Answer:
0,1,2,3............
Find the area of the rectangle shown
7 1/2 ft
5 1/4ft
Answer:
39 3/8 ft ^2
Step-by-step explanation:
To find the area of a rectangle, multiply the length times the width.
A = l*w
= 7 1/2 * 5 1/4
Change the mixed numbers to improper fractions.
A = 15/2 * 21/4
=315/8
Change back to a mixed number.
8 goes into 315 39 times with 3 left over.
= 39 3/8
Answer:
Area = 39.375 ft²
(you can round to 39.4)
Step-by-step explanation:
Find the area of the rectangle shown
7 1/2 ft
5 1/4ft
7 1/2 = 7.5 ft
5 1/4 = 5.25 ft
Area = L x W
Area = 7.5 x 5.25
Area = 39.375
3. The t test for two independent samples - Two-tailed example
“Bullying,” according to noted expert Dan Olweus, “poisons the educational environment and affects the learning of every child.” Bullying and victimization are evident as early as preschool, with the problem peaking in middle school. Suppose you are interested in the emotional well-being of not only the victims but also bystanders, bullies, and those who bully but who are also victims (bully-victims). You decide to measure depression in a group of victims and a group of bully-victims using a 26-item, 3-point depression scale. Assume scores on the depression scale are normally distributed and that the variances of the depression scores are the same among victims and bully-victims.
The group of 30 victims scored an average of 21.5 with a sample standard deviation of 10 on the depression scale. The group of 27 bully-victims scored an average of 25.8 with a sample standard deviation of 9 on the same scale. You do not have any presupposed assumptions about whether victims or bully-victims will be more depressed, so you formulate the null and alternative hypotheses as:
H0
: μvictims
– μbully-victims
= 0
H1
: μvictims
– μbully-victims
≠ 0
You conduct an independent-measures t test. Given your null and alternative hypotheses, this is a test. To use the Distributions tool to find the rejection region, you first need to set the degrees of freedom. The degrees of freedom is .
The critical t-scores that form the boundaries of the rejection region for α = 0.01 are ± .
In order to calculate the t statistic, you first need to calculate the standard error under the assumption that the null hypothesis is true. In order to calculate the standard error, you first need to calculate the pooled variance. The pooled variance is s2p
= . The standard error is s(M1 – M2)
= .
The t statistic is .
The t statistic in the rejection region. Therefore, the null hypothesis is . You conclude that victims have a different mean depression score than bully-victims. Thus, it can be said that these two means are different from one another.
The test statistics do not lie in the rejection so the null hypothesis does not reject.
How to solveHere we have the following information:
\(\bar{x}_{1}=25.3, n_{1}=25, s_{1}=9, \bar{x}_{2}=20.5, n_{2}=23, s_{2}=8\)
Here degree of feedom will be
\(df=n_{1}+n_{2}-2=25+23-2=46\)
The critical values of t are: +/- 2.687
Rejection region:
If t < -2.687 and t > 2.687, reject H0
Pooled variance is :
\(s^{2}_{p}=\frac{(n_{1}-1)s_{1}^{2}+\left ( n_{2}-1 \right )s_{2}^{2}}{n_{1}+n_{2}-2}=72.8696\)
The standard error is
\(s_{M_{1}-M_{2}}=s_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}=2.4664\)
and t-statistics will be
\(t=\frac{\bar{x}_{1}-\bar{x}_{2}}{s_{p}\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}}=1.946\)
The test statistics do not lie in the rejection so the null hypothesis does not reject.
You cannot conclude...
not
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How many division facts can you write to represent the factors of 15?
1
4
0
3
Determine the total surface area and volume of each figure.
The total surface area of solid is,
S = 220 m²
And, The volume of the prism is, 200 m³
We have to given that;
A solid prism is shown in figure.
Since, The surface area of a prism is,
S = (2 × Base Area) + (Base perimeter × height)
Where, "S" is the surface area of the prism.
Hence, We get;
base area = 5 x 10 = 50 m²
height = 4 m
Base Perimeter = 2 (5 + 10) = 30
Hence, We get;
S = (2 x 50) + (30 x 4)
S = 100 + 120
S = 220 m²
Since, A prism is a solid shape that is bound on all its sides by plane faces. The volume of a prism is expressed as;
V = base area × height.
Now, For given figure,
Volume of the prism = base area × height
base area = 5 x 10 = 50 m²
height = 4 m
Hence, Volume = 50 × 4 m³
= 200 m³
Thus, The volume of the prism is, 200 m³
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Use vector notation to describe the points that lie in the given configuration. (Let s and t be elements of the Reals.)
The plane spanned by:
v1 = (6, 5, 0)
and
v2 = (0, 6, 5)
l(s, t) = ?
Answer: I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }
Step-by-step explanation:
Given the data in the question;
A vector is in the span of V1 and V2 only if it is a linear combination.
of V1 and V2.
so 'V' is in the span if;
V = SV1 + tV2 [ S and t are real numbers ]
V = [ 6si + 5sj ] + [ 6tj + 5tz]
V = 6s, 5s+6t, 5t
so
I(s,t) = {(6s, 5s+6t, 5t)| sER, tER }
Vector notation is indeed a commonly utilized notation in maths and physics for expressing vectors, which can be either Euclidean carriers or, more generally, members of a vector space, and the calculated value "\(\bold{I(s,t) = {(2s,7s+2t,7t)| sER, tER}}\)".
Vector notation calculation:Vectors, like any other variable, are frequently represented in advanced maths as a basic italic font.A vector is a linear combination of \(v_1\ \text{and} \ v_2\), it would be in the span of \(v_1\ \text{and} \ v_2\). In other words, if v is in the span, it would be in the span.\(v = s v_1 + t v_2\) [ s and t are real numbers ]
\(v = [2si + 7sj ] + [ 2tj + 7tz]\\\\v = 2s,7s+2t,7t\\\\I(s,t) = {(2s,7s+2t,7t)| sER, tER}\)
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You have saved $14,000 for a down payment on a house. Your bank requires a minimum down payment of 17%. What is the maximum price you can offer for a home in order to have enough money for the down payment? (Round your answer to two decimal places.)
The maximum price you can offer for a home is approximately $82,352.94 for a 17% down payment.
To determine the maximum price you can offer for a home, you need to calculate 17% of the total price, which will be your down payment of $14,000.
Let's assume the maximum price you can offer for the home is P dollars.
According to the given information, the down payment requirement is 17% of the total price. So, we can set up the following equation:
\(0.17P = $14,000\)
To solve for P, divide both sides of the equation by 0.17:
P = $14,000 / 0.17
Calculating this expression, we find:
P ≈ $82,352.94
Therefore, the maximum price you can offer for a home in order to have enough money for the 17% down payment is approximately $82,352.94.
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How did the deregulation of media contribute to the success of televangelists such as Jerry Falwell?
A.
The Federal Communications Commission required that networks approve each evangelist's content before airing their shows.
B.
Religious programming on television experienced a surge in popularity in the 1980s.
C.
Local stations were controlled by the National Broadcasting Company, which regulated paid religious broadcasts.
D.
Broadcasters such as MTV helped gospel music become popular with the younger generation.
Answer:
D. Broadcasters such as MTV helped gospel music become popular with the younger generation.
Step-by-step explanation:
PLEASE HELP
If Joey can run 24 miles in 6 hours, how many miles
can he run in 2 hours? SHOW YOUR WORK! (Hint:
Use equivalent ratios/fracción
Answer:
8 miles
Step-by-step explanation:
24 miles/6 hours = 4 miles per hour
4 miles per hour x 2 hours = 8 miles
Answer:
8 miles
Step-by-step explanation:
24/6 is your ratio. He runs 4 miles an hour, but we need 2 hours. 4x2=8 miles in 2 hours.
need this done fast pls.
Answer:
45°Step-by-step explanation:
85 + 50 + ? = 180
? = 180 - 85 - 50
? = 45
Suppose that the functions h and g are defined as follows.
h(x) = (x+5)(x+5)
g(x) = 4x+5
h
¹(²)(-1).
(a) Find
h
(b) Find all values that are NOT in the domain of
g
If there is more than one value, separate them with commas.
For the given functions, we have that:
a) The numeric value of the division function at x = 4 is of (h/g)(4) = 81/21 = 3.86.
b) The value that is not in the domain of the division function is of x = -1.25.
