightλ = wavelengthν = frequency c is a constant of 2.998 x 10^8 m/s.

Calculating the frequency of light with a wavelength of

655 nm:λ = 655 nm = \(6.55 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(6.55 x 10^-7m)ν = 4.57 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 655 nm is 4.57 x \(10^14 Hz.\)

Calculating the frequency of light with a wavelength of 515 nm:λ = 515 nm = \(5.15 x 10^-7m\)

Using the above equation, we get

c = λνν = c/λ =\((2.998 x 10^8 m/s)/(5.15 x 10^-7m)ν = 5.82 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 515 nm is 5.82 x \(10^14 Hz\).

Calculating the frequency of light with a wavelength of 475 nm:λ = 475 nm = \(4.75 x 10^-7\)m Using the above equation, we get

c = λνν = c/λ = \((2.998 x 10^8 m/s)/(4.75 x 10^-7m)ν = 6.31 x 10^14 Hz\)

Therefore, the frequency of light with a wavelength of 475 nm is 6.31 x \(10^14 Hz.\)

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It takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

The formula for radioactive decay is \(A = A0 * (1/2)^{(t/t1/2)}\) where: A is the final activity A0 is the initial activity is the time elapsed t1/2 is the half-life of the sample

In this problem, the initial activity A0 is given as 1.07 x 105 Bq and the final activity A is given as 100 Bq.

The half-life of the sample is given as 5.7 days.

Substituting these values into the formula, we get: \(100 = 1.07 \times 105 * (1/2)^{(t/5.7)}\)

Dividing both sides by 1.07 x 105, we get:

\(0.000934579 = (1/2)^{(t/5.7)}\)

Taking the natural logarithm of both sides, we get:\(-7.072737 = (t/5.7) * ln(1/2)\)

Dividing both sides by ln(1/2), we get:

\(t = -7.072737 \div ln(1/2) * 5.7t \approx 28.3\) days

Therefore, it takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

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A. Identity vs role confusion: Mo's uncertainty about post-graduation plans.

B. Integrity vs despair: Mo's questioning of life accomplishments as an older adult.

C. Sensorimotor stage: Mo's development of motor skills and object permanence.

D. Intimacy vs isolation: Mo's struggle with forming relationships.

E. Concrete operational stage: Mo's ability to think logically and understand conservation.

A. The example matches with the Erikson stage of "identity vs role confusion." During this stage, individuals go through a period of exploration and self-discovery to establish a sense of identity and determine their roles and goals in life. Mo's uncertainty about what he wants to do after graduation reflects the challenges and decision-making processes associated with identity formation.

B. The example matches with the Erikson stage of "integrity vs despair." This stage occurs in late adulthood, where individuals reflect on their life choices, accomplishments, and experiences. Mo, as an older adult questioning his accomplishments, is facing the task of finding a sense of integrity and satisfaction with the life they have lived or experiencing feelings of despair and regret.

C. The example matches with the Piaget stage of "sensorimotor stage." This stage occurs in infancy, where children develop coordination and motor skills and begin to understand object permanence, which is the understanding that objects continue to exist even when they are out of sight. Mo's acquisition of motor skills and developing object permanence aligns with the characteristics of the sensorimotor stage.

D. The example matches with the Erikson stage of "intimacy vs isolation." This stage occurs during early adulthood, where individuals seek to form deep and meaningful relationships with others. Mo's struggle with forming a relationship with a significant other reflects the challenges and conflicts associated with the intimacy vs isolation stage.

E. The example matches with the Piaget stage of "concrete operational stage." This stage occurs in middle childhood, where children develop logical thinking and can grasp the concept of conservation. Mo's ability to think logically and understand the law of conservation aligns with the characteristics of the concrete operational stage.

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Answer:

a. 4 g/mL

Explanation:

First, we need to find the volume of the object. The volume is equal to the volume of the water displaced. So, it can be calculated as the difference in the volumes

75 mL - 50 mL = 25 mL

Then, the volume of the object is 25 mL and the mass is 100 g. Now, we can calculate the density as follows

density = mass/volume

density = 100 g/25 mL

density = 4 g/mL

Therefore, the answer is

a. 4 g/mL

The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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There is not enough information to determine the work done. Option iv

Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.

Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.

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Speeding up slowing down, and going around curves are all examples of acceleration .

A definition of acceleration is the speed at which velocity varies with respect to time.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Additionally, it is the first derivative of velocity with respect to time or the second derivative of position with respect to time.

The acceleration is given by the formula ,

a = v/t

where , a =acceleration

v = velocity

t = time

the unit of acceleration is m/s² .

The overall change in velocity during the specified interval divided by the total amount of time required for the change is the definition of average acceleration over a particular period of time. It is represented as for a specific amount of time.

a = Δv/Δt

The definition of instantaneous acceleration is the ratio of velocity change during a specified period of time such that the period of time ends.

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The use of the wheel barrow in this case makes it a simple machine

A wheelbarrow is an illustration of a straightforward device that can simplify labour by lowering the force needed to move a large load. The wheel and axle and the lever are two basic machines that are used.

The wheelbarrow's wheel is made of an axle and wheel. The friction between the wheel and the ground is decreased by the wheel's rotation around the axle. It can also be seen as one of the classes of the lever.

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Answer:

Explanation:

second one ??? pls i hope im right

Answer:

A bumper that crumbles (plato)

Explanation: