Find the potential energy of the bowling ball from the exercise above that is sitting on a shelf 2 meters high. Remember that g = 9.8m/s. Write equation, substitute values and units into equation, and show final answer.

After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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Answer:

x = 95 [m]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o} +a*t\)

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 0 (starts from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

Now we can find the acceleration

19 = 0 *a*(10)

a = 1.9 [m/s]

With the second equation we can find the distance:

\(v_{f} ^{2} =v_{o} ^{2} +(2*a*x)\)

where:

x = distance [m]

(19)² = (0)² + (2*1.9*x)

3.8*x = 361

x = 95 [m]

Greenhouse gases trap thermal energy and reflect the sun’s harmful radiation back to Earth is the answer

im not 100% sure tho

hope it helps:))

The diameter of the aluminum wire that must be used for the laboratory experiment is approximately 2.57 millimeters.

To determine the diameter of the aluminum wire, we can use the formula for the resistance of a wire:

R = (ρ * L) / A,

where R is the resistance, ρ is the resistivity of aluminum, L is the length of the wire, and A is the cross-sectional area of the wire. We are given the values of R and L and need to find A.

First, we need to calculate the resistivity of aluminum at 20.0°C. The resistivity of aluminum at 20.0°C is approximately 2.65 x 10^-8 Ω·m.

Next, we rearrange the formula to solve for A:

A = (ρ * L) / R.

Substituting the given values, we have:

A = (2.65 x 10^-8 Ω·m * 32.0 m) / 2.50 Ω.

Calculating this expression, we find that A is approximately 3.392 x 10^-7 m².

The cross-sectional area of a wire is related to its diameter by the formula:

A = π * (d/2)^2,

where d is the diameter of the wire.

Rearranging this formula to solve for d, we get:

d = sqrt((4 * A) / π).

Substituting the value of A, we can calculate the diameter:

d = sqrt((4 * 3.392 x 10^-7 m²) / π) ≈ 2.57 mm.

Therefore, the diameter of the aluminum wire that must be used for the laboratory experiment is approximately 2.57 millimeters.

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Answer:

A ball is thrown straight up with a speed of 30

m/s. What is the maximum height reached by

the ball?

The time period and amplitude of the given function are 4 and 3.5 respectively. Thus the correct option is C.

Wavelength is defined as the distance between two successive troughs or crests. The peak of the wave is the highest point, while the trough is the lowest point. The wavelength is also known as the distance between two locations in a wave that have the same oscillation phase.

The time taken by a complete vibrational cycle of the wave to pass a particle is known as the time period or period of the wave. The period of the given function will be 4.

The maximum distance moved by a point on a vibrating body from its mean position is known as amplitude.

Time period = 4

And the amplitude of the function will be

\(A = (5+2) / 2 \\\)

\(A = 3.5\)

Therefore, amplitude = 3.5 and period = 4.

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The complete question is -

What are the period and amplitude of the function?

period: 3, amplitude: 3.5

period: 3; amplitude: 7

period: 4; amplitude: 3.5

period: 4; amplitude: 7

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The maximum velocity of the bird is m * g / k. Answer: The maximum velocity of the bird is m * g / k.Let us consider the given data. A bird can fly with a maximum speed of v₁ if it flies vertically upwards and a maximum speed of v₂ if vertically downwards. Air friction is proportional to speed.

And, the force generated by the bird's wing is constant in any direction.We have to determine the maximum speed of the bird when it flies in the horizontal direction. Let us find the maximum speed of the bird when it flies vertically upwards. When the bird flies upwards, it faces two forces: the force due to its wings and the force of air friction. The force due to the bird's wings is equal to its weight since the bird is flying with a constant velocity. F = m * gT

Let us now find the maximum velocity of the bird when it flies horizontally. In this case, the direction of the force of air friction is opposite to the direction of velocity, which is horizontal. Therefore, we have F = -kv. Equating this to the force generated by the bird's wings, which is constant, we get m * g = kv. Solving for v, we get v = m * g / k. This is the maximum velocity of the bird when it flies horizontally.  

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Answer:

Vf = 2000 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

\(v_{f} =v_{o}+a*t\\\)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 1200 [m/s]

a = acceleration = 4 [m/s]

t = 200 [s]

Vf = 1200 + (4*200)

Vf = 1200 + 800

Vf = 2000 [m/s]

Answer:

third option down

Explanation:

The reaction constant or variable (1). Variable, because the slope changes as a function of time is the correct option.

Option 1 is the best choice given the available data, as the reaction's rate is varied as a result of the slope changing with time. When discussing a chemical reaction's rate, it is important to note that as the concentrations of reactants and products change over time, the rate can also fluctuate. The rate of a reaction is frequently calculated from the slope of a plot of reactant or product concentration vs time. However, this slope might change during the course of a reaction, indicating that the rate is variable rather than constant.

Therefore, the correct option is (1).

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Answer:

It sort of depends on the factors of which car is bigger and the power that each car holds. However, they both face the same force, as Newtons’ third law of motion states.