Division functionIn this problem, the functions that we are given are defined as follows:
h(x) = (x + 5)(x + 5).g(x) = 4x + 5.To find the quotient function of h(x) and g(x), we just divide the function h(x) by the function g(x), that is:
h(x)/g(x) = [(x + 5)(x + 5)]/(4x + 5).
At x = 4, the numeric value is found replacing each instante of x by 4, hence:
(h/g)(4) = [(4 + 5)(4 + 5)]/(4(4) + 5)) = 81/21 = 3.86.
The denominator of a fraction cannot be zero, as division by zero does not exist, hence the value of x that is not on the domain of the division function is found as follows:
4x + 5 = 0.
4x = -5.
x = -5/4
x = -1.25.
What is the missing information?The complete problem is given by the image at the end of the answer. There are lots of instances of this problem, just with different functions, so we use the functions given in this problem and not on the image.
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Sketch and label a net of the right triangular prism. Each square on the grid represents
1 square centimeter. Calculate the surface area of the prism by using its net.
The total surface area of the prism is determined as 216 cm².
What is the surface area of the prism?The surface area of the prism is calculated by applying the following formula.
The area of the two triangular faces is calculated as follows;
Area of the two triangles = 2 (¹/₂ x base x height )
Area of the two triangles = 2 (¹/₂ x 6 cm x 4 cm )
Area of the two triangles = 24 cm²
The area of rectangular faces is calculated as follows;
A = ( 5 cm x 12 cm ) + (5 cm x 12 cm ) + ( 6 cm x 12 cm )
A = 192 cm²
The total surface area of the prism is calculated as follows;
Area = 24 cm² + 192 cm²
Area = 216 cm²
The sketch of the triangular prism is in the image attached.
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Find the area of the region bounded by
• y = √x,
• y = 2-x², and
y = -√2x.
The area of the Region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.
To find the area of the region bounded by y = √x, y = 2-x², and y = -√2x, we need to graph the equations and determine the points of intersection. Then we can integrate to find the area.
Firstly, we'll graph the equations and find the points of intersection:
y = √xy = 2-x²y = -√2xGraph of y = √x, y = 2-x², and y = -√2xWe need to solve for the points of intersection, so we'll set the equations equal to each other and solve for x:√x = 2-x²√x + x² - 2 = 0Let's substitute u = x² + 1:√x + u - 3 = 0√x = 3 - u
(Note: Since we squared both sides, we have to check if the solution is valid.)u = -2x²u + x² + 1 = 0 (substituting back in for u
)Factoring gives us:u = (1, -2)We can then solve for x and y:x = ±1, y = 1y = 2 - 1 = 1, x = 0y = -√2x = -√2, x = 2y = 0, x = 0Graph of y = √x, y = 2-x², and y = -√2x with points of intersection to find the area, we need to integrate.
The area is bounded by the x-values -1 to 2, so we'll integrate with respect to x:$$\int_{-1}^0 (2 - x^2) - \sqrt{x} \ dx + \int_0^1 \sqrt{x} - \sqrt{2x} \ dx$$
We can then simplify and integrate:$$\left[\frac{2x^3}{3} - \frac{2x^{5/2}}{5/2} + \frac{4}{3}x^{3/2}\right]_{-1}^0 + \left[\frac{2x^{3/2}}{3} - \frac{4x^{3/2}}{3}\right]_0^1$$$$= \frac{4}{3} + \frac{4}{3} - \frac{4}{15} + \frac{4}{3} - \frac{4}{3}$$$$= \frac{32}{15}$$
Therefore, the area of the region bounded by y = √x, y = 2-x², and y = -√2x is $\frac{32}{15}$.
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a 22 foot ladder leans against a house so that the base of the ladder is 5 feet from the base of the house. what is the angle of the elevation of the ladder
Answer:
ok so get ready
Step-by-step explanation:
it would be 70 degrees because 180-(22*5)=70 and the equation to find an angle like this would be 180-(length of ladder * how far the ladder is from the house)= the angle of the ladders elevation.
You have 8 posters to hang in your room. You want to hang the posters as a border around the walls of your room. How many ways can you arrange the posters
Answer:
Number of ways = 40320 ways
Step-by-step explanation:
Total number of posters = 8
The points are to be arranged in the room without any definite pattern or configuration.
Since there is no definite pattern ir configuration to hang the posters, the number of ways f hanging the posters will be gotten by factorial method.
