Answer:
\( \huge{ \boxed{ \bold{ \text{ \: (4 \: ,\: 5.5)}}}}\)
Step-by-step explanation:
\( \text{Let \: the \: points \: be \: A\: and \:B} : \)
\( \rm{A(6 \:, 1) \longrightarrow \: (x1 \: ,y1)}\)
\( \rm{B(2 \: 10) \longrightarrow \: (x2 ,\: y2)}\)
\( \text{Finding \: the \: midpoint} : \)
\( \boxed{ \rm{midpoint = ( \frac{x1 \:+ x2}{2} \: , \: \frac{y1 + y2}{2} )}}\)
\( \rm{ \: ↦ midpoint = ( \frac{6 + 2}{2} \: , \frac{ 1 + 10}{2} )}\)
\( \rm{↦midpoint = ( \frac{8}{2} \: , \frac{11}{2} )}\)
\( \rm{↦ midpoint = (4 \: ,\: 5.5 \: )}\)
Hope I helped!
Best regards! :D
~\( \text{TheAnimeGirl}\)
A box is 21 centimeters tall. How tall would the box measure in meters?
Answer:
0.21
Step-by-step explanation:
divide the length value by 100 21 centimeters in meters is 0.21
Answer:
0.21 its the k12 test.
Step-by-step explanation:
What percent of 80 is 60
Answer:
80% of 75 is 60
Step-by-step explanation:
0.80x=60
x=60/0.80
x=75
which inequality is true?
100 Points! Algebra question. Photo attached. Find the length of the arcs below. Round to the nearest tenth. Please show as much work as possible. Thank you!
The length of the arcs are;
1. s = 6. 4π
2. s = 11. 0π
How to determine the valuesThe formula for calculating the length of an arc is expressed as;
s = rθ
Such that;
s is the length of the arcr is the radius of the circleθ is the central angle in radiansFrom the information given, we have that;
s = 4.25 × 3π/2
Multiply the values, we get
s = 12.75π/2
Divide by the coefficient , we get;
s = 6. 4π
2. The length of the arc would be;
s = 6.62 × 5π/3
Multiply the values, we have;
s = 33. 1π/3
Divide by the value, we get;
s = 11. 0π
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What are the values of a and b?
Answer:
a =17.08
b = 16.97
Step-by-step explanation:
What are the values of a and b?
Using pythagoras therem';
Hyp^2 = opp^2 + adj^2
Get the value of b;
18^2 = b^2 + 6^2
324 = b^2 + 36
b^2 = 324 - 36
b^2 = 288
b = √288
b = 16.97
Get the value of a;
b^2 + 2^2 = a^2
288 + 4 = a^2
292 = a^2
a^2 = 292
a = √292
a= 17.09
A standard sheet of paper in Europe is `29.7` centimeters long and `21` centimeters wide.
Which standard sheet of paper has a greater area?
Standard sheet of paper in Europe has a greater area i.e. 29.7 cm. long and 21 cm wide.
1 in = 2.54 cm (in Europe)
In SI units standard-sized paper is 21.0 cm by 29.7 cm, which is equivalent to 8.268 in by 11.693 in.
In U.S.
U.S. sized standard paper is 8.0 in by 11.0 in therefore the SI (internationally) sized paper is longer.
Standard sheet of paper in Europe has a greater area than standard sheet of paper in U.S.
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please help
Which linear regression equation best fits the given points?
(1, 0), (4, 5), (5, 12), (7, 16), (8, 25), (11, 22), (14, 32)
yˆ=25x+1.9
yˆ=−52x−1.9
yˆ=52x−1.5
yˆ=−25x+1.5
Answer:
I dont know. Im sorry im struggling with this problem too. I hope you get an answer :)
which shows the product of 23 and 39
Answer:
897
Step-by-step explanation:
"Product" in math refers to multiplication, so you would just multiply the two to get 897.
Answer:
897
Step-by-step explanation
multilpy
4-member curling team is randomly chosen from 6 grade 11 students and 8 grade 12 students. What is the probability that the team has at least 2 grade 11 students?
Answer:
0.5944 = 59.44% probability that the team has at least 2 grade 11 students
Step-by-step explanation:
The students are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
\(P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}\)
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
\(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
We have that:
6 + 8 = 14 students, which means that \(N = 14\)
6 grade 11 students means that \(k = 6\)
Teams of 4 members means that \(n = 4\)
What is the probability that the team has at least 2 grade 11 students?
