Find the midpoint of (-4,3) and (-11,-3)

Answer:

then study well

Step-by-step explanation:

that might help, but I could help with any study questions, but I cant do test questions from the test

Answer:

In the figure, the ray KM−→− bisects the angle ∠JKL .

The angles ∠JKM and ∠LKM are congruent.

So, m∠JKM=m∠LKM .

Step-by-step explanation:

Use 2.5th and 97.5th percentile of these values.

Bootstrapping, which is a type of test or metric that mimics the sampling process by using random sampling with replacement, belongs to the larger category of resampling techniques. With bootstrapping, sample estimates are given accuracy ratings such as bias, variance, confidence intervals, prediction error, etc.

A random sample with replacement from the original sample must be taken thousands of times in order to determine the 95% confidence interval for the population standard deviation. You calculate the sample standard deviation from each fresh sample. From the values of the 2.5th and the 97.5th percentile of these data, we can use the bootstrap method to determine the 95% confidence interval for the population standard deviation.

So we need to use 2.5th and the 97.5th percentile of these values.

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The equilibrium points of the given nonlinear ordinary differential equation dx/dt = x^2 - x - 6 are x = -2 and x = 3.

To find the equilibrium points of the given nonlinear ordinary differential equation, we set dx/dt equal to zero and solve for x. In this case, we have:

x^2 - x - 6 = 0

Factoring the quadratic equation, we get:

(x - 3)(x + 2) = 0

Setting each factor equal to zero, we find two equilibrium points:

x - 3 = 0  -->  x = 3

x + 2 = 0  -->  x = -2

So, the equilibrium points are x = -2 and x = 3.

To determine the stability of these equilibrium points, we can analyze the behavior of the system near each point. Stability is determined by the behavior of solutions to the differential equation when perturbed from the equilibrium points.

For the equilibrium point x = -2, we can substitute this value into the original equation:

dx/dt = (-2)^2 - (-2) - 6 = 4 + 2 - 6 = 0

The derivative is zero, indicating that the system is at rest at x = -2. To analyze stability, we can consider the behavior of nearby solutions. If the solutions tend to move away from x = -2, the equilibrium point is unstable. Conversely, if the solutions tend to move towards x = -2, the equilibrium point is stable.

For the equilibrium point x = 3, we substitute this value into the original equation:

dx/dt = 3^2 - 3 - 6 = 9 - 3 - 6 = 0

Similar to the previous case, the system is at rest at x = 3. To determine stability, we analyze the behavior of nearby solutions. If the solutions move away from x = 3, the equilibrium point is unstable. If the solutions move towards x = 3, the equilibrium point is stable.

In conclusion, the equilibrium points of the given nonlinear ordinary differential equation are x = -2 and x = 3. The stability of x = -2 and x = 3 can be determined by analyzing the behavior of nearby solutions.

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Answer: factor...

Step-by-step explanation:  If we divide a polynomial f(x) by (x - c), and (x - c) is a factor of the polynomial f(x), then the remainder of that division is simply equal to 0. Thus, according to this theorem, if the remainder of a division like those described above equals zero, (x - c) must be a factor.

Answer:

1

Step-by-step explanation:

Anything (besides 0) to the 0 power is 1.

B; the y axis is what moves up and down

Answer:

9:45 AM

Step-by-step explanation:

To get to work in the morning, Amanda cycles for 10 miles at the rate of 12 mph.

Time (hours) = Distance/speed

Hence, the time she spends cycling = 10mile/12 mph

= 0.8333333333 hour

Converting to minutes:

1 hour = 60 minutes

0.8333333333 hour =

0.8333333333 hours × 60 minutes/1 hour

= 50 minutes.

Hence, she spends 50 minutes cycling

She makes a 10 minutes stop for a cup of coffee, and then rides a bus for 15 minutes. The speed of the bus is 45 mph.

The total number of minutes she spends to get to work is calculated as:

(50 + 10 + 15)minutes

= 75 minutes.

It takes Amanda 75 minutes to get to work.

At what time will Amanda get to work if she leaves home at 8:30 AM?

= 8:30AM + 75 minutes

= 8:30 AM + 1 hour 15 minutes

= 9:45 AM

In hypothesis testing, the null hypothesis (H0) is a statement that there is no significant difference between two groups, or that a certain parameter is equal to a specified value. In this case, the null hypothesis is that the mean difference is 0, meaning there is no significant difference between the two groups being compared.

The alternative hypothesis (Ha), on the other hand, is a statement that contradicts the null hypothesis. It can be one-tailed (directional), indicating that the mean difference is greater than or less than 0, or two-tailed (non-directional), indicating that the mean difference is not equal to 0. So, to determine the null and alternative hypotheses in this case, we know that the null hypothesis is that the mean difference is 0. The alternative hypothesis can be either one of the following:
- Ha: The mean difference is not equal to 0 (two-tailed)
- Ha: The mean difference is greater than 0 (one-tailed)
- Ha: The mean difference is less than 0 (one-tailed)

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Answer: 22/13

Step-by-step explanation:

65e = 110

Divide 63 on both sides anyou get 22/13

Answer: 4(x-6)

Step-by-step explanation: If Leon is 6 years older than her sister, and her mother is 4 times the age of Anna, then their mother's age using Leon's age denoted as x would be 4(x-6).

The PMF of V can be found by taking the difference of the CDF values:

P_V(v) = F_V(v) - F_V(v-1) = { (1-p)(1-q) for v = 0, pq - (1-p)(1-q) for v = 1 }.

To find the CDF of Z = max{X,Y}, we note that Z = 1 if and only if at least one of X and Y is 1. Since X and Y are independent, we have:

P(Z = 1) = P(X = 1 or Y = 1) = P(X = 1) + P(Y = 1) - P(X = 1 and Y = 1)

= p + q - pq

Similarly, P(Z = 0) = P(X = 0 and Y = 0) = (1-p)(1-q). Therefore, the CDF of Z is given by:

F_Z(z) = P(Z ≤ z) = { 0 for z < 0,

(1-p)(1-q) for 0 ≤ z < 1,

p + q - pq for z ≥ 1 }

The PMF of Z can be found by taking the difference of the CDF values:

P_Z(z) = F_Z(z) - F_Z(z-1) = { (1-p)(1-q) for z = 0,

p + q - pq - (1-p)(1-q) for z = 1 }

Similarly, to find the CDF and PMF of V = min{X,Y}, note that V = 0 if and only if both X and Y are 0. We have:

P(V = 0) = P(X = 0 and Y = 0) = (1-p)(1-q)

Similarly, P(V = 1) = P(X = 1 and Y = 0 or X = 0 and Y = 1) = 2pq - pq = pq.

Therefore, the CDF of V is given by:

F_V(v) = P(V ≤ v) = { 0 for v < 0,

(1-p)(1-q) for 0 ≤ v < 1,

1 - pq for v ≥ 1 }

The PMF of V can be found by taking the difference of the CDF values:

P_V(v) = F_V(v) - F_V(v-1) = { (1-p)(1-q) for v = 0,

pq - (1-p)(1-q) for v = 1 }

The distribution of Z is known as a Bernoulli mixture distribution, while the distribution of V is known as a geometric mixture distribution.