Number of ways = 8!
Number of ways= 8*7*6*5*4*3*2*1
Number of ways = 56*30*12*2
Number of ways = 1680 * 24
Number of ways = 40320
if m<xyz = 58 and m<wxz = 51 find m<wzx
Answer:
m<wzx = 71
Step-by-step explanation:
Assuming these are interior angles of a triangle.
The sum of all three interior angles of a triangle is always 180 degrees, therefore:
m<xyz + m<wxz + m<wzx = 180
Substitute our values:
58 + 51 + m<wzx = 180
m<wzx = 180 - 58 - 51
m<wzx = 71
Determine the truth value of each of these statements if the domain for all variables consists of all integers.
a) ∀n∃m(n2 < m)
b) ∃n∀m(n < m2)
c) ∀n∃m(n + m = 0)
d) ∃n∀m(nm = m)
e) ∃n∃m(n2 + m2 = 5)
f ) ∃n∃m(n2 + m2 = 6)
g) ∃n∃m(n + m = 4 ∧ n − m = 1)
h) ∃n∃m(n + m = 4 ∧ n − m = 2)
i) ∀n∀m∃p(p = (m + n)∕2)
For each of the given statements the truth value are as follow:
a. ∀n ∃m (n²< m) is False.
b. ∃n ∀m (n < m²) is true.
As given in the question,
Domain of all the presents variables consists of integers.
Truth value for the given statements are as follow:
a. ∀n ∃m (n²< m)
For integers -2
(-2)² = 4
There is no such integer present whose square is less than the integer.
Truth value of above statement is false.
b. ∃n ∀m (n < m²)
For integers -3
(-3)² = 9
-3 < 9 is the true for all positive and negative integers.
Therefore, the truth value of the given statements are as follow:
a. ∀n ∃m (n²< m) is False.
b. ∃n ∀m (n < m²) is true.
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7
Are the two triangles similar? If so, why are they similar?
(a)
A The triangles are similar by the definition of similarity (all congruent angles, all proportional sides)
B The triangles are similar by AA- Theorem
The triangles are similar by SSS- Theorem
The triangles are not similar
(b)
If they are similar, what is the similarity statement?
A ASTR - ALKR
Answer:
option B is correct answer
because it is similar by AA similarity -.theorum
Consider the given functions. Select the expression that will produce h(x). A. f(x) + f(x) B. f(x) − g(x) C. f(x) + g(x) D. g(x) − f(x)
Answer:
here is your answer
Step-by-step explanation:
here is your answer
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Test Scores in Relation to Homework Hours of Homework (a) Is the relationship linear or not linear? Justify your response. (b) Is the relationship increasing or decreasing? (c) What is the domain and range of the data set? (d) Draw a line of best fit, and find the slope of that line.
The relationship is linear
It is an increasing functionThe slope is approximately 8Part (a) and (b): The relationship typeThe complete question and the line of best fit are added as an attachemnt
From the question, we have the following parameters that can be used in our computation:
The image of the scatter plot
On the scatter plot, we can see that
The points appear to be on a straight line
Also, we can see that
As the x values increases the y values decreases
This represents a decreasing linear association.
The domain and the rangeFrom the graph, we can see that the x and the y values are positive
So, the domain is x > 0 and the range is y > 0
The line of best fitSee attachment for the line of best fit
Using the points on the line, we have
Slope ≈ (30 - 70)/(0 - 5)
Slope ≈ 8
Hence, the slope is approximately 8
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i need to find da slope
Answer:
Slope is -1
Step-by-step explanation:
-5/5= -1
I am not sure if you want an explanation or just the answer, but I am willing to explain it if needed.
Which fraction is represented by point A on the number line?
The fraction represented by point A, it is crucial to have information about the scale, intervals, and the relative position of point A on the number line.
With these details, you can calculate the fraction accurately.
Point A on the number line represents a fraction that requires additional information to determine its precise value.
I can provide you with a general approach to finding the fraction corresponding to a given point on the number line.
A number line represents a range of values, typically with a specific scale or interval.
The scale can be divided into equal parts, such as units or fractions.
To determine the fraction represented by point A, we need to know the scale and the position of point A relative to that scale.
Let's consider a number line that ranges from 0 to 1, with evenly spaced tick marks representing tenths.