This is:
\(P(X \geq 2) = 1 - P(X < 2)\)
In which
\(P(X < 2) = P(X = 0) + P(X = 1)\)
So
\(P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}\)
\(P(X = 0) = h(0,14,4,6) = \frac{C_{6,0}*C_{8,4}}{C_{14,4}} = 0.0699\)
\(P(X = 1) = h(1,14,4,6) = \frac{C_{6,1}*C_{8,3}}{C_{14,4}} = 0.3357\)
Then
\(P(X < 2) = P(X = 0) + P(X = 1) = 0.0699 + 0.3357 = 0.4056\)
\(P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4056 = 0.5944\)
0.5944 = 59.44% probability that the team has at least 2 grade 11 students
Find the indicated measure in parallelogram ABCD m
In the parallelogram ABCD the measure of ∠BEC is obtained as 113°.
What is a parallelogram?
A quadrilateral with two sets of parallel sides is referred to as a parallelogram. In a parallelogram, the opposing sides are of equal length, and the opposing angles are of equal size. Additionally, the interior angles that are additional to the transversal on the same side.
It is given that ABCD is a parallelogram.
The measure of ∠EAD = 30°.
The measure of ∠EDA = 37°.
In the parallelogram ∠EBC = ∠EDA as they form alternate interior angles pair.
Similarly, ∠ECB = ∠EAD as they form alternate interior angles pair.
The measure of ∠ECB = 30°.
The measure of ∠EBC = 37°.
Since EBC forms a triangle, so the sum of the angles of a triangle is 180°.
The equation is -
∠ECB + ∠EBC + ∠BEC = 180°
Substitute the values into the equation -
30° + 37° + ∠BEC = 180°
67° + ∠BEC = 180°
∠BEC = 180° - 67°
∠BEC = 113°
Therefore, the measure of ∠BEC = 113°.
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11.
D
Name the postulate, if possible, that makes the triangles
congruent.
E
A
B
a) SSS
b) SAS
c) ASA
d) Not Possible
Answer:
Step-by-step explanation:
The two angles at E that are enclosed by DE and CE (<DEC) and AE and BE (AEB) are vertically opposite. Therefore you have 2 sides and an included angle.
The Postulate is SAS
The lengths of the sides of a triangle are 3 , 4 , 5 Classify the triangle as acute, right, or obtuse.
please guys asap guys i need it so badly thank you
Answer:
Step-by-step explanation:
Type < or > to make this statement true -a___-b
The comparisons that are true are 11. -5 < 0 12. 9 > -8 14. 55 > -75 15. -32 < -24 16. 89 > 73 17. -58 < -51 19. 17 < 23 20. 18 > -36 and that is not true are 13. -7 = -7 (not true) 18. -32 > 4 (not true)
To make each statement true, write < or >. We need to compare two values for each statement to determine whether it is true or false.
To indicate that the first value is less than the second value, write <.
Alternatively, to indicate that the first value is greater than the second value, write >.
Below are the comparisons: 11. -5 < 0 12. 9 > -8 13. -7 > -7 14. 55 > -75 15. -32 < -24 16. 89 > 73 17. -58 < -51 18. -32 > 4 19. 17 > 23 20. 18 > -36
To determine the direction of inequality, we need to compare the values.
We used inequality signs such as > (greater than) or < (less than) to indicate which value is larger or smaller than the other.
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The correct question would be as
Write > or < to make each statement true.
11. -5 0
12. 9 -8
13. -7 7
14. 55 -75
15. -32 -24
16. 89 73
17. -58 -51
18. -32 4
19. 17 23
20. 18 -36
Select the system of linear inequalities whose solution is graphed. O y < 3x-2, x + 2y > 4 O y ≤ 3x-2, x + 2y 2 4 O y> 3x-2, x + 2y < 4 O y2 3x-2, x + 2y ≤ 4
Option D is the correct answer.
From the graph, we can conclude that,
1. The two lines are continuous lines and not broken lines. So, the inequality sign should be either ≤ or ≥.
2. The points on the lines of the shaded region are also included in the solution.
The only option that matches with the above conditions is option D. So, option D is the correct answer.
Let us verify it.
Now, let us consider a point that is inside the shaded region and also on any one line.
Let us take (0, 2).
Plug in 0 for x and 2 for y in each of the options and check which inequality holds true.
Considering the inequalities,
y ≥ 3x - 2
x + 2y ≤ 4
Solving we get,
2 ≥ 3(0) - 2
2 ≥ -2
x + 2y ≤ 4
0 + 2(2) ≤ 4
4 ≤ 4
Here, both inequalities are correct.
So, option D is the correct answer.
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The complete question is =
Which system of linear inequalities is graphed?
A. y < 3x-2
x + 2y ≥ 4
B. y < 3x - 2
x + 2y > 4
C. y > 3x - 2
x + 2y < 4
D. y ≥ 3x - 2
x + 2y ≤ 4
Which of the following rational functions is graphed below F(X) = 1/4x squared
Jane and johnny are running a race. Jane's speed is 1/4 that of Johnny's.
What is Johnny's speed compared to Jane?
Explain.