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Answer:

47

Step-by-step explanation

4 weeks equals 28 days so you divide 1316 by 28

Answer:47

Step-by-step explanation:

Answer:

I know it’s 5 days late but yeehaw

Step-by-step explanation:

Answer: 4.7x + 7.9

Step-by-step explanation:

Answer:

Q4) 23

Q5) 18

Q6) 15

Step-by-step explanation:

Q6) In the given Stem and Leaf Plot, we have, the average weights as follows;

0.1, 0.1, 0.1, 0.2, 0.2, 0.3, 0.4, 0.4, 0.5, 1, 1, 1.2, 1.3, 1.7, 2.2

By counting the number of data given above, n = 15

Q5) The given data in the stem and leaf diagram are;

7, 9, 14, 15, 16, 18, 18, 21, 23, 30

The median of the 10 data points is the (10 + 1)/2 or the 5.5th data point

The fifth data point = 18

The sixth dat point = 18,

Therefore, the median, which is the 5.5th data point = 18 + (18 - 18)/2 = 18

The median = 18

Q4) The given data points are;

7, 9, 14, 15, 16, 18, 18, 21, 23, 30

The range = The largest data point value - The least data point value

Therefore;

The range = 30 - 7 = 23

The range = 23

Answer:

C

Step-by-step explanation:

Since y is squared we are going to square \(3^{(x+1)}\)

\(3^{^{(x+1)^{2} } ^{} }\)  We would multiply (x + 1) by 2 to get 2x + 2 as our exponent

The expression\(\( \frac{{z_1z_2}}{{z_3}} \) and \( \frac{{z_1}}{{z_3z_2}} \),\) the same steps can be followed to simplify and express them in both polar and standard forms.

To express \( \frac{{z_1z_3}}{{z_2}}, \frac{{z_1z_2}}{{z_3}},\) and \( \frac{{z_1}}{{z_3z_2}} \) in both polar and standard forms, let's simplify each expression step by step.

1. Expression: \( \frac{{z_1z_3}}{{z_2}} \)

Given:

\( z_1 = \frac{{-i}}{{-1 + i}} \)

\( z_2 = \frac{{1 + i}}{{1 - i}} \)

\( z_3 = \frac{{1}}{{10}} \left[2(i - 1)i + (-i + \sqrt{3})^3 + (1 - i)(1 - i)\right] \)

First, let's simplify each individual complex number:

\( z_1 = \frac{{-i}}{{-1 + i}} \)

To rationalize the denominator, we multiply the numerator and denominator by the conjugate of the denominator:

\( z_1 = \frac{{-i \cdot (1 + i)}}{{(-1 + i) \cdot (1 + i)}} \)

\( z_1 = \frac{{-i - i^2}}{{-1 + i - i + i^2}} \)

Since \( i^2 = -1 \), we have:

\( z_1 = \frac{{-i + 1}}{{2}} \)

\( z_1 = \frac{{1 - i}}{{2}} \)

\( z_2 = \frac{{1 + i}}{{1 - i}} \)

Again, rationalizing the denominator:

\( z_2 = \frac{{(1 + i) \cdot (1 + i)}}{{(1 - i) \cdot (1 + i)}} \)

\( z_2 = \frac{{1 + 2i + i^2}}{{1 - i + i - i^2}} \)

Simplifying with \( i^2 = -1 \):

\( z_2 = \frac{{1 + 2i - 1}}{{1 - (-1)}} \)

\( z_2 = \frac{{2i}}{{2}} \)

\( z_2 = i \)

Now, let's substitute these simplified forms back into the expression and simplify further:

\( \frac{{z_1z_3}}{{z_2}} = \frac{{\frac{{1 - i}}{{2}} \cdot z_3}}{{i}} \)

We'll now simplify \( z_3 \):

\( z_3 = \frac{{1}}{{10}} \left[2(i - 1)i + (-i + \sqrt{3})^3 + (1 - i)(1 - i)\right] \)

Expanding and simplifying each term:

\( z_3 = \frac{{1}}{{10}} \left[2(i^2 - i) + (-i + \sqrt{3})^3 + (1 - 2i + i^2)\right] \)

\( z_3 = \frac{{1}}{{10}} \left[2(-1 - i) + (-i + \sqrt{3})^3 + (1 - 2i - 1)\right] \)

\( z_3 = \frac{{1}}{{10}} \left[-2 - 2i + (-i + \sqrt{3})^3 - 2i\right] \)