Explanation:

Answer:

You would feel the greater Force

Explanation:

Essentially, you and the car have performed an elastic collision, this all correlates to the momentum conservation equation mvf=mvi. So essentially you and the car have to maintain the same momentum at all times because we know it is conserved; so speed would have to change to balance out the momentum of you and the car.

The volume that 1L of gas will occupy at 37°C and a constant pressure is 0.8L. Details about volume can be found below.

The volume of a gas can be calculated using the Charles law equation as follows:

V1/T1 = V2/T2

Where;

1/310 = V2/248

248 = 310V2

V2 = 248 ÷ 310

V2 = 0.8L

Therefore, the volume that 1L of gas will occupy at 37°C and a constant pressure is 0.8L.

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The microscope has two sets of lenses, one in the eyepiece and one in the objective lens. The amount of light is changed by adjusting the diaphragm of the microscope. The diaphragm controls the amount of light that passes through the stage and is focused on the object being viewed.

There are two types of diaphragms in a microscope: the iris diaphragm and the disk diaphragm. The iris diaphragm is adjustable, while the disk diaphragm is preset. The iris diaphragm is located near the base of the microscope and can be adjusted to control the amount of light that enters the microscope. It works like a camera aperture, opening or closing to let in more or less light. When the iris diaphragm is closed, less light enters the microscope, and the image appears darker.

When the iris diaphragm is open, more light enters the microscope, and the image appears brighter. By adjusting the iris diaphragm, you can get the best possible image of the object being viewed. To summarize, the diaphragm is the part of the microscope that you adjust to change the amount of light. The iris diaphragm is adjustable, while the disk diaphragm is preset. By adjusting the diaphragm, you can get the best possible image of the object being viewed.

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If the magma cools slowly, then the crystals have enough time to grow and become large.

If the growth does not experience any disturbance, then the mineral will have a perfect crystal form. But this perfect form is rarely found because in nature these disturbances are always there. Minerals that are found in nature often do not develop properly, making it difficult to classify minerals into crystallographic systems.

Instead the term crystal habit is used, the typical shape of a mineral is determined by the parts that form it, including the relative shape and size of these patches. We need to know some of the crystal stature found in certain types of minerals, so that the crystal stature can be used to determine the type of mineral, even though crystal stature is not a permanent characteristic of minerals.

Richard M Pearl (1975) divides crystal stature into 3 (three) groups, namely:

A. Elongated habits (long/streaky)

B. Flattened habits

C. Rounded habits (grain).

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Electromagnetic waves are those waves that are composed of electric and magnetic fields perpendicular to each other and to the direction of the propagation. All electromagnetic waves have the same speed.

That is, 3×10⁸ m/s.

X-ray is one of the electromagnetic waves. So are light, gamma rays, and radio waves.

Thus the speed of all these waves is equal.

Thus, the correct answer is option C, "Same as speed of radio waves"

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:

(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)

(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

(- 188.703, - 80.100) =  v · (- 0.259, 0.966) + u · (- 0.574, 0.819)

Then, we must solve the following system of linear equations:

- 0.259 · v - 0.574 · u = - 188.703

0.966 · v + 0.819 · u = - 80.100

The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.

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This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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Answer:

= 1.5 miles per hour

Explanation:

speed = Distance covered/ Time taken

we need to convert days into hours for easier computation

1 day = 24 hours

15days = ?

15×24 = 360 hours

= 540/360

= 1.5 miles per hour

Answer:

5.24m/s

Explanation:

Given parameters:

Initial velocity  = 4.7m/s

Acceleration  = 5.4m/s²

Time  = 0.1s

Unknown:

Final velocity of the particle = ?

Solution:

Acceleration is the rate of change of velocity with time.

   Acceleration  = \(\frac{v - u}{t}\)  

v is the final velocity

u is the initial velocity

t is the time taken

  Now find v;

           5.4  = \(\frac{v - 4.7}{0.1}\)  

             0.54  = v  - 4.7

          v  = 5.24m/s

The efficiency of a bulb can be calculated as the ratio of the useful energy output (in this case, the light energy) to the total energy input. In this scenario, the useful energy output is 500 J - 350 J = 150 J, and the total energy input is 500 J. So, the efficiency can be calculated as:

Efficiency = (useful energy output) / (total energy input) = (150 J) / (500 J) = 0.3 or 30%.

This means that 30% of the energy input was converted into useful light energy, while 70% was converted into heat. This is the efficiency of the bulb.

The thickness of insulation required to limit the heat flux through the composite wall to 60 W/m^2 in the case of gas free convection is approximately 17.998 m.

To determine the thickness of insulation required to limit the heat flux through the composite wall, we need to consider the different cases of heat transfer and use the appropriate convection heat transfer coefficient.

Let's calculate the thickness of insulation for each case:

1. Gas Free Convection (h = 5 W/m^2⋅K):

For this case, we can use the formula for one-dimensional heat conduction through a composite wall:

q = (T1 - T2) / (R_total)

where q is the heat flux, T1 is the temperature on one side of the wall, T2 is the temperature on the other side of the wall, and R_total is the total thermal resistance of the composite wall.