25%
50%
150%
400%
The right response is 400%. In other words, Johnny moves at four times the pace of Jane.
We must compare the speeds of Johnny and Jane in relation to one another in order to get their ratio. According to the issue, Jane moves at a pace that is 1/4 that of Johnny. In other words, Jane moves at a speed that is one-fourth that of Johnny.
We may compare the speeds as a fraction to figure out the ratio:
Johnny's speed divided by Jane's speed equals 4/1.
This indicates that Johnny is moving at a speed that is four times that of Jane. We can express Johnny's speed as 400% of Jane's speed in percentage terms.
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A plane flying with a constant speed of 360 km/h passes over a ground radar station at an altitude of 1 km and climbs at an angle of 30°. At what rate (in km/h) is the distance from the plane to the radar station increasing a minute later? (Round your answer to the nearest whole number.)
The rate (in km/h) at which the distance from the plane to the radar station is increasing a minute later is 0 km/h (rounded to the nearest whole number).
To solve this problem, we can use the concepts of trigonometry and related rates.
Let's denote the distance from the plane to the radar station as D(t), where t represents time. We want to find the rate at which D is changing with respect to time (dD/dt) one minute later.
Given:
The plane is flying with a constant speed of 360 km/h.
The plane passes over the radar station at an altitude of 1 km.
The plane is climbing at an angle of 30°.
We can visualize the situation as a right triangle, with the ground radar station at one vertex, the plane at another vertex, and the distance between them (D) as the hypotenuse. The altitude of the plane forms a vertical side, and the horizontal distance between the plane and the radar station forms the other side.
We can use the trigonometric relationship of sine to relate the altitude, angle, and hypotenuse:
sin(30°) = 1/D.
To find dD/dt, we can differentiate both sides of this equation with respect to time:
cos(30°) * d(30°)/dt = -1/D^2 * dD/dt.
Since the plane is flying with a constant speed, the rate of change of the angle (d(30°)/dt) is zero. Thus, the equation simplifies to:
cos(30°) * 0 = -1/D^2 * dD/dt.
We can substitute the known values:
cos(30°) = √3/2,
D = 1 km.
Therefore, we have:
√3/2 * 0 = -1/(1^2) * dD/dt.
Simplifying further:
0 = -1 * dD/dt.
This implies that the rate at which the distance from the plane to the radar station is changing is zero. In other words, the distance remains constant.
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What is the slope of the line
Step-by-step explanation:
Look at the points (0,-3) and ( 3,0)
slope, m = rise / run = 3 / 3 = 1
Answer:
1
Step-by-step explanation:
y=x+3
The length of a rectangle is six times its width. If the rectangle is 600 yd^2 find its perimeter
Answer:
8400 yd^2
Step-by-step explanation:
600x 6 because its six times
3600
L+L+W+W=p
8400 yd ^2
not allowed
The table shows information about the masses of some dogs.
a) Work out the minimum number of dogs that could have a mass of more than
26 kg.
b) Work out the maximum number of dogs that could have a mass of more than
26 kg.
Mass, x (kg)
0≤x≤10
10≤x≤20
20≤x≤30
30 < 10
Frequency
8
11
5
Based on the frequency table given,
a) The minimum number of dogs that could have a mass of more than 26 kg is of: 5.
b) The maximum number of dogs that could have a mass of more than 26 kg is of: 16.
How is this so?The frequency table displays the number of times each value, or range of values, appears in the data-set.
where 11 weights are between 20 and 30, and all of the dogs in the interval 20 × 30 have weights less than 26 kg, the lowest number of dogs that might have a mass more than 26 kg is 5.
This implies that only the dogs in the period 30 x 40 would have a mass greater than 26 kg.
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What fractions are less than, greater than an equal to 1/2
Answer:
1/4
1/8
1/12
1/100
1/1000
1/10000
The diameter of a circle is 2 units. What is the radius of the circle?
Answer:
The radius is 1 unit.
Step-by-step explanation:
The radius of a circle is half of its diameter. 2/2=1 unit
give the location of Denver as an ordered pair X,Y
Answer:
\(\huge\boxed{\sf{Ordered\:Pair:\:(-6, 3)}}\)
Step-by-step explanation:
Hello.
We need to find the coordinates of Denver.
Let's take a look at the coordinate plane and see if we can determine the coordinates of Denver.
The x-coordinate comes first. Look at the x-axis.
The x-coordinate of Denver is
-6
The y-coordinate of Denver is
3
The ordered pair is
(-6, 3)
I hope it helps.
Have a nice day.