\( z_3 = \frac{{1}}{{10}} \left[-2 - 4i + (-i^3 - 3i^2\sqrt{3} +

3i\sqrt{3} - \sqrt{3}^3) - 2i\right] \)

Simplifying further with \( i^2 = -1 \):

\( z_3 = \frac{{1}}{{10}} \left[-2 - 4i + (i^3 - 3i^2\sqrt{3} + 3i\sqrt{3} - 3) - 2i\right] \)

\( z_3 = \frac{{1}}{{10}} \left[-2 - 4i + (-i + 3i\sqrt{3} + 3i\sqrt{3} - 3) - 2i\right] \)

\( z_3 = \frac{{1}}{{10}} \left[-2 - 4i - i + 6i\sqrt{3} - 3 - 2i\right] \)

\( z_3 = \frac{{1}}{{10}} \left[-5 - 7i + 6i\sqrt{3}\right] \)

Now, substituting \( z_3 \) into the expression:

\(\( \frac{{z_1z_3}}{{z_2}} = \frac{{\frac{{1 - i}}{{2}} \cdot \left(\frac{{1}}{{10}} \left[-5 - 7i + 6i\sqrt{3}\right]\right)}}{{i}} \)\)

Simplifying further:

\(\( \frac{{z_1z_3}}{{z_2}} = \frac{{1 - i}}{{2}} \cdot \frac{{-5 - 7i + 6i\sqrt{3}}}{{10i}} \)\)

\(\( \frac{{z_1z_3}}{{z_2}} = \frac{{1 - i}}{{2}} \cdot \frac{{-5i - 7i^2 + 6i\sqrt{3}i}}{{10i}} \)\)

Using\(\( i^2 = -1 \)\):

\(\( \frac{{z_1z_3}}{{z_2}} = \frac{{1 - i}}{{2}} \cdot \frac{{-5i + 7 - 6\sqrt{3}}}{{10i}} \)\)

\(\( \frac{{z_1z_3}}{{z_2}} = \frac{{(1 - i)(7 - 6\sqrt{3} - 5i)}}{{20i}} \)\)

To express this expression in polar form, we need to convert the complex number \( 7 - 6\sqrt{3} - 5i \) into polar form:

Let \( a = 7 - 6\sqrt{3} \) and \( b = -5 \)

The magnitude (r) can be found using the Pythagorean theorem:\(\( r = \sqrt{a^2 + b^2} \)\)

The angle (θ) can be found using the inverse tangent: \(\( \theta = \arctan{\frac{b}{a}} \)\)

Calculating the values:

\( r = \sqrt{(7 - 6\sqrt{3})^2 + (-5)^2} \)

\( \theta = \arctan{\frac{-5}{7 - 6\sqrt{3}}} \)

Now, we can express the expression \( \frac{{z_1z_3}}{{z_2}} \) in both polar and standard forms:

\( \frac{{z_1z_3}}{{z_2}} = \frac{{(1 - i)(7 - 6\sqrt{3} - 5i)}}{{20

i}} \)

In standard form: \( \frac{{z_1z_3}}{{z_2}} = \frac{{7 - 6\sqrt{3} - 5i - 7i + 6\sqrt{3}i + 5}}{{20i}} \)

Simplifying: \( \frac{{z_1z_3}}{{z_2}} = \frac{{12 - 12i}}{{20i}} \)

\( \frac{{z_1z_3}}{{z_2}} = \frac{{3 - 3i}}{{5i}} \)

Multiplying the numerator and denominator by \( -i \) to rationalize the denominator:

\( \frac{{z_1z_3}}{{z_2}} = \frac{{3i + 3}}{{5}} \)

\( \frac{{z_1z_3}}{{z_2}} = \frac{{3}}{{5}}i + \frac{{3}}{{5}} \)

In polar form: \( \frac{{z_1z_3}}{{z_2}} = \frac{{(1 - i)(7 - 6\sqrt{3} - 5i)}}{{20i}} \)

For the expression \( \frac{{z_1z_2}}{{z_3}} \) and \( \frac{{z_1}}{{z_3z_2}} \), the same steps can be followed to simplify and express them in both polar and standard forms.