The total thermal resistance is given by:

R_total = R_insulation + R_ss1 + R_ss2

where R_insulation is the thermal resistance of the insulation, R_ss1 is the thermal resistance of the first stainless steel sheet, and R_ss2 is the thermal resistance of the second stainless steel sheet.

The thermal resistance can be calculated using the formula:

R = thickness / (k * A)

where R is the thermal resistance, thickness is the thickness of the material, k is the thermal conductivity, and A is the cross-sectional area of heat transfer.

Given:

k_ins = 1.5 W/m⋅K

k_ss = 15 W/m⋅K

Thickness of stainless steel sheets (ss): 1 mm = 0.001 m

Heat flux (q) = 60 W/m^2

T1 = 50°C

T2 = 25°C

h_gas_free_conv = 5 W/m^2⋅K

Let's calculate the thermal resistance for each layer:

R_ss1 = 0.001 m / (15 W/m⋅K * A)

R_ss2 = 0.001 m / (15 W/m⋅K * A)

R_insulation = x / (1.5 W/m⋅K * A)

Substituting these values into the equation for R_total, we get:

R_total = x / (1.5 W/m⋅K * A) + 0.001 m / (15 W/m⋅K * A) + 0.001 m / (15 W/m⋅K * A)

Now we can rearrange the equation for heat flux q and solve for the insulation thickness x:

x = q * (1.5 W/m⋅K * A) / (h_gas_free_conv * A) - 0.002 m

Substituting the given values, we have:

x = 60 W/m^2 * (1.5 W/m⋅K * A) / (5 W/m^2⋅K * A) - 0.002 m

Simplifying, we get:

x = 18 - 0.002 m

x ≈ 17.998 m

Therefore, the thickness of insulation required to limit the heat flux through the composite wall to 60 W/m^2 in the case of gas free convection is approximately 17.998 m.

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Answer:

P = 3000 Pa

Explanation:

Weight of Dorji, W = F = mg = 1500 N

The total surface area of soles of his feet is 0.5 m²

We need to find the pressure exerted by his body on the ground​. The pressure is equal to the force acting per unit area. So,

\(P=\dfrac{1500\ N}{0.5\ m^2}\\\\=3000\ Pa\)

So, the pressure exerted by his body on the ground​ is 3000 Pa.

The evidence that Wegener make use of to develop the theory of continental drift is a) Mountains in North America appear to be part of the same chain of mountains as those in Northern Europe.

Wegener and his supporters has collected a great deal of evidence for the continental drift hypothesis. Identical rocks, that are of the same type and age, are found on both sides of the Atlantic Ocean. He found that the rocks had formed side-by-side and that the land had since moved apart.

Mountain ranges with the same rock types, structures, and ages are presently on opposite sides of the Atlantic Ocean. The Appalachians of the eastern United States and Canada, for example, are like mountain ranges in eastern Greenland, Ireland, Great Britain, and Norway. He concluded that they formed as a single mountain range that was separated as the continents drifted.

He proposed that the organisms had lived side by side, but that the lands had moved apart after they were dead and fossilized. Grooves and rock deposits left by ancient glaciers are found today on different continents are very close to the equator. This indicates that the glaciers either formed in the middle of the ocean and/or covered most of the Earth.

Coral reefs and coal-forming swamps are found in tropical and subtropical environments, but the ancient coal seams and coral reefs are found in locations where it is much too cold today. He suggested that these creatures were alive in warm climate zones and that the fossils and coal later had drifted to new locations on the continents.

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Identification of compounds can benefit from density. It is also a useful feature since it connects (or acts as a conversion factor between) a substance's mass and volume. Volume and mass are extended (or extrinsic) qualities of matter that are quantity dependent.

The force of an air mass acting on the earth's surface is known as atmospheric pressure. Remember that wind currents are created when the densities of two separate air masses differ.

Our wind currents are driven by the atmospheric pressure density, and denser air exerts a higher pressure than less dense air. Compared to the cold and dry air, the warm and humid air is less dense. The less dense air will then float on top of the thicker air in certain regions.

Therefore, Warm air masses rise while cold air masses descend because they are less dense.

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Answer:

So you can have quark anti-quark pairs (charge anti-charge), or add the charges together (red+blue+green = white). This also holds for theorectical particles made of 4 quarks (2 quarks 2 anti-quarks) and 5 quarks (four quarks and 1 anti-quark or the reverse). In your example ud only has two quarks so only two colour charges so cannot exist. If you want a more indepth answer start reading about colour charge.

Explanation:

For the diffraction grating, the slits spacing should be comparable to the wavelength of length incident on the grating to observe the phenomenon of diffraction.

The wavelength of light considered for the for diffraction ranges from,

By simplifying the given value in meters,

As the value of 1000 nm fall in this range and thus, considered as most reasonable slit spacing.

Hence, option 2 (1000 nm) is the correct answer.

Answer: 35 degree Celsius

Explanation: Subtract both the temperatures And divide by two.