\(\boxed{imperturbability}\)
hii good morning the answer is (-6, 3)
Is the slope for the line below positive or negative
Answer:
negative
Step-by-step explanation:
positive -> as x increases, y increases
negative -> as x increases, y decreases
The Price of Pollo
In El Salvador, "Country Chicken" is the most popular fried chicken franchise
in the country. Like most fast-food establishments, they provide a carry-out
service on their menu. You can buy their chicken in several different
quantities: 2, 6, 9, 15, or 21 pieces per box.
Over the years, prices have steadily risen, as things have a way of doing in
many areas of modern life. For example, on July 1, 1993, a box of two
pieces cost 8.35 colones, and on December 31, 1995, that same purchase
would cost you 11.25 colones.
(Note: prices are given in their original Salvadorean currency, colones; $1 U.S
colones.)
Using these two data 'points', you can form a linear equation of the slope-inter
mx + b. The independent variable x is time; the dependent variable y represe
Your task for this problem is to:
1. Find this equation.
2. Use your equation to predict what the price should have been for a 2
July 1, 1999.
Answer:
Hope I helped!~
Step-by-step explanation:
To find the equation of the line, we can use the slope-intercept form of the equation:
y = mx + b
where m is the slope of the line and b is the y-intercept.
Using the two data points given, we can calculate the slope:
m = (11.25 - 8.35) / (1995 - 1993) = 1.95
To find the y-intercept, we can use one of the data points:
8.35 = 1.95(1993) + b
b = -3884.65
So the equation of the line is:
y = 1.95x - 3884.65
To predict the price of a box of two pieces on July 1, 1999, we can substitute x = 6 (since 1999 is 6 years after 1993) into the equation:
y = 1.95(6) - 3884.65
y = 11.7 - 3884.65
y = -3872.95
This gives us a negative price, which obviously does not make sense. It is likely that the price of a box of two pieces was not linearly increasing during this time period, or that there were other factors influencing the price. Therefore, we cannot use this equation to accurately predict the price of a box of two pieces on July 1, 1999.
PLS HELP!! ILL GIVE BRAINLYEST!!
The school cafeteria serves portions of fried rice that are 140 grams each.
A. If 64 portions of rice are served, how many grams of rice would that be?
B. Write an expression for the total weight in grams of rice needed for p portions.
C. One day, the total weight of rice served was 11,340 grams. How many portions were served that day?
D. Write an expression for the number of portions served if the total rice weighed t grams
Please answer all questions
A. The grams of rice served for 64 portion is 8960 grams.
B. The expression for the total weight in grams of rice needed for p portions is 140p.
C. The portion when a total weight of 11340 grams was served is 81 portion
D. The expression for the number of portions served if the total rice weighed t grams is t / 140
How to find the expression for the number of grams served?The school cafeteria serves portions of fried rice that are 140 grams each.
A.
64 portions of rice are served. The grams of rice served is as follows:
1 portion = 140 grams
64 portions = ?
cross multiply
grams of rice served = 64 × 140
grams of rice served = 8960 grams
B.
The expression for the total weight in grams of rice needed for p portions is as follows:
total weight = 140p
C.
The portion when a total weight of 11340 grams was served is as follows:
140 grams = 1 portion
11340 grams = ?
portion = 11340 / 140
portion = 81 portion
D.
The expression for the number of portions served if the total rice weighed t grams is as follows:
portion = t / 140
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what is the equation of the line that passes through the point (6,-5) and has a slope of -1/6
The equation of the line that passes through the point (6,-5) and has a slope of -1/6 is y = (-1/6)x - 4.
We know that, the slope intercept form of a line is given by:-
y = mx + c
Where,
m represents the slope of the line,
c represents the y -intercept and,
(x,y) represent the coordinates of each of the ordered pairs in the line
Hence, we can write,
m = -1/6
One of the ordered pairs, (x,y) is (6,-5).
Hence, we can write,
-5 = (-1/6)*6 + c
-5 = -1 + c
c = -5 + 1
c = - 4
Hence, the equation of the line is given by:-
y = (-1/6)x - 4
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find the dy/dx
y= sin²x/cos²x
Answer:
d y dx=0
Explanation:
From the given
y=sin2x+cos2x
The right side of the equation is
=1
y=1
d y d x=d d x(1)=0
or we can do it this way.
y = sin2x+cos2x
d y d x=2
⋅(sinx)2−1
⋅
d d x(sinx)+2
(cosx)2−1 d d x(cosx)
d y d x=2⋅
sinx⋅cosx+2⋅cosx⋅(−sinx)
dydx=2⋅sinx⋅cosx−2⋅sinx⋅cosx
dydx=0
God bless....I hope the explanation is useful.
Since we have
\(y = \dfrac{\sin^2(x)}{\cos^2(x)} = \tan^2(x)\)
by definition of tangent, differentiating with the chain rule gives
\(\dfrac{dy}{dx} = \boxed{2 \tan(x) \sec^2(x)}\)
(second choice)
Need answer if you could show work would be nice