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The required experimental probability that the next batter will get a hit is 2/11.

A number that indicates how likely an event is to occur is called its probability. It is communicated as a number in the reach from 0 and 1, or, utilizing rate documentation, in the reach from 0% to 100 percent. The higher the probability, the more likely the event is to occur.

The experimental probability of an event happening is defined as the number of times the event occurs divided by the total number of trials or events.

In this case, we are given that 4 out of 22 batters have gotten a hit so far. Therefore, the experimental probability that the next batter will get a hit is:

P(hit) = Number of hits / Total number of batters

P(hit) = 4/22

Simplifying:

P(hit) = 2/11

Therefore, the experimental probability that the next batter will get a hit is 2/11.

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The chain rule is a formula used in calculus to find the derivative of a composition of functions. It is an important tool for solving problems in many areas of mathematics and science.

The chain rule formula can be stated as follows:

If y = f(g(x)), then the derivative of y with respect to x is given by:

dy/dx = (df/dg) * (dg/dx)

In other words, the derivative of y with respect to x is equal to the derivative of f with respect to g, multiplied by the derivative of g with respect to x.

Here, f and g are functions of x, and y is a function of g. The chain rule formula tells us how to find the derivative of y with respect to x, by taking into account the effect of both f and g on the function y.

The chain rule can be extended to more complex compositions of functions, by applying the formula repeatedly. For example, if y = f(g(h(x))), then the chain rule can be applied twice, as follows:

dy/dx = (df/dg) * (dg/dh) * (dh/dx)

This formula tells us how to find the derivative of y with respect to x, by taking into account the effects of all three functions f, g, and h on the function y.

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Answer:

what you mean about circles but i do know probability

Step-by-step explanation:

conditional probability is a measure of the probability of an event occurring, given that another event has already occurred.

Answer:

$1800 and $2500

Step-by-step explanation:

Let he invested a total of  $P and$( P+700) in each investment so according to question

9.2*P*1+10.4*(P+700)*1= 42560

19.6P+ 7280= 42560

19.6P = 42560-7280= 35280

P=$ 1800

So, he invested $1800 and $2500 respectively.

Answer:7

Step-by-step explanation:Divide 84 by 12 and it gives you 7.

Hope it helps :)

Therefore, the unit rate of \(\frac{84}{12}\) is \(7\).

What is the simplification?

Simplification is reducing the expression/fraction/problem in a simpler form. It makes the problem easy with calculations and solving.

As per the given information

\(\frac{84}{12}=7\)

Hence, the unit rate of \(\frac{84}{12}\) is \(7\).

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The four functions can be described as follows: a) rect(x/8) - rectangular pulse centered at the origin with a width of 8 units, b) Δ(ω/10) - Dirac delta function with a spike at ω = 0 and zero everywhere else, c) rect(t-3/4) - rectangular pulse centered at t = 3/4 with a width of 1 unit, d) sinc(t) * rect(t/4) - modulated sinc function by a rectangular pulse of width 4 units centered at the origin.

a) rect(x/8):

The function rect(x/8) represents a rectangle function with a width of 8 units centered at the origin. It has a value of 1 within the interval [-4, 4] and a value of 0 outside this interval. The graph of rect(x/8) will consist of a rectangular pulse centered at the origin with a width of 8 units.

b) Δ(ω/10):

The function Δ(ω/10) represents a Dirac delta function with an argument ω/10. The Dirac delta function is a mathematical construct that is zero everywhere except at the origin, where it is infinitely tall and its integral is equal to 1. The graph of Δ(ω/10) will be a spike at ω = 0. The value of Δ(ω/10) at ω ≠ 0 is zero.

c) rect(t-3/4):