If point A is located halfway between the tick marks representing 0.4 and 0.5, then it represents the fraction 0.45 (or 9/20 in simplified form).
If the number line has a different scale or is divided into different intervals, the fraction represented by point A will be different.
Without specific details about the number line and the position of point A, it is impossible to determine the fraction precisely.
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Need help plzz%zzzzzzzzzzzz
Answer:
where is the question plez give question
Kaelyn is reading a book. The books thickness is 25 millimeters. How many of these books would fit on a shelf that is 1 meter long?
The number of books that can be fit on a shelf is 1 meter long and will be 40.
What is Algebra?Algebra is the study of mathematical symbols, and the rule is the manipulation of those symbols.
Kaelyn is reading a book.
The book's thickness is 25 millimeters.
Then the number of the books that can be fit on a shelf is 1 meter long will be
Let x be the number of the books.
The thickness of the book in meters will be 0.025 m.
Then we have
0.025x = 1
x = 1 / 0.025
x = 40
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if a sprinkler waters 1/14 of a lawn in 1/2 hour, how much time will it take to water the entire lawn
Answer:
7 hours
Step-by-step explanation:
1/14 * 14 = 1 whole lawn
1/2 hours = 30 minutes
14 * 30 = 420 minutes to water entire lawn
420 minutes = 7 hours
A parking garage in the city charges $2. 75 for the first hour and $1. 25 for each additional hour or part thereof. What is the maximum time in hours, x, that tony can park his car at the garage if he wants to pay less than $8?.
The maximum time that tony can park his car at the garage if he wants to pay less than $8 is 5.6 hours
Let's start by setting up an inequality that represents the situation:
Total cost for parking x hours <= $8
We know that the first hour costs $2.75, and each additional hour or part thereof costs $1.25. So the cost for x hours can be expressed as:
Cost = $2.75 + $1.25 × (x - 1)
Note that we subtract 1 from x because the first hour is already accounted for in the flat fee.
Now we can substitute this expression into the inequality:
$2.75 + $1.25 × (x - 1) <= $8
Simplifying this inequality, we get:
$1.25x <= $7
Dividing both sides by $1.25, we get:
x <= 5.6
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A 4-yard dumpster cost $95.00 monthly how much would it cost for the year?
Answer options:
A) 190.00
B) 180.00
C) 170.00
D) 160.00
If a 4-yard dumpster cost $95.00 monthly, the total cost for the year is $1,140.
How is the total cost determined?The total cost for the year of the dumpster is the product of the multiplication of the monthly cost and 12.
Multiplication is one of the four basic mathematical operations, including addition, subtraction, and division.
In any multiplication, there must be the multiplicand (the number being multiplied), the multiplier (the number multiplying the multiplicand), and the product (or the result).
The monthly cost of the 4-yard dumpster = $95.00
1 year = 12 months
The total annual cost = $1,140 ($95 x 12)
Thus, using the multiplication operation, we can find that none of the options is correct as the total annual cost but $1,140.
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Determine the period of the function y = Negative 2 sine (StartFraction pi Over 2 EndFraction) x.
a.
2
c.
-2
b.
3.14
d.
4
Answer: D. 4
Step-by-step explanation:
You are to act as a business owner and create a flyer to advertise one single item. As a student you will calculate how much the item will cost to a customer including the sales tax given a sales tax rate of 7%
Answer:
total cost = sell price + (sell price * 0.07)
What value for the
constant, h, in the equation
shown below will result in an infinite number of
solutions?
6t + 18 = h(3x + 9)
Therefore , As a result, h = 2 is the answer to the equation in the given question.
Explain equation.An equation is a mathematical representation of two equal variables, one on each side of a "equals" sign. Everyday issues can be resolved with equations. We commonly look for pre algebra help to deal with problems in real life. Pre-algebra is the fundamental foundation of mathematics.
Here,
The formula is as follows: 6x + 18 = h(3x + 9)
To ensure that the expression has an unlimited number of answers, h's value must be determined.
Take the expression now and continue solving it.
=> 6x + 18 = h(3x + 9)
=>3hx + 9h= 6x +8
The expression will have an endless number of solutions if the coefficients of the left-hand side and the right-hand side are equal.
Therefore, 3h = 6 and h = 2
As a result, h = 2 is the answer to the equation in the given question.
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