The function rect(t-3/4) represents a rectangle function with a width of 1 centered at t = 3/4. It has a value of 1 within the interval [3/4 - 1/2, 3/4 + 1/2] = [1/4, 5/4] and a value of 0 outside this interval. The graph of rect(t-3/4) will consist of a rectangular pulse centered at t = 3/4 with a width of 1 unit.

d) sinc(t) * rect(t/4):

The function sinc(t) * rect(t/4) represents the product of the sinc function and a rectangle function. The sinc function is defined as sinc(t) = sin(t)/t. The rectangle function rect(t/4) has a width of 4 units centered at the origin. The graph of sinc(t) * rect(t/4) will be the multiplication of the two functions, resulting in a modulated sinc function where the rectangular pulse shapes the sinc function.

Therefore, the four functions can be described as follows:

a) rect(x/8) - rectangular pulse centered at the origin with a width of 8 units.

b) Δ(ω/10) - Dirac delta function with a spike at ω = 0 and zero everywhere else.

c) rect(t-3/4) - rectangular pulse centered at t = 3/4 with a width of 1 unit.

d) sinc(t) * rect(t/4) - modulated sinc function by a rectangular pulse of width 4 units centered at the origin.

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Any state with a number of zip codes greater than 23.5 hundred would be considered a high outlier.

Since the five-number summary for the data is not provided in the question, we cannot determine the number of high outliers. However, we can explain how to find the number of high outliers using the five-number summary.

To find the number of high outliers, we need to first calculate the interquartile range (IQR), which is the difference between the third quartile (Q3) and the first quartile (Q1). Any data point that is greater than Q3 + 1.5 × IQR is considered a high outlier.

The five-number summary consists of the minimum value, Q1, Q2 (the median), Q3, and the maximum value of the data set. Let's assume that the five-number summary for the data set is given as follows:

- Minimum value: 2

- Q1: 6

- Q2 (median): 9

- Q3: 13

- Maximum value: 30

To find the IQR, we can subtract Q1 from Q3:

```

IQR = Q3 - Q1 = 13 - 6 = 7

```

To find the high outliers, we need to add 1.5 times the IQR to Q3 and consider any zip codes greater than this value as high outliers:

```

High outliers = Q3 + 1.5 × IQR

High outliers = 13 + 1.5 × 7

High outliers = 13 + 10.5

High outliers = 23.5

```

Therefore, any state with a number of zip codes greater than 23.5 hundred would be considered a high outlier. Since we do not know the actual number of zip codes assigned to each state, we cannot determine the number of high outliers.

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Answer:

The big blue rectangle and the bottom right green trapezoid

Step-by-step explanation:

The shapes with at least one pair of perpendicular sides are the blue shape and the green shape at the button-right corner.

That parallelogram in which adjacent sides are perpendicular to each other is called a rectangle.

A rectangle is always a parallelogram and a quadrilateral but reverse statement may or may not be true.

Perpendicular means two lines, or sides, that meet at a right angle.

A right angle is the measurement of 90 degrees.

We know that Perpendicular sides are found in shapes like; rectangles, squares and other shapes with at least one angle measurement equal to 90⁰.

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We need AC ≅ XZ to show that triangle ABC ≅ triangle XYZ by ASA congruence of triangle.

What is ASA congruence of triangle?

The two triangles are considered to be congruent according to the ASA rule if any two angles and the side located between the angles of one triangle are equal to the corresponding two angles and side located between the angles of the second triangle.

We are given the following:

1. ∠A ≅ ∠X

2. ∠C ≅ ∠Z

Now, in order to show the triangles as congruent by ASA congruence of triangle, we need the side which is in between both the angles.

The sides in between both the angles are AC and XZ.

Hence, we need AC ≅ XZ to show that triangle ABC ≅ triangle XYZ by ASA congruence of triangle.

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Answer:

\(2. \: x > 0 \\ 3. \: - 1 \leqslant x < 3 \\ 4. \: 0 > x > 2\)